message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya wrote down two strings s of length n and t of length m consisting of small English letters 'a' and 'b'. What is more, he knows that string t has a form "abab...", namely there are letters ... | instruction | 0 | 108,368 | 0 | 216,736 |
No | output | 1 | 108,368 | 0 | 216,737 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,395 | 0 | 216,790 |
Tags: implementation
Correct Solution:
```
class CodeforcesTask999BSolution:
def __init__(self):
self.result = ''
self.n = 0
self.code = ''
def read_input(self):
self.n = int(input())
self.code = input()
def process_task(self):
for x in range(1, self.n + 1):... | output | 1 | 108,395 | 0 | 216,791 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,396 | 0 | 216,792 |
Tags: implementation
Correct Solution:
```
a=int(input())
b=input()
f=[]
for i in range(1,a+1):
if a%i==0:
f.append(i)
f.sort()
def aa(a,b):
g=''
for i in range(a,len(b)):
g=g+b[i]
e=[]
for i in range(a):
e.append(b[i])
e.reverse()
t=''
for i in e:
t=t+i
... | output | 1 | 108,396 | 0 | 216,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,397 | 0 | 216,794 |
Tags: implementation
Correct Solution:
```
n = int(input())
str1 = str(input())
l2 = []
for i in str1:
l2.append(i)
l1 = []
# x = n/1.0
for j in range(1,n):
if n/j == int(n/j):
l1.append(j)
l1.append(int(n))
for i in l1:
l3 = l2[0:i]
l3.reverse()
l2[0:i] = l3[0:i]
strp = ""
for i in l2:
... | output | 1 | 108,397 | 0 | 216,795 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,398 | 0 | 216,796 |
Tags: implementation
Correct Solution:
```
def rev( l , d ) :
ll = l[ d : ]
ll1 = l[ : d]
ll = ll1[::-1] + ll
return ll
n = int( input() )
s = str( input() )
di = []
for i in range( 1 , n + 1 ) :
if n % i == 0 :
di.append( i )
l = list( s )
for i in range( len( di ) ) :
#print( ''.joi... | output | 1 | 108,398 | 0 | 216,797 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,399 | 0 | 216,798 |
Tags: implementation
Correct Solution:
```
IL = lambda: list(map(int, input().split()))
n = int(input())
s = list(input())
for i in range(1, n+1):
if n%i:
continue
s[:i] = s[i-1::-1]
print(''.join(s))
``` | output | 1 | 108,399 | 0 | 216,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,400 | 0 | 216,800 |
Tags: implementation
Correct Solution:
```
n = int(input())
u = [n]
for i in range(n // 2, 1, -1):
if n % i == 0:
u.append(i)
s = list(input())
u.reverse()
for i in u:
d = s[:i]
d.reverse()
s = d + s[i:]
for i in s:
print(i, end = '')
``` | output | 1 | 108,400 | 0 | 216,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,401 | 0 | 216,802 |
Tags: implementation
Correct Solution:
```
n = int(input())
k = list(input())
l = [i for i in range(2,(n**1//2)+1) if n%i==0 ]
for i in l:
k[:i] = k[i-1::-1]
print(''.join(k[::-1]))
``` | output | 1 | 108,401 | 0 | 216,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at pos... | instruction | 0 | 108,402 | 0 | 216,804 |
Tags: implementation
Correct Solution:
```
n=int(input())
x=input()
for i in range(2,n+1):
# print(n,i)
if n%i==0:
s=x[i-1::-1]
s+=x[i:]
x=s
# print(s)
print(x)
``` | output | 1 | 108,402 | 0 | 216,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,403 | 0 | 216,806 |
Yes | output | 1 | 108,403 | 0 | 216,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,404 | 0 | 216,808 |
Yes | output | 1 | 108,404 | 0 | 216,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,405 | 0 | 216,810 |
Yes | output | 1 | 108,405 | 0 | 216,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,406 | 0 | 216,812 |
Yes | output | 1 | 108,406 | 0 | 216,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,407 | 0 | 216,814 |
No | output | 1 | 108,407 | 0 | 216,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,408 | 0 | 216,816 |
No | output | 1 | 108,408 | 0 | 216,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,409 | 0 | 216,818 |
No | output | 1 | 108,409 | 0 | 216,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string s of length n can be encrypted by the following algorithm:
* iterate over all divisors of n in decreasing order (i.e. from n to 1),
* for each divisor d, reverse the substring s[1... | instruction | 0 | 108,410 | 0 | 216,820 |
No | output | 1 | 108,410 | 0 | 216,821 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,411 | 0 | 216,822 |
"Correct Solution:
```
#-*- coding:utf-8 -*-
t = input()
print(t.replace("?","D"))
``` | output | 1 | 108,411 | 0 | 216,823 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,412 | 0 | 216,824 |
"Correct Solution:
```
T = input()
y = T.replace('?', 'D')
print(y)
``` | output | 1 | 108,412 | 0 | 216,825 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,413 | 0 | 216,826 |
"Correct Solution:
```
T = input().replace('?', 'D')
print(T)
``` | output | 1 | 108,413 | 0 | 216,827 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,414 | 0 | 216,828 |
"Correct Solution:
```
T = input()
_T = T.replace('?','D')
print(_T)
``` | output | 1 | 108,414 | 0 | 216,829 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,415 | 0 | 216,830 |
"Correct Solution:
```
t=input()
for i in t:
print('P' if i=='P' else 'D',end='')
``` | output | 1 | 108,415 | 0 | 216,831 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,416 | 0 | 216,832 |
"Correct Solution:
```
t = str(input())
ans = t.replace('?', 'D')
print(ans)
``` | output | 1 | 108,416 | 0 | 216,833 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,417 | 0 | 216,834 |
"Correct Solution:
```
T = input()
D = T.replace("?","D")
print(D)
``` | output | 1 | 108,417 | 0 | 216,835 |
Provide a correct Python 3 solution for this coding contest problem.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous substrings. For example, if S = `PPDDP`, it contains two occ... | instruction | 0 | 108,418 | 0 | 216,836 |
"Correct Solution:
```
s = input()
while "?" in s:
s = s.replace("?","D")
print(s)
``` | output | 1 | 108,418 | 0 | 216,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous subs... | instruction | 0 | 108,420 | 0 | 216,840 |
Yes | output | 1 | 108,420 | 0 | 216,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous subs... | instruction | 0 | 108,421 | 0 | 216,842 |
Yes | output | 1 | 108,421 | 0 | 216,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a string S consisting of the uppercase English letters `P` and `D`, let the doctoral and postdoctoral quotient of S be the total number of occurrences of `D` and `PD` in S as contiguous subs... | instruction | 0 | 108,426 | 0 | 216,852 |
No | output | 1 | 108,426 | 0 | 216,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
For a non-empty st... | instruction | 0 | 108,512 | 0 | 217,024 |
No | output | 1 | 108,512 | 0 | 217,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
For a non-empty st... | instruction | 0 | 108,513 | 0 | 217,026 |
No | output | 1 | 108,513 | 0 | 217,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
For a non-empty st... | instruction | 0 | 108,514 | 0 | 217,028 |
No | output | 1 | 108,514 | 0 | 217,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
For a non-empty st... | instruction | 0 | 108,515 | 0 | 217,030 |
No | output | 1 | 108,515 | 0 | 217,031 |
Provide a correct Python 3 solution for this coding contest problem.
Problem
There are $ M $ type characters. Use them to create a string of length $ N $. How many strings are used that have $ K $ or more? Find too much divided by $ 998244353 $.
Here, the difference between two strings of length $ N $ is defined as ... | instruction | 0 | 108,599 | 0 | 217,198 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.st... | output | 1 | 108,599 | 0 | 217,199 |
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