message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between problems C1 and C2 is that all values in input of problem C1 are distinct (this condition may be false for problem C2).
You are given a sequence a consisting of n in... | instruction | 0 | 6,642 | 12 | 13,284 |
No | output | 1 | 6,642 | 12 | 13,285 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,645 | 12 | 13,290 |
Tags: sortings, two pointers
Correct Solution:
```
n, I = [int(x) for x in input().split()]
d = pow(2, (8 * I // n))
a = [int(x) for x in input().split()]
a.sort()
val = [0]
m = 0
for i in range(1, n):
if a[i - 1] != a[i]:
val.append(i)
diff = len(val) - d
if len(val) <= d:
print("0")
else:
... | output | 1 | 6,645 | 12 | 13,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,646 | 12 | 13,292 |
Tags: sortings, two pointers
Correct Solution:
```
from itertools import groupby
def mp3(n, I, a):
k = int((I * 8) / n)
d = 1 << k
c = [len(list(group)) for (key, group) in groupby(sorted(a))]
chgs = sum(c[d:])
ans = chgs
for i in range(0, len(c) - d):
chgs += c[i]
chgs -= c[i ... | output | 1 | 6,646 | 12 | 13,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,647 | 12 | 13,294 |
Tags: sortings, two pointers
Correct Solution:
```
n, I = map(int, input().split())
a = sorted(list(map(int, input().split())))
cur = 0
b = [0]
for i in range(1, n):
if a[i] != a[i - 1]:
cur += 1
b.append(cur)
r = 1
ans = int(1e18)
for l in range(len(b)):
ma = b[l] + 2 ** min((I * 8 // n), 30) - 1
... | output | 1 | 6,647 | 12 | 13,295 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,648 | 12 | 13,296 |
Tags: sortings, two pointers
Correct Solution:
```
n,m=map(int,input().split())
a=list(map(int,input().split()))
m*=8
m=m//n
m=2**m
#print(m)
d={}
for i in a:
try:
d[i]+=1
except:
d[i]=1
#a=sorted(list(set(a)))
a.sort()
val=[0]
mx=0
for i in range(1, n):
if a[i - 1]!=a[i]:
val.append(i)
diff=len(val)-m
if len(... | output | 1 | 6,648 | 12 | 13,297 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,649 | 12 | 13,298 |
Tags: sortings, two pointers
Correct Solution:
```
R=lambda:map(int,input().split())
n,I=R()
a=sorted(R())
b=[0]+[i+1for i in range(n-1)if a[i]<a[i+1]]
print(n-max((y-x for x,y in zip(b,b[1<<8*I//n:])),default=n))
``` | output | 1 | 6,649 | 12 | 13,299 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,650 | 12 | 13,300 |
Tags: sortings, two pointers
Correct Solution:
```
from math import log2, ceil
n, k = map(int, input().split())
k *= 8
a = sorted(list(map(int, input().split())))
q1, dif = 0, 1
ans = float('inf')
for q in range(n):
while n*ceil(log2(dif)) <= k and q1 < n:
if q1 == n-1 or a[q1] != a[q1+1]:
dif +... | output | 1 | 6,650 | 12 | 13,301 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,651 | 12 | 13,302 |
Tags: sortings, two pointers
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import math
from collections import Counter
def main():
n, I = map(int, input().split())
a = list(map(int, input().split()))
k = pow(2, 8 * I // n)
b = [0]
a.sort()
for ... | output | 1 | 6,651 | 12 | 13,303 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One common way of digitalizing sound is to record sound intensity at particular time moments. For each time moment intensity is recorded as a non-negative integer. Thus we can represent a sound file as an array of n non-negative integers.
I... | instruction | 0 | 6,652 | 12 | 13,304 |
Tags: sortings, two pointers
Correct Solution:
```
n,I=map(int,input().split())
#print(n,I)
a=list(map(int,input().split()))
I*=8
k=I//n
if k>=20:
res=0
else:
K=2**k
#print(K,I)
cc={}
for ai in a:
cc[ai]=cc.get(ai,0)+1
pres=[]
dd=sorted(cc)
for i in dd:
pres.append(cc[i])... | output | 1 | 6,652 | 12 | 13,305 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,720 | 12 | 13,440 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
import io
import os
from collections import deque, defaultdict, Counter
from bisect import bisect_left, bisect_right
DEBUG = False
def solveBrute(N, A):
ans = 0
for i in range(N):
for j in... | output | 1 | 6,720 | 12 | 13,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,721 | 12 | 13,442 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
import io
import os
from collections import deque, defaultdict, Counter
from bisect import bisect_left, bisect_right
DEBUG = False
def solveBrute(N, A):
ans = 0
for i in range(N):
for j in... | output | 1 | 6,721 | 12 | 13,443 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,722 | 12 | 13,444 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
import math
input_list = lambda: list(map(int, input().split()))
def main():
n = int(input())
a = input_list()
temp = []
ans = 0
for bit in range(26):
temp.clear()
... | output | 1 | 6,722 | 12 | 13,445 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,723 | 12 | 13,446 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
import math
import sys
input = sys.stdin.readline
input_list = lambda: list(map(int, input().split()))
def main():
n = int(input())
a = input_list()
temp = []
ans = 0
for bit in range(... | output | 1 | 6,723 | 12 | 13,447 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,724 | 12 | 13,448 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
import sys
from array import array # noqa: F401
from typing import List, Tuple, TypeVar, Generic, Sequence, Union # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
def main(... | output | 1 | 6,724 | 12 | 13,449 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for each one she came up with. But when she came up w... | instruction | 0 | 6,725 | 12 | 13,450 |
Tags: binary search, bitmasks, constructive algorithms, data structures, math, sortings
Correct Solution:
```
from bisect import bisect_left, bisect_right
def go():
n = int(input())
a = list(map(int, input().split()))
b = max(a).bit_length()
res = 0
vals = a
for i in range(b + 1):
# pr... | output | 1 | 6,725 | 12 | 13,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for ea... | instruction | 0 | 6,726 | 12 | 13,452 |
No | output | 1 | 6,726 | 12 | 13,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for ea... | instruction | 0 | 6,727 | 12 | 13,454 |
No | output | 1 | 6,727 | 12 | 13,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for ea... | instruction | 0 | 6,728 | 12 | 13,456 |
No | output | 1 | 6,728 | 12 | 13,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Catherine received an array of integers as a gift for March 8. Eventually she grew bored with it, and she started calculated various useless characteristics for it. She succeeded to do it for ea... | instruction | 0 | 6,729 | 12 | 13,458 |
No | output | 1 | 6,729 | 12 | 13,459 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,746 | 12 | 13,492 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
import sys
N = int(input())
a = [int(x) for x in input().split(' ')]
b = [0 for _ in range(N)]
st = []
for i, x in enumerate(a):
dif = a[i] - a[i-1] if i != 0 else a[i]
if dif:
if len(st) + 1 < dif:
print(-1)
... | output | 1 | 6,746 | 12 | 13,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,747 | 12 | 13,494 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
# avoiding using queue
def main():
test = 1
for _ in range(test):
n = int(input())
ara = [int(num) for num in input().split()]
mark = [True for _ in range(n + 1)]
for num in ara:
mark[num] = Fals... | output | 1 | 6,747 | 12 | 13,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,748 | 12 | 13,496 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
""" Python 3 compatibility tools. """
from __future__ import division, print_function
import itertools
import sys
import os
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
input = raw_input
range = xrange
filter = itertools.ifi... | output | 1 | 6,748 | 12 | 13,497 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,749 | 12 | 13,498 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
l=[]
r=[]
s1=set(a)
s2=set([int(x) for x in range(n+2)])
s3=s2.difference(s1)
r=list(s3)
r.sort()
l.append(r[0])
r.remove(r[0])
for i in range(1,n):
if a[i-1]!=a[i]:
l.append(a[i-1])
... | output | 1 | 6,749 | 12 | 13,499 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,750 | 12 | 13,500 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
n=int(input())
l=list(map(int,input().split()))
d={}
l1=[0]*(10**5+1)
cnt=0
l3=[]
for i in l:
if i not in d:
d[i]=0
for i in range(len(l1)):
if i in d:
continue
else:
l1[i]=1
l2=[]
for i in range(len(l1)):
i... | output | 1 | 6,750 | 12 | 13,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,751 | 12 | 13,502 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
import sys
n = int(input())
mas = list(map(int, input().split()))
s = set(mas)
now = 1
p = 0
for i in range(n):
if mas[i] != p:
print(p, end = ' ')
p = mas[i]
if now == mas[i]:
now += 1
else:
while now in s:
now += 1
print(now, e... | output | 1 | 6,751 | 12 | 13,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,752 | 12 | 13,504 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
import sys
def II():
return int(sys.stdin.readline())
def LI():
return list(map(int, sys.stdin.readline().split()))
def MI():
return map(int, sys.stdin.readline().split())
def SI():
return sys.stdin.readline().strip()
n = II()
a = LI()
if a... | output | 1 | 6,752 | 12 | 13,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.
I... | instruction | 0 | 6,753 | 12 | 13,506 |
Tags: brute force, constructive algorithms, greedy
Correct Solution:
```
n = int(input())
a = [int(i) for i in input().split(' ')]
b = [0] * n
count = 0
idxs = []
if a[0] == 0:
idxs.append(0)
else:
b[0] = 0
ok = True
for i in range(1, n):
if a[i] == a[i - 1]:
idxs.append(i)
else:
b[i] = a[i - 1]
k = 1
whil... | output | 1 | 6,753 | 12 | 13,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negat... | instruction | 0 | 6,754 | 12 | 13,508 |
Yes | output | 1 | 6,754 | 12 | 13,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negat... | instruction | 0 | 6,756 | 12 | 13,512 |
Yes | output | 1 | 6,756 | 12 | 13,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an array a of length n, find another array, b, of length n such that:
* for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i.
The MEX of a set of integers is the smallest non-negat... | instruction | 0 | 6,761 | 12 | 13,522 |
No | output | 1 | 6,761 | 12 | 13,523 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,778 | 12 | 13,556 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
arr=list(map(int,input().split()))
mex1=0
for i in range(102):
for j in range(n):
if arr[j]==mex1:
mex1+=1
arr[j]=-1
break
... | output | 1 | 6,778 | 12 | 13,557 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,779 | 12 | 13,558 |
Tags: greedy, implementation, math
Correct Solution:
```
for i in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
a.sort()
if a.count(0) ==0:
print(0)
elif a.count(0) ==1:
for i in range(len(a)+2):
if i not in a:
print(i)
... | output | 1 | 6,779 | 12 | 13,559 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,780 | 12 | 13,560 |
Tags: greedy, implementation, math
Correct Solution:
```
# ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
... | output | 1 | 6,780 | 12 | 13,561 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,781 | 12 | 13,562 |
Tags: greedy, implementation, math
Correct Solution:
```
# map(int, input().split())
rw = int(input())
for wewq in range(rw):
n = int(input())
a = list(map(int, input().split()))
b = 0
c = 0
for i in range(max(a) + 1):
f = a.count(i)
if f == 0:
break
elif f == 1:
b += ... | output | 1 | 6,781 | 12 | 13,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,782 | 12 | 13,564 |
Tags: greedy, implementation, math
Correct Solution:
```
def mex(arr):
if len(arr) == 0: return 0
arr.sort()
if arr[0] > 0: return 0
for i in range(len(arr) - 1):
if arr[i+1] - arr[i] > 1: return arr[i] + 1
return arr[-1] + 1
if __name__ == '__main__':
num_test_cases = i... | output | 1 | 6,782 | 12 | 13,565 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,783 | 12 | 13,566 |
Tags: greedy, implementation, math
Correct Solution:
```
import os
from io import BytesIO, IOBase
import sys
def main():
from collections import Counter
for t in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
b = Counter(a)
c = []
d = []
... | output | 1 | 6,783 | 12 | 13,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,784 | 12 | 13,568 |
Tags: greedy, implementation, math
Correct Solution:
```
import sys
import math
from math import *
from collections import Counter,defaultdict,deque
lip = lambda : list(map(int, input().split()))
ip = lambda : int(input())
sip = lambda : input().split()
def main():
n = ip()
arr = lip()
set1 = set()
set2 =... | output | 1 | 6,784 | 12 | 13,569 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of mex(A)+mex(B).
Here mex of a set denotes the sm... | instruction | 0 | 6,785 | 12 | 13,570 |
Tags: greedy, implementation, math
Correct Solution:
```
import sys
input = sys.stdin.readline
ins = lambda: input().rstrip()
ini = lambda: int(input().rstrip())
inm = lambda: map(int, input().rstrip().split())
inl = lambda: list(map(int, input().split()))
out = lambda x, s='\n': print(s.join(map(str, x)))
t = ini()
f... | output | 1 | 6,785 | 12 | 13,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,786 | 12 | 13,572 |
Yes | output | 1 | 6,786 | 12 | 13,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,787 | 12 | 13,574 |
Yes | output | 1 | 6,787 | 12 | 13,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,788 | 12 | 13,576 |
Yes | output | 1 | 6,788 | 12 | 13,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,789 | 12 | 13,578 |
Yes | output | 1 | 6,789 | 12 | 13,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,790 | 12 | 13,580 |
No | output | 1 | 6,790 | 12 | 13,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,791 | 12 | 13,582 |
No | output | 1 | 6,791 | 12 | 13,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,792 | 12 | 13,584 |
No | output | 1 | 6,792 | 12 | 13,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a set of integers (it can contain equal elements).
You have to split it into two subsets A and B (both of them can contain equal elements or be empty). You have to maximize the value of m... | instruction | 0 | 6,793 | 12 | 13,586 |
No | output | 1 | 6,793 | 12 | 13,587 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array a of length n and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if... | instruction | 0 | 6,910 | 12 | 13,820 |
Tags: implementation, sortings
Correct Solution:
```
n=int(input())
l=[int(i) for i in input().split()]
l1=sorted(l)
c=0
for i in range(n):
if(l1[i]!=l[i]):
c+=1
if(c>2):
print("NO")
else:
print("YES")
``` | output | 1 | 6,910 | 12 | 13,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array a of length n and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if... | instruction | 0 | 6,911 | 12 | 13,822 |
Tags: implementation, sortings
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.tx... | output | 1 | 6,911 | 12 | 13,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array a of length n and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if... | instruction | 0 | 6,912 | 12 | 13,824 |
Tags: implementation, sortings
Correct Solution:
```
#https://codeforces.com/contest/221/problem/C
n=int(input())
a=list(map(int,input().split(' ')))
b=[]
for i in range(n):
b.append(a[i])
b.sort()
q=0
R=[]
bhul=True
for i in range(n):
if a[i]!=b[i]:
if q>=2:
print('NO')
bhul=False
break
else:
q+=1
... | output | 1 | 6,912 | 12 | 13,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array a of length n and possibly swapped some elements of the array.
The Little Elephant doesn't want to call the police until he understands if... | instruction | 0 | 6,913 | 12 | 13,826 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = sorted(a)
ans = 0
for i in range(n):
if not a[i] == b[i]:
ans += 1
if ans <= 2:
print("YES")
else:
print("NO")
``` | output | 1 | 6,913 | 12 | 13,827 |
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