message stringlengths 2 23.4k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 129 108k | cluster float64 6 6 | __index_level_0__ int64 258 216k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
In this problem you will write a simple code generator for a 2D programming language derived from [Brainfuck](https://en.wikipedia.org/wiki/Brainfuck).
The code in this language is a rectangular grid of characters '.' and 'X'. The code is c... | instruction | 0 | 14,746 | 6 | 29,492 |
Tags: constructive algorithms
Correct Solution:
```
n = input()
s = ""
t = ""
for c in n:
i = ord(c)
s += ".X." + ".X.." * i + ".X.X." + ".." * i + "X.."
t += "..." + "XXX." * i + "XX.X." + "X." * i + "XX."
print(s)
print(t)
print(len(s) * ".")
``` | output | 1 | 14,746 | 6 | 29,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In this problem you will write a simple code generator for a 2D programming language derived from [Brainfuck](https://en.wikipedia.org/wiki/Brainfuck).
The code in this language is a rectangular grid of characters '.' and 'X'. The code is c... | instruction | 0 | 14,747 | 6 | 29,494 |
Tags: constructive algorithms
Correct Solution:
```
data = input()
lens = [(256 - ord(data[0]))]
for i in range(len(data) - 1):
lens.append((512 - (ord(data[i+1]) - ord(data[i]))) % 256)
line0 = "." * 512
line1 = ".X" + ("." * 510)
for i in range(len(data)):
if lens[i] == 0:
print(line1)
else:
... | output | 1 | 14,747 | 6 | 29,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,181 | 6 | 30,362 |
Tags: implementation, strings
Correct Solution:
```
x, y = input().split(' ')
x = int(x)
y = int(y)
s = ''
s1 = ''
s= (input().split(' '))
s1 = (input().split(' '))
q = int(input())
for i in range(q):
z = int(input())
print(s[(z-1)%x]+s1[(z-1)%y])
``` | output | 1 | 15,181 | 6 | 30,363 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,182 | 6 | 30,364 |
Tags: implementation, strings
Correct Solution:
```
n,m = [int(x) for x in input().split()]
s = input().strip().split()
t = input().strip().split()
q = int(input())
for _ in range(q):
y = int(input())
r1 = (y-1)%n
r2 = (y-1)%m
print(s[r1]+t[r2])
``` | output | 1 | 15,182 | 6 | 30,365 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,183 | 6 | 30,366 |
Tags: implementation, strings
Correct Solution:
```
from math import gcd
n, m = list(map(int, input().split()))
ar1 = list(input().split())
ar2 = list(input().split())
kek = n * m // gcd(n, m)
for _ in range(int(input())):
t = int(input())
t %= kek
print(ar1[(t - 1) % n] + ar2[(t - 1) % m])
``` | output | 1 | 15,183 | 6 | 30,367 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,184 | 6 | 30,368 |
Tags: implementation, strings
Correct Solution:
```
n,m=map(int,input().split())
a=list(map(str,input().split()))
b=list(map(str,input().split()))
for i in range(int(input())):
k=int(input())
x=k%len(a)
y=k%len(b)
print(a[x-1]+b[y-1])
``` | output | 1 | 15,184 | 6 | 30,369 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,185 | 6 | 30,370 |
Tags: implementation, strings
Correct Solution:
```
n,m=map(int,input().split())
s1=input().split()
s2=input().split()
l=[]
for i in range(n*m):
l.append(s1[i%n]+s2[i%m])
for i in range(int(input())):
k=int(input())
print (l[(k-1)%(n*m)])
``` | output | 1 | 15,185 | 6 | 30,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,186 | 6 | 30,372 |
Tags: implementation, strings
Correct Solution:
```
n,m=map(int,input().split())
pol=input().split()
kan=input().split()
a=[]
for i in range(1, n*m+1):
if(i%n==0):
a.append(pol[n-1])
else:
a.append(pol[i%n-1])
if(i%m==0):
a[-1]+=kan[m-1]
else:
a[-1]+=kan[i%m-1]
p=int(inpu... | output | 1 | 15,186 | 6 | 30,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,187 | 6 | 30,374 |
Tags: implementation, strings
Correct Solution:
```
a = list(map(int,input().split()))
n = input().split()
s = input().split()
q = int(input())
for i in range(q):
x = int(input())
t1 = x%a[0]
t2 = x%a[1]
print(n[t1-1]+s[t2-1])
``` | output | 1 | 15,187 | 6 | 30,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Happy new year! The year 2020 is also known as Year Gyeongja (κ²½μλ
, gyeongja-nyeon) in Korea. Where did the name come from? Let's briefly look at the Gapja system, which is traditionally used in Korea to name the years.
There are two sequenc... | instruction | 0 | 15,188 | 6 | 30,376 |
Tags: implementation, strings
Correct Solution:
```
from sys import stdin
from collections import deque
from math import sqrt, floor, ceil, log, log2, log10, pi, gcd, sin, cos, asin
def ii(): return int(stdin.readline())
def fi(): return float(stdin.readline())
def mi(): return map(int, stdin.readline().split())
def fm... | output | 1 | 15,188 | 6 | 30,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,197 | 6 | 30,394 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
for _ in range(int(input())):
s = input()
l = []
l.append(s[0])
f=0
m = 0
j=0
for i in range(1,len(s)):
if s[i] in l:
if l[j]==s[i]:
f=1
break
if j>0 and j<m an... | output | 1 | 15,197 | 6 | 30,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,198 | 6 | 30,396 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
from collections import Counter
t=int(input())
for tests in range(t):
s=input().strip()
if len(s)==1:
print("YES")
print("abcdefghijklmnopqrstuvwxyz")
continue
L=[set() fo... | output | 1 | 15,198 | 6 | 30,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,199 | 6 | 30,398 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
from sys import stdin
input=lambda : stdin.readline().strip()
from math import ceil,sqrt,factorial,gcd
from collections import deque
for _ in range(int(input())):
ans=deque()
s=input()
ans.append(s[0])
a=0
flag="YES"
for i in range(1,len(s)):
i... | output | 1 | 15,199 | 6 | 30,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,200 | 6 | 30,400 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
for _ in range(int(input())):
s=input()
p=s[0]
c=""
q="abcdefghijklmnopqrstuvwxyz"
flag=0
for i in range(1,len(s)):
if s[i] in p:
k=p.find(s[i])
if(len(p)==1):
if(s[i]!... | output | 1 | 15,200 | 6 | 30,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,201 | 6 | 30,402 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
t = int(input())
for i in range(t):
s = input()
f = True
st = set()
answer = ''
pos = 0
n = 0
for l in s:
if l not in st:
st.add(l)
n += 1
if pos == n - 1:
answer ... | output | 1 | 15,201 | 6 | 30,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,202 | 6 | 30,404 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
for _ in range(int(input())):
s = input()
finish = ""
x = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
y = [0]*52
u = 26
d = len(s)
ok = T... | output | 1 | 15,202 | 6 | 30,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,203 | 6 | 30,406 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
import sys
from collections import deque
alf = set(list('qwertyuiopasdfghjklzxcvbnm'))
input = lambda: sys.stdin.readline().strip()
# print(help(deque))
for i in range(int(input())):
s = input()
ans = deque()
used = set([s[0]])
ans.appe... | output | 1 | 15,203 | 6 | 30,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,204 | 6 | 30,408 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
from collections import Counter
from collections import deque
from sys import stdin
from bisect import *
from heapq import *
import math
g = lambda : stdin.readline().strip()
gl = lambda : g().split()
gil = lambda : [int(var) for var in gl()]
gfl =... | output | 1 | 15,204 | 6 | 30,409 |
Provide tags and a correct Python 2 solution for this coding contest problem.
Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him β his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.
Polycarp uses the same pas... | instruction | 0 | 15,205 | 6 | 30,410 |
Tags: dfs and similar, greedy, implementation
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
from fractions import gcd
import heapq
raw_input = stdin.readline
pr = stdout.write
mod=998244353
def ni():
return int(raw_... | output | 1 | 15,205 | 6 | 30,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,004 | 6 | 32,008 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
for i in range(n):
l = sorted(input())
s = set()
s.update(l)
print('Yes' if ord(l[-1]) - ord(l[0]) == len(l) - 1 and len(s) == len(l) else 'No')
``` | output | 1 | 16,004 | 6 | 32,009 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,005 | 6 | 32,010 |
Tags: implementation, strings
Correct Solution:
```
t=int(input())
for j in range(t):
s=input()
n=len(s)
d=0
c = [s[i] for i in range(len(s))]
c.sort(reverse = False)
for i in range(n-1):
if(ord(c[i])==(ord(c[i+1])-1)):
d=d+1
if(d==(n-1)):
print("Yes")
else:
... | output | 1 | 16,005 | 6 | 32,011 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,006 | 6 | 32,012 |
Tags: implementation, strings
Correct Solution:
```
def check(s):
s = sorted(s)
for i in range(1, len(s)):
if ord(s[i]) - ord(s[i-1]) != 1:
return 'No'
return 'Yes'
n = int(input())
for i in range(n):
print(check(input()))
``` | output | 1 | 16,006 | 6 | 32,013 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,007 | 6 | 32,014 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
for i in range(n):
s=input()
l=[]
for j in s:
l.append(j)
l.sort()
c=0
for j in range(0,len(l)-1,1):
if(ord(l[j+1])-ord(l[j])!=1):
c=c+1
break
if(c==1):
print("No")
else:
... | output | 1 | 16,007 | 6 | 32,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,008 | 6 | 32,016 |
Tags: implementation, strings
Correct Solution:
```
for _ in range(int(input())):
s=list(input())
a=set(s)
print(['NO','YES'][len(s)==len(a) and ord(max(s))-ord((min(s)))+1==len(s)])
``` | output | 1 | 16,008 | 6 | 32,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,009 | 6 | 32,018 |
Tags: implementation, strings
Correct Solution:
```
def diverse(s):
if len(s) == 1 or len(s) == 0:
return True
s = [c for c in s]
s.sort()
if not all(abs(ord(s[i])-ord(s[i+1])) == 1 for i in range(len(s)-1)):
return False
return True
for _ in range(int(input())):
if diverse(in... | output | 1 | 16,009 | 6 | 32,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,010 | 6 | 32,020 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
for i in range(n):
f=0
a=input()
b=sorted(a)
for j in range(len(a)-1):
if ord(b[j])+1==ord(b[j+1]):
continue
else:
f=1
break
if f==1:
print('No')
else:
print('Yes')
``` | output | 1 | 16,010 | 6 | 32,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not... | instruction | 0 | 16,011 | 6 | 32,022 |
Tags: implementation, strings
Correct Solution:
```
n= int(input())
L = []
for i in range(n):
L.append(input())
for i in L:
i = ''.join(sorted(i))
x = True
for j in range(len(i)-1):
if (ord(i[j+1])-ord(i[j]))!=1:
x = False
if x:
print("YES")
else:
print("NO"... | output | 1 | 16,011 | 6 | 32,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,194 | 6 | 32,388 |
Tags: implementation, strings
Correct Solution:
```
import re
s = input().strip()
s = re.sub('\s+', ' ', s)
s = re.sub('\s?([.,!?])\s?', '\\1 ', s)
print(s)
``` | output | 1 | 16,194 | 6 | 32,389 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,195 | 6 | 32,390 |
Tags: implementation, strings
Correct Solution:
```
string = input()
string = " ".join(string.split())
for j in ".,!?":
string = string.split(f"{j}")
for i in range(len(string)):
string[i] = string[i].strip()
string = f"{j} ".join(string)
print(string)
``` | output | 1 | 16,195 | 6 | 32,391 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,196 | 6 | 32,392 |
Tags: implementation, strings
Correct Solution:
```
sp = False
for ch in input():
if ch == ' ':
sp = True
elif ch.islower():
print(('', ' ')[sp] + ch, end='')
sp = False
else:
print(ch, end='')
sp = True
``` | output | 1 | 16,196 | 6 | 32,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,197 | 6 | 32,394 |
Tags: implementation, strings
Correct Solution:
```
# Why do we fall ? So we can learn to pick ourselves up.
import re
ss = input().strip()
s = re.findall("[\w']+|[.,!?]",ss)
ans = ""
for i in s:
if i == ',' or i == '?' or i == '!' or i == '.':
ans = ans.strip()
ans += i+" "
else:
ans +=... | output | 1 | 16,197 | 6 | 32,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,198 | 6 | 32,396 |
Tags: implementation, strings
Correct Solution:
```
x=list(map(str,input()))
z=""
i=0
while (i<len(x)):
while (i<len(x)) and (x[i]!=" ") :
if (x[i]==".") or (x[i]==",") or (x[i]=="!") or (x[i]=="?") and (x[i+1]!=" "):
z=z+x[i]+" "
else:
z=z+x[i]
i+=1
if (i+1<len(x... | output | 1 | 16,198 | 6 | 32,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,199 | 6 | 32,398 |
Tags: implementation, strings
Correct Solution:
```
def main():
line = input()
lineout=[]
for i in range(len(line)):
if line[i] == ' ' and i+1 < len(line):
if line[i+1] == ',' or line[i+1] == '.' or line[i+1] == '!' or line[i+1] == '?':
pass
elif line[i+1] == ... | output | 1 | 16,199 | 6 | 32,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,200 | 6 | 32,400 |
Tags: implementation, strings
Correct Solution:
```
s = input()
for ch in ',.!?':
s = s.replace(ch, ch + ' ')
while ' ' in s:
s = s.replace(' ', ' ')
for ch in ',.!?':
s = s.replace(' ' + ch, ch)
print(s.strip())
``` | output | 1 | 16,200 | 6 | 32,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the te... | instruction | 0 | 16,201 | 6 | 32,402 |
Tags: implementation, strings
Correct Solution:
```
d=[',','?','.',';','!']
z=input()
for t in d:
z=z.replace(t,'%s '%t)
for i in range(10,0,-1):
z=z.replace(' '*i,' ')
for j in d:
if j in z:
z=z.replace(' %s'%j,j)
print(z)
``` | output | 1 | 16,201 | 6 | 32,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,202 | 6 | 32,404 |
Yes | output | 1 | 16,202 | 6 | 32,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,203 | 6 | 32,406 |
Yes | output | 1 | 16,203 | 6 | 32,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,204 | 6 | 32,408 |
Yes | output | 1 | 16,204 | 6 | 32,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,205 | 6 | 32,410 |
Yes | output | 1 | 16,205 | 6 | 32,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,206 | 6 | 32,412 |
No | output | 1 | 16,206 | 6 | 32,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,207 | 6 | 32,414 |
No | output | 1 | 16,207 | 6 | 32,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,208 | 6 | 32,416 |
No | output | 1 | 16,208 | 6 | 32,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin... | instruction | 0 | 16,209 | 6 | 32,418 |
No | output | 1 | 16,209 | 6 | 32,419 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,242 | 6 | 32,484 |
Tags: dp
Correct Solution:
```
from collections import deque
from collections import OrderedDict
import math
import sys
import os
import threading
import bisect
import operator
import heapq
from atexit import register
from io import BytesIO
#sys.stdin = BytesIO(os.read(0, os.fstat(0).st_size))
#sys.stdout =... | output | 1 | 16,242 | 6 | 32,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,243 | 6 | 32,486 |
Tags: dp
Correct Solution:
```
string=input()
n=len(string)
upper=0
lower=0
count=0
i=0
k=n-1
while i<n and ord(string[i])<97:
i+=1
for j in range(n-1,i-1,-1):
if ord(string[j])>=97:
lower+=1
else:
upper+=1
if lower>=upper:
count+=upper
lower=0
upper=0
if j==... | output | 1 | 16,243 | 6 | 32,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,244 | 6 | 32,488 |
Tags: dp
Correct Solution:
```
s = input()
n = len(s)
a,b = 0,0
i = 0
j = n-1
while i<n and s[i].isupper():
i+=1
while j>=0 and s[j].islower():
j-=1
aa = []
if i==n or j==-1:
print(0)
else:
j+=1
if s[0].islower():
i = 0
if s[-1].isupper():
j = n
bb,cc=0,0
# print(s[... | output | 1 | 16,244 | 6 | 32,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,245 | 6 | 32,490 |
Tags: dp
Correct Solution:
```
s=input()
a,r=0,0
for x in s:
if x.islower():a+=1
elif x.isupper() and a>0:a-=1;r+=1
print(r)
``` | output | 1 | 16,245 | 6 | 32,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,246 | 6 | 32,492 |
Tags: dp
Correct Solution:
```
t = [0] + [i < 'a' for i in input()]
for i in range(2, len(t)):
t[i] += t[i - 1]
s = t[-1]
print(min(s - 2 * j + i for i, j in enumerate(t)))
``` | output | 1 | 16,246 | 6 | 32,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,247 | 6 | 32,494 |
Tags: dp
Correct Solution:
```
s=input()
count=1
ans=[]
for i in range(1,len(s)):
if((s[i].isupper() and s[i-1].isupper()) or (s[i].islower() and s[i-1].islower())):
count+=1
else:
ans.append(count)
count=1
ans.append(count)
dp=[0 for i in range(len(ans))]
if(s[0].isupper()):
sm=sum... | output | 1 | 16,247 | 6 | 32,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were upperca... | instruction | 0 | 16,248 | 6 | 32,496 |
Tags: dp
Correct Solution:
```
s = list(input())
n = len(s)
l=u=0
for i in s:
if i.isupper():
u+=1
else:
l+=1
i=low=0
ans=min(u,l)
while i<n and s[i].isupper():
u-=1
i+=1
for j in range(i,n):
if s[j].islower():
ans=min(ans,low+u)
low+=1
else:
u-=1
p... | output | 1 | 16,248 | 6 | 32,497 |
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