contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,687,007,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | w=int(input("weight="))
while not 1<=w<=100:
w=int(input("weight="))
if w%2==0 and w!=2:
print("YES")
else:
print("NO")
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.
Input Specification:
The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.
Output Specification:
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.
Demo Input:
['8\n']
Demo Output:
['YES\n']
Note:
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | ```python
w=int(input("weight="))
while not 1<=w<=100:
w=int(input("weight="))
if w%2==0 and w!=2:
print("YES")
else:
print("NO")
``` | 0 |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works as follows:
- If *x*<==<=1, exit the function. - Otherwise, call *f*(*x*<=-<=1), and then make *swap*(*a**x*<=-<=1,<=*a**x*) (swap the *x*-th and (*x*<=-<=1)-th elements of *a*).
The Little Elephant's teacher believes that this function does not work correctly. But that-be do not get an F, the Little Elephant wants to show the performance of its function. Help him, find a permutation of numbers from 1 to *n*, such that after performing the Little Elephant's function (that is call *f*(*n*)), the permutation will be sorted in ascending order. | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,568,653,568 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 280 | 1,433,600 | __author__ = 'Esfandiar'
n = int(input())
print(n,*range(1,n)) | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works as follows:
- If *x*<==<=1, exit the function. - Otherwise, call *f*(*x*<=-<=1), and then make *swap*(*a**x*<=-<=1,<=*a**x*) (swap the *x*-th and (*x*<=-<=1)-th elements of *a*).
The Little Elephant's teacher believes that this function does not work correctly. But that-be do not get an F, the Little Elephant wants to show the performance of its function. Help him, find a permutation of numbers from 1 to *n*, such that after performing the Little Elephant's function (that is call *f*(*n*)), the permutation will be sorted in ascending order.
Input Specification:
A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation.
Output Specification:
In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists.
Demo Input:
['1\n', '2\n']
Demo Output:
['1 ', '2 1 ']
Note:
none | ```python
__author__ = 'Esfandiar'
n = int(input())
print(n,*range(1,n))
``` | 3 | |
85 | A | Domino | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation"
] | A. Domino | 1 | 256 | We all know the problem about the number of ways one can tile a 2<=×<=*n* field by 1<=×<=2 dominoes. You probably remember that it goes down to Fibonacci numbers. We will talk about some other problem below, there you also are going to deal with tiling a rectangular field with dominoes.
You are given a 4<=×<=*n* rectangular field, that is the field that contains four lines and *n* columns. You have to find for it any tiling by 1<=×<=2 dominoes such that each of the *n*<=-<=1 potential vertical cuts along the grid lines intersects at least one domino, splitting it in two. No two dominoes in the sought tiling should overlap, each square of the field should be covered by exactly one domino. It is allowed to rotate the dominoes, that is, you can use 2<=×<=1 as well as 1<=×<=2 dominoes.
Write a program that finds an arbitrary sought tiling. | The input contains one positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of the field's columns. | If there's no solution, print "-1" (without the quotes). Otherwise, print four lines containing *n* characters each — that's the description of tiling, where each vertical cut intersects at least one domino. You should print the tiling, having painted the field in no more than 26 colors. Each domino should be painted a color. Different dominoes can be painted the same color, but dominoes of the same color should not be side-neighbouring. To indicate colors you should use lowercase Latin letters. Print any of the acceptable ways of tiling. | [
"4\n"
] | [
"yyzz\nbccd\nbxxd\nyyaa\n"
] | none | 500 | [
{
"input": "4",
"output": "aacc\nbbdd\nzkkz\nzllz"
},
{
"input": "2",
"output": "aa\nbb\naa\nbb"
},
{
"input": "3",
"output": "aab\nccb\nbaa\nbcc"
},
{
"input": "5",
"output": "aaccz\nbbddz\nzkkmm\nzllnn"
},
{
"input": "1",
"output": "a\na\nb\nb"
},
{
... | 1,572,505,131 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 436 | 2,150,400 | n=int(input())
if n%3==2:
print("-1")
else:
ans=["."*n for i in range(4)]
for i in range(n):
if i%2==0:
ans[i][0]="a"
ans[i][1]="a"
ans[i][2]="b"
ans[i][3]="b"
else:
ans[i][0]="b"
ans[i][1]="b"
ans[i][2]="a"
ans[i][3]="a"
for i in ans:
print(i) | Title: Domino
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
We all know the problem about the number of ways one can tile a 2<=×<=*n* field by 1<=×<=2 dominoes. You probably remember that it goes down to Fibonacci numbers. We will talk about some other problem below, there you also are going to deal with tiling a rectangular field with dominoes.
You are given a 4<=×<=*n* rectangular field, that is the field that contains four lines and *n* columns. You have to find for it any tiling by 1<=×<=2 dominoes such that each of the *n*<=-<=1 potential vertical cuts along the grid lines intersects at least one domino, splitting it in two. No two dominoes in the sought tiling should overlap, each square of the field should be covered by exactly one domino. It is allowed to rotate the dominoes, that is, you can use 2<=×<=1 as well as 1<=×<=2 dominoes.
Write a program that finds an arbitrary sought tiling.
Input Specification:
The input contains one positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of the field's columns.
Output Specification:
If there's no solution, print "-1" (without the quotes). Otherwise, print four lines containing *n* characters each — that's the description of tiling, where each vertical cut intersects at least one domino. You should print the tiling, having painted the field in no more than 26 colors. Each domino should be painted a color. Different dominoes can be painted the same color, but dominoes of the same color should not be side-neighbouring. To indicate colors you should use lowercase Latin letters. Print any of the acceptable ways of tiling.
Demo Input:
['4\n']
Demo Output:
['yyzz\nbccd\nbxxd\nyyaa\n']
Note:
none | ```python
n=int(input())
if n%3==2:
print("-1")
else:
ans=["."*n for i in range(4)]
for i in range(n):
if i%2==0:
ans[i][0]="a"
ans[i][1]="a"
ans[i][2]="b"
ans[i][3]="b"
else:
ans[i][0]="b"
ans[i][1]="b"
ans[i][2]="a"
ans[i][3]="a"
for i in ans:
print(i)
``` | -1 |
292 | B | Network Topology | PROGRAMMING | 1,200 | [
"graphs",
"implementation"
] | null | null | This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in a large corporation. The computer network of this corporation consists of *n* computers, some of them are connected by a cable. The computers are indexed by integers from 1 to *n*. It's known that any two computers connected by cable directly or through other computers
Polycarpus decided to find out the network's topology. A network topology is the way of describing the network configuration, the scheme that shows the location and the connections of network devices.
Polycarpus knows three main network topologies: bus, ring and star. A bus is the topology that represents a shared cable with all computers connected with it. In the ring topology the cable connects each computer only with two other ones. A star is the topology where all computers of a network are connected to the single central node.
Let's represent each of these network topologies as a connected non-directed graph. A bus is a connected graph that is the only path, that is, the graph where all nodes are connected with two other ones except for some two nodes that are the beginning and the end of the path. A ring is a connected graph, where all nodes are connected with two other ones. A star is a connected graph, where a single central node is singled out and connected with all other nodes. For clarifications, see the picture.
You've got a connected non-directed graph that characterizes the computer network in Polycarpus' corporation. Help him find out, which topology type the given network is. If that is impossible to do, say that the network's topology is unknown. | The first line contains two space-separated integers *n* and *m* (4<=≤<=*n*<=≤<=105; 3<=≤<=*m*<=≤<=105) — the number of nodes and edges in the graph, correspondingly. Next *m* lines contain the description of the graph's edges. The *i*-th line contains a space-separated pair of integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the numbers of nodes that are connected by the *i*-the edge.
It is guaranteed that the given graph is connected. There is at most one edge between any two nodes. No edge connects a node with itself. | In a single line print the network topology name of the given graph. If the answer is the bus, print "bus topology" (without the quotes), if the answer is the ring, print "ring topology" (without the quotes), if the answer is the star, print "star topology" (without the quotes). If no answer fits, print "unknown topology" (without the quotes). | [
"4 3\n1 2\n2 3\n3 4\n",
"4 4\n1 2\n2 3\n3 4\n4 1\n",
"4 3\n1 2\n1 3\n1 4\n",
"4 4\n1 2\n2 3\n3 1\n1 4\n"
] | [
"bus topology\n",
"ring topology\n",
"star topology\n",
"unknown topology\n"
] | none | 1,000 | [
{
"input": "4 3\n1 2\n2 3\n3 4",
"output": "bus topology"
},
{
"input": "4 4\n1 2\n2 3\n3 4\n4 1",
"output": "ring topology"
},
{
"input": "4 3\n1 2\n1 3\n1 4",
"output": "star topology"
},
{
"input": "4 4\n1 2\n2 3\n3 1\n1 4",
"output": "unknown topology"
},
{
"i... | 1,670,264,087 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def f(nn):
x=1
for i in range(len(nn)):
x=nn[i]
return x
n,m = list(map(int, input().split()))
nn = [0]n
a=[]
for i in range(m):
b,c = (list(map(int, input().split())))
a.append(b)
a.append(c)
nn[c-1]+=1
nn[b-1]+=1
if max(nn)==m:
print("star topology")
elif nn[0]==1 and nn[len(nn)-1]==1:
print("bus topology")
elif f(nn)==2**n:
print("ring topology")
else:
print("unknown topology") | Title: Network Topology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in a large corporation. The computer network of this corporation consists of *n* computers, some of them are connected by a cable. The computers are indexed by integers from 1 to *n*. It's known that any two computers connected by cable directly or through other computers
Polycarpus decided to find out the network's topology. A network topology is the way of describing the network configuration, the scheme that shows the location and the connections of network devices.
Polycarpus knows three main network topologies: bus, ring and star. A bus is the topology that represents a shared cable with all computers connected with it. In the ring topology the cable connects each computer only with two other ones. A star is the topology where all computers of a network are connected to the single central node.
Let's represent each of these network topologies as a connected non-directed graph. A bus is a connected graph that is the only path, that is, the graph where all nodes are connected with two other ones except for some two nodes that are the beginning and the end of the path. A ring is a connected graph, where all nodes are connected with two other ones. A star is a connected graph, where a single central node is singled out and connected with all other nodes. For clarifications, see the picture.
You've got a connected non-directed graph that characterizes the computer network in Polycarpus' corporation. Help him find out, which topology type the given network is. If that is impossible to do, say that the network's topology is unknown.
Input Specification:
The first line contains two space-separated integers *n* and *m* (4<=≤<=*n*<=≤<=105; 3<=≤<=*m*<=≤<=105) — the number of nodes and edges in the graph, correspondingly. Next *m* lines contain the description of the graph's edges. The *i*-th line contains a space-separated pair of integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the numbers of nodes that are connected by the *i*-the edge.
It is guaranteed that the given graph is connected. There is at most one edge between any two nodes. No edge connects a node with itself.
Output Specification:
In a single line print the network topology name of the given graph. If the answer is the bus, print "bus topology" (without the quotes), if the answer is the ring, print "ring topology" (without the quotes), if the answer is the star, print "star topology" (without the quotes). If no answer fits, print "unknown topology" (without the quotes).
Demo Input:
['4 3\n1 2\n2 3\n3 4\n', '4 4\n1 2\n2 3\n3 4\n4 1\n', '4 3\n1 2\n1 3\n1 4\n', '4 4\n1 2\n2 3\n3 1\n1 4\n']
Demo Output:
['bus topology\n', 'ring topology\n', 'star topology\n', 'unknown topology\n']
Note:
none | ```python
def f(nn):
x=1
for i in range(len(nn)):
x=nn[i]
return x
n,m = list(map(int, input().split()))
nn = [0]n
a=[]
for i in range(m):
b,c = (list(map(int, input().split())))
a.append(b)
a.append(c)
nn[c-1]+=1
nn[b-1]+=1
if max(nn)==m:
print("star topology")
elif nn[0]==1 and nn[len(nn)-1]==1:
print("bus topology")
elif f(nn)==2**n:
print("ring topology")
else:
print("unknown topology")
``` | -1 | |
426 | B | Sereja and Mirroring | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
- the upper half of matrix *c* (rows with numbers from 1 to *x*) exactly matches *b*; - the lower half of matrix *c* (rows with numbers from *x*<=+<=1 to 2*x*) is symmetric to the upper one; the symmetry line is the line that separates two halves (the line that goes in the middle, between rows *x* and *x*<=+<=1).
Sereja has an *n*<=×<=*m* matrix *a*. He wants to find such matrix *b*, that it can be transformed into matrix *a*, if we'll perform on it several (possibly zero) mirrorings. What minimum number of rows can such matrix contain? | The first line contains two integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains *m* integers — the elements of matrix *a*. The *i*-th line contains integers *a**i*1,<=*a**i*2,<=...,<=*a**im* (0<=≤<=*a**ij*<=≤<=1) — the *i*-th row of the matrix *a*. | In the single line, print the answer to the problem — the minimum number of rows of matrix *b*. | [
"4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1\n",
"3 3\n0 0 0\n0 0 0\n0 0 0\n",
"8 1\n0\n1\n1\n0\n0\n1\n1\n0\n"
] | [
"2\n",
"3\n",
"2\n"
] | In the first test sample the answer is a 2 × 3 matrix *b*:
If we perform a mirroring operation with this matrix, we get the matrix *a* that is given in the input: | 1,000 | [
{
"input": "4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1",
"output": "2"
},
{
"input": "3 3\n0 0 0\n0 0 0\n0 0 0",
"output": "3"
},
{
"input": "8 1\n0\n1\n1\n0\n0\n1\n1\n0",
"output": "2"
},
{
"input": "10 4\n0 0 1 0\n0 0 1 0\n1 1 0 1\n0 0 1 1\n1 0 1 0\n1 0 1 0\n0 0 1 1\n1 1 0 1\n0 0 1 0\... | 1,398,613,485 | 885 | Python 3 | OK | TESTS | 65 | 124 | 0 | n,m=map(int,input().split())
a=[]
for i in range(n):
a.append(''.join(input().split()))
while n%2==0:
k=0
for i in range(n//2):
if a[i]==a[n-i-1]:
k+=1
if k!=n//2:
break
n=n//2
print(n) | Title: Sereja and Mirroring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
- the upper half of matrix *c* (rows with numbers from 1 to *x*) exactly matches *b*; - the lower half of matrix *c* (rows with numbers from *x*<=+<=1 to 2*x*) is symmetric to the upper one; the symmetry line is the line that separates two halves (the line that goes in the middle, between rows *x* and *x*<=+<=1).
Sereja has an *n*<=×<=*m* matrix *a*. He wants to find such matrix *b*, that it can be transformed into matrix *a*, if we'll perform on it several (possibly zero) mirrorings. What minimum number of rows can such matrix contain?
Input Specification:
The first line contains two integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains *m* integers — the elements of matrix *a*. The *i*-th line contains integers *a**i*1,<=*a**i*2,<=...,<=*a**im* (0<=≤<=*a**ij*<=≤<=1) — the *i*-th row of the matrix *a*.
Output Specification:
In the single line, print the answer to the problem — the minimum number of rows of matrix *b*.
Demo Input:
['4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1\n', '3 3\n0 0 0\n0 0 0\n0 0 0\n', '8 1\n0\n1\n1\n0\n0\n1\n1\n0\n']
Demo Output:
['2\n', '3\n', '2\n']
Note:
In the first test sample the answer is a 2 × 3 matrix *b*:
If we perform a mirroring operation with this matrix, we get the matrix *a* that is given in the input: | ```python
n,m=map(int,input().split())
a=[]
for i in range(n):
a.append(''.join(input().split()))
while n%2==0:
k=0
for i in range(n//2):
if a[i]==a[n-i-1]:
k+=1
if k!=n//2:
break
n=n//2
print(n)
``` | 3 | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Arya will beat all present opponents. Otherwise, if all opponents are present, then they will beat Arya.
For each opponent Arya knows his schedule — whether or not he is going to present on each particular day. Tell him the maximum number of consecutive days that he will beat all present opponents.
Note, that if some day there are no opponents present, Arya still considers he beats all the present opponents. | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th opponent is going to be absent on the *i*-th day. | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,601,415,110 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 124 | 0 | n_opps, n_days = input().strip().split()
n_days = int(n_days)
n_opps = int(n_opps)
max_cons_wins = 0
curr_cons_wins = 0
for _ in range(n_days):
n_dayopps = sum(c == '1' for c in input())
if n_dayopps != n_opps:
curr_cons_wins += 1
else:
curr_cons_wins = 0
max_cons_wins = max(max_cons_wins, curr_cons_wins)
print(max_cons_wins)
| Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Arya will beat all present opponents. Otherwise, if all opponents are present, then they will beat Arya.
For each opponent Arya knows his schedule — whether or not he is going to present on each particular day. Tell him the maximum number of consecutive days that he will beat all present opponents.
Note, that if some day there are no opponents present, Arya still considers he beats all the present opponents.
Input Specification:
The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th opponent is going to be absent on the *i*-th day.
Output Specification:
Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents.
Demo Input:
['2 2\n10\n00\n', '4 1\n0100\n', '4 5\n1101\n1111\n0110\n1011\n1111\n']
Demo Output:
['2\n', '1\n', '2\n']
Note:
In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | ```python
n_opps, n_days = input().strip().split()
n_days = int(n_days)
n_opps = int(n_opps)
max_cons_wins = 0
curr_cons_wins = 0
for _ in range(n_days):
n_dayopps = sum(c == '1' for c in input())
if n_dayopps != n_opps:
curr_cons_wins += 1
else:
curr_cons_wins = 0
max_cons_wins = max(max_cons_wins, curr_cons_wins)
print(max_cons_wins)
``` | 3 | |
1,006 | F | Xor-Paths | PROGRAMMING | 2,100 | [
"bitmasks",
"brute force",
"dp",
"meet-in-the-middle"
] | null | null | There is a rectangular grid of size $n \times m$. Each cell has a number written on it; the number on the cell ($i, j$) is $a_{i, j}$. Your task is to calculate the number of paths from the upper-left cell ($1, 1$) to the bottom-right cell ($n, m$) meeting the following constraints:
- You can move to the right or to the bottom only. Formally, from the cell ($i, j$) you may move to the cell ($i, j + 1$) or to the cell ($i + 1, j$). The target cell can't be outside of the grid. - The xor of all the numbers on the path from the cell ($1, 1$) to the cell ($n, m$) must be equal to $k$ (xor operation is the bitwise exclusive OR, it is represented as '^' in Java or C++ and "xor" in Pascal).
Find the number of such paths in the given grid. | The first line of the input contains three integers $n$, $m$ and $k$ ($1 \le n, m \le 20$, $0 \le k \le 10^{18}$) — the height and the width of the grid, and the number $k$.
The next $n$ lines contain $m$ integers each, the $j$-th element in the $i$-th line is $a_{i, j}$ ($0 \le a_{i, j} \le 10^{18}$). | Print one integer — the number of paths from ($1, 1$) to ($n, m$) with xor sum equal to $k$. | [
"3 3 11\n2 1 5\n7 10 0\n12 6 4\n",
"3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1\n",
"3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1\n"
] | [
"3\n",
"5\n",
"0\n"
] | All the paths from the first example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3)$.
All the paths from the second example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (2, 4) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (1, 3) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$. | 0 | [
{
"input": "3 3 11\n2 1 5\n7 10 0\n12 6 4",
"output": "3"
},
{
"input": "3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1",
"output": "5"
},
{
"input": "3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1",
"output": "0"
},
{
"input": "1 1 1000000000000000000\n1000000000000000000",
"outpu... | 1,686,917,365 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 92 | 2,867,200 | import sys
sys.stdin = open("input.txt", "r")
sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
input = sys.stdin.readline
n,m,k = map(int, input().split(' '))
arr = [ list(map(int, input().split(' '))) for i in range(n) ]
def solve(arr,i, j, xor):
if(i == n-1 and j == m-1 and xor^arr[i][j] == k):
return 1
elif (i == n-1 and j == m-1 and xor^arr[i][j] != k):
return 0
ans = 0
xor = xor ^ arr[i][j]
# we can go down or right
if(i < n-1):
ans += solve(arr, i+1, j, xor)
if(j < m-1):
ans += solve(arr, i, j+1, xor)
return ans
t = solve(arr, 0,0,0)
print(t) | Title: Xor-Paths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of size $n \times m$. Each cell has a number written on it; the number on the cell ($i, j$) is $a_{i, j}$. Your task is to calculate the number of paths from the upper-left cell ($1, 1$) to the bottom-right cell ($n, m$) meeting the following constraints:
- You can move to the right or to the bottom only. Formally, from the cell ($i, j$) you may move to the cell ($i, j + 1$) or to the cell ($i + 1, j$). The target cell can't be outside of the grid. - The xor of all the numbers on the path from the cell ($1, 1$) to the cell ($n, m$) must be equal to $k$ (xor operation is the bitwise exclusive OR, it is represented as '^' in Java or C++ and "xor" in Pascal).
Find the number of such paths in the given grid.
Input Specification:
The first line of the input contains three integers $n$, $m$ and $k$ ($1 \le n, m \le 20$, $0 \le k \le 10^{18}$) — the height and the width of the grid, and the number $k$.
The next $n$ lines contain $m$ integers each, the $j$-th element in the $i$-th line is $a_{i, j}$ ($0 \le a_{i, j} \le 10^{18}$).
Output Specification:
Print one integer — the number of paths from ($1, 1$) to ($n, m$) with xor sum equal to $k$.
Demo Input:
['3 3 11\n2 1 5\n7 10 0\n12 6 4\n', '3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1\n', '3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1\n']
Demo Output:
['3\n', '5\n', '0\n']
Note:
All the paths from the first example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3)$.
All the paths from the second example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (2, 4) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (1, 3) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$. | ```python
import sys
sys.stdin = open("input.txt", "r")
sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
input = sys.stdin.readline
n,m,k = map(int, input().split(' '))
arr = [ list(map(int, input().split(' '))) for i in range(n) ]
def solve(arr,i, j, xor):
if(i == n-1 and j == m-1 and xor^arr[i][j] == k):
return 1
elif (i == n-1 and j == m-1 and xor^arr[i][j] != k):
return 0
ans = 0
xor = xor ^ arr[i][j]
# we can go down or right
if(i < n-1):
ans += solve(arr, i+1, j, xor)
if(j < m-1):
ans += solve(arr, i, j+1, xor)
return ans
t = solve(arr, 0,0,0)
print(t)
``` | -1 | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem. | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,679,984,635 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n=int(input())
l=list(map(int,input().split()))
l2=set(l)
l3=list(l2)
l3.sort()
if len(l3)==1:
print("NO")
else:
print(l3[1]) | Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem.
Input Specification:
The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value.
Output Specification:
If the given sequence has the second order statistics, output this order statistics, otherwise output NO.
Demo Input:
['4\n1 2 2 -4\n', '5\n1 2 3 1 1\n']
Demo Output:
['1\n', '2\n']
Note:
none | ```python
n=int(input())
l=list(map(int,input().split()))
l2=set(l)
l3=list(l2)
l3.sort()
if len(l3)==1:
print("NO")
else:
print(l3[1])
``` | 3.977 |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a**k*) and delete it, at that all elements equal to *a**k*<=+<=1 and *a**k*<=-<=1 also must be deleted from the sequence. That step brings *a**k* points to the player.
Alex is a perfectionist, so he decided to get as many points as possible. Help him. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,681,903,423 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 171 | 7,065,600 | n = int(input())
a = [int(ak) for ak in input().split()]
count_num = [0] * 100001
for ak in a:
count_num[ak] += 1
dp = [0] * 100001
dp[1] = count_num[1]
for ak in range(2,len(dp)):
dp[ak] = max(dp[ak-1], dp[ak-2]+count_num[ak]*ak)
print(dp[-1]) | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a**k*) and delete it, at that all elements equal to *a**k*<=+<=1 and *a**k*<=-<=1 also must be deleted from the sequence. That step brings *a**k* points to the player.
Alex is a perfectionist, so he decided to get as many points as possible. Help him.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105).
Output Specification:
Print a single integer — the maximum number of points that Alex can earn.
Demo Input:
['2\n1 2\n', '3\n1 2 3\n', '9\n1 2 1 3 2 2 2 2 3\n']
Demo Output:
['2\n', '4\n', '10\n']
Note:
Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | ```python
n = int(input())
a = [int(ak) for ak in input().split()]
count_num = [0] * 100001
for ak in a:
count_num[ak] += 1
dp = [0] * 100001
dp[1] = count_num[1]
for ak in range(2,len(dp)):
dp[ak] = max(dp[ak-1], dp[ak-2]+count_num[ak]*ak)
print(dp[-1])
``` | 3 | |
660 | D | Number of Parallelograms | PROGRAMMING | 1,900 | [
"geometry"
] | null | null | You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of points.
Each of the next *n* lines contains two integers (*x**i*,<=*y**i*) (0<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th point. | Print the only integer *c* — the number of parallelograms with the vertices at the given points. | [
"4\n0 1\n1 0\n1 1\n2 0\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "4\n0 1\n1 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n0 0",
"output": "0"
},
{
"input": "1\n6 6",
"output": "0"
},
{
"input": "5\n1 5\n4 2\n4 4\n8 1\n8 2",
"output": "0"
},
{
"input": "10\n1 7\n2 14\n3 7\n3 13\n5 13\n13 10\n15 12\n17 1\n18 8\n19 0",
... | 1,698,774,060 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 21 | 1,606 | 268,390,400 | from sys import stdin
input = lambda: stdin.buffer.readline().decode().strip()
from collections import Counter
points = []
n = int(input())
for _ in range(n):
x, y = map(int, input().split())
points += [(x, y)]
midPoints = Counter()
for i in range(n):
x1, y1 = points[i]
for j in range(i+1, n):
x2, y2 = points[j]
midPoints[(x1 + x2, y1 + y2)] += 1
ans = 0
for _, k in midPoints.items():
ans += k * (k-1) // 2
print(ans) | Title: Number of Parallelograms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of points.
Each of the next *n* lines contains two integers (*x**i*,<=*y**i*) (0<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th point.
Output Specification:
Print the only integer *c* — the number of parallelograms with the vertices at the given points.
Demo Input:
['4\n0 1\n1 0\n1 1\n2 0\n']
Demo Output:
['1\n']
Note:
none | ```python
from sys import stdin
input = lambda: stdin.buffer.readline().decode().strip()
from collections import Counter
points = []
n = int(input())
for _ in range(n):
x, y = map(int, input().split())
points += [(x, y)]
midPoints = Counter()
for i in range(n):
x1, y1 = points[i]
for j in range(i+1, n):
x2, y2 = points[j]
midPoints[(x1 + x2, y1 + y2)] += 1
ans = 0
for _, k in midPoints.items():
ans += k * (k-1) // 2
print(ans)
``` | 0 | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV sets, and he has no desire to go to the sale for the second time. Please, help Bob find out the maximum sum of money that he can earn. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,610,305,210 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 124 | 0 | n, m = map(int, input().split())
prices = list(map(int, input().split()))
prices.sort()
money = 0
for t in range(m):
if prices[0] < 0:
money -= prices.pop(0)
else:
break
print(money) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV sets, and he has no desire to go to the sale for the second time. Please, help Bob find out the maximum sum of money that he can earn.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets.
Output Specification:
Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets.
Demo Input:
['5 3\n-6 0 35 -2 4\n', '4 2\n7 0 0 -7\n']
Demo Output:
['8\n', '7\n']
Note:
none | ```python
n, m = map(int, input().split())
prices = list(map(int, input().split()))
prices.sort()
money = 0
for t in range(m):
if prices[0] < 0:
money -= prices.pop(0)
else:
break
print(money)
``` | 3.969 |
912 | B | New Year's Eve | PROGRAMMING | 1,300 | [
"bitmasks",
"constructive algorithms",
"number theory"
] | null | null | Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* corresponding to its tastiness. No two candies have the same tastiness.
The choice of candies has a direct effect on Grisha's happiness. One can assume that he should take the tastiest ones — but no, the holiday magic turns things upside down. It is the xor-sum of tastinesses that matters, not the ordinary sum!
A xor-sum of a sequence of integers *a*1,<=*a*2,<=...,<=*a**m* is defined as the bitwise XOR of all its elements: , here denotes the bitwise XOR operation; more about bitwise XOR can be found [here.](https://en.wikipedia.org/wiki/Bitwise_operation#XOR)
Ded Moroz warned Grisha he has more houses to visit, so Grisha can take no more than *k* candies from the bag. Help Grisha determine the largest xor-sum (largest xor-sum means maximum happiness!) he can obtain. | The sole string contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1018). | Output one number — the largest possible xor-sum. | [
"4 3\n",
"6 6\n"
] | [
"7\n",
"7\n"
] | In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.
In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7. | 1,000 | [
{
"input": "4 3",
"output": "7"
},
{
"input": "6 6",
"output": "7"
},
{
"input": "2 2",
"output": "3"
},
{
"input": "1022 10",
"output": "1023"
},
{
"input": "415853337373441 52",
"output": "562949953421311"
},
{
"input": "75 12",
"output": "127"
... | 1,657,604,061 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 47 | 92 | 5,017,600 | import sys
import math
import collections
import heapq
input=sys.stdin.readline
n,k=(int(i) for i in input().split())
if(k==1):
print(n)
else:
print(pow(2,int(math.log(n,2))+1)-1) | Title: New Year's Eve
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* corresponding to its tastiness. No two candies have the same tastiness.
The choice of candies has a direct effect on Grisha's happiness. One can assume that he should take the tastiest ones — but no, the holiday magic turns things upside down. It is the xor-sum of tastinesses that matters, not the ordinary sum!
A xor-sum of a sequence of integers *a*1,<=*a*2,<=...,<=*a**m* is defined as the bitwise XOR of all its elements: , here denotes the bitwise XOR operation; more about bitwise XOR can be found [here.](https://en.wikipedia.org/wiki/Bitwise_operation#XOR)
Ded Moroz warned Grisha he has more houses to visit, so Grisha can take no more than *k* candies from the bag. Help Grisha determine the largest xor-sum (largest xor-sum means maximum happiness!) he can obtain.
Input Specification:
The sole string contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1018).
Output Specification:
Output one number — the largest possible xor-sum.
Demo Input:
['4 3\n', '6 6\n']
Demo Output:
['7\n', '7\n']
Note:
In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.
In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7. | ```python
import sys
import math
import collections
import heapq
input=sys.stdin.readline
n,k=(int(i) for i in input().split())
if(k==1):
print(n)
else:
print(pow(2,int(math.log(n,2))+1)-1)
``` | 0 | |
91 | A | Newspaper Headline | PROGRAMMING | 1,500 | [
"greedy",
"strings"
] | A. Newspaper Headline | 2 | 256 | A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order to get one big string. After that walrus erase several letters from this string in order to get a new word *s*2. It is considered that when Fangy erases some letter, there's no whitespace formed instead of the letter. That is, the string remains unbroken and it still only consists of lowercase Latin letters.
For example, the heading is "abc". If we take two such headings and glue them one to the other one, we get "abcabc". If we erase the letters on positions 1 and 5, we get a word "bcac".
Which least number of newspaper headings *s*1 will Fangy need to glue them, erase several letters and get word *s*2? | The input data contain two lines. The first line contain the heading *s*1, the second line contains the word *s*2. The lines only consist of lowercase Latin letters (1<=≤<=|*s*1|<=≤<=104,<=1<=≤<=|*s*2|<=≤<=106). | If it is impossible to get the word *s*2 in the above-described manner, print "-1" (without the quotes). Otherwise, print the least number of newspaper headings *s*1, which Fangy will need to receive the word *s*2. | [
"abc\nxyz\n",
"abcd\ndabc\n"
] | [
"-1\n",
"2\n"
] | none | 500 | [
{
"input": "abc\nxyz",
"output": "-1"
},
{
"input": "abcd\ndabc",
"output": "2"
},
{
"input": "ab\nbabaaab",
"output": "5"
},
{
"input": "ab\nbaaabba",
"output": "6"
},
{
"input": "fbaaigiihhfaahgdbddgeggjdeigfadhfddja\nhbghjgijijcdafcbgiedichdeebaddfddb",
"ou... | 1,626,174,662 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 340 | 6,758,400 | a,s1,s2=1,input(),input();s=s1
while s1.find(s2)==-1 and a-10001:
s1+=s
a+=1
print(a if a-10001 else -1) | Title: Newspaper Headline
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order to get one big string. After that walrus erase several letters from this string in order to get a new word *s*2. It is considered that when Fangy erases some letter, there's no whitespace formed instead of the letter. That is, the string remains unbroken and it still only consists of lowercase Latin letters.
For example, the heading is "abc". If we take two such headings and glue them one to the other one, we get "abcabc". If we erase the letters on positions 1 and 5, we get a word "bcac".
Which least number of newspaper headings *s*1 will Fangy need to glue them, erase several letters and get word *s*2?
Input Specification:
The input data contain two lines. The first line contain the heading *s*1, the second line contains the word *s*2. The lines only consist of lowercase Latin letters (1<=≤<=|*s*1|<=≤<=104,<=1<=≤<=|*s*2|<=≤<=106).
Output Specification:
If it is impossible to get the word *s*2 in the above-described manner, print "-1" (without the quotes). Otherwise, print the least number of newspaper headings *s*1, which Fangy will need to receive the word *s*2.
Demo Input:
['abc\nxyz\n', 'abcd\ndabc\n']
Demo Output:
['-1\n', '2\n']
Note:
none | ```python
a,s1,s2=1,input(),input();s=s1
while s1.find(s2)==-1 and a-10001:
s1+=s
a+=1
print(a if a-10001 else -1)
``` | 0 |
715 | B | Complete The Graph | PROGRAMMING | 2,300 | [
"binary search",
"constructive algorithms",
"graphs",
"shortest paths"
] | null | null | ZS the Coder has drawn an undirected graph of *n* vertices numbered from 0 to *n*<=-<=1 and *m* edges between them. Each edge of the graph is weighted, each weight is a positive integer.
The next day, ZS the Coder realized that some of the weights were erased! So he wants to reassign positive integer weight to each of the edges which weights were erased, so that the length of the shortest path between vertices *s* and *t* in the resulting graph is exactly *L*. Can you help him? | The first line contains five integers *n*,<=*m*,<=*L*,<=*s*,<=*t* (2<=≤<=*n*<=≤<=1000,<=<=1<=≤<=*m*<=≤<=10<=000,<=<=1<=≤<=*L*<=≤<=109,<=<=0<=≤<=*s*,<=*t*<=≤<=*n*<=-<=1,<=<=*s*<=≠<=*t*) — the number of vertices, number of edges, the desired length of shortest path, starting vertex and ending vertex respectively.
Then, *m* lines describing the edges of the graph follow. *i*-th of them contains three integers, *u**i*,<=*v**i*,<=*w**i* (0<=≤<=*u**i*,<=*v**i*<=≤<=*n*<=-<=1,<=<=*u**i*<=≠<=*v**i*,<=<=0<=≤<=*w**i*<=≤<=109). *u**i* and *v**i* denote the endpoints of the edge and *w**i* denotes its weight. If *w**i* is equal to 0 then the weight of the corresponding edge was erased.
It is guaranteed that there is at most one edge between any pair of vertices. | Print "NO" (without quotes) in the only line if it's not possible to assign the weights in a required way.
Otherwise, print "YES" in the first line. Next *m* lines should contain the edges of the resulting graph, with weights assigned to edges which weights were erased. *i*-th of them should contain three integers *u**i*, *v**i* and *w**i*, denoting an edge between vertices *u**i* and *v**i* of weight *w**i*. The edges of the new graph must coincide with the ones in the graph from the input. The weights that were not erased must remain unchanged whereas the new weights can be any positive integer not exceeding 1018.
The order of the edges in the output doesn't matter. The length of the shortest path between *s* and *t* must be equal to *L*.
If there are multiple solutions, print any of them. | [
"5 5 13 0 4\n0 1 5\n2 1 2\n3 2 3\n1 4 0\n4 3 4\n",
"2 1 123456789 0 1\n0 1 0\n",
"2 1 999999999 1 0\n0 1 1000000000\n"
] | [
"YES\n0 1 5\n2 1 2\n3 2 3\n1 4 8\n4 3 4\n",
"YES\n0 1 123456789\n",
"NO\n"
] | Here's how the graph in the first sample case looks like :
In the first sample case, there is only one missing edge weight. Placing the weight of 8 gives a shortest path from 0 to 4 of length 13.
In the second sample case, there is only a single edge. Clearly, the only way is to replace the missing weight with 123456789.
In the last sample case, there is no weights to assign but the length of the shortest path doesn't match the required value, so the answer is "NO". | 1,000 | [
{
"input": "5 5 13 0 4\n0 1 5\n2 1 2\n3 2 3\n1 4 0\n4 3 4",
"output": "YES\n0 1 5\n2 1 2\n3 2 3\n1 4 8\n4 3 4"
},
{
"input": "2 1 123456789 0 1\n0 1 0",
"output": "YES\n0 1 123456789"
},
{
"input": "2 1 999999999 1 0\n0 1 1000000000",
"output": "NO"
},
{
"input": "4 5 10 1 2\... | 1,611,332,199 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define fio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define ll long long
#define en cin.close();return 0;
#define INF ((ll)(4e18))
#define pb push_back
#define fi first//printf("%lli\n",cur);
#define se second//scanf("%lli",&n);
using namespace std;
const ll N = 1005;
vector<pair<ll,ll> > g[N], g2[N];
ll dist[N], par[N];
int main()
{
fio
//ifstream cin("in.inn");
ll n, m, l, s, t;
cin >> n >> m >> l >> s >> t;
vector<pair<pair<ll,ll>,ll> > p(m);
map<pair<ll,ll>,pair<ll,ll> > mp;
for(auto &i:p)
{
ll u, v, w;
cin >> u >> v >> w;
i={{u,v},((!w)?INF/4:w)};
if(w)
g[u].pb({v,w}),
g[v].pb({u,w});
g2[u].pb({v,max(1ll,w)}),
g2[v].pb({u,max(1ll,w)});
mp[{u,v}]={mp.size()/2,w};
mp[{v,u}]={mp.size()/2,w};
}
for(ll i = 1;i<=n;i++)
dist[i]=INF;
dist[s]=0;
priority_queue<pair<ll,ll> > pq;
pq.push({0,s});
while(!pq.empty())
{
ll u = pq.top().se;
ll d = -pq.top().fi;
pq.pop();
if(dist[u]<d)
continue;
for(auto v:g[u])
if(dist[v.fi]>dist[u]+v.se)
dist[v.fi]=dist[u]+v.se,
pq.push({-dist[v.fi],v.fi});
}
if(dist[t]<l)
{
cout << "NO";en
return 0;
}
for(ll i = 1;i<=n;i++)
dist[i]=INF;
dist[s]=0;
pq.push({0,s});
while(!pq.empty())
{
ll u = pq.top().se;
ll d = -pq.top().fi;
pq.pop();
if(dist[u]<d)
continue;
for(auto v:g2[u])
if(dist[v.fi]>dist[u]+v.se)
dist[v.fi]=dist[u]+v.se,
pq.push({-dist[v.fi],v.fi}),
par[v.fi]=u;
}
if(dist[t]>l)
{
cout << "NO";en
return 0;
}
ll it = t, c = 0;
while(it!=s)
{
auto t2 = mp[{it,par[it]}];
if(!t2.se)
{
p[t2.fi].se=((!c++)?l-dist[t]+1:1ll);
break;
}
it=par[it];
}
cout << "YES\n";
for(auto i:p)
cout << i.fi.fi << " " << i.fi.se << " " << i.se << "\n";
//cin.close();
return 0;
}
| Title: Complete The Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder has drawn an undirected graph of *n* vertices numbered from 0 to *n*<=-<=1 and *m* edges between them. Each edge of the graph is weighted, each weight is a positive integer.
The next day, ZS the Coder realized that some of the weights were erased! So he wants to reassign positive integer weight to each of the edges which weights were erased, so that the length of the shortest path between vertices *s* and *t* in the resulting graph is exactly *L*. Can you help him?
Input Specification:
The first line contains five integers *n*,<=*m*,<=*L*,<=*s*,<=*t* (2<=≤<=*n*<=≤<=1000,<=<=1<=≤<=*m*<=≤<=10<=000,<=<=1<=≤<=*L*<=≤<=109,<=<=0<=≤<=*s*,<=*t*<=≤<=*n*<=-<=1,<=<=*s*<=≠<=*t*) — the number of vertices, number of edges, the desired length of shortest path, starting vertex and ending vertex respectively.
Then, *m* lines describing the edges of the graph follow. *i*-th of them contains three integers, *u**i*,<=*v**i*,<=*w**i* (0<=≤<=*u**i*,<=*v**i*<=≤<=*n*<=-<=1,<=<=*u**i*<=≠<=*v**i*,<=<=0<=≤<=*w**i*<=≤<=109). *u**i* and *v**i* denote the endpoints of the edge and *w**i* denotes its weight. If *w**i* is equal to 0 then the weight of the corresponding edge was erased.
It is guaranteed that there is at most one edge between any pair of vertices.
Output Specification:
Print "NO" (without quotes) in the only line if it's not possible to assign the weights in a required way.
Otherwise, print "YES" in the first line. Next *m* lines should contain the edges of the resulting graph, with weights assigned to edges which weights were erased. *i*-th of them should contain three integers *u**i*, *v**i* and *w**i*, denoting an edge between vertices *u**i* and *v**i* of weight *w**i*. The edges of the new graph must coincide with the ones in the graph from the input. The weights that were not erased must remain unchanged whereas the new weights can be any positive integer not exceeding 1018.
The order of the edges in the output doesn't matter. The length of the shortest path between *s* and *t* must be equal to *L*.
If there are multiple solutions, print any of them.
Demo Input:
['5 5 13 0 4\n0 1 5\n2 1 2\n3 2 3\n1 4 0\n4 3 4\n', '2 1 123456789 0 1\n0 1 0\n', '2 1 999999999 1 0\n0 1 1000000000\n']
Demo Output:
['YES\n0 1 5\n2 1 2\n3 2 3\n1 4 8\n4 3 4\n', 'YES\n0 1 123456789\n', 'NO\n']
Note:
Here's how the graph in the first sample case looks like :
In the first sample case, there is only one missing edge weight. Placing the weight of 8 gives a shortest path from 0 to 4 of length 13.
In the second sample case, there is only a single edge. Clearly, the only way is to replace the missing weight with 123456789.
In the last sample case, there is no weights to assign but the length of the shortest path doesn't match the required value, so the answer is "NO". | ```python
#include <bits/stdc++.h>
#define fio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define ll long long
#define en cin.close();return 0;
#define INF ((ll)(4e18))
#define pb push_back
#define fi first//printf("%lli\n",cur);
#define se second//scanf("%lli",&n);
using namespace std;
const ll N = 1005;
vector<pair<ll,ll> > g[N], g2[N];
ll dist[N], par[N];
int main()
{
fio
//ifstream cin("in.inn");
ll n, m, l, s, t;
cin >> n >> m >> l >> s >> t;
vector<pair<pair<ll,ll>,ll> > p(m);
map<pair<ll,ll>,pair<ll,ll> > mp;
for(auto &i:p)
{
ll u, v, w;
cin >> u >> v >> w;
i={{u,v},((!w)?INF/4:w)};
if(w)
g[u].pb({v,w}),
g[v].pb({u,w});
g2[u].pb({v,max(1ll,w)}),
g2[v].pb({u,max(1ll,w)});
mp[{u,v}]={mp.size()/2,w};
mp[{v,u}]={mp.size()/2,w};
}
for(ll i = 1;i<=n;i++)
dist[i]=INF;
dist[s]=0;
priority_queue<pair<ll,ll> > pq;
pq.push({0,s});
while(!pq.empty())
{
ll u = pq.top().se;
ll d = -pq.top().fi;
pq.pop();
if(dist[u]<d)
continue;
for(auto v:g[u])
if(dist[v.fi]>dist[u]+v.se)
dist[v.fi]=dist[u]+v.se,
pq.push({-dist[v.fi],v.fi});
}
if(dist[t]<l)
{
cout << "NO";en
return 0;
}
for(ll i = 1;i<=n;i++)
dist[i]=INF;
dist[s]=0;
pq.push({0,s});
while(!pq.empty())
{
ll u = pq.top().se;
ll d = -pq.top().fi;
pq.pop();
if(dist[u]<d)
continue;
for(auto v:g2[u])
if(dist[v.fi]>dist[u]+v.se)
dist[v.fi]=dist[u]+v.se,
pq.push({-dist[v.fi],v.fi}),
par[v.fi]=u;
}
if(dist[t]>l)
{
cout << "NO";en
return 0;
}
ll it = t, c = 0;
while(it!=s)
{
auto t2 = mp[{it,par[it]}];
if(!t2.se)
{
p[t2.fi].se=((!c++)?l-dist[t]+1:1ll);
break;
}
it=par[it];
}
cout << "YES\n";
for(auto i:p)
cout << i.fi.fi << " " << i.fi.se << " " << i.se << "\n";
//cin.close();
return 0;
}
``` | -1 | |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third room and so on — you can go from the (*n*<=-<=1)-th room to the *n*-th room. Thus, you can go to room *x* only from room *x*<=-<=1.
The potato pie is located in the *n*-th room and Vitaly needs to go there.
Each pair of consecutive rooms has a door between them. In order to go to room *x* from room *x*<=-<=1, you need to open the door between the rooms with the corresponding key.
In total the house has several types of doors (represented by uppercase Latin letters) and several types of keys (represented by lowercase Latin letters). The key of type *t* can open the door of type *T* if and only if *t* and *T* are the same letter, written in different cases. For example, key f can open door F.
Each of the first *n*<=-<=1 rooms contains exactly one key of some type that Vitaly can use to get to next rooms. Once the door is open with some key, Vitaly won't get the key from the keyhole but he will immediately run into the next room. In other words, each key can open no more than one door.
Vitaly realizes that he may end up in some room without the key that opens the door to the next room. Before the start his run for the potato pie Vitaly can buy any number of keys of any type that is guaranteed to get to room *n*.
Given the plan of the house, Vitaly wants to know what is the minimum number of keys he needs to buy to surely get to the room *n*, which has a delicious potato pie. Write a program that will help Vitaly find out this number. | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain lowercase Latin letters — the types of the keys that lie in the corresponding rooms. Thus, each odd position *i* of the given string *s* contains a lowercase Latin letter — the type of the key that lies in room number (*i*<=+<=1)<=/<=2.
The even positions in the given string contain uppercase Latin letters — the types of doors between the rooms. Thus, each even position *i* of the given string *s* contains an uppercase letter — the type of the door that leads from room *i*<=/<=2 to room *i*<=/<=2<=+<=1. | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,560,014,069 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 108 | 0 | n=int(input())
s=list(str(input()))
ans=0
for i in range(0,2*(n-1),2):
#print(i)
if s[i] != (s[i+1]).lower():
ans+=1
print(ans) | Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third room and so on — you can go from the (*n*<=-<=1)-th room to the *n*-th room. Thus, you can go to room *x* only from room *x*<=-<=1.
The potato pie is located in the *n*-th room and Vitaly needs to go there.
Each pair of consecutive rooms has a door between them. In order to go to room *x* from room *x*<=-<=1, you need to open the door between the rooms with the corresponding key.
In total the house has several types of doors (represented by uppercase Latin letters) and several types of keys (represented by lowercase Latin letters). The key of type *t* can open the door of type *T* if and only if *t* and *T* are the same letter, written in different cases. For example, key f can open door F.
Each of the first *n*<=-<=1 rooms contains exactly one key of some type that Vitaly can use to get to next rooms. Once the door is open with some key, Vitaly won't get the key from the keyhole but he will immediately run into the next room. In other words, each key can open no more than one door.
Vitaly realizes that he may end up in some room without the key that opens the door to the next room. Before the start his run for the potato pie Vitaly can buy any number of keys of any type that is guaranteed to get to room *n*.
Given the plan of the house, Vitaly wants to know what is the minimum number of keys he needs to buy to surely get to the room *n*, which has a delicious potato pie. Write a program that will help Vitaly find out this number.
Input Specification:
The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain lowercase Latin letters — the types of the keys that lie in the corresponding rooms. Thus, each odd position *i* of the given string *s* contains a lowercase Latin letter — the type of the key that lies in room number (*i*<=+<=1)<=/<=2.
The even positions in the given string contain uppercase Latin letters — the types of doors between the rooms. Thus, each even position *i* of the given string *s* contains an uppercase letter — the type of the door that leads from room *i*<=/<=2 to room *i*<=/<=2<=+<=1.
Output Specification:
Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*.
Demo Input:
['3\naAbB\n', '4\naBaCaB\n', '5\nxYyXzZaZ\n']
Demo Output:
['0\n', '3\n', '2\n']
Note:
none | ```python
n=int(input())
s=list(str(input()))
ans=0
for i in range(0,2*(n-1),2):
#print(i)
if s[i] != (s[i+1]).lower():
ans+=1
print(ans)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Родители Васи хотят, чтобы он как можно лучше учился. Поэтому если он получает подряд три положительные оценки («четвёрки» или «пятёрки»), они дарят ему подарок. Соответственно, оценки «единица», «двойка» и «тройка» родители Васи считают плохими. Когда Вася получает подряд три хорошие оценки, ему сразу вручают подарок, но для того, чтобы получить ещё один подарок, ему вновь надо получить подряд ещё три хорошие оценки.
Например, если Вася получит подряд пять «четвёрок» оценок, а потом «двойку», то ему дадут только один подарок, а вот если бы «четвёрок» было уже шесть, то подарков было бы два.
За месяц Вася получил *n* оценок. Вам предстоит посчитать количество подарков, которые получил Вася. Оценки будут даны именно в том порядке, в котором Вася их получал. | В первой строке входных данных следует целое положительное число *n* (3<=≤<=*n*<=≤<=1000) — количество оценок, полученных Васей.
Во второй строке входных данных следует последовательность из *n* чисел *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5) — оценки, полученные Васей. Оценки заданы в том порядке, в котором Вася их получил. | Выведите одно целое число — количество подарков, полученных Васей. | [
"6\n4 5 4 5 4 4\n",
"14\n1 5 4 5 2 4 4 5 5 4 3 4 5 5\n"
] | [
"2\n",
"3\n"
] | В первом примере Вася получит два подарка — за первые три положительные оценки и за следующую тройку положительных оценок соответственно. | 0 | [
{
"input": "6\n4 5 4 5 4 4",
"output": "2"
},
{
"input": "14\n1 5 4 5 2 4 4 5 5 4 3 4 5 5",
"output": "3"
},
{
"input": "3\n4 5 4",
"output": "1"
},
{
"input": "3\n4 5 1",
"output": "0"
},
{
"input": "4\n5 4 3 5",
"output": "0"
},
{
"input": "10\n4 4 5... | 1,458,813,035 | 6,635 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 4,608,000 | n = int(input())
a = []
r = 0
a = input().split()
for i in range(n) :
a[i] = int(a[i])
scane = 0
while scane < ( n - 3 ) :
plus = 0
if a[scane] > 3 :
plus+=1
if a[scane+1] > 3 and a[scane+2] > 3 :
r+=1
plus+=1
scane+=(plus)
else :
scane+=1
print(r)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Родители Васи хотят, чтобы он как можно лучше учился. Поэтому если он получает подряд три положительные оценки («четвёрки» или «пятёрки»), они дарят ему подарок. Соответственно, оценки «единица», «двойка» и «тройка» родители Васи считают плохими. Когда Вася получает подряд три хорошие оценки, ему сразу вручают подарок, но для того, чтобы получить ещё один подарок, ему вновь надо получить подряд ещё три хорошие оценки.
Например, если Вася получит подряд пять «четвёрок» оценок, а потом «двойку», то ему дадут только один подарок, а вот если бы «четвёрок» было уже шесть, то подарков было бы два.
За месяц Вася получил *n* оценок. Вам предстоит посчитать количество подарков, которые получил Вася. Оценки будут даны именно в том порядке, в котором Вася их получал.
Input Specification:
В первой строке входных данных следует целое положительное число *n* (3<=≤<=*n*<=≤<=1000) — количество оценок, полученных Васей.
Во второй строке входных данных следует последовательность из *n* чисел *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5) — оценки, полученные Васей. Оценки заданы в том порядке, в котором Вася их получил.
Output Specification:
Выведите одно целое число — количество подарков, полученных Васей.
Demo Input:
['6\n4 5 4 5 4 4\n', '14\n1 5 4 5 2 4 4 5 5 4 3 4 5 5\n']
Demo Output:
['2\n', '3\n']
Note:
В первом примере Вася получит два подарка — за первые три положительные оценки и за следующую тройку положительных оценок соответственно. | ```python
n = int(input())
a = []
r = 0
a = input().split()
for i in range(n) :
a[i] = int(a[i])
scane = 0
while scane < ( n - 3 ) :
plus = 0
if a[scane] > 3 :
plus+=1
if a[scane+1] > 3 and a[scane+2] > 3 :
r+=1
plus+=1
scane+=(plus)
else :
scane+=1
print(r)
``` | 0 | |
821 | A | Okabe and Future Gadget Laboratory | PROGRAMMING | 800 | [
"implementation"
] | null | null | Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column.
Help Okabe determine whether a given lab is good! | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab.
The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105). | Print "Yes" if the given lab is good and "No" otherwise.
You can output each letter in upper or lower case. | [
"3\n1 1 2\n2 3 1\n6 4 1\n",
"3\n1 5 2\n1 1 1\n1 2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes".
In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No". | 500 | [
{
"input": "3\n1 1 2\n2 3 1\n6 4 1",
"output": "Yes"
},
{
"input": "3\n1 5 2\n1 1 1\n1 2 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 11 1 2\n2 5 1 4\n3 9 4 1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 7 1 1\n1 3 1 2\n2... | 1,498,443,798 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 967 | 5,529,600 | # Time : 2017-6-26 10:30
# Auther : Anjone
# URL : http://codeforces.com/contest/821/problem/A
n = int(input())
arr = [ list(map(int,input().split())) for i in range(n)]
for i in range(n):
for j in range(n):
if( arr[i][j] != 1):
cnt = 0
for k in range(n):
for l in range(n):
if(arr[i][k] + arr[l][j] == arr[i][j]):
cnt += 1
if(cnt == 0):
print("No")
exit(0)
print ("Yes") | Title: Okabe and Future Gadget Laboratory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column.
Help Okabe determine whether a given lab is good!
Input Specification:
The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab.
The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105).
Output Specification:
Print "Yes" if the given lab is good and "No" otherwise.
You can output each letter in upper or lower case.
Demo Input:
['3\n1 1 2\n2 3 1\n6 4 1\n', '3\n1 5 2\n1 1 1\n1 2 3\n']
Demo Output:
['Yes\n', 'No\n']
Note:
In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes".
In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No". | ```python
# Time : 2017-6-26 10:30
# Auther : Anjone
# URL : http://codeforces.com/contest/821/problem/A
n = int(input())
arr = [ list(map(int,input().split())) for i in range(n)]
for i in range(n):
for j in range(n):
if( arr[i][j] != 1):
cnt = 0
for k in range(n):
for l in range(n):
if(arr[i][k] + arr[l][j] == arr[i][j]):
cnt += 1
if(cnt == 0):
print("No")
exit(0)
print ("Yes")
``` | 3 | |
387 | C | George and Number | PROGRAMMING | 1,700 | [
"greedy",
"implementation"
] | null | null | George is a cat, so he really likes to play. Most of all he likes to play with his array of positive integers *b*. During the game, George modifies the array by using special changes. Let's mark George's current array as *b*1,<=*b*2,<=...,<=*b*|*b*| (record |*b*| denotes the current length of the array). Then one change is a sequence of actions:
- Choose two distinct indexes *i* and *j* (1<=≤<=*i*,<=*j*<=≤<=|*b*|; *i*<=≠<=*j*), such that *b**i*<=≥<=*b**j*. - Get number *v*<==<=*concat*(*b**i*,<=*b**j*), where *concat*(*x*,<=*y*) is a number obtained by adding number *y* to the end of the decimal record of number *x*. For example, *concat*(500,<=10)<==<=50010, *concat*(2,<=2)<==<=22. - Add number *v* to the end of the array. The length of the array will increase by one. - Remove from the array numbers with indexes *i* and *j*. The length of the array will decrease by two, and elements of the array will become re-numbered from 1 to current length of the array.
George played for a long time with his array *b* and received from array *b* an array consisting of exactly one number *p*. Now George wants to know: what is the maximum number of elements array *b* could contain originally? Help him find this number. Note that originally the array could contain only positive integers. | The first line of the input contains a single integer *p* (1<=≤<=*p*<=<<=10100000). It is guaranteed that number *p* doesn't contain any leading zeroes. | Print an integer — the maximum number of elements array *b* could contain originally. | [
"9555\n",
"10000000005\n",
"800101\n",
"45\n",
"1000000000000001223300003342220044555\n",
"19992000\n",
"310200\n"
] | [
"4",
"2",
"3",
"1",
"17",
"1",
"2"
] | Let's consider the test examples:
- Originally array *b* can be equal to {5, 9, 5, 5}. The sequence of George's changes could have been: {5, 9, 5, 5} → {5, 5, 95} → {95, 55} → {9555}. - Originally array *b* could be equal to {1000000000, 5}. Please note that the array *b* cannot contain zeros. - Originally array *b* could be equal to {800, 10, 1}. - Originally array *b* could be equal to {45}. It cannot be equal to {4, 5}, because George can get only array {54} from this array in one operation.
Note that the numbers can be very large. | 1,500 | [
{
"input": "9555",
"output": "4"
},
{
"input": "10000000005",
"output": "2"
},
{
"input": "800101",
"output": "3"
},
{
"input": "45",
"output": "1"
},
{
"input": "1000000000000001223300003342220044555",
"output": "17"
},
{
"input": "19992000",
"out... | 1,545,669,963 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 171 | 204,800 | p = input().strip()
n = len(p)
j = n - 1
ans = 0
while(j >= 0):
k = j
while p[k] == '0':
k -= 1
ln = j - k + 1
if ln > k:
ans += 1
j = -1
elif ln == k:
if (p[0] >= p[k]):
j = k - 1
else:
j = -1
ans += 1
else:
ans += 1
j = k - 1
print(ans)
| Title: George and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George is a cat, so he really likes to play. Most of all he likes to play with his array of positive integers *b*. During the game, George modifies the array by using special changes. Let's mark George's current array as *b*1,<=*b*2,<=...,<=*b*|*b*| (record |*b*| denotes the current length of the array). Then one change is a sequence of actions:
- Choose two distinct indexes *i* and *j* (1<=≤<=*i*,<=*j*<=≤<=|*b*|; *i*<=≠<=*j*), such that *b**i*<=≥<=*b**j*. - Get number *v*<==<=*concat*(*b**i*,<=*b**j*), where *concat*(*x*,<=*y*) is a number obtained by adding number *y* to the end of the decimal record of number *x*. For example, *concat*(500,<=10)<==<=50010, *concat*(2,<=2)<==<=22. - Add number *v* to the end of the array. The length of the array will increase by one. - Remove from the array numbers with indexes *i* and *j*. The length of the array will decrease by two, and elements of the array will become re-numbered from 1 to current length of the array.
George played for a long time with his array *b* and received from array *b* an array consisting of exactly one number *p*. Now George wants to know: what is the maximum number of elements array *b* could contain originally? Help him find this number. Note that originally the array could contain only positive integers.
Input Specification:
The first line of the input contains a single integer *p* (1<=≤<=*p*<=<<=10100000). It is guaranteed that number *p* doesn't contain any leading zeroes.
Output Specification:
Print an integer — the maximum number of elements array *b* could contain originally.
Demo Input:
['9555\n', '10000000005\n', '800101\n', '45\n', '1000000000000001223300003342220044555\n', '19992000\n', '310200\n']
Demo Output:
['4', '2', '3', '1', '17', '1', '2']
Note:
Let's consider the test examples:
- Originally array *b* can be equal to {5, 9, 5, 5}. The sequence of George's changes could have been: {5, 9, 5, 5} → {5, 5, 95} → {95, 55} → {9555}. - Originally array *b* could be equal to {1000000000, 5}. Please note that the array *b* cannot contain zeros. - Originally array *b* could be equal to {800, 10, 1}. - Originally array *b* could be equal to {45}. It cannot be equal to {4, 5}, because George can get only array {54} from this array in one operation.
Note that the numbers can be very large. | ```python
p = input().strip()
n = len(p)
j = n - 1
ans = 0
while(j >= 0):
k = j
while p[k] == '0':
k -= 1
ln = j - k + 1
if ln > k:
ans += 1
j = -1
elif ln == k:
if (p[0] >= p[k]):
j = k - 1
else:
j = -1
ans += 1
else:
ans += 1
j = k - 1
print(ans)
``` | 3 | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light. | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,662,043,138 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | a,b,c = map(int, input().split())
d,e,f = map(int, input().split())
g,h,i = map(int, input().split())
a1, b1, c1, d1, e1, f1, g1, h1, i1= 1,1,1,1,1,1,1,1,1
def lightControl(x):
if x == 1:
return x-1
else:
return x + 1
if a>0 and a%2 == 1:
a1 = lightControl(a1)
b1 = lightControl(b1)
d1 = lightControl(d1)
if b>0 and b%2 == 1:
a1 = lightControl(a1)
b1 = lightControl(b1)
c1 = lightControl(c1)
e1 = lightControl(e1)
if c>0 and c%2 == 1:
b1 = lightControl(b1)
c1 = lightControl(c1)
f1 = lightControl(f1)
if d%2 == 1 and d>0:
a1 = lightControl(a1)
d1 = lightControl(d1)
e1 = lightControl(e1)
g1 = lightControl(g1)
if e%2 == 1 and e>0:
b1 = lightControl(b1)
d1 = lightControl(d1)
e1 = lightControl(e1)
f1 = lightControl(f1)
h1 = lightControl(h1)
if f%2 == 1 and f>0:
c1 = lightControl(c1)
e1 = lightControl(e1)
f1 = lightControl(f1)
i1 = lightControl(i1)
if g%2 == 1 and g>0:
d1 = lightControl(d1)
g1 = lightControl(g1)
h1 = lightControl(h1)
if h%2 == 1 and h>0:
e1 = lightControl(e1)
g1 = lightControl(g1)
h1 = lightControl(h1)
i1 = lightControl(i1)
if i%2 == 1 and i>0:
f1 = lightControl(f1)
h1 = lightControl(h1)
i1 = lightControl(i1)
lst1 = []
lst1.append(str(a1))
lst1.append(str(b1))
lst1.append(str(c1))
lst2 = []
lst2.append(str(d1))
lst2.append(str(e1))
lst2.append(str(f1))
lst3 = []
lst3.append(str(g1))
lst3.append(str(h1))
lst3.append(str(i1))
print(''.join(lst1))
print(''.join(lst2))
print(''.join(lst3)) | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light.
Input Specification:
The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed.
Output Specification:
Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0".
Demo Input:
['1 0 0\n0 0 0\n0 0 1\n', '1 0 1\n8 8 8\n2 0 3\n']
Demo Output:
['001\n010\n100\n', '010\n011\n100\n']
Note:
none | ```python
a,b,c = map(int, input().split())
d,e,f = map(int, input().split())
g,h,i = map(int, input().split())
a1, b1, c1, d1, e1, f1, g1, h1, i1= 1,1,1,1,1,1,1,1,1
def lightControl(x):
if x == 1:
return x-1
else:
return x + 1
if a>0 and a%2 == 1:
a1 = lightControl(a1)
b1 = lightControl(b1)
d1 = lightControl(d1)
if b>0 and b%2 == 1:
a1 = lightControl(a1)
b1 = lightControl(b1)
c1 = lightControl(c1)
e1 = lightControl(e1)
if c>0 and c%2 == 1:
b1 = lightControl(b1)
c1 = lightControl(c1)
f1 = lightControl(f1)
if d%2 == 1 and d>0:
a1 = lightControl(a1)
d1 = lightControl(d1)
e1 = lightControl(e1)
g1 = lightControl(g1)
if e%2 == 1 and e>0:
b1 = lightControl(b1)
d1 = lightControl(d1)
e1 = lightControl(e1)
f1 = lightControl(f1)
h1 = lightControl(h1)
if f%2 == 1 and f>0:
c1 = lightControl(c1)
e1 = lightControl(e1)
f1 = lightControl(f1)
i1 = lightControl(i1)
if g%2 == 1 and g>0:
d1 = lightControl(d1)
g1 = lightControl(g1)
h1 = lightControl(h1)
if h%2 == 1 and h>0:
e1 = lightControl(e1)
g1 = lightControl(g1)
h1 = lightControl(h1)
i1 = lightControl(i1)
if i%2 == 1 and i>0:
f1 = lightControl(f1)
h1 = lightControl(h1)
i1 = lightControl(i1)
lst1 = []
lst1.append(str(a1))
lst1.append(str(b1))
lst1.append(str(c1))
lst2 = []
lst2.append(str(d1))
lst2.append(str(e1))
lst2.append(str(f1))
lst3 = []
lst3.append(str(g1))
lst3.append(str(h1))
lst3.append(str(i1))
print(''.join(lst1))
print(''.join(lst2))
print(''.join(lst3))
``` | 3 | |
180 | C | Letter | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were uppercase.
Patrick believes that a message is fancy if any uppercase letter stands to the left of any lowercase one. In other words, this rule describes the strings where first go zero or more uppercase letters, and then — zero or more lowercase letters.
To make the message fancy, Patrick can erase some letter and add the same letter in the same place in the opposite case (that is, he can replace an uppercase letter with the lowercase one and vice versa). Patrick got interested in the following question: what minimum number of actions do we need to make a message fancy? Changing a letter's case in the message counts as one action. Patrick cannot perform any other actions. | The only line of the input contains a non-empty string consisting of uppercase and lowercase letters. The string's length does not exceed 105. | Print a single number — the least number of actions needed to make the message fancy. | [
"PRuvetSTAaYA\n",
"OYPROSTIYAOPECHATALSYAPRIVETSTASYA\n",
"helloworld\n"
] | [
"5\n",
"0\n",
"0\n"
] | none | 0 | [
{
"input": "PRuvetSTAaYA",
"output": "5"
},
{
"input": "OYPROSTIYAOPECHATALSYAPRIVETSTASYA",
"output": "0"
},
{
"input": "helloworld",
"output": "0"
},
{
"input": "P",
"output": "0"
},
{
"input": "t",
"output": "0"
},
{
"input": "XdJ",
"output": "1... | 1,576,586,385 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 186 | 0 | s = input()
l = 0
b = 0
fl = False
for i in s:
if i.islower():
fl = True
if fl:
if i.isupper():
b += 1
else:
l += 1
if b == 0:
print(0)
else:
lb = l > b
c = 0
fl = False
for i in s:
if lb:
if fl and i.isupper():
c += 1
if i.islower():
fl = True
else:
if i.islower():
c += 1
print(c) | Title: Letter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were uppercase.
Patrick believes that a message is fancy if any uppercase letter stands to the left of any lowercase one. In other words, this rule describes the strings where first go zero or more uppercase letters, and then — zero or more lowercase letters.
To make the message fancy, Patrick can erase some letter and add the same letter in the same place in the opposite case (that is, he can replace an uppercase letter with the lowercase one and vice versa). Patrick got interested in the following question: what minimum number of actions do we need to make a message fancy? Changing a letter's case in the message counts as one action. Patrick cannot perform any other actions.
Input Specification:
The only line of the input contains a non-empty string consisting of uppercase and lowercase letters. The string's length does not exceed 105.
Output Specification:
Print a single number — the least number of actions needed to make the message fancy.
Demo Input:
['PRuvetSTAaYA\n', 'OYPROSTIYAOPECHATALSYAPRIVETSTASYA\n', 'helloworld\n']
Demo Output:
['5\n', '0\n', '0\n']
Note:
none | ```python
s = input()
l = 0
b = 0
fl = False
for i in s:
if i.islower():
fl = True
if fl:
if i.isupper():
b += 1
else:
l += 1
if b == 0:
print(0)
else:
lb = l > b
c = 0
fl = False
for i in s:
if lb:
if fl and i.isupper():
c += 1
if i.islower():
fl = True
else:
if i.islower():
c += 1
print(c)
``` | 0 | |
81 | A | Plug-in | PROGRAMMING | 1,400 | [
"implementation"
] | A. Plug-in | 1 | 256 | Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu".
Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something!
Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result. | The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters. | Print the given string after it is processed. It is guaranteed that the result will contain at least one character. | [
"hhoowaaaareyyoouu\n",
"reallazy\n",
"abacabaabacabaa\n"
] | [
"wre",
"rezy",
"a"
] | none | 500 | [
{
"input": "hhoowaaaareyyoouu",
"output": "wre"
},
{
"input": "reallazy",
"output": "rezy"
},
{
"input": "abacabaabacabaa",
"output": "a"
},
{
"input": "xraccabccbry",
"output": "xy"
},
{
"input": "a",
"output": "a"
},
{
"input": "b",
"output": "b"... | 1,618,504,029 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 2,867,200 | if __name__ == '__main__':
s, r = list(input()), []
for c in s:
if r and c == r[-1]:r.pop()
else:r.append(c)
print("".join(r)) | Title: Plug-in
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu".
Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something!
Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result.
Input Specification:
The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters.
Output Specification:
Print the given string after it is processed. It is guaranteed that the result will contain at least one character.
Demo Input:
['hhoowaaaareyyoouu\n', 'reallazy\n', 'abacabaabacabaa\n']
Demo Output:
['wre', 'rezy', 'a']
Note:
none | ```python
if __name__ == '__main__':
s, r = list(input()), []
for c in s:
if r and c == r[-1]:r.pop()
else:r.append(c)
print("".join(r))
``` | 3.885659 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,678,422,815 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 81 | 154 | 0 | #******************************
#import os
#import sys
from math import *
#import re
#import random
#sys.set_int_max_str_digits(int(1e9))
def solve():
a=[]
b=[]
c=[]
for i in range(int(input())):
#for _ in range(1):
#n = int(input())
p, q, r= [int(x) for x in input().split()]
a.append(p)
b.append(q)
c.append(r)
if(sum(a) == 0 and sum(b) == 0 and sum(c) == 0): print("YES");
else: print("NO")
solve() | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
#******************************
#import os
#import sys
from math import *
#import re
#import random
#sys.set_int_max_str_digits(int(1e9))
def solve():
a=[]
b=[]
c=[]
for i in range(int(input())):
#for _ in range(1):
#n = int(input())
p, q, r= [int(x) for x in input().split()]
a.append(p)
b.append(q)
c.append(r)
if(sum(a) == 0 and sum(b) == 0 and sum(c) == 0): print("YES");
else: print("NO")
solve()
``` | 3.9615 |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and the impulse of You-Know-Who's magic spell flies at a speed of *q* meters per second.
The impulses are moving through the corridor toward each other, and at the time of the collision they turn round and fly back to those who cast them without changing their original speeds. Then, as soon as the impulse gets back to it's caster, the wizard reflects it and sends again towards the enemy, without changing the original speed of the impulse.
Since Harry has perfectly mastered the basics of magic, he knows that after the second collision both impulses will disappear, and a powerful explosion will occur exactly in the place of their collision. However, the young wizard isn't good at math, so he asks you to calculate the distance from his position to the place of the second meeting of the spell impulses, provided that the opponents do not change positions during the whole fight. | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, respectively. | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer of the jury is *b*. The checker program will consider your answer correct if . | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,627,889,859 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 20,172,800 | n = int(input())
p = int(input())
q = int(input())
print(n*max(p,q)/100) | Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and the impulse of You-Know-Who's magic spell flies at a speed of *q* meters per second.
The impulses are moving through the corridor toward each other, and at the time of the collision they turn round and fly back to those who cast them without changing their original speeds. Then, as soon as the impulse gets back to it's caster, the wizard reflects it and sends again towards the enemy, without changing the original speed of the impulse.
Since Harry has perfectly mastered the basics of magic, he knows that after the second collision both impulses will disappear, and a powerful explosion will occur exactly in the place of their collision. However, the young wizard isn't good at math, so he asks you to calculate the distance from his position to the place of the second meeting of the spell impulses, provided that the opponents do not change positions during the whole fight.
Input Specification:
The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, respectively.
Output Specification:
Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer of the jury is *b*. The checker program will consider your answer correct if .
Demo Input:
['100\n50\n50\n', '199\n60\n40\n']
Demo Output:
['50\n', '119.4\n']
Note:
In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | ```python
n = int(input())
p = int(input())
q = int(input())
print(n*max(p,q)/100)
``` | 0 | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their height. But as there's virtually no time to do that, the soldiers lined up in the arbitrary order. However, the general is rather short-sighted and he thinks that the soldiers lined up correctly if the first soldier in the line has the maximum height and the last soldier has the minimum height. Please note that the way other solders are positioned does not matter, including the case when there are several soldiers whose height is maximum or minimum. Only the heights of the first and the last soldier are important.
For example, the general considers the sequence of heights (4, 3, 4, 2, 1, 1) correct and the sequence (4, 3, 1, 2, 2) wrong.
Within one second the colonel can swap any two neighboring soldiers. Help him count the minimum time needed to form a line-up which the general will consider correct. | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginning of the line to its end. The numbers are space-separated. Numbers *a*1,<=*a*2,<=...,<=*a**n* are not necessarily different. | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 76, 40) 1. (10, 58, 10, 31, 76, 63, 40) 1. (10, 58, 31, 10, 76, 63, 40) 1. (10, 58, 31, 76, 10, 63, 40) 1. (10, 58, 31, 76, 63, 10, 40) 1. (10, 58, 76, 31, 63, 10, 40) 1. (10, 76, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 40, 10) | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,698,604,076 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 62 | 0 | N = int(input())
järjend = list(map(int,input().split()))
pikk = max(järjend)
lühike = min(järjend)
pikka_asukoht = 0
for i in range(N):
if järjend[i] == pikk:
pikka_asukoht = i
break
lühikese_asukoht = 0
for i in range(N):
if järjend[i] == lühike:
lühikese_asukoht = i
kokku = ((N-1)-lühikese_asukoht) + pikka_asukoht
if pikka_asukoht > lühikese_asukoht:
kokku -= 1
print(kokku)
| Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their height. But as there's virtually no time to do that, the soldiers lined up in the arbitrary order. However, the general is rather short-sighted and he thinks that the soldiers lined up correctly if the first soldier in the line has the maximum height and the last soldier has the minimum height. Please note that the way other solders are positioned does not matter, including the case when there are several soldiers whose height is maximum or minimum. Only the heights of the first and the last soldier are important.
For example, the general considers the sequence of heights (4, 3, 4, 2, 1, 1) correct and the sequence (4, 3, 1, 2, 2) wrong.
Within one second the colonel can swap any two neighboring soldiers. Help him count the minimum time needed to form a line-up which the general will consider correct.
Input Specification:
The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginning of the line to its end. The numbers are space-separated. Numbers *a*1,<=*a*2,<=...,<=*a**n* are not necessarily different.
Output Specification:
Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like.
Demo Input:
['4\n33 44 11 22\n', '7\n10 10 58 31 63 40 76\n']
Demo Output:
['2\n', '10\n']
Note:
In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 76, 40) 1. (10, 58, 10, 31, 76, 63, 40) 1. (10, 58, 31, 10, 76, 63, 40) 1. (10, 58, 31, 76, 10, 63, 40) 1. (10, 58, 31, 76, 63, 10, 40) 1. (10, 58, 76, 31, 63, 10, 40) 1. (10, 76, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 40, 10) | ```python
N = int(input())
järjend = list(map(int,input().split()))
pikk = max(järjend)
lühike = min(järjend)
pikka_asukoht = 0
for i in range(N):
if järjend[i] == pikk:
pikka_asukoht = i
break
lühikese_asukoht = 0
for i in range(N):
if järjend[i] == lühike:
lühikese_asukoht = i
kokku = ((N-1)-lühikese_asukoht) + pikka_asukoht
if pikka_asukoht > lühikese_asukoht:
kokku -= 1
print(kokku)
``` | 3 | |
919 | B | Perfect Number | PROGRAMMING | 1,100 | [
"binary search",
"brute force",
"dp",
"implementation",
"number theory"
] | null | null | We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer. | A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$). | A single number, denoting the $k$-th smallest perfect integer. | [
"1\n",
"2\n"
] | [
"19\n",
"28\n"
] | The first perfect integer is $19$ and the second one is $28$. | 750 | [
{
"input": "1",
"output": "19"
},
{
"input": "2",
"output": "28"
},
{
"input": "13",
"output": "136"
},
{
"input": "101",
"output": "1432"
},
{
"input": "1023",
"output": "100270"
},
{
"input": "9999",
"output": "10800010"
},
{
"input": "10... | 1,696,700,817 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 31 | 0 | res = []
for number in range(1, 10000):
if sum([int(i) for i in str(number)]) == 10:
res.append(number)
print(res[int(input()) - 1]) | Title: Perfect Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.
Input Specification:
A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$).
Output Specification:
A single number, denoting the $k$-th smallest perfect integer.
Demo Input:
['1\n', '2\n']
Demo Output:
['19\n', '28\n']
Note:
The first perfect integer is $19$ and the second one is $28$. | ```python
res = []
for number in range(1, 10000):
if sum([int(i) for i in str(number)]) == 10:
res.append(number)
print(res[int(input()) - 1])
``` | -1 | |
784 | F | Crunching Numbers Just for You | PROGRAMMING | 1,900 | [
"*special",
"implementation"
] | null | null | You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done...
You are given an array of integers. Sort it in non-descending order. | The input consists of a single line of space-separated integers. The first number is *n* (1<=≤<=*n*<=≤<=10) — the size of the array. The following *n* numbers are the elements of the array (1<=≤<=*a**i*<=≤<=100). | Output space-separated elements of the sorted array. | [
"3 3 1 2\n"
] | [
"1 2 3 \n"
] | Remember, this is a very important feature, and you have to make sure the customers appreciate it! | 0 | [
{
"input": "3 3 1 2",
"output": "1 2 3 "
},
{
"input": "10 54 100 27 1 33 27 80 49 27 6",
"output": "1 6 27 27 27 33 49 54 80 100 "
}
] | 1,617,051,921 | 5,121 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | print('1 2 3') | Title: Crunching Numbers Just for You
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done...
You are given an array of integers. Sort it in non-descending order.
Input Specification:
The input consists of a single line of space-separated integers. The first number is *n* (1<=≤<=*n*<=≤<=10) — the size of the array. The following *n* numbers are the elements of the array (1<=≤<=*a**i*<=≤<=100).
Output Specification:
Output space-separated elements of the sorted array.
Demo Input:
['3 3 1 2\n']
Demo Output:
['1 2 3 \n']
Note:
Remember, this is a very important feature, and you have to make sure the customers appreciate it! | ```python
print('1 2 3')
``` | 0 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party. | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,694,045,151 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | numeros = str(input())
lista = []
spacePlace = numeros.find(" ")
iguales = []
for i in range(4):
if (spacePlace != -1):
lista.append(int(numeros[:spacePlace + 1]))
numeros = numeros[(spacePlace + 1):]
spacePlace = numeros.find(' ')
else:
lista.append(int(numeros))
for item in lista:
if item not in iguales:
iguales.append(item)
print(4 - (len(iguales)))
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party.
Input Specification:
The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers.
Output Specification:
Print a single integer — the minimum number of horseshoes Valera needs to buy.
Demo Input:
['1 7 3 3\n', '7 7 7 7\n']
Demo Output:
['1\n', '3\n']
Note:
none | ```python
numeros = str(input())
lista = []
spacePlace = numeros.find(" ")
iguales = []
for i in range(4):
if (spacePlace != -1):
lista.append(int(numeros[:spacePlace + 1]))
numeros = numeros[(spacePlace + 1):]
spacePlace = numeros.find(' ')
else:
lista.append(int(numeros))
for item in lista:
if item not in iguales:
iguales.append(item)
print(4 - (len(iguales)))
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,617,396,074 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | M_str = input()
M = int(M_str)
N_str = input("How many columns on the rectangular board?:\n")
N = int(N_str)
if M < 1 or M > 1000000 and N < 1 or N > 1000000 :
print ('The number of columns and rows should be between 1 and 1000000.')
else:
number_of_squares = M * N
print (number_of_squares // 2)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
M_str = input()
M = int(M_str)
N_str = input("How many columns on the rectangular board?:\n")
N = int(N_str)
if M < 1 or M > 1000000 and N < 1 or N > 1000000 :
print ('The number of columns and rows should be between 1 and 1000000.')
else:
number_of_squares = M * N
print (number_of_squares // 2)
``` | -1 |
631 | C | Report | PROGRAMMING | 1,700 | [
"data structures",
"sortings"
] | null | null | Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that denotes corresponding revenue. Before the report gets to Blake, it passes through the hands of *m* managers. Each of them may reorder the elements in some order. Namely, the *i*-th manager either sorts first *r**i* numbers in non-descending or non-ascending order and then passes the report to the manager *i*<=+<=1, or directly to Blake (if this manager has number *i*<==<=*m*).
Employees of the "Blake Technologies" are preparing the report right now. You know the initial sequence *a**i* of length *n* and the description of each manager, that is value *r**i* and his favourite order. You are asked to speed up the process and determine how the final report will look like. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of commodities in the report and the number of managers, respectively.
The second line contains *n* integers *a**i* (|*a**i*|<=≤<=109) — the initial report before it gets to the first manager.
Then follow *m* lines with the descriptions of the operations managers are going to perform. The *i*-th of these lines contains two integers *t**i* and *r**i* (, 1<=≤<=*r**i*<=≤<=*n*), meaning that the *i*-th manager sorts the first *r**i* numbers either in the non-descending (if *t**i*<==<=1) or non-ascending (if *t**i*<==<=2) order. | Print *n* integers — the final report, which will be passed to Blake by manager number *m*. | [
"3 1\n1 2 3\n2 2\n",
"4 2\n1 2 4 3\n2 3\n1 2\n"
] | [
"2 1 3 ",
"2 4 1 3 "
] | In the first sample, the initial report looked like: 1 2 3. After the first manager the first two numbers were transposed: 2 1 3. The report got to Blake in this form.
In the second sample the original report was like this: 1 2 4 3. After the first manager the report changed to: 4 2 1 3. After the second manager the report changed to: 2 4 1 3. This report was handed over to Blake. | 1,500 | [
{
"input": "3 1\n1 2 3\n2 2",
"output": "2 1 3 "
},
{
"input": "4 2\n1 2 4 3\n2 3\n1 2",
"output": "2 4 1 3 "
},
{
"input": "4 1\n4 3 2 1\n1 4",
"output": "1 2 3 4 "
},
{
"input": "5 1\n1 2 3 4 5\n2 5",
"output": "5 4 3 2 1 "
},
{
"input": "6 2\n3 1 2 6 4 5\n1 6\n... | 1,459,428,670 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 30,924,800 | a, b = (int(i) for i in input().split())
f = []
t = input().split()
for i in range(a):
f.append(int(t[i]))
d = []
for i in range(b):
c, e = (int(t) for t in input().split())
d.append([c, e])
for i in range(b):
u = int(d[i][1])
if d[i][0] == 1:
g = sorted(f[:u])
f[:u] = g
else:
g = sorted(f[:u])[::-1]
f[:u] = g
for i in range(a):
print(f[i],end = ' ')
| Title: Report
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that denotes corresponding revenue. Before the report gets to Blake, it passes through the hands of *m* managers. Each of them may reorder the elements in some order. Namely, the *i*-th manager either sorts first *r**i* numbers in non-descending or non-ascending order and then passes the report to the manager *i*<=+<=1, or directly to Blake (if this manager has number *i*<==<=*m*).
Employees of the "Blake Technologies" are preparing the report right now. You know the initial sequence *a**i* of length *n* and the description of each manager, that is value *r**i* and his favourite order. You are asked to speed up the process and determine how the final report will look like.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of commodities in the report and the number of managers, respectively.
The second line contains *n* integers *a**i* (|*a**i*|<=≤<=109) — the initial report before it gets to the first manager.
Then follow *m* lines with the descriptions of the operations managers are going to perform. The *i*-th of these lines contains two integers *t**i* and *r**i* (, 1<=≤<=*r**i*<=≤<=*n*), meaning that the *i*-th manager sorts the first *r**i* numbers either in the non-descending (if *t**i*<==<=1) or non-ascending (if *t**i*<==<=2) order.
Output Specification:
Print *n* integers — the final report, which will be passed to Blake by manager number *m*.
Demo Input:
['3 1\n1 2 3\n2 2\n', '4 2\n1 2 4 3\n2 3\n1 2\n']
Demo Output:
['2 1 3 ', '2 4 1 3 ']
Note:
In the first sample, the initial report looked like: 1 2 3. After the first manager the first two numbers were transposed: 2 1 3. The report got to Blake in this form.
In the second sample the original report was like this: 1 2 4 3. After the first manager the report changed to: 4 2 1 3. After the second manager the report changed to: 2 4 1 3. This report was handed over to Blake. | ```python
a, b = (int(i) for i in input().split())
f = []
t = input().split()
for i in range(a):
f.append(int(t[i]))
d = []
for i in range(b):
c, e = (int(t) for t in input().split())
d.append([c, e])
for i in range(b):
u = int(d[i][1])
if d[i][0] == 1:
g = sorted(f[:u])
f[:u] = g
else:
g = sorted(f[:u])[::-1]
f[:u] = g
for i in range(a):
print(f[i],end = ' ')
``` | 0 | |
81 | A | Plug-in | PROGRAMMING | 1,400 | [
"implementation"
] | A. Plug-in | 1 | 256 | Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu".
Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something!
Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result. | The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters. | Print the given string after it is processed. It is guaranteed that the result will contain at least one character. | [
"hhoowaaaareyyoouu\n",
"reallazy\n",
"abacabaabacabaa\n"
] | [
"wre",
"rezy",
"a"
] | none | 500 | [
{
"input": "hhoowaaaareyyoouu",
"output": "wre"
},
{
"input": "reallazy",
"output": "rezy"
},
{
"input": "abacabaabacabaa",
"output": "a"
},
{
"input": "xraccabccbry",
"output": "xy"
},
{
"input": "a",
"output": "a"
},
{
"input": "b",
"output": "b"... | 1,572,756,321 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 342 | 2,560,000 | def plugin(string):
stack = []
for i in string:
if len(stack) == 0:
stack.append(i)
else:
if stack[-1] == i:
stack.pop()
else:
stack.append(i)
return "".join(stack)
string = input()
print(plugin(string)) | Title: Plug-in
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu".
Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something!
Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result.
Input Specification:
The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters.
Output Specification:
Print the given string after it is processed. It is guaranteed that the result will contain at least one character.
Demo Input:
['hhoowaaaareyyoouu\n', 'reallazy\n', 'abacabaabacabaa\n']
Demo Output:
['wre', 'rezy', 'a']
Note:
none | ```python
def plugin(string):
stack = []
for i in string:
if len(stack) == 0:
stack.append(i)
else:
if stack[-1] == i:
stack.pop()
else:
stack.append(i)
return "".join(stack)
string = input()
print(plugin(string))
``` | 3.824232 |
821 | A | Okabe and Future Gadget Laboratory | PROGRAMMING | 800 | [
"implementation"
] | null | null | Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column.
Help Okabe determine whether a given lab is good! | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab.
The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105). | Print "Yes" if the given lab is good and "No" otherwise.
You can output each letter in upper or lower case. | [
"3\n1 1 2\n2 3 1\n6 4 1\n",
"3\n1 5 2\n1 1 1\n1 2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes".
In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No". | 500 | [
{
"input": "3\n1 1 2\n2 3 1\n6 4 1",
"output": "Yes"
},
{
"input": "3\n1 5 2\n1 1 1\n1 2 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 11 1 2\n2 5 1 4\n3 9 4 1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 7 1 1\n1 3 1 2\n2... | 1,598,046,009 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 171 | 22,630,400 | n = int(input())
aij = [list(map(int,input().split())) for i in range(n)]
ans = "YES"
for i in range(n):
for j in range(n):
if aij[i][j] != 1:
flag = 0
for i2 in range(n):
for j2 in range(n):
if i2 != i and j2 != j and aij[i2][j] + aij[i][j2] == aij[i][j]:
flag = 1
if flag == 0:
ans = "NO"
print(ans)
| Title: Okabe and Future Gadget Laboratory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column.
Help Okabe determine whether a given lab is good!
Input Specification:
The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab.
The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105).
Output Specification:
Print "Yes" if the given lab is good and "No" otherwise.
You can output each letter in upper or lower case.
Demo Input:
['3\n1 1 2\n2 3 1\n6 4 1\n', '3\n1 5 2\n1 1 1\n1 2 3\n']
Demo Output:
['Yes\n', 'No\n']
Note:
In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes".
In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No". | ```python
n = int(input())
aij = [list(map(int,input().split())) for i in range(n)]
ans = "YES"
for i in range(n):
for j in range(n):
if aij[i][j] != 1:
flag = 0
for i2 in range(n):
for j2 in range(n):
if i2 != i and j2 != j and aij[i2][j] + aij[i][j2] == aij[i][j]:
flag = 1
if flag == 0:
ans = "NO"
print(ans)
``` | 3 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit. | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,588,939,295 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 248 | 7,065,600 | import copy
import math
n=int(input())
a=list(map(int,input().split()))
x=[]
for i in range(0,n-1):
c=int(math.fabs(a[i]-a[i+1]))
x.append(c)
c=int(math.fabs(a[0]-a[n-1]))
x.append(c)
d=min(x)
for i in range(0,n):
if d==x[i]:
if i==n-1:
print(1,n)
else:
print(i+1,i+2)
break
else:
continue
| Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.
Input Specification:
The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction.
Output Specification:
Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.
Demo Input:
['5\n10 12 13 15 10\n', '4\n10 20 30 40\n']
Demo Output:
['5 1\n', '1 2\n']
Note:
none | ```python
import copy
import math
n=int(input())
a=list(map(int,input().split()))
x=[]
for i in range(0,n-1):
c=int(math.fabs(a[i]-a[i+1]))
x.append(c)
c=int(math.fabs(a[0]-a[n-1]))
x.append(c)
d=min(x)
for i in range(0,n):
if d==x[i]:
if i==n-1:
print(1,n)
else:
print(i+1,i+2)
break
else:
continue
``` | 3.924839 |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least one problem with complexity exactly *a*1, at least one with complexity exactly *a*2, ..., and at least one with complexity exactly *a**n*. Of course, the round can also have problems with other complexities.
George has a poor imagination. It's easier for him to make some already prepared problem simpler than to come up with a new one and prepare it. George is magnificent at simplifying problems. He can simplify any already prepared problem with complexity *c* to any positive integer complexity *d* (*c*<=≥<=*d*), by changing limits on the input data.
However, nothing is so simple. George understood that even if he simplifies some problems, he can run out of problems for a good round. That's why he decided to find out the minimum number of problems he needs to come up with in addition to the *m* he's prepared in order to make a good round. Note that George can come up with a new problem of any complexity. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirements for the complexity of the problems in a good round. The third line contains space-separated integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b*1<=≤<=*b*2...<=≤<=*b**m*<=≤<=106) — the complexities of the problems prepared by George. | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems with complexities: 2, 3, 4. | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,566,440,791 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 0 | def main():
nk = list(map(int, input("").split()))
set1 = set(map(int, input("").split()))
set2 = set(map(int, input("").split()))
n = nk[0]
k = nk[1]
print(len(set1 - set2))
if __name__ == '__main__':
main() | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least one problem with complexity exactly *a*1, at least one with complexity exactly *a*2, ..., and at least one with complexity exactly *a**n*. Of course, the round can also have problems with other complexities.
George has a poor imagination. It's easier for him to make some already prepared problem simpler than to come up with a new one and prepare it. George is magnificent at simplifying problems. He can simplify any already prepared problem with complexity *c* to any positive integer complexity *d* (*c*<=≥<=*d*), by changing limits on the input data.
However, nothing is so simple. George understood that even if he simplifies some problems, he can run out of problems for a good round. That's why he decided to find out the minimum number of problems he needs to come up with in addition to the *m* he's prepared in order to make a good round. Note that George can come up with a new problem of any complexity.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirements for the complexity of the problems in a good round. The third line contains space-separated integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b*1<=≤<=*b*2...<=≤<=*b**m*<=≤<=106) — the complexities of the problems prepared by George.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['3 5\n1 2 3\n1 2 2 3 3\n', '3 5\n1 2 3\n1 1 1 1 1\n', '3 1\n2 3 4\n1\n']
Demo Output:
['0\n', '2\n', '3\n']
Note:
In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems with complexities: 2, 3, 4. | ```python
def main():
nk = list(map(int, input("").split()))
set1 = set(map(int, input("").split()))
set2 = set(map(int, input("").split()))
n = nk[0]
k = nk[1]
print(len(set1 - set2))
if __name__ == '__main__':
main()
``` | 0 | |
225 | C | Barcode | PROGRAMMING | 1,700 | [
"dp",
"matrices"
] | null | null | You've got an *n*<=×<=*m* pixel picture. Each pixel can be white or black. Your task is to change the colors of as few pixels as possible to obtain a barcode picture.
A picture is a barcode if the following conditions are fulfilled:
- All pixels in each column are of the same color. - The width of each monochrome vertical line is at least *x* and at most *y* pixels. In other words, if we group all neighbouring columns of the pixels with equal color, the size of each group can not be less than *x* or greater than *y*. | The first line contains four space-separated integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*,<=*x*,<=*y*<=≤<=1000; *x*<=≤<=*y*).
Then follow *n* lines, describing the original image. Each of these lines contains exactly *m* characters. Character "." represents a white pixel and "#" represents a black pixel. The picture description doesn't have any other characters besides "." and "#". | In the first line print the minimum number of pixels to repaint. It is guaranteed that the answer exists. | [
"6 5 1 2\n##.#.\n.###.\n###..\n#...#\n.##.#\n###..\n",
"2 5 1 1\n#####\n.....\n"
] | [
"11\n",
"5\n"
] | In the first test sample the picture after changing some colors can looks as follows:
In the second test sample the picture after changing some colors can looks as follows: | 1,500 | [
{
"input": "6 5 1 2\n##.#.\n.###.\n###..\n#...#\n.##.#\n###..",
"output": "11"
},
{
"input": "10 5 3 7\n.####\n###..\n##.##\n#..#.\n.#...\n#.##.\n.##..\n.#.##\n#.#..\n.#..#",
"output": "24"
},
{
"input": "6 3 1 4\n##.\n#..\n#..\n..#\n.#.\n#.#",
"output": "6"
},
{
"input": "5 ... | 1,653,742,428 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n,m,x1,y=map(int,input().split());a=[]
for i in range(n):
s=list(map(str,str(input())))
a.append(s)
o=0;l=0;h=n-2;p=0
while h<n:
x=x1
for i in range(x,y+1):
if n==6:
l=1
for j in range(m):
if a[i][j]=='#':
p+=1
x+=1
if p==0:
o=0;break
if o==0:
break
h+=y
if l==1:
p=n+m
else:
p=0
for i in range(m):
p+=1
print(p)
| Title: Barcode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an *n*<=×<=*m* pixel picture. Each pixel can be white or black. Your task is to change the colors of as few pixels as possible to obtain a barcode picture.
A picture is a barcode if the following conditions are fulfilled:
- All pixels in each column are of the same color. - The width of each monochrome vertical line is at least *x* and at most *y* pixels. In other words, if we group all neighbouring columns of the pixels with equal color, the size of each group can not be less than *x* or greater than *y*.
Input Specification:
The first line contains four space-separated integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*,<=*x*,<=*y*<=≤<=1000; *x*<=≤<=*y*).
Then follow *n* lines, describing the original image. Each of these lines contains exactly *m* characters. Character "." represents a white pixel and "#" represents a black pixel. The picture description doesn't have any other characters besides "." and "#".
Output Specification:
In the first line print the minimum number of pixels to repaint. It is guaranteed that the answer exists.
Demo Input:
['6 5 1 2\n##.#.\n.###.\n###..\n#...#\n.##.#\n###..\n', '2 5 1 1\n#####\n.....\n']
Demo Output:
['11\n', '5\n']
Note:
In the first test sample the picture after changing some colors can looks as follows:
In the second test sample the picture after changing some colors can looks as follows: | ```python
n,m,x1,y=map(int,input().split());a=[]
for i in range(n):
s=list(map(str,str(input())))
a.append(s)
o=0;l=0;h=n-2;p=0
while h<n:
x=x1
for i in range(x,y+1):
if n==6:
l=1
for j in range(m):
if a[i][j]=='#':
p+=1
x+=1
if p==0:
o=0;break
if o==0:
break
h+=y
if l==1:
p=n+m
else:
p=0
for i in range(m):
p+=1
print(p)
``` | 0 | |
129 | A | Cookies | PROGRAMMING | 900 | [
"implementation"
] | null | null | Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even? | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag. | Print in the only line the only number — the sought number of ways. If there are no such ways print 0. | [
"1\n1\n",
"10\n1 2 2 3 4 4 4 2 2 2\n",
"11\n2 2 2 2 2 2 2 2 2 2 99\n"
] | [
"1\n",
"8\n",
"1\n"
] | In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | 500 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 2 2 3 4 4 4 2 2 2",
"output": "8"
},
{
"input": "11\n2 2 2 2 2 2 2 2 2 2 99",
"output": "1"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n2 2",
"output": "2"
},
{
"input": "2\n1 2",
"o... | 1,658,337,878 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n=str(input())
z=n.count('0')
o=n.count('1')
if z>7 or o>7:
print("YES")
else:print("NO") | Title: Cookies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input Specification:
The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag.
Output Specification:
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Demo Input:
['1\n1\n', '10\n1 2 2 3 4 4 4 2 2 2\n', '11\n2 2 2 2 2 2 2 2 2 2 99\n']
Demo Output:
['1\n', '8\n', '1\n']
Note:
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | ```python
n=str(input())
z=n.count('0')
o=n.count('1')
if z>7 or o>7:
print("YES")
else:print("NO")
``` | 0 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves. | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,697,703,780 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
a = list(map(int,input().split()))
d = [0] * n
for i in range(n):
ind = a.index(a[i])
l = a[i]-1
d[l] = ind+1
print(d)
| Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves.
Output Specification:
Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*.
Demo Input:
['4\n2 3 4 1\n', '3\n1 3 2\n', '2\n1 2\n']
Demo Output:
['4 1 2 3\n', '1 3 2\n', '1 2\n']
Note:
none | ```python
n = int(input())
a = list(map(int,input().split()))
d = [0] * n
for i in range(n):
ind = a.index(a[i])
l = a[i]-1
d[l] = ind+1
print(d)
``` | 0 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consists of the remaining binary digits, written in the corresponding order (possible, with leading zeroes).
The Little Elephant wants the number he is going to write on the paper to be as large as possible. Help him find the maximum number that he can obtain after deleting exactly one binary digit and print it in the binary notation. | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub class="lower-index">10</sub>. | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,668,854,818 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 124 | 0 | s=input()
i=s.find('0')
if i==-1:print(s[:len(s)-1])
else:print(s[:i]+s[i+1:]) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consists of the remaining binary digits, written in the corresponding order (possible, with leading zeroes).
The Little Elephant wants the number he is going to write on the paper to be as large as possible. Help him find the maximum number that he can obtain after deleting exactly one binary digit and print it in the binary notation.
Input Specification:
The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits.
Output Specification:
In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem.
Demo Input:
['101\n', '110010\n']
Demo Output:
['11\n', '11010\n']
Note:
In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub class="lower-index">10</sub>. | ```python
s=input()
i=s.find('0')
if i==-1:print(s[:len(s)-1])
else:print(s[:i]+s[i+1:])
``` | 3 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves. | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,681,462,772 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n=int(input())
arr=list(map(int,input().split()))
a=[]
for i in range(n):
# k=arr.index(i)
a.insert(arr[i]-1,i)
for i in a:
print(i,end=' ') | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves.
Output Specification:
Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*.
Demo Input:
['4\n2 3 4 1\n', '3\n1 3 2\n', '2\n1 2\n']
Demo Output:
['4 1 2 3\n', '1 3 2\n', '1 2\n']
Note:
none | ```python
n=int(input())
arr=list(map(int,input().split()))
a=[]
for i in range(n):
# k=arr.index(i)
a.insert(arr[i]-1,i)
for i in a:
print(i,end=' ')
``` | 0 | |
637 | C | Promocodes with Mistakes | PROGRAMMING | 1,400 | [
"*special",
"brute force",
"constructive algorithms",
"implementation"
] | null | null | During a New Year special offer the "Sudislavl Bars" offered *n* promo codes. Each promo code consists of exactly six digits and gives right to one free cocktail at the bar "Mosquito Shelter". Of course, all the promocodes differ.
As the "Mosquito Shelter" opens only at 9, and partying in Sudislavl usually begins at as early as 6, many problems may arise as to how to type a promotional code without errors. It is necessary to calculate such maximum *k*, that the promotional code could be uniquely identified if it was typed with no more than *k* errors. At that, *k*<==<=0 means that the promotional codes must be entered exactly.
A mistake in this problem should be considered as entering the wrong numbers. For example, value "123465" contains two errors relative to promocode "123456". Regardless of the number of errors the entered value consists of exactly six digits. | The first line of the output contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of promocodes.
Each of the next *n* lines contains a single promocode, consisting of exactly 6 digits. It is guaranteed that all the promocodes are distinct. Promocodes can start from digit "0". | Print the maximum *k* (naturally, not exceeding the length of the promocode), such that any promocode can be uniquely identified if it is typed with at most *k* mistakes. | [
"2\n000000\n999999\n",
"6\n211111\n212111\n222111\n111111\n112111\n121111\n"
] | [
"2\n",
"0\n"
] | In the first sample *k* < 3, so if a bar customer types in value "090909", then it will be impossible to define which promocode exactly corresponds to it. | 1,500 | [
{
"input": "2\n000000\n999999",
"output": "2"
},
{
"input": "6\n211111\n212111\n222111\n111111\n112111\n121111",
"output": "0"
},
{
"input": "1\n123456",
"output": "6"
},
{
"input": "2\n000000\n099999",
"output": "2"
},
{
"input": "2\n000000\n009999",
"output"... | 1,457,907,266 | 36,866 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 0 | # -*- coding: utf-8 -*-
"""
Created on Sun Mar 13 19:40:03 2016
@author: Kostya S.
"""
from math import ceil
def hem(s,t):
r = 0
for u,v in zip(s,t):
r += u != v
return r
n = int(input())
code = set()
for _ in range(n):
c = (input())
code.add(c)
dist = set()
a = set()
k = 0
q = 0
for c1 in code:
for c2 in code:
a.add(hem(c1,c2))
ans = max(a)//2 - 1
print(ans)
| Title: Promocodes with Mistakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During a New Year special offer the "Sudislavl Bars" offered *n* promo codes. Each promo code consists of exactly six digits and gives right to one free cocktail at the bar "Mosquito Shelter". Of course, all the promocodes differ.
As the "Mosquito Shelter" opens only at 9, and partying in Sudislavl usually begins at as early as 6, many problems may arise as to how to type a promotional code without errors. It is necessary to calculate such maximum *k*, that the promotional code could be uniquely identified if it was typed with no more than *k* errors. At that, *k*<==<=0 means that the promotional codes must be entered exactly.
A mistake in this problem should be considered as entering the wrong numbers. For example, value "123465" contains two errors relative to promocode "123456". Regardless of the number of errors the entered value consists of exactly six digits.
Input Specification:
The first line of the output contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of promocodes.
Each of the next *n* lines contains a single promocode, consisting of exactly 6 digits. It is guaranteed that all the promocodes are distinct. Promocodes can start from digit "0".
Output Specification:
Print the maximum *k* (naturally, not exceeding the length of the promocode), such that any promocode can be uniquely identified if it is typed with at most *k* mistakes.
Demo Input:
['2\n000000\n999999\n', '6\n211111\n212111\n222111\n111111\n112111\n121111\n']
Demo Output:
['2\n', '0\n']
Note:
In the first sample *k* < 3, so if a bar customer types in value "090909", then it will be impossible to define which promocode exactly corresponds to it. | ```python
# -*- coding: utf-8 -*-
"""
Created on Sun Mar 13 19:40:03 2016
@author: Kostya S.
"""
from math import ceil
def hem(s,t):
r = 0
for u,v in zip(s,t):
r += u != v
return r
n = int(input())
code = set()
for _ in range(n):
c = (input())
code.add(c)
dist = set()
a = set()
k = 0
q = 0
for c1 in code:
for c2 in code:
a.add(hem(c1,c2))
ans = max(a)//2 - 1
print(ans)
``` | 0 | |
660 | C | Hard Process | PROGRAMMING | 1,600 | [
"binary search",
"dp",
"two pointers"
] | null | null | You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can change no more than *k* zeroes to ones to maximize *f*(*a*). | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=3·105,<=0<=≤<=*k*<=≤<=*n*) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1) — the elements of *a*. | On the first line print a non-negative integer *z* — the maximal value of *f*(*a*) after no more than *k* changes of zeroes to ones.
On the second line print *n* integers *a**j* — the elements of the array *a* after the changes.
If there are multiple answers, you can print any one of them. | [
"7 1\n1 0 0 1 1 0 1\n",
"10 2\n1 0 0 1 0 1 0 1 0 1\n"
] | [
"4\n1 0 0 1 1 1 1\n",
"5\n1 0 0 1 1 1 1 1 0 1\n"
] | none | 0 | [
{
"input": "7 1\n1 0 0 1 1 0 1",
"output": "4\n1 0 0 1 1 1 1"
},
{
"input": "10 2\n1 0 0 1 0 1 0 1 0 1",
"output": "5\n1 0 0 1 1 1 1 1 0 1"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "7 0\n0 1 0 0 0 1 0",
"o... | 1,692,178,249 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n, k = map(int, input().split())
elements = list(map(int, input().split()))
left_pointer = 0 # Left pointer of the sliding window
max_length = 0 # Maximum length of the subsegment
zero_count = 0 # Count of zeroes in the current subsegment
for right_pointer in range(n):
if elements[right_pointer] == 0:
zero_count += 1
# If the number of zeroes in the current window exceeds k, move the left pointer
while zero_count > k:
if elements[left_pointer] == 0:
zero_count -= 1
left_pointer += 1
# Update the maximum length
max_length = max(max_length, right_pointer - left_pointer + 1)
print(max_length)
| Title: Hard Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can change no more than *k* zeroes to ones to maximize *f*(*a*).
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=3·105,<=0<=≤<=*k*<=≤<=*n*) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1) — the elements of *a*.
Output Specification:
On the first line print a non-negative integer *z* — the maximal value of *f*(*a*) after no more than *k* changes of zeroes to ones.
On the second line print *n* integers *a**j* — the elements of the array *a* after the changes.
If there are multiple answers, you can print any one of them.
Demo Input:
['7 1\n1 0 0 1 1 0 1\n', '10 2\n1 0 0 1 0 1 0 1 0 1\n']
Demo Output:
['4\n1 0 0 1 1 1 1\n', '5\n1 0 0 1 1 1 1 1 0 1\n']
Note:
none | ```python
n, k = map(int, input().split())
elements = list(map(int, input().split()))
left_pointer = 0 # Left pointer of the sliding window
max_length = 0 # Maximum length of the subsegment
zero_count = 0 # Count of zeroes in the current subsegment
for right_pointer in range(n):
if elements[right_pointer] == 0:
zero_count += 1
# If the number of zeroes in the current window exceeds k, move the left pointer
while zero_count > k:
if elements[left_pointer] == 0:
zero_count -= 1
left_pointer += 1
# Update the maximum length
max_length = max(max_length, right_pointer - left_pointer + 1)
print(max_length)
``` | 0 | |
309 | A | Morning run | PROGRAMMING | 2,000 | [
"binary search",
"math",
"two pointers"
] | null | null | People like to be fit. That's why many of them are ready to wake up at dawn, go to the stadium and run. In this problem your task is to help a company design a new stadium.
The city of N has a shabby old stadium. Many people like it and every morning thousands of people come out to this stadium to run. The stadium can be represented as a circle, its length is exactly *l* meters with a marked start line. However, there can't be simultaneous start in the morning, so exactly at 7, each runner goes to his favorite spot on the stadium and starts running from there. Note that not everybody runs in the same manner as everybody else. Some people run in the clockwise direction, some of them run in the counter-clockwise direction. It mostly depends on the runner's mood in the morning, so you can assume that each running direction is equiprobable for each runner in any fixed morning.
The stadium is tiny and is in need of major repair, for right now there only is one running track! You can't get too playful on a single track, that's why all runners keep the same running speed — exactly 1 meter per a time unit. Nevertheless, the runners that choose different directions bump into each other as they meet.
The company wants to design a new stadium, but they first need to know how bad the old one is. For that they need the expectation of the number of bumpings by *t* time units after the running has begun. Help the company count the required expectation. Note that each runner chooses a direction equiprobably, independently from the others and then all runners start running simultaneously at 7 a.m. Assume that each runner runs for *t* time units without stopping. Consider the runners to bump at a certain moment if at that moment they found themselves at the same point in the stadium. A pair of runners can bump more than once. | The first line of the input contains three integers *n*, *l*, *t* (1<=≤<=*n*<=≤<=106,<=1<=≤<=*l*<=≤<=109,<=1<=≤<=*t*<=≤<=109). The next line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=<<=*l*), here *a**i* is the clockwise distance from the start line to the *i*-th runner's starting position. | Print a single real number — the answer to the problem with absolute or relative error of at most 10<=-<=6. | [
"2 5 1\n0 2\n",
"3 7 3\n0 1 6\n"
] | [
"0.2500000000\n",
"1.5000000000\n"
] | There are two runners in the first example. If the first runner run clockwise direction, then in 1 time unit he will be 1m away from the start line. If the second runner run counter-clockwise direction then in 1 time unit he will be also 1m away from the start line. And it is the only possible way to meet. We assume that each running direction is equiprobable, so the answer for the example is equal to 0.5·0.5 = 0.25. | 500 | [] | 1,689,434,564 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689434564.5995135")# 1689434564.5995345 | Title: Morning run
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
People like to be fit. That's why many of them are ready to wake up at dawn, go to the stadium and run. In this problem your task is to help a company design a new stadium.
The city of N has a shabby old stadium. Many people like it and every morning thousands of people come out to this stadium to run. The stadium can be represented as a circle, its length is exactly *l* meters with a marked start line. However, there can't be simultaneous start in the morning, so exactly at 7, each runner goes to his favorite spot on the stadium and starts running from there. Note that not everybody runs in the same manner as everybody else. Some people run in the clockwise direction, some of them run in the counter-clockwise direction. It mostly depends on the runner's mood in the morning, so you can assume that each running direction is equiprobable for each runner in any fixed morning.
The stadium is tiny and is in need of major repair, for right now there only is one running track! You can't get too playful on a single track, that's why all runners keep the same running speed — exactly 1 meter per a time unit. Nevertheless, the runners that choose different directions bump into each other as they meet.
The company wants to design a new stadium, but they first need to know how bad the old one is. For that they need the expectation of the number of bumpings by *t* time units after the running has begun. Help the company count the required expectation. Note that each runner chooses a direction equiprobably, independently from the others and then all runners start running simultaneously at 7 a.m. Assume that each runner runs for *t* time units without stopping. Consider the runners to bump at a certain moment if at that moment they found themselves at the same point in the stadium. A pair of runners can bump more than once.
Input Specification:
The first line of the input contains three integers *n*, *l*, *t* (1<=≤<=*n*<=≤<=106,<=1<=≤<=*l*<=≤<=109,<=1<=≤<=*t*<=≤<=109). The next line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=<<=*l*), here *a**i* is the clockwise distance from the start line to the *i*-th runner's starting position.
Output Specification:
Print a single real number — the answer to the problem with absolute or relative error of at most 10<=-<=6.
Demo Input:
['2 5 1\n0 2\n', '3 7 3\n0 1 6\n']
Demo Output:
['0.2500000000\n', '1.5000000000\n']
Note:
There are two runners in the first example. If the first runner run clockwise direction, then in 1 time unit he will be 1m away from the start line. If the second runner run counter-clockwise direction then in 1 time unit he will be also 1m away from the start line. And it is the only possible way to meet. We assume that each running direction is equiprobable, so the answer for the example is equal to 0.5·0.5 = 0.25. | ```python
print("_RANDOM_GUESS_1689434564.5995135")# 1689434564.5995345
``` | 0 | |
729 | B | Spotlights | PROGRAMMING | 1,200 | [
"dp",
"implementation"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of the four directions (if you look at the stage from above) — left, right, up or down. Thus, the spotlight's position is a cell it is placed to and a direction it shines.
A position is good if two conditions hold:
- there is no actor in the cell the spotlight is placed to; - there is at least one actor in the direction the spotlight projects.
Count the number of good positions for placing the spotlight. Two positions of spotlight are considered to be different if the location cells or projection direction differ. | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell will remain empty. It is guaranteed that there is at least one actor in the plan. | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and up direction; 1. the (2, 2) and right direction; 1. the (2, 4) cell and left direction.
Therefore, there are 9 good positions in this example. | 1,000 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,584,870,861 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 15,667,200 | n,m = map(int,input().split())
stage_matrix = []
dp_row = [[0 for i in range(m+1)] for j in range(n+1)]
dp_col = [[0 for i in range(n+1)] for j in range(m+1)]
for i in range(n):
stage_matrix.append(list(map(int,input().split())))
for i in range(1,n+1):
for j in range(1,m+1):
if stage_matrix[i-1][j-1] == 1:
dp_row[i][j] = dp_row[i][j-1] + 1
else:
dp_row[i][j] = dp_row[i][j-1]
for i in range(1,m+1):
for j in range(1,n+1):
if stage_matrix[j-1][i-1] == 1:
dp_col[i][j] = dp_col[i][j-1] + 1
else:
dp_col[i][j] = dp_col[i][j-1]
c = 0
for i in range(n):
for j in range(m):
if stage_matrix[i][j] == 0:
if dp_col[j+1][i] > 0:
c = c + 1
if dp_col[j+1][n] - dp_col[j+1][i+1] > 0:
c = c + 1
if dp_row[i+1][j] != 0:
c = c + 1
if dp_row[i+1][m] - dp_row[i+1][j+1] != 0:
c = c + 1
print(c) | Title: Spotlights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of the four directions (if you look at the stage from above) — left, right, up or down. Thus, the spotlight's position is a cell it is placed to and a direction it shines.
A position is good if two conditions hold:
- there is no actor in the cell the spotlight is placed to; - there is at least one actor in the direction the spotlight projects.
Count the number of good positions for placing the spotlight. Two positions of spotlight are considered to be different if the location cells or projection direction differ.
Input Specification:
The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell will remain empty. It is guaranteed that there is at least one actor in the plan.
Output Specification:
Print one integer — the number of good positions for placing the spotlight.
Demo Input:
['2 4\n0 1 0 0\n1 0 1 0\n', '4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n']
Demo Output:
['9\n', '20\n']
Note:
In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and up direction; 1. the (2, 2) and right direction; 1. the (2, 4) cell and left direction.
Therefore, there are 9 good positions in this example. | ```python
n,m = map(int,input().split())
stage_matrix = []
dp_row = [[0 for i in range(m+1)] for j in range(n+1)]
dp_col = [[0 for i in range(n+1)] for j in range(m+1)]
for i in range(n):
stage_matrix.append(list(map(int,input().split())))
for i in range(1,n+1):
for j in range(1,m+1):
if stage_matrix[i-1][j-1] == 1:
dp_row[i][j] = dp_row[i][j-1] + 1
else:
dp_row[i][j] = dp_row[i][j-1]
for i in range(1,m+1):
for j in range(1,n+1):
if stage_matrix[j-1][i-1] == 1:
dp_col[i][j] = dp_col[i][j-1] + 1
else:
dp_col[i][j] = dp_col[i][j-1]
c = 0
for i in range(n):
for j in range(m):
if stage_matrix[i][j] == 0:
if dp_col[j+1][i] > 0:
c = c + 1
if dp_col[j+1][n] - dp_col[j+1][i+1] > 0:
c = c + 1
if dp_row[i+1][j] != 0:
c = c + 1
if dp_row[i+1][m] - dp_row[i+1][j+1] != 0:
c = c + 1
print(c)
``` | 0 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,697,466,376 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a=int(input())
b=list(map(int,input().split()))
b.sort()
d=sum(b)
c=[]
for n in range(len(b)):
if sum(c)<=d-sum(c):
c.append(b[n])
print(c)
| Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces.
Output Specification:
In the single line print the single number — the minimum needed number of coins.
Demo Input:
['2\n3 3\n', '3\n2 1 2\n']
Demo Output:
['2\n', '2\n']
Note:
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | ```python
a=int(input())
b=list(map(int,input().split()))
b.sort()
d=sum(b)
c=[]
for n in range(len(b)):
if sum(c)<=d-sum(c):
c.append(b[n])
print(c)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Levko has an array that consists of integers: *a*1,<=*a*2,<=... ,<=*a**n*. But he doesn’t like this array at all.
Levko thinks that the beauty of the array *a* directly depends on value *c*(*a*), which can be calculated by the formula:
It’s time to change the world and Levko is going to change his array for the better. To be exact, Levko wants to change the values of at most *k* array elements (it is allowed to replace the values by any integers). Of course, the changes should make the array as beautiful as possible.
Help Levko and calculate what minimum number *c*(*a*) he can reach. | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2000). The second line contains space-separated integers *a*1,<=*a*2,<=... ,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | A single number — the minimum value of *c*(*a*) Levko can get. | [
"5 2\n4 7 4 7 4\n",
"3 1\n-100 0 100\n",
"6 3\n1 2 3 7 8 9\n"
] | [
"0\n",
"100\n",
"1\n"
] | In the first sample Levko can change the second and fourth elements and get array: 4, 4, 4, 4, 4.
In the third sample he can get array: 1, 2, 3, 4, 5, 6. | 0 | [
{
"input": "5 2\n4 7 4 7 4",
"output": "0"
},
{
"input": "3 1\n-100 0 100",
"output": "100"
},
{
"input": "6 3\n1 2 3 7 8 9",
"output": "1"
},
{
"input": "4 1\n-1000000000 -1000000000 1000000000 1000000000",
"output": "1000000000"
},
{
"input": "10 1\n-6 5 -7 -7 -... | 1,608,157,631 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 3,276,800 | import sys
import math
MAX = int(1e9)
MIN = int(1e9)
N = 2000
def reset(dp):
for i in range(1, N):
# Can always change all preceding entries
dp[i] = i
def check(n, k, arr, c, dp):
# dp[i]: minimum # of changes to make cost <= c from 0..i and i is unchanged.
reset(dp)
for i in range(1, n):
for j in range(0, i):
# Number of changeable spaces I have
have = i - j - 1
# Nicer check that intervals of length c can cover the range
if abs(arr[i] - arr[j]) <= c * (i - j):
dp[i] = min(dp[i], dp[j] + have)
for i in range(n):
# A solution must have a first unchanged element from the right
# Treat i as such and see if it works
if dp[i] + n - i - 1 <= k:
return True
return False
def main():
# Parse input
lines = sys.stdin.readlines()
l1, l2 = lines[0], lines[1]
n, k = [int(x) for x in l1.strip().split(' ')]
arr = [int(x) for x in l2.strip().split(' ')]
dp = [0 for _ in range(N)]
# Binary search on c
lo = 0
hi = 2 * MAX
while lo < hi:
c = (lo + hi) // 2
valid = check(n, k, arr, c, dp)
if valid:
hi = c
else:
lo = c + 1
print(lo)
if __name__ == '__main__':
main()
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko has an array that consists of integers: *a*1,<=*a*2,<=... ,<=*a**n*. But he doesn’t like this array at all.
Levko thinks that the beauty of the array *a* directly depends on value *c*(*a*), which can be calculated by the formula:
It’s time to change the world and Levko is going to change his array for the better. To be exact, Levko wants to change the values of at most *k* array elements (it is allowed to replace the values by any integers). Of course, the changes should make the array as beautiful as possible.
Help Levko and calculate what minimum number *c*(*a*) he can reach.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2000). The second line contains space-separated integers *a*1,<=*a*2,<=... ,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109).
Output Specification:
A single number — the minimum value of *c*(*a*) Levko can get.
Demo Input:
['5 2\n4 7 4 7 4\n', '3 1\n-100 0 100\n', '6 3\n1 2 3 7 8 9\n']
Demo Output:
['0\n', '100\n', '1\n']
Note:
In the first sample Levko can change the second and fourth elements and get array: 4, 4, 4, 4, 4.
In the third sample he can get array: 1, 2, 3, 4, 5, 6. | ```python
import sys
import math
MAX = int(1e9)
MIN = int(1e9)
N = 2000
def reset(dp):
for i in range(1, N):
# Can always change all preceding entries
dp[i] = i
def check(n, k, arr, c, dp):
# dp[i]: minimum # of changes to make cost <= c from 0..i and i is unchanged.
reset(dp)
for i in range(1, n):
for j in range(0, i):
# Number of changeable spaces I have
have = i - j - 1
# Nicer check that intervals of length c can cover the range
if abs(arr[i] - arr[j]) <= c * (i - j):
dp[i] = min(dp[i], dp[j] + have)
for i in range(n):
# A solution must have a first unchanged element from the right
# Treat i as such and see if it works
if dp[i] + n - i - 1 <= k:
return True
return False
def main():
# Parse input
lines = sys.stdin.readlines()
l1, l2 = lines[0], lines[1]
n, k = [int(x) for x in l1.strip().split(' ')]
arr = [int(x) for x in l2.strip().split(' ')]
dp = [0 for _ in range(N)]
# Binary search on c
lo = 0
hi = 2 * MAX
while lo < hi:
c = (lo + hi) // 2
valid = check(n, k, arr, c, dp)
if valid:
hi = c
else:
lo = c + 1
print(lo)
if __name__ == '__main__':
main()
``` | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,617,603,418 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | M, N = input().split()
M, N = int(M), int(N)
A1= int(M*N/2)
if M <= N: print(A1)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
M, N = input().split()
M, N = int(M), int(N)
A1= int(M*N/2)
if M <= N: print(A1)
``` | 3.969 |
0 | none | none | none | 0 | [
"none"
] | null | null | Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a certain order (one after another, in this order strictly), which is specified by permutation of letters' indices of the word *t*: *a*1... *a*|*t*|. We denote the length of word *x* as |*x*|. Note that after removing one letter, the indices of other letters don't change. For example, if *t*<==<="nastya" and *a*<==<=[4,<=1,<=5,<=3,<=2,<=6] then removals make the following sequence of words "nastya" "nastya" "nastya" "nastya" "nastya" "nastya" "nastya".
Sergey knows this permutation. His goal is to stop his sister at some point and continue removing by himself to get the word *p*. Since Nastya likes this activity, Sergey wants to stop her as late as possible. Your task is to determine, how many letters Nastya can remove before she will be stopped by Sergey.
It is guaranteed that the word *p* can be obtained by removing the letters from word *t*. | The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*a*2,<=...,<=*a*|*t*| of letter indices that specifies the order in which Nastya removes letters of *t* (1<=≤<=*a**i*<=≤<=|*t*|, all *a**i* are distinct). | Print a single integer number, the maximum number of letters that Nastya can remove. | [
"ababcba\nabb\n5 3 4 1 7 6 2\n",
"bbbabb\nbb\n1 6 3 4 2 5\n"
] | [
"3",
"4"
] | In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba"
Nastya can not continue, because it is impossible to get word "abb" from word "ababcba".
So, Nastya will remove only three letters. | 0 | [
{
"input": "ababcba\nabb\n5 3 4 1 7 6 2",
"output": "3"
},
{
"input": "bbbabb\nbb\n1 6 3 4 2 5",
"output": "4"
},
{
"input": "cacaccccccacccc\ncacc\n10 9 14 5 1 7 15 3 6 12 4 8 11 13 2",
"output": "9"
},
{
"input": "aaaabaaabaabaaaaaaaa\naaaa\n18 5 4 6 13 9 1 3 7 8 16 10 12 1... | 1,488,111,461 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 1,356 | 19,456,000 | a = input()
b = input()
p = list(map(int, input().split()))
for i in range(len(p)):
p[i] -= 1
def good(m):
pos = 0
a1 = list(a)
for i in range(m):
a1[p[i]] = "#"
for i in range(len(a1)):
if a1[i] == b[pos]:
pos += 1
if pos == len(b):
return True
return False
l = 0
r = len(a)
while r - l > 1:
m = (l + r) // 2
if good(m):
l = m
else:
r = m
print(l) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a certain order (one after another, in this order strictly), which is specified by permutation of letters' indices of the word *t*: *a*1... *a*|*t*|. We denote the length of word *x* as |*x*|. Note that after removing one letter, the indices of other letters don't change. For example, if *t*<==<="nastya" and *a*<==<=[4,<=1,<=5,<=3,<=2,<=6] then removals make the following sequence of words "nastya" "nastya" "nastya" "nastya" "nastya" "nastya" "nastya".
Sergey knows this permutation. His goal is to stop his sister at some point and continue removing by himself to get the word *p*. Since Nastya likes this activity, Sergey wants to stop her as late as possible. Your task is to determine, how many letters Nastya can remove before she will be stopped by Sergey.
It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Input Specification:
The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*a*2,<=...,<=*a*|*t*| of letter indices that specifies the order in which Nastya removes letters of *t* (1<=≤<=*a**i*<=≤<=|*t*|, all *a**i* are distinct).
Output Specification:
Print a single integer number, the maximum number of letters that Nastya can remove.
Demo Input:
['ababcba\nabb\n5 3 4 1 7 6 2\n', 'bbbabb\nbb\n1 6 3 4 2 5\n']
Demo Output:
['3', '4']
Note:
In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba"
Nastya can not continue, because it is impossible to get word "abb" from word "ababcba".
So, Nastya will remove only three letters. | ```python
a = input()
b = input()
p = list(map(int, input().split()))
for i in range(len(p)):
p[i] -= 1
def good(m):
pos = 0
a1 = list(a)
for i in range(m):
a1[p[i]] = "#"
for i in range(len(a1)):
if a1[i] == b[pos]:
pos += 1
if pos == len(b):
return True
return False
l = 0
r = len(a)
while r - l > 1:
m = (l + r) // 2
if good(m):
l = m
else:
r = m
print(l)
``` | 3 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not. | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence. | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,679,816,337 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def func(n,str):
c=0
m=0
q=list(str)
for i in range(len(q)-1):
if (q[i]+q[i+1])=="SF":
c=c+1
elif (q[i]+q[i+1])=="FS":
m=m+1
if c>m:
return "yes"
else:
return "no"
n=4
st="FSSF"
P=func(n,st)
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not.
Input Specification:
The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output Specification:
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Demo Input:
['4\nFSSF\n', '2\nSF\n', '10\nFFFFFFFFFF\n', '10\nSSFFSFFSFF\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n', 'YES\n']
Note:
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | ```python
def func(n,str):
c=0
m=0
q=list(str)
for i in range(len(q)-1):
if (q[i]+q[i+1])=="SF":
c=c+1
elif (q[i]+q[i+1])=="FS":
m=m+1
if c>m:
return "yes"
else:
return "no"
n=4
st="FSSF"
P=func(n,st)
``` | 0 | |
687 | D | Dividing Kingdom II | PROGRAMMING | 2,500 | [
"brute force",
"data structures",
"dsu",
"graphs",
"sortings"
] | null | null | Long time ago, there was a great kingdom and it was being ruled by The Great Arya and Pari The Great. These two had some problems about the numbers they like, so they decided to divide the great kingdom between themselves.
The great kingdom consisted of *n* cities numbered from 1 to *n* and *m* bidirectional roads between these cities, numbered from 1 to *m*. The *i*-th road had length equal to *w**i*. The Great Arya and Pari The Great were discussing about destructing some prefix (all road with numbers less than some *x*) and suffix (all roads with numbers greater than some *x*) of the roads so there will remain only the roads with numbers *l*,<=*l*<=+<=1,<=...,<=*r*<=-<=1 and *r*.
After that they will divide the great kingdom into two pieces (with each city belonging to exactly one piece) such that the hardness of the division is minimized. The hardness of a division is the maximum length of a road such that its both endpoints are in the same piece of the kingdom. In case there is no such road, the hardness of the division is considered to be equal to <=-<=1.
Historians found the map of the great kingdom, and they have *q* guesses about the *l* and *r* chosen by those great rulers. Given these data, for each guess *l**i* and *r**i* print the minimum possible hardness of the division of the kingdom. | The first line of the input contains three integers *n*, *m* and *q* (1<=≤<=*n*,<=*q*<=≤<=1000, ) — the number of cities and roads in the great kingdom, and the number of guesses, respectively.
The *i*-th line of the following *m* lines contains three integers *u**i*,<=*v**i* and *w**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*,<=0<=≤<=*w**i*<=≤<=109), denoting the road number *i* connects cities *u**i* and *v**i* and its length is equal *w**i*. It's guaranteed that no road connects the city to itself and no pair of cities is connected by more than one road.
Each of the next *q* lines contains a pair of integers *l**i* and<=*r**i* (1<=<=≤<=*l**i*<=≤<=*r**i*<=≤<=*m*) — a guess from the historians about the remaining roads in the kingdom. | For each guess print the minimum possible hardness of the division in described scenario. | [
"5 6 5\n5 4 86\n5 1 0\n1 3 38\n2 1 33\n2 4 28\n2 3 40\n3 5\n2 6\n1 3\n2 3\n1 6\n"
] | [
"-1\n33\n-1\n-1\n33\n"
] | none | 2,000 | [] | 1,664,984,855 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 6,000 | 116,838,400 | from collections import deque
class UnionFind():
def __init__(self,size):
self.table = [-1 for _ in range(size)]
self.member_num = [1 for _ in range(size)]
#representative
#O(a(N))
def find(self,x):
Q = deque()
while self.table[x] >= 0:
Q.append(x)
x = self.table[x]
while len(Q)>0:
y = Q.pop()
self.table[y] = x
return x
def union(self,x,y):
s1 = self.find(x)
s2 = self.find(y)
m1=self.member_num[s1]
m2=self.member_num[s2]
if s1 != s2:
if m1 != m2:
if m1 < m2:
self.table[s1] = s2
self.member_num[s2]=m1+m2
return [m1,m2]
else:
self.table[s2] = s1
self.member_num[s1]=m1+m2
return [m1,m2]
else:
self.table[s1] = -1
self.table[s2] = s1
self.member_num[s1] = m1+m2
return [m1,m2]
return [0,0]
n,m,q = list(map(int,input().split()))
edges = []
for i in range(m):
edges.append(list(map(int,input().split())))
for i in range(q):
l,r = list(map(int,input().split()))
edges1 = edges[l-1:r]
edges1.sort(key=lambda x:x[2],reverse=True)
uf = UnionFind(2*n)
ans = -1
for u,v,w in edges1:
par1 = uf.find(u-1)
par2 = uf.find(v-1)
if par1==par2:
ans = w
break
par1 = uf.find(u-1)
par2 = uf.find(v+n-1)
if par1!=par2:
uf.union(u-1,v+n-1)
uf.union(u+n-1,v-1)
print(ans) | Title: Dividing Kingdom II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Long time ago, there was a great kingdom and it was being ruled by The Great Arya and Pari The Great. These two had some problems about the numbers they like, so they decided to divide the great kingdom between themselves.
The great kingdom consisted of *n* cities numbered from 1 to *n* and *m* bidirectional roads between these cities, numbered from 1 to *m*. The *i*-th road had length equal to *w**i*. The Great Arya and Pari The Great were discussing about destructing some prefix (all road with numbers less than some *x*) and suffix (all roads with numbers greater than some *x*) of the roads so there will remain only the roads with numbers *l*,<=*l*<=+<=1,<=...,<=*r*<=-<=1 and *r*.
After that they will divide the great kingdom into two pieces (with each city belonging to exactly one piece) such that the hardness of the division is minimized. The hardness of a division is the maximum length of a road such that its both endpoints are in the same piece of the kingdom. In case there is no such road, the hardness of the division is considered to be equal to <=-<=1.
Historians found the map of the great kingdom, and they have *q* guesses about the *l* and *r* chosen by those great rulers. Given these data, for each guess *l**i* and *r**i* print the minimum possible hardness of the division of the kingdom.
Input Specification:
The first line of the input contains three integers *n*, *m* and *q* (1<=≤<=*n*,<=*q*<=≤<=1000, ) — the number of cities and roads in the great kingdom, and the number of guesses, respectively.
The *i*-th line of the following *m* lines contains three integers *u**i*,<=*v**i* and *w**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*,<=0<=≤<=*w**i*<=≤<=109), denoting the road number *i* connects cities *u**i* and *v**i* and its length is equal *w**i*. It's guaranteed that no road connects the city to itself and no pair of cities is connected by more than one road.
Each of the next *q* lines contains a pair of integers *l**i* and<=*r**i* (1<=<=≤<=*l**i*<=≤<=*r**i*<=≤<=*m*) — a guess from the historians about the remaining roads in the kingdom.
Output Specification:
For each guess print the minimum possible hardness of the division in described scenario.
Demo Input:
['5 6 5\n5 4 86\n5 1 0\n1 3 38\n2 1 33\n2 4 28\n2 3 40\n3 5\n2 6\n1 3\n2 3\n1 6\n']
Demo Output:
['-1\n33\n-1\n-1\n33\n']
Note:
none | ```python
from collections import deque
class UnionFind():
def __init__(self,size):
self.table = [-1 for _ in range(size)]
self.member_num = [1 for _ in range(size)]
#representative
#O(a(N))
def find(self,x):
Q = deque()
while self.table[x] >= 0:
Q.append(x)
x = self.table[x]
while len(Q)>0:
y = Q.pop()
self.table[y] = x
return x
def union(self,x,y):
s1 = self.find(x)
s2 = self.find(y)
m1=self.member_num[s1]
m2=self.member_num[s2]
if s1 != s2:
if m1 != m2:
if m1 < m2:
self.table[s1] = s2
self.member_num[s2]=m1+m2
return [m1,m2]
else:
self.table[s2] = s1
self.member_num[s1]=m1+m2
return [m1,m2]
else:
self.table[s1] = -1
self.table[s2] = s1
self.member_num[s1] = m1+m2
return [m1,m2]
return [0,0]
n,m,q = list(map(int,input().split()))
edges = []
for i in range(m):
edges.append(list(map(int,input().split())))
for i in range(q):
l,r = list(map(int,input().split()))
edges1 = edges[l-1:r]
edges1.sort(key=lambda x:x[2],reverse=True)
uf = UnionFind(2*n)
ans = -1
for u,v,w in edges1:
par1 = uf.find(u-1)
par2 = uf.find(v-1)
if par1==par2:
ans = w
break
par1 = uf.find(u-1)
par2 = uf.find(v+n-1)
if par1!=par2:
uf.union(u-1,v+n-1)
uf.union(u+n-1,v-1)
print(ans)
``` | 0 | |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of his handle to become red. He considers his performance in the rated contest to be good if he outscored some participant, whose handle was colored red before the contest and his rating has increased after it.
Anton has written a program that analyses contest results and determines whether he performed good or not. Are you able to do the same? | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*before**i*,<=*after**i*<=≤<=4000) — participant's rating before and after the contest, respectively. Each handle is a non-empty string, consisting of no more than 10 characters, which might be lowercase and uppercase English letters, digits, characters «_» and «-» characters.
It is guaranteed that all handles are distinct. | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before the contest. | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,646,972,552 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 31 | 0 | con=True
for _ in [0]*int(input()):
a=[*map(int,input().split()[1:])]
if a[0]>=2400 and a[1]>a[0] and con:print('YES');con=False
if con:print('NO') | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of his handle to become red. He considers his performance in the rated contest to be good if he outscored some participant, whose handle was colored red before the contest and his rating has increased after it.
Anton has written a program that analyses contest results and determines whether he performed good or not. Are you able to do the same?
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*before**i*,<=*after**i*<=≤<=4000) — participant's rating before and after the contest, respectively. Each handle is a non-empty string, consisting of no more than 10 characters, which might be lowercase and uppercase English letters, digits, characters «_» and «-» characters.
It is guaranteed that all handles are distinct.
Output Specification:
Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise.
Demo Input:
['3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n', '3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n']
Demo Output:
['YES', 'NO']
Note:
In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before the contest. | ```python
con=True
for _ in [0]*int(input()):
a=[*map(int,input().split()[1:])]
if a[0]>=2400 and a[1]>a[0] and con:print('YES');con=False
if con:print('NO')
``` | 3 | |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins? | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,603,986,543 | 2,147,483,647 | PyPy 3 | OK | TESTS | 38 | 140 | 0 | a,b=map(int,input().split())
c1,c2,c3=0,0,0
l=[]
for i in range(1,7):
l.append((abs(i-a),abs(i-b)))
for i in range(len(l)):
if(l[i][0]>l[i][1]):
c3+=1
elif(l[i][0]<l[i][1]):
c1+=1
else:
c2+=1
print(c1,c2,c3) | Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many ways to throw a dice are there, at which the first player wins, or there is a draw, or the second player wins?
Input Specification:
The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly.
Output Specification:
Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly.
Demo Input:
['2 5\n', '2 4\n']
Demo Output:
['3 0 3\n', '2 1 3\n']
Note:
The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | ```python
a,b=map(int,input().split())
c1,c2,c3=0,0,0
l=[]
for i in range(1,7):
l.append((abs(i-a),abs(i-b)))
for i in range(len(l)):
if(l[i][0]>l[i][1]):
c3+=1
elif(l[i][0]<l[i][1]):
c1+=1
else:
c2+=1
print(c1,c2,c3)
``` | 3 | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps. | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,638,842,391 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | import math
r,x0,y0,x1,y1=map(int,input().split())
print(x0,y0,x1,y1)
d = math.sqrt((x1-x0)**2+(y1-y0)**2)
s = d/(r<<1)
print(d,s)
print(math.ceil(s))
| Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps.
Input Specification:
Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively.
Output Specification:
Output a single integer — minimum number of steps required to move the center of the circle to the destination point.
Demo Input:
['2 0 0 0 4\n', '1 1 1 4 4\n', '4 5 6 5 6\n']
Demo Output:
['1\n', '3\n', '0\n']
Note:
In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
import math
r,x0,y0,x1,y1=map(int,input().split())
print(x0,y0,x1,y1)
d = math.sqrt((x1-x0)**2+(y1-y0)**2)
s = d/(r<<1)
print(d,s)
print(math.ceil(s))
``` | 0 | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is called a permutation if it contains all integers from 1 to *n* exactly once.
You are given an arbitrary sequence *a*1,<=*a*2,<=...,<=*a**n* containing *n* integers. Each integer is not less than 1 and not greater than 5000. Determine what minimum number of elements Polycarpus needs to change to get a permutation (he should not delete or add numbers). In a single change he can modify any single sequence element (i. e. replace it with another integer). | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with number 2. | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,589,718,399 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 218 | 20,172,800 | n = int(input())
num = list(map(int, input().split(" ")))
aux = map(lambda x: 1 if x > n else 1, num)
print(sum(aux))
| Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is called a permutation if it contains all integers from 1 to *n* exactly once.
You are given an arbitrary sequence *a*1,<=*a*2,<=...,<=*a**n* containing *n* integers. Each integer is not less than 1 and not greater than 5000. Determine what minimum number of elements Polycarpus needs to change to get a permutation (he should not delete or add numbers). In a single change he can modify any single sequence element (i. e. replace it with another integer).
Input Specification:
The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*).
Output Specification:
Print the only number — the minimum number of changes needed to get the permutation.
Demo Input:
['3\n3 1 2\n', '2\n2 2\n', '5\n5 3 3 3 1\n']
Demo Output:
['0\n', '1\n', '2\n']
Note:
The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with number 2. | ```python
n = int(input())
num = list(map(int, input().split(" ")))
aux = map(lambda x: 1 if x > n else 1, num)
print(sum(aux))
``` | 0 | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks? | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,638,623,807 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | n, m = map(int, input().split())
day = 0
x = n + n // m
y = x // m + n
#while x > 0:
# x = x - 1
# day = day + 1
print(y) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | ```python
n, m = map(int, input().split())
day = 0
x = n + n // m
y = x // m + n
#while x > 0:
# x = x - 1
# day = day + 1
print(y)
``` | 0 | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,580,230,876 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 248 | 512,000 | def solution(n,m):
print(m+n-1)
if n>=m:
t=1
for i in range(1,n+1):
while t<=m:
print(i,t)
t+=1
t=2
for i in range(1,m+1):
while t<=n:
print(t,i)
t+=1
else:
t=1
for i in range(1,m+1):
while t<=n:
print(i,t)
t+=1
t=2
for i in range(1,n+1):
while t<=m:
print(t,i)
t+=1
a=list(map(int,input('').split()))
solution(a[0],a[1]) | Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room.
Output Specification:
In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*.
Demo Input:
['2 1\n', '2 2\n']
Demo Output:
['2\n1 1\n2 1\n', '3\n1 1\n1 2\n2 2\n']
Note:
In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | ```python
def solution(n,m):
print(m+n-1)
if n>=m:
t=1
for i in range(1,n+1):
while t<=m:
print(i,t)
t+=1
t=2
for i in range(1,m+1):
while t<=n:
print(t,i)
t+=1
else:
t=1
for i in range(1,m+1):
while t<=n:
print(i,t)
t+=1
t=2
for i in range(1,n+1):
while t<=m:
print(t,i)
t+=1
a=list(map(int,input('').split()))
solution(a[0],a[1])
``` | 0 | |
195 | A | Let's Watch Football | PROGRAMMING | 1,000 | [
"binary search",
"brute force",
"math"
] | null | null | Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second.
The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch.
Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video.
Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses. | The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds. | Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses. | [
"4 1 1\n",
"10 3 2\n",
"13 12 1\n"
] | [
"3\n",
"5\n",
"1\n"
] | In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching.
In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary. | 500 | [
{
"input": "4 1 1",
"output": "3"
},
{
"input": "10 3 2",
"output": "5"
},
{
"input": "13 12 1",
"output": "1"
},
{
"input": "2 1 3",
"output": "3"
},
{
"input": "6 2 4",
"output": "8"
},
{
"input": "5 2 1",
"output": "2"
},
{
"input": "2 1... | 1,650,508,043 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 92 | 0 | def round_up(x):
if x % 1 == 0:
return int(x)
else:
return int(x // 1 + 1)
a, b, c = [int(x) for x in input().split()]
latency = a * c / b - c
print(round_up(latency))
| Title: Let's Watch Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second.
The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch.
Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video.
Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses.
Input Specification:
The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds.
Output Specification:
Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses.
Demo Input:
['4 1 1\n', '10 3 2\n', '13 12 1\n']
Demo Output:
['3\n', '5\n', '1\n']
Note:
In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching.
In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary. | ```python
def round_up(x):
if x % 1 == 0:
return int(x)
else:
return int(x // 1 + 1)
a, b, c = [int(x) for x in input().split()]
latency = a * c / b - c
print(round_up(latency))
``` | 3 | |
859 | B | Lazy Security Guard | PROGRAMMING | 1,000 | [
"brute force",
"geometry",
"math"
] | null | null | Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite lazy and would like your help to find the shortest possible route that meets the requirements. The city is laid out in a square grid pattern, and is large enough that for the sake of the problem it can be considered infinite. | Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route. | Print the minimum perimeter that can be achieved. | [
"4\n",
"11\n",
"22\n"
] | [
"8\n",
"14\n",
"20\n"
] | Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 750 | [
{
"input": "4",
"output": "8"
},
{
"input": "11",
"output": "14"
},
{
"input": "22",
"output": "20"
},
{
"input": "3",
"output": "8"
},
{
"input": "1024",
"output": "128"
},
{
"input": "101",
"output": "42"
},
{
"input": "30",
"output":... | 1,505,584,912 | 1,612 | Python 3 | OK | TESTS | 35 | 62 | 0 | n = int(input())
temp = int(n**0.5)
n -= temp ** 2
if n // temp != n / temp:
print(temp * 4 + (n//temp+1) * 2)
else:
print(temp * 4 + (n//temp) * 2)
| Title: Lazy Security Guard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite lazy and would like your help to find the shortest possible route that meets the requirements. The city is laid out in a square grid pattern, and is large enough that for the sake of the problem it can be considered infinite.
Input Specification:
Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route.
Output Specification:
Print the minimum perimeter that can be achieved.
Demo Input:
['4\n', '11\n', '22\n']
Demo Output:
['8\n', '14\n', '20\n']
Note:
Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
n = int(input())
temp = int(n**0.5)
n -= temp ** 2
if n // temp != n / temp:
print(temp * 4 + (n//temp+1) * 2)
else:
print(temp * 4 + (n//temp) * 2)
``` | 3 | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song. | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word. | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,681,139,692 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | string = input()
string = string.strip("WUB")
string = string.replace("WUB", " ")
print(string) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input Specification:
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output Specification:
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Demo Input:
['WUBWUBABCWUB\n', 'WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n']
Demo Output:
['ABC ', 'WE ARE THE CHAMPIONS MY FRIEND ']
Note:
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | ```python
string = input()
string = string.strip("WUB")
string = string.replace("WUB", " ")
print(string)
``` | 0 | |
318 | A | Even Odds | PROGRAMMING | 900 | [
"math"
] | null | null | Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first *n*. He writes down the following sequence of numbers: firstly all odd integers from 1 to *n* (in ascending order), then all even integers from 1 to *n* (also in ascending order). Help our hero to find out which number will stand at the position number *k*. | The only line of input contains integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print the number that will stand at the position number *k* after Volodya's manipulations. | [
"10 3\n",
"7 7\n"
] | [
"5",
"6"
] | In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | 500 | [
{
"input": "10 3",
"output": "5"
},
{
"input": "7 7",
"output": "6"
},
{
"input": "7 1",
"output": "1"
},
{
"input": "7 2",
"output": "3"
},
{
"input": "8 5",
"output": "2"
},
{
"input": "8 3",
"output": "5"
},
{
"input": "8 4",
"output... | 1,697,084,782 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 62 | 0 | def main():
n, k = tuple(map(int, input().split()))
odd_count = (n+1)//2
if k <= odd_count:
print(2*k-1)
else:
k -= odd_count
print(2*k)
if __name__ == '__main__':
main() | Title: Even Odds
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first *n*. He writes down the following sequence of numbers: firstly all odd integers from 1 to *n* (in ascending order), then all even integers from 1 to *n* (also in ascending order). Help our hero to find out which number will stand at the position number *k*.
Input Specification:
The only line of input contains integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print the number that will stand at the position number *k* after Volodya's manipulations.
Demo Input:
['10 3\n', '7 7\n']
Demo Output:
['5', '6']
Note:
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | ```python
def main():
n, k = tuple(map(int, input().split()))
odd_count = (n+1)//2
if k <= odd_count:
print(2*k-1)
else:
k -= odd_count
print(2*k)
if __name__ == '__main__':
main()
``` | 3 | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the side equals *n* squares (*n* is an odd number) and each unit square contains some small letter of the English alphabet.
Valera needs to know if the letters written on the square piece of paper form letter "X". Valera's teacher thinks that the letters on the piece of paper form an "X", if:
- on both diagonals of the square paper all letters are the same; - all other squares of the paper (they are not on the diagonals) contain the same letter that is different from the letters on the diagonals.
Help Valera, write the program that completes the described task for him. | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,601,460,059 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 139 | 0 | def main():
n = int(input())
lines = []
for _ in range(n):
lines.append(input())
y = lines[0][1]
for i in range(n):
for j in range(n):
if i == j or i == n - j - 1:
continue
if lines[i][j] != y:
print("NO")
return
x = lines[0][0]
for i in range(n):
if lines[i][i] != x or lines[i][n - i - 1] != x:
print("NO")
return
print("YES")
if __name__ == "__main__":
main() | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the side equals *n* squares (*n* is an odd number) and each unit square contains some small letter of the English alphabet.
Valera needs to know if the letters written on the square piece of paper form letter "X". Valera's teacher thinks that the letters on the piece of paper form an "X", if:
- on both diagonals of the square paper all letters are the same; - all other squares of the paper (they are not on the diagonals) contain the same letter that is different from the letters on the diagonals.
Help Valera, write the program that completes the described task for him.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper.
Output Specification:
Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes.
Demo Input:
['5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n', '3\nwsw\nsws\nwsw\n', '3\nxpx\npxp\nxpe\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n']
Note:
none | ```python
def main():
n = int(input())
lines = []
for _ in range(n):
lines.append(input())
y = lines[0][1]
for i in range(n):
for j in range(n):
if i == j or i == n - j - 1:
continue
if lines[i][j] != y:
print("NO")
return
x = lines[0][0]
for i in range(n):
if lines[i][i] != x or lines[i][n - i - 1] != x:
print("NO")
return
print("YES")
if __name__ == "__main__":
main()
``` | 0 | |
558 | B | Amr and The Large Array | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Amr has got a large array of size *n*. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible. | The first line contains one number *n* (1<=≤<=*n*<=≤<=105), the size of the array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106), representing elements of the array. | Output two integers *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them. | [
"5\n1 1 2 2 1\n",
"5\n1 2 2 3 1\n",
"6\n1 2 2 1 1 2\n"
] | [
"1 5",
"2 3",
"1 5"
] | A subsegment *B* of an array *A* from *l* to *r* is an array of size *r* - *l* + 1 where *B*<sub class="lower-index">*i*</sub> = *A*<sub class="lower-index">*l* + *i* - 1</sub> for all 1 ≤ *i* ≤ *r* - *l* + 1 | 1,000 | [
{
"input": "5\n1 1 2 2 1",
"output": "1 5"
},
{
"input": "5\n1 2 2 3 1",
"output": "2 3"
},
{
"input": "6\n1 2 2 1 1 2",
"output": "1 5"
},
{
"input": "10\n1 1000000 2 1000000 3 2 1000000 1 2 1",
"output": "2 7"
},
{
"input": "10\n1 2 3 4 5 5 1 2 3 4",
"output... | 1,436,888,452 | 1,852 | Python 3 | OK | TESTS | 49 | 327 | 15,257,600 | n=int(input())
mas=list(map(int,input().split(" ")))
dic={i:[0,-1,-1] for i in set(mas)}
ma=0
for i in range(n):
if dic[mas[i]][1]==-1:
dic[mas[i]][1]=i
dic[mas[i]][0]+=1
dic[mas[i]][2]=i
if dic[mas[i]][0]>ma:ma=dic[mas[i]][0]
mi=9999999999
a=0
b=0
for i in range(n):
if(dic[mas[i]][0]==ma and dic[mas[i]][2]-dic[mas[i]][1]<mi):
a=dic[mas[i]][1]
b=dic[mas[i]][2]
mi=b-a
print(a+1,b+1)
| Title: Amr and The Large Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr has got a large array of size *n*. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input Specification:
The first line contains one number *n* (1<=≤<=*n*<=≤<=105), the size of the array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106), representing elements of the array.
Output Specification:
Output two integers *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Demo Input:
['5\n1 1 2 2 1\n', '5\n1 2 2 3 1\n', '6\n1 2 2 1 1 2\n']
Demo Output:
['1 5', '2 3', '1 5']
Note:
A subsegment *B* of an array *A* from *l* to *r* is an array of size *r* - *l* + 1 where *B*<sub class="lower-index">*i*</sub> = *A*<sub class="lower-index">*l* + *i* - 1</sub> for all 1 ≤ *i* ≤ *r* - *l* + 1 | ```python
n=int(input())
mas=list(map(int,input().split(" ")))
dic={i:[0,-1,-1] for i in set(mas)}
ma=0
for i in range(n):
if dic[mas[i]][1]==-1:
dic[mas[i]][1]=i
dic[mas[i]][0]+=1
dic[mas[i]][2]=i
if dic[mas[i]][0]>ma:ma=dic[mas[i]][0]
mi=9999999999
a=0
b=0
for i in range(n):
if(dic[mas[i]][0]==ma and dic[mas[i]][2]-dic[mas[i]][1]<mi):
a=dic[mas[i]][1]
b=dic[mas[i]][2]
mi=b-a
print(a+1,b+1)
``` | 3 | |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to *a*? | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a regular triangle, and in the last test case — a square. | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,697,011,278 | 2,147,483,647 | Python 3 | OK | TESTS | 3 | 62 | 0 | '''
2300015897
吴杰稀
光华管理学院
'''
cases = int(input())
for i in range(cases):
angle = int(input())
t = 180 - angle
if 360 % t == 0 and 360 // t >= 3:
print("YES")
else:
print("NO") | Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to *a*?
Input Specification:
The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees.
Output Specification:
For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible.
Demo Input:
['3\n30\n60\n90\n']
Demo Output:
['NO\nYES\nYES\n']
Note:
In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a regular triangle, and in the last test case — a square. | ```python
'''
2300015897
吴杰稀
光华管理学院
'''
cases = int(input())
for i in range(cases):
angle = int(input())
t = 180 - angle
if 360 % t == 0 and 360 // t >= 3:
print("YES")
else:
print("NO")
``` | 3 | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to determine the length of the longest balanced substring of *s*. | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,625,485,696 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n=int(input())
p=input()
c_0=p.count('0')
c_1=p.count('1')
s=2*min(c_0,c_1)
print(s)
| Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to determine the length of the longest balanced substring of *s*.
Input Specification:
The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*.
Output Specification:
If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring.
Demo Input:
['8\n11010111\n', '3\n111\n']
Demo Output:
['4\n', '0\n']
Note:
In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | ```python
n=int(input())
p=input()
c_0=p.count('0')
c_1=p.count('1')
s=2*min(c_0,c_1)
print(s)
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,694,259,243 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 77 | 0 | import math
def main():
dms=[]
ins = input()
dms = ins.split()
d1 = int(dms[0])/int(dms[2]);
d2 = int(dms[1])/int(dms[2]);
print(math.ceil(d1)*math.ceil(d2))
main() | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
import math
def main():
dms=[]
ins = input()
dms = ins.split()
d1 = int(dms[0])/int(dms[2]);
d2 = int(dms[1])/int(dms[2]);
print(math.ceil(d1)*math.ceil(d2))
main()
``` | 3.9615 |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem. | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,667,822,601 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 102,400 | import os,sys,io,math
from array import array
from math import *
from bisect import *
from heapq import *
from functools import *
from itertools import *
from collections import Counter,defaultdict
I=lambda:[*map(int,sys.stdin.readline().split())]
IS=lambda:input()
IN=lambda:int(input())
IF=lambda:float(input())
n,l=IN(),I()
s=sorted(list(set(l)))
print(s[1] if len(s)>1 else "NO") | Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem.
Input Specification:
The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value.
Output Specification:
If the given sequence has the second order statistics, output this order statistics, otherwise output NO.
Demo Input:
['4\n1 2 2 -4\n', '5\n1 2 3 1 1\n']
Demo Output:
['1\n', '2\n']
Note:
none | ```python
import os,sys,io,math
from array import array
from math import *
from bisect import *
from heapq import *
from functools import *
from itertools import *
from collections import Counter,defaultdict
I=lambda:[*map(int,sys.stdin.readline().split())]
IS=lambda:input()
IN=lambda:int(input())
IF=lambda:float(input())
n,l=IN(),I()
s=sorted(list(set(l)))
print(s[1] if len(s)>1 else "NO")
``` | 3.976809 |
312 | B | Archer | PROGRAMMING | 1,300 | [
"math",
"probabilities"
] | null | null | SmallR is an archer. SmallR is taking a match of archer with Zanoes. They try to shoot in the target in turns, and SmallR shoots first. The probability of shooting the target each time is for SmallR while for Zanoes. The one who shoots in the target first should be the winner.
Output the probability that SmallR will win the match. | A single line contains four integers . | Print a single real number, the probability that SmallR will win the match.
The answer will be considered correct if the absolute or relative error doesn't exceed 10<=-<=6. | [
"1 2 1 2\n"
] | [
"0.666666666667"
] | none | 1,000 | [
{
"input": "1 2 1 2",
"output": "0.666666666667"
},
{
"input": "1 3 1 3",
"output": "0.600000000000"
},
{
"input": "1 3 2 3",
"output": "0.428571428571"
},
{
"input": "3 4 3 4",
"output": "0.800000000000"
},
{
"input": "1 2 10 11",
"output": "0.523809523810"
... | 1,656,851,163 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | import math
a,b,c,d=list(map(int,input().split()))
print((b/(math.factorial(b+d)/(math.factorial(b)*math.factorial(d))))*(b+d-(a+c))) | Title: Archer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
SmallR is an archer. SmallR is taking a match of archer with Zanoes. They try to shoot in the target in turns, and SmallR shoots first. The probability of shooting the target each time is for SmallR while for Zanoes. The one who shoots in the target first should be the winner.
Output the probability that SmallR will win the match.
Input Specification:
A single line contains four integers .
Output Specification:
Print a single real number, the probability that SmallR will win the match.
The answer will be considered correct if the absolute or relative error doesn't exceed 10<=-<=6.
Demo Input:
['1 2 1 2\n']
Demo Output:
['0.666666666667']
Note:
none | ```python
import math
a,b,c,d=list(map(int,input().split()))
print((b/(math.factorial(b+d)/(math.factorial(b)*math.factorial(d))))*(b+d-(a+c)))
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,648,488,336 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 2,048,000 | import re
s = input()
if re.match(r'.*h.*e.*l,*l.*o.*', s):
print(True)
else:
print(False)
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
import re
s = input()
if re.match(r'.*h.*e.*l,*l.*o.*', s):
print(True)
else:
print(False)
``` | 0 |
710 | B | Optimal Point on a Line | PROGRAMMING | 1,400 | [
"brute force",
"sortings"
] | null | null | You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal. | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of points on the line.
The second line contains *n* integers *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the given *n* points. | Print the only integer *x* — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer. | [
"4\n1 2 3 4\n"
] | [
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "5\n-1 -10 2 6 7",
"output": "2"
},
{
"input": "10\n-68 10 87 22 30 89 82 -97 -52 25",
"output": "22"
},
{
"input": "100\n457 827 807 17 871 935 907 -415 536 170 551 -988 865 758 -457 -892 -875 -488 684 19 0 555 -807 -624 -... | 1,614,596,176 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | n = int(input())
coo = [int(i) for i in input().split(" ")]
print(coo[(n - 1) // 2])
| Title: Optimal Point on a Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of points on the line.
The second line contains *n* integers *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the given *n* points.
Output Specification:
Print the only integer *x* — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer.
Demo Input:
['4\n1 2 3 4\n']
Demo Output:
['2\n']
Note:
none | ```python
n = int(input())
coo = [int(i) for i in input().split(" ")]
print(coo[(n - 1) // 2])
``` | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,642,423,558 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | mn=[int(i) for i in input().split()]
print(int(mn[0]*mn[1]/2)) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
mn=[int(i) for i in input().split()]
print(int(mn[0]*mn[1]/2))
``` | 3.969 |
518 | B | Tanya and Postcard | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"strings"
] | null | null | Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she found a newspaper and decided to cut out the letters and glue them into the postcard to achieve string *s*. The newspaper contains string *t*, consisting of uppercase and lowercase English letters. We know that the length of string *t* greater or equal to the length of the string *s*.
The newspaper may possibly have too few of some letters needed to make the text and too many of some other letters. That's why Tanya wants to cut some *n* letters out of the newspaper and make a message of length exactly *n*, so that it looked as much as possible like *s*. If the letter in some position has correct value and correct letter case (in the string *s* and in the string that Tanya will make), then she shouts joyfully "YAY!", and if the letter in the given position has only the correct value but it is in the wrong case, then the girl says "WHOOPS".
Tanya wants to make such message that lets her shout "YAY!" as much as possible. If there are multiple ways to do this, then her second priority is to maximize the number of times she says "WHOOPS". Your task is to help Tanya make the message. | The first line contains line *s* (1<=≤<=|*s*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text of Tanya's message.
The second line contains line *t* (|*s*|<=≤<=|*t*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text written in the newspaper.
Here |*a*| means the length of the string *a*. | Print two integers separated by a space:
- the first number is the number of times Tanya shouts "YAY!" while making the message, - the second number is the number of times Tanya says "WHOOPS" while making the message. | [
"AbC\nDCbA\n",
"ABC\nabc\n",
"abacaba\nAbaCaBA\n"
] | [
"3 0\n",
"0 3\n",
"3 4\n"
] | none | 1,000 | [
{
"input": "AbC\nDCbA",
"output": "3 0"
},
{
"input": "ABC\nabc",
"output": "0 3"
},
{
"input": "abacaba\nAbaCaBA",
"output": "3 4"
},
{
"input": "zzzzz\nZZZZZ",
"output": "0 5"
},
{
"input": "zzzZZZ\nZZZzzZ",
"output": "5 1"
},
{
"input": "abcdefghijk... | 1,612,135,004 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 202 | 4,505,600 | s=input()
t=input()
swaps=s.swapcase()
swapt=t.swapcase()
alp=[]
countalp=[]
salp=[]
scountalp=[]
yay=0
woops=0
for i,x in enumerate(s):
if x not in alp:
alp.append(x)
n=s.count(x)
countalp.append(n)
for i,x in enumerate(t):
if x not in salp:
salp.append(x)
n=t.count(x)
scountalp.append(n)
for b,y in enumerate(alp):
tcount=t.count(y)
if tcount>0:
if abs(countalp[b]-tcount)==0:
yay+=tcount
scountalp[salp.index(y)]-=tcount
countalp[b]-=tcount
else:
yay+=min(countalp[b],tcount)
if (countalp[b]-tcount)<0:
countalp[b]=0
scountalp[salp.index(y)]-=countalp[b]
else:
countalp[b]-=tcount
scountalp[salp.index(y)]=0
for k,z in enumerate(alp):
if countalp[alp.index(z)]>0 and scountalp[salp.index(z.swapcase())]>0:
woops+=countalp[k]
# print(alp,countalp)
# print(salp,scountalp)
print(yay,woops)
| Title: Tanya and Postcard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she found a newspaper and decided to cut out the letters and glue them into the postcard to achieve string *s*. The newspaper contains string *t*, consisting of uppercase and lowercase English letters. We know that the length of string *t* greater or equal to the length of the string *s*.
The newspaper may possibly have too few of some letters needed to make the text and too many of some other letters. That's why Tanya wants to cut some *n* letters out of the newspaper and make a message of length exactly *n*, so that it looked as much as possible like *s*. If the letter in some position has correct value and correct letter case (in the string *s* and in the string that Tanya will make), then she shouts joyfully "YAY!", and if the letter in the given position has only the correct value but it is in the wrong case, then the girl says "WHOOPS".
Tanya wants to make such message that lets her shout "YAY!" as much as possible. If there are multiple ways to do this, then her second priority is to maximize the number of times she says "WHOOPS". Your task is to help Tanya make the message.
Input Specification:
The first line contains line *s* (1<=≤<=|*s*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text of Tanya's message.
The second line contains line *t* (|*s*|<=≤<=|*t*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text written in the newspaper.
Here |*a*| means the length of the string *a*.
Output Specification:
Print two integers separated by a space:
- the first number is the number of times Tanya shouts "YAY!" while making the message, - the second number is the number of times Tanya says "WHOOPS" while making the message.
Demo Input:
['AbC\nDCbA\n', 'ABC\nabc\n', 'abacaba\nAbaCaBA\n']
Demo Output:
['3 0\n', '0 3\n', '3 4\n']
Note:
none | ```python
s=input()
t=input()
swaps=s.swapcase()
swapt=t.swapcase()
alp=[]
countalp=[]
salp=[]
scountalp=[]
yay=0
woops=0
for i,x in enumerate(s):
if x not in alp:
alp.append(x)
n=s.count(x)
countalp.append(n)
for i,x in enumerate(t):
if x not in salp:
salp.append(x)
n=t.count(x)
scountalp.append(n)
for b,y in enumerate(alp):
tcount=t.count(y)
if tcount>0:
if abs(countalp[b]-tcount)==0:
yay+=tcount
scountalp[salp.index(y)]-=tcount
countalp[b]-=tcount
else:
yay+=min(countalp[b],tcount)
if (countalp[b]-tcount)<0:
countalp[b]=0
scountalp[salp.index(y)]-=countalp[b]
else:
countalp[b]-=tcount
scountalp[salp.index(y)]=0
for k,z in enumerate(alp):
if countalp[alp.index(z)]>0 and scountalp[salp.index(z.swapcase())]>0:
woops+=countalp[k]
# print(alp,countalp)
# print(salp,scountalp)
print(yay,woops)
``` | 0 | |
724 | D | Dense Subsequence | PROGRAMMING | 1,900 | [
"data structures",
"greedy",
"strings"
] | null | null | You are given a string *s*, consisting of lowercase English letters, and the integer *m*.
One should choose some symbols from the given string so that any contiguous subsegment of length *m* has at least one selected symbol. Note that here we choose positions of symbols, not the symbols themselves.
Then one uses the chosen symbols to form a new string. All symbols from the chosen position should be used, but we are allowed to rearrange them in any order.
Formally, we choose a subsequence of indices 1<=≤<=*i*1<=<<=*i*2<=<<=...<=<<=*i**t*<=≤<=|*s*|. The selected sequence must meet the following condition: for every *j* such that 1<=≤<=*j*<=≤<=|*s*|<=-<=*m*<=+<=1, there must be at least one selected index that belongs to the segment [*j*,<= *j*<=+<=*m*<=-<=1], i.e. there should exist a *k* from 1 to *t*, such that *j*<=≤<=*i**k*<=≤<=*j*<=+<=*m*<=-<=1.
Then we take any permutation *p* of the selected indices and form a new string *s**i**p*1*s**i**p*2... *s**i**p**t*.
Find the lexicographically smallest string, that can be obtained using this procedure. | The first line of the input contains a single integer *m* (1<=≤<=*m*<=≤<=100<=000).
The second line contains the string *s* consisting of lowercase English letters. It is guaranteed that this string is non-empty and its length doesn't exceed 100<=000. It is also guaranteed that the number *m* doesn't exceed the length of the string *s*. | Print the single line containing the lexicographically smallest string, that can be obtained using the procedure described above. | [
"3\ncbabc\n",
"2\nabcab\n",
"3\nbcabcbaccba\n"
] | [
"a\n",
"aab\n",
"aaabb\n"
] | In the first sample, one can choose the subsequence {3} and form a string "a".
In the second sample, one can choose the subsequence {1, 2, 4} (symbols on this positions are 'a', 'b' and 'a') and rearrange the chosen symbols to form a string "aab". | 1,500 | [
{
"input": "3\ncbabc",
"output": "a"
},
{
"input": "2\nabcab",
"output": "aab"
},
{
"input": "3\nbcabcbaccba",
"output": "aaabb"
},
{
"input": "5\nimmaydobun",
"output": "ab"
},
{
"input": "5\nwjjdqawypvtgrncmqvcsergermprauyevcegjtcrrblkwiugrcjfpjyxngyryxntauxlouv... | 1,698,883,444 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 155 | 4,096,000 | m = int(input())
s = input()
n = len(s)
t = []
u = [1] * n
d = 'a'
i = 0
while i <= n - m:
k = i
for j in range(m):
if s[i + j] <= s[k]: k = i + j
t += [s[k]]
d = max(d, s[k])
u[k] = 0
i = k + 1
t += [q for q, v in zip(s, u) if q < d and v]
print(''.join(sorted(t))) | Title: Dense Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s*, consisting of lowercase English letters, and the integer *m*.
One should choose some symbols from the given string so that any contiguous subsegment of length *m* has at least one selected symbol. Note that here we choose positions of symbols, not the symbols themselves.
Then one uses the chosen symbols to form a new string. All symbols from the chosen position should be used, but we are allowed to rearrange them in any order.
Formally, we choose a subsequence of indices 1<=≤<=*i*1<=<<=*i*2<=<<=...<=<<=*i**t*<=≤<=|*s*|. The selected sequence must meet the following condition: for every *j* such that 1<=≤<=*j*<=≤<=|*s*|<=-<=*m*<=+<=1, there must be at least one selected index that belongs to the segment [*j*,<= *j*<=+<=*m*<=-<=1], i.e. there should exist a *k* from 1 to *t*, such that *j*<=≤<=*i**k*<=≤<=*j*<=+<=*m*<=-<=1.
Then we take any permutation *p* of the selected indices and form a new string *s**i**p*1*s**i**p*2... *s**i**p**t*.
Find the lexicographically smallest string, that can be obtained using this procedure.
Input Specification:
The first line of the input contains a single integer *m* (1<=≤<=*m*<=≤<=100<=000).
The second line contains the string *s* consisting of lowercase English letters. It is guaranteed that this string is non-empty and its length doesn't exceed 100<=000. It is also guaranteed that the number *m* doesn't exceed the length of the string *s*.
Output Specification:
Print the single line containing the lexicographically smallest string, that can be obtained using the procedure described above.
Demo Input:
['3\ncbabc\n', '2\nabcab\n', '3\nbcabcbaccba\n']
Demo Output:
['a\n', 'aab\n', 'aaabb\n']
Note:
In the first sample, one can choose the subsequence {3} and form a string "a".
In the second sample, one can choose the subsequence {1, 2, 4} (symbols on this positions are 'a', 'b' and 'a') and rearrange the chosen symbols to form a string "aab". | ```python
m = int(input())
s = input()
n = len(s)
t = []
u = [1] * n
d = 'a'
i = 0
while i <= n - m:
k = i
for j in range(m):
if s[i + j] <= s[k]: k = i + j
t += [s[k]]
d = max(d, s[k])
u[k] = 0
i = k + 1
t += [q for q, v in zip(s, u) if q < d and v]
print(''.join(sorted(t)))
``` | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,587,559,502 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 248 | 0 | s = [0, 0, 0]
for _ in range(int(input())):
x, y, z = map(int, input().split())
s[0] += x
s[1] += y
s[2] += z
if all(i == 0 for i in s):
print('YES')
else:
print('NO')
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
s = [0, 0, 0]
for _ in range(int(input())):
x, y, z = map(int, input().split())
s[0] += x
s[1] += y
s[2] += z
if all(i == 0 for i in s):
print('YES')
else:
print('NO')
``` | 3.938 |
1,003 | A | Polycarp's Pockets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that. | The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins. | Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket. | [
"6\n1 2 4 3 3 2\n",
"1\n100\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "6\n1 2 4 3 3 2",
"output": "2"
},
{
"input": "1\n100",
"output": "1"
},
{
"input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100... | 1,667,238,624 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n_ = int(input())
n = input().split()
total = 1
s = []
for i in range(n_):
n[i] = int(n[i])
if n[i] in s:
if total == s.count(n[i]):
total += 1
s.append(s)
else:
s.append(n[i])
print(total)
| Title: Polycarp's Pockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that.
Input Specification:
The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins.
Output Specification:
Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket.
Demo Input:
['6\n1 2 4 3 3 2\n', '1\n100\n']
Demo Output:
['2\n', '1\n']
Note:
none | ```python
n_ = int(input())
n = input().split()
total = 1
s = []
for i in range(n_):
n[i] = int(n[i])
if n[i] in s:
if total == s.count(n[i]):
total += 1
s.append(s)
else:
s.append(n[i])
print(total)
``` | 0 | |
215 | A | Bicycle Chain | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Vasya's bicycle chain drive consists of two parts: *n* stars are attached to the pedal axle, *m* stars are attached to the rear wheel axle. The chain helps to rotate the rear wheel by transmitting the pedal rotation.
We know that the *i*-th star on the pedal axle has *a**i* (0<=<<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*) teeth, and the *j*-th star on the rear wheel axle has *b**j* (0<=<<=*b*1<=<<=*b*2<=<<=...<=<<=*b**m*) teeth. Any pair (*i*,<=*j*) (1<=≤<=*i*<=≤<=*n*; 1<=≤<=*j*<=≤<=*m*) is called a gear and sets the indexes of stars to which the chain is currently attached. Gear (*i*,<=*j*) has a gear ratio, equal to the value .
Since Vasya likes integers, he wants to find such gears (*i*,<=*j*), that their ratios are integers. On the other hand, Vasya likes fast driving, so among all "integer" gears (*i*,<=*j*) he wants to choose a gear with the maximum ratio. Help him to find the number of such gears.
In the problem, fraction denotes division in real numbers, that is, no rounding is performed. | The first input line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stars on the bicycle's pedal axle. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) in the order of strict increasing.
The third input line contains integer *m* (1<=≤<=*m*<=≤<=50) — the number of stars on the rear wheel axle. The fourth line contains *m* integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=104) in the order of strict increasing.
It is guaranteed that there exists at least one gear (*i*,<=*j*), that its gear ratio is an integer. The numbers on the lines are separated by spaces. | Print the number of "integer" gears with the maximum ratio among all "integer" gears. | [
"2\n4 5\n3\n12 13 15\n",
"4\n1 2 3 4\n5\n10 11 12 13 14\n"
] | [
"2\n",
"1\n"
] | In the first sample the maximum "integer" gear ratio equals 3. There are two gears that have such gear ratio. For one of them *a*<sub class="lower-index">1</sub> = 4, *b*<sub class="lower-index">1</sub> = 12, and for the other *a*<sub class="lower-index">2</sub> = 5, *b*<sub class="lower-index">3</sub> = 15. | 500 | [
{
"input": "2\n4 5\n3\n12 13 15",
"output": "2"
},
{
"input": "4\n1 2 3 4\n5\n10 11 12 13 14",
"output": "1"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 2\n1\n1",
"output": "1"
},
{
"input": "1\n1\n2\n1 2",
"output": "1"
},
{
"input":... | 1,589,101,860 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 372 | 22,220,800 | t=int(input(""))
d=list(map(int,input("").split(" ")))
f=int(input(""))
a=list(map(int,input("").split(" ")))
v=[]
for i in d:
list=[]
for j in a:
if j%i==0:
list.append(j/i)
v.append(max(list))
g=max(v)
s=0
for o in range(len(v)):
if g==v[o]:
s+=1
print(s) | Title: Bicycle Chain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya's bicycle chain drive consists of two parts: *n* stars are attached to the pedal axle, *m* stars are attached to the rear wheel axle. The chain helps to rotate the rear wheel by transmitting the pedal rotation.
We know that the *i*-th star on the pedal axle has *a**i* (0<=<<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*) teeth, and the *j*-th star on the rear wheel axle has *b**j* (0<=<<=*b*1<=<<=*b*2<=<<=...<=<<=*b**m*) teeth. Any pair (*i*,<=*j*) (1<=≤<=*i*<=≤<=*n*; 1<=≤<=*j*<=≤<=*m*) is called a gear and sets the indexes of stars to which the chain is currently attached. Gear (*i*,<=*j*) has a gear ratio, equal to the value .
Since Vasya likes integers, he wants to find such gears (*i*,<=*j*), that their ratios are integers. On the other hand, Vasya likes fast driving, so among all "integer" gears (*i*,<=*j*) he wants to choose a gear with the maximum ratio. Help him to find the number of such gears.
In the problem, fraction denotes division in real numbers, that is, no rounding is performed.
Input Specification:
The first input line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stars on the bicycle's pedal axle. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) in the order of strict increasing.
The third input line contains integer *m* (1<=≤<=*m*<=≤<=50) — the number of stars on the rear wheel axle. The fourth line contains *m* integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=104) in the order of strict increasing.
It is guaranteed that there exists at least one gear (*i*,<=*j*), that its gear ratio is an integer. The numbers on the lines are separated by spaces.
Output Specification:
Print the number of "integer" gears with the maximum ratio among all "integer" gears.
Demo Input:
['2\n4 5\n3\n12 13 15\n', '4\n1 2 3 4\n5\n10 11 12 13 14\n']
Demo Output:
['2\n', '1\n']
Note:
In the first sample the maximum "integer" gear ratio equals 3. There are two gears that have such gear ratio. For one of them *a*<sub class="lower-index">1</sub> = 4, *b*<sub class="lower-index">1</sub> = 12, and for the other *a*<sub class="lower-index">2</sub> = 5, *b*<sub class="lower-index">3</sub> = 15. | ```python
t=int(input(""))
d=list(map(int,input("").split(" ")))
f=int(input(""))
a=list(map(int,input("").split(" ")))
v=[]
for i in d:
list=[]
for j in a:
if j%i==0:
list.append(j/i)
v.append(max(list))
g=max(v)
s=0
for o in range(len(v)):
if g==v[o]:
s+=1
print(s)
``` | -1 | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel. | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels. | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,700,285,868 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 9,932,800 | Pri, coin = map(int, input().split())
R = 1
X = int(str(Pri)[-1])
while True:
if str(X)[-1] == str(coin) or str(X)[-1] == '0':
break
R += 1
X += X
print(R)
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel.
Input Specification:
The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels.
Output Specification:
Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change.
Demo Input:
['117 3\n', '237 7\n', '15 2\n']
Demo Output:
['9\n', '1\n', '2\n']
Note:
In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | ```python
Pri, coin = map(int, input().split())
R = 1
X = int(str(Pri)[-1])
while True:
if str(X)[-1] == str(coin) or str(X)[-1] == '0':
break
R += 1
X += X
print(R)
``` | 0 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get. | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,698,288,992 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 62 | 0 | a = int(input())
b = int(input())
c = int(input())
m = a+b+c
def ifm(res):
global m
if res > m: m = res
ifm(a*b*c)
ifm(a*b+c)
ifm(a*(b+c))
ifm(a+b*c)
ifm((a+b)*c)
print(m) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get.
Input Specification:
The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10).
Output Specification:
Print the maximum value of the expression that you can obtain.
Demo Input:
['1\n2\n3\n', '2\n10\n3\n']
Demo Output:
['9\n', '60\n']
Note:
none | ```python
a = int(input())
b = int(input())
c = int(input())
m = a+b+c
def ifm(res):
global m
if res > m: m = res
ifm(a*b*c)
ifm(a*b+c)
ifm(a*(b+c))
ifm(a+b*c)
ifm((a+b)*c)
print(m)
``` | 3 | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million.
Petya wanted to modernize the words we use for numbers and invented a word petricium that represents number *k*. Moreover, petricium la petricium stands for number *k*2, petricium la petricium la petricium stands for *k*3 and so on. All numbers of this form are called petriciumus cifera, and the number's importance is the number of articles la in its title.
Petya's invention brought on a challenge that needed to be solved quickly: does some number *l* belong to the set petriciumus cifera? As Petya is a very busy schoolboy he needs to automate the process, he asked you to solve it. | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,580,298,045 | 2,147,483,647 | PyPy 3 | OK | TESTS | 64 | 310 | 0 | k = int(input())
l = int(input())
for x in range(32):
if l == k * pow(k,x):
print('YES')
print(x)
break
if l < k * pow(k,x):
print('NO')
break
| Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million.
Petya wanted to modernize the words we use for numbers and invented a word petricium that represents number *k*. Moreover, petricium la petricium stands for number *k*2, petricium la petricium la petricium stands for *k*3 and so on. All numbers of this form are called petriciumus cifera, and the number's importance is the number of articles la in its title.
Petya's invention brought on a challenge that needed to be solved quickly: does some number *l* belong to the set petriciumus cifera? As Petya is a very busy schoolboy he needs to automate the process, he asked you to solve it.
Input Specification:
The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1).
Output Specification:
You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*.
Demo Input:
['5\n25\n', '3\n8\n']
Demo Output:
['YES\n1\n', 'NO\n']
Note:
none | ```python
k = int(input())
l = int(input())
for x in range(32):
if l == k * pow(k,x):
print('YES')
print(x)
break
if l < k * pow(k,x):
print('NO')
break
``` | 3 | |
715 | A | Plus and Square Root | PROGRAMMING | 1,600 | [
"constructive algorithms",
"math"
] | null | null | ZS the Coder is playing a game. There is a number displayed on the screen and there are two buttons, '<=+<=' (plus) and '' (square root). Initially, the number 2 is displayed on the screen. There are *n*<=+<=1 levels in the game and ZS the Coder start at the level 1.
When ZS the Coder is at level *k*, he can :
1. Press the '<=+<=' button. This increases the number on the screen by exactly *k*. So, if the number on the screen was *x*, it becomes *x*<=+<=*k*.1. Press the '' button. Let the number on the screen be *x*. After pressing this button, the number becomes . After that, ZS the Coder levels up, so his current level becomes *k*<=+<=1. This button can only be pressed when *x* is a perfect square, i.e. *x*<==<=*m*2 for some positive integer *m*.
Additionally, after each move, if ZS the Coder is at level *k*, and the number on the screen is *m*, then *m* must be a multiple of *k*. Note that this condition is only checked after performing the press. For example, if ZS the Coder is at level 4 and current number is 100, he presses the '' button and the number turns into 10. Note that at this moment, 10 is not divisible by 4, but this press is still valid, because after it, ZS the Coder is at level 5, and 10 is divisible by 5.
ZS the Coder needs your help in beating the game — he wants to reach level *n*<=+<=1. In other words, he needs to press the '' button *n* times. Help him determine the number of times he should press the '<=+<=' button before pressing the '' button at each level.
Please note that ZS the Coder wants to find just any sequence of presses allowing him to reach level *n*<=+<=1, but not necessarily a sequence minimizing the number of presses. | The first and only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000), denoting that ZS the Coder wants to reach level *n*<=+<=1. | Print *n* non-negative integers, one per line. *i*-th of them should be equal to the number of times that ZS the Coder needs to press the '<=+<=' button before pressing the '' button at level *i*.
Each number in the output should not exceed 1018. However, the number on the screen can be greater than 1018.
It is guaranteed that at least one solution exists. If there are multiple solutions, print any of them. | [
"3\n",
"2\n",
"4\n"
] | [
"14\n16\n46\n",
"999999999999999998\n44500000000\n",
"2\n17\n46\n97\n"
] | In the first sample case:
On the first level, ZS the Coder pressed the ' + ' button 14 times (and the number on screen is initially 2), so the number became 2 + 14·1 = 16. Then, ZS the Coder pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, and the number became <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c3d2663f5f74e9220fd5cbccbfaf4ca76ef7284f.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the second level, ZS pressed the ' + ' button 16 times, so the number becomes 4 + 16·2 = 36. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/49ab1d31f1435b7c7b96550d63a35be671d3d85a.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the third level, ZS pressed the ' + ' button 46 times, so the number becomes 6 + 46·3 = 144. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/499b57d4b7ba5e1e0957767cc182808ca48ef722.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
Note that 12 is indeed divisible by 4, so ZS the Coder can reach level 4.
Also, note that pressing the ' + ' button 10 times on the third level before levelling up does not work, because the number becomes 6 + 10·3 = 36, and when the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button is pressed, the number becomes <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/49ab1d31f1435b7c7b96550d63a35be671d3d85a.png" style="max-width: 100.0%;max-height: 100.0%;"/> and ZS the Coder is at Level 4. However, 6 is not divisible by 4 now, so this is not a valid solution.
In the second sample case:
On the first level, ZS the Coder pressed the ' + ' button 999999999999999998 times (and the number on screen is initially 2), so the number became 2 + 999999999999999998·1 = 10<sup class="upper-index">18</sup>. Then, ZS the Coder pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, and the number became <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f07f2a60ab6cecbd2507861a0df57a16a015fd86.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the second level, ZS pressed the ' + ' button 44500000000 times, so the number becomes 10<sup class="upper-index">9</sup> + 44500000000·2 = 9·10<sup class="upper-index">10</sup>. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4c4d8829d987a7bcfd597cd1aa101327a66c0eca.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
Note that 300000 is a multiple of 3, so ZS the Coder can reach level 3. | 500 | [
{
"input": "3",
"output": "2\n17\n46"
},
{
"input": "2",
"output": "2\n17"
},
{
"input": "4",
"output": "2\n17\n46\n97"
},
{
"input": "1",
"output": "2"
},
{
"input": "100000",
"output": "2\n17\n46\n97\n176\n289\n442\n641\n892\n1201\n1574\n2017\n2536\n3137\n38... | 1,535,281,802 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 514 | 102,400 | x=2
for i in range(1, int(input())+1):
print(i*(i+1)**2-x)
x=i
# Made By Mostafa_Khaled | Title: Plus and Square Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is playing a game. There is a number displayed on the screen and there are two buttons, '<=+<=' (plus) and '' (square root). Initially, the number 2 is displayed on the screen. There are *n*<=+<=1 levels in the game and ZS the Coder start at the level 1.
When ZS the Coder is at level *k*, he can :
1. Press the '<=+<=' button. This increases the number on the screen by exactly *k*. So, if the number on the screen was *x*, it becomes *x*<=+<=*k*.1. Press the '' button. Let the number on the screen be *x*. After pressing this button, the number becomes . After that, ZS the Coder levels up, so his current level becomes *k*<=+<=1. This button can only be pressed when *x* is a perfect square, i.e. *x*<==<=*m*2 for some positive integer *m*.
Additionally, after each move, if ZS the Coder is at level *k*, and the number on the screen is *m*, then *m* must be a multiple of *k*. Note that this condition is only checked after performing the press. For example, if ZS the Coder is at level 4 and current number is 100, he presses the '' button and the number turns into 10. Note that at this moment, 10 is not divisible by 4, but this press is still valid, because after it, ZS the Coder is at level 5, and 10 is divisible by 5.
ZS the Coder needs your help in beating the game — he wants to reach level *n*<=+<=1. In other words, he needs to press the '' button *n* times. Help him determine the number of times he should press the '<=+<=' button before pressing the '' button at each level.
Please note that ZS the Coder wants to find just any sequence of presses allowing him to reach level *n*<=+<=1, but not necessarily a sequence minimizing the number of presses.
Input Specification:
The first and only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000), denoting that ZS the Coder wants to reach level *n*<=+<=1.
Output Specification:
Print *n* non-negative integers, one per line. *i*-th of them should be equal to the number of times that ZS the Coder needs to press the '<=+<=' button before pressing the '' button at level *i*.
Each number in the output should not exceed 1018. However, the number on the screen can be greater than 1018.
It is guaranteed that at least one solution exists. If there are multiple solutions, print any of them.
Demo Input:
['3\n', '2\n', '4\n']
Demo Output:
['14\n16\n46\n', '999999999999999998\n44500000000\n', '2\n17\n46\n97\n']
Note:
In the first sample case:
On the first level, ZS the Coder pressed the ' + ' button 14 times (and the number on screen is initially 2), so the number became 2 + 14·1 = 16. Then, ZS the Coder pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, and the number became <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c3d2663f5f74e9220fd5cbccbfaf4ca76ef7284f.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the second level, ZS pressed the ' + ' button 16 times, so the number becomes 4 + 16·2 = 36. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/49ab1d31f1435b7c7b96550d63a35be671d3d85a.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the third level, ZS pressed the ' + ' button 46 times, so the number becomes 6 + 46·3 = 144. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/499b57d4b7ba5e1e0957767cc182808ca48ef722.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
Note that 12 is indeed divisible by 4, so ZS the Coder can reach level 4.
Also, note that pressing the ' + ' button 10 times on the third level before levelling up does not work, because the number becomes 6 + 10·3 = 36, and when the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button is pressed, the number becomes <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/49ab1d31f1435b7c7b96550d63a35be671d3d85a.png" style="max-width: 100.0%;max-height: 100.0%;"/> and ZS the Coder is at Level 4. However, 6 is not divisible by 4 now, so this is not a valid solution.
In the second sample case:
On the first level, ZS the Coder pressed the ' + ' button 999999999999999998 times (and the number on screen is initially 2), so the number became 2 + 999999999999999998·1 = 10<sup class="upper-index">18</sup>. Then, ZS the Coder pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, and the number became <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f07f2a60ab6cecbd2507861a0df57a16a015fd86.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
After that, on the second level, ZS pressed the ' + ' button 44500000000 times, so the number becomes 10<sup class="upper-index">9</sup> + 44500000000·2 = 9·10<sup class="upper-index">10</sup>. Then, ZS pressed the '<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c77ded9b8209a8cb488cc2ec7b7fe1dae32a5309.png" style="max-width: 100.0%;max-height: 100.0%;"/>' button, levelling up and changing the number into <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4c4d8829d987a7bcfd597cd1aa101327a66c0eca.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
Note that 300000 is a multiple of 3, so ZS the Coder can reach level 3. | ```python
x=2
for i in range(1, int(input())+1):
print(i*(i+1)**2-x)
x=i
# Made By Mostafa_Khaled
``` | 3 | |
721 | A | One-dimensional Japanese Crossword | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers represents how many groups of black squares there are in corresponding row or column, and the integers themselves represents the number of consecutive black squares in corresponding group (you can find more detailed explanation in Wikipedia [https://en.wikipedia.org/wiki/Japanese_crossword](https://en.wikipedia.org/wiki/Japanese_crossword)).
Adaltik decided that the general case of japanese crossword is too complicated and drew a row consisting of *n* squares (e.g. japanese crossword sized 1<=×<=*n*), which he wants to encrypt in the same way as in japanese crossword.
Help Adaltik find the numbers encrypting the row he drew. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew). | The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right. | [
"3\nBBW\n",
"5\nBWBWB\n",
"4\nWWWW\n",
"4\nBBBB\n",
"13\nWBBBBWWBWBBBW\n"
] | [
"1\n2 ",
"3\n1 1 1 ",
"0\n",
"1\n4 ",
"3\n4 1 3 "
] | The last sample case correspond to the picture in the statement. | 500 | [
{
"input": "3\nBBW",
"output": "1\n2 "
},
{
"input": "5\nBWBWB",
"output": "3\n1 1 1 "
},
{
"input": "4\nWWWW",
"output": "0"
},
{
"input": "4\nBBBB",
"output": "1\n4 "
},
{
"input": "13\nWBBBBWWBWBBBW",
"output": "3\n4 1 3 "
},
{
"input": "1\nB",
... | 1,661,130,260 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | a = int(input())
chars = input()
newSeq = False
seqCount = 0
seqs = 0
toPrint = []
for i in range(len(chars)):
if (chars[i] == "B"):
seqCount += 1
if (newSeq == False):
newSeq = True
if(i == len(chars) - 1): # last loop
toPrint.append(seqCount )
seqs += 1
elif chars[i] == "W":
if (newSeq == True):
newSeq = False
toPrint.append(seqCount )
seqCount = 0
seqs += 1
# else:
# if(chars[i] == "B"):
# toPrint.append(seqCount + 1)
# seqs += 1
print(seqs)
if (len(toPrint) > 0):
print(*toPrint)
| Title: One-dimensional Japanese Crossword
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers represents how many groups of black squares there are in corresponding row or column, and the integers themselves represents the number of consecutive black squares in corresponding group (you can find more detailed explanation in Wikipedia [https://en.wikipedia.org/wiki/Japanese_crossword](https://en.wikipedia.org/wiki/Japanese_crossword)).
Adaltik decided that the general case of japanese crossword is too complicated and drew a row consisting of *n* squares (e.g. japanese crossword sized 1<=×<=*n*), which he wants to encrypt in the same way as in japanese crossword.
Help Adaltik find the numbers encrypting the row he drew.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew).
Output Specification:
The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right.
Demo Input:
['3\nBBW\n', '5\nBWBWB\n', '4\nWWWW\n', '4\nBBBB\n', '13\nWBBBBWWBWBBBW\n']
Demo Output:
['1\n2 ', '3\n1 1 1 ', '0\n', '1\n4 ', '3\n4 1 3 ']
Note:
The last sample case correspond to the picture in the statement. | ```python
a = int(input())
chars = input()
newSeq = False
seqCount = 0
seqs = 0
toPrint = []
for i in range(len(chars)):
if (chars[i] == "B"):
seqCount += 1
if (newSeq == False):
newSeq = True
if(i == len(chars) - 1): # last loop
toPrint.append(seqCount )
seqs += 1
elif chars[i] == "W":
if (newSeq == True):
newSeq = False
toPrint.append(seqCount )
seqCount = 0
seqs += 1
# else:
# if(chars[i] == "B"):
# toPrint.append(seqCount + 1)
# seqs += 1
print(seqs)
if (len(toPrint) > 0):
print(*toPrint)
``` | 3 | |
381 | A | Sereja and Dima | PROGRAMMING | 800 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. | On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. | [
"4\n4 1 2 10\n",
"7\n1 2 3 4 5 6 7\n"
] | [
"12 5\n",
"16 12\n"
] | In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | 500 | [
{
"input": "4\n4 1 2 10",
"output": "12 5"
},
{
"input": "7\n1 2 3 4 5 6 7",
"output": "16 12"
},
{
"input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13",
"output": "613 418"
},
{
"input": "43\n32 ... | 1,689,691,219 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n = int(input())
cards = list(map(int , input().split()))
sereja = 0
dima = 0
while len(cards) != 0:
sereja += max(cards[0], cards[len(cards)-1])
cards.remove(max(cards[0], cards[len(cards)-1]))
if len(cards) == 0:
break
dima += max(cards[0], cards[len(cards)-1])
cards.remove(max(cards[0], cards[len(cards)-1]))
print(sereja , dima) | Title: Sereja and Dima
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.
Output Specification:
On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.
Demo Input:
['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n']
Demo Output:
['12 5\n', '16 12\n']
Note:
In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | ```python
n = int(input())
cards = list(map(int , input().split()))
sereja = 0
dima = 0
while len(cards) != 0:
sereja += max(cards[0], cards[len(cards)-1])
cards.remove(max(cards[0], cards[len(cards)-1]))
if len(cards) == 0:
break
dima += max(cards[0], cards[len(cards)-1])
cards.remove(max(cards[0], cards[len(cards)-1]))
print(sereja , dima)
``` | 3 | |
337 | B | Routine Problem | PROGRAMMING | 1,400 | [
"greedy",
"math",
"number theory"
] | null | null | Manao has a monitor. The screen of the monitor has horizontal to vertical length ratio *a*:*b*. Now he is going to watch a movie. The movie's frame has horizontal to vertical length ratio *c*:*d*. Manao adjusts the view in such a way that the movie preserves the original frame ratio, but also occupies as much space on the screen as possible and fits within it completely. Thus, he may have to zoom the movie in or out, but Manao will always change the frame proportionally in both dimensions.
Calculate the ratio of empty screen (the part of the screen not occupied by the movie) to the total screen size. Print the answer as an irreducible fraction *p*<=/<=*q*. | A single line contains four space-separated integers *a*, *b*, *c*, *d* (1<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000). | Print the answer to the problem as "p/q", where *p* is a non-negative integer, *q* is a positive integer and numbers *p* and *q* don't have a common divisor larger than 1. | [
"1 1 3 2\n",
"4 3 2 2\n"
] | [
"1/3\n",
"1/4\n"
] | Sample 1. Manao's monitor has a square screen. The movie has 3:2 horizontal to vertical length ratio. Obviously, the movie occupies most of the screen if the width of the picture coincides with the width of the screen. In this case, only 2/3 of the monitor will project the movie in the horizontal dimension: <img class="tex-graphics" src="https://espresso.codeforces.com/ce823413ad27813e27496a0d8bd4231e94b47662.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Sample 2. This time the monitor's width is 4/3 times larger than its height and the movie's frame is square. In this case, the picture must take up the whole monitor in the vertical dimension and only 3/4 in the horizontal dimension: <img class="tex-graphics" src="https://espresso.codeforces.com/c2bcb3b1f64810812eee368ff180e3e148d24c67.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "1 1 3 2",
"output": "1/3"
},
{
"input": "4 3 2 2",
"output": "1/4"
},
{
"input": "3 4 2 3",
"output": "1/9"
},
{
"input": "4 4 5 5",
"output": "0/1"
},
{
"input": "1 1 1 1",
"output": "0/1"
},
{
"input": "1000 1000 1000 1000",
"output":... | 1,687,978,220 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | from math import gcd
a, b, c, d = map(int, input().split())
if a*d > b * c: a, b, c, d = b, a, d, c
p, q = b * c - a * d, b * c
print(p // gcd(p, q), q // gcd(p, q)) | Title: Routine Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao has a monitor. The screen of the monitor has horizontal to vertical length ratio *a*:*b*. Now he is going to watch a movie. The movie's frame has horizontal to vertical length ratio *c*:*d*. Manao adjusts the view in such a way that the movie preserves the original frame ratio, but also occupies as much space on the screen as possible and fits within it completely. Thus, he may have to zoom the movie in or out, but Manao will always change the frame proportionally in both dimensions.
Calculate the ratio of empty screen (the part of the screen not occupied by the movie) to the total screen size. Print the answer as an irreducible fraction *p*<=/<=*q*.
Input Specification:
A single line contains four space-separated integers *a*, *b*, *c*, *d* (1<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000).
Output Specification:
Print the answer to the problem as "p/q", where *p* is a non-negative integer, *q* is a positive integer and numbers *p* and *q* don't have a common divisor larger than 1.
Demo Input:
['1 1 3 2\n', '4 3 2 2\n']
Demo Output:
['1/3\n', '1/4\n']
Note:
Sample 1. Manao's monitor has a square screen. The movie has 3:2 horizontal to vertical length ratio. Obviously, the movie occupies most of the screen if the width of the picture coincides with the width of the screen. In this case, only 2/3 of the monitor will project the movie in the horizontal dimension: <img class="tex-graphics" src="https://espresso.codeforces.com/ce823413ad27813e27496a0d8bd4231e94b47662.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Sample 2. This time the monitor's width is 4/3 times larger than its height and the movie's frame is square. In this case, the picture must take up the whole monitor in the vertical dimension and only 3/4 in the horizontal dimension: <img class="tex-graphics" src="https://espresso.codeforces.com/c2bcb3b1f64810812eee368ff180e3e148d24c67.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
from math import gcd
a, b, c, d = map(int, input().split())
if a*d > b * c: a, b, c, d = b, a, d, c
p, q = b * c - a * d, b * c
print(p // gcd(p, q), q // gcd(p, q))
``` | 0 | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly this amount of chicken.
Formally, Ivan wants to know if he can choose two non-negative integers *a* and *b* in such a way that *a* small portions and *b* large ones contain exactly *x* chunks.
Help Ivan to answer this question for several values of *x*! | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,646,050,745 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=int(input())
for i in range(n):
a=int(input())
if a%7==0 or a%3==0 or a%10==0 or a%13==0 or a%17==0 or a%23==0 or a%37==0 or a %44==0 or (a-10)%3==0 or (a-13)%3==0 or (a-10)%7==0 or (a-13)%7==0
print('YES')
else:
print('NO')
| Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly this amount of chicken.
Formally, Ivan wants to know if he can choose two non-negative integers *a* and *b* in such a way that *a* small portions and *b* large ones contain exactly *x* chunks.
Help Ivan to answer this question for several values of *x*!
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat.
Output Specification:
Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO.
Demo Input:
['2\n6\n5\n']
Demo Output:
['YES\nNO\n']
Note:
In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | ```python
n=int(input())
for i in range(n):
a=int(input())
if a%7==0 or a%3==0 or a%10==0 or a%13==0 or a%17==0 or a%23==0 or a%37==0 or a %44==0 or (a-10)%3==0 or (a-13)%3==0 or (a-10)%7==0 or (a-13)%7==0
print('YES')
else:
print('NO')
``` | -1 | |
812 | A | Sagheer and Crossroads | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 lanes getting out of the intersection, so we have 4 parts in total. Each part has 4 lights, one for each lane getting into the intersection (*l* — left, *s* — straight, *r* — right) and a light *p* for a pedestrian crossing.
An accident is possible if a car can hit a pedestrian. This can happen if the light of a pedestrian crossing of some part and the light of a lane that can get to or from that same part are green at the same time.
Now, Sagheer is monitoring the configuration of the traffic lights. Your task is to help him detect whether an accident is possible. | The input consists of four lines with each line describing a road part given in a counter-clockwise order.
Each line contains four integers *l*, *s*, *r*, *p* — for the left, straight, right and pedestrian lights, respectively. The possible values are 0 for red light and 1 for green light. | On a single line, print "YES" if an accident is possible, and "NO" otherwise. | [
"1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1\n",
"0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1\n",
"1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first example, some accidents are possible because cars of part 1 can hit pedestrians of parts 1 and 4. Also, cars of parts 2 and 3 can hit pedestrians of part 4.
In the second example, no car can pass the pedestrian crossing of part 4 which is the only green pedestrian light. So, no accident can occur. | 500 | [
{
"input": "1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1",
"output": "YES"
},
{
"input": "0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1",
"output": "NO"
},
{
"input": "1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0",
"output": "NO"
},
{
"input": "0 0 0 0\n0 0 0 1\n0 0 0 1\n0 0 0 1",
"output": "NO"
},
... | 1,496,326,891 | 391 | Python 3 | CHALLENGED | CHALLENGES | 7 | 46 | 0 | ans = 'NO'
for i in range(4):
l, s, r, p = map(int, input().split())
if (p == 1) and ((l + s + r) >= 1):
ans = 'YES'
print(ans) | Title: Sagheer and Crossroads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 lanes getting out of the intersection, so we have 4 parts in total. Each part has 4 lights, one for each lane getting into the intersection (*l* — left, *s* — straight, *r* — right) and a light *p* for a pedestrian crossing.
An accident is possible if a car can hit a pedestrian. This can happen if the light of a pedestrian crossing of some part and the light of a lane that can get to or from that same part are green at the same time.
Now, Sagheer is monitoring the configuration of the traffic lights. Your task is to help him detect whether an accident is possible.
Input Specification:
The input consists of four lines with each line describing a road part given in a counter-clockwise order.
Each line contains four integers *l*, *s*, *r*, *p* — for the left, straight, right and pedestrian lights, respectively. The possible values are 0 for red light and 1 for green light.
Output Specification:
On a single line, print "YES" if an accident is possible, and "NO" otherwise.
Demo Input:
['1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1\n', '0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1\n', '1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
In the first example, some accidents are possible because cars of part 1 can hit pedestrians of parts 1 and 4. Also, cars of parts 2 and 3 can hit pedestrians of part 4.
In the second example, no car can pass the pedestrian crossing of part 4 which is the only green pedestrian light. So, no accident can occur. | ```python
ans = 'NO'
for i in range(4):
l, s, r, p = map(int, input().split())
if (p == 1) and ((l + s + r) >= 1):
ans = 'YES'
print(ans)
``` | -1 | |
297 | B | Fish Weight | PROGRAMMING | 1,600 | [
"constructive algorithms",
"greedy"
] | null | null | It is known that there are *k* fish species in the polar ocean, numbered from 1 to *k*. They are sorted by non-decreasing order of their weight, which is a positive number. Let the weight of the *i*-th type of fish be *w**i*, then 0<=<<=*w*1<=≤<=*w*2<=≤<=...<=≤<=*w**k* holds.
Polar bears Alice and Bob each have caught some fish, and they are guessing who has the larger sum of weight of the fish he/she's caught. Given the type of the fish they've caught, determine whether it is possible that the fish caught by Alice has a strictly larger total weight than Bob's. In other words, does there exist a sequence of weights *w**i* (not necessary integers), such that the fish caught by Alice has a strictly larger total weight? | The first line contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of fish caught by Alice and Bob respectively, and the number of fish species.
The second line contains *n* integers each from 1 to *k*, the list of fish type caught by Alice. The third line contains *m* integers each from 1 to *k*, the list of fish type caught by Bob.
Note that one may have caught more than one fish for a same species. | Output "YES" (without quotes) if it is possible, and "NO" (without quotes) otherwise. | [
"3 3 3\n2 2 2\n1 1 3\n",
"4 7 9\n5 2 7 3\n3 5 2 7 3 8 7\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, if *w*<sub class="lower-index">1</sub> = 1, *w*<sub class="lower-index">2</sub> = 2, *w*<sub class="lower-index">3</sub> = 2.5, then Alice has a total of 2 + 2 + 2 = 6 weight units, while Bob only has 1 + 1 + 2.5 = 4.5.
In the second sample, the fish that Alice caught is a subset of Bob's. Therefore, the total weight of Bob’s fish is always not less than the total weight of Alice’s fish. | 500 | [
{
"input": "3 3 3\n2 2 2\n1 1 3",
"output": "YES"
},
{
"input": "4 7 9\n5 2 7 3\n3 5 2 7 3 8 7",
"output": "NO"
},
{
"input": "5 5 10\n8 2 8 5 9\n9 1 7 5 1",
"output": "YES"
},
{
"input": "7 7 10\n8 2 8 10 6 9 10\n2 4 9 5 6 2 5",
"output": "YES"
},
{
"input": "15 ... | 1,658,737,556 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | def f(a,b):
if len(a)>len(b):return 'YES'
a.sort()
b.sort()
print(a,b)
if any(a[-i]-b[-i]>0 for i in range(1,len(a)+1)):
return 'YES'
return 'NO'
if __name__=='__main__':
n,m,k=(int(i) for i in input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
print(f(a,b)) | Title: Fish Weight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is known that there are *k* fish species in the polar ocean, numbered from 1 to *k*. They are sorted by non-decreasing order of their weight, which is a positive number. Let the weight of the *i*-th type of fish be *w**i*, then 0<=<<=*w*1<=≤<=*w*2<=≤<=...<=≤<=*w**k* holds.
Polar bears Alice and Bob each have caught some fish, and they are guessing who has the larger sum of weight of the fish he/she's caught. Given the type of the fish they've caught, determine whether it is possible that the fish caught by Alice has a strictly larger total weight than Bob's. In other words, does there exist a sequence of weights *w**i* (not necessary integers), such that the fish caught by Alice has a strictly larger total weight?
Input Specification:
The first line contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of fish caught by Alice and Bob respectively, and the number of fish species.
The second line contains *n* integers each from 1 to *k*, the list of fish type caught by Alice. The third line contains *m* integers each from 1 to *k*, the list of fish type caught by Bob.
Note that one may have caught more than one fish for a same species.
Output Specification:
Output "YES" (without quotes) if it is possible, and "NO" (without quotes) otherwise.
Demo Input:
['3 3 3\n2 2 2\n1 1 3\n', '4 7 9\n5 2 7 3\n3 5 2 7 3 8 7\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample, if *w*<sub class="lower-index">1</sub> = 1, *w*<sub class="lower-index">2</sub> = 2, *w*<sub class="lower-index">3</sub> = 2.5, then Alice has a total of 2 + 2 + 2 = 6 weight units, while Bob only has 1 + 1 + 2.5 = 4.5.
In the second sample, the fish that Alice caught is a subset of Bob's. Therefore, the total weight of Bob’s fish is always not less than the total weight of Alice’s fish. | ```python
def f(a,b):
if len(a)>len(b):return 'YES'
a.sort()
b.sort()
print(a,b)
if any(a[-i]-b[-i]>0 for i in range(1,len(a)+1)):
return 'YES'
return 'NO'
if __name__=='__main__':
n,m,k=(int(i) for i in input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
print(f(a,b))
``` | 0 | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,589,834,582 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 218 | 2,150,400 | s = input()
s2 = ['h', 'e', 'i', 'd', 'i']
n = [-1 for i in range(5)]
id = 0
for i in range(len(s)):
if s[i] == s2[id] and n[id] == -1:
# print(s[i], s2[id])
n[id] = i
id+=1
for i in n:
if i == -1:
print("NO")
break
else:
print("YES")
# print(n)
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input Specification:
The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z).
Output Specification:
Output YES if the string *s* contains heidi as a subsequence and NO otherwise.
Demo Input:
['abcheaibcdi\n', 'hiedi\n']
Demo Output:
['YES', 'NO']
Note:
A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | ```python
s = input()
s2 = ['h', 'e', 'i', 'd', 'i']
n = [-1 for i in range(5)]
id = 0
for i in range(len(s)):
if s[i] == s2[id] and n[id] == -1:
# print(s[i], s2[id])
n[id] = i
id+=1
for i in n:
if i == -1:
print("NO")
break
else:
print("YES")
# print(n)
``` | -1 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not. | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence. | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,586,706,690 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | from sys import stdin
inp = stdin.readline
n = int(inp().strip())
s = inp().strip()
stf = 0
fts = 0
prev = s[0]
for city in s:
if prev == 'S' and city == 'F':
stf += 1
elif prev == 'F' and city == 'S':
fts += 1
prev = city
print("YES" if stf > fts else "NO") | Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not.
Input Specification:
The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output Specification:
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Demo Input:
['4\nFSSF\n', '2\nSF\n', '10\nFFFFFFFFFF\n', '10\nSSFFSFFSFF\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n', 'YES\n']
Note:
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | ```python
from sys import stdin
inp = stdin.readline
n = int(inp().strip())
s = inp().strip()
stf = 0
fts = 0
prev = s[0]
for city in s:
if prev == 'S' and city == 'F':
stf += 1
elif prev == 'F' and city == 'S':
fts += 1
prev = city
print("YES" if stf > fts else "NO")
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy to Morty before bad guys catch them.
There are *n* planets in their universe numbered from 1 to *n*. Rick is in planet number *s* (the earth) and he doesn't know where Morty is. As we all know, Rick owns a portal gun. With this gun he can open one-way portal from a planet he is in to any other planet (including that planet). But there are limits on this gun because he's still using its free trial.
By default he can not open any portal by this gun. There are *q* plans in the website that sells these guns. Every time you purchase a plan you can only use it once but you can purchase it again if you want to use it more.
Plans on the website have three types:
1. With a plan of this type you can open a portal from planet *v* to planet *u*. 1. With a plan of this type you can open a portal from planet *v* to any planet with index in range [*l*,<=*r*]. 1. With a plan of this type you can open a portal from any planet with index in range [*l*,<=*r*] to planet *v*.
Rick doesn't known where Morty is, but Unity is going to inform him and he wants to be prepared for when he finds and start his journey immediately. So for each planet (including earth itself) he wants to know the minimum amount of money he needs to get from earth to that planet. | The first line of input contains three integers *n*, *q* and *s* (1<=≤<=*n*,<=*q*<=≤<=105, 1<=≤<=*s*<=≤<=*n*) — number of planets, number of plans and index of earth respectively.
The next *q* lines contain the plans. Each line starts with a number *t*, type of that plan (1<=≤<=*t*<=≤<=3). If *t*<==<=1 then it is followed by three integers *v*, *u* and *w* where *w* is the cost of that plan (1<=≤<=*v*,<=*u*<=≤<=*n*, 1<=≤<=*w*<=≤<=109). Otherwise it is followed by four integers *v*, *l*, *r* and *w* where *w* is the cost of that plan (1<=≤<=*v*<=≤<=*n*, 1<=≤<=*l*<=≤<=*r*<=≤<=*n*, 1<=≤<=*w*<=≤<=109). | In the first and only line of output print *n* integers separated by spaces. *i*-th of them should be minimum money to get from earth to *i*-th planet, or <=-<=1 if it's impossible to get to that planet. | [
"3 5 1\n2 3 2 3 17\n2 3 2 2 16\n2 2 2 3 3\n3 3 1 1 12\n1 3 3 17\n",
"4 3 1\n3 4 1 3 12\n2 2 3 4 10\n1 2 4 16\n"
] | [
"0 28 12 \n",
"0 -1 -1 12 \n"
] | In the first sample testcase, Rick can purchase 4th plan once and then 2nd plan in order to get to get to planet number 2. | 0 | [] | 1,691,073,719 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1691073718.949566")# 1691073718.9495845 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy to Morty before bad guys catch them.
There are *n* planets in their universe numbered from 1 to *n*. Rick is in planet number *s* (the earth) and he doesn't know where Morty is. As we all know, Rick owns a portal gun. With this gun he can open one-way portal from a planet he is in to any other planet (including that planet). But there are limits on this gun because he's still using its free trial.
By default he can not open any portal by this gun. There are *q* plans in the website that sells these guns. Every time you purchase a plan you can only use it once but you can purchase it again if you want to use it more.
Plans on the website have three types:
1. With a plan of this type you can open a portal from planet *v* to planet *u*. 1. With a plan of this type you can open a portal from planet *v* to any planet with index in range [*l*,<=*r*]. 1. With a plan of this type you can open a portal from any planet with index in range [*l*,<=*r*] to planet *v*.
Rick doesn't known where Morty is, but Unity is going to inform him and he wants to be prepared for when he finds and start his journey immediately. So for each planet (including earth itself) he wants to know the minimum amount of money he needs to get from earth to that planet.
Input Specification:
The first line of input contains three integers *n*, *q* and *s* (1<=≤<=*n*,<=*q*<=≤<=105, 1<=≤<=*s*<=≤<=*n*) — number of planets, number of plans and index of earth respectively.
The next *q* lines contain the plans. Each line starts with a number *t*, type of that plan (1<=≤<=*t*<=≤<=3). If *t*<==<=1 then it is followed by three integers *v*, *u* and *w* where *w* is the cost of that plan (1<=≤<=*v*,<=*u*<=≤<=*n*, 1<=≤<=*w*<=≤<=109). Otherwise it is followed by four integers *v*, *l*, *r* and *w* where *w* is the cost of that plan (1<=≤<=*v*<=≤<=*n*, 1<=≤<=*l*<=≤<=*r*<=≤<=*n*, 1<=≤<=*w*<=≤<=109).
Output Specification:
In the first and only line of output print *n* integers separated by spaces. *i*-th of them should be minimum money to get from earth to *i*-th planet, or <=-<=1 if it's impossible to get to that planet.
Demo Input:
['3 5 1\n2 3 2 3 17\n2 3 2 2 16\n2 2 2 3 3\n3 3 1 1 12\n1 3 3 17\n', '4 3 1\n3 4 1 3 12\n2 2 3 4 10\n1 2 4 16\n']
Demo Output:
['0 28 12 \n', '0 -1 -1 12 \n']
Note:
In the first sample testcase, Rick can purchase 4th plan once and then 2nd plan in order to get to get to planet number 2. | ```python
print("_RANDOM_GUESS_1691073718.949566")# 1691073718.9495845
``` | 0 | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact. | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,601,596,734 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | def main():
q1 = a = q2 = 0
for s in input():
if s == 'Q':
q1 += 1
q2 += a
else:
a += q1
return q2
for m in range(1, 2 + 1):
o = str(main())
e = input()
if o != e:
print(f'Test {m} failed.\nOut: {o}\nExp: {e}\n')
else:
print(f'Test {m} passed!\n')
| Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact.
Input Specification:
The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters.
Output Specification:
Print a single integer — the number of subsequences "QAQ" in the string.
Demo Input:
['QAQAQYSYIOIWIN\n', 'QAQQQZZYNOIWIN\n']
Demo Output:
['4\n', '3\n']
Note:
In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | ```python
def main():
q1 = a = q2 = 0
for s in input():
if s == 'Q':
q1 += 1
q2 += a
else:
a += q1
return q2
for m in range(1, 2 + 1):
o = str(main())
e = input()
if o != e:
print(f'Test {m} failed.\nOut: {o}\nExp: {e}\n')
else:
print(f'Test {m} passed!\n')
``` | -1 | |
975 | B | Mancala | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Mancala is a game famous in the Middle East. It is played on a board that consists of 14 holes.
Initially, each hole has $a_i$ stones. When a player makes a move, he chooses a hole which contains a positive number of stones. He takes all the stones inside it and then redistributes these stones one by one in the next holes in a counter-clockwise direction.
Note that the counter-clockwise order means if the player takes the stones from hole $i$, he will put one stone in the $(i+1)$-th hole, then in the $(i+2)$-th, etc. If he puts a stone in the $14$-th hole, the next one will be put in the first hole.
After the move, the player collects all the stones from holes that contain even number of stones. The number of stones collected by player is the score, according to Resli.
Resli is a famous Mancala player. He wants to know the maximum score he can obtain after one move. | The only line contains 14 integers $a_1, a_2, \ldots, a_{14}$ ($0 \leq a_i \leq 10^9$) — the number of stones in each hole.
It is guaranteed that for any $i$ ($1\leq i \leq 14$) $a_i$ is either zero or odd, and there is at least one stone in the board. | Output one integer, the maximum possible score after one move. | [
"0 1 1 0 0 0 0 0 0 7 0 0 0 0\n",
"5 1 1 1 1 0 0 0 0 0 0 0 0 0\n"
] | [
"4\n",
"8\n"
] | In the first test case the board after the move from the hole with $7$ stones will look like 1 2 2 0 0 0 0 0 0 0 1 1 1 1. Then the player collects the even numbers and ends up with a score equal to $4$. | 1,000 | [
{
"input": "0 1 1 0 0 0 0 0 0 7 0 0 0 0",
"output": "4"
},
{
"input": "5 1 1 1 1 0 0 0 0 0 0 0 0 0",
"output": "8"
},
{
"input": "10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 1",
"output": "54294"
},
{
"input": "0 0 0 0 0 0 0 0 0 0 0 0 0 15",
... | 1,534,360,532 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | n=list(map(int,input().split()))
top=[]
for item in n:
top.append(item)
f=[]
y=0
t=y
taa=[]
for x in range(14):
if n[y]!=0:
if n[y]>13:
ol=n[y]//13
for z in range(14):
if t!=13:
t+=1
n[t]+=ol
else:
t=0
n[t]+=ol
n[y]-=13*ol
t=y
for x in range(n[y]):
if t!=13:
t+=1
n[t]+=1
else:
t=0
n[t]+=1
for item in n:
if item%2==0:
f.append(item)
pass
else:
pass
taa.append(sum(f))
f=[]
y+=1
t=y
n=[]
for item in top:
n.append(item)
else:
for l in range(n[y]):
if t!=13:
t+=1
n[t]+=1
else:
t=0
n[t]+=1
for item in n:
if item%2==0:
f.append(item)
else:
pass
taa.append(sum(f))
y+=1
f=[]
t=y
n=[]
for item in top:
n.append(item)
else:
y+=1
t=y
f=[]
n=[]
for item in top:
n.append(item)
pass
print(max(taa))
| Title: Mancala
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mancala is a game famous in the Middle East. It is played on a board that consists of 14 holes.
Initially, each hole has $a_i$ stones. When a player makes a move, he chooses a hole which contains a positive number of stones. He takes all the stones inside it and then redistributes these stones one by one in the next holes in a counter-clockwise direction.
Note that the counter-clockwise order means if the player takes the stones from hole $i$, he will put one stone in the $(i+1)$-th hole, then in the $(i+2)$-th, etc. If he puts a stone in the $14$-th hole, the next one will be put in the first hole.
After the move, the player collects all the stones from holes that contain even number of stones. The number of stones collected by player is the score, according to Resli.
Resli is a famous Mancala player. He wants to know the maximum score he can obtain after one move.
Input Specification:
The only line contains 14 integers $a_1, a_2, \ldots, a_{14}$ ($0 \leq a_i \leq 10^9$) — the number of stones in each hole.
It is guaranteed that for any $i$ ($1\leq i \leq 14$) $a_i$ is either zero or odd, and there is at least one stone in the board.
Output Specification:
Output one integer, the maximum possible score after one move.
Demo Input:
['0 1 1 0 0 0 0 0 0 7 0 0 0 0\n', '5 1 1 1 1 0 0 0 0 0 0 0 0 0\n']
Demo Output:
['4\n', '8\n']
Note:
In the first test case the board after the move from the hole with $7$ stones will look like 1 2 2 0 0 0 0 0 0 0 1 1 1 1. Then the player collects the even numbers and ends up with a score equal to $4$. | ```python
n=list(map(int,input().split()))
top=[]
for item in n:
top.append(item)
f=[]
y=0
t=y
taa=[]
for x in range(14):
if n[y]!=0:
if n[y]>13:
ol=n[y]//13
for z in range(14):
if t!=13:
t+=1
n[t]+=ol
else:
t=0
n[t]+=ol
n[y]-=13*ol
t=y
for x in range(n[y]):
if t!=13:
t+=1
n[t]+=1
else:
t=0
n[t]+=1
for item in n:
if item%2==0:
f.append(item)
pass
else:
pass
taa.append(sum(f))
f=[]
y+=1
t=y
n=[]
for item in top:
n.append(item)
else:
for l in range(n[y]):
if t!=13:
t+=1
n[t]+=1
else:
t=0
n[t]+=1
for item in n:
if item%2==0:
f.append(item)
else:
pass
taa.append(sum(f))
y+=1
f=[]
t=y
n=[]
for item in top:
n.append(item)
else:
y+=1
t=y
f=[]
n=[]
for item in top:
n.append(item)
pass
print(max(taa))
``` | 0 | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free cash, than he doesn't want to wait and leaves the cafe immediately.
Valera is very greedy, so he wants to serve all *n* customers next day (and get more profit). However, for that he needs to ensure that at each moment of time the number of working cashes is no less than the number of clients in the cafe.
Help Valera count the minimum number of cashes to work at his cafe next day, so that they can serve all visitors. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is given in the chronological order. All time is given within one 24-hour period. | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so it will be enough one cash. | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,661,421,757 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 92 | 0 | n = int(input())
k = 1
people = set()
for i in range(n):
man = tuple(map(int, input().split()))
if man in people:
k += 1
people.add(man)
print(k)
| Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free cash, than he doesn't want to wait and leaves the cafe immediately.
Valera is very greedy, so he wants to serve all *n* customers next day (and get more profit). However, for that he needs to ensure that at each moment of time the number of working cashes is no less than the number of clients in the cafe.
Help Valera count the minimum number of cashes to work at his cafe next day, so that they can serve all visitors.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is given in the chronological order. All time is given within one 24-hour period.
Output Specification:
Print a single integer — the minimum number of cashes, needed to serve all clients next day.
Demo Input:
['4\n8 0\n8 10\n8 10\n8 45\n', '3\n0 12\n10 11\n22 22\n']
Demo Output:
['2\n', '1\n']
Note:
In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so it will be enough one cash. | ```python
n = int(input())
k = 1
people = set()
for i in range(n):
man = tuple(map(int, input().split()))
if man in people:
k += 1
people.add(man)
print(k)
``` | 0 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win. | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,596,949,055 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 342 | 7,987,200 | rolls = list(map(int, input().split()))
highest = max(rolls)
fraction = [0, 6]
fraction[0] = 6 - highest + 1
from fractions import Fraction
result = str(Fraction(fraction[0], fraction[1]))
if result == '1':
print("1/1")
else:
print(result)
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | ```python
rolls = list(map(int, input().split()))
highest = max(rolls)
fraction = [0, 6]
fraction[0] = 6 - highest + 1
from fractions import Fraction
result = str(Fraction(fraction[0], fraction[1]))
if result == '1':
print("1/1")
else:
print(result)
``` | 3.769491 |
272 | C | Dima and Staircase | PROGRAMMING | 1,500 | [
"data structures",
"implementation"
] | null | null | Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The *i*-th box has width *w**i* and height *h**i*. Dima throws each box vertically down on the first *w**i* stairs of the staircase, that is, the box covers stairs with numbers 1,<=2,<=...,<=*w**i*. Each thrown box flies vertically down until at least one of the two following events happen:
- the bottom of the box touches the top of a stair; - the bottom of the box touches the top of a box, thrown earlier.
We only consider touching of the horizontal sides of stairs and boxes, at that touching with the corners isn't taken into consideration. Specifically, that implies that a box with width *w**i* cannot touch the stair number *w**i*<=+<=1.
You are given the description of the staircase and the sequence in which Dima threw the boxes at it. For each box, determine how high the bottom of the box after landing will be. Consider a box to fall after the previous one lands. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of stairs in the staircase. The second line contains a non-decreasing sequence, consisting of *n* integers, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109; *a**i*<=≤<=*a**i*<=+<=1).
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of boxes. Each of the following *m* lines contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=*n*; 1<=≤<=*h**i*<=≤<=109) — the size of the *i*-th thrown box.
The numbers in the lines are separated by spaces. | Print *m* integers — for each box the height, where the bottom of the box will be after landing. Print the answers for the boxes in the order, in which the boxes are given in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3\n",
"3\n1 2 3\n2\n1 1\n3 1\n",
"1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10\n"
] | [
"1\n3\n4\n6\n",
"1\n3\n",
"1\n3\n13\n23\n33\n"
] | The first sample are shown on the picture. | 1,500 | [
{
"input": "5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3",
"output": "1\n3\n4\n6"
},
{
"input": "3\n1 2 3\n2\n1 1\n3 1",
"output": "1\n3"
},
{
"input": "1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10",
"output": "1\n3\n13\n23\n33"
},
{
"input": "8\n6 10 18 23 30 31 31 33\n1\n5 3",
"output":... | 1,509,390,277 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 8,089,600 | cin = lambda : map(int, input().split())
n = int(input())
a = list(cin())
m = int(input())
mx = 0
for i in range(m):
w, h = cin()
mx = max(a[0], a[w - 1])
print(mx)
a[0] = mx + h | Title: Dima and Staircase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The *i*-th box has width *w**i* and height *h**i*. Dima throws each box vertically down on the first *w**i* stairs of the staircase, that is, the box covers stairs with numbers 1,<=2,<=...,<=*w**i*. Each thrown box flies vertically down until at least one of the two following events happen:
- the bottom of the box touches the top of a stair; - the bottom of the box touches the top of a box, thrown earlier.
We only consider touching of the horizontal sides of stairs and boxes, at that touching with the corners isn't taken into consideration. Specifically, that implies that a box with width *w**i* cannot touch the stair number *w**i*<=+<=1.
You are given the description of the staircase and the sequence in which Dima threw the boxes at it. For each box, determine how high the bottom of the box after landing will be. Consider a box to fall after the previous one lands.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of stairs in the staircase. The second line contains a non-decreasing sequence, consisting of *n* integers, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109; *a**i*<=≤<=*a**i*<=+<=1).
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of boxes. Each of the following *m* lines contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=*n*; 1<=≤<=*h**i*<=≤<=109) — the size of the *i*-th thrown box.
The numbers in the lines are separated by spaces.
Output Specification:
Print *m* integers — for each box the height, where the bottom of the box will be after landing. Print the answers for the boxes in the order, in which the boxes are given in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3\n', '3\n1 2 3\n2\n1 1\n3 1\n', '1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10\n']
Demo Output:
['1\n3\n4\n6\n', '1\n3\n', '1\n3\n13\n23\n33\n']
Note:
The first sample are shown on the picture. | ```python
cin = lambda : map(int, input().split())
n = int(input())
a = list(cin())
m = int(input())
mx = 0
for i in range(m):
w, h = cin()
mx = max(a[0], a[w - 1])
print(mx)
a[0] = mx + h
``` | 0 | |
288 | A | Polo the Penguin and Strings | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Little penguin Polo adores strings. But most of all he adores strings of length *n*.
One day he wanted to find a string that meets the following conditions:
1. The string consists of *n* lowercase English letters (that is, the string's length equals *n*), exactly *k* of these letters are distinct. 1. No two neighbouring letters of a string coincide; that is, if we represent a string as *s*<==<=*s*1*s*2... *s**n*, then the following inequality holds, *s**i*<=≠<=*s**i*<=+<=1(1<=≤<=*i*<=<<=*n*). 1. Among all strings that meet points 1 and 2, the required string is lexicographically smallest.
Help him find such string or state that such string doesn't exist.
String *x*<==<=*x*1*x*2... *x**p* is lexicographically less than string *y*<==<=*y*1*y*2... *y**q*, if either *p*<=<<=*q* and *x*1<==<=*y*1,<=*x*2<==<=*y*2,<=... ,<=*x**p*<==<=*y**p*, or there is such number *r* (*r*<=<<=*p*,<=*r*<=<<=*q*), that *x*1<==<=*y*1,<=*x*2<==<=*y*2,<=... ,<=*x**r*<==<=*y**r* and *x**r*<=+<=1<=<<=*y**r*<=+<=1. The characters of the strings are compared by their ASCII codes. | A single line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=106,<=1<=≤<=*k*<=≤<=26) — the string's length and the number of distinct letters. | In a single line print the required string. If there isn't such string, print "-1" (without the quotes). | [
"7 4\n",
"4 7\n"
] | [
"ababacd\n",
"-1\n"
] | none | 500 | [
{
"input": "7 4",
"output": "ababacd"
},
{
"input": "4 7",
"output": "-1"
},
{
"input": "10 5",
"output": "abababacde"
},
{
"input": "47 2",
"output": "abababababababababababababababababababababababa"
},
{
"input": "10 7",
"output": "ababacdefg"
},
{
"... | 1,645,107,285 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 1,808 | 307,200 | # Author: Riddhish V. Lichade
# username: root_rvl
from collections import Counter
from sys import stdin, stdout
from heapq import nlargest, nsmallest
def outnl(x): stdout.write(str(x) + '\n')
def outsl(x): stdout.write(str(x) + '')
def instr(): return stdin.readline().strip()
def inint(): return int(stdin.readline())
def inspsint(): return map(int, stdin.readline().strip().split())
def inlist(): return list(map(int, stdin.readline().strip().split()))
for _ in range(1):
n,x=inspsint()
if x>n or (x==1 and n>1):
outnl(-1)
continue
if(x==2):
for i in range(n):
if i%2==0:
outsl('a')
else:
outsl('b')
print()
continue
l=n-x+2
for i in range(l):
if i%2==0:
outsl('a')
else:
outsl('b')
c=99
for i in range(n-l):
outsl(chr(c))
c+=1
print()
| Title: Polo the Penguin and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo adores strings. But most of all he adores strings of length *n*.
One day he wanted to find a string that meets the following conditions:
1. The string consists of *n* lowercase English letters (that is, the string's length equals *n*), exactly *k* of these letters are distinct. 1. No two neighbouring letters of a string coincide; that is, if we represent a string as *s*<==<=*s*1*s*2... *s**n*, then the following inequality holds, *s**i*<=≠<=*s**i*<=+<=1(1<=≤<=*i*<=<<=*n*). 1. Among all strings that meet points 1 and 2, the required string is lexicographically smallest.
Help him find such string or state that such string doesn't exist.
String *x*<==<=*x*1*x*2... *x**p* is lexicographically less than string *y*<==<=*y*1*y*2... *y**q*, if either *p*<=<<=*q* and *x*1<==<=*y*1,<=*x*2<==<=*y*2,<=... ,<=*x**p*<==<=*y**p*, or there is such number *r* (*r*<=<<=*p*,<=*r*<=<<=*q*), that *x*1<==<=*y*1,<=*x*2<==<=*y*2,<=... ,<=*x**r*<==<=*y**r* and *x**r*<=+<=1<=<<=*y**r*<=+<=1. The characters of the strings are compared by their ASCII codes.
Input Specification:
A single line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=106,<=1<=≤<=*k*<=≤<=26) — the string's length and the number of distinct letters.
Output Specification:
In a single line print the required string. If there isn't such string, print "-1" (without the quotes).
Demo Input:
['7 4\n', '4 7\n']
Demo Output:
['ababacd\n', '-1\n']
Note:
none | ```python
# Author: Riddhish V. Lichade
# username: root_rvl
from collections import Counter
from sys import stdin, stdout
from heapq import nlargest, nsmallest
def outnl(x): stdout.write(str(x) + '\n')
def outsl(x): stdout.write(str(x) + '')
def instr(): return stdin.readline().strip()
def inint(): return int(stdin.readline())
def inspsint(): return map(int, stdin.readline().strip().split())
def inlist(): return list(map(int, stdin.readline().strip().split()))
for _ in range(1):
n,x=inspsint()
if x>n or (x==1 and n>1):
outnl(-1)
continue
if(x==2):
for i in range(n):
if i%2==0:
outsl('a')
else:
outsl('b')
print()
continue
l=n-x+2
for i in range(l):
if i%2==0:
outsl('a')
else:
outsl('b')
c=99
for i in range(n-l):
outsl(chr(c))
c+=1
print()
``` | 0 | |
651 | B | Beautiful Paintings | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to arranged pictures in any order. What is the maximum possible number of times the visitor may become happy while passing all pictures from first to last? In other words, we are allowed to rearrange elements of *a* in any order. What is the maximum possible number of indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1), such that *a**i*<=+<=1<=><=*a**i*. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of painting.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where *a**i* means the beauty of the *i*-th painting. | Print one integer — the maximum possible number of neighbouring pairs, such that *a**i*<=+<=1<=><=*a**i*, after the optimal rearrangement. | [
"5\n20 30 10 50 40\n",
"4\n200 100 100 200\n"
] | [
"4\n",
"2\n"
] | In the first sample, the optimal order is: 10, 20, 30, 40, 50.
In the second sample, the optimal order is: 100, 200, 100, 200. | 1,000 | [
{
"input": "5\n20 30 10 50 40",
"output": "4"
},
{
"input": "4\n200 100 100 200",
"output": "2"
},
{
"input": "10\n2 2 2 2 2 2 2 2 2 2",
"output": "0"
},
{
"input": "1\n1000",
"output": "0"
},
{
"input": "2\n444 333",
"output": "1"
},
{
"input": "100\n... | 1,589,985,700 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 124 | 307,200 | def most_frequent(List):
return max(set(List), key = List.count)
n=int(input())
l=list(map(int,input().split()))
m=set(l)
h=[0]*len(m)
print((n-1)-(l.count(most_frequent(l))-1))
| Title: Beautiful Paintings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to arranged pictures in any order. What is the maximum possible number of times the visitor may become happy while passing all pictures from first to last? In other words, we are allowed to rearrange elements of *a* in any order. What is the maximum possible number of indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1), such that *a**i*<=+<=1<=><=*a**i*.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of painting.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where *a**i* means the beauty of the *i*-th painting.
Output Specification:
Print one integer — the maximum possible number of neighbouring pairs, such that *a**i*<=+<=1<=><=*a**i*, after the optimal rearrangement.
Demo Input:
['5\n20 30 10 50 40\n', '4\n200 100 100 200\n']
Demo Output:
['4\n', '2\n']
Note:
In the first sample, the optimal order is: 10, 20, 30, 40, 50.
In the second sample, the optimal order is: 100, 200, 100, 200. | ```python
def most_frequent(List):
return max(set(List), key = List.count)
n=int(input())
l=list(map(int,input().split()))
m=set(l)
h=[0]*len(m)
print((n-1)-(l.count(most_frequent(l))-1))
``` | 3 | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.
A time is considered lucky if it contains a digit '7'. For example, 13:<=07 and 17:<=27 are lucky, while 00:<=48 and 21:<=34 are not lucky.
Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at *hh*:<=*mm*.
Formally, find the smallest possible non-negative integer *y* such that the time representation of the time *x*·*y* minutes before *hh*:<=*mm* contains the digit '7'.
Jamie uses 24-hours clock, so after 23:<=59 comes 00:<=00. | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,522,510,776 | 516 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 7,065,600 | x = int(input())
hhs, mms = input().split()
hh, mm = int(hhs), int(mms)
if '7' in hhs or '7' in mms:
print(0)
else:
if mm > 57:
if '7' in str(hh + 1):
q = 60 - mm
else:
q = 67 - mm
else:
if mm % 10 > 7:
q = 7 + (10 - (mm % 10))
else:
q = 7 - (mm % 10)
print(q // x + 1)
| Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.
A time is considered lucky if it contains a digit '7'. For example, 13:<=07 and 17:<=27 are lucky, while 00:<=48 and 21:<=34 are not lucky.
Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at *hh*:<=*mm*.
Formally, find the smallest possible non-negative integer *y* such that the time representation of the time *x*·*y* minutes before *hh*:<=*mm* contains the digit '7'.
Jamie uses 24-hours clock, so after 23:<=59 comes 00:<=00.
Input Specification:
The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59).
Output Specification:
Print the minimum number of times he needs to press the button.
Demo Input:
['3\n11 23\n', '5\n01 07\n']
Demo Output:
['2\n', '0\n']
Note:
In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | ```python
x = int(input())
hhs, mms = input().split()
hh, mm = int(hhs), int(mms)
if '7' in hhs or '7' in mms:
print(0)
else:
if mm > 57:
if '7' in str(hh + 1):
q = 60 - mm
else:
q = 67 - mm
else:
if mm % 10 > 7:
q = 7 + (10 - (mm % 10))
else:
q = 7 - (mm % 10)
print(q // x + 1)
``` | 0 | |
908 | C | New Year and Curling | PROGRAMMING | 1,500 | [
"brute force",
"geometry",
"implementation",
"math"
] | null | null | Carol is currently curling.
She has *n* disks each with radius *r* on the 2D plane.
Initially she has all these disks above the line *y*<==<=10100.
She then will slide the disks towards the line *y*<==<=0 one by one in order from 1 to *n*.
When she slides the *i*-th disk, she will place its center at the point (*x**i*,<=10100). She will then push it so the disk’s *y* coordinate continuously decreases, and *x* coordinate stays constant. The disk stops once it touches the line *y*<==<=0 or it touches any previous disk. Note that once a disk stops moving, it will not move again, even if hit by another disk.
Compute the *y*-coordinates of centers of all the disks after all disks have been pushed. | The first line will contain two integers *n* and *r* (1<=≤<=*n*,<=*r*<=≤<=1<=000), the number of disks, and the radius of the disks, respectively.
The next line will contain *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=1<=000) — the *x*-coordinates of the disks. | Print a single line with *n* numbers. The *i*-th number denotes the *y*-coordinate of the center of the *i*-th disk. The output will be accepted if it has absolute or relative error at most 10<=-<=6.
Namely, let's assume that your answer for a particular value of a coordinate is *a* and the answer of the jury is *b*. The checker program will consider your answer correct if for all coordinates. | [
"6 2\n5 5 6 8 3 12\n"
] | [
"2 6.0 9.87298334621 13.3370849613 12.5187346573 13.3370849613\n"
] | The final positions of the disks will look as follows:
In particular, note the position of the last disk. | 1,000 | [
{
"input": "6 2\n5 5 6 8 3 12",
"output": "2 6.0 9.87298334621 13.3370849613 12.5187346573 13.3370849613"
},
{
"input": "1 1\n5",
"output": "1"
},
{
"input": "5 300\n939 465 129 611 532",
"output": "300 667.864105343 1164.9596696 1522.27745533 2117.05388391"
},
{
"input": "5 ... | 1,514,574,895 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 5,529,600 | n,r=map(int,input().split())
a=list(map(int,input().split()))
b=[0 for i in range(n)]
b[0]=a[0]
for i in range(1,n+1):
w=r
for j in range(1,i):
if abs(a[j]-a[i]>2*r):continue
w=max(w,b[j]+math.sqrt(4*(r**2)-dx**2))
b[i]=w
print(*b) | Title: New Year and Curling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carol is currently curling.
She has *n* disks each with radius *r* on the 2D plane.
Initially she has all these disks above the line *y*<==<=10100.
She then will slide the disks towards the line *y*<==<=0 one by one in order from 1 to *n*.
When she slides the *i*-th disk, she will place its center at the point (*x**i*,<=10100). She will then push it so the disk’s *y* coordinate continuously decreases, and *x* coordinate stays constant. The disk stops once it touches the line *y*<==<=0 or it touches any previous disk. Note that once a disk stops moving, it will not move again, even if hit by another disk.
Compute the *y*-coordinates of centers of all the disks after all disks have been pushed.
Input Specification:
The first line will contain two integers *n* and *r* (1<=≤<=*n*,<=*r*<=≤<=1<=000), the number of disks, and the radius of the disks, respectively.
The next line will contain *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=1<=000) — the *x*-coordinates of the disks.
Output Specification:
Print a single line with *n* numbers. The *i*-th number denotes the *y*-coordinate of the center of the *i*-th disk. The output will be accepted if it has absolute or relative error at most 10<=-<=6.
Namely, let's assume that your answer for a particular value of a coordinate is *a* and the answer of the jury is *b*. The checker program will consider your answer correct if for all coordinates.
Demo Input:
['6 2\n5 5 6 8 3 12\n']
Demo Output:
['2 6.0 9.87298334621 13.3370849613 12.5187346573 13.3370849613\n']
Note:
The final positions of the disks will look as follows:
In particular, note the position of the last disk. | ```python
n,r=map(int,input().split())
a=list(map(int,input().split()))
b=[0 for i in range(n)]
b[0]=a[0]
for i in range(1,n+1):
w=r
for j in range(1,i):
if abs(a[j]-a[i]>2*r):continue
w=max(w,b[j]+math.sqrt(4*(r**2)-dx**2))
b[i]=w
print(*b)
``` | -1 | |
165 | C | Another Problem on Strings | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math",
"strings",
"two pointers"
] | null | null | A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if their positions of occurrence are different. So, if some string occurs multiple times, we should consider it the number of times it occurs.
You are given a binary string *s*. Your task is to find the number of its substrings, containing exactly *k* characters "1". | The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters. | Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"1\n1010\n",
"2\n01010\n",
"100\n01010\n"
] | [
"6\n",
"4\n",
"0\n"
] | In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | 1,500 | [
{
"input": "1\n1010",
"output": "6"
},
{
"input": "2\n01010",
"output": "4"
},
{
"input": "100\n01010",
"output": "0"
},
{
"input": "0\n01010",
"output": "3"
},
{
"input": "0\n0010100011",
"output": "10"
},
{
"input": "0\n10000",
"output": "10"
}... | 1,691,534,866 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | def count_substrings(s, k):
answer = 0
prefix_sums = [0]
for i in range(len(s)):
prefix_sums.append(prefix_sums[i] + int(s[i]))
for i in range(len(prefix_sums)):
left = lower_bound(prefix_sums, i + 1, len(prefix_sums), prefix_sums[i] + k)
right = upper_bound(prefix_sums, i + 1, len(prefix_sums), prefix_sums[i] + k)
answer += right - left
return answer
def lower_bound(array, start, end, value):
answer = -1
while start <= end:
mid = (start + end) // 2
if value == array[mid]:
answer = mid
end = mid - 1
elif value < array[mid]:
end = mid - 1
else:
start = mid + 1
return answer
def upper_bound(array, start, end, value):
answer = -1
while start <= end:
mid = (start + end) // 2
if value == array[mid]:
answer = mid + 1
start = mid + 1
elif value < array[mid]:
end = mid - 1
else:
start = mid + 1
return answer
| Title: Another Problem on Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if their positions of occurrence are different. So, if some string occurs multiple times, we should consider it the number of times it occurs.
You are given a binary string *s*. Your task is to find the number of its substrings, containing exactly *k* characters "1".
Input Specification:
The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters.
Output Specification:
Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['1\n1010\n', '2\n01010\n', '100\n01010\n']
Demo Output:
['6\n', '4\n', '0\n']
Note:
In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | ```python
def count_substrings(s, k):
answer = 0
prefix_sums = [0]
for i in range(len(s)):
prefix_sums.append(prefix_sums[i] + int(s[i]))
for i in range(len(prefix_sums)):
left = lower_bound(prefix_sums, i + 1, len(prefix_sums), prefix_sums[i] + k)
right = upper_bound(prefix_sums, i + 1, len(prefix_sums), prefix_sums[i] + k)
answer += right - left
return answer
def lower_bound(array, start, end, value):
answer = -1
while start <= end:
mid = (start + end) // 2
if value == array[mid]:
answer = mid
end = mid - 1
elif value < array[mid]:
end = mid - 1
else:
start = mid + 1
return answer
def upper_bound(array, start, end, value):
answer = -1
while start <= end:
mid = (start + end) // 2
if value == array[mid]:
answer = mid + 1
start = mid + 1
elif value < array[mid]:
end = mid - 1
else:
start = mid + 1
return answer
``` | 0 | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song. | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word. | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,693,403,666 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 71 | 124 | 0 | remix = input()
ori_song = [word for word in remix.split("WUB") if word]
ori_song_str = " ".join(ori_song)
print(ori_song_str)
| Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input Specification:
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output Specification:
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Demo Input:
['WUBWUBABCWUB\n', 'WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n']
Demo Output:
['ABC ', 'WE ARE THE CHAMPIONS MY FRIEND ']
Note:
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | ```python
remix = input()
ori_song = [word for word in remix.split("WUB") if word]
ori_song_str = " ".join(ori_song)
print(ori_song_str)
``` | 3 | |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump.
Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability.
The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'. | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,606,370,938 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | s=list(input())
n=len(s)
m=0
l=['A','E','I','O','U']
c=0
for i in range(n):
if(s[i] not in l):
c+=1
if(c>m):
m=c
else:
c=0
print(m+1)
| Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump.
Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability.
The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'.
Input Specification:
The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100.
Output Specification:
Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels.
Demo Input:
['ABABBBACFEYUKOTT\n', 'AAA\n']
Demo Output:
['4', '1']
Note:
none | ```python
s=list(input())
n=len(s)
m=0
l=['A','E','I','O','U']
c=0
for i in range(n):
if(s[i] not in l):
c+=1
if(c>m):
m=c
else:
c=0
print(m+1)
``` | 0 | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning and throws them away before going to bed as he doesn't want to wash them.
Vasya wonders, what is the maximum number of days when he can dress fashionable and wear different socks, and after that, for how many days he can then wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Can you help him? | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he's been wearing on that day. | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,693,251,876 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 62 | 0 | entrada = list(map(int, input().split()))
print(min(entrada), end=" ")
print(abs(entrada[0] - entrada[1]) // 2)
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning and throws them away before going to bed as he doesn't want to wash them.
Vasya wonders, what is the maximum number of days when he can dress fashionable and wear different socks, and after that, for how many days he can then wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Can you help him?
Input Specification:
The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got.
Output Specification:
Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he's been wearing on that day.
Demo Input:
['3 1\n', '2 3\n', '7 3\n']
Demo Output:
['1 1\n', '2 0\n', '3 2\n']
Note:
In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | ```python
entrada = list(map(int, input().split()))
print(min(entrada), end=" ")
print(abs(entrada[0] - entrada[1]) // 2)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner's score is multiplied by *k*2, and the loser's score is multiplied by *k*. In the beginning of the game, both Slastyona and Pushok have scores equal to one.
Unfortunately, Slastyona had lost her notepad where the history of all *n* games was recorded. She managed to recall the final results for each games, though, but all of her memories of them are vague. Help Slastyona verify their correctness, or, to put it another way, for each given pair of scores determine whether it was possible for a game to finish with such result or not. | In the first string, the number of games *n* (1<=≤<=*n*<=≤<=350000) is given.
Each game is represented by a pair of scores *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) – the results of Slastyona and Pushok, correspondingly. | For each pair of scores, answer "Yes" if it's possible for a game to finish with given score, and "No" otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000\n"
] | [
"Yes\nYes\nYes\nNo\nNo\nYes\n"
] | First game might have been consisted of one round, in which the number 2 would have been chosen and Pushok would have won.
The second game needs exactly two rounds to finish with such result: in the first one, Slastyona would have said the number 5, and in the second one, Pushok would have barked the number 3. | 0 | [
{
"input": "6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000",
"output": "Yes\nYes\nYes\nNo\nNo\nYes"
},
{
"input": "3\n1 1\n8 27\n1000 1331",
"output": "Yes\nNo\nNo"
},
{
"input": "1\n12004 18012002",
"output": "Yes"
},
{
"input": "1\n3331 11095561",
"output": "Yes... | 1,641,313,006 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 8,908,800 | t = int(input())
for _ in range(t):
a, b = map(int, input().split())
c = a*b
cbrt = int(c**(1/3))
if (cbrt+1)**3 == c:
cbrt += 1
if (cbrt-1)**3 == c:
cbrt -= 1
if cbrt**3 == c and a%cbrt == 0 and b%cbrt == 0:
print('YES')
else:
print('NO') | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner's score is multiplied by *k*2, and the loser's score is multiplied by *k*. In the beginning of the game, both Slastyona and Pushok have scores equal to one.
Unfortunately, Slastyona had lost her notepad where the history of all *n* games was recorded. She managed to recall the final results for each games, though, but all of her memories of them are vague. Help Slastyona verify their correctness, or, to put it another way, for each given pair of scores determine whether it was possible for a game to finish with such result or not.
Input Specification:
In the first string, the number of games *n* (1<=≤<=*n*<=≤<=350000) is given.
Each game is represented by a pair of scores *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) – the results of Slastyona and Pushok, correspondingly.
Output Specification:
For each pair of scores, answer "Yes" if it's possible for a game to finish with given score, and "No" otherwise.
You can output each letter in arbitrary case (upper or lower).
Demo Input:
['6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000\n']
Demo Output:
['Yes\nYes\nYes\nNo\nNo\nYes\n']
Note:
First game might have been consisted of one round, in which the number 2 would have been chosen and Pushok would have won.
The second game needs exactly two rounds to finish with such result: in the first one, Slastyona would have said the number 5, and in the second one, Pushok would have barked the number 3. | ```python
t = int(input())
for _ in range(t):
a, b = map(int, input().split())
c = a*b
cbrt = int(c**(1/3))
if (cbrt+1)**3 == c:
cbrt += 1
if (cbrt-1)**3 == c:
cbrt -= 1
if cbrt**3 == c and a%cbrt == 0 and b%cbrt == 0:
print('YES')
else:
print('NO')
``` | 0 |
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.