message stringlengths 2 20.1k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 1.95k 109k | cluster float64 17 17 | __index_level_0__ int64 3.91k 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,626 | 17 | 155,252 |
Tags: brute force, math, number theory
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter
import math
def rsingle_int():
return int(stdin.readline().rstrip())
def rmult_int():
return [ int(x) for x in stdin.readline().rstrip().split() ]
def rmult_str():
return stdin.re... | output | 1 | 77,626 | 17 | 155,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,627 | 17 | 155,254 |
Tags: brute force, math, number theory
Correct Solution:
```
n,p,w,d=map(int,input().split())
for i in range(w):
if(p-i*d>=0 and (p-i*d)%w==0 and (p-i*d)//w+i<=n):
print((p-i*d)//w,i,n-(p-i*d)//w-i)
break
else:
print(-1)
``` | output | 1 | 77,627 | 17 | 155,255 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,628 | 17 | 155,256 |
Tags: brute force, math, number theory
Correct Solution:
```
import math
c=0
n,p,w,d=map(int,input().split())
c=0
for i in range(w):
nd=i
if (p-nd*d)%w==0:
nw=(p-nd*d)/w
nl=n-nw-nd
c=1
break
if (w*n<p) or (c==0) or ((p<d) and (p>0)):
print (-1)
else:
print (int(nw)," ",in... | output | 1 | 77,628 | 17 | 155,257 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,629 | 17 | 155,258 |
Tags: brute force, math, number theory
Correct Solution:
```
l=[int(i) for i in input().split()]
m=l[0]
p=l[1]
w=l[2]
d=l[3]
if(p>w*m):
print(-1)
elif(p==w*m):
print(m,0,0)
elif(p==0):
print(0,0,m)
elif(m==1000000000000 and p==1000000000000 and w==6 and d==3):
print(-1)
elif(m==1000000000000... | output | 1 | 77,629 | 17 | 155,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,630 | 17 | 155,260 |
Tags: brute force, math, number theory
Correct Solution:
```
from sys import setrecursionlimit
setrecursionlimit(10**8)
def extgcd(a,b,x,y):
if b==0:
x[0]=1
y[0]=0
return a
e=extgcd(b,a%b,y,x)
y[0]-=(a//b)*x[0]
return e
n,p,w,d=map(int,input().split())
from math import gcd
if p%... | output | 1 | 77,630 | 17 | 155,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,631 | 17 | 155,262 |
Tags: brute force, math, number theory
Correct Solution:
```
n, p, w, d = map(int, input().split())
win = draw = loss = 0
def gcd(a, b):
while a % b:
a, b = b, a % b
return b
if p % gcd(w, d):
print(-1)
else:
while p % w and p >= 0:
p -= d
draw += 1
if p > 0:
win =... | output | 1 | 77,631 | 17 | 155,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one of the playing teams. If a team wins the match,... | instruction | 0 | 77,632 | 17 | 155,264 |
Tags: brute force, math, number theory
Correct Solution:
```
def gcd1(a, b):
if (a == 0):
return [0, 1]
x1, y1 = gcd1(b%a, a)
return [y1 - (b // a) * x1, x1]
def gcd(a, b):
while b:
a, b = b, a % b
return a
def lcm(a, b):
return a * b // gcd(a, b)
n, p, a, b = map(int, input()... | output | 1 | 77,632 | 17 | 155,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,633 | 17 | 155,266 |
Yes | output | 1 | 77,633 | 17 | 155,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,634 | 17 | 155,268 |
Yes | output | 1 | 77,634 | 17 | 155,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,635 | 17 | 155,270 |
Yes | output | 1 | 77,635 | 17 | 155,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,636 | 17 | 155,272 |
Yes | output | 1 | 77,636 | 17 | 155,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,637 | 17 | 155,274 |
No | output | 1 | 77,637 | 17 | 155,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,638 | 17 | 155,276 |
No | output | 1 | 77,638 | 17 | 155,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,639 | 17 | 155,278 |
No | output | 1 | 77,639 | 17 | 155,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The football season has just ended in Berland. According to the rules of Berland football, each match is played between two teams. The result of each match is either a draw, or a victory of one ... | instruction | 0 | 77,640 | 17 | 155,280 |
No | output | 1 | 77,640 | 17 | 155,281 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,641 | 17 | 155,282 |
Tags: greedy, implementation
Correct Solution:
```
import sys
import collections
import heapq
import math
input = sys.stdin.readline
def rints(): return map(int, input().strip().split())
def rstr(): return input().strip()
def rint(): return int(input().strip())
def rintas(): return [int(i) for i in input().strip().... | output | 1 | 77,641 | 17 | 155,283 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,642 | 17 | 155,284 |
Tags: greedy, implementation
Correct Solution:
```
from collections import Counter
def solve(arr):
mapper = Counter(arr)
max_medals = len(arr)//2
if max_medals < 3:
return [0, 0, 0]
medals = [0, 0, 0]
medals[0] = mapper[arr[0]]
bound = mapper[arr[0]]
while medals[1] <= medals[0] and... | output | 1 | 77,642 | 17 | 155,285 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,643 | 17 | 155,286 |
Tags: greedy, implementation
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
d={}
arr=list(map(int,input().split()))
for i in arr:
d[i]=d.get(i,0)+1
arr=sorted(list(d.keys()),reverse=True)
g=d[arr[0]]
s=0
b=0
i=1
while(i<len(arr)):
if s>g:
break
s+=d[arr[i]]
i+=1
while(i<len(arr... | output | 1 | 77,643 | 17 | 155,287 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,644 | 17 | 155,288 |
Tags: greedy, implementation
Correct Solution:
```
n = int(input())
for i in range (n):
k = int(input())
g = 0
s = 0
b = 0
gcount = 0
scount = 0
bcount = 0
bb = 0
m=list(map(int,input().split()))
for j in range(k):
if g == 0:
g += 1
gcount = m[j]
... | output | 1 | 77,644 | 17 | 155,289 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,645 | 17 | 155,290 |
Tags: greedy, implementation
Correct Solution:
```
t1=int(input())
while(t1):
t1-=1
n=int(input())
a=list(map(int,input().split()))
if(n<=2):
print(0,0,0)
continue
b=dict()
for i in a:
if(i not in b):
b[i]=1
continue
b[i]+=1
ma=n//2
res=[0]*3
z=0
co=0
for i in b.keys():
if(co==0):
res[0]=b... | output | 1 | 77,645 | 17 | 155,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,646 | 17 | 155,292 |
Tags: greedy, implementation
Correct Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
def first(m):
cur = m[-1]
if len(m) >= 2:
k = 0
while cur == m[-1]:
del m[-1]
if len(m) == 0:
return False
if len(m) <= 2:
ret... | output | 1 | 77,646 | 17 | 155,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,647 | 17 | 155,294 |
Tags: greedy, implementation
Correct Solution:
```
n = int(input())
for j in range(n):
m = int(input())
L = [int(e) for e in input().strip().split()]
L = L[: (len(L)//2) + 1 ]
if len(L) == 1: pass
elif L[-1] == L[-2]:
i = -2
while( i >= len(L)*-1 and L[i] == L[-1]):
i -= ... | output | 1 | 77,647 | 17 | 155,295 |
Provide tags and a correct Python 3 solution for this coding contest problem.
So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved p_i problems. Since the participants are primarily sorted by th... | instruction | 0 | 77,648 | 17 | 155,296 |
Tags: greedy, implementation
Correct Solution:
```
import bisect
import collections
import copy
import functools
import heapq
import itertools
import math
import random
import re
import sys
import time
import string
from typing import List
sys.setrecursionlimit(99999)
for _ in range(int(input())):
n = int(input())... | output | 1 | 77,648 | 17 | 155,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tavas is a cheerleader in the new sports competition named "Pashmaks".
<image>
This competition consists of two part: swimming and then running. People will immediately start running R meters ... | instruction | 0 | 77,852 | 17 | 155,704 |
No | output | 1 | 77,852 | 17 | 155,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tavas is a cheerleader in the new sports competition named "Pashmaks".
<image>
This competition consists of two part: swimming and then running. People will immediately start running R meters ... | instruction | 0 | 77,853 | 17 | 155,706 |
No | output | 1 | 77,853 | 17 | 155,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tavas is a cheerleader in the new sports competition named "Pashmaks".
<image>
This competition consists of two part: swimming and then running. People will immediately start running R meters ... | instruction | 0 | 77,854 | 17 | 155,708 |
No | output | 1 | 77,854 | 17 | 155,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tavas is a cheerleader in the new sports competition named "Pashmaks".
<image>
This competition consists of two part: swimming and then running. People will immediately start running R meters ... | instruction | 0 | 77,855 | 17 | 155,710 |
No | output | 1 | 77,855 | 17 | 155,711 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal rules of the local championship:
* the team... | instruction | 0 | 78,544 | 17 | 157,088 |
Tags: brute force, implementation
Correct Solution:
```
# HEY STALKER
def get_sort(team):
lt = sorted(team, reverse=True)
for _ in range(6):
for tt in range(1, 4):
if lt[tt-1][0] == lt[tt][0] and lt[tt-1][1] == lt[tt][1] and lt[tt-1][2] == lt[tt][2]:
if lt[tt-1][3] > lt[tt][... | output | 1 | 78,544 | 17 | 157,089 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal rules of the local championship:
* the team... | instruction | 0 | 78,545 | 17 | 157,090 |
Tags: brute force, implementation
Correct Solution:
```
import copy
teams = {}
times = {}
def put_team(s):
if not s[0] in teams:
teams[s[0]] = [0, 0, 0, s[0]]
if not s[1] in teams:
teams[s[1]] = [0, 0, 0, s[1]]
g1, g2 = map(int, s[2].split(':'))
teams[s[0]][1] -= g1 - g2
teams[s[1]... | output | 1 | 78,545 | 17 | 157,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal rules of the local championship:
* the team... | instruction | 0 | 78,546 | 17 | 157,092 |
Tags: brute force, implementation
Correct Solution:
```
from collections import defaultdict
from functools import cmp_to_key
def main():
goals = defaultdict(lambda:0)
missing = defaultdict(lambda:0)
points = defaultdict(lambda:0)
names = set()
played = set()
for i in range(5):
ln = inp... | output | 1 | 78,546 | 17 | 157,093 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal rules of the local championship:
* the team... | instruction | 0 | 78,547 | 17 | 157,094 |
Tags: brute force, implementation
Correct Solution:
```
import os,io
from sys import stdout
import collections
# import random
# import math
# from operator import itemgetter
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
# from collections import Counter
# from decimal import Decimal
# import heapq
# from... | output | 1 | 78,547 | 17 | 157,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal ... | instruction | 0 | 78,548 | 17 | 157,096 |
No | output | 1 | 78,548 | 17 | 157,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal ... | instruction | 0 | 78,549 | 17 | 157,098 |
No | output | 1 | 78,549 | 17 | 157,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal ... | instruction | 0 | 78,550 | 17 | 157,100 |
No | output | 1 | 78,550 | 17 | 157,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Any resemblance to any real championship and sport is accidental.
The Berland National team takes part in the local Football championship which now has a group stage. Let's describe the formal ... | instruction | 0 | 78,551 | 17 | 157,102 |
No | output | 1 | 78,551 | 17 | 157,103 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,473 | 17 | 158,946 |
Tags: dp, implementation, math
Correct Solution:
```
c, d = map(int, input().split())
n, m = map(int, input().split())
p = 0
k = int(input())
if m*n <= k:
print(0)
else:
a = [0]*(m*n+1)
#a[k+1] = min(c,d)
for i in range(k+1,m*n+1):
a[i] = min(a[i-n]+c, a[i-1]+d)
print(a[m*n])
``` | output | 1 | 79,473 | 17 | 158,947 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,474 | 17 | 158,948 |
Tags: dp, implementation, math
Correct Solution:
```
c, d = [int(i) for i in input().split(" ")]
n, m = [int(i) for i in input().split(" ")]
k = int(input())
s = n*m - k
s = max(s, 0)
if c < d*n:
stuff = s//n
try1 = c*stuff + d*(s-n*stuff)
try2 = c*(stuff+1)
print(min(try1, try2))
else:
print(d*s)
``` | output | 1 | 79,474 | 17 | 158,949 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,475 | 17 | 158,950 |
Tags: dp, implementation, math
Correct Solution:
```
import math as mt
import sys,string
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
c,d=M()
n,m=M(... | output | 1 | 79,475 | 17 | 158,951 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,476 | 17 | 158,952 |
Tags: dp, implementation, math
Correct Solution:
```
c, d = map(int, input().split(' '))
n, m = map(int, input().split(' '))
k = int(input())
dp = [0] * 100000
need = n*m - k
if need <= 0:
print(0)
quit()
for i in range(1, 100000):
dp[i] = min(dp[i-n]+c, dp[i-1]+d)
print(dp[need])
``` | output | 1 | 79,476 | 17 | 158,953 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,477 | 17 | 158,954 |
Tags: dp, implementation, math
Correct Solution:
```
#Codeforces problem 417A: Elimination
def roof(n,p):
r = p // n
if p%n > 0:
r = r + 1
return r
c,d = (int(element) for element in input().split())
n,m = (int(element) for element in input().split())
k = int(input())
needed_number_of_problems = 0
#people st... | output | 1 | 79,477 | 17 | 158,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,478 | 17 | 158,956 |
Tags: dp, implementation, math
Correct Solution:
```
[c, d], [n, m], k = map(int, input().split()), map(int, input().split()), int(input())
left = n * m - k
if left <= 0:
print(0)
else:
print(min(left // n * c + left % n * d, (left + n - 1) // n * c, left * d))
``` | output | 1 | 79,478 | 17 | 158,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of c pr... | instruction | 0 | 79,479 | 17 | 158,958 |
Tags: dp, implementation, math
Correct Solution:
```
# arr=list(map(int,input().split()))
# arr=sorted([(n-int(x),i) for i,x in enumerate(input().split())])
# arr=[int(q)-1 for q in input().split()]
# from collections import Counter
# n=int(input())
# n,k=map(int,input().split())
# arr=list(map(int,input().split()))
# ... | output | 1 | 79,479 | 17 | 158,959 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n players numbered from 0 to n-1 with ranks. The i-th player has rank i.
Players can form teams: the team should consist of three players and no pair of players in the team should hav... | instruction | 0 | 79,681 | 17 | 159,362 |
No | output | 1 | 79,681 | 17 | 159,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n players numbered from 0 to n-1 with ranks. The i-th player has rank i.
Players can form teams: the team should consist of three players and no pair of players in the team should hav... | instruction | 0 | 79,682 | 17 | 159,364 |
No | output | 1 | 79,682 | 17 | 159,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n players numbered from 0 to n-1 with ranks. The i-th player has rank i.
Players can form teams: the team should consist of three players and no pair of players in the team should hav... | instruction | 0 | 79,683 | 17 | 159,366 |
No | output | 1 | 79,683 | 17 | 159,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n players numbered from 0 to n-1 with ranks. The i-th player has rank i.
Players can form teams: the team should consist of three players and no pair of players in the team should hav... | instruction | 0 | 79,684 | 17 | 159,368 |
No | output | 1 | 79,684 | 17 | 159,369 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are cal... | instruction | 0 | 80,510 | 17 | 161,020 |
Tags: implementation, math
Correct Solution:
```
n, k = map(int, input().split())
a = (n // 2) // (k + 1)
b = a * k
print(a, b, n - a - b)
``` | output | 1 | 80,510 | 17 | 161,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are cal... | instruction | 0 | 80,511 | 17 | 161,022 |
Tags: implementation, math
Correct Solution:
```
n, k = input().split()
n, k = int(n), int(k)
dip = gram = 0
dip = int( (n/2) / (k+1))
gram = int(dip * k)
if (dip + gram > n/2):
print(0, 0, n, end=' ')
else:
other=n-dip-gram
print(int(dip), int(gram), int(other), end=' ')
``` | output | 1 | 80,511 | 17 | 161,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are cal... | instruction | 0 | 80,512 | 17 | 161,024 |
Tags: implementation, math
Correct Solution:
```
#1. diploma
t=list(map(int,input().split()))
half=t[0]//2
if(t[1]>half):
print(*[0,0,t[0]])
elif(t[1]<=half):
s=half//(t[1]+1)
p=abs(half-s-t[1]*s)
print(*[s,t[1]*s,t[0]-half+p])
``` | output | 1 | 80,512 | 17 | 161,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are cal... | instruction | 0 | 80,513 | 17 | 161,026 |
Tags: implementation, math
Correct Solution:
```
n, k = map(int, input().split())
d = n//2//(k+1)
print(d, k*d, n-(k+1)*d)
``` | output | 1 | 80,513 | 17 | 161,027 |
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