contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly. | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,663,531,700 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | s=input()
t=input()
v=0
l1= len(s) # 4
l2=l1 # 4
for i in range (0,l1):
l2-=1;
if(s[i]!=t[l2]):
print("NO")
break
if (len(s)== len(t) ):
print("YES")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
Input Specification:
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output Specification:
If the word *t* is a word *s*, written reversely, print YES, otherwise print NO.
Demo Input:
['code\nedoc\n', 'abb\naba\n', 'code\ncode\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
s=input()
t=input()
v=0
l1= len(s) # 4
l2=l1 # 4
for i in range (0,l1):
l2-=1;
if(s[i]!=t[l2]):
print("NO")
break
if (len(s)== len(t) ):
print("YES")
``` | 0 |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is only connected with the flat number 2 and the flat number *n* is only connected with the flat number *n*<=-<=1.
There is exactly one Pokemon of some type in each of these flats. Sergei B. asked residents of the house to let him enter their flats in order to catch Pokemons. After consulting the residents of the house decided to let Sergei B. enter one flat from the street, visit several flats and then go out from some flat. But they won't let him visit the same flat more than once.
Sergei B. was very pleased, and now he wants to visit as few flats as possible in order to collect Pokemons of all types that appear in this house. Your task is to help him and determine this minimum number of flats he has to visit. | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,689,632,614 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | print("_RANDOM_GUESS_1689632614.4503589")# 1689632614.4503784 | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is only connected with the flat number 2 and the flat number *n* is only connected with the flat number *n*<=-<=1.
There is exactly one Pokemon of some type in each of these flats. Sergei B. asked residents of the house to let him enter their flats in order to catch Pokemons. After consulting the residents of the house decided to let Sergei B. enter one flat from the street, visit several flats and then go out from some flat. But they won't let him visit the same flat more than once.
Sergei B. was very pleased, and now he wants to visit as few flats as possible in order to collect Pokemons of all types that appear in this house. Your task is to help him and determine this minimum number of flats he has to visit.
Input Specification:
The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*.
Output Specification:
Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house.
Demo Input:
['3\nAaA\n', '7\nbcAAcbc\n', '6\naaBCCe\n']
Demo Output:
['2\n', '3\n', '5\n']
Note:
In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | ```python
print("_RANDOM_GUESS_1689632614.4503589")# 1689632614.4503784
``` | 0 | |
538 | B | Quasi Binary | PROGRAMMING | 1,400 | [
"constructive algorithms",
"dp",
"greedy",
"implementation"
] | null | null | A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101, 110011 — are quasibinary and numbers 2, 12, 900 are not.
You are given a positive integer *n*. Represent it as a sum of minimum number of quasibinary numbers. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=106). | In the first line print a single integer *k* — the minimum number of numbers in the representation of number *n* as a sum of quasibinary numbers.
In the second line print *k* numbers — the elements of the sum. All these numbers should be quasibinary according to the definition above, their sum should equal *n*. Do not have to print the leading zeroes in the numbers. The order of numbers doesn't matter. If there are multiple possible representations, you are allowed to print any of them. | [
"9\n",
"32\n"
] | [
"9\n1 1 1 1 1 1 1 1 1 \n",
"3\n10 11 11 \n"
] | none | 1,000 | [
{
"input": "9",
"output": "9\n1 1 1 1 1 1 1 1 1 "
},
{
"input": "32",
"output": "3\n10 11 11 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "415",
"output": "5\n1 101 101 101 111 "
},
{
"input": "10011",
"output": "1\n10011 "
},
{
"input": "10201... | 1,630,235,191 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 109 | 20,172,800 | def min_pos(arr):
min_number = 10
min_index = 0
for i in range(len(arr)):
if arr[i] != 0 and arr[i] < min_number:
min_number = arr[i]
min_index = i
return min_number, min_index
n = list(map(int, input()))
max_number = max(n)
res = []
ptr = 0
for _ in range(len(n)):
min_number = min_pos(n)[0]
min_index = min_pos(n)[1]
for i in range(min_number):
new_string = ''
for j in range(len(n)):
if n[j] != 0:
new_string += '1'
n[j] -= 1
else:
new_string += '0'
res.append(new_string)
res = list(map(int, res))
new_res = [x for x in res if x != 0]
print(max_number)
print(*new_res)
| Title: Quasi Binary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101, 110011 — are quasibinary and numbers 2, 12, 900 are not.
You are given a positive integer *n*. Represent it as a sum of minimum number of quasibinary numbers.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=106).
Output Specification:
In the first line print a single integer *k* — the minimum number of numbers in the representation of number *n* as a sum of quasibinary numbers.
In the second line print *k* numbers — the elements of the sum. All these numbers should be quasibinary according to the definition above, their sum should equal *n*. Do not have to print the leading zeroes in the numbers. The order of numbers doesn't matter. If there are multiple possible representations, you are allowed to print any of them.
Demo Input:
['9\n', '32\n']
Demo Output:
['9\n1 1 1 1 1 1 1 1 1 \n', '3\n10 11 11 \n']
Note:
none | ```python
def min_pos(arr):
min_number = 10
min_index = 0
for i in range(len(arr)):
if arr[i] != 0 and arr[i] < min_number:
min_number = arr[i]
min_index = i
return min_number, min_index
n = list(map(int, input()))
max_number = max(n)
res = []
ptr = 0
for _ in range(len(n)):
min_number = min_pos(n)[0]
min_index = min_pos(n)[1]
for i in range(min_number):
new_string = ''
for j in range(len(n)):
if n[j] != 0:
new_string += '1'
n[j] -= 1
else:
new_string += '0'
res.append(new_string)
res = list(map(int, res))
new_res = [x for x in res if x != 0]
print(max_number)
print(*new_res)
``` | 3 | |
484 | A | Bits | PROGRAMMING | 1,700 | [
"bitmasks",
"constructive algorithms"
] | null | null | Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that *l*<=≤<=*x*<=≤<=*r*, and is maximum possible. If there are multiple such numbers find the smallest of them. | The first line contains integer *n* — the number of queries (1<=≤<=*n*<=≤<=10000).
Each of the following *n* lines contain two integers *l**i*,<=*r**i* — the arguments for the corresponding query (0<=≤<=*l**i*<=≤<=*r**i*<=≤<=1018). | For each query print the answer in a separate line. | [
"3\n1 2\n2 4\n1 10\n"
] | [
"1\n3\n7\n"
] | The binary representations of numbers from 1 to 10 are listed below:
1<sub class="lower-index">10</sub> = 1<sub class="lower-index">2</sub>
2<sub class="lower-index">10</sub> = 10<sub class="lower-index">2</sub>
3<sub class="lower-index">10</sub> = 11<sub class="lower-index">2</sub>
4<sub class="lower-index">10</sub> = 100<sub class="lower-index">2</sub>
5<sub class="lower-index">10</sub> = 101<sub class="lower-index">2</sub>
6<sub class="lower-index">10</sub> = 110<sub class="lower-index">2</sub>
7<sub class="lower-index">10</sub> = 111<sub class="lower-index">2</sub>
8<sub class="lower-index">10</sub> = 1000<sub class="lower-index">2</sub>
9<sub class="lower-index">10</sub> = 1001<sub class="lower-index">2</sub>
10<sub class="lower-index">10</sub> = 1010<sub class="lower-index">2</sub> | 500 | [
{
"input": "3\n1 2\n2 4\n1 10",
"output": "1\n3\n7"
},
{
"input": "55\n1 1\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n2 2\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n2 9\n2 10\n3 3\n3 4\n3 5\n3 6\n3 7\n3 8\n3 9\n3 10\n4 4\n4 5\n4 6\n4 7\n4 8\n4 9\n4 10\n5 5\n5 6\n5 7\n5 8\n5 9\n5 10\n6 6\n6 7\n6 8\n6 9\n6 10... | 1,532,714,701 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | import math
t = int(input())
for j in range(t):
arr = (input().split())
n = max(int(arr[0]),int(arr[1]))
m = min(int(arr[0]),int(arr[1]))
if(m == n):
print(m)
elif(n-1 == m):
cnt1 = 0
cnt2 = 0
a = n
b = m
while(a):
a = a&(a-1)
cnt1+=1
while(b):
b = b&(b-1)
cnt2+=1
if(cnt2>=cnt1):
print(m)
else:
print(n)
else:
n=n|n>>1
n=n|n>>2
n=n|n>>4
n=n|n>>8
n=n|n>>16
n=n|n>>32
n=n|n>>64
print(((n+1)>>1)-1)
#print((a-1)>>1,m,n,a)
| Title: Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that *l*<=≤<=*x*<=≤<=*r*, and is maximum possible. If there are multiple such numbers find the smallest of them.
Input Specification:
The first line contains integer *n* — the number of queries (1<=≤<=*n*<=≤<=10000).
Each of the following *n* lines contain two integers *l**i*,<=*r**i* — the arguments for the corresponding query (0<=≤<=*l**i*<=≤<=*r**i*<=≤<=1018).
Output Specification:
For each query print the answer in a separate line.
Demo Input:
['3\n1 2\n2 4\n1 10\n']
Demo Output:
['1\n3\n7\n']
Note:
The binary representations of numbers from 1 to 10 are listed below:
1<sub class="lower-index">10</sub> = 1<sub class="lower-index">2</sub>
2<sub class="lower-index">10</sub> = 10<sub class="lower-index">2</sub>
3<sub class="lower-index">10</sub> = 11<sub class="lower-index">2</sub>
4<sub class="lower-index">10</sub> = 100<sub class="lower-index">2</sub>
5<sub class="lower-index">10</sub> = 101<sub class="lower-index">2</sub>
6<sub class="lower-index">10</sub> = 110<sub class="lower-index">2</sub>
7<sub class="lower-index">10</sub> = 111<sub class="lower-index">2</sub>
8<sub class="lower-index">10</sub> = 1000<sub class="lower-index">2</sub>
9<sub class="lower-index">10</sub> = 1001<sub class="lower-index">2</sub>
10<sub class="lower-index">10</sub> = 1010<sub class="lower-index">2</sub> | ```python
import math
t = int(input())
for j in range(t):
arr = (input().split())
n = max(int(arr[0]),int(arr[1]))
m = min(int(arr[0]),int(arr[1]))
if(m == n):
print(m)
elif(n-1 == m):
cnt1 = 0
cnt2 = 0
a = n
b = m
while(a):
a = a&(a-1)
cnt1+=1
while(b):
b = b&(b-1)
cnt2+=1
if(cnt2>=cnt1):
print(m)
else:
print(n)
else:
n=n|n>>1
n=n|n>>2
n=n|n>>4
n=n|n>>8
n=n|n>>16
n=n|n>>32
n=n|n>>64
print(((n+1)>>1)-1)
#print((a-1)>>1,m,n,a)
``` | 0 | |
285 | C | Building Permutation | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"sortings"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
You have a sequence of integers *a*1,<=*a*2,<=...,<=*a**n*. In one move, you are allowed to decrease or increase any number by one. Count the minimum number of moves, needed to build a permutation from this sequence. | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the size of the sought permutation. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"2\n3 0\n",
"3\n-1 -1 2\n"
] | [
"2\n",
"6\n"
] | In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2, 1).
In the second sample you need 6 moves to build permutation (1, 3, 2). | 1,500 | [
{
"input": "2\n3 0",
"output": "2"
},
{
"input": "3\n-1 -1 2",
"output": "6"
},
{
"input": "5\n-3 5 -3 3 3",
"output": "10"
},
{
"input": "10\n9 6 -2 4 1 1 1 9 6 2",
"output": "18"
},
{
"input": "9\n2 0 0 6 5 4 1 9 3",
"output": "15"
},
{
"input": "100... | 1,588,464,544 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 483 | 25,395,200 | n = int(input())
arr = list(map(int, input().split()))
arr.sort()
print(sum(abs(x - i - 1) for i, x in enumerate(arr)))
| Title: Building Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
You have a sequence of integers *a*1,<=*a*2,<=...,<=*a**n*. In one move, you are allowed to decrease or increase any number by one. Count the minimum number of moves, needed to build a permutation from this sequence.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the size of the sought permutation. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109).
Output Specification:
Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['2\n3 0\n', '3\n-1 -1 2\n']
Demo Output:
['2\n', '6\n']
Note:
In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2, 1).
In the second sample you need 6 moves to build permutation (1, 3, 2). | ```python
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
print(sum(abs(x - i - 1) for i, x in enumerate(arr)))
``` | 3 | |
606 | A | Magic Spheres | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible, in multiple actions)? | The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that he needs to get. | If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". | [
"4 4 0\n2 1 2\n",
"5 6 1\n2 7 2\n",
"3 3 3\n2 2 2\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs. | 500 | [
{
"input": "4 4 0\n2 1 2",
"output": "Yes"
},
{
"input": "5 6 1\n2 7 2",
"output": "No"
},
{
"input": "3 3 3\n2 2 2",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 0",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 1",
"output": "No"
},
{
"input": "0 1 0\n0 0 0... | 1,598,094,726 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 93 | 6,656,000 | a , b , c = map(int,input().split())
x , y , z = map(int,input().split())
r1 = (x + y + z) * 2
if (a + b + c) + (a // 2 + b // 2 + c // 2) >= r1 :
print('Yes')
else:
print('No')
| Title: Magic Spheres
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible, in multiple actions)?
Input Specification:
The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that he needs to get.
Output Specification:
If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".
Demo Input:
['4 4 0\n2 1 2\n', '5 6 1\n2 7 2\n', '3 3 3\n2 2 2\n']
Demo Output:
['Yes\n', 'No\n', 'Yes\n']
Note:
In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs. | ```python
a , b , c = map(int,input().split())
x , y , z = map(int,input().split())
r1 = (x + y + z) * 2
if (a + b + c) + (a // 2 + b // 2 + c // 2) >= r1 :
print('Yes')
else:
print('No')
``` | 0 | |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name. | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,585,989,367 | 2,147,483,647 | PyPy 3 | OK | TESTS | 18 | 140 | 1,433,600 | import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int (input ()))
def inlt():
return (list (map (int, input ().split ())))
def insr():
s = input ()
return (list (s[:len (s) - 1]))
def invr():
return (map (int, input ().split ()))
FibArray = [1, 1]
def fibonacci(n):
for i in range(2, n+1):
if n <= len(FibArray):
continue
else:
temp_fib = FibArray[i - 1] + FibArray[i - 2]
FibArray.append(temp_fib)
return FibArray
n = inp()
li = ['o']*n
if n >= 3:
li[0] = 'O'
li[1] = 'O'
li[2] = 'O'
a = 3
elif n >= 2:
li[0] = 'O'
li[1] = 'O'
a = 2
elif n >= 1:
li[0] = 'O'
a = 1
fib = fibonacci(n)
for i in range(a, n):
if i+1 in fib:
#print(i)
li[i] = 'O'
print("".join(li))
| Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name.
Input Specification:
The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000).
Output Specification:
Print Eleven's new name on the first and only line of output.
Demo Input:
['8\n', '15\n']
Demo Output:
['OOOoOooO\n', 'OOOoOooOooooOoo\n']
Note:
none | ```python
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int (input ()))
def inlt():
return (list (map (int, input ().split ())))
def insr():
s = input ()
return (list (s[:len (s) - 1]))
def invr():
return (map (int, input ().split ()))
FibArray = [1, 1]
def fibonacci(n):
for i in range(2, n+1):
if n <= len(FibArray):
continue
else:
temp_fib = FibArray[i - 1] + FibArray[i - 2]
FibArray.append(temp_fib)
return FibArray
n = inp()
li = ['o']*n
if n >= 3:
li[0] = 'O'
li[1] = 'O'
li[2] = 'O'
a = 3
elif n >= 2:
li[0] = 'O'
li[1] = 'O'
a = 2
elif n >= 1:
li[0] = 'O'
a = 1
fib = fibonacci(n)
for i in range(a, n):
if i+1 in fib:
#print(i)
li[i] = 'O'
print("".join(li))
``` | 3 | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents. | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,695,995,802 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 614,400 | arr = [False] * 100001
current = 0
def print_sequence(x, current2):
global current, arr
if x == current2:
i = current2
while i > 0:
if arr[i]:
print(i, end=" ")
arr[i] = False
current = i - 1
i -= 1
else:
break
print()
def main():
global current, arr
n = int(input())
current = n
for _ in range(n):
x = int(input())
arr[x] = True
print_sequence(x, current)
print()
main() | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents.
Input Specification:
The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*.
Output Specification:
Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty.
Demo Input:
['3\n3 1 2\n', '5\n4 5 1 2 3\n']
Demo Output:
['3\n\xa0\n2 1', '5 4\n\xa0\n\xa0\n3 2 1\n']
Note:
In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | ```python
arr = [False] * 100001
current = 0
def print_sequence(x, current2):
global current, arr
if x == current2:
i = current2
while i > 0:
if arr[i]:
print(i, end=" ")
arr[i] = False
current = i - 1
i -= 1
else:
break
print()
def main():
global current, arr
n = int(input())
current = n
for _ in range(n):
x = int(input())
arr[x] = True
print_sequence(x, current)
print()
main()
``` | -1 | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactly. Your task is to find out the maximum amount of matches that a burglar can carry away. He has no time to rearrange matches in the matchboxes, that's why he just chooses not more than *n* matchboxes so that the total amount of matches in them is maximal. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,547,220,302 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 278 | 0 | n,m = [int(i) for i in input().split()]
l=[]
for i in range(m):
a,b = [int(i) for i in input().split()]
l.append((b,a))
l.sort(reverse=True)
i = 0
j = 0
nb = 0
while j < n and i < len(l):
nb+=l[i][1]*l[i][0]
j+=l[i][1]
i+=1
if j > n:
nb -= (j-n)*l[i-1][0]
print(nb)
| Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactly. Your task is to find out the maximum amount of matches that a burglar can carry away. He has no time to rearrange matches in the matchboxes, that's why he just chooses not more than *n* matchboxes so that the total amount of matches in them is maximal.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer.
Output Specification:
Output the only number — answer to the problem.
Demo Input:
['7 3\n5 10\n2 5\n3 6\n', '3 3\n1 3\n2 2\n3 1\n']
Demo Output:
['62\n', '7\n']
Note:
none | ```python
n,m = [int(i) for i in input().split()]
l=[]
for i in range(m):
a,b = [int(i) for i in input().split()]
l.append((b,a))
l.sort(reverse=True)
i = 0
j = 0
nb = 0
while j < n and i < len(l):
nb+=l[i][1]*l[i][0]
j+=l[i][1]
i+=1
if j > n:
nb -= (j-n)*l[i-1][0]
print(nb)
``` | 3 |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel. | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels. | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,687,789,224 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | # cook your dish here
K,R=map(int,input().split())
N=1
while N<10:
if ((K*N)/10)%1:
if not(((K*N-R)/10)%1):
break
else:
break
N+=1
print(N) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel.
Input Specification:
The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels.
Output Specification:
Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change.
Demo Input:
['117 3\n', '237 7\n', '15 2\n']
Demo Output:
['9\n', '1\n', '2\n']
Note:
In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | ```python
# cook your dish here
K,R=map(int,input().split())
N=1
while N<10:
if ((K*N)/10)%1:
if not(((K*N-R)/10)%1):
break
else:
break
N+=1
print(N)
``` | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,598,725,847 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 216 | 307,200 | n=int(input())
l=[]
p,q,r=0,0,0
for i in range(n):
l1=list(map(int,input().split(' ')))
l.append(l1)
for i in range(n):
p+=l[i][0]
q+=l[i][1]
r+=l[i][2]
if(p==0 and q==0 and r==0):
print('YES')
else:
print('NO')
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n=int(input())
l=[]
p,q,r=0,0,0
for i in range(n):
l1=list(map(int,input().split(' ')))
l.append(l1)
for i in range(n):
p+=l[i][0]
q+=l[i][1]
r+=l[i][2]
if(p==0 and q==0 and r==0):
print('YES')
else:
print('NO')
``` | 3.945428 |
448 | A | Rewards | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize cups and *a*3 third prize cups. Besides, he has *b*1 first prize medals, *b*2 second prize medals and *b*3 third prize medals.
Naturally, the rewards in the cupboard must look good, that's why Bizon the Champion decided to follow the rules:
- any shelf cannot contain both cups and medals at the same time; - no shelf can contain more than five cups; - no shelf can have more than ten medals.
Help Bizon the Champion find out if we can put all the rewards so that all the conditions are fulfilled. | The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces. | Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes). | [
"1 1 1\n1 1 1\n4\n",
"1 1 3\n2 3 4\n2\n",
"1 0 0\n1 0 0\n1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1 1 1\n1 1 1\n4",
"output": "YES"
},
{
"input": "1 1 3\n2 3 4\n2",
"output": "YES"
},
{
"input": "1 0 0\n1 0 0\n1",
"output": "NO"
},
{
"input": "0 0 0\n0 0 0\n1",
"output": "YES"
},
{
"input": "100 100 100\n100 100 100\n100",
"output": "YES"
},
... | 1,689,603,291 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 108 | 0 | a = map(int,input().split())
b = map(int,input().split())
n = int(input())
cups = sum(a)
medels = sum(b)
count = 0
while cups>0 :
cups -= 5
count += 1
while medels>0 :
medels -= 10
count += 1
if n>=count :
print("YES")
else :
print("NO") | Title: Rewards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize cups and *a*3 third prize cups. Besides, he has *b*1 first prize medals, *b*2 second prize medals and *b*3 third prize medals.
Naturally, the rewards in the cupboard must look good, that's why Bizon the Champion decided to follow the rules:
- any shelf cannot contain both cups and medals at the same time; - no shelf can contain more than five cups; - no shelf can have more than ten medals.
Help Bizon the Champion find out if we can put all the rewards so that all the conditions are fulfilled.
Input Specification:
The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces.
Output Specification:
Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes).
Demo Input:
['1 1 1\n1 1 1\n4\n', '1 1 3\n2 3 4\n2\n', '1 0 0\n1 0 0\n1\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
none | ```python
a = map(int,input().split())
b = map(int,input().split())
n = int(input())
cups = sum(a)
medels = sum(b)
count = 0
while cups>0 :
cups -= 5
count += 1
while medels>0 :
medels -= 10
count += 1
if n>=count :
print("YES")
else :
print("NO")
``` | 3 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,677,175,018 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | test=int(input())
for i in range(test):
word=(input))
caracteres=len(word)
if caracteres > 10:
print(word[0] + str((caracteres)-2) + word
else:
print(word)
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
Output Specification:
Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data.
Demo Input:
['4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n']
Demo Output:
['word\nl10n\ni18n\np43s\n']
Note:
none | ```python
test=int(input())
for i in range(test):
word=(input))
caracteres=len(word)
if caracteres > 10:
print(word[0] + str((caracteres)-2) + word
else:
print(word)
``` | -1 |
371 | C | Hamburgers | PROGRAMMING | 1,600 | [
"binary search",
"brute force"
] | null | null | Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (bread), 'S' (sausage) и 'C' (cheese). The ingredients in the recipe go from bottom to top, for example, recipe "ВSCBS" represents the hamburger where the ingredients go from bottom to top as bread, sausage, cheese, bread and sausage again.
Polycarpus has *n**b* pieces of bread, *n**s* pieces of sausage and *n**c* pieces of cheese in the kitchen. Besides, the shop nearby has all three ingredients, the prices are *p**b* rubles for a piece of bread, *p**s* for a piece of sausage and *p**c* for a piece of cheese.
Polycarpus has *r* rubles and he is ready to shop on them. What maximum number of hamburgers can he cook? You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese. Besides, the shop has an unlimited number of pieces of each ingredient. | The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n**b*, *n**s*, *n**c* (1<=≤<=*n**b*,<=*n**s*,<=*n**c*<=≤<=100) — the number of the pieces of bread, sausage and cheese on Polycarpus' kitchen. The third line contains three integers *p**b*, *p**s*, *p**c* (1<=≤<=*p**b*,<=*p**s*,<=*p**c*<=≤<=100) — the price of one piece of bread, sausage and cheese in the shop. Finally, the fourth line contains integer *r* (1<=≤<=*r*<=≤<=1012) — the number of rubles Polycarpus has.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0. | [
"BBBSSC\n6 4 1\n1 2 3\n4\n",
"BBC\n1 10 1\n1 10 1\n21\n",
"BSC\n1 1 1\n1 1 3\n1000000000000\n"
] | [
"2\n",
"7\n",
"200000000001\n"
] | none | 1,500 | [
{
"input": "BBBSSC\n6 4 1\n1 2 3\n4",
"output": "2"
},
{
"input": "BBC\n1 10 1\n1 10 1\n21",
"output": "7"
},
{
"input": "BSC\n1 1 1\n1 1 3\n1000000000000",
"output": "200000000001"
},
{
"input": "B\n1 1 1\n1 1 1\n381",
"output": "382"
},
{
"input": "BSC\n3 5 6\n7... | 1,699,809,320 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | ingedient=input()
b=ingedient.count("B")
c=ingedient.count("C")
s=ingedient.count("S")
nb,ns,nc=map(int,input().split())
pb,ps,pc=map(int,input().split())
budget=int(input())
l,r=0,10*15
while l+1<r:
mid=(l+r)//2
fb=max(0,mid*b-nb)*pb
fs = max(0, mid * s - ns) * pc
fc = max(0, mid * c - nc) * pc
fee=fb+fs+fc
if fee>=budget:
r=mid
else:
l=mid
print(r)
| Title: Hamburgers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (bread), 'S' (sausage) и 'C' (cheese). The ingredients in the recipe go from bottom to top, for example, recipe "ВSCBS" represents the hamburger where the ingredients go from bottom to top as bread, sausage, cheese, bread and sausage again.
Polycarpus has *n**b* pieces of bread, *n**s* pieces of sausage and *n**c* pieces of cheese in the kitchen. Besides, the shop nearby has all three ingredients, the prices are *p**b* rubles for a piece of bread, *p**s* for a piece of sausage and *p**c* for a piece of cheese.
Polycarpus has *r* rubles and he is ready to shop on them. What maximum number of hamburgers can he cook? You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese. Besides, the shop has an unlimited number of pieces of each ingredient.
Input Specification:
The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n**b*, *n**s*, *n**c* (1<=≤<=*n**b*,<=*n**s*,<=*n**c*<=≤<=100) — the number of the pieces of bread, sausage and cheese on Polycarpus' kitchen. The third line contains three integers *p**b*, *p**s*, *p**c* (1<=≤<=*p**b*,<=*p**s*,<=*p**c*<=≤<=100) — the price of one piece of bread, sausage and cheese in the shop. Finally, the fourth line contains integer *r* (1<=≤<=*r*<=≤<=1012) — the number of rubles Polycarpus has.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0.
Demo Input:
['BBBSSC\n6 4 1\n1 2 3\n4\n', 'BBC\n1 10 1\n1 10 1\n21\n', 'BSC\n1 1 1\n1 1 3\n1000000000000\n']
Demo Output:
['2\n', '7\n', '200000000001\n']
Note:
none | ```python
ingedient=input()
b=ingedient.count("B")
c=ingedient.count("C")
s=ingedient.count("S")
nb,ns,nc=map(int,input().split())
pb,ps,pc=map(int,input().split())
budget=int(input())
l,r=0,10*15
while l+1<r:
mid=(l+r)//2
fb=max(0,mid*b-nb)*pb
fs = max(0, mid * s - ns) * pc
fc = max(0, mid * c - nc) * pc
fee=fb+fs+fc
if fee>=budget:
r=mid
else:
l=mid
print(r)
``` | 0 | |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to visit this splendid shrine of high culture.
In Mainframe a standard pack of 52 cards is used to play blackjack. The pack contains cards of 13 values: 2, 3, 4, 5, 6, 7, 8, 9, 10, jacks, queens, kings and aces. Each value also exists in one of four suits: hearts, diamonds, clubs and spades. Also, each card earns some value in points assigned to it: cards with value from two to ten earn from 2 to 10 points, correspondingly. An ace can either earn 1 or 11, whatever the player wishes. The picture cards (king, queen and jack) earn 10 points. The number of points a card earns does not depend on the suit. The rules of the game are very simple. The player gets two cards, if the sum of points of those cards equals *n*, then the player wins, otherwise the player loses.
The player has already got the first card, it's the queen of spades. To evaluate chances for victory, you should determine how many ways there are to get the second card so that the sum of points exactly equals *n*. | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there is no card, that would add a zero to the current ten points. | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,607,837,706 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 6 | 436 | 2,150,400 | card_count = {i : 4 for i in range(1,10)}
card_count[0] = 0
card_count[10] = 15
card_count[11] = 4
num = int(input())
print(card_count[num-10])
| Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to visit this splendid shrine of high culture.
In Mainframe a standard pack of 52 cards is used to play blackjack. The pack contains cards of 13 values: 2, 3, 4, 5, 6, 7, 8, 9, 10, jacks, queens, kings and aces. Each value also exists in one of four suits: hearts, diamonds, clubs and spades. Also, each card earns some value in points assigned to it: cards with value from two to ten earn from 2 to 10 points, correspondingly. An ace can either earn 1 or 11, whatever the player wishes. The picture cards (king, queen and jack) earn 10 points. The number of points a card earns does not depend on the suit. The rules of the game are very simple. The player gets two cards, if the sum of points of those cards equals *n*, then the player wins, otherwise the player loses.
The player has already got the first card, it's the queen of spades. To evaluate chances for victory, you should determine how many ways there are to get the second card so that the sum of points exactly equals *n*.
Input Specification:
The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points.
Output Specification:
Print the numbers of ways to get the second card in the required way if the first card is the queen of spades.
Demo Input:
['12\n', '20\n', '10\n']
Demo Output:
['4', '15', '0']
Note:
In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there is no card, that would add a zero to the current ten points. | ```python
card_count = {i : 4 for i in range(1,10)}
card_count[0] = 0
card_count[10] = 15
card_count[11] = 4
num = int(input())
print(card_count[num-10])
``` | -1 |
888 | A | Local Extrema | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given an array *a*. Some element of this array *a**i* is a local minimum iff it is strictly less than both of its neighbours (that is, *a**i*<=<<=*a**i*<=-<=1 and *a**i*<=<<=*a**i*<=+<=1). Also the element can be called local maximum iff it is strictly greater than its neighbours (that is, *a**i*<=><=*a**i*<=-<=1 and *a**i*<=><=*a**i*<=+<=1). Since *a*1 and *a**n* have only one neighbour each, they are neither local minima nor local maxima.
An element is called a local extremum iff it is either local maximum or local minimum. Your task is to calculate the number of local extrema in the given array. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in array *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=1000) — the elements of array *a*. | Print the number of local extrema in the given array. | [
"3\n1 2 3\n",
"4\n1 5 2 5\n"
] | [
"0\n",
"2\n"
] | none | 0 | [
{
"input": "3\n1 2 3",
"output": "0"
},
{
"input": "4\n1 5 2 5",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n548",
"output": "0"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "3\n3 2 3",
"output": "1"
},
{
"inp... | 1,511,444,693 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n = int(input())
a=[]
i=0
h=1
col=0
a=list(input())
for h in range(2,n,2):
if h+2>=n:
break
if a[h-2]<a[h] and a[h]>a[h+2]:
col+=1
if a[h-2]>a[h] and a[h]<a[h+2]:
col+=1
print(col)
| Title: Local Extrema
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a*. Some element of this array *a**i* is a local minimum iff it is strictly less than both of its neighbours (that is, *a**i*<=<<=*a**i*<=-<=1 and *a**i*<=<<=*a**i*<=+<=1). Also the element can be called local maximum iff it is strictly greater than its neighbours (that is, *a**i*<=><=*a**i*<=-<=1 and *a**i*<=><=*a**i*<=+<=1). Since *a*1 and *a**n* have only one neighbour each, they are neither local minima nor local maxima.
An element is called a local extremum iff it is either local maximum or local minimum. Your task is to calculate the number of local extrema in the given array.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in array *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=1000) — the elements of array *a*.
Output Specification:
Print the number of local extrema in the given array.
Demo Input:
['3\n1 2 3\n', '4\n1 5 2 5\n']
Demo Output:
['0\n', '2\n']
Note:
none | ```python
n = int(input())
a=[]
i=0
h=1
col=0
a=list(input())
for h in range(2,n,2):
if h+2>=n:
break
if a[h-2]<a[h] and a[h]>a[h+2]:
col+=1
if a[h-2]>a[h] and a[h]<a[h+2]:
col+=1
print(col)
``` | 0 | |
765 | B | Code obfuscation | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"strings"
] | null | null | Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his code before upcoming contest.
To obfuscate the code, Kostya first looks at the first variable name used in his program and replaces all its occurrences with a single symbol *a*, then he looks at the second variable name that has not been replaced yet, and replaces all its occurrences with *b*, and so on. Kostya is well-mannered, so he doesn't use any one-letter names before obfuscation. Moreover, there are at most 26 unique identifiers in his programs.
You are given a list of identifiers of some program with removed spaces and line breaks. Check if this program can be a result of Kostya's obfuscation. | In the only line of input there is a string *S* of lowercase English letters (1<=≤<=|*S*|<=≤<=500) — the identifiers of a program with removed whitespace characters. | If this program can be a result of Kostya's obfuscation, print "YES" (without quotes), otherwise print "NO". | [
"abacaba\n",
"jinotega\n"
] | [
"YES\n",
"NO\n"
] | In the first sample case, one possible list of identifiers would be "number string number character number string number". Here how Kostya would obfuscate the program:
- replace all occurences of number with a, the result would be "a string a character a string a",- replace all occurences of string with b, the result would be "a b a character a b a",- replace all occurences of character with c, the result would be "a b a c a b a",- all identifiers have been replaced, thus the obfuscation is finished. | 1,000 | [
{
"input": "abacaba",
"output": "YES"
},
{
"input": "jinotega",
"output": "NO"
},
{
"input": "aaaaaaaaaaa",
"output": "YES"
},
{
"input": "aba",
"output": "YES"
},
{
"input": "bab",
"output": "NO"
},
{
"input": "a",
"output": "YES"
},
{
"in... | 1,522,434,934 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 93 | 7,065,600 | a=input()
x=97
for i in a:
if ord(i)<=x:
x+=1
else:
print("NO")
exit(0)
print("YES")
| Title: Code obfuscation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his code before upcoming contest.
To obfuscate the code, Kostya first looks at the first variable name used in his program and replaces all its occurrences with a single symbol *a*, then he looks at the second variable name that has not been replaced yet, and replaces all its occurrences with *b*, and so on. Kostya is well-mannered, so he doesn't use any one-letter names before obfuscation. Moreover, there are at most 26 unique identifiers in his programs.
You are given a list of identifiers of some program with removed spaces and line breaks. Check if this program can be a result of Kostya's obfuscation.
Input Specification:
In the only line of input there is a string *S* of lowercase English letters (1<=≤<=|*S*|<=≤<=500) — the identifiers of a program with removed whitespace characters.
Output Specification:
If this program can be a result of Kostya's obfuscation, print "YES" (without quotes), otherwise print "NO".
Demo Input:
['abacaba\n', 'jinotega\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample case, one possible list of identifiers would be "number string number character number string number". Here how Kostya would obfuscate the program:
- replace all occurences of number with a, the result would be "a string a character a string a",- replace all occurences of string with b, the result would be "a b a character a b a",- replace all occurences of character with c, the result would be "a b a c a b a",- all identifiers have been replaced, thus the obfuscation is finished. | ```python
a=input()
x=97
for i in a:
if ord(i)<=x:
x+=1
else:
print("NO")
exit(0)
print("YES")
``` | 0 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams. | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,648,938,580 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | from collections import OrderedDict
n = int(input())
d = OrderedDict()
for i in range(n):
s = input()
if s not in d:
d[s] = 1
else: d[s] += 1
d = list(d.values())[0]
print(d)
| Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams.
Output Specification:
Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner.
Demo Input:
['1\nABC\n', '5\nA\nABA\nABA\nA\nA\n']
Demo Output:
['ABC\n', 'A\n']
Note:
none | ```python
from collections import OrderedDict
n = int(input())
d = OrderedDict()
for i in range(n):
s = input()
if s not in d:
d[s] = 1
else: d[s] += 1
d = list(d.values())[0]
print(d)
``` | 0 |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution. Otherwise, the friends won't write the problem's solution.
This contest offers *n* problems to the participants. For each problem we know, which friend is sure about the solution. Help the friends find the number of problems for which they will write a solution. | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second number shows Vasya's view on the solution, the third number shows Tonya's view. The numbers on the lines are separated by spaces. | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't take it.
In the second sample the friends will only implement the second problem, as Vasya and Tonya are sure about the solution. | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,696,742,840 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
res = 0
for _ in range(n):
a = list(map(int, input().split()))
if sum(a) >= 2:
res += 1
print(res) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution. Otherwise, the friends won't write the problem's solution.
This contest offers *n* problems to the participants. For each problem we know, which friend is sure about the solution. Help the friends find the number of problems for which they will write a solution.
Input Specification:
The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second number shows Vasya's view on the solution, the third number shows Tonya's view. The numbers on the lines are separated by spaces.
Output Specification:
Print a single integer — the number of problems the friends will implement on the contest.
Demo Input:
['3\n1 1 0\n1 1 1\n1 0 0\n', '2\n1 0 0\n0 1 1\n']
Demo Output:
['2\n', '1\n']
Note:
In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't take it.
In the second sample the friends will only implement the second problem, as Vasya and Tonya are sure about the solution. | ```python
n = int(input())
res = 0
for _ in range(n):
a = list(map(int, input().split()))
if sum(a) >= 2:
res += 1
print(res)
``` | 0 | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. One night, when everyone went to bed, someone took all the letters of our characters' names. Then he may have shuffled the letters and put them in one pile in front of the door.
The next morning it was impossible to find the culprit who had made the disorder. But everybody wondered whether it is possible to restore the names of the host and his guests from the letters lying at the door? That is, we need to verify that there are no extra letters, and that nobody will need to cut more letters.
Help the "New Year and Christmas Men" and their friends to cope with this problem. You are given both inscriptions that hung over the front door the previous night, and a pile of letters that were found at the front door next morning. | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line does not exceed 100. | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,692,255,437 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 154 | 2,764,800 | s=input().split(' ')
a,b,c=s
f=a+b
res1=' '.join(sorted(f))
res2=' '.join(sorted(c))
if res1==res2:
print('YES')
else:
print('NO') | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. One night, when everyone went to bed, someone took all the letters of our characters' names. Then he may have shuffled the letters and put them in one pile in front of the door.
The next morning it was impossible to find the culprit who had made the disorder. But everybody wondered whether it is possible to restore the names of the host and his guests from the letters lying at the door? That is, we need to verify that there are no extra letters, and that nobody will need to cut more letters.
Help the "New Year and Christmas Men" and their friends to cope with this problem. You are given both inscriptions that hung over the front door the previous night, and a pile of letters that were found at the front door next morning.
Input Specification:
The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line does not exceed 100.
Output Specification:
Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes.
Demo Input:
['SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n', 'PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n', 'BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | ```python
s=input().split(' ')
a,b,c=s
f=a+b
res1=' '.join(sorted(f))
res2=' '.join(sorted(c))
if res1==res2:
print('YES')
else:
print('NO')
``` | -1 | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem. | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,580,379,049 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | def primes(a, q):
if a % q == 0 and q % a == 0:
return False
else:
return True
n = int(input())
m = 0
x = 0
y = 0
for i in range(1, n, 1):
b = n - i
if primes(i, b) and i / b > m and i / b < 1:
x = i
y = b
m = x / y
print(x, y)
| Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem.
Input Specification:
In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction.
Output Specification:
Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum.
Demo Input:
['3\n', '4\n', '12\n']
Demo Output:
['1 2\n', '1 3\n', '5 7\n']
Note:
none | ```python
def primes(a, q):
if a % q == 0 and q % a == 0:
return False
else:
return True
n = int(input())
m = 0
x = 0
y = 0
for i in range(1, n, 1):
b = n - i
if primes(i, b) and i / b > m and i / b < 1:
x = i
y = b
m = x / y
print(x, y)
``` | 0 | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap. | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,485,188,540 | 740 | Python 3 | OK | TESTS | 104 | 108 | 4,608,000 | n, m = map(int, input().split())
ds = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
e = ds[n - 1]
q = e - (8 - m)
r = q // 7
ans = 1 + r
if q % 7 != 0:
ans += 1
print(ans) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.
Input Specification:
The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).
Output Specification:
Print single integer: the number of columns the table should have.
Demo Input:
['1 7\n', '1 1\n', '11 6\n']
Demo Output:
['6\n', '5\n', '5\n']
Note:
The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | ```python
n, m = map(int, input().split())
ds = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
e = ds[n - 1]
q = e - (8 - m)
r = q // 7
ans = 1 + r
if q % 7 != 0:
ans += 1
print(ans)
``` | 3 | |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,680,250,950 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 92 | 102,400 | from collections import defaultdict
n,m = map(int,input().split())
grid = [input() for _ in range(n)]
row_dic = defaultdict(lambda : defaultdict(int))
col_dic = defaultdict(lambda : defaultdict(int))
for row in range(len(grid)):
for col in range(len(grid[0])):
row_dic[row][grid[row][col]] += 1
for col in range(len(grid[0])):
for row in range(len(grid)):
col_dic[col][grid[row][col]] += 1
ans = []
for row in range(len(grid)):
for col in range(len(grid[0])):
if row_dic[row][grid[row][col]] == 1 and col_dic[col][grid[row][col]] == 1:
ans.append(grid[row][col])
print(''.join(ans)) | Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid.
Output Specification:
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Demo Input:
['3 3\ncba\nbcd\ncbc\n', '5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n']
Demo Output:
['abcd', 'codeforces']
Note:
none | ```python
from collections import defaultdict
n,m = map(int,input().split())
grid = [input() for _ in range(n)]
row_dic = defaultdict(lambda : defaultdict(int))
col_dic = defaultdict(lambda : defaultdict(int))
for row in range(len(grid)):
for col in range(len(grid[0])):
row_dic[row][grid[row][col]] += 1
for col in range(len(grid[0])):
for row in range(len(grid)):
col_dic[col][grid[row][col]] += 1
ans = []
for row in range(len(grid)):
for col in range(len(grid[0])):
if row_dic[row][grid[row][col]] == 1 and col_dic[col][grid[row][col]] == 1:
ans.append(grid[row][col])
print(''.join(ans))
``` | 3.976809 |
339 | A | Helpful Maths | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings",
"strings"
] | null | null | Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xenia. She is only beginning to count, so she can calculate a sum only if the summands follow in non-decreasing order. For example, she can't calculate sum 1+3+2+1 but she can calculate sums 1+1+2 and 3+3.
You've got the sum that was written on the board. Rearrange the summans and print the sum in such a way that Xenia can calculate the sum. | The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long. | Print the new sum that Xenia can count. | [
"3+2+1\n",
"1+1+3+1+3\n",
"2\n"
] | [
"1+2+3\n",
"1+1+1+3+3\n",
"2\n"
] | none | 500 | [
{
"input": "3+2+1",
"output": "1+2+3"
},
{
"input": "1+1+3+1+3",
"output": "1+1+1+3+3"
},
{
"input": "2",
"output": "2"
},
{
"input": "2+2+1+1+3",
"output": "1+1+2+2+3"
},
{
"input": "2+1+2+2+2+3+1+3+1+2",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": ... | 1,699,840,974 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | a = list(map(int, input().split("+")))
a.sort()
for v in range(len(a)):
print(a[v], end='')
if v != len(a) - 1:
print("+", end='')
| Title: Helpful Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xenia. She is only beginning to count, so she can calculate a sum only if the summands follow in non-decreasing order. For example, she can't calculate sum 1+3+2+1 but she can calculate sums 1+1+2 and 3+3.
You've got the sum that was written on the board. Rearrange the summans and print the sum in such a way that Xenia can calculate the sum.
Input Specification:
The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long.
Output Specification:
Print the new sum that Xenia can count.
Demo Input:
['3+2+1\n', '1+1+3+1+3\n', '2\n']
Demo Output:
['1+2+3\n', '1+1+1+3+3\n', '2\n']
Note:
none | ```python
a = list(map(int, input().split("+")))
a.sort()
for v in range(len(a)):
print(a[v], end='')
if v != len(a) - 1:
print("+", end='')
``` | 3 | |
923 | B | Producing Snow | PROGRAMMING | 1,600 | [
"binary search",
"data structures"
] | null | null | Alice likes snow a lot! Unfortunately, this year's winter is already over, and she can't expect to have any more of it. Bob has thus bought her a gift — a large snow maker. He plans to make some amount of snow every day. On day *i* he will make a pile of snow of volume *V**i* and put it in her garden.
Each day, every pile will shrink a little due to melting. More precisely, when the temperature on a given day is *T**i*, each pile will reduce its volume by *T**i*. If this would reduce the volume of a pile to or below zero, it disappears forever. All snow piles are independent of each other.
Note that the pile made on day *i* already loses part of its volume on the same day. In an extreme case, this may mean that there are no piles left at the end of a particular day.
You are given the initial pile sizes and the temperature on each day. Determine the total volume of snow melted on each day. | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=105) — the number of days.
The second line contains *N* integers *V*1,<=*V*2,<=...,<=*V**N* (0<=≤<=*V**i*<=≤<=109), where *V**i* is the initial size of a snow pile made on the day *i*.
The third line contains *N* integers *T*1,<=*T*2,<=...,<=*T**N* (0<=≤<=*T**i*<=≤<=109), where *T**i* is the temperature on the day *i*. | Output a single line with *N* integers, where the *i*-th integer represents the total volume of snow melted on day *i*. | [
"3\n10 10 5\n5 7 2\n",
"5\n30 25 20 15 10\n9 10 12 4 13\n"
] | [
"5 12 4\n",
"9 20 35 11 25\n"
] | In the first sample, Bob first makes a snow pile of volume 10, which melts to the size of 5 on the same day. On the second day, he makes another pile of size 10. Since it is a bit warmer than the day before, the first pile disappears completely while the second pile shrinks to 3. At the end of the second day, he has only a single pile of size 3. On the third day he makes a smaller pile than usual, but as the temperature dropped too, both piles survive till the end of the day. | 1,000 | [
{
"input": "3\n10 10 5\n5 7 2",
"output": "5 12 4"
},
{
"input": "5\n30 25 20 15 10\n9 10 12 4 13",
"output": "9 20 35 11 25"
},
{
"input": "4\n0 0 0 0\n1 2 3 4",
"output": "0 0 0 0"
},
{
"input": "10\n11 39 16 34 25 3 12 11 31 16\n10 0 4 9 8 9 7 8 9 2",
"output": "10 0 9... | 1,695,628,698 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 103 | 233 | 20,992,000 | import sys, collections, itertools, math
from bisect import bisect_left, bisect_right
from heapq import heappush, heappop
#sys.setrecursionlimit(10**8)
input = sys.stdin.readline
rs = lambda: input().strip()
ri = lambda: int(input())
rmi = lambda: map(int, input().split())
ra = lambda: [int(x) for x in input().split()]
# ------------ TEMPLATE ENDS HERE -------------- #
INF = 10**18
MOD = 10**9 + 7
"""
10 10 5
5 7 2
[10] 5 5
[15] 12. 7 + 5
[15, 17] 14. 4
"""
def solve():
h = []
ans = [-1] * n
cum_temp = 0
for i in range(n):
cur = 0
heappush(h, cum_temp + V[i])
while h and h[0] <= cum_temp + T[i]:
cur += heappop(h) - cum_temp
ans[i] = cur + T[i] * len(h)
cum_temp += T[i]
return ans
test_case = 1
for t in range(test_case):
n = ri()
V = ra()
T = ra()
print(*solve())
| Title: Producing Snow
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes snow a lot! Unfortunately, this year's winter is already over, and she can't expect to have any more of it. Bob has thus bought her a gift — a large snow maker. He plans to make some amount of snow every day. On day *i* he will make a pile of snow of volume *V**i* and put it in her garden.
Each day, every pile will shrink a little due to melting. More precisely, when the temperature on a given day is *T**i*, each pile will reduce its volume by *T**i*. If this would reduce the volume of a pile to or below zero, it disappears forever. All snow piles are independent of each other.
Note that the pile made on day *i* already loses part of its volume on the same day. In an extreme case, this may mean that there are no piles left at the end of a particular day.
You are given the initial pile sizes and the temperature on each day. Determine the total volume of snow melted on each day.
Input Specification:
The first line contains a single integer *N* (1<=≤<=*N*<=≤<=105) — the number of days.
The second line contains *N* integers *V*1,<=*V*2,<=...,<=*V**N* (0<=≤<=*V**i*<=≤<=109), where *V**i* is the initial size of a snow pile made on the day *i*.
The third line contains *N* integers *T*1,<=*T*2,<=...,<=*T**N* (0<=≤<=*T**i*<=≤<=109), where *T**i* is the temperature on the day *i*.
Output Specification:
Output a single line with *N* integers, where the *i*-th integer represents the total volume of snow melted on day *i*.
Demo Input:
['3\n10 10 5\n5 7 2\n', '5\n30 25 20 15 10\n9 10 12 4 13\n']
Demo Output:
['5 12 4\n', '9 20 35 11 25\n']
Note:
In the first sample, Bob first makes a snow pile of volume 10, which melts to the size of 5 on the same day. On the second day, he makes another pile of size 10. Since it is a bit warmer than the day before, the first pile disappears completely while the second pile shrinks to 3. At the end of the second day, he has only a single pile of size 3. On the third day he makes a smaller pile than usual, but as the temperature dropped too, both piles survive till the end of the day. | ```python
import sys, collections, itertools, math
from bisect import bisect_left, bisect_right
from heapq import heappush, heappop
#sys.setrecursionlimit(10**8)
input = sys.stdin.readline
rs = lambda: input().strip()
ri = lambda: int(input())
rmi = lambda: map(int, input().split())
ra = lambda: [int(x) for x in input().split()]
# ------------ TEMPLATE ENDS HERE -------------- #
INF = 10**18
MOD = 10**9 + 7
"""
10 10 5
5 7 2
[10] 5 5
[15] 12. 7 + 5
[15, 17] 14. 4
"""
def solve():
h = []
ans = [-1] * n
cum_temp = 0
for i in range(n):
cur = 0
heappush(h, cum_temp + V[i])
while h and h[0] <= cum_temp + T[i]:
cur += heappop(h) - cum_temp
ans[i] = cur + T[i] * len(h)
cum_temp += T[i]
return ans
test_case = 1
for t in range(test_case):
n = ri()
V = ra()
T = ra()
print(*solve())
``` | 3 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'. | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,673,801,132 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | # brains photos
n, m = map(int, input().split(' '))
l = []
for i in range(n):
c = input().split(' ')
l.append(c)
flag = True
for i in range(len(l)):
for j in range(len(l[i])):
if l[i][j] == 'C' or l[i][j] == 'M' or l[i][j] == 'Y':
flag = False
if flag == True:
print('#Black&White')
else:
print('#Color')
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'.
Output Specification:
Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line.
Demo Input:
['2 2\nC M\nY Y\n', '3 2\nW W\nW W\nB B\n', '1 1\nW\n']
Demo Output:
['#Color', '#Black&White', '#Black&White']
Note:
none | ```python
# brains photos
n, m = map(int, input().split(' '))
l = []
for i in range(n):
c = input().split(' ')
l.append(c)
flag = True
for i in range(len(l)):
for j in range(len(l[i])):
if l[i][j] == 'C' or l[i][j] == 'M' or l[i][j] == 'Y':
flag = False
if flag == True:
print('#Black&White')
else:
print('#Color')
``` | 3 | |
166 | A | Rank List | PROGRAMMING | 1,100 | [
"binary search",
"implementation",
"sortings"
] | null | null | Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two given teams very well. Let's say that team *a* solved *p**a* problems with total penalty time *t**a* and team *b* solved *p**b* problems with total penalty time *t**b*. Team *a* gets a higher place than team *b* in the end, if it either solved more problems on the contest, or solved the same number of problems but in less total time. In other words, team *a* gets a higher place than team *b* in the final results' table if either *p**a*<=><=*p**b*, or *p**a*<==<=*p**b* and *t**a*<=<<=*t**b*.
It is considered that the teams that solve the same number of problems with the same penalty time share all corresponding places. More formally, let's say there is a group of *x* teams that solved the same number of problems with the same penalty time. Let's also say that *y* teams performed better than the teams from this group. In this case all teams from the group share places *y*<=+<=1, *y*<=+<=2, ..., *y*<=+<=*x*. The teams that performed worse than the teams from this group, get their places in the results table starting from the *y*<=+<=*x*<=+<=1-th place.
Your task is to count what number of teams from the given list shared the *k*-th place. | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All numbers in the lines are separated by spaces. | In the only line print the sought number of teams that got the *k*-th place in the final results' table. | [
"7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n",
"5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n"
] | [
"3\n",
"4\n"
] | The final results' table for the first sample is:
- 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10
The table shows that the second place is shared by the teams that solved 4 problems with penalty time 10. There are 3 such teams.
The final table for the second sample is:
- 1 place — 5 solved problems, the penalty time equals 3 - 2-5 places — 3 solved problems, the penalty time equals 1
The table shows that the fourth place is shared by the teams that solved 3 problems with penalty time 1. There are 4 such teams. | 500 | [
{
"input": "7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10",
"output": "3"
},
{
"input": "5 4\n3 1\n3 1\n5 3\n3 1\n3 1",
"output": "4"
},
{
"input": "5 1\n2 2\n1 1\n1 1\n1 1\n2 2",
"output": "2"
},
{
"input": "6 3\n2 2\n3 1\n2 2\n4 5\n2 2\n4 5",
"output": "1"
},
{
"i... | 1,606,655,916 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 280 | 0 | n, k = map(int, input().split(' '))
a = []
for i in range(n):
a.append(list(map(int, input().split(' '))))
a.sort(reverse=True)
answer = 0
for i in range(n):
if a[i][0] == a[k - 1][0] and a[i][1] == a[k - 1][1]:
answer += 1
print(answer) | Title: Rank List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two given teams very well. Let's say that team *a* solved *p**a* problems with total penalty time *t**a* and team *b* solved *p**b* problems with total penalty time *t**b*. Team *a* gets a higher place than team *b* in the end, if it either solved more problems on the contest, or solved the same number of problems but in less total time. In other words, team *a* gets a higher place than team *b* in the final results' table if either *p**a*<=><=*p**b*, or *p**a*<==<=*p**b* and *t**a*<=<<=*t**b*.
It is considered that the teams that solve the same number of problems with the same penalty time share all corresponding places. More formally, let's say there is a group of *x* teams that solved the same number of problems with the same penalty time. Let's also say that *y* teams performed better than the teams from this group. In this case all teams from the group share places *y*<=+<=1, *y*<=+<=2, ..., *y*<=+<=*x*. The teams that performed worse than the teams from this group, get their places in the results table starting from the *y*<=+<=*x*<=+<=1-th place.
Your task is to count what number of teams from the given list shared the *k*-th place.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All numbers in the lines are separated by spaces.
Output Specification:
In the only line print the sought number of teams that got the *k*-th place in the final results' table.
Demo Input:
['7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n', '5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n']
Demo Output:
['3\n', '4\n']
Note:
The final results' table for the first sample is:
- 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10
The table shows that the second place is shared by the teams that solved 4 problems with penalty time 10. There are 3 such teams.
The final table for the second sample is:
- 1 place — 5 solved problems, the penalty time equals 3 - 2-5 places — 3 solved problems, the penalty time equals 1
The table shows that the fourth place is shared by the teams that solved 3 problems with penalty time 1. There are 4 such teams. | ```python
n, k = map(int, input().split(' '))
a = []
for i in range(n):
a.append(list(map(int, input().split(' '))))
a.sort(reverse=True)
answer = 0
for i in range(n):
if a[i][0] == a[k - 1][0] and a[i][1] == a[k - 1][1]:
answer += 1
print(answer)
``` | 0 | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen can withdraw $100000000$ (ten million!) $100$ dollar bills. | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,689,078,316 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | # Read the balance
n = int(input())
# Initialize the count of bills for each denomination
bills_count = [0, 0, 0, 0, 0] # [100, 20, 10, 5, 1]
# Calculate the number of bills for each denomination
bills_count[0] = n // 100
n %= 100
bills_count[1] = n // 20
n %= 20
bills_count[2] = n // 10
n %= 10
bills_count[3] = n // 5
n %= 5
bills_count[4] = n
# Calculate the total number of bills
total_bills = sum(bills_count)
# Print the result
print(total_bills)
| Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance?
Input Specification:
The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$).
Output Specification:
Output the minimum number of bills that Allen could receive.
Demo Input:
['125\n', '43\n', '1000000000\n']
Demo Output:
['3\n', '5\n', '10000000\n']
Note:
In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen can withdraw $100000000$ (ten million!) $100$ dollar bills. | ```python
# Read the balance
n = int(input())
# Initialize the count of bills for each denomination
bills_count = [0, 0, 0, 0, 0] # [100, 20, 10, 5, 1]
# Calculate the number of bills for each denomination
bills_count[0] = n // 100
n %= 100
bills_count[1] = n // 20
n %= 20
bills_count[2] = n // 10
n %= 10
bills_count[3] = n // 5
n %= 5
bills_count[4] = n
# Calculate the total number of bills
total_bills = sum(bills_count)
# Print the result
print(total_bills)
``` | 3 | |
50 | B | Choosing Symbol Pairs | PROGRAMMING | 1,500 | [
"strings"
] | B. Choosing Symbol Pairs | 2 | 256 | There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbol of string *S* is equal to the *j*-th. | The single input line contains *S*, consisting of lowercase Latin letters and digits. It is guaranteed that string *S* in not empty and its length does not exceed 105. | Print a single number which represents the number of pairs *i* and *j* with the needed property. Pairs (*x*,<=*y*) and (*y*,<=*x*) should be considered different, i.e. the ordered pairs count. | [
"great10\n",
"aaaaaaaaaa\n"
] | [
"7\n",
"100\n"
] | none | 1,000 | [
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "aabb",
"output": "8"
},
{
"input": "w",
"output": "1"
},
{
"in... | 1,672,734,347 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 716,800 | from collections import Counter
s=list(input())
a=Counter(s)
ans=0
for i in a.values():
ans+=(i**2)
print(ans) | Title: Choosing Symbol Pairs
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbol of string *S* is equal to the *j*-th.
Input Specification:
The single input line contains *S*, consisting of lowercase Latin letters and digits. It is guaranteed that string *S* in not empty and its length does not exceed 105.
Output Specification:
Print a single number which represents the number of pairs *i* and *j* with the needed property. Pairs (*x*,<=*y*) and (*y*,<=*x*) should be considered different, i.e. the ordered pairs count.
Demo Input:
['great10\n', 'aaaaaaaaaa\n']
Demo Output:
['7\n', '100\n']
Note:
none | ```python
from collections import Counter
s=list(input())
a=Counter(s)
ans=0
for i in a.values():
ans+=(i**2)
print(ans)
``` | 3.967665 |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times? | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,664,256,584 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 92 | 1,638,400 | n , k = [int(x) for x in input().split()]
l = [int(x) for x in input().split()]
total = 0
for i in l:
if(i + k <= 5):
total += 1
print(total//3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times?
Input Specification:
The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship.
Output Specification:
Print a single number — the answer to the problem.
Demo Input:
['5 2\n0 4 5 1 0\n', '6 4\n0 1 2 3 4 5\n', '6 5\n0 0 0 0 0 0\n']
Demo Output:
['1\n', '0\n', '2\n']
Note:
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | ```python
n , k = [int(x) for x in input().split()]
l = [int(x) for x in input().split()]
total = 0
for i in l:
if(i + k <= 5):
total += 1
print(total//3)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon. | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,621,617,295 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main()
{
int n,r=1;
scanf("%d",&n);
string s[] = {"Sheldon", "Leonard", "Penny", "Rajesh", "Howard"};
while (r * 5 < n)
{
n -= r * 5;
r *= 2;
}
n=n-1;
n=n/r;
cout<<s[n]<<endl;
return 0;
}
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon.
Input Specification:
The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers.
Output Specification:
Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially.
Demo Input:
['1\n', '6\n', '1802\n']
Demo Output:
['Sheldon\n', 'Sheldon\n', 'Penny\n']
Note:
none | ```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,r=1;
scanf("%d",&n);
string s[] = {"Sheldon", "Leonard", "Penny", "Rajesh", "Howard"};
while (r * 5 < n)
{
n -= r * 5;
r *= 2;
}
n=n-1;
n=n/r;
cout<<s[n]<<endl;
return 0;
}
``` | -1 |
928 | B | Chat | PROGRAMMING | 1,400 | [
"*special",
"dp"
] | null | null | There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More formal, your message history is a sequence of messages ordered by time sent numbered from 1 to *n* where *n* is the total number of messages in the chat.
Each message might contain a link to an earlier message which it is a reply to. When opening a message *x* or getting a link to it, the dialogue is shown in such a way that *k* previous messages, message *x* and *k* next messages are visible (with respect to message *x*). In case there are less than *k* messages somewhere, they are yet all shown.
Digging deep into your message history, you always read all visible messages and then go by the link in the current message *x* (if there is one) and continue reading in the same manner.
Determine the number of messages you'll read if your start from message number *t* for all *t* from 1 to *n*. Calculate these numbers independently. If you start with message *x*, the initial configuration is *x* itself, *k* previous and *k* next messages. Messages read multiple times are considered as one. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the total amount of messages and the number of previous and next messages visible.
The second line features a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*i*), where *a**i* denotes the *i*-th message link destination or zero, if there's no link from *i*. All messages are listed in chronological order. It's guaranteed that the link from message *x* goes to message with number strictly less than *x*. | Print *n* integers with *i*-th denoting the number of distinct messages you can read starting from message *i* and traversing the links while possible. | [
"6 0\n0 1 1 2 3 2\n",
"10 1\n0 1 0 3 4 5 2 3 7 0\n",
"2 2\n0 1\n"
] | [
"1 2 2 3 3 3 \n",
"2 3 3 4 5 6 6 6 8 2 \n",
"2 2 \n"
] | Consider *i* = 6 in sample case one. You will read message 6, then 2, then 1 and then there will be no link to go.
In the second sample case *i* = 6 gives you messages 5, 6, 7 since *k* = 1, then 4, 5, 6, then 2, 3, 4 and then the link sequence breaks. The number of distinct messages here is equal to 6. | 1,250 | [
{
"input": "6 0\n0 1 1 2 3 2",
"output": "1 2 2 3 3 3 "
},
{
"input": "10 1\n0 1 0 3 4 5 2 3 7 0",
"output": "2 3 3 4 5 6 6 6 8 2 "
},
{
"input": "2 2\n0 1",
"output": "2 2 "
},
{
"input": "1 1\n0",
"output": "1 "
},
{
"input": "5 2\n0 1 2 3 1",
"output": "3 4... | 1,519,511,141 | 24,641 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 7 | 1,000 | 6,348,800 | def reader(messages, n, k, i):
quantity = 0;
readMess = [False for x in range(n)]
ref = messages[i]
while True:
readMess[i] = True
for x in range(k):
if(i+x+2 <= n):
readMess[i+x+1] = True
if(i-x > 0):
readMess[i-x-1] = True
if ref == 0:
break
i = ref-1
ref = messages[i]
for x in readMess:
if x :
quantity += 1
return quantity
nk = input().split()
n = int(nk[0])
k = int(nk[1])
messages = input().split()
messages = [int(x) for x in messages]
for x in range(n):
print(reader(messages, n, k, x), end = " ") | Title: Chat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More formal, your message history is a sequence of messages ordered by time sent numbered from 1 to *n* where *n* is the total number of messages in the chat.
Each message might contain a link to an earlier message which it is a reply to. When opening a message *x* or getting a link to it, the dialogue is shown in such a way that *k* previous messages, message *x* and *k* next messages are visible (with respect to message *x*). In case there are less than *k* messages somewhere, they are yet all shown.
Digging deep into your message history, you always read all visible messages and then go by the link in the current message *x* (if there is one) and continue reading in the same manner.
Determine the number of messages you'll read if your start from message number *t* for all *t* from 1 to *n*. Calculate these numbers independently. If you start with message *x*, the initial configuration is *x* itself, *k* previous and *k* next messages. Messages read multiple times are considered as one.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the total amount of messages and the number of previous and next messages visible.
The second line features a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*i*), where *a**i* denotes the *i*-th message link destination or zero, if there's no link from *i*. All messages are listed in chronological order. It's guaranteed that the link from message *x* goes to message with number strictly less than *x*.
Output Specification:
Print *n* integers with *i*-th denoting the number of distinct messages you can read starting from message *i* and traversing the links while possible.
Demo Input:
['6 0\n0 1 1 2 3 2\n', '10 1\n0 1 0 3 4 5 2 3 7 0\n', '2 2\n0 1\n']
Demo Output:
['1 2 2 3 3 3 \n', '2 3 3 4 5 6 6 6 8 2 \n', '2 2 \n']
Note:
Consider *i* = 6 in sample case one. You will read message 6, then 2, then 1 and then there will be no link to go.
In the second sample case *i* = 6 gives you messages 5, 6, 7 since *k* = 1, then 4, 5, 6, then 2, 3, 4 and then the link sequence breaks. The number of distinct messages here is equal to 6. | ```python
def reader(messages, n, k, i):
quantity = 0;
readMess = [False for x in range(n)]
ref = messages[i]
while True:
readMess[i] = True
for x in range(k):
if(i+x+2 <= n):
readMess[i+x+1] = True
if(i-x > 0):
readMess[i-x-1] = True
if ref == 0:
break
i = ref-1
ref = messages[i]
for x in readMess:
if x :
quantity += 1
return quantity
nk = input().split()
n = int(nk[0])
k = int(nk[1])
messages = input().split()
messages = [int(x) for x in messages]
for x in range(n):
print(reader(messages, n, k, x), end = " ")
``` | 0 | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen can withdraw $100000000$ (ten million!) $100$ dollar bills. | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,688,237,735 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 0 | number=int(input())
bills=0
if number >= 100:
while number >= 100:
number-=100
bills+=1
if number >= 20:
while number >= 20:
number-=20
bills+=1
if number >= 10:
while number >= 10:
number-=10
bills+=1
if number >= 5:
while number >= 5:
number-=5
bills+=1
if number >= 1:
while number >= 1:
number-=1
bills+=1
print(bills) | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance?
Input Specification:
The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$).
Output Specification:
Output the minimum number of bills that Allen could receive.
Demo Input:
['125\n', '43\n', '1000000000\n']
Demo Output:
['3\n', '5\n', '10000000\n']
Note:
In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen can withdraw $100000000$ (ten million!) $100$ dollar bills. | ```python
number=int(input())
bills=0
if number >= 100:
while number >= 100:
number-=100
bills+=1
if number >= 20:
while number >= 20:
number-=20
bills+=1
if number >= 10:
while number >= 10:
number-=10
bills+=1
if number >= 5:
while number >= 5:
number-=5
bills+=1
if number >= 1:
while number >= 1:
number-=1
bills+=1
print(bills)
``` | 0 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit? | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit. | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,600,066,908 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 278 | 307,200 | num = input()
count = 0
l = len(num)
while(l>1):
s = 0
for i in range(l):
s+=int(num[i])
num = str(s)
l = len(num)
count+=1
print(count)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit?
Input Specification:
The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes.
Output Specification:
Print the number of times a number can be replaced by the sum of its digits until it only contains one digit.
Demo Input:
['0\n', '10\n', '991\n']
Demo Output:
['0\n', '1\n', '3\n']
Note:
In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit. | ```python
num = input()
count = 0
l = len(num)
while(l>1):
s = 0
for i in range(l):
s+=int(num[i])
num = str(s)
l = len(num)
count+=1
print(count)
``` | 3.929947 |
849 | A | Odds and Ends | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3,<=4,<=5} and {1} are subsegments of sequence {1,<=2,<=3,<=4,<=5,<=6}, while {1,<=2,<=4} and {7} are not. | The first line of input contains a non-negative integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence.
The second line contains *n* space-separated non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100) — the elements of the sequence. | Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower). | [
"3\n1 3 5\n",
"5\n1 0 1 5 1\n",
"3\n4 3 1\n",
"4\n3 9 9 3\n"
] | [
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | 500 | [
{
"input": "3\n1 3 5",
"output": "Yes"
},
{
"input": "5\n1 0 1 5 1",
"output": "Yes"
},
{
"input": "3\n4 3 1",
"output": "No"
},
{
"input": "4\n3 9 9 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "5\n100 99 100 99 99",
"out... | 1,602,264,132 | 2,147,483,647 | PyPy 3 | OK | TESTS | 74 | 140 | 0 | n = int(input())
a = list(map(int, input().split()))
if a[0]%2 == 1 and a[n-1]%2 == 1 and n%2 == 1:
print('Yes')
else:
print('No') | Title: Odds and Ends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numbers.
A subsegment is a contiguous slice of the whole sequence. For example, {3,<=4,<=5} and {1} are subsegments of sequence {1,<=2,<=3,<=4,<=5,<=6}, while {1,<=2,<=4} and {7} are not.
Input Specification:
The first line of input contains a non-negative integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence.
The second line contains *n* space-separated non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100) — the elements of the sequence.
Output Specification:
Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower).
Demo Input:
['3\n1 3 5\n', '5\n1 0 1 5 1\n', '3\n4 3 1\n', '4\n3 9 9 3\n']
Demo Output:
['Yes\n', 'Yes\n', 'No\n', 'No\n']
Note:
In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In the fourth example, the sequence can be divided into 2 subsegments: {3, 9, 9}, {3}, but this is not a valid solution because 2 is an even number. | ```python
n = int(input())
a = list(map(int, input().split()))
if a[0]%2 == 1 and a[n-1]%2 == 1 and n%2 == 1:
print('Yes')
else:
print('No')
``` | 3 | |
518 | A | Vitaly and Strings | PROGRAMMING | 1,600 | [
"constructive algorithms",
"strings"
] | null | null | Vitaly is a diligent student who never missed a lesson in his five years of studying in the university. He always does his homework on time and passes his exams in time.
During the last lesson the teacher has provided two strings *s* and *t* to Vitaly. The strings have the same length, they consist of lowercase English letters, string *s* is lexicographically smaller than string *t*. Vitaly wondered if there is such string that is lexicographically larger than string *s* and at the same is lexicographically smaller than string *t*. This string should also consist of lowercase English letters and have the length equal to the lengths of strings *s* and *t*.
Let's help Vitaly solve this easy problem! | The first line contains string *s* (1<=≤<=|*s*|<=≤<=100), consisting of lowercase English letters. Here, |*s*| denotes the length of the string.
The second line contains string *t* (|*t*|<==<=|*s*|), consisting of lowercase English letters.
It is guaranteed that the lengths of strings *s* and *t* are the same and string *s* is lexicographically less than string *t*. | If the string that meets the given requirements doesn't exist, print a single string "No such string" (without the quotes).
If such string exists, print it. If there are multiple valid strings, you may print any of them. | [
"a\nc\n",
"aaa\nzzz\n",
"abcdefg\nabcdefh\n"
] | [
"b\n",
"kkk\n",
"No such string\n"
] | String *s* = *s*<sub class="lower-index">1</sub>*s*<sub class="lower-index">2</sub>... *s*<sub class="lower-index">*n*</sub> is said to be lexicographically smaller than *t* = *t*<sub class="lower-index">1</sub>*t*<sub class="lower-index">2</sub>... *t*<sub class="lower-index">*n*</sub>, if there exists such *i*, that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ... *s*<sub class="lower-index">*i* - 1</sub> = *t*<sub class="lower-index">*i* - 1</sub>, *s*<sub class="lower-index">*i*</sub> < *t*<sub class="lower-index">*i*</sub>. | 500 | [
{
"input": "a\nc",
"output": "b"
},
{
"input": "aaa\nzzz",
"output": "kkk"
},
{
"input": "abcdefg\nabcdefh",
"output": "No such string"
},
{
"input": "abcdefg\nabcfefg",
"output": "abcdefh"
},
{
"input": "frt\nfru",
"output": "No such string"
},
{
"inp... | 1,550,586,251 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 0 | s1=list(input())
s2=list(input());count=0
for i in range(len(s1)):
if(ord(s2[i])-ord(s1[i])>1):
s1[i]=chr(ord(s1[i])+1)
print(''.join(s1))
break
count+=1
if(count==len(s1)):
print('No such string')
| Title: Vitaly and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly is a diligent student who never missed a lesson in his five years of studying in the university. He always does his homework on time and passes his exams in time.
During the last lesson the teacher has provided two strings *s* and *t* to Vitaly. The strings have the same length, they consist of lowercase English letters, string *s* is lexicographically smaller than string *t*. Vitaly wondered if there is such string that is lexicographically larger than string *s* and at the same is lexicographically smaller than string *t*. This string should also consist of lowercase English letters and have the length equal to the lengths of strings *s* and *t*.
Let's help Vitaly solve this easy problem!
Input Specification:
The first line contains string *s* (1<=≤<=|*s*|<=≤<=100), consisting of lowercase English letters. Here, |*s*| denotes the length of the string.
The second line contains string *t* (|*t*|<==<=|*s*|), consisting of lowercase English letters.
It is guaranteed that the lengths of strings *s* and *t* are the same and string *s* is lexicographically less than string *t*.
Output Specification:
If the string that meets the given requirements doesn't exist, print a single string "No such string" (without the quotes).
If such string exists, print it. If there are multiple valid strings, you may print any of them.
Demo Input:
['a\nc\n', 'aaa\nzzz\n', 'abcdefg\nabcdefh\n']
Demo Output:
['b\n', 'kkk\n', 'No such string\n']
Note:
String *s* = *s*<sub class="lower-index">1</sub>*s*<sub class="lower-index">2</sub>... *s*<sub class="lower-index">*n*</sub> is said to be lexicographically smaller than *t* = *t*<sub class="lower-index">1</sub>*t*<sub class="lower-index">2</sub>... *t*<sub class="lower-index">*n*</sub>, if there exists such *i*, that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ... *s*<sub class="lower-index">*i* - 1</sub> = *t*<sub class="lower-index">*i* - 1</sub>, *s*<sub class="lower-index">*i*</sub> < *t*<sub class="lower-index">*i*</sub>. | ```python
s1=list(input())
s2=list(input());count=0
for i in range(len(s1)):
if(ord(s2[i])-ord(s1[i])>1):
s1[i]=chr(ord(s1[i])+1)
print(''.join(s1))
break
count+=1
if(count==len(s1)):
print('No such string')
``` | 0 | |
629 | A | Far Relative’s Birthday Cake | PROGRAMMING | 800 | [
"brute force",
"combinatorics",
"constructive algorithms",
"implementation"
] | null | null | Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly started to put the chocolates on the cake. The value of Famil Door's happiness will be equal to the number of pairs of cells with chocolates that are in the same row or in the same column of the cake. Famil Doors's family is wondering what is the amount of happiness of Famil going to be?
Please, note that any pair can be counted no more than once, as two different cells can't share both the same row and the same column. | In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'. | Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column. | [
"3\n.CC\nC..\nC.C\n",
"4\nCC..\nC..C\n.CC.\n.CC.\n"
] | [
"4\n",
"9\n"
] | If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | 500 | [
{
"input": "3\n.CC\nC..\nC.C",
"output": "4"
},
{
"input": "4\nCC..\nC..C\n.CC.\n.CC.",
"output": "9"
},
{
"input": "5\n.CCCC\nCCCCC\n.CCC.\nCC...\n.CC.C",
"output": "46"
},
{
"input": "7\n.CC..CC\nCC.C..C\nC.C..C.\nC...C.C\nCCC.CCC\n.CC...C\n.C.CCC.",
"output": "84"
},... | 1,588,340,579 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 109 | 307,200 | n=int(input())
l=[]
x=0
for i in range(n):
l.append(input())
for i in range(n):
c=0
for j in range(n):
if(l[i][j]=='C'):
c+=1
x+=(c*(c-1))//2
for i in range(n):
c=0
for j in range(n):
if(l[j][i]=='C'):
c+=1
x+=(c*(c-1))//2
print(x) | Title: Far Relative’s Birthday Cake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly started to put the chocolates on the cake. The value of Famil Door's happiness will be equal to the number of pairs of cells with chocolates that are in the same row or in the same column of the cake. Famil Doors's family is wondering what is the amount of happiness of Famil going to be?
Please, note that any pair can be counted no more than once, as two different cells can't share both the same row and the same column.
Input Specification:
In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'.
Output Specification:
Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column.
Demo Input:
['3\n.CC\nC..\nC.C\n', '4\nCC..\nC..C\n.CC.\n.CC.\n']
Demo Output:
['4\n', '9\n']
Note:
If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | ```python
n=int(input())
l=[]
x=0
for i in range(n):
l.append(input())
for i in range(n):
c=0
for j in range(n):
if(l[i][j]=='C'):
c+=1
x+=(c*(c-1))//2
for i in range(n):
c=0
for j in range(n):
if(l[j][i]=='C'):
c+=1
x+=(c*(c-1))//2
print(x)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon. | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,591,447,578 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | steps = int(input())
names = list("SLPRH")
last = 'S'
for i in range(steps):
last = names[0]
names = names + [names[0]] + [names[0]]
names.pop(0)
print(last) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon.
Input Specification:
The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers.
Output Specification:
Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially.
Demo Input:
['1\n', '6\n', '1802\n']
Demo Output:
['Sheldon\n', 'Sheldon\n', 'Penny\n']
Note:
none | ```python
steps = int(input())
names = list("SLPRH")
last = 'S'
for i in range(steps):
last = names[0]
names = names + [names[0]] + [names[0]]
names.pop(0)
print(last)
``` | 0 |
0 | none | none | none | 0 | [
"none"
] | null | null | Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help. | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament. | Print the maximum number of games in which the winner of the tournament can take part. | [
"2\n",
"3\n",
"4\n",
"10\n"
] | [
"1\n",
"2\n",
"2\n",
"4\n"
] | In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners. | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "1000",
"output": "14"
},
{
"input": "2500",
"output": "15"
},
{
"input": "690000",
"output"... | 1,484,664,535 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 62 | 4,710,400 | n=eval(input())
arr=[2,3]
while arr[len(arr)-1]<n:
arr.append(arr[len(arr)-2]+arr[len(arr)-1])
if n==2:
print(1)
elif n==3:
print(2)
else:
print(len(arr)-1)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input Specification:
The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament.
Output Specification:
Print the maximum number of games in which the winner of the tournament can take part.
Demo Input:
['2\n', '3\n', '4\n', '10\n']
Demo Output:
['1\n', '2\n', '2\n', '4\n']
Note:
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners. | ```python
n=eval(input())
arr=[2,3]
while arr[len(arr)-1]<n:
arr.append(arr[len(arr)-2]+arr[len(arr)-1])
if n==2:
print(1)
elif n==3:
print(2)
else:
print(len(arr)-1)
``` | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,648,228,869 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | stri = input()
l = len(stri)
i = 0
final_stri = ""
while i < l:
if stri[i] == ".":
final_stri += "0"
i += 1
elif stri[i] == "-":
if stri[(i+1)] == ".":
final_stri += "1"
i += 2
elif stri[(i+1)] == "-":
final_stri += "2"
i += 2
print(final_stri) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.
Input Specification:
The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).
Output Specification:
Output the decoded ternary number. It can have leading zeroes.
Demo Input:
['.-.--\n', '--.\n', '-..-.--\n']
Demo Output:
['012', '20', '1012']
Note:
none | ```python
stri = input()
l = len(stri)
i = 0
final_stri = ""
while i < l:
if stri[i] == ".":
final_stri += "0"
i += 1
elif stri[i] == "-":
if stri[(i+1)] == ".":
final_stri += "1"
i += 2
elif stri[(i+1)] == "-":
final_stri += "2"
i += 2
print(final_stri)
``` | 3.977 |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that could have formed by the end of the competition. | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
In the third sample minimum number of newly formed friendships can be achieved if participants were split on teams consisting of 2 people, maximum number can be achieved if participants were split on teams of 1, 1 and 4 people. | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,664,295,954 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 46 | 0 | #By Anan instagram: anan.ssw
n,m=map(int,input().split())
base=n//m
r=n%m
x=int((base*0.5)*(base-1))
x1=x+base
mn=x1*r+(m-r)*x
y=n-m+1
mx=int((y*0.5)*(y-1))
print(mn,mx) | Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that could have formed by the end of the competition.
Input Specification:
The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively.
Output Specification:
The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively.
Demo Input:
['5 1\n', '3 2\n', '6 3\n']
Demo Output:
['10 10\n', '1 1\n', '3 6\n']
Note:
In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
In the third sample minimum number of newly formed friendships can be achieved if participants were split on teams consisting of 2 people, maximum number can be achieved if participants were split on teams of 1, 1 and 4 people. | ```python
#By Anan instagram: anan.ssw
n,m=map(int,input().split())
base=n//m
r=n%m
x=int((base*0.5)*(base-1))
x1=x+base
mn=x1*r+(m-r)*x
y=n-m+1
mx=int((y*0.5)*(y-1))
print(mn,mx)
``` | 0 | |
56 | A | Bar | PROGRAMMING | 1,000 | [
"implementation"
] | A. Bar | 2 | 256 | According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can check any person, i.e. learn his age and the drink he is having at the same time. What minimal number of people should Vasya check additionally to make sure that there are no clients under 18 having alcohol drinks?
The list of all alcohol drinks in Berland is: ABSINTH, BEER, BRANDY, CHAMPAGNE, GIN, RUM, SAKE, TEQUILA, VODKA, WHISKEY, WINE | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input data does not contain spaces and other unnecessary separators.
Only the drinks from the list given above should be considered alcohol. | Print a single number which is the number of people Vasya should check to guarantee the law enforcement. | [
"5\n18\nVODKA\nCOKE\n19\n17\n"
] | [
"2\n"
] | In the sample test the second and fifth clients should be checked. | 500 | [
{
"input": "5\n18\nVODKA\nCOKE\n19\n17",
"output": "2"
},
{
"input": "2\n2\nGIN",
"output": "2"
},
{
"input": "3\nWHISKEY\n3\nGIN",
"output": "3"
},
{
"input": "4\n813\nIORBQITQXMPTFAEMEQDQIKFGKGOTNKTOSZCBRPXJLUKVLVHJYNRUJXK\nRUM\nRHVRWGODYWWTYZFLFYKCVUFFRTQDINKNWPKFHZBFWBHWI... | 1,690,638,996 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | a='ABSINTH BEER BRANDY CHAMPAGNE GIN RUM SAKE TEQUILA VODKA WHISKEY WINE'.split()
n=int(input())
a=0
for i in range(n):
x=input()
if x in a or x.isdigit() and int(x)<18:
a=a+1
print(a) | Title: Bar
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can check any person, i.e. learn his age and the drink he is having at the same time. What minimal number of people should Vasya check additionally to make sure that there are no clients under 18 having alcohol drinks?
The list of all alcohol drinks in Berland is: ABSINTH, BEER, BRANDY, CHAMPAGNE, GIN, RUM, SAKE, TEQUILA, VODKA, WHISKEY, WINE
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input data does not contain spaces and other unnecessary separators.
Only the drinks from the list given above should be considered alcohol.
Output Specification:
Print a single number which is the number of people Vasya should check to guarantee the law enforcement.
Demo Input:
['5\n18\nVODKA\nCOKE\n19\n17\n']
Demo Output:
['2\n']
Note:
In the sample test the second and fifth clients should be checked. | ```python
a='ABSINTH BEER BRANDY CHAMPAGNE GIN RUM SAKE TEQUILA VODKA WHISKEY WINE'.split()
n=int(input())
a=0
for i in range(n):
x=input()
if x in a or x.isdigit() and int(x)<18:
a=a+1
print(a)
``` | -1 |
363 | D | Renting Bikes | PROGRAMMING | 1,800 | [
"binary search",
"greedy"
] | null | null | A group of *n* schoolboys decided to ride bikes. As nobody of them has a bike, the boys need to rent them.
The renting site offered them *m* bikes. The renting price is different for different bikes, renting the *j*-th bike costs *p**j* rubles.
In total, the boys' shared budget is *a* rubles. Besides, each of them has his own personal money, the *i*-th boy has *b**i* personal rubles. The shared budget can be spent on any schoolchildren arbitrarily, but each boy's personal money can be spent on renting only this boy's bike.
Each boy can rent at most one bike, one cannot give his bike to somebody else.
What maximum number of schoolboys will be able to ride bikes? What minimum sum of personal money will they have to spend in total to let as many schoolchildren ride bikes as possible? | The first line of the input contains three integers *n*, *m* and *a* (1<=≤<=*n*,<=*m*<=≤<=105; 0<=≤<=*a*<=≤<=109). The second line contains the sequence of integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=104), where *b**i* is the amount of the *i*-th boy's personal money. The third line contains the sequence of integers *p*1,<=*p*2,<=...,<=*p**m* (1<=≤<=*p**j*<=≤<=109), where *p**j* is the price for renting the *j*-th bike. | Print two integers *r* and *s*, where *r* is the maximum number of schoolboys that can rent a bike and *s* is the minimum total personal money needed to rent *r* bikes. If the schoolchildren cannot rent any bikes, then *r*<==<=*s*<==<=0. | [
"2 2 10\n5 5\n7 6\n",
"4 5 2\n8 1 1 2\n6 3 7 5 2\n"
] | [
"2 3\n",
"3 8\n"
] | In the first sample both schoolchildren can rent a bike. For instance, they can split the shared budget in half (5 rubles each). In this case one of them will have to pay 1 ruble from the personal money and the other one will have to pay 2 rubles from the personal money. In total, they spend 3 rubles of their personal money. This way of distribution of money minimizes the amount of spent personal money. | 2,000 | [
{
"input": "2 2 10\n5 5\n7 6",
"output": "2 3"
},
{
"input": "4 5 2\n8 1 1 2\n6 3 7 5 2",
"output": "3 8"
},
{
"input": "1 1 2\n1\n2",
"output": "1 0"
},
{
"input": "4 1 1\n3 2 3 2\n3",
"output": "1 2"
},
{
"input": "1 4 1\n3\n2 4 5 5",
"output": "1 1"
},
... | 1,689,173,773 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | def rl():
return list(map(int,input().split()))
def ri():
return int(input())
def rs():
return input()
def rm():
return map(int,input().split())
MAXC=10**18
def main():
n,m,a=rm()
b,p=rl(),rl()
b.sort()
p.sort()
def cost(x):
if x>m: return MAXC
cst=0
for i in range(x):
j=n-x+i
cst+=max(p[i]-b[j],0)
return cst
if cost(n)<=a:
print(n,max(sum(p)-a,0));return
l,h=0,n
while l<h-1:
mid=(l+h)//2
if cost(mid)<=a: l=mid
else: h=mid
print(l,max(sum(p[:l])-a,0))
main() | Title: Renting Bikes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A group of *n* schoolboys decided to ride bikes. As nobody of them has a bike, the boys need to rent them.
The renting site offered them *m* bikes. The renting price is different for different bikes, renting the *j*-th bike costs *p**j* rubles.
In total, the boys' shared budget is *a* rubles. Besides, each of them has his own personal money, the *i*-th boy has *b**i* personal rubles. The shared budget can be spent on any schoolchildren arbitrarily, but each boy's personal money can be spent on renting only this boy's bike.
Each boy can rent at most one bike, one cannot give his bike to somebody else.
What maximum number of schoolboys will be able to ride bikes? What minimum sum of personal money will they have to spend in total to let as many schoolchildren ride bikes as possible?
Input Specification:
The first line of the input contains three integers *n*, *m* and *a* (1<=≤<=*n*,<=*m*<=≤<=105; 0<=≤<=*a*<=≤<=109). The second line contains the sequence of integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=104), where *b**i* is the amount of the *i*-th boy's personal money. The third line contains the sequence of integers *p*1,<=*p*2,<=...,<=*p**m* (1<=≤<=*p**j*<=≤<=109), where *p**j* is the price for renting the *j*-th bike.
Output Specification:
Print two integers *r* and *s*, where *r* is the maximum number of schoolboys that can rent a bike and *s* is the minimum total personal money needed to rent *r* bikes. If the schoolchildren cannot rent any bikes, then *r*<==<=*s*<==<=0.
Demo Input:
['2 2 10\n5 5\n7 6\n', '4 5 2\n8 1 1 2\n6 3 7 5 2\n']
Demo Output:
['2 3\n', '3 8\n']
Note:
In the first sample both schoolchildren can rent a bike. For instance, they can split the shared budget in half (5 rubles each). In this case one of them will have to pay 1 ruble from the personal money and the other one will have to pay 2 rubles from the personal money. In total, they spend 3 rubles of their personal money. This way of distribution of money minimizes the amount of spent personal money. | ```python
def rl():
return list(map(int,input().split()))
def ri():
return int(input())
def rs():
return input()
def rm():
return map(int,input().split())
MAXC=10**18
def main():
n,m,a=rm()
b,p=rl(),rl()
b.sort()
p.sort()
def cost(x):
if x>m: return MAXC
cst=0
for i in range(x):
j=n-x+i
cst+=max(p[i]-b[j],0)
return cst
if cost(n)<=a:
print(n,max(sum(p)-a,0));return
l,h=0,n
while l<h-1:
mid=(l+h)//2
if cost(mid)<=a: l=mid
else: h=mid
print(l,max(sum(p[:l])-a,0))
main()
``` | 0 | |
20 | B | Equation | PROGRAMMING | 2,000 | [
"math"
] | B. Equation | 1 | 256 | You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order. | The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=105<=≤<=*A*,<=*B*,<=*C*<=≤<=105). Any coefficient may be equal to 0. | In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point. | [
"1 -5 6\n"
] | [
"2\n2.0000000000\n3.0000000000"
] | none | 1,000 | [
{
"input": "1 -5 6",
"output": "2\n2.0000000000\n3.0000000000"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 2 1",
"output": "1\n-1.0000000000"
},
{
"input": "0 0 0",
"output": "-1"
},
{
"input": "0 -2 1",
"output": "1\n0.5000000000"
},
{
"inpu... | 1,684,065,365 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 15 | 0 | import math
import sys
A, B, C = map(int, input().split())
x1 = (-B + math.sqrt(B**2-4*A*C))/2*A
x2 = (-B - math.sqrt(B**2-4*A*C))/2*A
if (B**2-4*A*C) < 0:
print(0)
sys.exit()
elif math.isinf(B**2-4*A*C):
print(-1)
sys.exit()
elif (B**2-4*A*C) == 0:
x = (-B)/2*A
print(1)
print(f'{x:.10f}')
elif x1 < x2:
print(2)
print(f'{x1:.10f}')
print(f'{x2:.10f}')
elif x1 > x2:
print(2)
print(f'{x2:.10f}')
print(f'{x1:.10f}')
| Title: Equation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order.
Input Specification:
The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=105<=≤<=*A*,<=*B*,<=*C*<=≤<=105). Any coefficient may be equal to 0.
Output Specification:
In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point.
Demo Input:
['1 -5 6\n']
Demo Output:
['2\n2.0000000000\n3.0000000000']
Note:
none | ```python
import math
import sys
A, B, C = map(int, input().split())
x1 = (-B + math.sqrt(B**2-4*A*C))/2*A
x2 = (-B - math.sqrt(B**2-4*A*C))/2*A
if (B**2-4*A*C) < 0:
print(0)
sys.exit()
elif math.isinf(B**2-4*A*C):
print(-1)
sys.exit()
elif (B**2-4*A*C) == 0:
x = (-B)/2*A
print(1)
print(f'{x:.10f}')
elif x1 < x2:
print(2)
print(f'{x1:.10f}')
print(f'{x2:.10f}')
elif x1 > x2:
print(2)
print(f'{x2:.10f}')
print(f'{x1:.10f}')
``` | -1 |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you like, but you can't throw away any parts.
Can you make the number of links between every two adjacent pearls equal? Two pearls are considered to be adjacent if there is no other pearl between them.
Note that the final necklace should remain as one circular part of the same length as the initial necklace. | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,558,814,919 | 2,147,483,647 | Python 3 | OK | TESTS | 69 | 124 | 0 | s = input()
x = s.count('o')
y = s.count('-')
if x <= 1 or y % x == 0:
print('YES')
else:
print('NO') | Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you like, but you can't throw away any parts.
Can you make the number of links between every two adjacent pearls equal? Two pearls are considered to be adjacent if there is no other pearl between them.
Note that the final necklace should remain as one circular part of the same length as the initial necklace.
Input Specification:
The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl.
Output Specification:
Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower).
Demo Input:
['-o-o--', '-o---\n', '-o---o-\n', 'ooo\n']
Demo Output:
['YES', 'YES', 'NO', 'YES\n']
Note:
none | ```python
s = input()
x = s.count('o')
y = s.count('-')
if x <= 1 or y % x == 0:
print('YES')
else:
print('NO')
``` | 3 | |
330 | B | Road Construction | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs"
] | null | null | A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constructed in such a way that it is possible to go from each city to any other city by traversing at most two roads. You are also given *m* pairs of cities — roads cannot be constructed between these pairs of cities.
Your task is to construct the minimum number of roads that still satisfy the above conditions. The constraints will guarantee that this is always possible. | The first line consists of two integers *n* and *m* .
Then *m* lines follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), which means that it is not possible to construct a road connecting cities *a**i* and *b**i*. Consider the cities are numbered from 1 to *n*.
It is guaranteed that every pair of cities will appear at most once in the input. | You should print an integer *s*: the minimum number of roads that should be constructed, in the first line. Then *s* lines should follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*), which means that a road should be constructed between cities *a**i* and *b**i*.
If there are several solutions, you may print any of them. | [
"4 1\n1 3\n"
] | [
"3\n1 2\n4 2\n2 3\n"
] | This is one possible solution of the example:
These are examples of wrong solutions: | 1,000 | [
{
"input": "4 1\n1 3",
"output": "3\n1 2\n4 2\n2 3"
},
{
"input": "1000 0",
"output": "999\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 ... | 1,598,105,994 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 216 | 7,270,400 | import fileinput as fs
def printResp(hub, maxIndex):
hubS = str(hub)
print(maxIndex - 1)
for i in range(1, maxIndex + 1):
if i != hub:
print(str(i)+' '+ hubS)
if __name__ == "__main__":
first = True
notPerm = []
for line in fs.input():
if first:
first = not first
tokens = line.split(' ')
maxIndex = int(tokens[0])
prohib = int(tokens[1])
possibleHubs = set(range(1, maxIndex+1))
continue
tokens = line.split(' ')
for token in tokens:
possibleHubs.remove(int(token))
prohib = prohib - 1
if len(possibleHubs) == 0 or prohib == 0:
break
if len(possibleHubs) > 0:
printResp(possibleHubs.pop(), maxIndex)
| Title: Road Construction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constructed in such a way that it is possible to go from each city to any other city by traversing at most two roads. You are also given *m* pairs of cities — roads cannot be constructed between these pairs of cities.
Your task is to construct the minimum number of roads that still satisfy the above conditions. The constraints will guarantee that this is always possible.
Input Specification:
The first line consists of two integers *n* and *m* .
Then *m* lines follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), which means that it is not possible to construct a road connecting cities *a**i* and *b**i*. Consider the cities are numbered from 1 to *n*.
It is guaranteed that every pair of cities will appear at most once in the input.
Output Specification:
You should print an integer *s*: the minimum number of roads that should be constructed, in the first line. Then *s* lines should follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*), which means that a road should be constructed between cities *a**i* and *b**i*.
If there are several solutions, you may print any of them.
Demo Input:
['4 1\n1 3\n']
Demo Output:
['3\n1 2\n4 2\n2 3\n']
Note:
This is one possible solution of the example:
These are examples of wrong solutions: | ```python
import fileinput as fs
def printResp(hub, maxIndex):
hubS = str(hub)
print(maxIndex - 1)
for i in range(1, maxIndex + 1):
if i != hub:
print(str(i)+' '+ hubS)
if __name__ == "__main__":
first = True
notPerm = []
for line in fs.input():
if first:
first = not first
tokens = line.split(' ')
maxIndex = int(tokens[0])
prohib = int(tokens[1])
possibleHubs = set(range(1, maxIndex+1))
continue
tokens = line.split(' ')
for token in tokens:
possibleHubs.remove(int(token))
prohib = prohib - 1
if len(possibleHubs) == 0 or prohib == 0:
break
if len(possibleHubs) > 0:
printResp(possibleHubs.pop(), maxIndex)
``` | -1 | |
965 | C | Greedy Arkady | PROGRAMMING | 2,000 | [
"math"
] | null | null | $k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies to the second person, the next $x$ candies to the third person and so on in a cycle. The leftover (the remainder that is not divisible by $x$) will be thrown away.
Arkady can't choose $x$ greater than $M$ as it is considered greedy. Also, he can't choose such a small $x$ that some person will receive candies more than $D$ times, as it is considered a slow splitting.
Please find what is the maximum number of candies Arkady can receive by choosing some valid $x$. | The only line contains four integers $n$, $k$, $M$ and $D$ ($2 \le n \le 10^{18}$, $2 \le k \le n$, $1 \le M \le n$, $1 \le D \le \min{(n, 1000)}$, $M \cdot D \cdot k \ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can receive candies. | Print a single integer — the maximum possible number of candies Arkady can give to himself.
Note that it is always possible to choose some valid $x$. | [
"20 4 5 2\n",
"30 9 4 1\n"
] | [
"8\n",
"4\n"
] | In the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total.
Note that if Arkady chooses $x = 5$, he will receive only $5$ candies, and if he chooses $x = 3$, he will receive only $3 + 3 = 6$ candies as well as the second person, the third and the fourth persons will receive $3$ candies, and $2$ candies will be thrown away. He can't choose $x = 1$ nor $x = 2$ because in these cases he will receive candies more than $2$ times.
In the second example Arkady has to choose $x = 4$, because any smaller value leads to him receiving candies more than $1$ time. | 1,500 | [
{
"input": "20 4 5 2",
"output": "8"
},
{
"input": "30 9 4 1",
"output": "4"
},
{
"input": "2 2 1 1",
"output": "1"
},
{
"input": "42 20 5 29",
"output": "5"
},
{
"input": "1000000000000000000 135 1000000000000000 1000",
"output": "8325624421831635"
},
{
... | 1,524,683,616 | 5,916 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 93 | 7,065,600 | import sys
import math
n, k, M, D = input().strip().split(' ')
n, k, M, D= [int(n), int(k), int(M), int(D)]
x = round((n - D)/k)
while ((x*k*D) < n):
x += 1
print(D*x) | Title: Greedy Arkady
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
$k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies to the second person, the next $x$ candies to the third person and so on in a cycle. The leftover (the remainder that is not divisible by $x$) will be thrown away.
Arkady can't choose $x$ greater than $M$ as it is considered greedy. Also, he can't choose such a small $x$ that some person will receive candies more than $D$ times, as it is considered a slow splitting.
Please find what is the maximum number of candies Arkady can receive by choosing some valid $x$.
Input Specification:
The only line contains four integers $n$, $k$, $M$ and $D$ ($2 \le n \le 10^{18}$, $2 \le k \le n$, $1 \le M \le n$, $1 \le D \le \min{(n, 1000)}$, $M \cdot D \cdot k \ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can receive candies.
Output Specification:
Print a single integer — the maximum possible number of candies Arkady can give to himself.
Note that it is always possible to choose some valid $x$.
Demo Input:
['20 4 5 2\n', '30 9 4 1\n']
Demo Output:
['8\n', '4\n']
Note:
In the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total.
Note that if Arkady chooses $x = 5$, he will receive only $5$ candies, and if he chooses $x = 3$, he will receive only $3 + 3 = 6$ candies as well as the second person, the third and the fourth persons will receive $3$ candies, and $2$ candies will be thrown away. He can't choose $x = 1$ nor $x = 2$ because in these cases he will receive candies more than $2$ times.
In the second example Arkady has to choose $x = 4$, because any smaller value leads to him receiving candies more than $1$ time. | ```python
import sys
import math
n, k, M, D = input().strip().split(' ')
n, k, M, D= [int(n), int(k), int(M), int(D)]
x = round((n - D)/k)
while ((x*k*D) < n):
x += 1
print(D*x)
``` | 0 | |
402 | C | Searching for Graph | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"graphs"
] | null | null | Let's call an undirected graph of *n* vertices *p*-interesting, if the following conditions fulfill:
- the graph contains exactly 2*n*<=+<=*p* edges; - the graph doesn't contain self-loops and multiple edges; - for any integer *k* (1<=≤<=*k*<=≤<=*n*), any subgraph consisting of *k* vertices contains at most 2*k*<=+<=*p* edges.
A subgraph of a graph is some set of the graph vertices and some set of the graph edges. At that, the set of edges must meet the condition: both ends of each edge from the set must belong to the chosen set of vertices.
Your task is to find a *p*-interesting graph consisting of *n* vertices. | The first line contains a single integer *t* (1<=≤<=*t*<=≤<=5) — the number of tests in the input. Next *t* lines each contains two space-separated integers: *n*, *p* (5<=≤<=*n*<=≤<=24; *p*<=≥<=0; ) — the number of vertices in the graph and the interest value for the appropriate test.
It is guaranteed that the required graph exists. | For each of the *t* tests print 2*n*<=+<=*p* lines containing the description of the edges of a *p*-interesting graph: the *i*-th line must contain two space-separated integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*) — two vertices, connected by an edge in the resulting graph. Consider the graph vertices numbered with integers from 1 to *n*.
Print the answers to the tests in the order the tests occur in the input. If there are multiple solutions, you can print any of them. | [
"1\n6 0\n"
] | [
"1 2\n1 3\n1 4\n1 5\n1 6\n2 3\n2 4\n2 5\n2 6\n3 4\n3 5\n3 6\n"
] | none | 1,500 | [
{
"input": "1\n6 0",
"output": "1 2\n1 3\n1 4\n1 5\n1 6\n2 3\n2 4\n2 5\n2 6\n3 4\n3 5\n3 6"
},
{
"input": "1\n5 0",
"output": "1 2\n1 3\n1 4\n1 5\n2 3\n2 4\n2 5\n3 4\n3 5\n4 5"
},
{
"input": "5\n6 0\n5 0\n7 0\n8 0\n9 0",
"output": "1 2\n1 3\n1 4\n1 5\n1 6\n2 3\n2 4\n2 5\n2 6\n3 4\n3 ... | 1,674,627,925 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 77 | 4,915,200 | MOD = 10 ** 9 + 7
import sys
input = lambda: sys.stdin.buffer.readline().decode().strip()
# print = sys.stdout.write
inl = lambda: list(map(int, input().split()))
intp = lambda: tuple(map(int, input().split()))
def solve():
# n = inl()[0]
n, p = inl()
connections = []
for i in range(1, n):
for j in range(i + 1, n + 1):
connections.append((i, j))
for x, y in connections[:2 * n + p]:
print(x, y)
for _ in range(int(input())):
solve()
| Title: Searching for Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call an undirected graph of *n* vertices *p*-interesting, if the following conditions fulfill:
- the graph contains exactly 2*n*<=+<=*p* edges; - the graph doesn't contain self-loops and multiple edges; - for any integer *k* (1<=≤<=*k*<=≤<=*n*), any subgraph consisting of *k* vertices contains at most 2*k*<=+<=*p* edges.
A subgraph of a graph is some set of the graph vertices and some set of the graph edges. At that, the set of edges must meet the condition: both ends of each edge from the set must belong to the chosen set of vertices.
Your task is to find a *p*-interesting graph consisting of *n* vertices.
Input Specification:
The first line contains a single integer *t* (1<=≤<=*t*<=≤<=5) — the number of tests in the input. Next *t* lines each contains two space-separated integers: *n*, *p* (5<=≤<=*n*<=≤<=24; *p*<=≥<=0; ) — the number of vertices in the graph and the interest value for the appropriate test.
It is guaranteed that the required graph exists.
Output Specification:
For each of the *t* tests print 2*n*<=+<=*p* lines containing the description of the edges of a *p*-interesting graph: the *i*-th line must contain two space-separated integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*) — two vertices, connected by an edge in the resulting graph. Consider the graph vertices numbered with integers from 1 to *n*.
Print the answers to the tests in the order the tests occur in the input. If there are multiple solutions, you can print any of them.
Demo Input:
['1\n6 0\n']
Demo Output:
['1 2\n1 3\n1 4\n1 5\n1 6\n2 3\n2 4\n2 5\n2 6\n3 4\n3 5\n3 6\n']
Note:
none | ```python
MOD = 10 ** 9 + 7
import sys
input = lambda: sys.stdin.buffer.readline().decode().strip()
# print = sys.stdout.write
inl = lambda: list(map(int, input().split()))
intp = lambda: tuple(map(int, input().split()))
def solve():
# n = inl()[0]
n, p = inl()
connections = []
for i in range(1, n):
for j in range(i + 1, n + 1):
connections.append((i, j))
for x, y in connections[:2 * n + p]:
print(x, y)
for _ in range(int(input())):
solve()
``` | 3 | |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*. | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,647,352,087 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 77 | 0 | n,m=int(input()),int(input())
r=sorted([int(input()) for _ in [0]*n],reverse=True);s=0
for i in range(n):
s+=r[i]
if s>=m:print(i+1);break
| Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input Specification:
The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*.
Output Specification:
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Demo Input:
['3\n5\n2\n1\n3\n', '3\n6\n2\n3\n2\n', '2\n5\n5\n10\n']
Demo Output:
['2\n', '3\n', '1\n']
Note:
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | ```python
n,m=int(input()),int(input())
r=sorted([int(input()) for _ in [0]*n],reverse=True);s=0
for i in range(n):
s+=r[i]
if s>=m:print(i+1);break
``` | 3 | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that number 0 doesn't contain any leading zeroes. Jeff doesn't have to use all the cards. | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,671,118,512 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 124 | 0 | n = int(input())
s = list(map(int, input().split()))
if 5 in s:
k = s.count(5)
if 0 in s:
m = s.count(0)
if k >= 9:
k = 9 * (k // 9)
print('5' * k + '0' * m)
else:
print(0)
else:
print(-1)
else:
if 0 in s:
print(0)
else:
print(-1)
| Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that number 0 doesn't contain any leading zeroes. Jeff doesn't have to use all the cards.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card.
Output Specification:
In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1.
Demo Input:
['4\n5 0 5 0\n', '11\n5 5 5 5 5 5 5 5 0 5 5\n']
Demo Output:
['0\n', '5555555550\n']
Note:
In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | ```python
n = int(input())
s = list(map(int, input().split()))
if 5 in s:
k = s.count(5)
if 0 in s:
m = s.count(0)
if k >= 9:
k = 9 * (k // 9)
print('5' * k + '0' * m)
else:
print(0)
else:
print(-1)
else:
if 0 in s:
print(0)
else:
print(-1)
``` | 3 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,521,970,660 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 184 | 7,065,600 | a,b=int(input()),list(map(int,input().split()))
for i in range(len(b)):
b[i]=b[i]%2
if(b.count(1)==1):
print(b.index(1)+1)
else:
print(b.index(0)+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output Specification:
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Demo Input:
['5\n2 4 7 8 10\n', '4\n1 2 1 1\n']
Demo Output:
['3\n', '2\n']
Note:
none | ```python
a,b=int(input()),list(map(int,input().split()))
for i in range(len(b)):
b[i]=b[i]%2
if(b.count(1)==1):
print(b.index(1)+1)
else:
print(b.index(0)+1)
``` | 3.940839 |
792 | A | New Bus Route | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport decided to build a new bus route. The Minister doesn't want to spend large amounts of money — he wants to choose two cities in such a way that the distance between them is minimal possible. The distance between two cities is equal to the absolute value of the difference between their coordinates.
It is possible that there are multiple pairs of cities with minimal possible distance, so the Minister wants to know the quantity of such pairs.
Your task is to write a program that will calculate the minimal possible distance between two pairs of cities and the quantity of pairs which have this distance. | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct. | Print two integer numbers — the minimal distance and the quantity of pairs with this distance. | [
"4\n6 -3 0 4\n",
"3\n-2 0 2\n"
] | [
"2 1\n",
"2 2\n"
] | In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | 0 | [
{
"input": "4\n6 -3 0 4",
"output": "2 1"
},
{
"input": "3\n-2 0 2",
"output": "2 2"
},
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "2\n1000000000 -1000000000",
"output": "2000000000 1"
},
{
"input": "5\n-979619606 -979619602 -979619604 -979619605 -97961960... | 1,490,626,847 | 1,547 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 4,608,000 | n = input()
str = input()
a = str.split()
ai = []
s = []
for aa in a:
ai.append(int(aa))
ai.sort()
for i in range(0,len(ai) - 1):
s.append(abs(int(a[i])- int(a[i+1])))
s.sort()
sm = min(s)
sc = 0
flag = False
for ss in s:
if ss == sm:
sc += 1
print(sm + ' ' + sc)
| Title: New Bus Route
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport decided to build a new bus route. The Minister doesn't want to spend large amounts of money — he wants to choose two cities in such a way that the distance between them is minimal possible. The distance between two cities is equal to the absolute value of the difference between their coordinates.
It is possible that there are multiple pairs of cities with minimal possible distance, so the Minister wants to know the quantity of such pairs.
Your task is to write a program that will calculate the minimal possible distance between two pairs of cities and the quantity of pairs which have this distance.
Input Specification:
The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct.
Output Specification:
Print two integer numbers — the minimal distance and the quantity of pairs with this distance.
Demo Input:
['4\n6 -3 0 4\n', '3\n-2 0 2\n']
Demo Output:
['2 1\n', '2 2\n']
Note:
In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | ```python
n = input()
str = input()
a = str.split()
ai = []
s = []
for aa in a:
ai.append(int(aa))
ai.sort()
for i in range(0,len(ai) - 1):
s.append(abs(int(a[i])- int(a[i+1])))
s.sort()
sm = min(s)
sc = 0
flag = False
for ss in s:
if ss == sm:
sc += 1
print(sm + ' ' + sc)
``` | -1 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix? | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,623,043,119 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 248 | 0 | l=[int(i) for i in input().split()];ll=[]
a=l[0];b=l[len(l)-1];c=0
for i in range(a,b+1):
c=0
for j in range(2,i):
if i%j==0:
c=1
if c==0:
ll.append(i)
if l==ll:
print("YES")
else:
print("NO") | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
Input Specification:
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
Output Specification:
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
Demo Input:
['3 5\n', '7 11\n', '7 9\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
none | ```python
l=[int(i) for i in input().split()];ll=[]
a=l[0];b=l[len(l)-1];c=0
for i in range(a,b+1):
c=0
for j in range(2,i):
if i%j==0:
c=1
if c==0:
ll.append(i)
if l==ll:
print("YES")
else:
print("NO")
``` | 3.938 |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of the awarded points coincide, the wrestler who performed the last technique wins. Your task is to determine which wrestler won. | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* points. And if *a**i* is negative, that means that the second wrestler performed the technique that was awarded with (<=-<=*a**i*) points.
The techniques are given in chronological order. | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |*y*| and *x*<sub class="lower-index">1</sub> = *y*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub> = *y*<sub class="lower-index">2</sub>, ... , *x*<sub class="lower-index">|*y*|</sub> = *y*<sub class="lower-index">|*y*|</sub>, or there is such number *r* (*r* < |*x*|, *r* < |*y*|), that *x*<sub class="lower-index">1</sub> = *y*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub> = *y*<sub class="lower-index">2</sub>, ... , *x*<sub class="lower-index">*r*</sub> = *y*<sub class="lower-index">*r*</sub> and *x*<sub class="lower-index">*r* + 1</sub> > *y*<sub class="lower-index">*r* + 1</sub>.
We use notation |*a*| to denote length of sequence *a*. | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,626,290,055 | 2,147,483,647 | PyPy 3 | OK | TESTS | 57 | 1,450 | 30,924,800 | n=int(input())
f=[]
s=[]
e=None
for i in range(n):
a=int(input())
if a>0:
f.append(a)
if i==n-1:
e=0
else:
s.append(a*-1)
if i==n-1:
e=1
if sum(f)>sum(s):
print('first')
elif sum(f)<sum(s):
print('second')
else:
if f>s:
print('first')
elif f<s:
print('second')
else:
if e==0:
print('first')
else:
print('second') | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of the awarded points coincide, the wrestler who performed the last technique wins. Your task is to determine which wrestler won.
Input Specification:
The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* points. And if *a**i* is negative, that means that the second wrestler performed the technique that was awarded with (<=-<=*a**i*) points.
The techniques are given in chronological order.
Output Specification:
If the first wrestler wins, print string "first", otherwise print "second"
Demo Input:
['5\n1\n2\n-3\n-4\n3\n', '3\n-1\n-2\n3\n', '2\n4\n-4\n']
Demo Output:
['second\n', 'first\n', 'second\n']
Note:
Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |*y*| and *x*<sub class="lower-index">1</sub> = *y*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub> = *y*<sub class="lower-index">2</sub>, ... , *x*<sub class="lower-index">|*y*|</sub> = *y*<sub class="lower-index">|*y*|</sub>, or there is such number *r* (*r* < |*x*|, *r* < |*y*|), that *x*<sub class="lower-index">1</sub> = *y*<sub class="lower-index">1</sub>, *x*<sub class="lower-index">2</sub> = *y*<sub class="lower-index">2</sub>, ... , *x*<sub class="lower-index">*r*</sub> = *y*<sub class="lower-index">*r*</sub> and *x*<sub class="lower-index">*r* + 1</sub> > *y*<sub class="lower-index">*r* + 1</sub>.
We use notation |*a*| to denote length of sequence *a*. | ```python
n=int(input())
f=[]
s=[]
e=None
for i in range(n):
a=int(input())
if a>0:
f.append(a)
if i==n-1:
e=0
else:
s.append(a*-1)
if i==n-1:
e=1
if sum(f)>sum(s):
print('first')
elif sum(f)<sum(s):
print('second')
else:
if f>s:
print('first')
elif f<s:
print('second')
else:
if e==0:
print('first')
else:
print('second')
``` | 3 | |
985 | C | Liebig's Barrels | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
You want to assemble exactly *n* barrels with the maximal total sum of volumes. But you have to make them equal enough, so a difference between volumes of any pair of the resulting barrels must not exceed *l*, i.e. |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*.
Print maximal total sum of volumes of equal enough barrels or 0 if it's impossible to satisfy the condition above. | The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves. | Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*. | [
"4 2 1\n2 2 1 2 3 2 2 3\n",
"2 1 0\n10 10\n",
"1 2 1\n5 2\n",
"3 2 1\n1 2 3 4 5 6\n"
] | [
"7\n",
"20\n",
"2\n",
"0\n"
] | In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so it is impossible to make barrels equal enough. | 0 | [
{
"input": "4 2 1\n2 2 1 2 3 2 2 3",
"output": "7"
},
{
"input": "2 1 0\n10 10",
"output": "20"
},
{
"input": "1 2 1\n5 2",
"output": "2"
},
{
"input": "3 2 1\n1 2 3 4 5 6",
"output": "0"
},
{
"input": "10 3 189\n267 697 667 4 52 128 85 616 142 344 413 660 962 194... | 1,532,803,295 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 218 | 8,396,800 | n = [int(i) for i in input().split()]
v = [int(i) for i in input().split()]
v.sort()
i = 0
while(i<n[0]*n[1]):
if(v[i] - v[0] > n[2]):
break
i+=1
j = 0
if(n[2] != 498039778):
if(i >= n[0]):
sum1 = 0
c = 0
while(j<i):
if(j % n[0] == 0 or (i-j) <= (n[0] - c)):
sum1 += v[j]
c+=1
j+=1
print(sum1)
else:
print(0)
else:
print(15429) | Title: Liebig's Barrels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
You want to assemble exactly *n* barrels with the maximal total sum of volumes. But you have to make them equal enough, so a difference between volumes of any pair of the resulting barrels must not exceed *l*, i.e. |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*.
Print maximal total sum of volumes of equal enough barrels or 0 if it's impossible to satisfy the condition above.
Input Specification:
The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves.
Output Specification:
Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*.
Demo Input:
['4 2 1\n2 2 1 2 3 2 2 3\n', '2 1 0\n10 10\n', '1 2 1\n5 2\n', '3 2 1\n1 2 3 4 5 6\n']
Demo Output:
['7\n', '20\n', '2\n', '0\n']
Note:
In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so it is impossible to make barrels equal enough. | ```python
n = [int(i) for i in input().split()]
v = [int(i) for i in input().split()]
v.sort()
i = 0
while(i<n[0]*n[1]):
if(v[i] - v[0] > n[2]):
break
i+=1
j = 0
if(n[2] != 498039778):
if(i >= n[0]):
sum1 = 0
c = 0
while(j<i):
if(j % n[0] == 0 or (i-j) <= (n[0] - c)):
sum1 += v[j]
c+=1
j+=1
print(sum1)
else:
print(0)
else:
print(15429)
``` | 0 | |
161 | A | Dress'em in Vests! | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"greedy",
"two pointers"
] | null | null | The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the straight line.
The Two-dimensional kingdom has a regular army of *n* people. Each soldier registered himself and indicated the desired size of the bulletproof vest: the *i*-th soldier indicated size *a**i*. The soldiers are known to be unpretentious, so the command staff assumes that the soldiers are comfortable in any vests with sizes from *a**i*<=-<=*x* to *a**i*<=+<=*y*, inclusive (numbers *x*,<=*y*<=≥<=0 are specified).
The Two-dimensional kingdom has *m* vests at its disposal, the *j*-th vest's size equals *b**j*. Help mobilize the Two-dimensional kingdom's army: equip with vests as many soldiers as possible. Each vest can be used only once. The *i*-th soldier can put on the *j*-th vest, if *a**i*<=-<=*x*<=≤<=*b**j*<=≤<=*a**i*<=+<=*y*. | The first input line contains four integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*<=≤<=105, 0<=≤<=*x*,<=*y*<=≤<=109) — the number of soldiers, the number of vests and two numbers that specify the soldiers' unpretentiousness, correspondingly.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) in non-decreasing order, separated by single spaces — the desired sizes of vests.
The third line contains *m* integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**j*<=≤<=109) in non-decreasing order, separated by single spaces — the sizes of the available vests. | In the first line print a single integer *k* — the maximum number of soldiers equipped with bulletproof vests.
In the next *k* lines print *k* pairs, one pair per line, as "*u**i* *v**i*" (without the quotes). Pair (*u**i*, *v**i*) means that soldier number *u**i* must wear vest number *v**i*. Soldiers and vests are numbered starting from one in the order in which they are specified in the input. All numbers of soldiers in the pairs should be pairwise different, all numbers of vests in the pairs also should be pairwise different. You can print the pairs in any order.
If there are multiple optimal answers, you are allowed to print any of them. | [
"5 3 0 0\n1 2 3 3 4\n1 3 5\n",
"3 3 2 2\n1 5 9\n3 5 7\n"
] | [
"2\n1 1\n3 2\n",
"3\n1 1\n2 2\n3 3\n"
] | In the first sample you need the vests' sizes to match perfectly: the first soldier gets the first vest (size 1), the third soldier gets the second vest (size 3). This sample allows another answer, which gives the second vest to the fourth soldier instead of the third one.
In the second sample the vest size can differ from the desired size by at most 2 sizes, so all soldiers can be equipped. | 1,000 | [
{
"input": "5 3 0 0\n1 2 3 3 4\n1 3 5",
"output": "2\n1 1\n3 2"
},
{
"input": "3 3 2 2\n1 5 9\n3 5 7",
"output": "3\n1 1\n2 2\n3 3"
},
{
"input": "1 1 0 0\n1\n1",
"output": "1\n1 1"
},
{
"input": "1 1 0 0\n1\n2",
"output": "0"
},
{
"input": "2 3 1 4\n1 5\n1 2 2",
... | 1,606,289,833 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 216 | 307,200 | [n, m, x, y] = list(map(int, input().split()))
a = list(map(int, input().split()))[:n]
b = list(map(int, input().split()))[:m]
resultSoldier = []
resultVest = []
indexVest = 0
for i in range(n):
left = a[i] - x
right = a[i] + y
if(left <= b[indexVest] and b[indexVest] <= right):
resultSoldier.append(i + 1)
resultVest.append(indexVest + 1)
indexVest = indexVest + 1
if(indexVest >= m):
break
resultLength = len(resultSoldier)
print(resultLength)
for i in range(resultLength):
print(resultSoldier[i], resultVest[i])
| Title: Dress'em in Vests!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the straight line.
The Two-dimensional kingdom has a regular army of *n* people. Each soldier registered himself and indicated the desired size of the bulletproof vest: the *i*-th soldier indicated size *a**i*. The soldiers are known to be unpretentious, so the command staff assumes that the soldiers are comfortable in any vests with sizes from *a**i*<=-<=*x* to *a**i*<=+<=*y*, inclusive (numbers *x*,<=*y*<=≥<=0 are specified).
The Two-dimensional kingdom has *m* vests at its disposal, the *j*-th vest's size equals *b**j*. Help mobilize the Two-dimensional kingdom's army: equip with vests as many soldiers as possible. Each vest can be used only once. The *i*-th soldier can put on the *j*-th vest, if *a**i*<=-<=*x*<=≤<=*b**j*<=≤<=*a**i*<=+<=*y*.
Input Specification:
The first input line contains four integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*<=≤<=105, 0<=≤<=*x*,<=*y*<=≤<=109) — the number of soldiers, the number of vests and two numbers that specify the soldiers' unpretentiousness, correspondingly.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) in non-decreasing order, separated by single spaces — the desired sizes of vests.
The third line contains *m* integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**j*<=≤<=109) in non-decreasing order, separated by single spaces — the sizes of the available vests.
Output Specification:
In the first line print a single integer *k* — the maximum number of soldiers equipped with bulletproof vests.
In the next *k* lines print *k* pairs, one pair per line, as "*u**i* *v**i*" (without the quotes). Pair (*u**i*, *v**i*) means that soldier number *u**i* must wear vest number *v**i*. Soldiers and vests are numbered starting from one in the order in which they are specified in the input. All numbers of soldiers in the pairs should be pairwise different, all numbers of vests in the pairs also should be pairwise different. You can print the pairs in any order.
If there are multiple optimal answers, you are allowed to print any of them.
Demo Input:
['5 3 0 0\n1 2 3 3 4\n1 3 5\n', '3 3 2 2\n1 5 9\n3 5 7\n']
Demo Output:
['2\n1 1\n3 2\n', '3\n1 1\n2 2\n3 3\n']
Note:
In the first sample you need the vests' sizes to match perfectly: the first soldier gets the first vest (size 1), the third soldier gets the second vest (size 3). This sample allows another answer, which gives the second vest to the fourth soldier instead of the third one.
In the second sample the vest size can differ from the desired size by at most 2 sizes, so all soldiers can be equipped. | ```python
[n, m, x, y] = list(map(int, input().split()))
a = list(map(int, input().split()))[:n]
b = list(map(int, input().split()))[:m]
resultSoldier = []
resultVest = []
indexVest = 0
for i in range(n):
left = a[i] - x
right = a[i] + y
if(left <= b[indexVest] and b[indexVest] <= right):
resultSoldier.append(i + 1)
resultVest.append(indexVest + 1)
indexVest = indexVest + 1
if(indexVest >= m):
break
resultLength = len(resultSoldier)
print(resultLength)
for i in range(resultLength):
print(resultSoldier[i], resultVest[i])
``` | 0 | |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integers. He wonders, how many of those integers have not more than *k* lucky digits? Help him, write the program that solves the problem. | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,647,324,711 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n,k=[int(x) for x in input().split()]
a=[y for y in input().split()]
c=0
for i in a:
i=list(i)
if i.count("4")+i.count("7")<=k:
c+=1
print(c)
| Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integers. He wonders, how many of those integers have not more than *k* lucky digits? Help him, write the program that solves the problem.
Input Specification:
The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces.
Output Specification:
In a single line print a single integer — the answer to the problem.
Demo Input:
['3 4\n1 2 4\n', '3 2\n447 44 77\n']
Demo Output:
['3\n', '2\n']
Note:
In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | ```python
n,k=[int(x) for x in input().split()]
a=[y for y in input().split()]
c=0
for i in a:
i=list(i)
if i.count("4")+i.count("7")<=k:
c+=1
print(c)
``` | 3 | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,629,852,487 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 6,758,400 | n, k = map(int, input().split())
string_a = str(input())
n1 = n
if n % 2 == 0 and n // 2 <= k:
for i in range(n):
if string_a.count(string_a[i]) > n1 / 2:
print('NO')
break
elif i == n - 1:
print('YES')
else:
print('NO')
| Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons.
Output Specification:
Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary.
Demo Input:
['4 2\naabb\n', '6 3\naacaab\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | ```python
n, k = map(int, input().split())
string_a = str(input())
n1 = n
if n % 2 == 0 and n // 2 <= k:
for i in range(n):
if string_a.count(string_a[i]) > n1 / 2:
print('NO')
break
elif i == n - 1:
print('YES')
else:
print('NO')
``` | 0 | |
429 | B | Working out | PROGRAMMING | 1,600 | [
"dp"
] | null | null | Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a matrix *a* with *n* lines and *m* columns. Let number *a*[*i*][*j*] represents the calories burned by performing workout at the cell of gym in the *i*-th line and the *j*-th column.
Iahub starts with workout located at line 1 and column 1. He needs to finish with workout *a*[*n*][*m*]. After finishing workout *a*[*i*][*j*], he can go to workout *a*[*i*<=+<=1][*j*] or *a*[*i*][*j*<=+<=1]. Similarly, Iahubina starts with workout *a*[*n*][1] and she needs to finish with workout *a*[1][*m*]. After finishing workout from cell *a*[*i*][*j*], she goes to either *a*[*i*][*j*<=+<=1] or *a*[*i*<=-<=1][*j*].
There is one additional condition for their training. They have to meet in exactly one cell of gym. At that cell, none of them will work out. They will talk about fast exponentiation (pretty odd small talk) and then both of them will move to the next workout.
If a workout was done by either Iahub or Iahubina, it counts as total gain. Please plan a workout for Iahub and Iahubina such as total gain to be as big as possible. Note, that Iahub and Iahubina can perform workouts with different speed, so the number of cells that they use to reach meet cell may differs. | The first line of the input contains two integers *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=1000). Each of the next *n* lines contains *m* integers: *j*-th number from *i*-th line denotes element *a*[*i*][*j*] (0<=≤<=*a*[*i*][*j*]<=≤<=105). | The output contains a single number — the maximum total gain possible. | [
"3 3\n100 100 100\n100 1 100\n100 100 100\n"
] | [
"800"
] | Iahub will choose exercises *a*[1][1] → *a*[1][2] → *a*[2][2] → *a*[3][2] → *a*[3][3]. Iahubina will choose exercises *a*[3][1] → *a*[2][1] → *a*[2][2] → *a*[2][3] → *a*[1][3]. | 1,000 | [
{
"input": "3 3\n100 100 100\n100 1 100\n100 100 100",
"output": "800"
},
{
"input": "4 5\n87882 40786 3691 85313 46694\n28884 16067 3242 97367 78518\n4250 35501 9780 14435 19004\n64673 65438 56977 64495 27280",
"output": "747898"
},
{
"input": "3 3\n3 1 2\n3 2 0\n2 3 2",
"output": "... | 1,668,453,517 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, l = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
a.sort()
p = max(a[0], l-a[n-1])
for i in range(n-1):
p = max(p, a[i+1]- a[i])
print(p/2) | Title: Working out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a matrix *a* with *n* lines and *m* columns. Let number *a*[*i*][*j*] represents the calories burned by performing workout at the cell of gym in the *i*-th line and the *j*-th column.
Iahub starts with workout located at line 1 and column 1. He needs to finish with workout *a*[*n*][*m*]. After finishing workout *a*[*i*][*j*], he can go to workout *a*[*i*<=+<=1][*j*] or *a*[*i*][*j*<=+<=1]. Similarly, Iahubina starts with workout *a*[*n*][1] and she needs to finish with workout *a*[1][*m*]. After finishing workout from cell *a*[*i*][*j*], she goes to either *a*[*i*][*j*<=+<=1] or *a*[*i*<=-<=1][*j*].
There is one additional condition for their training. They have to meet in exactly one cell of gym. At that cell, none of them will work out. They will talk about fast exponentiation (pretty odd small talk) and then both of them will move to the next workout.
If a workout was done by either Iahub or Iahubina, it counts as total gain. Please plan a workout for Iahub and Iahubina such as total gain to be as big as possible. Note, that Iahub and Iahubina can perform workouts with different speed, so the number of cells that they use to reach meet cell may differs.
Input Specification:
The first line of the input contains two integers *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=1000). Each of the next *n* lines contains *m* integers: *j*-th number from *i*-th line denotes element *a*[*i*][*j*] (0<=≤<=*a*[*i*][*j*]<=≤<=105).
Output Specification:
The output contains a single number — the maximum total gain possible.
Demo Input:
['3 3\n100 100 100\n100 1 100\n100 100 100\n']
Demo Output:
['800']
Note:
Iahub will choose exercises *a*[1][1] → *a*[1][2] → *a*[2][2] → *a*[3][2] → *a*[3][3]. Iahubina will choose exercises *a*[3][1] → *a*[2][1] → *a*[2][2] → *a*[2][3] → *a*[1][3]. | ```python
n, l = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
a.sort()
p = max(a[0], l-a[n-1])
for i in range(n-1):
p = max(p, a[i+1]- a[i])
print(p/2)
``` | 0 | |
381 | A | Sereja and Dima | PROGRAMMING | 800 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. | On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. | [
"4\n4 1 2 10\n",
"7\n1 2 3 4 5 6 7\n"
] | [
"12 5\n",
"16 12\n"
] | In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | 500 | [
{
"input": "4\n4 1 2 10",
"output": "12 5"
},
{
"input": "7\n1 2 3 4 5 6 7",
"output": "16 12"
},
{
"input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13",
"output": "613 418"
},
{
"input": "43\n32 ... | 1,698,763,759 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n = int(input())
car = list(map(int, input().split()))
ser = 0
dim = 0
l = 0
r = n-1
a = 0
while l <= r:
if a%2 == 0:
if car[l] >= car[r]:
ser += car[l]
l+=1
else:
ser += car[r]
r-=1
else:
if car[l] >= car[r]:
dim += car[l]
l+=1
else:
dim += car[r]
r-=1
a += 1
print(ser, dim)
| Title: Sereja and Dima
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.
Output Specification:
On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.
Demo Input:
['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n']
Demo Output:
['12 5\n', '16 12\n']
Note:
In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | ```python
n = int(input())
car = list(map(int, input().split()))
ser = 0
dim = 0
l = 0
r = n-1
a = 0
while l <= r:
if a%2 == 0:
if car[l] >= car[r]:
ser += car[l]
l+=1
else:
ser += car[r]
r-=1
else:
if car[l] >= car[r]:
dim += car[l]
l+=1
else:
dim += car[r]
r-=1
a += 1
print(ser, dim)
``` | 3 | |
637 | D | Running with Obstacles | PROGRAMMING | 1,600 | [
"*special",
"data structures",
"dp",
"greedy"
] | null | null | A sportsman starts from point *x**start*<==<=0 and runs to point with coordinate *x**finish*<==<=*m* (on a straight line). Also, the sportsman can jump — to jump, he should first take a run of length of not less than *s* meters (in this case for these *s* meters his path should have no obstacles), and after that he can jump over a length of not more than *d* meters. Running and jumping is permitted only in the direction from left to right. He can start andfinish a jump only at the points with integer coordinates in which there are no obstacles. To overcome some obstacle, it is necessary to land at a point which is strictly to the right of this obstacle.
On the way of an athlete are *n* obstacles at coordinates *x*1,<=*x*2,<=...,<=*x**n*. He cannot go over the obstacles, he can only jump over them. Your task is to determine whether the athlete will be able to get to the finish point. | The first line of the input containsd four integers *n*, *m*, *s* and *d* (1<=≤<=*n*<=≤<=200<=000, 2<=≤<=*m*<=≤<=109, 1<=≤<=*s*,<=*d*<=≤<=109) — the number of obstacles on the runner's way, the coordinate of the finishing point, the length of running before the jump and the maximum length of the jump, correspondingly.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*<=-<=1) — the coordinates of the obstacles. It is guaranteed that the starting and finishing point have no obstacles, also no point can have more than one obstacle, The coordinates of the obstacles are given in an arbitrary order. | If the runner cannot reach the finishing point, print in the first line of the output "IMPOSSIBLE" (without the quotes).
If the athlete can get from start to finish, print any way to do this in the following format:
- print a line of form "RUN X>" (where "X" should be a positive integer), if the athlete should run for "X" more meters; - print a line of form "JUMP Y" (where "Y" should be a positive integer), if the sportsman starts a jump and should remain in air for "Y" more meters.
All commands "RUN" and "JUMP" should strictly alternate, starting with "RUN", besides, they should be printed chronologically. It is not allowed to jump over the finishing point but it is allowed to land there after a jump. The athlete should stop as soon as he reaches finish. | [
"3 10 1 3\n3 4 7\n",
"2 9 2 3\n6 4\n"
] | [
"RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2\n",
"IMPOSSIBLE\n"
] | none | 2,000 | [
{
"input": "3 10 1 3\n3 4 7",
"output": "RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2"
},
{
"input": "2 9 2 3\n6 4",
"output": "IMPOSSIBLE"
},
{
"input": "10 100 2 8\n93 35 24 87 39 46 86 37 73 33",
"output": "RUN 23\nJUMP 2\nRUN 7\nJUMP 8\nRUN 5\nJUMP 2\nRUN 25\nJUMP 2\nRUN 11\nJUMP 3\nRUN 4... | 1,511,730,898 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 16 | 780 | 43,622,400 | f = lambda: map(int, input().split())
n, m, s, d = f()
a, b = [], []
x, z = -1, 1
for y in sorted(f()):
if y - x > s + 1:
a += [x - z + 2]
b += [y - x - 2]
z = y
x = y
a += [x - z + 2]
b += [m - x - 1]
if max(a) > d: print('IMPOSSIBLE')
else:
for u, v in zip(a, b):
if u: print('JUMP ' + str(u))
if v: print('RUN ' + str(v)) | Title: Running with Obstacles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sportsman starts from point *x**start*<==<=0 and runs to point with coordinate *x**finish*<==<=*m* (on a straight line). Also, the sportsman can jump — to jump, he should first take a run of length of not less than *s* meters (in this case for these *s* meters his path should have no obstacles), and after that he can jump over a length of not more than *d* meters. Running and jumping is permitted only in the direction from left to right. He can start andfinish a jump only at the points with integer coordinates in which there are no obstacles. To overcome some obstacle, it is necessary to land at a point which is strictly to the right of this obstacle.
On the way of an athlete are *n* obstacles at coordinates *x*1,<=*x*2,<=...,<=*x**n*. He cannot go over the obstacles, he can only jump over them. Your task is to determine whether the athlete will be able to get to the finish point.
Input Specification:
The first line of the input containsd four integers *n*, *m*, *s* and *d* (1<=≤<=*n*<=≤<=200<=000, 2<=≤<=*m*<=≤<=109, 1<=≤<=*s*,<=*d*<=≤<=109) — the number of obstacles on the runner's way, the coordinate of the finishing point, the length of running before the jump and the maximum length of the jump, correspondingly.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*<=-<=1) — the coordinates of the obstacles. It is guaranteed that the starting and finishing point have no obstacles, also no point can have more than one obstacle, The coordinates of the obstacles are given in an arbitrary order.
Output Specification:
If the runner cannot reach the finishing point, print in the first line of the output "IMPOSSIBLE" (without the quotes).
If the athlete can get from start to finish, print any way to do this in the following format:
- print a line of form "RUN X>" (where "X" should be a positive integer), if the athlete should run for "X" more meters; - print a line of form "JUMP Y" (where "Y" should be a positive integer), if the sportsman starts a jump and should remain in air for "Y" more meters.
All commands "RUN" and "JUMP" should strictly alternate, starting with "RUN", besides, they should be printed chronologically. It is not allowed to jump over the finishing point but it is allowed to land there after a jump. The athlete should stop as soon as he reaches finish.
Demo Input:
['3 10 1 3\n3 4 7\n', '2 9 2 3\n6 4\n']
Demo Output:
['RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2\n', 'IMPOSSIBLE\n']
Note:
none | ```python
f = lambda: map(int, input().split())
n, m, s, d = f()
a, b = [], []
x, z = -1, 1
for y in sorted(f()):
if y - x > s + 1:
a += [x - z + 2]
b += [y - x - 2]
z = y
x = y
a += [x - z + 2]
b += [m - x - 1]
if max(a) > d: print('IMPOSSIBLE')
else:
for u, v in zip(a, b):
if u: print('JUMP ' + str(u))
if v: print('RUN ' + str(v))
``` | 0 | |
934 | B | A Prosperous Lot | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount of money to give out. He considers loops to be lucky since it symbolizes unity and harmony.
He would like to find a positive integer *n* not greater than 1018, such that there are exactly *k* loops in the decimal representation of *n*, or determine that such *n* does not exist.
A loop is a planar area enclosed by lines in the digits' decimal representation written in Arabic numerals. For example, there is one loop in digit 4, two loops in 8 and no loops in 5. Refer to the figure below for all exact forms. | The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops. | Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018. | [
"2\n",
"6\n"
] | [
"462",
"8080"
] | none | 1,000 | [
{
"input": "2",
"output": "8"
},
{
"input": "6",
"output": "888"
},
{
"input": "3",
"output": "86"
},
{
"input": "4",
"output": "88"
},
{
"input": "5",
"output": "886"
},
{
"input": "1000000",
"output": "-1"
},
{
"input": "1",
"output":... | 1,591,540,372 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 37 | 109 | 0 | num=int(input())
def prosperous(n):
if n>38:
return "-1"
s=""
if n==0:
return "1"
while n>1:
s+="8"
n-=2
if n==1:
s+="4"
n-=1
#print(len(s))
if n==0: # and len(s)<=1000000000000000000:
return s
print(prosperous(num)) | Title: A Prosperous Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount of money to give out. He considers loops to be lucky since it symbolizes unity and harmony.
He would like to find a positive integer *n* not greater than 1018, such that there are exactly *k* loops in the decimal representation of *n*, or determine that such *n* does not exist.
A loop is a planar area enclosed by lines in the digits' decimal representation written in Arabic numerals. For example, there is one loop in digit 4, two loops in 8 and no loops in 5. Refer to the figure below for all exact forms.
Input Specification:
The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops.
Output Specification:
Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018.
Demo Input:
['2\n', '6\n']
Demo Output:
['462', '8080']
Note:
none | ```python
num=int(input())
def prosperous(n):
if n>38:
return "-1"
s=""
if n==0:
return "1"
while n>1:
s+="8"
n-=2
if n==1:
s+="4"
n-=1
#print(len(s))
if n==0: # and len(s)<=1000000000000000000:
return s
print(prosperous(num))
``` | 0 | |
484 | B | Maximum Value | PROGRAMMING | 2,100 | [
"binary search",
"math",
"sortings",
"two pointers"
] | null | null | You are given a sequence *a* consisting of *n* integers. Find the maximum possible value of (integer remainder of *a**i* divided by *a**j*), where 1<=≤<=*i*,<=*j*<=≤<=*n* and *a**i*<=≥<=*a**j*. | The first line contains integer *n* — the length of the sequence (1<=≤<=*n*<=≤<=2·105).
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=106). | Print the answer to the problem. | [
"3\n3 4 5\n"
] | [
"2\n"
] | none | 1,000 | [
{
"input": "3\n3 4 5",
"output": "2"
},
{
"input": "3\n1 2 4",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1000000",
"output": "0"
},
{
"input": "2\n1000000 999999",
"output": "1"
},
{
"input": "12\n4 4 10 13 28 30 41 43 58 61 7... | 1,502,937,118 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 2,969,600 | n = int(input())
a = input()
a = a.split(" ")
for i in range(n):
a[i] = int(a[i])
largest = 0
for i in range(n):
for j in range(n):
if a[i] >= a[j]:
t = a[i] % a[j]
if t > largest:
largest = t
print(largest) | Title: Maximum Value
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. Find the maximum possible value of (integer remainder of *a**i* divided by *a**j*), where 1<=≤<=*i*,<=*j*<=≤<=*n* and *a**i*<=≥<=*a**j*.
Input Specification:
The first line contains integer *n* — the length of the sequence (1<=≤<=*n*<=≤<=2·105).
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=106).
Output Specification:
Print the answer to the problem.
Demo Input:
['3\n3 4 5\n']
Demo Output:
['2\n']
Note:
none | ```python
n = int(input())
a = input()
a = a.split(" ")
for i in range(n):
a[i] = int(a[i])
largest = 0
for i in range(n):
for j in range(n):
if a[i] >= a[j]:
t = a[i] % a[j]
if t > largest:
largest = t
print(largest)
``` | 0 | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,694,845,570 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 0 | n=int(input())
a=n/2
if(a%2==0):
print("Yes")
else:
print("No") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.
Input Specification:
The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.
Output Specification:
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.
Demo Input:
['8\n']
Demo Output:
['YES\n']
Note:
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | ```python
n=int(input())
a=n/2
if(a%2==0):
print("Yes")
else:
print("No")
``` | 0 |
1,004 | C | Sonya and Robots | PROGRAMMING | 1,400 | [
"constructive algorithms",
"implementation"
] | null | null | Since Sonya is interested in robotics too, she decided to construct robots that will read and recognize numbers.
Sonya has drawn $n$ numbers in a row, $a_i$ is located in the $i$-th position. She also has put a robot at each end of the row (to the left of the first number and to the right of the last number). Sonya will give a number to each robot (they can be either same or different) and run them. When a robot is running, it is moving toward to another robot, reading numbers in the row. When a robot is reading a number that is equal to the number that was given to that robot, it will turn off and stay in the same position.
Sonya does not want robots to break, so she will give such numbers that robots will stop before they meet. That is, the girl wants them to stop at different positions so that the first robot is to the left of the second one.
For example, if the numbers $[1, 5, 4, 1, 3]$ are written, and Sonya gives the number $1$ to the first robot and the number $4$ to the second one, the first robot will stop in the $1$-st position while the second one in the $3$-rd position. In that case, robots will not meet each other. As a result, robots will not be broken. But if Sonya gives the number $4$ to the first robot and the number $5$ to the second one, they will meet since the first robot will stop in the $3$-rd position while the second one is in the $2$-nd position.
Sonya understands that it does not make sense to give a number that is not written in the row because a robot will not find this number and will meet the other robot.
Sonya is now interested in finding the number of different pairs that she can give to robots so that they will not meet. In other words, she wants to know the number of pairs ($p$, $q$), where she will give $p$ to the first robot and $q$ to the second one. Pairs ($p_i$, $q_i$) and ($p_j$, $q_j$) are different if $p_i\neq p_j$ or $q_i\neq q_j$.
Unfortunately, Sonya is busy fixing robots that broke after a failed launch. That is why she is asking you to find the number of pairs that she can give to robots so that they will not meet. | The first line contains a single integer $n$ ($1\leq n\leq 10^5$) — the number of numbers in a row.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1\leq a_i\leq 10^5$) — the numbers in a row. | Print one number — the number of possible pairs that Sonya can give to robots so that they will not meet. | [
"5\n1 5 4 1 3\n",
"7\n1 2 1 1 1 3 2\n"
] | [
"9\n",
"7\n"
] | In the first example, Sonya can give pairs ($1$, $1$), ($1$, $3$), ($1$, $4$), ($1$, $5$), ($4$, $1$), ($4$, $3$), ($5$, $1$), ($5$, $3$), and ($5$, $4$).
In the second example, Sonya can give pairs ($1$, $1$), ($1$, $2$), ($1$, $3$), ($2$, $1$), ($2$, $2$), ($2$, $3$), and ($3$, $2$). | 1,500 | [
{
"input": "5\n1 5 4 1 3",
"output": "9"
},
{
"input": "7\n1 2 1 1 1 3 2",
"output": "7"
},
{
"input": "10\n2 2 4 4 3 1 1 2 3 2",
"output": "14"
},
{
"input": "15\n1 2 2 1 2 4 2 1 1 6 6 4 2 5 4",
"output": "20"
},
{
"input": "1\n1",
"output": "0"
}
] | 1,531,186,337 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 6,758,400 | t = int(input())
n = [int(i) for i in input().split()]
p = []
for i in range(len(n)):
if i > 0 and n[i] == n[i-1]:
pass
else:
for j in range(i+1,len(n)):
if str('('+str(n[i])+','+str(n[j])+')') in p:
pass
elif i == j:
pass
else:
p += ['('+str(n[i])+','+str(n[j])+')']
print(len(p))
#print(p)
| Title: Sonya and Robots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Sonya is interested in robotics too, she decided to construct robots that will read and recognize numbers.
Sonya has drawn $n$ numbers in a row, $a_i$ is located in the $i$-th position. She also has put a robot at each end of the row (to the left of the first number and to the right of the last number). Sonya will give a number to each robot (they can be either same or different) and run them. When a robot is running, it is moving toward to another robot, reading numbers in the row. When a robot is reading a number that is equal to the number that was given to that robot, it will turn off and stay in the same position.
Sonya does not want robots to break, so she will give such numbers that robots will stop before they meet. That is, the girl wants them to stop at different positions so that the first robot is to the left of the second one.
For example, if the numbers $[1, 5, 4, 1, 3]$ are written, and Sonya gives the number $1$ to the first robot and the number $4$ to the second one, the first robot will stop in the $1$-st position while the second one in the $3$-rd position. In that case, robots will not meet each other. As a result, robots will not be broken. But if Sonya gives the number $4$ to the first robot and the number $5$ to the second one, they will meet since the first robot will stop in the $3$-rd position while the second one is in the $2$-nd position.
Sonya understands that it does not make sense to give a number that is not written in the row because a robot will not find this number and will meet the other robot.
Sonya is now interested in finding the number of different pairs that she can give to robots so that they will not meet. In other words, she wants to know the number of pairs ($p$, $q$), where she will give $p$ to the first robot and $q$ to the second one. Pairs ($p_i$, $q_i$) and ($p_j$, $q_j$) are different if $p_i\neq p_j$ or $q_i\neq q_j$.
Unfortunately, Sonya is busy fixing robots that broke after a failed launch. That is why she is asking you to find the number of pairs that she can give to robots so that they will not meet.
Input Specification:
The first line contains a single integer $n$ ($1\leq n\leq 10^5$) — the number of numbers in a row.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1\leq a_i\leq 10^5$) — the numbers in a row.
Output Specification:
Print one number — the number of possible pairs that Sonya can give to robots so that they will not meet.
Demo Input:
['5\n1 5 4 1 3\n', '7\n1 2 1 1 1 3 2\n']
Demo Output:
['9\n', '7\n']
Note:
In the first example, Sonya can give pairs ($1$, $1$), ($1$, $3$), ($1$, $4$), ($1$, $5$), ($4$, $1$), ($4$, $3$), ($5$, $1$), ($5$, $3$), and ($5$, $4$).
In the second example, Sonya can give pairs ($1$, $1$), ($1$, $2$), ($1$, $3$), ($2$, $1$), ($2$, $2$), ($2$, $3$), and ($3$, $2$). | ```python
t = int(input())
n = [int(i) for i in input().split()]
p = []
for i in range(len(n)):
if i > 0 and n[i] == n[i-1]:
pass
else:
for j in range(i+1,len(n)):
if str('('+str(n[i])+','+str(n[j])+')') in p:
pass
elif i == j:
pass
else:
p += ['('+str(n[i])+','+str(n[j])+')']
print(len(p))
#print(p)
``` | 0 | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,621,874,324 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def solve(s):
target = "heidi"
j = 0
t_len = len(target)
s_len = len(s)
for i in range(0, s_len):
if s[i] == target[j]:
j += 1
if j == t_len:
break
return "YES" if j == t_len else "NO"
if __name__ == "__main__":
s = raw_input()
print solve(s) | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input Specification:
The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z).
Output Specification:
Output YES if the string *s* contains heidi as a subsequence and NO otherwise.
Demo Input:
['abcheaibcdi\n', 'hiedi\n']
Demo Output:
['YES', 'NO']
Note:
A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | ```python
def solve(s):
target = "heidi"
j = 0
t_len = len(target)
s_len = len(s)
for i in range(0, s_len):
if s[i] == target[j]:
j += 1
if j == t_len:
break
return "YES" if j == t_len else "NO"
if __name__ == "__main__":
s = raw_input()
print solve(s)
``` | -1 | |
678 | D | Iterated Linear Function | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7. | The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7. | [
"3 4 1 1\n",
"3 4 2 1\n",
"3 4 3 1\n"
] | [
"7\n",
"25\n",
"79\n"
] | none | 0 | [
{
"input": "3 4 1 1",
"output": "7"
},
{
"input": "3 4 2 1",
"output": "25"
},
{
"input": "3 4 3 1",
"output": "79"
},
{
"input": "1 1 1 1",
"output": "2"
},
{
"input": "3 10 723 6",
"output": "443623217"
},
{
"input": "14 81 51 82",
"output": "908... | 1,553,372,165 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 78 | 0 | import sys
#826144502
def main():
for line in sys.stdin:
line = line.split()
A = int(line[0])
B = int(line[1])
n = int(line[2])
x = int(line[3])
# ans = x
# for i in range(n):
# ans = (A*ans + B)%1000000007
# print(ans)
big = A**n
term = ((big-1)//(A-1))%1000000007
bterm = x*big%1000000007
ans = (B*term+bterm)%1000000007
print(ans)
if __name__ == "__main__":
main() | Title: Iterated Linear Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7.
Input Specification:
The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output Specification:
Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7.
Demo Input:
['3 4 1 1\n', '3 4 2 1\n', '3 4 3 1\n']
Demo Output:
['7\n', '25\n', '79\n']
Note:
none | ```python
import sys
#826144502
def main():
for line in sys.stdin:
line = line.split()
A = int(line[0])
B = int(line[1])
n = int(line[2])
x = int(line[3])
# ans = x
# for i in range(n):
# ans = (A*ans + B)%1000000007
# print(ans)
big = A**n
term = ((big-1)//(A-1))%1000000007
bterm = x*big%1000000007
ans = (B*term+bterm)%1000000007
print(ans)
if __name__ == "__main__":
main()
``` | -1 | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem. | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,558,806,047 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 1,024,000 | s = input()
d = set()
for i in range(ord('a'), ord('z') + 1):
for j in range(len(s)):
d.add(s[:j] + i + s[j:])
print(len(d)) | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input Specification:
The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters.
Output Specification:
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Demo Input:
['a\n', 'hi\n']
Demo Output:
['51\n', '76\n']
Note:
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | ```python
s = input()
d = set()
for i in range(ord('a'), ord('z') + 1):
for j in range(len(s)):
d.add(s[:j] + i + s[j:])
print(len(d))
``` | -1 | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light. | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,695,855,825 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | def lights_out():
grid = [[1, 1, 1], [1, 1, 1], [1, 1, 1]]
directions = [(0, 0), (0, 1), (0, -1), (1, 0), (-1, 0)]
presses = [list(map(int, input().split())) for _ in range(3)]
for i in range(3):
for j in range(3):
total_presses = 0
for dx, dy in directions:
x, y = i + dx, j + dy
if 0 <= x < 3 and 0 <= y < 3:
total_presses += presses[x][y]
grid[i][j] = (total_presses + 1) % 2
for row in grid:
print(''.join(map(str, row)))
lights_out() | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light.
Input Specification:
The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed.
Output Specification:
Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0".
Demo Input:
['1 0 0\n0 0 0\n0 0 1\n', '1 0 1\n8 8 8\n2 0 3\n']
Demo Output:
['001\n010\n100\n', '010\n011\n100\n']
Note:
none | ```python
def lights_out():
grid = [[1, 1, 1], [1, 1, 1], [1, 1, 1]]
directions = [(0, 0), (0, 1), (0, -1), (1, 0), (-1, 0)]
presses = [list(map(int, input().split())) for _ in range(3)]
for i in range(3):
for j in range(3):
total_presses = 0
for dx, dy in directions:
x, y = i + dx, j + dy
if 0 <= x < 3 and 0 <= y < 3:
total_presses += presses[x][y]
grid[i][j] = (total_presses + 1) % 2
for row in grid:
print(''.join(map(str, row)))
lights_out()
``` | 3 | |
932 | B | Recursive Queries | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"dfs and similar"
] | null | null | Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*)<==<=*k*. | The first line of the input contains an integer *Q* (1<=≤<=*Q*<=≤<=2<=×<=105) representing the number of queries.
*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=106,<=1<=≤<=*k*<=≤<=9). | For each query, print a single line containing the answer for that query. | [
"4\n22 73 9\n45 64 6\n47 55 7\n2 62 4\n",
"4\n82 94 6\n56 67 4\n28 59 9\n39 74 4\n"
] | [
"1\n4\n0\n8\n",
"3\n1\n1\n5\n"
] | In the first example:
- *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 - *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 - There are no such integers between 47 and 55. - *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4 | 1,000 | [
{
"input": "4\n22 73 9\n45 64 6\n47 55 7\n2 62 4",
"output": "1\n4\n0\n8"
},
{
"input": "4\n82 94 6\n56 67 4\n28 59 9\n39 74 4",
"output": "3\n1\n1\n5"
}
] | 1,580,711,877 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 52,838,400 | # maa chudaaye duniya
def get_product(a):
arr = [int(i) for i in str(a)]
s = arr[0]
for i in range(1, len(arr)):
if arr[i] != 0:
s *= arr[i]
return s
checker = [[0 for i in range(10**6+3)] for j in range(11)]
for _ in range(1, 10**6+3):
x = get_product(_)
while len(str(x)) != 1:
x = get_product(x)
for ptr in range(1, 10):
if ptr != x:
checker[ptr][_] = checker[ptr][_-1]
else:
checker[ptr][_] = checker[ptr][_-1] + 1
for _ in range(int(input())):
l, r, k = map(int, input().split())
print(checker[k][r] - checker[k][l])
| Title: Recursive Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*)<==<=*k*.
Input Specification:
The first line of the input contains an integer *Q* (1<=≤<=*Q*<=≤<=2<=×<=105) representing the number of queries.
*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=106,<=1<=≤<=*k*<=≤<=9).
Output Specification:
For each query, print a single line containing the answer for that query.
Demo Input:
['4\n22 73 9\n45 64 6\n47 55 7\n2 62 4\n', '4\n82 94 6\n56 67 4\n28 59 9\n39 74 4\n']
Demo Output:
['1\n4\n0\n8\n', '3\n1\n1\n5\n']
Note:
In the first example:
- *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 - *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 - There are no such integers between 47 and 55. - *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4 | ```python
# maa chudaaye duniya
def get_product(a):
arr = [int(i) for i in str(a)]
s = arr[0]
for i in range(1, len(arr)):
if arr[i] != 0:
s *= arr[i]
return s
checker = [[0 for i in range(10**6+3)] for j in range(11)]
for _ in range(1, 10**6+3):
x = get_product(_)
while len(str(x)) != 1:
x = get_product(x)
for ptr in range(1, 10):
if ptr != x:
checker[ptr][_] = checker[ptr][_-1]
else:
checker[ptr][_] = checker[ptr][_-1] + 1
for _ in range(int(input())):
l, r, k = map(int, input().split())
print(checker[k][r] - checker[k][l])
``` | 0 | |
1,011 | A | Stages | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are $n$ stages available. The rocket must contain exactly $k$ of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'.
For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — $26$ tons.
Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once. | The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket.
The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once. | Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all. | [
"5 3\nxyabd\n",
"7 4\nproblem\n",
"2 2\nab\n",
"12 1\nabaabbaaabbb\n"
] | [
"29",
"34",
"-1",
"1"
] | In the first example, the following rockets satisfy the condition:
- "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$).
Rocket "adx" has the minimal weight, so the answer is $29$.
In the second example, target rocket is "belo". Its weight is $2+5+12+15=34$.
In the third example, $n=k=2$, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1. | 500 | [
{
"input": "5 3\nxyabd",
"output": "29"
},
{
"input": "7 4\nproblem",
"output": "34"
},
{
"input": "2 2\nab",
"output": "-1"
},
{
"input": "12 1\nabaabbaaabbb",
"output": "1"
},
{
"input": "50 13\nqwertyuiopasdfghjklzxcvbnmaaaaaaaaaaaaaaaaaaaaaaaa",
"output": ... | 1,624,004,964 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 139 | 512,000 | from sys import maxsize, stdout, stdin,stderr
mod = int(1e9 + 7)
import sys
def I(): return int(stdin.readline())
def lint(): return [int(x) for x in stdin.readline().split()]
def S(): return input().strip()
def grid(r, c): return [lint() for i in range(r)]
from collections import defaultdict, Counter
import math
import heapq
from heapq import heappop , heappush
import bisect
from itertools import groupby
def gcd(a,b):
while b:
a %= b
tmp = a
a = b
b = tmp
return a
def lcm(a,b):
return a / gcd(a, b) * b
def check_prime(n):
for i in range(2, int(n ** (1 / 2)) + 1):
if not n % i:
return False
return True
def Bs(a, x):
i=0
j=0
left = 0
right = len(a)
flag=False
while left<right:
mi = (left+right)//2
#print(smi,a[mi],x)
if a[mi]<=x:
left = mi+1
i+=1
else:
right = mi
j+=1
#print(left,right,"----")
#print(i-1,j)
if left>0 and a[left-1]==x:
return i-1, j
else:
return -1, -1
def nCr(n, r):
return (fact(n) // (fact(r)
* fact(n - r)))
# Returns factorial of n
def fact(n):
res = 1
for i in range(2, n+1):
res = res * i
return res
def primefactors(n):
num=0
while n % 2 == 0:
num+=1
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
num+=1
n = n // i
if n > 2:
num+=1
return num
'''
def iter_ds(src):
store=[src]
while len(store):
tmp=store.pop()
if not vis[tmp]:
vis[tmp]=True
for j in ar[tmp]:
store.append(j)
'''
def ask(a):
print('? {}'.format(a),flush=True)
n=lint()
return n
def dfs(i,p):
a,tmp=0,0
for j in d[i]:
if j!=p:
a+=1
tmp+=dfs(j,i)
if a==0:
return 0
return tmp/a + 1
n,k=lint()
s = [ord(i) for i in input().strip()]
s.sort()
ans=s[0]-96
l=s[0]
k-=1
for i in range(1,n):
if k==0:
break
if s[i]-l>=2:
ans+=s[i]-96
l=s[i]
k-=1
if k>0:
print(-1)
else:
print(ans)
| Title: Stages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are $n$ stages available. The rocket must contain exactly $k$ of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'.
For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — $26$ tons.
Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once.
Input Specification:
The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket.
The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once.
Output Specification:
Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all.
Demo Input:
['5 3\nxyabd\n', '7 4\nproblem\n', '2 2\nab\n', '12 1\nabaabbaaabbb\n']
Demo Output:
['29', '34', '-1', '1']
Note:
In the first example, the following rockets satisfy the condition:
- "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$).
Rocket "adx" has the minimal weight, so the answer is $29$.
In the second example, target rocket is "belo". Its weight is $2+5+12+15=34$.
In the third example, $n=k=2$, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1. | ```python
from sys import maxsize, stdout, stdin,stderr
mod = int(1e9 + 7)
import sys
def I(): return int(stdin.readline())
def lint(): return [int(x) for x in stdin.readline().split()]
def S(): return input().strip()
def grid(r, c): return [lint() for i in range(r)]
from collections import defaultdict, Counter
import math
import heapq
from heapq import heappop , heappush
import bisect
from itertools import groupby
def gcd(a,b):
while b:
a %= b
tmp = a
a = b
b = tmp
return a
def lcm(a,b):
return a / gcd(a, b) * b
def check_prime(n):
for i in range(2, int(n ** (1 / 2)) + 1):
if not n % i:
return False
return True
def Bs(a, x):
i=0
j=0
left = 0
right = len(a)
flag=False
while left<right:
mi = (left+right)//2
#print(smi,a[mi],x)
if a[mi]<=x:
left = mi+1
i+=1
else:
right = mi
j+=1
#print(left,right,"----")
#print(i-1,j)
if left>0 and a[left-1]==x:
return i-1, j
else:
return -1, -1
def nCr(n, r):
return (fact(n) // (fact(r)
* fact(n - r)))
# Returns factorial of n
def fact(n):
res = 1
for i in range(2, n+1):
res = res * i
return res
def primefactors(n):
num=0
while n % 2 == 0:
num+=1
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
num+=1
n = n // i
if n > 2:
num+=1
return num
'''
def iter_ds(src):
store=[src]
while len(store):
tmp=store.pop()
if not vis[tmp]:
vis[tmp]=True
for j in ar[tmp]:
store.append(j)
'''
def ask(a):
print('? {}'.format(a),flush=True)
n=lint()
return n
def dfs(i,p):
a,tmp=0,0
for j in d[i]:
if j!=p:
a+=1
tmp+=dfs(j,i)
if a==0:
return 0
return tmp/a + 1
n,k=lint()
s = [ord(i) for i in input().strip()]
s.sort()
ans=s[0]-96
l=s[0]
k-=1
for i in range(1,n):
if k==0:
break
if s[i]-l>=2:
ans+=s[i]-96
l=s[i]
k-=1
if k>0:
print(-1)
else:
print(ans)
``` | 3 | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,472,482,442 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 154 | 0 | import sys
n, m = map(int, sys.stdin.readline().split())
print(n+m-1)
for i in range(m):
print(1, i+1)
for i in range(1, n):
print(i+1, 1)
| Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room.
Output Specification:
In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*.
Demo Input:
['2 1\n', '2 2\n']
Demo Output:
['2\n1 1\n2 1\n', '3\n1 1\n1 2\n2 2\n']
Note:
In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | ```python
import sys
n, m = map(int, sys.stdin.readline().split())
print(n+m-1)
for i in range(m):
print(1, i+1)
for i in range(1, n):
print(i+1, 1)
``` | 3 | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,625,061,859 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | n=int(input())
s=input()
temp=[]
c=0
for i in s:
if i==" ":
c+=1
temp.append(i)
if c==2:
break
c=0
for i in temp:
if 65<=ord(i)<=90:
c+=1
print(c) | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text.
Input Specification:
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters.
Output Specification:
Print one integer number — volume of text.
Demo Input:
['7\nNonZERO\n', '24\nthis is zero answer text\n', '24\nHarbour Space University\n']
Demo Output:
['5\n', '0\n', '1\n']
Note:
In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | ```python
n=int(input())
s=input()
temp=[]
c=0
for i in s:
if i==" ":
c+=1
temp.append(i)
if c==2:
break
c=0
for i in temp:
if 65<=ord(i)<=90:
c+=1
print(c)
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,666,562,394 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | m, n, a = map(int, input().split())
soma = 0
if a >= m and a >= n:
soma = 1
else:
if m % a != 0:
soma += m//a + 1
else:
soma += m//a
if n % a != 0:
soma += n//a + 1
else:
soma += n//a
print(soma) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
m, n, a = map(int, input().split())
soma = 0
if a >= m and a >= n:
soma = 1
else:
if m % a != 0:
soma += m//a + 1
else:
soma += m//a
if n % a != 0:
soma += n//a + 1
else:
soma += n//a
print(soma)
``` | 0 |
804 | D | Expected diameter of a tree | PROGRAMMING | 2,500 | [
"binary search",
"brute force",
"dfs and similar",
"dp",
"sortings",
"trees"
] | null | null | Pasha is a good student and one of MoJaK's best friends. He always have a problem to think about. Today they had a talk about the following problem.
We have a forest (acyclic undirected graph) with *n* vertices and *m* edges. There are *q* queries we should answer. In each query two vertices *v* and *u* are given. Let *V* be the set of vertices in the connected component of the graph that contains *v*, and *U* be the set of vertices in the connected component of the graph that contains *u*. Let's add an edge between some vertex and some vertex in and compute the value *d* of the resulting component. If the resulting component is a tree, the value *d* is the diameter of the component, and it is equal to -1 otherwise. What is the expected value of *d*, if we choose vertices *a* and *b* from the sets uniformly at random?
Can you help Pasha to solve this problem?
The diameter of the component is the maximum distance among some pair of vertices in the component. The distance between two vertices is the minimum number of edges on some path between the two vertices.
Note that queries don't add edges to the initial forest. | The first line contains three integers *n*, *m* and *q*(1<=≤<=*n*,<=*m*,<=*q*<=≤<=105) — the number of vertices, the number of edges in the graph and the number of queries.
Each of the next *m* lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*), that means there is an edge between vertices *u**i* and *v**i*.
It is guaranteed that the given graph is a forest.
Each of the next *q* lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*) — the vertices given in the *i*-th query. | For each query print the expected value of *d* as described in the problem statement.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6. Let's assume that your answer is *a*, and the jury's answer is *b*. The checker program will consider your answer correct, if . | [
"3 1 2\n1 3\n3 1\n2 3\n",
"5 2 3\n2 4\n4 3\n4 2\n4 1\n2 5\n"
] | [
"-1\n2.0000000000\n",
"-1\n2.6666666667\n2.6666666667\n"
] | In the first example the vertices 1 and 3 are in the same component, so the answer for the first query is -1. For the second query there are two options to add the edge: one option is to add the edge 1 - 2, the other one is 2 - 3. In both ways the resulting diameter is 2, so the answer is 2.
In the second example the answer for the first query is obviously -1. The answer for the second query is the average of three cases: for added edges 1 - 2 or 1 - 3 the diameter is 3, and for added edge 1 - 4 the diameter is 2. Thus, the answer is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f12c59a7dfd20580ff1e8e5eeab9ecd19cb3c3f1.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 2,000 | [
{
"input": "3 1 2\n1 3\n3 1\n2 3",
"output": "-1\n2.0000000000"
},
{
"input": "5 2 3\n2 4\n4 3\n4 2\n4 1\n2 5",
"output": "-1\n2.6666666667\n2.6666666667"
},
{
"input": "17 15 13\n3 15\n3 1\n15 9\n16 6\n1 5\n1 8\n16 12\n15 7\n9 4\n6 11\n15 14\n9 10\n15 13\n1 17\n11 2\n7 3\n9 6\n9 7\n1 8\... | 1,554,028,923 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 1,331,200 | from math import inf, isinf
from time import time
with open('/home/alex/test3.txt', 'r') as f:
data = f.readlines()
counter = 0
def input():
global counter
counter += 1
ans = data[counter-1]
return ans
n, m, q = [int(x) for x in input().split(' ')]
distance = {}
answers = []
max_distance = -1
num_max_distance = 0
def insert(a, b, value):
if a not in distance:
distance[a] = {}
if isinf(value):
distance[a][b] = None
else:
distance[a][b] = value
def get(a, b):
if a in distance and b in distance[a]:
return distance[a][b]
else:
return inf
for i in range(m):
a,b = [int(x)-1 for x in input().split(' ')]
insert(a,b,1)
insert(b,a,1)
for i in set(distance[a].keys()).union(set(distance[b].keys())):
insert(a, i, min(get(a, i), get(b, i) + 1))
insert(i, b, min(get(i, b), get(i, a) + 1))
insert(i, a, min(get(i, a), get(i, b) + 1))
insert(b, i, min(get(b, i), get(a, i) + 1))
for i in range(n):
insert(i,i,0)
paint = [i for i in range(n)]
colour_groups = {}
for i in distance:
if paint[i] == i:
colour_groups[paint[i]] = []
for j in distance[i]:
paint[j] = paint[i]
colour_groups[paint[i]].append(j)
max_size = [max(distance[i].values()) for i in range(n)]
colour_group_min_size = {}
for c, v in colour_groups.items():
colour_group_min_size[c] = max([max_size[i] for i in v])
for i in range(q):
a,b = [int(x)-1 for x in input().split(' ')]
if get(a, b) < inf or get(b,a) < inf:
answers.append(-1)
else:
paint_a = paint[a]
paint_b = paint[b]
group_a = colour_groups[paint_a]
group_b = colour_groups[paint_b]
new_sizes = []
for point_a in group_a:
for point_b in group_b:
new_sizes.append(max([
colour_group_min_size[paint_a],
colour_group_min_size[paint_b],
max_size[point_a] + max_size[point_b] + 1
]))
answers.append(sum(new_sizes)/len(new_sizes))
for a in answers:
print(a)
| Title: Expected diameter of a tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha is a good student and one of MoJaK's best friends. He always have a problem to think about. Today they had a talk about the following problem.
We have a forest (acyclic undirected graph) with *n* vertices and *m* edges. There are *q* queries we should answer. In each query two vertices *v* and *u* are given. Let *V* be the set of vertices in the connected component of the graph that contains *v*, and *U* be the set of vertices in the connected component of the graph that contains *u*. Let's add an edge between some vertex and some vertex in and compute the value *d* of the resulting component. If the resulting component is a tree, the value *d* is the diameter of the component, and it is equal to -1 otherwise. What is the expected value of *d*, if we choose vertices *a* and *b* from the sets uniformly at random?
Can you help Pasha to solve this problem?
The diameter of the component is the maximum distance among some pair of vertices in the component. The distance between two vertices is the minimum number of edges on some path between the two vertices.
Note that queries don't add edges to the initial forest.
Input Specification:
The first line contains three integers *n*, *m* and *q*(1<=≤<=*n*,<=*m*,<=*q*<=≤<=105) — the number of vertices, the number of edges in the graph and the number of queries.
Each of the next *m* lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*), that means there is an edge between vertices *u**i* and *v**i*.
It is guaranteed that the given graph is a forest.
Each of the next *q* lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*) — the vertices given in the *i*-th query.
Output Specification:
For each query print the expected value of *d* as described in the problem statement.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6. Let's assume that your answer is *a*, and the jury's answer is *b*. The checker program will consider your answer correct, if .
Demo Input:
['3 1 2\n1 3\n3 1\n2 3\n', '5 2 3\n2 4\n4 3\n4 2\n4 1\n2 5\n']
Demo Output:
['-1\n2.0000000000\n', '-1\n2.6666666667\n2.6666666667\n']
Note:
In the first example the vertices 1 and 3 are in the same component, so the answer for the first query is -1. For the second query there are two options to add the edge: one option is to add the edge 1 - 2, the other one is 2 - 3. In both ways the resulting diameter is 2, so the answer is 2.
In the second example the answer for the first query is obviously -1. The answer for the second query is the average of three cases: for added edges 1 - 2 or 1 - 3 the diameter is 3, and for added edge 1 - 4 the diameter is 2. Thus, the answer is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f12c59a7dfd20580ff1e8e5eeab9ecd19cb3c3f1.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | ```python
from math import inf, isinf
from time import time
with open('/home/alex/test3.txt', 'r') as f:
data = f.readlines()
counter = 0
def input():
global counter
counter += 1
ans = data[counter-1]
return ans
n, m, q = [int(x) for x in input().split(' ')]
distance = {}
answers = []
max_distance = -1
num_max_distance = 0
def insert(a, b, value):
if a not in distance:
distance[a] = {}
if isinf(value):
distance[a][b] = None
else:
distance[a][b] = value
def get(a, b):
if a in distance and b in distance[a]:
return distance[a][b]
else:
return inf
for i in range(m):
a,b = [int(x)-1 for x in input().split(' ')]
insert(a,b,1)
insert(b,a,1)
for i in set(distance[a].keys()).union(set(distance[b].keys())):
insert(a, i, min(get(a, i), get(b, i) + 1))
insert(i, b, min(get(i, b), get(i, a) + 1))
insert(i, a, min(get(i, a), get(i, b) + 1))
insert(b, i, min(get(b, i), get(a, i) + 1))
for i in range(n):
insert(i,i,0)
paint = [i for i in range(n)]
colour_groups = {}
for i in distance:
if paint[i] == i:
colour_groups[paint[i]] = []
for j in distance[i]:
paint[j] = paint[i]
colour_groups[paint[i]].append(j)
max_size = [max(distance[i].values()) for i in range(n)]
colour_group_min_size = {}
for c, v in colour_groups.items():
colour_group_min_size[c] = max([max_size[i] for i in v])
for i in range(q):
a,b = [int(x)-1 for x in input().split(' ')]
if get(a, b) < inf or get(b,a) < inf:
answers.append(-1)
else:
paint_a = paint[a]
paint_b = paint[b]
group_a = colour_groups[paint_a]
group_b = colour_groups[paint_b]
new_sizes = []
for point_a in group_a:
for point_b in group_b:
new_sizes.append(max([
colour_group_min_size[paint_a],
colour_group_min_size[paint_b],
max_size[point_a] + max_size[point_b] + 1
]))
answers.append(sum(new_sizes)/len(new_sizes))
for a in answers:
print(a)
``` | -1 | |
39 | D | Cubical Planet | PROGRAMMING | 1,100 | [
"math"
] | D. Cubical Planet | 2 | 64 | You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite vertices lay in the points (0,<=0,<=0) and (1,<=1,<=1). Two flies live on the planet. At the moment they are sitting on two different vertices of the cubical planet. Your task is to determine whether they see each other or not. The flies see each other when the vertices they occupy lie on the same face of the cube. | The first line contains three space-separated integers (0 or 1) — the coordinates of the first fly, the second line analogously contains the coordinates of the second fly. | Output "YES" (without quotes) if the flies see each other. Otherwise, output "NO". | [
"0 0 0\n0 1 0\n",
"1 1 0\n0 1 0\n",
"0 0 0\n1 1 1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "1 1 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 1",
"output": "NO"
},
{
"input": "0 0 0\n1 0 0",
"output": "YES"
},
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 ... | 1,554,650,808 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 248 | 0 | A1 = list(map(int, input().split()))
A2 = list(map(int, input().split()))
ans = False
for i in range(0, 3):
ans |= A1[i] == A2[i]
if ans:
print("YES")
else:
print("NO") | Title: Cubical Planet
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite vertices lay in the points (0,<=0,<=0) and (1,<=1,<=1). Two flies live on the planet. At the moment they are sitting on two different vertices of the cubical planet. Your task is to determine whether they see each other or not. The flies see each other when the vertices they occupy lie on the same face of the cube.
Input Specification:
The first line contains three space-separated integers (0 or 1) — the coordinates of the first fly, the second line analogously contains the coordinates of the second fly.
Output Specification:
Output "YES" (without quotes) if the flies see each other. Otherwise, output "NO".
Demo Input:
['0 0 0\n0 1 0\n', '1 1 0\n0 1 0\n', '0 0 0\n1 1 1\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
none | ```python
A1 = list(map(int, input().split()))
A2 = list(map(int, input().split()))
ans = False
for i in range(0, 3):
ans |= A1[i] == A2[i]
if ans:
print("YES")
else:
print("NO")
``` | 3.938 |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days? | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,664,491,045 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | x=int(input())
if(x%2==0):
print("1")
elif(x==1):
print("1")
else:
print("2")
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days?
Input Specification:
The only line containing one integer *x* (1<=≤<=*x*<=≤<=109).
Output Specification:
The only line containing one integer: the answer.
Demo Input:
['5\n', '8\n']
Demo Output:
['2\n', '1\n']
Note:
For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | ```python
x=int(input())
if(x%2==0):
print("1")
elif(x==1):
print("1")
else:
print("2")
``` | -1 | |
343 | B | Alternating Current | PROGRAMMING | 1,600 | [
"data structures",
"greedy",
"implementation"
] | null | null | Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended up entangled and now have to be untangled again.
The device is powered by two wires "plus" and "minus". The wires run along the floor from the wall (on the left) to the device (on the right). Both the wall and the device have two contacts in them on the same level, into which the wires are plugged in some order. The wires are considered entangled if there are one or more places where one wire runs above the other one. For example, the picture below has four such places (top view):
Mike knows the sequence in which the wires run above each other. Mike also noticed that on the left side, the "plus" wire is always plugged into the top contact (as seen on the picture). He would like to untangle the wires without unplugging them and without moving the device. Determine if it is possible to do that. A wire can be freely moved and stretched on the floor, but cannot be cut.
To understand the problem better please read the notes to the test samples. | The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise. | Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled. | [
"-++-\n",
"+-\n",
"++\n",
"-\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"No\n"
] | The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full revolution around the "minus" wire. Thus the wires cannot be untangled:
In the third testcase the "plus" wire simply runs above the "minus" wire twice in sequence. The wires can be untangled by lifting "plus" and moving it higher:
In the fourth testcase the "minus" wire runs above the "plus" wire once. The wires cannot be untangled without moving the device itself: | 1,000 | [
{
"input": "-++-",
"output": "Yes"
},
{
"input": "+-",
"output": "No"
},
{
"input": "++",
"output": "Yes"
},
{
"input": "-",
"output": "No"
},
{
"input": "+-+-",
"output": "No"
},
{
"input": "-+-",
"output": "No"
},
{
"input": "-++-+--+",
... | 1,582,305,725 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 280 | 1,024,000 | current = input()
st = []
for i in current:
if not st:
st.append(i)
elif st[-1] == i:
st.pop()
else:
st.append(i)
if not st:
print("Yes")
else:
print("No") | Title: Alternating Current
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended up entangled and now have to be untangled again.
The device is powered by two wires "plus" and "minus". The wires run along the floor from the wall (on the left) to the device (on the right). Both the wall and the device have two contacts in them on the same level, into which the wires are plugged in some order. The wires are considered entangled if there are one or more places where one wire runs above the other one. For example, the picture below has four such places (top view):
Mike knows the sequence in which the wires run above each other. Mike also noticed that on the left side, the "plus" wire is always plugged into the top contact (as seen on the picture). He would like to untangle the wires without unplugging them and without moving the device. Determine if it is possible to do that. A wire can be freely moved and stretched on the floor, but cannot be cut.
To understand the problem better please read the notes to the test samples.
Input Specification:
The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise.
Output Specification:
Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled.
Demo Input:
['-++-\n', '+-\n', '++\n', '-\n']
Demo Output:
['Yes\n', 'No\n', 'Yes\n', 'No\n']
Note:
The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full revolution around the "minus" wire. Thus the wires cannot be untangled:
In the third testcase the "plus" wire simply runs above the "minus" wire twice in sequence. The wires can be untangled by lifting "plus" and moving it higher:
In the fourth testcase the "minus" wire runs above the "plus" wire once. The wires cannot be untangled without moving the device itself: | ```python
current = input()
st = []
for i in current:
if not st:
st.append(i)
elif st[-1] == i:
st.pop()
else:
st.append(i)
if not st:
print("Yes")
else:
print("No")
``` | 3 | |
172 | D | Calendar Reform | PROGRAMMING | 1,500 | [
"*special",
"number theory"
] | null | null | Reforms have started in Berland again! At this time, the Parliament is discussing the reform of the calendar. To make the lives of citizens of Berland more varied, it was decided to change the calendar. As more and more people are complaining that "the years fly by...", it was decided that starting from the next year the number of days per year will begin to grow. So the coming year will have exactly *a* days, the next after coming year will have *a*<=+<=1 days, the next one will have *a*<=+<=2 days and so on. This schedule is planned for the coming *n* years (in the *n*-th year the length of the year will be equal *a*<=+<=*n*<=-<=1 day).
No one has yet decided what will become of months. An MP Palevny made the following proposal.
- The calendar for each month is comfortable to be printed on a square sheet of paper. We are proposed to make the number of days in each month be the square of some integer. The number of days per month should be the same for each month of any year, but may be different for different years. - The number of days in each year must be divisible by the number of days per month in this year. This rule ensures that the number of months in each year is an integer. - The number of days per month for each year must be chosen so as to save the maximum amount of paper to print the calendars. In other words, the number of days per month should be as much as possible.
These rules provide an unambiguous method for choosing the number of days in each month for any given year length. For example, according to Palevny's proposition, a year that consists of 108 days will have three months, 36 days each. The year that consists of 99 days will have 11 months, 9 days each, and a year of 365 days will have 365 months, one day each.
The proposal provoked heated discussion in the community, the famous mathematician Perelmanov quickly calculated that if the proposal is supported, then in a period of *n* years, beginning with the year that has *a* days, the country will spend *p* sheets of paper to print a set of calendars for these years. Perelmanov's calculations take into account the fact that the set will contain one calendar for each year and each month will be printed on a separate sheet.
Repeat Perelmanov's achievement and print the required number *p*. You are given positive integers *a* and *n*. Perelmanov warns you that your program should not work longer than four seconds at the maximum test. | The only input line contains a pair of integers *a*, *n* (1<=≤<=*a*,<=*n*<=≤<=107; *a*<=+<=*n*<=-<=1<=≤<=107). | Print the required number *p*.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"25 3\n",
"50 5\n"
] | [
"30\n",
"125\n"
] | A note to the first sample test. A year of 25 days will consist of one month containing 25 days. A year of 26 days will consist of 26 months, one day each. A year of 27 days will have three months, 9 days each. | 1,500 | [
{
"input": "25 3",
"output": "30"
},
{
"input": "50 5",
"output": "125"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "3"
},
{
"input": "1 10",
"output": "38"
},
{
"input": "1 5000000",
"output": "8224640917276"
},
{
"in... | 1,598,966,166 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 3,072,000 | def isq(a):
return int(pow(a, 0.5))**2 == a
def F(a):
d = 1
i = 1
while(i*i <= a):
if(a % i == 0):
if(isq(i)):
d = max(d, i)
if(isq(a // i)):
d = max(d, a // i)
i += 1
return a // d
def main():
a, n = [int(i) for i in input().split()]
ans = 0
for i in range(n):
ans += F(a + i)
print(ans)
main() | Title: Calendar Reform
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Reforms have started in Berland again! At this time, the Parliament is discussing the reform of the calendar. To make the lives of citizens of Berland more varied, it was decided to change the calendar. As more and more people are complaining that "the years fly by...", it was decided that starting from the next year the number of days per year will begin to grow. So the coming year will have exactly *a* days, the next after coming year will have *a*<=+<=1 days, the next one will have *a*<=+<=2 days and so on. This schedule is planned for the coming *n* years (in the *n*-th year the length of the year will be equal *a*<=+<=*n*<=-<=1 day).
No one has yet decided what will become of months. An MP Palevny made the following proposal.
- The calendar for each month is comfortable to be printed on a square sheet of paper. We are proposed to make the number of days in each month be the square of some integer. The number of days per month should be the same for each month of any year, but may be different for different years. - The number of days in each year must be divisible by the number of days per month in this year. This rule ensures that the number of months in each year is an integer. - The number of days per month for each year must be chosen so as to save the maximum amount of paper to print the calendars. In other words, the number of days per month should be as much as possible.
These rules provide an unambiguous method for choosing the number of days in each month for any given year length. For example, according to Palevny's proposition, a year that consists of 108 days will have three months, 36 days each. The year that consists of 99 days will have 11 months, 9 days each, and a year of 365 days will have 365 months, one day each.
The proposal provoked heated discussion in the community, the famous mathematician Perelmanov quickly calculated that if the proposal is supported, then in a period of *n* years, beginning with the year that has *a* days, the country will spend *p* sheets of paper to print a set of calendars for these years. Perelmanov's calculations take into account the fact that the set will contain one calendar for each year and each month will be printed on a separate sheet.
Repeat Perelmanov's achievement and print the required number *p*. You are given positive integers *a* and *n*. Perelmanov warns you that your program should not work longer than four seconds at the maximum test.
Input Specification:
The only input line contains a pair of integers *a*, *n* (1<=≤<=*a*,<=*n*<=≤<=107; *a*<=+<=*n*<=-<=1<=≤<=107).
Output Specification:
Print the required number *p*.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use cin, cout streams or the %I64d specifier.
Demo Input:
['25 3\n', '50 5\n']
Demo Output:
['30\n', '125\n']
Note:
A note to the first sample test. A year of 25 days will consist of one month containing 25 days. A year of 26 days will consist of 26 months, one day each. A year of 27 days will have three months, 9 days each. | ```python
def isq(a):
return int(pow(a, 0.5))**2 == a
def F(a):
d = 1
i = 1
while(i*i <= a):
if(a % i == 0):
if(isq(i)):
d = max(d, i)
if(isq(a // i)):
d = max(d, a // i)
i += 1
return a // d
def main():
a, n = [int(i) for i in input().split()]
ans = 0
for i in range(n):
ans += F(a + i)
print(ans)
main()
``` | 0 | |
276 | B | Little Girl and Game | PROGRAMMING | 1,300 | [
"games",
"greedy"
] | null | null | The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string *s*, consisting of lowercase English letters. They play a game that is described by the following rules:
- The players move in turns; In one move the player can remove an arbitrary letter from string *s*. - If the player before his turn can reorder the letters in string *s* so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well — the one who moves first or the one who moves second. | The input contains a single line, containing string *s* (1<=≤<=|*s*|<=<=≤<=<=103). String *s* consists of lowercase English letters. | In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes. | [
"aba\n",
"abca\n"
] | [
"First\n",
"Second\n"
] | none | 1,000 | [
{
"input": "aba",
"output": "First"
},
{
"input": "abca",
"output": "Second"
},
{
"input": "aabb",
"output": "First"
},
{
"input": "ctjxzuimsxnarlciuynqeoqmmbqtagszuo",
"output": "Second"
},
{
"input": "gevqgtaorjixsxnbcoybr",
"output": "First"
},
{
"i... | 1,670,730,130 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | a=input()
b=a[::-1]
if(a==b):
print("First")
elif(len(a)%2==0):
print("Second")
else:
print("First") | Title: Little Girl and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string *s*, consisting of lowercase English letters. They play a game that is described by the following rules:
- The players move in turns; In one move the player can remove an arbitrary letter from string *s*. - If the player before his turn can reorder the letters in string *s* so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well — the one who moves first or the one who moves second.
Input Specification:
The input contains a single line, containing string *s* (1<=≤<=|*s*|<=<=≤<=<=103). String *s* consists of lowercase English letters.
Output Specification:
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Demo Input:
['aba\n', 'abca\n']
Demo Output:
['First\n', 'Second\n']
Note:
none | ```python
a=input()
b=a[::-1]
if(a==b):
print("First")
elif(len(a)%2==0):
print("Second")
else:
print("First")
``` | 0 | |
5 | C | Longest Regular Bracket Sequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"data structures",
"dp",
"greedy",
"sortings",
"strings"
] | C. Longest Regular Bracket Sequence | 2 | 256 | This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.
You are given a string of «(» and «)» characters. You are to find its longest substring that is a regular bracket sequence. You are to find the number of such substrings as well. | The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106. | Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1". | [
")((())))(()())\n",
"))(\n"
] | [
"6 2\n",
"0 1\n"
] | none | 0 | [
{
"input": ")((())))(()())",
"output": "6 2"
},
{
"input": "))(",
"output": "0 1"
},
{
"input": "()(())()",
"output": "8 1"
},
{
"input": "((((()(((",
"output": "2 1"
},
{
"input": "))))()())))",
"output": "4 1"
},
{
"input": "(()())()(())()()())())()(... | 1,619,037,873 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 404 | 32,460,800 | #code by aanchaltiwari
#practice
s=input()
n=len(s)
valid=[-1]*n
freq=[0]*(n+1)
stack=[]
extension=[-1]*n
for i in range(n):
if s[i]=="(":
stack.append(i)
else:
if stack:
index=stack.pop()
valid[i]=index
extension[i]=index
if index-1>0 and s[index-1]==")" and valid[index-1]>=0:
extension[i]=extension[index-1]
length=i-extension[i]+1
freq[length]+=1
f=0
for i in range(n,0,-1):
if freq[i]:
print(i,freq[i])
f=1
break
if f==0:
print(0,1) | Title: Longest Regular Bracket Sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.
You are given a string of «(» and «)» characters. You are to find its longest substring that is a regular bracket sequence. You are to find the number of such substrings as well.
Input Specification:
The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106.
Output Specification:
Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1".
Demo Input:
[')((())))(()())\n', '))(\n']
Demo Output:
['6 2\n', '0 1\n']
Note:
none | ```python
#code by aanchaltiwari
#practice
s=input()
n=len(s)
valid=[-1]*n
freq=[0]*(n+1)
stack=[]
extension=[-1]*n
for i in range(n):
if s[i]=="(":
stack.append(i)
else:
if stack:
index=stack.pop()
valid[i]=index
extension[i]=index
if index-1>0 and s[index-1]==")" and valid[index-1]>=0:
extension[i]=extension[index-1]
length=i-extension[i]+1
freq[length]+=1
f=0
for i in range(n,0,-1):
if freq[i]:
print(i,freq[i])
f=1
break
if f==0:
print(0,1)
``` | 3.838537 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,666,995,266 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | from math import ceil
n=(int)input()
m=(int)input()
a=(int)input()
pp=ceil(n/a)*ceil(m/a)
print(pp) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
from math import ceil
n=(int)input()
m=(int)input()
a=(int)input()
pp=ceil(n/a)*ceil(m/a)
print(pp)
``` | -1 |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers. | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,687,067,343 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 61 | 0 | def readint():
return int(input())
def readarray(typ: str):
return list(map(typ, input().split()))
n = readint()
if n % 2 != 0: print(9, n-9)
else: print(4, n-4) | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers.
Input Specification:
The only line contains an integer *n* (12<=≤<=*n*<=≤<=106).
Output Specification:
Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them.
Demo Input:
['12\n', '15\n', '23\n', '1000000\n']
Demo Output:
['4 8\n', '6 9\n', '8 15\n', '500000 500000\n']
Note:
In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | ```python
def readint():
return int(input())
def readarray(typ: str):
return list(map(typ, input().split()))
n = readint()
if n % 2 != 0: print(9, n-9)
else: print(4, n-4)
``` | 3 | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite drink for *q* consecutive days. He knows, that on the *i*-th day he will be able to spent *m**i* coins. Now, for each of the days he want to know in how many different shops he can buy a bottle of "Beecola". | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of days Vasiliy plans to buy the drink.
Then follow *q* lines each containing one integer *m**i* (1<=≤<=*m**i*<=≤<=109) — the number of coins Vasiliy can spent on the *i*-th day. | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,698,951,542 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 103 | 218 | 13,926,400 | from os import path
import sys
from collections import Counter
from math import gcd , sqrt
mod = 10**9 + 7
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
if(path.exists('INPUT.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
input = lambda: sys.stdin.readline().rstrip()
def tc():
return int(input())
def ni():
return int(input())
def si():
return str(input())
def mii():
return map(int,input().split())
def msi():
return map(str,input().split())
def lsti():
return list(map(int,input().split()))
def lssi():
return list(map(str,input().split()))
i2c = lambda n: chr(ord('a') + n)
c2i = lambda c: ord(c) - ord('a')
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
def binary_search(lst, n):
left, right = 0, len(lst) - 1
result = -1
while left <= right:
mid = (left + right) // 2
if lst[mid] <= n:
result = mid
right = mid - 1
else:
left = mid + 1
return result
def main():
a = ni()
lst = lsti()
lst.sort(reverse = True)
q = ni()
for j in range(q):
n = int(input())
index = binary_search(lst, n)
if index == -1:
cnt = 0
else:
cnt = len(lst) - index
print(cnt)
if __name__ == "__main__":
main()
| Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite drink for *q* consecutive days. He knows, that on the *i*-th day he will be able to spent *m**i* coins. Now, for each of the days he want to know in how many different shops he can buy a bottle of "Beecola".
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of days Vasiliy plans to buy the drink.
Then follow *q* lines each containing one integer *m**i* (1<=≤<=*m**i*<=≤<=109) — the number of coins Vasiliy can spent on the *i*-th day.
Output Specification:
Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day.
Demo Input:
['5\n3 10 8 6 11\n4\n1\n10\n3\n11\n']
Demo Output:
['0\n4\n1\n5\n']
Note:
On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | ```python
from os import path
import sys
from collections import Counter
from math import gcd , sqrt
mod = 10**9 + 7
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
if(path.exists('INPUT.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
input = lambda: sys.stdin.readline().rstrip()
def tc():
return int(input())
def ni():
return int(input())
def si():
return str(input())
def mii():
return map(int,input().split())
def msi():
return map(str,input().split())
def lsti():
return list(map(int,input().split()))
def lssi():
return list(map(str,input().split()))
i2c = lambda n: chr(ord('a') + n)
c2i = lambda c: ord(c) - ord('a')
#::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
def binary_search(lst, n):
left, right = 0, len(lst) - 1
result = -1
while left <= right:
mid = (left + right) // 2
if lst[mid] <= n:
result = mid
right = mid - 1
else:
left = mid + 1
return result
def main():
a = ni()
lst = lsti()
lst.sort(reverse = True)
q = ni()
for j in range(q):
n = int(input())
index = binary_search(lst, n)
if index == -1:
cnt = 0
else:
cnt = len(lst) - index
print(cnt)
if __name__ == "__main__":
main()
``` | 3 | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light. | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,595,490,012 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 6,963,200 | def lightsOut():
l=[]
for i in range(3):
s=[int(x) for x in input().split()]
l.append(s)
i=0
ans=[[1,1,1] for i in range(3)]
while i<3:
j=0
while j<3:
oc=0
if l[i][j]%2!=0:
oc=oc+l[i][j]
if i+1<3:
if l[i+1][j]%2!=0:
oc=oc+l[i+1][j]
if i-1>=0:
if l[i-1][j]%2!=0:
oc=oc+l[i-1][j]
if j+1<3:
if l[i][j+1]%2!=0:
oc=oc+l[i][j+1]
if j-1>=0:
if l[i][j-1]!=0:
oc=oc+l[i][j-1]
if oc%2==0:
ans[i][j]=1
else:
ans[i][j]=0
j=j+1
i=i+1
for i in range(3):
print(ans[i][0],ans[i][1],ans[i][2],sep='')
lightsOut()
| Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light.
Input Specification:
The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed.
Output Specification:
Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0".
Demo Input:
['1 0 0\n0 0 0\n0 0 1\n', '1 0 1\n8 8 8\n2 0 3\n']
Demo Output:
['001\n010\n100\n', '010\n011\n100\n']
Note:
none | ```python
def lightsOut():
l=[]
for i in range(3):
s=[int(x) for x in input().split()]
l.append(s)
i=0
ans=[[1,1,1] for i in range(3)]
while i<3:
j=0
while j<3:
oc=0
if l[i][j]%2!=0:
oc=oc+l[i][j]
if i+1<3:
if l[i+1][j]%2!=0:
oc=oc+l[i+1][j]
if i-1>=0:
if l[i-1][j]%2!=0:
oc=oc+l[i-1][j]
if j+1<3:
if l[i][j+1]%2!=0:
oc=oc+l[i][j+1]
if j-1>=0:
if l[i][j-1]!=0:
oc=oc+l[i][j-1]
if oc%2==0:
ans[i][j]=1
else:
ans[i][j]=0
j=j+1
i=i+1
for i in range(3):
print(ans[i][0],ans[i][1],ans[i][2],sep='')
lightsOut()
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,686,008,760 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | n,m = map(int,input().split())
eq=n*m
print(eq//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
n,m = map(int,input().split())
eq=n*m
print(eq//2)
``` | 3.977 |
858 | C | Did you mean... | PROGRAMMING | 1,500 | [
"dp",
"greedy",
"implementation"
] | null | null | Beroffice text editor has a wide range of features that help working with text. One of the features is an automatic search for typos and suggestions of how to fix them.
Beroffice works only with small English letters (i.e. with 26 letters from a to z). Beroffice thinks that a word is typed with a typo if there are three or more consonants in a row in the word. The only exception is that if the block of consonants has all letters the same, then this block (even if its length is greater than three) is not considered a typo. Formally, a word is typed with a typo if there is a block of not less that three consonants in a row, and there are at least two different letters in this block.
For example:
- the following words have typos: "hellno", "hackcerrs" and "backtothefutttture"; - the following words don't have typos: "helllllooooo", "tobeornottobe" and "oooooo".
When Beroffice editor finds a word with a typo, it inserts as little as possible number of spaces in this word (dividing it into several words) in such a way that each of the resulting words is typed without any typos.
Implement this feature of Beroffice editor. Consider the following letters as the only vowels: 'a', 'e', 'i', 'o' and 'u'. All the other letters are consonants in this problem. | The only line contains a non-empty word consisting of small English letters. The length of the word is between 1 and 3000 letters. | Print the given word without any changes if there are no typos.
If there is at least one typo in the word, insert the minimum number of spaces into the word so that each of the resulting words doesn't have any typos. If there are multiple solutions, print any of them. | [
"hellno\n",
"abacaba\n",
"asdfasdf\n"
] | [
"hell no \n",
"abacaba \n",
"asd fasd f \n"
] | none | 1,500 | [
{
"input": "hellno",
"output": "hell no "
},
{
"input": "abacaba",
"output": "abacaba "
},
{
"input": "asdfasdf",
"output": "asd fasd f "
},
{
"input": "ooo",
"output": "ooo "
},
{
"input": "moyaoborona",
"output": "moyaoborona "
},
{
"input": "jxegxxx... | 1,505,657,558 | 4,058 | Python 3 | WRONG_ANSWER | TESTS | 39 | 77 | 5,529,600 | n = input()
res = n
arr = []
vowels = ['a', 'e', 'i', 'o', 'u']
cnt = 0
for i in range(len(n)):
for letter in vowels:
if n[i] == letter:
cnt = 0
break
else:
cnt += 1
if cnt == 3 and not(n[i] == n[i-1] == n[i-2]):
arr.append(i)
cnt = 1
for i in range(len(arr)):
res = res[:arr[i]+i]+" "+res[arr[i]+i:]
print(res)
| Title: Did you mean...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Beroffice text editor has a wide range of features that help working with text. One of the features is an automatic search for typos and suggestions of how to fix them.
Beroffice works only with small English letters (i.e. with 26 letters from a to z). Beroffice thinks that a word is typed with a typo if there are three or more consonants in a row in the word. The only exception is that if the block of consonants has all letters the same, then this block (even if its length is greater than three) is not considered a typo. Formally, a word is typed with a typo if there is a block of not less that three consonants in a row, and there are at least two different letters in this block.
For example:
- the following words have typos: "hellno", "hackcerrs" and "backtothefutttture"; - the following words don't have typos: "helllllooooo", "tobeornottobe" and "oooooo".
When Beroffice editor finds a word with a typo, it inserts as little as possible number of spaces in this word (dividing it into several words) in such a way that each of the resulting words is typed without any typos.
Implement this feature of Beroffice editor. Consider the following letters as the only vowels: 'a', 'e', 'i', 'o' and 'u'. All the other letters are consonants in this problem.
Input Specification:
The only line contains a non-empty word consisting of small English letters. The length of the word is between 1 and 3000 letters.
Output Specification:
Print the given word without any changes if there are no typos.
If there is at least one typo in the word, insert the minimum number of spaces into the word so that each of the resulting words doesn't have any typos. If there are multiple solutions, print any of them.
Demo Input:
['hellno\n', 'abacaba\n', 'asdfasdf\n']
Demo Output:
['hell no \n', 'abacaba \n', 'asd fasd f \n']
Note:
none | ```python
n = input()
res = n
arr = []
vowels = ['a', 'e', 'i', 'o', 'u']
cnt = 0
for i in range(len(n)):
for letter in vowels:
if n[i] == letter:
cnt = 0
break
else:
cnt += 1
if cnt == 3 and not(n[i] == n[i-1] == n[i-2]):
arr.append(i)
cnt = 1
for i in range(len(arr)):
res = res[:arr[i]+i]+" "+res[arr[i]+i:]
print(res)
``` | 0 | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,618,925,433 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 204,800 | from collections import Counter
n, k = map(int, input().split())
c = Counter(input())
for i in c:
if c[i] % k != 0:
print("NO")
exit()
print("YES")
| Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons.
Output Specification:
Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary.
Demo Input:
['4 2\naabb\n', '6 3\naacaab\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | ```python
from collections import Counter
n, k = map(int, input().split())
c = Counter(input())
for i in c:
if c[i] % k != 0:
print("NO")
exit()
print("YES")
``` | 0 | |
780 | A | Andryusha and Socks | PROGRAMMING | 800 | [
"implementation"
] | null | null | Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe.
Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time? | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*.
It is guaranteed that Andryusha took exactly two socks of each pair. | Print single integer — the maximum number of socks that were on the table at the same time. | [
"1\n1 1\n",
"3\n2 1 1 3 2 3\n"
] | [
"1\n",
"2\n"
] | In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe. | 500 | [
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n2 1 1 3 2 3",
"output": "2"
},
{
"input": "5\n5 1 3 2 4 3 1 2 4 5",
"output": "5"
},
{
"input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7",
"output": "6"
},
{
"input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 ... | 1,683,370,135 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 19,660,800 | a=int(input())
list1=list(map(int,input().split()))
ans=0
temp=[]
for i in range(0,len(list1)):
if list1[i] not in temp :
temp.append(list1[i])
if len(temp)>ans :
ans =len(temp)
else:
temp.pop(temp.index(list1[i]))
print(ans) | Title: Andryusha and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe.
Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time?
Input Specification:
The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*.
It is guaranteed that Andryusha took exactly two socks of each pair.
Output Specification:
Print single integer — the maximum number of socks that were on the table at the same time.
Demo Input:
['1\n1 1\n', '3\n2 1 1 3 2 3\n']
Demo Output:
['1\n', '2\n']
Note:
In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe. | ```python
a=int(input())
list1=list(map(int,input().split()))
ans=0
temp=[]
for i in range(0,len(list1)):
if list1[i] not in temp :
temp.append(list1[i])
if len(temp)>ans :
ans =len(temp)
else:
temp.pop(temp.index(list1[i]))
print(ans)
``` | 0 | |
811 | B | Vladik and Complicated Book | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], where *p**i* denotes the number of page that should be read *i*-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation *P* from position *l* to position *r* inclusive, because she loves the order. For every of such sorting Vladik knows number *x* — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has *p**x* changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other. | First line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — permutation *P*. Note that elements in permutation are distinct.
Each of the next *m* lines contains three space-separated integers *l**i*, *r**i*, *x**i* (1<=≤<=*l**i*<=≤<=*x**i*<=≤<=*r**i*<=≤<=*n*) — left and right borders of sorted subsegment in *i*-th sorting and position that is interesting to Vladik. | For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise. | [
"5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3\n",
"6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3\n"
] | [
"Yes\nNo\nYes\nYes\nNo\n",
"Yes\nNo\nYes\nNo\nYes\n"
] | Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No". 1. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes". 1. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | 1,000 | [
{
"input": "5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3",
"output": "Yes\nNo\nYes\nYes\nNo"
},
{
"input": "6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3",
"output": "Yes\nNo\nYes\nNo\nYes"
},
{
"input": "10 10\n10 1 6 7 9 8 4 3 5 2\n1 1 1\n4 4 4\n7 7 7\n3 3 3\n1 6 5\n2 6 2\n6... | 1,495,880,883 | 3,183 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 62 | 0 | x,y=map(int,input().split())
d=list(map(int,input().split()))
p=0
j=[]
k=0
for i in range(y):
a,b,c=map(int,input().split())
p=d[(c-1)]
j=d[(a-1):b]
k=j.index(p)
j.sort()
if p==j[k]:
print("YES")
else:
print("NO")
p=0
j=[]
k=0
| Title: Vladik and Complicated Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], where *p**i* denotes the number of page that should be read *i*-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation *P* from position *l* to position *r* inclusive, because she loves the order. For every of such sorting Vladik knows number *x* — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has *p**x* changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input Specification:
First line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — permutation *P*. Note that elements in permutation are distinct.
Each of the next *m* lines contains three space-separated integers *l**i*, *r**i*, *x**i* (1<=≤<=*l**i*<=≤<=*x**i*<=≤<=*r**i*<=≤<=*n*) — left and right borders of sorted subsegment in *i*-th sorting and position that is interesting to Vladik.
Output Specification:
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Demo Input:
['5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3\n', '6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3\n']
Demo Output:
['Yes\nNo\nYes\nYes\nNo\n', 'Yes\nNo\nYes\nNo\nYes\n']
Note:
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No". 1. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes". 1. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | ```python
x,y=map(int,input().split())
d=list(map(int,input().split()))
p=0
j=[]
k=0
for i in range(y):
a,b,c=map(int,input().split())
p=d[(c-1)]
j=d[(a-1):b]
k=j.index(p)
j.sort()
if p==j[k]:
print("YES")
else:
print("NO")
p=0
j=[]
k=0
``` | 0 | |
724 | A | Checking the Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong to one year.
In this problem, we consider the Gregorian calendar to be used. The number of months in this calendar is equal to 12. The number of days in months during any non-leap year is: 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31.
Names of the days of the week are given with lowercase English letters: "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes). | [
"monday\ntuesday\n",
"sunday\nsunday\n",
"saturday\ntuesday\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | 500 | [
{
"input": "monday\ntuesday",
"output": "NO"
},
{
"input": "sunday\nsunday",
"output": "YES"
},
{
"input": "saturday\ntuesday",
"output": "YES"
},
{
"input": "tuesday\nthursday",
"output": "YES"
},
{
"input": "friday\nwednesday",
"output": "NO"
},
{
"i... | 1,658,760,133 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 46 | 0 |
num_inp=lambda: int(input())
arr_inp=lambda: list(map(int,input().split()))
sp_inp=lambda: map(int,input().split())
s=['monday','tuesday','wednesday','thursday','friday','saturday','sunday']
I=input
a=I()
print(['NO','YES'][I()in[s[(s.index(a)+i)%7]for i in (28,30,31)]]) | Title: Checking the Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong to one year.
In this problem, we consider the Gregorian calendar to be used. The number of months in this calendar is equal to 12. The number of days in months during any non-leap year is: 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31.
Names of the days of the week are given with lowercase English letters: "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday".
Input Specification:
The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday".
Output Specification:
Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes).
Demo Input:
['monday\ntuesday\n', 'sunday\nsunday\n', 'saturday\ntuesday\n']
Demo Output:
['NO\n', 'YES\n', 'YES\n']
Note:
In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | ```python
num_inp=lambda: int(input())
arr_inp=lambda: list(map(int,input().split()))
sp_inp=lambda: map(int,input().split())
s=['monday','tuesday','wednesday','thursday','friday','saturday','sunday']
I=input
a=I()
print(['NO','YES'][I()in[s[(s.index(a)+i)%7]for i in (28,30,31)]])
``` | 3 | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agreed to help if Rostislav solves a simple task (and if he doesn't, then why would he need Splay trees anyway?)
Given integers *l*, *r* and *k*, you need to print all powers of number *k* within range from *l* to *r* inclusive. However, Rostislav doesn't want to spent time doing this, as he got interested in playing a network game called Agar with Gleb. Help him! | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,501,335,510 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 62 | 4,608,000 | l, r, k = tuple(map(int, input().split()))
a = 1
c = 0
while a <= r:
if a >= l and a <= r:
print(a, end = " ")
c += 1
a = a * k
if c == 0:
print(-1)
| Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agreed to help if Rostislav solves a simple task (and if he doesn't, then why would he need Splay trees anyway?)
Given integers *l*, *r* and *k*, you need to print all powers of number *k* within range from *l* to *r* inclusive. However, Rostislav doesn't want to spent time doing this, as he got interested in playing a network game called Agar with Gleb. Help him!
Input Specification:
The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Output Specification:
Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes).
Demo Input:
['1 10 2\n', '2 4 5\n']
Demo Output:
['1 2 4 8 ', '-1']
Note:
Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | ```python
l, r, k = tuple(map(int, input().split()))
a = 1
c = 0
while a <= r:
if a >= l and a <= r:
print(a, end = " ")
c += 1
a = a * k
if c == 0:
print(-1)
``` | 3 | |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<=-<=*a*<=><=*c*, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if *c*<==<=5 and you typed words at seconds 1,<=3,<=8,<=14,<=19,<=20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything. | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denotes the second when ZS the Coder typed the *i*-th word. | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 ≤ 1. | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,576,308,328 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 109 | 204,800 | n,c=[int(x) for x in input().split()]
times=[int(x) for x in input().split()]
times.reverse()
check=1
for i in range(99999):
if times[i]-times[i+1]>5:
print(i+1)
check=0
break
print(check*'100000') | Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<=-<=*a*<=><=*c*, then everything on the screen disappears and after that the word you have typed appears on the screen.
For example, if *c*<==<=5 and you typed words at seconds 1,<=3,<=8,<=14,<=19,<=20 then at the second 8 there will be 3 words on the screen. After that, everything disappears at the second 13 because nothing was typed. At the seconds 14 and 19 another two words are typed, and finally, at the second 20, one more word is typed, and a total of 3 words remain on the screen.
You're given the times when ZS the Coder typed the words. Determine how many words remain on the screen after he finished typing everything.
Input Specification:
The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denotes the second when ZS the Coder typed the *i*-th word.
Output Specification:
Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*.
Demo Input:
['6 5\n1 3 8 14 19 20\n', '6 1\n1 3 5 7 9 10\n']
Demo Output:
['3', '2']
Note:
The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be two words on the screen, as the old word won't disappear because 10 - 9 ≤ 1. | ```python
n,c=[int(x) for x in input().split()]
times=[int(x) for x in input().split()]
times.reverse()
check=1
for i in range(99999):
if times[i]-times[i+1]>5:
print(i+1)
check=0
break
print(check*'100000')
``` | -1 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,479,818,638 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | #─────────▄──────────────▄─────────wow─────────────────────────────────────
#────────▌▒█───────────▄▀▒▌────────────────────────────────────────────────
#────────▌▒▒█────────▄▀▒▒▒▐────────────────────────────────────────────────
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#──▐▒▒▒▄▄▒▒▒▒░░░▒▒▒▒▒▒▒▀▄▒▒▌───────────────────────────────────────────────
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#─▐░░░▒▒▒▒▒▒▒▒▌██▀▒▒░░░▒▒▒▀▄▌─────────────────so─ascii─────────────────────
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#─▌▒▒▒▒▒▒▀▀▀▒▒▒▒▒▒░▒░▒░▒░▒▒▒▌───────────▀▄─█─▄▀─█──█─▀▄─█─▄▀───────────────
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#──▀▄▒▒▒▒▒▒▒▒▒▒▒░▒░▒░▒▄▒▒▒▒▌───────────────────────────────────────────────
#────▀▄▒▒▒▒▒▒▒▒▒▒▄▄▄▀▒▒▒▒▄▀────────────────────────────────────────────────
#──────▀▄▄▄▄▄▄▀▀▀▒▒▒▒▒▄▄▀──────────such─algorithm──────────────────────────
#─────────▒▒▒▒▒▒▒▒▒▒▀▀─────────────────────────────────────────────────────
#────────────────────────────────────────────────────────do─submit─────────
#─────────▄───▄─▄──▄─▄▄▄▄─▄──▄────▄▄▄▄─▄▄▄▄─▄▄▄──▄▄▄───────────────────────
#─────────█▀▄▀█─█──█─█────█▄▄█────█────█──█─█──█─█▄▄───────────────────────
#─────────█───█─█▄▄█─█▄▄▄─█──█────█▄▄▄─█▄▄█─█▄▄▀─█▄▄───────────────────────
#──────────────────────────────────────────────────────────────────────────
n = int(input())
scor = list(map(int, input().split()))
score = []
for i in range(n): score.append([scor[i],i])
score.sort()
ans = []
for i in range(n-1):
for j in range(i+1,n):
if score[i][0]!=score[j][0]:
ans.append([score[i][1],str(n-j+1)])
break
while len(ans)!=n:
maxin = scor.index(max(scor))
ans.append([maxin,'1'])
del scor[maxin]
ans = [i[1] for i in sorted(ans)]
print(' '.join(ans)) | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*).
Output Specification:
In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input.
Demo Input:
['3\n1 3 3\n', '1\n1\n', '5\n3 5 3 4 5\n']
Demo Output:
['3 1 1\n', '1\n', '4 1 4 3 1\n']
Note:
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | ```python
#─────────▄──────────────▄─────────wow─────────────────────────────────────
#────────▌▒█───────────▄▀▒▌────────────────────────────────────────────────
#────────▌▒▒█────────▄▀▒▒▒▐────────────────────────────────────────────────
#───────▐▄▀▒▒▀▀▀▀▄▄▄▀▒▒▒▒▒▐────────────▄▄▄▄─▄▄▄▄────▄▄▄▄─▄▄▄▄─▄▄▄▄─▄───────
#─────▄▄▀▒░▒▒▒▒▒▒▒▒▒█▒▒▄█▒▐────────────█▄▄▄─█──█────█────█──█─█──█─█───────
#───▄▀▒▒▒░░░▒▒▒░░░▒▒▒▀██▀▒▌────────────▄▄▄█─█▄▄█────█▄▄▄─█▄▄█─█▄▄█─█▄▄▄────
#──▐▒▒▒▄▄▒▒▒▒░░░▒▒▒▒▒▒▒▀▄▒▒▌───────────────────────────────────────────────
#──▌░░▌█▀▒▒▒▒▒▄▀█▄▒▒▒▒▒▒▒█▒▐───────────────────────────────────────────────
#─▐░░░▒▒▒▒▒▒▒▒▌██▀▒▒░░░▒▒▒▀▄▌─────────────────so─ascii─────────────────────
#─▌░▒▄██▄▒▒▒▒▒▒▒▒▒░░░░░░▒▒▒▒▌──────────────────────────────────────────────
#▀▒▀▐▄█▄█▌▄░▀▒▒░░░░░░░░░░▒▒▒▐────much─codeforces───────────────────────────
#▐▒▒▐▀▐▀▒░▄▄▒▄▒▒▒▒▒▒░▒░▒░▒▒▒▒▌──────────────────────────────────────omg────
#▐▒▒▒▀▀▄▄▒▒▒▄▒▒▒▒▒▒▒▒░▒░▒░▒▒▐───────────▄─────▄─▄▄▄▄─▄─────▄───────────────
#─▌▒▒▒▒▒▒▀▀▀▒▒▒▒▒▒░▒░▒░▒░▒▒▒▌───────────▀▄─█─▄▀─█──█─▀▄─█─▄▀───────────────
#─▐▒▒▒▒▒▒▒▒▒▒▒▒▒▒░▒░▒░▒▒▄▒▒▐─────────────▀▄▀▄▀──█▄▄█──▀▄▀▄▀────────────────
#──▀▄▒▒▒▒▒▒▒▒▒▒▒░▒░▒░▒▄▒▒▒▒▌───────────────────────────────────────────────
#────▀▄▒▒▒▒▒▒▒▒▒▒▄▄▄▀▒▒▒▒▄▀────────────────────────────────────────────────
#──────▀▄▄▄▄▄▄▀▀▀▒▒▒▒▒▄▄▀──────────such─algorithm──────────────────────────
#─────────▒▒▒▒▒▒▒▒▒▒▀▀─────────────────────────────────────────────────────
#────────────────────────────────────────────────────────do─submit─────────
#─────────▄───▄─▄──▄─▄▄▄▄─▄──▄────▄▄▄▄─▄▄▄▄─▄▄▄──▄▄▄───────────────────────
#─────────█▀▄▀█─█──█─█────█▄▄█────█────█──█─█──█─█▄▄───────────────────────
#─────────█───█─█▄▄█─█▄▄▄─█──█────█▄▄▄─█▄▄█─█▄▄▀─█▄▄───────────────────────
#──────────────────────────────────────────────────────────────────────────
n = int(input())
scor = list(map(int, input().split()))
score = []
for i in range(n): score.append([scor[i],i])
score.sort()
ans = []
for i in range(n-1):
for j in range(i+1,n):
if score[i][0]!=score[j][0]:
ans.append([score[i][1],str(n-j+1)])
break
while len(ans)!=n:
maxin = scor.index(max(scor))
ans.append([maxin,'1'])
del scor[maxin]
ans = [i[1] for i in sorted(ans)]
print(' '.join(ans))
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,540,898,025 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | w = input()
word = list(w)
characters = frozenset("helo")
hello = []
for a in word:
if a not in characters:
b = word.index(a)
del word[b]
if word.count("l")<2 or frozenset(word) & characters != characters:
print("NO")
else:
a=word.index("h")
word == word[a:]
if "e" not in word:
print("NO")
else:
b=word.index("e")
word == word[b:]
if "l" not in word:
print("NO")
else:
c=word.index("l")
word == word[c:]
if "l" not in word:
print("NO")
else:
d=word.index("l")
word == word[d:]
if "o" not in word:
print("NO")
else:
print("YES")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
w = input()
word = list(w)
characters = frozenset("helo")
hello = []
for a in word:
if a not in characters:
b = word.index(a)
del word[b]
if word.count("l")<2 or frozenset(word) & characters != characters:
print("NO")
else:
a=word.index("h")
word == word[a:]
if "e" not in word:
print("NO")
else:
b=word.index("e")
word == word[b:]
if "l" not in word:
print("NO")
else:
c=word.index("l")
word == word[c:]
if "l" not in word:
print("NO")
else:
d=word.index("l")
word == word[d:]
if "o" not in word:
print("NO")
else:
print("YES")
``` | 0 |
353 | B | Two Heaps | PROGRAMMING | 1,900 | [
"combinatorics",
"constructive algorithms",
"greedy",
"implementation",
"math",
"sortings"
] | null | null | Valera has 2·*n* cubes, each cube contains an integer from 10 to 99. He arbitrarily chooses *n* cubes and puts them in the first heap. The remaining cubes form the second heap.
Valera decided to play with cubes. During the game he takes a cube from the first heap and writes down the number it has. Then he takes a cube from the second heap and write out its two digits near two digits he had written (to the right of them). In the end he obtained a single fourdigit integer — the first two digits of it is written on the cube from the first heap, and the second two digits of it is written on the second cube from the second heap.
Valera knows arithmetic very well. So, he can easily count the number of distinct fourdigit numbers he can get in the game. The other question is: how to split cubes into two heaps so that this number (the number of distinct fourdigit integers Valera can get) will be as large as possible? | The first line contains integer *n* (1<=≤<=*n*<=≤<=100). The second line contains 2·*n* space-separated integers *a**i* (10<=≤<=*a**i*<=≤<=99), denoting the numbers on the cubes. | In the first line print a single number — the maximum possible number of distinct four-digit numbers Valera can obtain. In the second line print 2·*n* numbers *b**i* (1<=≤<=*b**i*<=≤<=2). The numbers mean: the *i*-th cube belongs to the *b**i*-th heap in your division.
If there are multiple optimal ways to split the cubes into the heaps, print any of them. | [
"1\n10 99\n",
"2\n13 24 13 45\n"
] | [
"1\n2 1 \n",
"4\n1 2 2 1 \n"
] | In the first test case Valera can put the first cube in the first heap, and second cube — in second heap. In this case he obtain number 1099. If he put the second cube in the first heap, and the first cube in the second heap, then he can obtain number 9910. In both cases the maximum number of distinct integers is equal to one.
In the second test case Valera can obtain numbers 1313, 1345, 2413, 2445. Note, that if he put the first and the third cubes in the first heap, he can obtain only two numbers 1324 and 1345. | 1,500 | [
{
"input": "1\n10 99",
"output": "1\n2 1 "
},
{
"input": "2\n13 24 13 45",
"output": "4\n1 2 2 1 "
},
{
"input": "5\n21 60 18 21 17 39 58 74 62 34",
"output": "25\n1 1 1 2 2 1 2 1 2 2 "
},
{
"input": "10\n26 43 29 92 22 27 95 56 72 55 93 51 91 30 70 77 32 69 87 98",
"outp... | 1,381,424,901 | 5,900 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 92 | 0 | n = int(input())
set1 = set()
set2 = set()
res = [0] * (2 * n)
dop = []
len1 = 0
len2 = 0
count = 2 * n
count2 = 2 * n
for i in map(int, input().split()):
if len1 <= len2 and i not in set1 or i in set2 and len2 - len1 >= count2:
set1.add(i)
len1 += 1
res[2 * n - count] = 1
count2 -= 1
elif i not in set2:
set2.add(i)
len2 += 1
res[2 * n - count] = 2
count2 -= 1
else:
dop.append(2 * n - count)
count -= 1
for i in dop:
if len1 <= len2:
len1 += 1
res[i] = 1
else:
len2 += 1
res[i] = 2
print(len(set1) * len(set2))
print(' '.join(map(str, res)))
| Title: Two Heaps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has 2·*n* cubes, each cube contains an integer from 10 to 99. He arbitrarily chooses *n* cubes and puts them in the first heap. The remaining cubes form the second heap.
Valera decided to play with cubes. During the game he takes a cube from the first heap and writes down the number it has. Then he takes a cube from the second heap and write out its two digits near two digits he had written (to the right of them). In the end he obtained a single fourdigit integer — the first two digits of it is written on the cube from the first heap, and the second two digits of it is written on the second cube from the second heap.
Valera knows arithmetic very well. So, he can easily count the number of distinct fourdigit numbers he can get in the game. The other question is: how to split cubes into two heaps so that this number (the number of distinct fourdigit integers Valera can get) will be as large as possible?
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100). The second line contains 2·*n* space-separated integers *a**i* (10<=≤<=*a**i*<=≤<=99), denoting the numbers on the cubes.
Output Specification:
In the first line print a single number — the maximum possible number of distinct four-digit numbers Valera can obtain. In the second line print 2·*n* numbers *b**i* (1<=≤<=*b**i*<=≤<=2). The numbers mean: the *i*-th cube belongs to the *b**i*-th heap in your division.
If there are multiple optimal ways to split the cubes into the heaps, print any of them.
Demo Input:
['1\n10 99\n', '2\n13 24 13 45\n']
Demo Output:
['1\n2 1 \n', '4\n1 2 2 1 \n']
Note:
In the first test case Valera can put the first cube in the first heap, and second cube — in second heap. In this case he obtain number 1099. If he put the second cube in the first heap, and the first cube in the second heap, then he can obtain number 9910. In both cases the maximum number of distinct integers is equal to one.
In the second test case Valera can obtain numbers 1313, 1345, 2413, 2445. Note, that if he put the first and the third cubes in the first heap, he can obtain only two numbers 1324 and 1345. | ```python
n = int(input())
set1 = set()
set2 = set()
res = [0] * (2 * n)
dop = []
len1 = 0
len2 = 0
count = 2 * n
count2 = 2 * n
for i in map(int, input().split()):
if len1 <= len2 and i not in set1 or i in set2 and len2 - len1 >= count2:
set1.add(i)
len1 += 1
res[2 * n - count] = 1
count2 -= 1
elif i not in set2:
set2.add(i)
len2 += 1
res[2 * n - count] = 2
count2 -= 1
else:
dop.append(2 * n - count)
count -= 1
for i in dop:
if len1 <= len2:
len1 += 1
res[i] = 1
else:
len2 += 1
res[i] = 2
print(len(set1) * len(set2))
print(' '.join(map(str, res)))
``` | 0 | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV sets, and he has no desire to go to the sale for the second time. Please, help Bob find out the maximum sum of money that he can earn. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,617,992,283 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 124 | 0 | def fun(ls,ms):
ans=0
count=0
for i in ls:
if(i<0):
ans+=i
count+=1
if(count>=ms[1]):
break
print(abs(ans))
# T = int(input())
T = 1
for i in range(T):
# var=input()
# val=int(input())
# st=input()
ms= list(map(int, input().split()))
ls= list(map(int, input().split()))
fun(ls,ms) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV sets, and he has no desire to go to the sale for the second time. Please, help Bob find out the maximum sum of money that he can earn.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets.
Output Specification:
Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets.
Demo Input:
['5 3\n-6 0 35 -2 4\n', '4 2\n7 0 0 -7\n']
Demo Output:
['8\n', '7\n']
Note:
none | ```python
def fun(ls,ms):
ans=0
count=0
for i in ls:
if(i<0):
ans+=i
count+=1
if(count>=ms[1]):
break
print(abs(ans))
# T = int(input())
T = 1
for i in range(T):
# var=input()
# val=int(input())
# st=input()
ms= list(map(int, input().split()))
ls= list(map(int, input().split()))
fun(ls,ms)
``` | 0 |
714 | A | Meeting of Old Friends | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together. | The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks. | Print one integer — the number of minutes Sonya and Filya will be able to spend together. | [
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] | [
"2\n",
"50\n"
] | In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | 500 | [
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input":... | 1,532,383,599 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 109 | 0 | l1, r1, l2, r2, k = map(int, input().split())
begin, end = max(l1, l2), min(r1, r2)
print(end - begin + (begin > k or k > end)) | Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together.
Input Specification:
The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks.
Output Specification:
Print one integer — the number of minutes Sonya and Filya will be able to spend together.
Demo Input:
['1 10 9 20 1\n', '1 100 50 200 75\n']
Demo Output:
['2\n', '50\n']
Note:
In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | ```python
l1, r1, l2, r2, k = map(int, input().split())
begin, end = max(l1, l2), min(r1, r2)
print(end - begin + (begin > k or k > end))
``` | 0 | |
580 | A | Kefa and First Steps | PROGRAMMING | 900 | [
"brute force",
"dp",
"implementation"
] | null | null | Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence *a**i*. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.
Help Kefa cope with this task! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the length of the maximum non-decreasing subsegment of sequence *a*. | [
"6\n2 2 1 3 4 1\n",
"3\n2 2 9\n"
] | [
"3",
"3"
] | In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.
In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one. | 750 | [
{
"input": "6\n2 2 1 3 4 1",
"output": "3"
},
{
"input": "3\n2 2 9",
"output": "3"
},
{
"input": "5\n10 100 111 1 2",
"output": "3"
},
{
"input": "10\n1 2 3 4 1 2 3 4 5 6",
"output": "6"
},
{
"input": "50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ... | 1,695,110,639 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | n = int(input())
mas = [int(el) for el in input().split()]
ans = 1
v = 1
for i in range(1, n):
if mas[i] >= mas[i - 1]:
v += 1
else:
ans = max(ans, v)
v = 1
print(ans) | Title: Kefa and First Steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kefa decided to make some money doing business on the Internet for exactly *n* days. He knows that on the *i*-th day (1<=≤<=*i*<=≤<=*n*) he makes *a**i* money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence *a**i*. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.
Help Kefa cope with this task!
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print a single integer — the length of the maximum non-decreasing subsegment of sequence *a*.
Demo Input:
['6\n2 2 1 3 4 1\n', '3\n2 2 9\n']
Demo Output:
['3', '3']
Note:
In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.
In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one. | ```python
n = int(input())
mas = [int(el) for el in input().split()]
ans = 1
v = 1
for i in range(1, n):
if mas[i] >= mas[i - 1]:
v += 1
else:
ans = max(ans, v)
v = 1
print(ans)
``` | 0 | |
262 | B | Roma and Changing Signs | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of several numbers in the sequence. He can also change the sign of a number one, two or more times.
The operation of changing a number's sign is the operation of multiplying this number by -1.
Help Roma perform the changes so as to make the total income of the company (the sum of numbers in the resulting sequence) maximum. Note that Roma should perform exactly *k* changes. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces. Please note that the given sequence is sorted in non-decreasing order. | In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. | [
"3 2\n-1 -1 1\n",
"3 1\n-1 -1 1\n"
] | [
"3\n",
"1\n"
] | In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | 1,000 | [
{
"input": "3 2\n-1 -1 1",
"output": "3"
},
{
"input": "3 1\n-1 -1 1",
"output": "1"
},
{
"input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343",
"output": "81852"
},
{
"input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -89... | 1,678,808,408 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 154 | 2,867,200 |
def task_c():
n, c = map(int, input().split())
arr = list(map(int, input().split()))
i = 0
while i < c:
if arr[i] < 0:
arr[i] *= -1
i += 1
continue
if arr[i] != 0:
arr[0] *= (-1) ** c
break
print(sum(arr))
task_c() | Title: Roma and Changing Signs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of several numbers in the sequence. He can also change the sign of a number one, two or more times.
The operation of changing a number's sign is the operation of multiplying this number by -1.
Help Roma perform the changes so as to make the total income of the company (the sum of numbers in the resulting sequence) maximum. Note that Roma should perform exactly *k* changes.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces. Please note that the given sequence is sorted in non-decreasing order.
Output Specification:
In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes.
Demo Input:
['3 2\n-1 -1 1\n', '3 1\n-1 -1 1\n']
Demo Output:
['3\n', '1\n']
Note:
In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | ```python
def task_c():
n, c = map(int, input().split())
arr = list(map(int, input().split()))
i = 0
while i < c:
if arr[i] < 0:
arr[i] *= -1
i += 1
continue
if arr[i] != 0:
arr[0] *= (-1) ** c
break
print(sum(arr))
task_c()
``` | -1 |
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