message stringlengths 2 22.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,079 | 9 | 178,158 |
"Correct Solution:
```
N,X=map(int,input().split())
m=[int(input()) for _ in range(N)]
#print(m)
print(N+(X-sum(m))//min(m))
``` | output | 1 | 89,079 | 9 | 178,159 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,080 | 9 | 178,160 |
"Correct Solution:
```
N, X = map(int, input().split())
L = [int(input()) for i in range(N)]
print((X-sum(L))//min(L)+N)
``` | output | 1 | 89,080 | 9 | 178,161 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,081 | 9 | 178,162 |
"Correct Solution:
```
import sys
N,X=map(int,input().split())
m=[int(input()) for i in range(N)]
X-=sum(m)
print(N+X//min(m))
``` | output | 1 | 89,081 | 9 | 178,163 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,082 | 9 | 178,164 |
"Correct Solution:
```
n,x=map(int,input().split())
M=sorted([int(input()) for i in range(n)])
print(len(M)+(x-sum(M))//M[0])
``` | output | 1 | 89,082 | 9 | 178,165 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,083 | 9 | 178,166 |
"Correct Solution:
```
n,x=map(int,input().split())
m=[int(input()) for i in range(n)]
print(int((x-sum(m))/min(m))+len(m))
``` | output | 1 | 89,083 | 9 | 178,167 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,084 | 9 | 178,168 |
"Correct Solution:
```
n, x = map(int, input().split())
a = [int(input()) for i in range(n)]
print(n+(x-sum(a))//(min(a)))
``` | output | 1 | 89,084 | 9 | 178,169 |
Provide a correct Python 3 solution for this coding contest problem.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In orde... | instruction | 0 | 89,085 | 9 | 178,170 |
"Correct Solution:
```
n,x = map(int,input().split())
M = [int(input()) for i in range(n)]
print(n+(x-sum(M))//min(M))
``` | output | 1 | 89,085 | 9 | 178,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,086 | 9 | 178,172 |
Yes | output | 1 | 89,086 | 9 | 178,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,087 | 9 | 178,174 |
Yes | output | 1 | 89,087 | 9 | 178,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,088 | 9 | 178,176 |
Yes | output | 1 | 89,088 | 9 | 178,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,089 | 9 | 178,178 |
Yes | output | 1 | 89,089 | 9 | 178,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,090 | 9 | 178,180 |
No | output | 1 | 89,090 | 9 | 178,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,091 | 9 | 178,182 |
No | output | 1 | 89,091 | 9 | 178,183 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,092 | 9 | 178,184 |
No | output | 1 | 89,092 | 9 | 178,185 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Akaki, a patissier, can make N kinds of doughnut using only a certain powder called "Okashi no Moto" (literally "material of pastry", simply called Moto below) as ingredient. These doughnuts are... | instruction | 0 | 89,093 | 9 | 178,186 |
No | output | 1 | 89,093 | 9 | 178,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,818 | 9 | 179,636 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
import math
class Person:
def __init__(self, slices, a_happiness, b_happiness):
self.slices = slices
self.a_happiness = a_happiness
self.b_happiness = b_happiness
self.choice = None
def make_greedy_choice(self):
if self.a_happiness > self... | output | 1 | 89,818 | 9 | 179,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,819 | 9 | 179,638 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
def solve(arr):
arr.sort(key=lambda q: q[1] - q[0])
m = sum(si for a, b, si in arr)
k = s * (m // s)
n = m - k
x, y, z = 0, 0, 0
for a, b, si in arr:
if k >= si:
k -= si
z += si * a
elif k... | output | 1 | 89,819 | 9 | 179,639 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,820 | 9 | 179,640 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
import sys
n, s = tuple(map(int, input().split()))
x = []
for i in range(n):
si, a, b = tuple(map(int, input().split()))
x.append([si, a, b])
x = sorted(x, key=lambda t: abs(t[1] - t[2]))
labels = []
sum1 = 0
sum2 = 0
res = 0
for i in ran... | output | 1 | 89,820 | 9 | 179,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,821 | 9 | 179,642 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
def solve(ls):
ls.sort(key=lambda q: q[1] - q[0])
m = sum(si for a, b, si in ls)
k = s * (m // s)
n = m - k
x = y = z = 0
for a, b, si in ls:
if k >= si:
k -= si
z += si * a
elif k:
... | output | 1 | 89,821 | 9 | 179,643 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,822 | 9 | 179,644 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
def get_losts(persons, count):
persons.sort(key = lambda p : p.lost)
losts = 0
i = 0
while count > 0:
df = min(count, persons[i].s)
losts += df * persons[i].lost
count -= df
i += 1
return losts
... | output | 1 | 89,822 | 9 | 179,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,823 | 9 | 179,646 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
def solve(ls):
ls.sort(key=lambda q: q[1] - q[0])
m = sum(si for a, b, si in ls)
k = s * (m // s)
n = m - k
x = y = z = 0
for a, b, si in ls:
if k >= si:
k -= si
z += si * a
elif... | output | 1 | 89,823 | 9 | 179,647 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,824 | 9 | 179,648 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
n, S = map(int, input().split())
arr = []
suma = 0
happy = 0
sumb = 0
dif = []
for i in range(n):
c, a, b = map(int, input().split())
if a >= b:
suma += c
happy += a * c
else:
sumb += c
happy += b * c
dif... | output | 1 | 89,824 | 9 | 179,649 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the problem), and all pizzas contain exactly S slices.
... | instruction | 0 | 89,825 | 9 | 179,650 |
Tags: binary search, sortings, ternary search
Correct Solution:
```
f = lambda: map(int, input().split())
n, s = f()
u, v = [], []
for i in range(n):
d, a, b = f()
if a > b:
u.append([a, b, d])
else:
v.append([b, a, d])
def g(t):
t.sort(key=lambda q: q[1] - q[0])
m = sum(d fo... | output | 1 | 89,825 | 9 | 179,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,826 | 9 | 179,652 |
Yes | output | 1 | 89,826 | 9 | 179,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,827 | 9 | 179,654 |
Yes | output | 1 | 89,827 | 9 | 179,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,828 | 9 | 179,656 |
Yes | output | 1 | 89,828 | 9 | 179,657 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,829 | 9 | 179,658 |
Yes | output | 1 | 89,829 | 9 | 179,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,830 | 9 | 179,660 |
No | output | 1 | 89,830 | 9 | 179,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,831 | 9 | 179,662 |
No | output | 1 | 89,831 | 9 | 179,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,832 | 9 | 179,664 |
No | output | 1 | 89,832 | 9 | 179,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's another Start[c]up finals, and that means there is pizza to order for the onsite contestants. There are only 2 types of pizza (obviously not, but let's just pretend for the sake of the prob... | instruction | 0 | 89,833 | 9 | 179,666 |
No | output | 1 | 89,833 | 9 | 179,667 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,835 | 9 | 179,670 |
Tags: binary search, implementation, math
Correct Solution:
```
import math
s = input()
s = s.split()
s = list(map(int, s))
k = s[0]
d = s[1]
t = s[2]
i = math.ceil(k / d)
c = i * d
m = (c + k) / 2
r1 = int(t / m)
remain = t - r1 * m
if remain < k:
print(r1 * c + remain)
else:
print(r1 * c + (... | output | 1 | 89,835 | 9 | 179,671 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,836 | 9 | 179,672 |
Tags: binary search, implementation, math
Correct Solution:
```
k, d, t = (int(x) for x in input().split())
import math as m
if d >= k:
chunksize = d
chunkspeed = k + (d-k)/2
else:
lcm = k // m.gcd(k, d) * d
lft = 0
rgt = lcm//d
while lft != rgt:
cur = (lft+rgt)//2
if d*cur < ... | output | 1 | 89,836 | 9 | 179,673 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,837 | 9 | 179,674 |
Tags: binary search, implementation, math
Correct Solution:
```
import math
k, d, t = map(int, input().split())
if d >= k:
off = d - k
else:
off = math.ceil(k / d) * d - k
times = t // (off / 2 + k)
t1 = times * (off + k)
t2 = t % (off / 2 + k)
if t2 > k:
t2 = k + (t2 - k) * 2
ans = t1 + t2
print (ans)
``` | output | 1 | 89,837 | 9 | 179,675 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,838 | 9 | 179,676 |
Tags: binary search, implementation, math
Correct Solution:
```
k, d, t = list(map(int, input().split()))
if k % d == 0:
print(t)
exit()
m = (k+d-1) // d * d
if 2*t % (m+k) == 0:
print(m*2*t / (m+k))
exit()
n = 2*t // (m+k)
res = n*m
f = 1 - (m +k) * n/(2*t)
if f <= k/t:
print(res+f*t)
else:
res... | output | 1 | 89,838 | 9 | 179,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,839 | 9 | 179,678 |
Tags: binary search, implementation, math
Correct Solution:
```
k, d, t = [int(x) for x in input().split()]
if d >= k:
off1 = d - k
else:
if k%d == 0:
off1 = 0
else:
off1 = d - k%d
reptime = k + off1/2
times = t // reptime
trest = t - times * reptime
sol = times * (k + off1)
if trest <= k:
... | output | 1 | 89,839 | 9 | 179,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,840 | 9 | 179,680 |
Tags: binary search, implementation, math
Correct Solution:
```
import math
k,d,t = [int(x) for x in input().split(' ')]
v = (d*math.ceil(k/d))
cyc = k + ((v-k)/2)
a = (t//cyc)
c = t-(a*cyc)-k
ans = 0
if c>0:
ans = c
print(t-(a*cyc)+(a*v)+ans)
``` | output | 1 | 89,840 | 9 | 179,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,841 | 9 | 179,682 |
Tags: binary search, implementation, math
Correct Solution:
```
k, d, t = map(int, input().split())
if k >= t or k%d == 0:
print(t)
exit()
if d < k:
dd = d*(k//d)
d = dd+d
no_of_cycles = 2*t//(k+d)
cooked = no_of_cycles*(k+d)/(2*t)
remaining = 1-cooked
ans = no_of_cycles*d
# print(no_of_cycles, ans, remaining, c... | output | 1 | 89,841 | 9 | 179,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes to the kitchen every d minutes and turns on the ... | instruction | 0 | 89,842 | 9 | 179,684 |
Tags: binary search, implementation, math
Correct Solution:
```
k, d, t = (int(x) for x in input().split())
if d >= k:
chunksize = d
chunkspeed = k + (d-k)/2
else:
if k % d == 0:
chunksize = k
else:
chunksize = ((k // d) + 1) * d
chunkspeed = k + (chunksize-k)/2
chunks = int(t / ch... | output | 1 | 89,842 | 9 | 179,685 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,844 | 9 | 179,688 |
Yes | output | 1 | 89,844 | 9 | 179,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,845 | 9 | 179,690 |
Yes | output | 1 | 89,845 | 9 | 179,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,846 | 9 | 179,692 |
Yes | output | 1 | 89,846 | 9 | 179,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,847 | 9 | 179,694 |
No | output | 1 | 89,847 | 9 | 179,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,848 | 9 | 179,696 |
No | output | 1 | 89,848 | 9 | 179,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,849 | 9 | 179,698 |
No | output | 1 | 89,849 | 9 | 179,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after k minutes after turning on.
During cooking, Julia goes t... | instruction | 0 | 89,850 | 9 | 179,700 |
No | output | 1 | 89,850 | 9 | 179,701 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
My grandmother uses a balance. The balance will balance if you place the same size on both of the two dishes, otherwise it will tilt to the heavier side. The weights of the 10 weights are 1g, 2g, 4g, 8g, 16g, 32g, 64g, 128g, 256g, 512g in o... | instruction | 0 | 90,010 | 9 | 180,020 |
"Correct Solution:
```
if __name__ == '__main__':
while True:
try:
n = int(input())
ans = []
for i in range(9,-1,-1):
if n >= 2**i:
ans.append(2**i)
n -= 2**i
print(*sorted(ans))
except EOFError:
break
``` | output | 1 | 90,010 | 9 | 180,021 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
My grandmother uses a balance. The balance will balance if you place the same size on both of the two dishes, otherwise it will tilt to the heavier side. The weights of the 10 weights are 1g, 2g, 4g, 8g, 16g, 32g, 64g, 128g, 256g, 512g in o... | instruction | 0 | 90,011 | 9 | 180,022 |
"Correct Solution:
```
# AOJ 0031 Weight
# Python3 2018.6.14 bal4u
w = [1, 2, 4, 8, 16, 32, 64, 128, 256, 512];
while True:
try:
a = int(input())
ans = []
i = 0
while a > 0:
if a & 1:
ans.append(w[i])
a >>= 1
i += 1
print(*ans)
except EOFError:
break
``` | output | 1 | 90,011 | 9 | 180,023 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
My grandmother uses a balance. The balance will balance if you place the same size on both of the two dishes, otherwise it will tilt to the heavier side. The weights of the 10 weights are 1g, 2g, 4g, 8g, 16g, 32g, 64g, 128g, 256g, 512g in o... | instruction | 0 | 90,012 | 9 | 180,024 |
"Correct Solution:
```
import sys
for line in sys.stdin:
weight = [1, 2, 4, 8, 16, 32, 64, 128, 256, 512]
ans = []
n = bin(int(line))[2:]
for i, x in enumerate(n[::-1]):
if x == "1":
ans.append(str(weight[i]))
print(" ".join(ans))
``` | output | 1 | 90,012 | 9 | 180,025 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
My grandmother uses a balance. The balance will balance if you place the same size on both of the two dishes, otherwise it will tilt to the heavier side. The weights of the 10 weights are 1g, 2g, 4g, 8g, 16g, 32g, 64g, 128g, 256g, 512g in o... | instruction | 0 | 90,013 | 9 | 180,026 |
"Correct Solution:
```
def solve(x):
B=list(map(int,x))
B.reverse()
for i in range(len(B)):
B[i]=B[i]*(2**i)
#remove 0
while 0 in B:
B.remove(0)
print(" ".join(map(str,B)))
while True:
try:
x=int(input())
solve(format(x,'b'))
except EOFError:
break
``` | output | 1 | 90,013 | 9 | 180,027 |
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