message stringlengths 2 11.9k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his c... | instruction | 0 | 3,845 | 18 | 7,690 |
No | output | 1 | 3,845 | 18 | 7,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his c... | instruction | 0 | 3,846 | 18 | 7,692 |
No | output | 1 | 3,846 | 18 | 7,693 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,948 | 18 | 7,896 |
"Correct Solution:
```
s = str(input())
if(s[-1]=="s"):
print(s+"es")
else:
print(s+"s")
``` | output | 1 | 3,948 | 18 | 7,897 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,949 | 18 | 7,898 |
"Correct Solution:
```
S=input()
if S[-1] == 's':
print(S+"es")
else:
print(S+"s")
``` | output | 1 | 3,949 | 18 | 7,899 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,950 | 18 | 7,900 |
"Correct Solution:
```
s = input()
if s[-1] == "s":
print(s+"es")
else:
print(s+"s")
``` | output | 1 | 3,950 | 18 | 7,901 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,951 | 18 | 7,902 |
"Correct Solution:
```
S = input()
if S.endswith("s"): print(S + "es")
else: print(S + "s")
``` | output | 1 | 3,951 | 18 | 7,903 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,952 | 18 | 7,904 |
"Correct Solution:
```
s = input()
a = s[-1]
if(a == 's'):print(s+"es")
else:print(s+"s")
``` | output | 1 | 3,952 | 18 | 7,905 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,953 | 18 | 7,906 |
"Correct Solution:
```
a=input()
if(a[len(a)-1]=="s"):
a+="e"
print(a+"s")
``` | output | 1 | 3,953 | 18 | 7,907 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,954 | 18 | 7,908 |
"Correct Solution:
```
x=input()
if x[-1]=="s":
print(x+"es")
else:
print(x+"s")
``` | output | 1 | 3,954 | 18 | 7,909 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a noun's singular form does not end with `s`, append `s` to t... | instruction | 0 | 3,955 | 18 | 7,910 |
"Correct Solution:
```
A = input()
A = A + "es" if A[-1] == "s" else A + "s"
print(A)
``` | output | 1 | 3,955 | 18 | 7,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,956 | 18 | 7,912 |
Yes | output | 1 | 3,956 | 18 | 7,913 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,957 | 18 | 7,914 |
Yes | output | 1 | 3,957 | 18 | 7,915 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,958 | 18 | 7,916 |
Yes | output | 1 | 3,958 | 18 | 7,917 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,959 | 18 | 7,918 |
Yes | output | 1 | 3,959 | 18 | 7,919 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,960 | 18 | 7,920 |
No | output | 1 | 3,960 | 18 | 7,921 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,961 | 18 | 7,922 |
No | output | 1 | 3,961 | 18 | 7,923 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,962 | 18 | 7,924 |
No | output | 1 | 3,962 | 18 | 7,925 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.
In Taknese, the plural form of a noun is spelled based on the following rules:
* If a nou... | instruction | 0 | 3,963 | 18 | 7,926 |
No | output | 1 | 3,963 | 18 | 7,927 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,044 | 18 | 8,088 |
"Correct Solution:
```
S=input()
T=S.count("o")
print(700+T*100)
``` | output | 1 | 4,044 | 18 | 8,089 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,045 | 18 | 8,090 |
"Correct Solution:
```
s = input()
x = s.count("o")
print(700+x*100)
``` | output | 1 | 4,045 | 18 | 8,091 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,046 | 18 | 8,092 |
"Correct Solution:
```
s=input()
print(int(700+100*s.count('o')))
``` | output | 1 | 4,046 | 18 | 8,093 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,047 | 18 | 8,094 |
"Correct Solution:
```
print(len(input().replace("x",""))*100+700)
``` | output | 1 | 4,047 | 18 | 8,095 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,048 | 18 | 8,096 |
"Correct Solution:
```
a=input()
print(a.count("o")*100+700)
``` | output | 1 | 4,048 | 18 | 8,097 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,050 | 18 | 8,100 |
"Correct Solution:
```
S = input()
print(700+(S.count("o")*100))
``` | output | 1 | 4,050 | 18 | 8,101 |
Provide a correct Python 3 solution for this coding contest problem.
In "Takahashi-ya", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).
A customer ordered a bowl of ramen and told which toppings to put on his ram... | instruction | 0 | 4,051 | 18 | 8,102 |
"Correct Solution:
```
s=input();print(700+100*(s.count('o')))
``` | output | 1 | 4,051 | 18 | 8,103 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,076 | 18 | 8,152 |
"Correct Solution:
```
# coding: utf-8
w = input()
print("No" if sum(w.count(s)%2 for s in w) else "Yes")
``` | output | 1 | 4,076 | 18 | 8,153 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,077 | 18 | 8,154 |
"Correct Solution:
```
w = input()
for c in w:
if w.count(c) % 2:
print("No")
quit()
print("Yes")
``` | output | 1 | 4,077 | 18 | 8,155 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,078 | 18 | 8,156 |
"Correct Solution:
```
s=input()
if all(s.count(i)%2==0 for i in set(s)):
print('Yes')
else:
print('No')
``` | output | 1 | 4,078 | 18 | 8,157 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,079 | 18 | 8,158 |
"Correct Solution:
```
S = input()
if all([S.count(i) % 2 == 0 for i in S]):
print('Yes')
else:
print('No')
``` | output | 1 | 4,079 | 18 | 8,159 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,080 | 18 | 8,160 |
"Correct Solution:
```
w=input()
print("YNeos"[sum(map(lambda x:w.count(x)%2,w))!=0::2])
``` | output | 1 | 4,080 | 18 | 8,161 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,081 | 18 | 8,162 |
"Correct Solution:
```
s=input()
f=True
for a in s:
if s.count(a)%2 != 0:
f=False
print('Yes' if f else 'No')
``` | output | 1 | 4,081 | 18 | 8,163 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,082 | 18 | 8,164 |
"Correct Solution:
```
s=input();print('NYoe s'[all([s.count(i)%2==0 for i in set(s)])::2])
``` | output | 1 | 4,082 | 18 | 8,165 |
Provide a correct Python 3 solution for this coding contest problem.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times in w.
You are given the string w. Determine if w is b... | instruction | 0 | 4,083 | 18 | 8,166 |
"Correct Solution:
```
s=input()
print("Yes" if all([s.count(i)%2==0 for i in s]) else "No")
``` | output | 1 | 4,083 | 18 | 8,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,084 | 18 | 8,168 |
Yes | output | 1 | 4,084 | 18 | 8,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,085 | 18 | 8,170 |
Yes | output | 1 | 4,085 | 18 | 8,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,086 | 18 | 8,172 |
Yes | output | 1 | 4,086 | 18 | 8,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,087 | 18 | 8,174 |
Yes | output | 1 | 4,087 | 18 | 8,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,088 | 18 | 8,176 |
No | output | 1 | 4,088 | 18 | 8,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,089 | 18 | 8,178 |
No | output | 1 | 4,089 | 18 | 8,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,090 | 18 | 8,180 |
No | output | 1 | 4,090 | 18 | 8,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let w be a string consisting of lowercase letters. We will call w beautiful if the following condition is satisfied:
* Each lowercase letter of the English alphabet occurs even number of times ... | instruction | 0 | 4,091 | 18 | 8,182 |
No | output | 1 | 4,091 | 18 | 8,183 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,231 | 18 | 8,462 |
Yes | output | 1 | 4,231 | 18 | 8,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,233 | 18 | 8,466 |
Yes | output | 1 | 4,233 | 18 | 8,467 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,234 | 18 | 8,468 |
Yes | output | 1 | 4,234 | 18 | 8,469 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,235 | 18 | 8,470 |
No | output | 1 | 4,235 | 18 | 8,471 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,236 | 18 | 8,472 |
No | output | 1 | 4,236 | 18 | 8,473 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,237 | 18 | 8,474 |
No | output | 1 | 4,237 | 18 | 8,475 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tom loves vowels, and he likes long words with many vowels. His favorite words are vowelly words. We say a word of length k is vowelly if there are positive integers n and m such that n⋅ m = k a... | instruction | 0 | 4,238 | 18 | 8,476 |
No | output | 1 | 4,238 | 18 | 8,477 |
Provide a correct Python 3 solution for this coding contest problem.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that da... | instruction | 0 | 4,811 | 18 | 9,622 |
"Correct Solution:
```
s = input()
if s == 'RSR':
print(1)
else:
print(s.count(('R')))
``` | output | 1 | 4,811 | 18 | 9,623 |
Provide a correct Python 3 solution for this coding contest problem.
We have weather records at AtCoder Town for some consecutive three days. A string of length 3, S, represents the records - if the i-th character is `S`, it means it was sunny on the i-th day; if that character is `R`, it means it was rainy on that da... | instruction | 0 | 4,812 | 18 | 9,624 |
"Correct Solution:
```
S = input()
if S == "RSR":
print(1)
else:
print(S.count('R'))
``` | output | 1 | 4,812 | 18 | 9,625 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.