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|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to split a stick into four parts so that it's possible to form a rectangle using these parts, but is impossible to form a square.
Your task is to help Pasha and count the number of such ways. Two ways to cut the stick are considered distinct if there exists some integer *x*, such that the number of parts of length *x* in the first way differ from the number of parts of length *x* in the second way. | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,451,413,950 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 62 | 0 | x=int(input())
print((x%2==0)*((x//2-1)//2)) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to split a stick into four parts so that it's possible to form a rectangle using these parts, but is impossible to form a square.
Your task is to help Pasha and count the number of such ways. Two ways to cut the stick are considered distinct if there exists some integer *x*, such that the number of parts of length *x* in the first way differ from the number of parts of length *x* in the second way.
Input Specification:
The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick.
Output Specification:
The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square.
Demo Input:
['6\n', '20\n']
Demo Output:
['1\n', '4\n']
Note:
There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | ```python
x=int(input())
print((x%2==0)*((x//2-1)//2))
``` | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly. | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,633,785,990 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 122 | 6,963,200 | a = str(input())
b = str(input())
if a==b:
print("YES")
else:
b = b[::-1]
count =0
for i in range(0,len(a)):
for j in range(0,len(b)):
if a[i]==b[j]:
count +=1
if count==len(a):
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
Input Specification:
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output Specification:
If the word *t* is a word *s*, written reversely, print YES, otherwise print NO.
Demo Input:
['code\nedoc\n', 'abb\naba\n', 'code\ncode\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
a = str(input())
b = str(input())
if a==b:
print("YES")
else:
b = b[::-1]
count =0
for i in range(0,len(a)):
for j in range(0,len(b)):
if a[i]==b[j]:
count +=1
if count==len(a):
print("YES")
else:
print("NO")
``` | 0 |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house. | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,696,700,013 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | x= int(input())
if x < 6:
print(1)
else:
if x%5 == 0:
print((x//5))
else:
print((x//5)+1) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house.
Input Specification:
The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house.
Output Specification:
Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*.
Demo Input:
['5\n', '12\n']
Demo Output:
['1\n', '3\n']
Note:
In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | ```python
x= int(input())
if x < 6:
print(1)
else:
if x%5 == 0:
print((x//5))
else:
print((x//5)+1)
``` | 3 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix? | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,666,524,849 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 0 | n_ = input().split()
n = int(n_[0]) + 1
m = int(n_[1])
flag_1 = True
while flag_1:
flag_2 = True
for i in range(2, n):
if flag_2:
if n % i == 0:
flag_2 = False
if flag_2:
flag = False
res = n
n += 1
if m == res:
print('YES')
else:
print('NO')
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
Input Specification:
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
Output Specification:
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
Demo Input:
['3 5\n', '7 11\n', '7 9\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
none | ```python
n_ = input().split()
n = int(n_[0]) + 1
m = int(n_[1])
flag_1 = True
while flag_1:
flag_2 = True
for i in range(2, n):
if flag_2:
if n % i == 0:
flag_2 = False
if flag_2:
flag = False
res = n
n += 1
if m == res:
print('YES')
else:
print('NO')
``` | 0 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,599,765,782 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 80 | 280 | 0 | n = int(input())
if sum([sum([int(i) for i in input().split(' ')]) for j in range(n)]) == 0:
print('YES')
else:
print('NO')
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n = int(input())
if sum([sum([int(i) for i in input().split(' ')]) for j in range(n)]) == 0:
print('YES')
else:
print('NO')
``` | 0 |
667 | B | Coat of Anticubism | PROGRAMMING | 1,100 | [
"constructive algorithms",
"geometry"
] | null | null | As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, whose self-portrait you can contemplate, hates cubism. He is more impressed by the idea to transmit two-dimensional objects through three-dimensional objects by using his magnificent sculptures. And his new project is connected with this. Cicasso wants to make a coat for the haters of anticubism. To do this, he wants to create a sculpture depicting a well-known geometric primitive — convex polygon.
Cicasso prepared for this a few blanks, which are rods with integer lengths, and now he wants to bring them together. The *i*-th rod is a segment of length *l**i*.
The sculptor plans to make a convex polygon with a nonzero area, using all rods he has as its sides. Each rod should be used as a side to its full length. It is forbidden to cut, break or bend rods. However, two sides may form a straight angle .
Cicasso knows that it is impossible to make a convex polygon with a nonzero area out of the rods with the lengths which he had chosen. Cicasso does not want to leave the unused rods, so the sculptor decides to make another rod-blank with an integer length so that his problem is solvable. Of course, he wants to make it as short as possible, because the materials are expensive, and it is improper deed to spend money for nothing.
Help sculptor! | The first line contains an integer *n* (3<=≤<=*n*<=≤<=105) — a number of rod-blanks.
The second line contains *n* integers *l**i* (1<=≤<=*l**i*<=≤<=109) — lengths of rods, which Cicasso already has. It is guaranteed that it is impossible to make a polygon with *n* vertices and nonzero area using the rods Cicasso already has. | Print the only integer *z* — the minimum length of the rod, so that after adding it it can be possible to construct convex polygon with (*n*<=+<=1) vertices and nonzero area from all of the rods. | [
"3\n1 2 1\n",
"5\n20 4 3 2 1\n"
] | [
"1\n",
"11\n"
] | In the first example triangle with sides {1 + 1 = 2, 2, 1} can be formed from a set of lengths {1, 1, 1, 2}.
In the second example you can make a triangle with lengths {20, 11, 4 + 3 + 2 + 1 = 10}. | 1,000 | [
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n20 4 3 2 1",
"output": "11"
},
{
"input": "7\n77486105 317474713 89523018 332007362 7897847 949616701 54820086",
"output": "70407571"
},
{
"input": "14\n245638694 2941428 4673577 12468 991349408 44735727 14046308 60637707... | 1,559,845,235 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 140 | 3,481,600 | n = int(input())
l = list(map(int, input().split()))
s = 0
for i in range(n):
s += l[i]
m = max(l)
s1 = s - m
dlina = m+1-s1
print(dlina)
| Title: Coat of Anticubism
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, whose self-portrait you can contemplate, hates cubism. He is more impressed by the idea to transmit two-dimensional objects through three-dimensional objects by using his magnificent sculptures. And his new project is connected with this. Cicasso wants to make a coat for the haters of anticubism. To do this, he wants to create a sculpture depicting a well-known geometric primitive — convex polygon.
Cicasso prepared for this a few blanks, which are rods with integer lengths, and now he wants to bring them together. The *i*-th rod is a segment of length *l**i*.
The sculptor plans to make a convex polygon with a nonzero area, using all rods he has as its sides. Each rod should be used as a side to its full length. It is forbidden to cut, break or bend rods. However, two sides may form a straight angle .
Cicasso knows that it is impossible to make a convex polygon with a nonzero area out of the rods with the lengths which he had chosen. Cicasso does not want to leave the unused rods, so the sculptor decides to make another rod-blank with an integer length so that his problem is solvable. Of course, he wants to make it as short as possible, because the materials are expensive, and it is improper deed to spend money for nothing.
Help sculptor!
Input Specification:
The first line contains an integer *n* (3<=≤<=*n*<=≤<=105) — a number of rod-blanks.
The second line contains *n* integers *l**i* (1<=≤<=*l**i*<=≤<=109) — lengths of rods, which Cicasso already has. It is guaranteed that it is impossible to make a polygon with *n* vertices and nonzero area using the rods Cicasso already has.
Output Specification:
Print the only integer *z* — the minimum length of the rod, so that after adding it it can be possible to construct convex polygon with (*n*<=+<=1) vertices and nonzero area from all of the rods.
Demo Input:
['3\n1 2 1\n', '5\n20 4 3 2 1\n']
Demo Output:
['1\n', '11\n']
Note:
In the first example triangle with sides {1 + 1 = 2, 2, 1} can be formed from a set of lengths {1, 1, 1, 2}.
In the second example you can make a triangle with lengths {20, 11, 4 + 3 + 2 + 1 = 10}. | ```python
n = int(input())
l = list(map(int, input().split()))
s = 0
for i in range(n):
s += l[i]
m = max(l)
s1 = s - m
dlina = m+1-s1
print(dlina)
``` | 3 | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,688,300,340 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 |
n = int(input())
if n % 2 == 0:
print("Bob")
else:
print("Alice") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.
Input Specification:
The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.
Output Specification:
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.
Demo Input:
['8\n']
Demo Output:
['YES\n']
Note:
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | ```python
n = int(input())
if n % 2 == 0:
print("Bob")
else:
print("Alice")
``` | 0 |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,673,674,104 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | class solve:
def __init__(self):
s=input()
if s[0]!="1":
print("NO")
elif s.find("444"):
print("NO")
else:
flag=1
for i in s:
if i=="1" or i=="4":
continue
else:
print("NO")
flag=0
break
if flag:
print("YES")
obj=solve() | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not.
Input Specification:
The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros.
Output Specification:
Print "YES" if *n* is a magic number or print "NO" if it's not.
Demo Input:
['114114\n', '1111\n', '441231\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
none | ```python
class solve:
def __init__(self):
s=input()
if s[0]!="1":
print("NO")
elif s.find("444"):
print("NO")
else:
flag=1
for i in s:
if i=="1" or i=="4":
continue
else:
print("NO")
flag=0
break
if flag:
print("YES")
obj=solve()
``` | 0 | |
550 | A | Two Substrings | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"implementation",
"strings"
] | null | null | You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order). | The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters. | Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise. | [
"ABA\n",
"BACFAB\n",
"AXBYBXA\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | 1,000 | [
{
"input": "ABA",
"output": "NO"
},
{
"input": "BACFAB",
"output": "YES"
},
{
"input": "AXBYBXA",
"output": "NO"
},
{
"input": "ABABAB",
"output": "YES"
},
{
"input": "BBBBBBBBBB",
"output": "NO"
},
{
"input": "ABBA",
"output": "YES"
},
{
"... | 1,699,994,192 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 35 | 62 | 0 | s=input()
i1=s.count("AB")
i2=s.count("BA")
i3=s.count("ABA")
i4=s.count("BAB")
i5=s.count("BABA")
i6=s.count("ABAB")
if i5 or i6:
print("YES")
elif i1>1 and i2>1:
print("YES")
elif i1==1 and i2>1:
print("YES")
elif i1>1 and i2==1:
print("YES")
elif i1==1 and i2==1 and i3==0 and i4==0:
print("YES")
else :
print("NO")
| Title: Two Substrings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).
Input Specification:
The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters.
Output Specification:
Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise.
Demo Input:
['ABA\n', 'BACFAB\n', 'AXBYBXA\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n']
Note:
In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | ```python
s=input()
i1=s.count("AB")
i2=s.count("BA")
i3=s.count("ABA")
i4=s.count("BAB")
i5=s.count("BABA")
i6=s.count("ABAB")
if i5 or i6:
print("YES")
elif i1>1 and i2>1:
print("YES")
elif i1==1 and i2>1:
print("YES")
elif i1>1 and i2==1:
print("YES")
elif i1==1 and i2==1 and i3==0 and i4==0:
print("YES")
else :
print("NO")
``` | 0 | |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time playing, so she hid all of his cards. Vanya became sad and started looking for the cards but he only found *n* of them. Vanya loves the balance, so he wants the sum of all numbers on found cards equal to zero. On the other hand, he got very tired of looking for cards. Help the boy and say what is the minimum number of cards does he need to find to make the sum equal to zero?
You can assume that initially Vanya had infinitely many cards with each integer number from <=-<=*x* to *x*. | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their absolute value. | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,587,651,214 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 140 | 0 | from math import ceil
n, k = [int(i) for i in input().split()]
arr = [int(i) for i in input().split()]
s = abs(sum(arr))
k = abs(k)
print(ceil(s / k)) | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time playing, so she hid all of his cards. Vanya became sad and started looking for the cards but he only found *n* of them. Vanya loves the balance, so he wants the sum of all numbers on found cards equal to zero. On the other hand, he got very tired of looking for cards. Help the boy and say what is the minimum number of cards does he need to find to make the sum equal to zero?
You can assume that initially Vanya had infinitely many cards with each integer number from <=-<=*x* to *x*.
Input Specification:
The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their absolute value.
Output Specification:
Print a single number — the answer to the problem.
Demo Input:
['3 2\n-1 1 2\n', '2 3\n-2 -2\n']
Demo Output:
['1\n', '2\n']
Note:
In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | ```python
from math import ceil
n, k = [int(i) for i in input().split()]
arr = [int(i) for i in input().split()]
s = abs(sum(arr))
k = abs(k)
print(ceil(s / k))
``` | 3 | |
413 | B | Spyke Chatting | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | The R2 company has *n* employees working for it. The work involves constant exchange of ideas, sharing the stories of success and upcoming challenging. For that, R2 uses a famous instant messaging program Spyke.
R2 has *m* Spyke chats just to discuss all sorts of issues. In each chat, some group of employees exchanges messages daily. An employee can simultaneously talk in multiple chats. If some employee is in the *k*-th chat, he can write messages to this chat and receive notifications about messages from this chat. If an employee writes a message in the chat, all other participants of the chat receive a message notification.
The R2 company is conducting an audit. Now the specialists study effective communication between the employees. For this purpose, they have a chat log and the description of chat structure. You, as one of audit specialists, are commissioned to write a program that will use this data to determine the total number of message notifications received by each employee. | The first line contains three space-separated integers *n*, *m* and *k* (2<=≤<=*n*<=≤<=2·104; 1<=≤<=*m*<=≤<=10; 1<=≤<=*k*<=≤<=2·105) — the number of the employees, the number of chats and the number of events in the log, correspondingly.
Next *n* lines contain matrix *a* of size *n*<=×<=*m*, consisting of numbers zero and one. The element of this matrix, recorded in the *j*-th column of the *i*-th line, (let's denote it as *a**ij*) equals 1, if the *i*-th employee is the participant of the *j*-th chat, otherwise the element equals 0. Assume that the employees are numbered from 1 to *n* and the chats are numbered from 1 to *m*.
Next *k* lines contain the description of the log events. The *i*-th line contains two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=≤<=*n*; 1<=≤<=*y**i*<=≤<=*m*) which mean that the employee number *x**i* sent one message to chat number *y**i*. It is guaranteed that employee number *x**i* is a participant of chat *y**i*. It is guaranteed that each chat contains at least two employees. | Print in the single line *n* space-separated integers, where the *i*-th integer shows the number of message notifications the *i*-th employee receives. | [
"3 4 5\n1 1 1 1\n1 0 1 1\n1 1 0 0\n1 1\n3 1\n1 3\n2 4\n3 2\n",
"4 3 4\n0 1 1\n1 0 1\n1 1 1\n0 0 0\n1 2\n2 1\n3 1\n1 3\n"
] | [
"3 3 1 ",
"0 2 3 0 "
] | none | 1,000 | [
{
"input": "3 4 5\n1 1 1 1\n1 0 1 1\n1 1 0 0\n1 1\n3 1\n1 3\n2 4\n3 2",
"output": "3 3 1 "
},
{
"input": "4 3 4\n0 1 1\n1 0 1\n1 1 1\n0 0 0\n1 2\n2 1\n3 1\n1 3",
"output": "0 2 3 0 "
},
{
"input": "2 1 1\n1\n1\n1 1",
"output": "0 1 "
},
{
"input": "3 3 1\n1 1 1\n1 1 1\n1 1 1\... | 1,612,499,218 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 358 | 10,854,400 | from sys import stdin,stdout
n,m,k=map(int,input().split())
l=[[0]*m]*n
for i in range(n):
l[i]=list(map(int,stdin.readline().split()))
t=[[0]*2]*k
e=[0]*n
c=[0]*m
for i in range(k):
t0,t1=map(int,stdin.readline().split())
e[t0-1]-=1
c[t1-1]+=1
p=[""]*n
for i in range(n):
for j in range(m):
e[i]=e[i]+c[j]*l[i][j]
p[i]=str(e[i])
stdout.write(" ".join(p)) | Title: Spyke Chatting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R2 company has *n* employees working for it. The work involves constant exchange of ideas, sharing the stories of success and upcoming challenging. For that, R2 uses a famous instant messaging program Spyke.
R2 has *m* Spyke chats just to discuss all sorts of issues. In each chat, some group of employees exchanges messages daily. An employee can simultaneously talk in multiple chats. If some employee is in the *k*-th chat, he can write messages to this chat and receive notifications about messages from this chat. If an employee writes a message in the chat, all other participants of the chat receive a message notification.
The R2 company is conducting an audit. Now the specialists study effective communication between the employees. For this purpose, they have a chat log and the description of chat structure. You, as one of audit specialists, are commissioned to write a program that will use this data to determine the total number of message notifications received by each employee.
Input Specification:
The first line contains three space-separated integers *n*, *m* and *k* (2<=≤<=*n*<=≤<=2·104; 1<=≤<=*m*<=≤<=10; 1<=≤<=*k*<=≤<=2·105) — the number of the employees, the number of chats and the number of events in the log, correspondingly.
Next *n* lines contain matrix *a* of size *n*<=×<=*m*, consisting of numbers zero and one. The element of this matrix, recorded in the *j*-th column of the *i*-th line, (let's denote it as *a**ij*) equals 1, if the *i*-th employee is the participant of the *j*-th chat, otherwise the element equals 0. Assume that the employees are numbered from 1 to *n* and the chats are numbered from 1 to *m*.
Next *k* lines contain the description of the log events. The *i*-th line contains two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=≤<=*n*; 1<=≤<=*y**i*<=≤<=*m*) which mean that the employee number *x**i* sent one message to chat number *y**i*. It is guaranteed that employee number *x**i* is a participant of chat *y**i*. It is guaranteed that each chat contains at least two employees.
Output Specification:
Print in the single line *n* space-separated integers, where the *i*-th integer shows the number of message notifications the *i*-th employee receives.
Demo Input:
['3 4 5\n1 1 1 1\n1 0 1 1\n1 1 0 0\n1 1\n3 1\n1 3\n2 4\n3 2\n', '4 3 4\n0 1 1\n1 0 1\n1 1 1\n0 0 0\n1 2\n2 1\n3 1\n1 3\n']
Demo Output:
['3 3 1 ', '0 2 3 0 ']
Note:
none | ```python
from sys import stdin,stdout
n,m,k=map(int,input().split())
l=[[0]*m]*n
for i in range(n):
l[i]=list(map(int,stdin.readline().split()))
t=[[0]*2]*k
e=[0]*n
c=[0]*m
for i in range(k):
t0,t1=map(int,stdin.readline().split())
e[t0-1]-=1
c[t1-1]+=1
p=[""]*n
for i in range(n):
for j in range(m):
e[i]=e[i]+c[j]*l[i][j]
p[i]=str(e[i])
stdout.write(" ".join(p))
``` | 3 | |
549 | H | Degenerate Matrix | PROGRAMMING | 2,100 | [
"binary search",
"math"
] | null | null | The determinant of a matrix 2<=×<=2 is defined as follows:
A matrix is called degenerate if its determinant is equal to zero.
The norm ||*A*|| of a matrix *A* is defined as a maximum of absolute values of its elements.
You are given a matrix . Consider any degenerate matrix *B* such that norm ||*A*<=-<=*B*|| is minimum possible. Determine ||*A*<=-<=*B*||. | The first line contains two integers *a* and *b* (|*a*|,<=|*b*|<=≤<=109), the elements of the first row of matrix *A*.
The second line contains two integers *c* and *d* (|*c*|,<=|*d*|<=≤<=109) the elements of the second row of matrix *A*. | Output a single real number, the minimum possible value of ||*A*<=-<=*B*||. Your answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=9. | [
"1 2\n3 4\n",
"1 0\n0 1\n"
] | [
"0.2000000000\n",
"0.5000000000\n"
] | In the first sample matrix *B* is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ce214ad27bde5d77f87492eedd74d34c745f72a1.png" style="max-width: 100.0%;max-height: 100.0%;"/>
In the second sample matrix *B* is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a07c34fbc6e9328bcb519d3f780eea6e02e5dc87.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,500 | [
{
"input": "1 2\n3 4",
"output": "0.2000000000"
},
{
"input": "1 0\n0 1",
"output": "0.5000000000"
},
{
"input": "1000000000 0\n0 1000000000",
"output": "500000000.0000000000"
},
{
"input": "8205 9482\n11 -63",
"output": "35.0198432832"
},
{
"input": "0 0\n0 0",
... | 1,689,433,725 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689433725.0883727")# 1689433725.0883923 | Title: Degenerate Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The determinant of a matrix 2<=×<=2 is defined as follows:
A matrix is called degenerate if its determinant is equal to zero.
The norm ||*A*|| of a matrix *A* is defined as a maximum of absolute values of its elements.
You are given a matrix . Consider any degenerate matrix *B* such that norm ||*A*<=-<=*B*|| is minimum possible. Determine ||*A*<=-<=*B*||.
Input Specification:
The first line contains two integers *a* and *b* (|*a*|,<=|*b*|<=≤<=109), the elements of the first row of matrix *A*.
The second line contains two integers *c* and *d* (|*c*|,<=|*d*|<=≤<=109) the elements of the second row of matrix *A*.
Output Specification:
Output a single real number, the minimum possible value of ||*A*<=-<=*B*||. Your answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=9.
Demo Input:
['1 2\n3 4\n', '1 0\n0 1\n']
Demo Output:
['0.2000000000\n', '0.5000000000\n']
Note:
In the first sample matrix *B* is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ce214ad27bde5d77f87492eedd74d34c745f72a1.png" style="max-width: 100.0%;max-height: 100.0%;"/>
In the second sample matrix *B* is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a07c34fbc6e9328bcb519d3f780eea6e02e5dc87.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
print("_RANDOM_GUESS_1689433725.0883727")# 1689433725.0883923
``` | 0 | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a**k*) and delete it, at that all elements equal to *a**k*<=+<=1 and *a**k*<=-<=1 also must be deleted from the sequence. That step brings *a**k* points to the player.
Alex is a perfectionist, so he decided to get as many points as possible. Help him. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,695,472,023 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | points = []
tests = int(input())
nums = [int(n) for n in input().split()]
def test(num, nums = nums):
p = 0
for n in nums:
if n != num:
if n == num+1 or n == num-1:
p+=n
return p
for num in nums:
points.append(test(num))
print(max(points)) | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a**k*) and delete it, at that all elements equal to *a**k*<=+<=1 and *a**k*<=-<=1 also must be deleted from the sequence. That step brings *a**k* points to the player.
Alex is a perfectionist, so he decided to get as many points as possible. Help him.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105).
Output Specification:
Print a single integer — the maximum number of points that Alex can earn.
Demo Input:
['2\n1 2\n', '3\n1 2 3\n', '9\n1 2 1 3 2 2 2 2 3\n']
Demo Output:
['2\n', '4\n', '10\n']
Note:
Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | ```python
points = []
tests = int(input())
nums = [int(n) for n in input().split()]
def test(num, nums = nums):
p = 0
for n in nums:
if n != num:
if n == num+1 or n == num-1:
p+=n
return p
for num in nums:
points.append(test(num))
print(max(points))
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,591,977,083 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 6 | 436 | 2,252,800 |
def main():
n = int(input())
matrix = []
for _ in range(n):
x = list(map(int,input().split()))
matrix.append(x)
for i in range(n):
x = [p[i] for p in matrix]
if sum(x) != 0:
print("NO")
return
print("YES")
main() | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
def main():
n = int(input())
matrix = []
for _ in range(n):
x = list(map(int,input().split()))
matrix.append(x)
for i in range(n):
x = [p[i] for p in matrix]
if sum(x) != 0:
print("NO")
return
print("YES")
main()
``` | -1 |
203 | C | Photographer | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of people he can serve.
The camera's memory is *d* megabytes. Valera's camera can take photos of high and low quality. One low quality photo takes *a* megabytes of memory, one high quality photo take *b* megabytes of memory. For unknown reasons, each client asks him to make several low quality photos and several high quality photos. More formally, the *i*-th client asks to make *x**i* low quality photos and *y**i* high quality photos.
Valera wants to serve as many clients per day as possible, provided that they will be pleased with his work. To please the *i*-th client, Valera needs to give him everything he wants, that is, to make *x**i* low quality photos and *y**i* high quality photos. To make one low quality photo, the camera must have at least *a* megabytes of free memory space. Similarly, to make one high quality photo, the camera must have at least *b* megabytes of free memory space. Initially the camera's memory is empty. Valera also does not delete photos from the camera so that the camera's memory gradually fills up.
Calculate the maximum number of clients Valera can successfully serve and print the numbers of these clients. | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*d*<=≤<=109) — the number of clients and the camera memory size, correspondingly. The second line contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=104) — the size of one low quality photo and of one high quality photo, correspondingly.
Next *n* lines describe the clients. The *i*-th line contains two integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=105) — the number of low quality photos and high quality photos the *i*-th client wants, correspondingly.
All numbers on all lines are separated by single spaces. | On the first line print the answer to the problem — the maximum number of clients that Valera can successfully serve. Print on the second line the numbers of the client in any order. All numbers must be distinct. If there are multiple answers, print any of them. The clients are numbered starting with 1 in the order in which they are defined in the input data. | [
"3 10\n2 3\n1 4\n2 1\n1 0\n",
"3 6\n6 6\n1 1\n1 0\n1 0\n"
] | [
"2\n3 2 ",
"1\n2 "
] | none | 1,500 | [
{
"input": "3 10\n2 3\n1 4\n2 1\n1 0",
"output": "2\n3 2 "
},
{
"input": "3 6\n6 6\n1 1\n1 0\n1 0",
"output": "1\n2 "
},
{
"input": "4 5\n6 8\n1 2\n3 0\n10 2\n0 4",
"output": "0"
},
{
"input": "4 10\n6 6\n1 2\n2 2\n0 0\n0 0",
"output": "2\n3 4 "
},
{
"input": "10 ... | 1,512,703,035 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 5,529,600 | def manager(A,maxmem, lmem, hmem):
print(maxmem)
memory = [0 for x in range(len(A))]
for i in range(len(A)):
memory[i] = A[i][0]*lmem + A[i][1]*hmem
L = [int(x) for x in range(len(memory))]
k = bubbleSort(memory, L)
total = 0
ind = 0
for i in range(len(k[0])):
if(total+k[0][i]<=maxmem):
total = total+k[0][i]
else:
ind = i
break
print(ind)
for i in range(ind):
print(L[i]+1, end = ' ')
def bubbleSort(alist, L):
for passnum in range(len(alist)-1,0,-1):
for i in range(passnum):
if alist[i]>alist[i+1]:
temp = alist[i]
temp1 = L[i]
alist[i] = alist[i+1]
L[i] = L[i+1]
alist[i+1] = temp
L[i+1] = temp1
return alist,L
mem = [int(x) for x in input().split()]
indmem = [int(x) for x in input().split()]
A = []
for i in range(mem[0]):
a = [int(x) for x in input().split()]
A.append(a)
manager(A,mem[1],indmem[0],indmem[1])
| Title: Photographer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of people he can serve.
The camera's memory is *d* megabytes. Valera's camera can take photos of high and low quality. One low quality photo takes *a* megabytes of memory, one high quality photo take *b* megabytes of memory. For unknown reasons, each client asks him to make several low quality photos and several high quality photos. More formally, the *i*-th client asks to make *x**i* low quality photos and *y**i* high quality photos.
Valera wants to serve as many clients per day as possible, provided that they will be pleased with his work. To please the *i*-th client, Valera needs to give him everything he wants, that is, to make *x**i* low quality photos and *y**i* high quality photos. To make one low quality photo, the camera must have at least *a* megabytes of free memory space. Similarly, to make one high quality photo, the camera must have at least *b* megabytes of free memory space. Initially the camera's memory is empty. Valera also does not delete photos from the camera so that the camera's memory gradually fills up.
Calculate the maximum number of clients Valera can successfully serve and print the numbers of these clients.
Input Specification:
The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*d*<=≤<=109) — the number of clients and the camera memory size, correspondingly. The second line contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=104) — the size of one low quality photo and of one high quality photo, correspondingly.
Next *n* lines describe the clients. The *i*-th line contains two integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=105) — the number of low quality photos and high quality photos the *i*-th client wants, correspondingly.
All numbers on all lines are separated by single spaces.
Output Specification:
On the first line print the answer to the problem — the maximum number of clients that Valera can successfully serve. Print on the second line the numbers of the client in any order. All numbers must be distinct. If there are multiple answers, print any of them. The clients are numbered starting with 1 in the order in which they are defined in the input data.
Demo Input:
['3 10\n2 3\n1 4\n2 1\n1 0\n', '3 6\n6 6\n1 1\n1 0\n1 0\n']
Demo Output:
['2\n3 2 ', '1\n2 ']
Note:
none | ```python
def manager(A,maxmem, lmem, hmem):
print(maxmem)
memory = [0 for x in range(len(A))]
for i in range(len(A)):
memory[i] = A[i][0]*lmem + A[i][1]*hmem
L = [int(x) for x in range(len(memory))]
k = bubbleSort(memory, L)
total = 0
ind = 0
for i in range(len(k[0])):
if(total+k[0][i]<=maxmem):
total = total+k[0][i]
else:
ind = i
break
print(ind)
for i in range(ind):
print(L[i]+1, end = ' ')
def bubbleSort(alist, L):
for passnum in range(len(alist)-1,0,-1):
for i in range(passnum):
if alist[i]>alist[i+1]:
temp = alist[i]
temp1 = L[i]
alist[i] = alist[i+1]
L[i] = L[i+1]
alist[i+1] = temp
L[i+1] = temp1
return alist,L
mem = [int(x) for x in input().split()]
indmem = [int(x) for x in input().split()]
A = []
for i in range(mem[0]):
a = [int(x) for x in input().split()]
A.append(a)
manager(A,mem[1],indmem[0],indmem[1])
``` | 0 | |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for this was very simple: Hexadecimal didn't perceive any information, apart from numbers written in binary format. This means that if a number in a decimal representation contained characters apart from 0 and 1, it was not stored in the memory. Now Megabyte wants to know, how many numbers were loaded successfully. | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,595,416,568 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 218 | 6,963,200 | n = int(input())
temp = n
dp = []
digitCount = 0
while (temp != 0):
dp.append(temp % 10)
temp = int(temp/10)
digitCount += 1
dp.reverse()
sum = 0
for i in range(digitCount - 1):
sum += 2**i
two = 2**(digitCount-1)
if(dp[0]==1):
for i in range(1,len(dp)):
if(dp[i]>1):
break
elif(dp[i]==1):
continue
else:
two-=2**(digitCount-i-1)
sum+=two
print(sum) | Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for this was very simple: Hexadecimal didn't perceive any information, apart from numbers written in binary format. This means that if a number in a decimal representation contained characters apart from 0 and 1, it was not stored in the memory. Now Megabyte wants to know, how many numbers were loaded successfully.
Input Specification:
Input data contains the only number *n* (1<=≤<=*n*<=≤<=109).
Output Specification:
Output the only number — answer to the problem.
Demo Input:
['10\n']
Demo Output:
['2']
Note:
For *n* = 10 the answer includes numbers 1 and 10. | ```python
n = int(input())
temp = n
dp = []
digitCount = 0
while (temp != 0):
dp.append(temp % 10)
temp = int(temp/10)
digitCount += 1
dp.reverse()
sum = 0
for i in range(digitCount - 1):
sum += 2**i
two = 2**(digitCount-1)
if(dp[0]==1):
for i in range(1,len(dp)):
if(dp[i]>1):
break
elif(dp[i]==1):
continue
else:
two-=2**(digitCount-i-1)
sum+=two
print(sum)
``` | 3.83912 |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing? | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,697,137,958 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 16 | 1,000 | 1,740,800 | n, d = tuple(map(int, input().strip().split()))
c = 0
a = list(map(int, input().strip().split()))
for i in range(1, n):
while a[i] <= a[i-1]:
a[i] += d
c += 1
print(c)
| Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing?
Input Specification:
The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106).
Output Specification:
Output the minimal number of moves needed to make the sequence increasing.
Demo Input:
['4 2\n1 3 3 2\n']
Demo Output:
['3\n']
Note:
none | ```python
n, d = tuple(map(int, input().strip().split()))
c = 0
a = list(map(int, input().strip().split()))
for i in range(1, n):
while a[i] <= a[i-1]:
a[i] += d
c += 1
print(c)
``` | 0 |
129 | A | Cookies | PROGRAMMING | 900 | [
"implementation"
] | null | null | Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even? | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag. | Print in the only line the only number — the sought number of ways. If there are no such ways print 0. | [
"1\n1\n",
"10\n1 2 2 3 4 4 4 2 2 2\n",
"11\n2 2 2 2 2 2 2 2 2 2 99\n"
] | [
"1\n",
"8\n",
"1\n"
] | In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | 500 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 2 2 3 4 4 4 2 2 2",
"output": "8"
},
{
"input": "11\n2 2 2 2 2 2 2 2 2 2 99",
"output": "1"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n2 2",
"output": "2"
},
{
"input": "2\n1 2",
"o... | 1,635,262,944 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 92 | 4,505,600 | bags = int(input())
cookies = input().split()
summa = 0
odd = 0
even = 0
for i in range(bags):
summa += int(cookies[i])
if int(cookies[i]) % 2 == 0:
even += 1
else:
odd += 1
if summa % 2 == 0:
print(even)
else:
print(odd) | Title: Cookies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input Specification:
The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag.
Output Specification:
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Demo Input:
['1\n1\n', '10\n1 2 2 3 4 4 4 2 2 2\n', '11\n2 2 2 2 2 2 2 2 2 2 99\n']
Demo Output:
['1\n', '8\n', '1\n']
Note:
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | ```python
bags = int(input())
cookies = input().split()
summa = 0
odd = 0
even = 0
for i in range(bags):
summa += int(cookies[i])
if int(cookies[i]) % 2 == 0:
even += 1
else:
odd += 1
if summa % 2 == 0:
print(even)
else:
print(odd)
``` | 3 | |
817 | A | Treasure Hunt | PROGRAMMING | 1,200 | [
"implementation",
"math",
"number theory"
] | null | null | Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with potion has two values *x* and *y* written on it. These values define four moves which can be performed using the potion:
- - - -
Map shows that the position of Captain Bill the Hummingbird is (*x*1,<=*y*1) and the position of the treasure is (*x*2,<=*y*2).
You task is to tell Captain Bill the Hummingbird whether he should accept this challenge or decline. If it is possible for Captain to reach the treasure using the potion then output "YES", otherwise "NO" (without quotes).
The potion can be used infinite amount of times. | The first line contains four integer numbers *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=105<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=105) — positions of Captain Bill the Hummingbird and treasure respectively.
The second line contains two integer numbers *x*,<=*y* (1<=≤<=*x*,<=*y*<=≤<=105) — values on the potion bottle. | Print "YES" if it is possible for Captain to reach the treasure using the potion, otherwise print "NO" (without quotes). | [
"0 0 0 6\n2 3\n",
"1 1 3 6\n1 5\n"
] | [
"YES\n",
"NO\n"
] | In the first example there exists such sequence of moves:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c939890fb4ed35688177327dac981bfa9216c00.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the first type of move 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/afbfa42fbac4e0641e7466e3aac74cbbb08ed597.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the third type of move | 0 | [
{
"input": "0 0 0 6\n2 3",
"output": "YES"
},
{
"input": "1 1 3 6\n1 5",
"output": "NO"
},
{
"input": "5 4 6 -10\n1 1",
"output": "NO"
},
{
"input": "6 -3 -7 -7\n1 2",
"output": "NO"
},
{
"input": "2 -5 -8 8\n2 1",
"output": "YES"
},
{
"input": "70 -81... | 1,663,989,351 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 46 | 0 | def main():
positions = list(input().split())
x1 = int(positions[0])
y1 = int(positions[1])
x2 = int(positions[2])
y2 = int(positions[3])
potion_pos = list(input().split())
x = int(potion_pos[0])
y = int(potion_pos[1])
left = x1 - x2
right = y1 - y2
if left % x == 0 and right % y == 0 and (left / x) % 2 == (right / y) % 2:
print("YES")
else:
print("NO")
if __name__ == '__main__':
main()
| Title: Treasure Hunt
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with potion has two values *x* and *y* written on it. These values define four moves which can be performed using the potion:
- - - -
Map shows that the position of Captain Bill the Hummingbird is (*x*1,<=*y*1) and the position of the treasure is (*x*2,<=*y*2).
You task is to tell Captain Bill the Hummingbird whether he should accept this challenge or decline. If it is possible for Captain to reach the treasure using the potion then output "YES", otherwise "NO" (without quotes).
The potion can be used infinite amount of times.
Input Specification:
The first line contains four integer numbers *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=105<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=105) — positions of Captain Bill the Hummingbird and treasure respectively.
The second line contains two integer numbers *x*,<=*y* (1<=≤<=*x*,<=*y*<=≤<=105) — values on the potion bottle.
Output Specification:
Print "YES" if it is possible for Captain to reach the treasure using the potion, otherwise print "NO" (without quotes).
Demo Input:
['0 0 0 6\n2 3\n', '1 1 3 6\n1 5\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first example there exists such sequence of moves:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c939890fb4ed35688177327dac981bfa9216c00.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the first type of move 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/afbfa42fbac4e0641e7466e3aac74cbbb08ed597.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the third type of move | ```python
def main():
positions = list(input().split())
x1 = int(positions[0])
y1 = int(positions[1])
x2 = int(positions[2])
y2 = int(positions[3])
potion_pos = list(input().split())
x = int(potion_pos[0])
y = int(potion_pos[1])
left = x1 - x2
right = y1 - y2
if left % x == 0 and right % y == 0 and (left / x) % 2 == (right / y) % 2:
print("YES")
else:
print("NO")
if __name__ == '__main__':
main()
``` | 3 | |
985 | D | Sand Fortress | PROGRAMMING | 2,100 | [
"binary search",
"constructive algorithms",
"math"
] | null | null | You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars. Spots are numbered 1 through infinity from left to right.
Obviously, there is not enough sand on the beach, so you brought *n* packs of sand with you. Let height *h**i* of the sand pillar on some spot *i* be the number of sand packs you spent on it. You can't split a sand pack to multiple pillars, all the sand from it should go to a single one. There is a fence of height equal to the height of pillar with *H* sand packs to the left of the first spot and you should prevent sand from going over it.
Finally you ended up with the following conditions to building the castle:
- *h*1<=≤<=*H*: no sand from the leftmost spot should go over the fence; - For any |*h**i*<=-<=*h**i*<=+<=1|<=≤<=1: large difference in heights of two neighboring pillars can lead sand to fall down from the higher one to the lower, you really don't want this to happen; - : you want to spend all the sand you brought with you.
As you have infinite spots to build, it is always possible to come up with some valid castle structure. Though you want the castle to be as compact as possible.
Your task is to calculate the minimum number of spots you can occupy so that all the aforementioned conditions hold. | The only line contains two integer numbers *n* and *H* (1<=≤<=*n*,<=*H*<=≤<=1018) — the number of sand packs you have and the height of the fence, respectively. | Print the minimum number of spots you can occupy so the all the castle building conditions hold. | [
"5 2\n",
"6 8\n"
] | [
"3\n",
"3\n"
] | Here are the heights of some valid castles:
- *n* = 5, *H* = 2, [2, 2, 1, 0, ...], [2, 1, 1, 1, 0, ...], [1, 0, 1, 2, 1, 0, ...] - *n* = 6, *H* = 8, [3, 2, 1, 0, ...], [2, 2, 1, 1, 0, ...], [0, 1, 0, 1, 2, 1, 1, 0...] (this one has 5 spots occupied)
The first list for both cases is the optimal answer, 3 spots are occupied in them.
And here are some invalid ones:
- *n* = 5, *H* = 2, [3, 2, 0, ...], [2, 3, 0, ...], [1, 0, 2, 2, ...] - *n* = 6, *H* = 8, [2, 2, 2, 0, ...], [6, 0, ...], [1, 4, 1, 0...], [2, 2, 1, 0, ...] | 0 | [
{
"input": "5 2",
"output": "3"
},
{
"input": "6 8",
"output": "3"
},
{
"input": "20 4",
"output": "7"
},
{
"input": "1000000000000000000 1000000000000000000",
"output": "1414213562"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 10000000000000000... | 1,528,472,234 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 92 | 0 | from math import *
def gs(x):
return x * (x + 1) // 2
r = 10**30 + 7
n, h = [int(i) for i in input().strip().split()]
l = 0
r = min(h + 1, r)
while (r - l > 1):
m = (l + r) // 2
if (gs(m) <= n):
l = m
else:
r = m
print(l + (n - gs(l) + h - 1) // h) | Title: Sand Fortress
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars. Spots are numbered 1 through infinity from left to right.
Obviously, there is not enough sand on the beach, so you brought *n* packs of sand with you. Let height *h**i* of the sand pillar on some spot *i* be the number of sand packs you spent on it. You can't split a sand pack to multiple pillars, all the sand from it should go to a single one. There is a fence of height equal to the height of pillar with *H* sand packs to the left of the first spot and you should prevent sand from going over it.
Finally you ended up with the following conditions to building the castle:
- *h*1<=≤<=*H*: no sand from the leftmost spot should go over the fence; - For any |*h**i*<=-<=*h**i*<=+<=1|<=≤<=1: large difference in heights of two neighboring pillars can lead sand to fall down from the higher one to the lower, you really don't want this to happen; - : you want to spend all the sand you brought with you.
As you have infinite spots to build, it is always possible to come up with some valid castle structure. Though you want the castle to be as compact as possible.
Your task is to calculate the minimum number of spots you can occupy so that all the aforementioned conditions hold.
Input Specification:
The only line contains two integer numbers *n* and *H* (1<=≤<=*n*,<=*H*<=≤<=1018) — the number of sand packs you have and the height of the fence, respectively.
Output Specification:
Print the minimum number of spots you can occupy so the all the castle building conditions hold.
Demo Input:
['5 2\n', '6 8\n']
Demo Output:
['3\n', '3\n']
Note:
Here are the heights of some valid castles:
- *n* = 5, *H* = 2, [2, 2, 1, 0, ...], [2, 1, 1, 1, 0, ...], [1, 0, 1, 2, 1, 0, ...] - *n* = 6, *H* = 8, [3, 2, 1, 0, ...], [2, 2, 1, 1, 0, ...], [0, 1, 0, 1, 2, 1, 1, 0...] (this one has 5 spots occupied)
The first list for both cases is the optimal answer, 3 spots are occupied in them.
And here are some invalid ones:
- *n* = 5, *H* = 2, [3, 2, 0, ...], [2, 3, 0, ...], [1, 0, 2, 2, ...] - *n* = 6, *H* = 8, [2, 2, 2, 0, ...], [6, 0, ...], [1, 4, 1, 0...], [2, 2, 1, 0, ...] | ```python
from math import *
def gs(x):
return x * (x + 1) // 2
r = 10**30 + 7
n, h = [int(i) for i in input().strip().split()]
l = 0
r = min(h + 1, r)
while (r - l > 1):
m = (l + r) // 2
if (gs(m) <= n):
l = m
else:
r = m
print(l + (n - gs(l) + h - 1) // h)
``` | 0 | |
601 | A | The Two Routes | PROGRAMMING | 1,600 | [
"graphs",
"shortest paths"
] | null | null | In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road between towns *x* and *y* if and only if there is no railway between them. Travelling to a different town using one railway or one road always takes exactly one hour.
A train and a bus leave town 1 at the same time. They both have the same destination, town *n*, and don't make any stops on the way (but they can wait in town *n*). The train can move only along railways and the bus can move only along roads.
You've been asked to plan out routes for the vehicles; each route can use any road/railway multiple times. One of the most important aspects to consider is safety — in order to avoid accidents at railway crossings, the train and the bus must not arrive at the same town (except town *n*) simultaneously.
Under these constraints, what is the minimum number of hours needed for both vehicles to reach town *n* (the maximum of arrival times of the bus and the train)? Note, that bus and train are not required to arrive to the town *n* at the same moment of time, but are allowed to do so. | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=400, 0<=≤<=*m*<=≤<=*n*(*n*<=-<=1)<=/<=2) — the number of towns and the number of railways respectively.
Each of the next *m* lines contains two integers *u* and *v*, denoting a railway between towns *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*).
You may assume that there is at most one railway connecting any two towns. | Output one integer — the smallest possible time of the later vehicle's arrival in town *n*. If it's impossible for at least one of the vehicles to reach town *n*, output <=-<=1. | [
"4 2\n1 3\n3 4\n",
"4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n",
"5 5\n4 2\n3 5\n4 5\n5 1\n1 2\n"
] | [
"2\n",
"-1\n",
"3\n"
] | In the first sample, the train can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c0aa60a06309ef607b7159fd7f3687ea0d943ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> and the bus can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a26c2f3e93c9d9be6c21cb5d2bd6ac1f99f4ff55.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Note that they can arrive at town 4 at the same time.
In the second sample, Absurdistan is ruled by railwaymen. There are no roads, so there's no way for the bus to reach town 4. | 500 | [
{
"input": "4 2\n1 3\n3 4",
"output": "2"
},
{
"input": "4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4",
"output": "-1"
},
{
"input": "5 5\n4 2\n3 5\n4 5\n5 1\n1 2",
"output": "3"
},
{
"input": "5 4\n1 2\n3 2\n3 4\n5 4",
"output": "4"
},
{
"input": "3 1\n1 2",
"output": "... | 1,695,636,976 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 3,379,200 | from queue import Queue
def solve():
n,m = map(int,input().split())
rail = [[]for i in range(n+1)]
road = [[]for i in range(n+1)]
v1 = [False]*(n+1)
v2 = [False]*(n+2)
for i in range(m):
a,b = map(int,input().split())
print(a,b)
rail[a].append(b)
rail[b].append(a)
for i in range(1,n+1):
for j in range(i+1,n+1):
if j not in rail[i]:
road[i].append(j)
road[j].append(i)
q = Queue()
q.put((1,0))
ans = 1
a1 = False
a2 = False
v1[1] = True
v2[1] = True
while q:
s = q.get()
if s[0] == n:
ans = max(ans,s[1])
a1 = True
break
for i in rail[s[0]]:
if not v1[i]:
q.put((i,s[1]+1))
v1[i] = True
q = Queue()
q.put((1,0))
while q:
s = q.get()
if s[0] == n:
ans = max(ans,s[1])
a2 = True
break
for i in road[s[0]]:
if not v2[i]:
q.put((i,s[1]+1))
v2[i] = True
if not a1 or not a2:
print(-1)
return
print(ans)
# number of test cases
t = 1
#t = int(input())
for i in range(t):
solve()
| Title: The Two Routes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road between towns *x* and *y* if and only if there is no railway between them. Travelling to a different town using one railway or one road always takes exactly one hour.
A train and a bus leave town 1 at the same time. They both have the same destination, town *n*, and don't make any stops on the way (but they can wait in town *n*). The train can move only along railways and the bus can move only along roads.
You've been asked to plan out routes for the vehicles; each route can use any road/railway multiple times. One of the most important aspects to consider is safety — in order to avoid accidents at railway crossings, the train and the bus must not arrive at the same town (except town *n*) simultaneously.
Under these constraints, what is the minimum number of hours needed for both vehicles to reach town *n* (the maximum of arrival times of the bus and the train)? Note, that bus and train are not required to arrive to the town *n* at the same moment of time, but are allowed to do so.
Input Specification:
The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=400, 0<=≤<=*m*<=≤<=*n*(*n*<=-<=1)<=/<=2) — the number of towns and the number of railways respectively.
Each of the next *m* lines contains two integers *u* and *v*, denoting a railway between towns *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*).
You may assume that there is at most one railway connecting any two towns.
Output Specification:
Output one integer — the smallest possible time of the later vehicle's arrival in town *n*. If it's impossible for at least one of the vehicles to reach town *n*, output <=-<=1.
Demo Input:
['4 2\n1 3\n3 4\n', '4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n', '5 5\n4 2\n3 5\n4 5\n5 1\n1 2\n']
Demo Output:
['2\n', '-1\n', '3\n']
Note:
In the first sample, the train can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c0aa60a06309ef607b7159fd7f3687ea0d943ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> and the bus can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a26c2f3e93c9d9be6c21cb5d2bd6ac1f99f4ff55.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Note that they can arrive at town 4 at the same time.
In the second sample, Absurdistan is ruled by railwaymen. There are no roads, so there's no way for the bus to reach town 4. | ```python
from queue import Queue
def solve():
n,m = map(int,input().split())
rail = [[]for i in range(n+1)]
road = [[]for i in range(n+1)]
v1 = [False]*(n+1)
v2 = [False]*(n+2)
for i in range(m):
a,b = map(int,input().split())
print(a,b)
rail[a].append(b)
rail[b].append(a)
for i in range(1,n+1):
for j in range(i+1,n+1):
if j not in rail[i]:
road[i].append(j)
road[j].append(i)
q = Queue()
q.put((1,0))
ans = 1
a1 = False
a2 = False
v1[1] = True
v2[1] = True
while q:
s = q.get()
if s[0] == n:
ans = max(ans,s[1])
a1 = True
break
for i in rail[s[0]]:
if not v1[i]:
q.put((i,s[1]+1))
v1[i] = True
q = Queue()
q.put((1,0))
while q:
s = q.get()
if s[0] == n:
ans = max(ans,s[1])
a2 = True
break
for i in road[s[0]]:
if not v2[i]:
q.put((i,s[1]+1))
v2[i] = True
if not a1 or not a2:
print(-1)
return
print(ans)
# number of test cases
t = 1
#t = int(input())
for i in range(t):
solve()
``` | 0 | |
983 | A | Finite or not? | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | You are given several queries. Each query consists of three integers $p$, $q$ and $b$. You need to answer whether the result of $p/q$ in notation with base $b$ is a finite fraction.
A fraction in notation with base $b$ is finite if it contains finite number of numerals after the decimal point. It is also possible that a fraction has zero numerals after the decimal point. | The first line contains a single integer $n$ ($1 \le n \le 10^5$) — the number of queries.
Next $n$ lines contain queries, one per line. Each line contains three integers $p$, $q$, and $b$ ($0 \le p \le 10^{18}$, $1 \le q \le 10^{18}$, $2 \le b \le 10^{18}$). All numbers are given in notation with base $10$. | For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise. | [
"2\n6 12 10\n4 3 10\n",
"4\n1 1 2\n9 36 2\n4 12 3\n3 5 4\n"
] | [
"Finite\nInfinite\n",
"Finite\nFinite\nFinite\nInfinite\n"
] | $\frac{6}{12} = \frac{1}{2} = 0,5_{10}$
$\frac{4}{3} = 1,(3)_{10}$
$\frac{9}{36} = \frac{1}{4} = 0,01_2$
$\frac{4}{12} = \frac{1}{3} = 0,1_3$ | 500 | [
{
"input": "2\n6 12 10\n4 3 10",
"output": "Finite\nInfinite"
},
{
"input": "4\n1 1 2\n9 36 2\n4 12 3\n3 5 4",
"output": "Finite\nFinite\nFinite\nInfinite"
},
{
"input": "10\n10 5 3\n1 7 10\n7 5 7\n4 4 9\n6 5 2\n6 7 5\n9 9 7\n7 5 5\n6 6 4\n10 8 2",
"output": "Finite\nInfinite\nInfini... | 1,600,860,071 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 0 | for _ in range(int(input())):
p,q,b=map(int,input().split())
if(p==0):
print('Finite')
else:
xx=b
for i in range(6):
xx*=(xx*b)%q
if((p*xx)%q==0):
print('Finite')
else:
print('Infinite') | Title: Finite or not?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. Each query consists of three integers $p$, $q$ and $b$. You need to answer whether the result of $p/q$ in notation with base $b$ is a finite fraction.
A fraction in notation with base $b$ is finite if it contains finite number of numerals after the decimal point. It is also possible that a fraction has zero numerals after the decimal point.
Input Specification:
The first line contains a single integer $n$ ($1 \le n \le 10^5$) — the number of queries.
Next $n$ lines contain queries, one per line. Each line contains three integers $p$, $q$, and $b$ ($0 \le p \le 10^{18}$, $1 \le q \le 10^{18}$, $2 \le b \le 10^{18}$). All numbers are given in notation with base $10$.
Output Specification:
For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise.
Demo Input:
['2\n6 12 10\n4 3 10\n', '4\n1 1 2\n9 36 2\n4 12 3\n3 5 4\n']
Demo Output:
['Finite\nInfinite\n', 'Finite\nFinite\nFinite\nInfinite\n']
Note:
$\frac{6}{12} = \frac{1}{2} = 0,5_{10}$
$\frac{4}{3} = 1,(3)_{10}$
$\frac{9}{36} = \frac{1}{4} = 0,01_2$
$\frac{4}{12} = \frac{1}{3} = 0,1_3$ | ```python
for _ in range(int(input())):
p,q,b=map(int,input().split())
if(p==0):
print('Finite')
else:
xx=b
for i in range(6):
xx*=(xx*b)%q
if((p*xx)%q==0):
print('Finite')
else:
print('Infinite')
``` | 0 | |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maximum number of times "VK" can appear as a substring (i. e. a letter "K" right after a letter "V") in the resulting string. | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we can change the fourth character from a "K" to a "V". This will give us the string "VKKVKKKKKKVVVVVVVVVK". This has three occurrences of the string "VK" as a substring. We can check no other moves can give us strictly more occurrences. | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,495,087,866 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 46 | 0 | a = input()
counter = 0
flag =False
for i in range(1,len(a)):
if a[i-1] == "V" and a[i] == "K":
counter += 1
if not flag:
if a[i-1] == "V" and a[i] != "K":
counter += 1
flag = True
print(counter)
| Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maximum number of times "VK" can appear as a substring (i. e. a letter "K" right after a letter "V") in the resulting string.
Input Specification:
The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100.
Output Specification:
Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character.
Demo Input:
['VK\n', 'VV\n', 'V\n', 'VKKKKKKKKKVVVVVVVVVK\n', 'KVKV\n']
Demo Output:
['1\n', '1\n', '0\n', '3\n', '1\n']
Note:
For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we can change the fourth character from a "K" to a "V". This will give us the string "VKKVKKKKKKVVVVVVVVVK". This has three occurrences of the string "VK" as a substring. We can check no other moves can give us strictly more occurrences. | ```python
a = input()
counter = 0
flag =False
for i in range(1,len(a)):
if a[i-1] == "V" and a[i] == "K":
counter += 1
if not flag:
if a[i-1] == "V" and a[i] != "K":
counter += 1
flag = True
print(counter)
``` | 0 | |
442 | B | Andrey and Problem | PROGRAMMING | 1,800 | [
"greedy",
"math",
"probabilities"
] | null | null | Andrey needs one more problem to conduct a programming contest. He has *n* friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of Andrey's friends. The second line contains *n* real numbers *p**i* (0.0<=≤<=*p**i*<=≤<=1.0) — the probability that the *i*-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point. | Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10<=-<=9. | [
"4\n0.1 0.2 0.3 0.8\n",
"2\n0.1 0.2\n"
] | [
"0.800000000000\n",
"0.260000000000\n"
] | In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | 1,500 | [
{
"input": "4\n0.1 0.2 0.3 0.8",
"output": "0.800000000000"
},
{
"input": "2\n0.1 0.2",
"output": "0.260000000000"
},
{
"input": "1\n0.217266",
"output": "0.217266000000"
},
{
"input": "2\n0.608183 0.375030",
"output": "0.608183000000"
},
{
"input": "3\n0.388818 0... | 1,601,985,059 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 109 | 307,200 | def cali(subset):
z = [1-i for i in subset]
ans = 0
for i in range(len(subset)):
ha = subset[i]
for j in range(len(subset)):
if i!=j:
ha*=z[j]
ans+=ha
return ans
def solve():
n = int(input())
l = list(map(float,input().split()))
l.sort()
if l[-1]>=0.5:
print(l[-1])
else:
ans = 0
yo = -1
ha = []
for i in range(4):
ha.append(l[yo])
z = cali(ha)
ans = max(ans,z)
yo-=1
if yo == -(n+1):
break
print(ans)
# t = int(input())
# for _ in range(t):
solve()
| Title: Andrey and Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrey needs one more problem to conduct a programming contest. He has *n* friends who are always willing to help. He can ask some of them to come up with a contest problem. Andrey knows one value for each of his fiends — the probability that this friend will come up with a problem if Andrey asks him.
Help Andrey choose people to ask. As he needs only one problem, Andrey is going to be really upset if no one comes up with a problem or if he gets more than one problem from his friends. You need to choose such a set of people that maximizes the chances of Andrey not getting upset.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of Andrey's friends. The second line contains *n* real numbers *p**i* (0.0<=≤<=*p**i*<=≤<=1.0) — the probability that the *i*-th friend can come up with a problem. The probabilities are given with at most 6 digits after decimal point.
Output Specification:
Print a single real number — the probability that Andrey won't get upset at the optimal choice of friends. The answer will be considered valid if it differs from the correct one by at most 10<=-<=9.
Demo Input:
['4\n0.1 0.2 0.3 0.8\n', '2\n0.1 0.2\n']
Demo Output:
['0.800000000000\n', '0.260000000000\n']
Note:
In the first sample the best strategy for Andrey is to ask only one of his friends, the most reliable one.
In the second sample the best strategy for Andrey is to ask all of his friends to come up with a problem. Then the probability that he will get exactly one problem is 0.1·0.8 + 0.9·0.2 = 0.26. | ```python
def cali(subset):
z = [1-i for i in subset]
ans = 0
for i in range(len(subset)):
ha = subset[i]
for j in range(len(subset)):
if i!=j:
ha*=z[j]
ans+=ha
return ans
def solve():
n = int(input())
l = list(map(float,input().split()))
l.sort()
if l[-1]>=0.5:
print(l[-1])
else:
ans = 0
yo = -1
ha = []
for i in range(4):
ha.append(l[yo])
z = cali(ha)
ans = max(ans,z)
yo-=1
if yo == -(n+1):
break
print(ans)
# t = int(input())
# for _ in range(t):
solve()
``` | 0 | |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name. | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,544,816,661 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 109 | 0 | #In the name of GOD!
n = int(input())
a = b = 1
for i in range(1, n + 1):
if i == a:
print('O', end = '')
c = b
b = a
a += c
else:
print('o', end = '')
| Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name.
Input Specification:
The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000).
Output Specification:
Print Eleven's new name on the first and only line of output.
Demo Input:
['8\n', '15\n']
Demo Output:
['OOOoOooO\n', 'OOOoOooOooooOoo\n']
Note:
none | ```python
#In the name of GOD!
n = int(input())
a = b = 1
for i in range(1, n + 1):
if i == a:
print('O', end = '')
c = b
b = a
a += c
else:
print('o', end = '')
``` | 3 | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. One night, when everyone went to bed, someone took all the letters of our characters' names. Then he may have shuffled the letters and put them in one pile in front of the door.
The next morning it was impossible to find the culprit who had made the disorder. But everybody wondered whether it is possible to restore the names of the host and his guests from the letters lying at the door? That is, we need to verify that there are no extra letters, and that nobody will need to cut more letters.
Help the "New Year and Christmas Men" and their friends to cope with this problem. You are given both inscriptions that hung over the front door the previous night, and a pile of letters that were found at the front door next morning. | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line does not exceed 100. | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,688,485,473 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | santa = "SANTA"
claus = "CLAUS"
lines = [input().strip() for _ in range(3)]
combined_lines = "".join(lines)
if santa in combined_lines or claus in combined_lines:
print("YES")
else:
print("NO") | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. One night, when everyone went to bed, someone took all the letters of our characters' names. Then he may have shuffled the letters and put them in one pile in front of the door.
The next morning it was impossible to find the culprit who had made the disorder. But everybody wondered whether it is possible to restore the names of the host and his guests from the letters lying at the door? That is, we need to verify that there are no extra letters, and that nobody will need to cut more letters.
Help the "New Year and Christmas Men" and their friends to cope with this problem. You are given both inscriptions that hung over the front door the previous night, and a pile of letters that were found at the front door next morning.
Input Specification:
The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line does not exceed 100.
Output Specification:
Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes.
Demo Input:
['SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n', 'PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n', 'BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | ```python
santa = "SANTA"
claus = "CLAUS"
lines = [input().strip() for _ in range(3)]
combined_lines = "".join(lines)
if santa in combined_lines or claus in combined_lines:
print("YES")
else:
print("NO")
``` | 0 | |
702 | A | Maximum Increase | PROGRAMMING | 800 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous. | The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the maximum length of an increasing subarray of the given array. | [
"5\n1 7 2 11 15\n",
"6\n100 100 100 100 100 100\n",
"3\n1 2 3\n"
] | [
"3\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "5\n1 7 2 11 15",
"output": "3"
},
{
"input": "6\n100 100 100 100 100 100",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "1"
},
{
"input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 7... | 1,665,495,546 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | n = int(input())
a = list(map(int, input().split()))
count = 0
c_max = 0
for i in a:
if i > c_max:
count += 1
c_max = i
elif i < c_max:
count = 1
c_max = i
print(count)
| Title: Maximum Increase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous.
Input Specification:
The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print the maximum length of an increasing subarray of the given array.
Demo Input:
['5\n1 7 2 11 15\n', '6\n100 100 100 100 100 100\n', '3\n1 2 3\n']
Demo Output:
['3\n', '1\n', '3\n']
Note:
none | ```python
n = int(input())
a = list(map(int, input().split()))
count = 0
c_max = 0
for i in a:
if i > c_max:
count += 1
c_max = i
elif i < c_max:
count = 1
c_max = i
print(count)
``` | 0 | |
45 | J | Planting Trees | PROGRAMMING | 1,800 | [
"constructive algorithms"
] | J. Planting Trees | 2 | 256 | Vasya is a Greencode wildlife preservation society proponent. One day he found an empty field nobody owned, divided it into *n*<=×<=*m* squares and decided to plant a forest there. Vasya will plant *nm* trees of all different heights from 1 to *nm*. For his forest to look more natural he wants any two trees growing in the side neighbouring squares to have the absolute value of difference in heights to be strictly more than 1. Help Vasya: make the plan of the forest planting for which this condition is fulfilled. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of rows and columns on Vasya's field | If there's no solution, print -1. Otherwise, print *n* lines containing *m* numbers each — the trees' planting plan. In every square of the plan the height of a tree that should be planted on this square should be written. If there are several solutions to that problem, print any of them. | [
"2 3\n",
"2 1\n"
] | [
"3 6 2\n5 1 4\n",
"-1\n"
] | none | 0 | [
{
"input": "2 3",
"output": "4 1 5 \n2 6 3 "
},
{
"input": "2 1",
"output": "-1"
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "1 3",
"output": "-1"
},
{
"input": "1 4",
"output": "3 1 4 2 "
},
{
"inp... | 1,664,601,192 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 80 | 154 | 3,481,600 | n, m = map(int, input().split())
def solve0(n, m):
swapped = False
if n < m:
n, m = m, n
swapped = True
ret = solve(n, m)
new_ret = [[0 for i in range(n)] for j in range(m)]
if swapped and ret != -1:
for i in range(m):
for j in range(n):
new_ret[i][j] = ret[j][i]
ret = new_ret
return ret
def solve(n, m):
if m == 1 and n == 4:
return [[3], [1], [4], [2]]
if m == 2 and n == 3:
return [[5, 3], [1, 6], [4, 2]]
field = [[0 for i in range(m)] for j in range(n)]
def adv(i, j):
j += 1
if j == m:
j = 0
i += 1
return i, j
def arrange(vals0, vals1):
i, j = 0, 0
for val in vals0:
field[i][j] = val
i, j = adv(i, j)
for val in vals1:
field[i][j] = val
i, j = adv(i, j)
good = True
for i in range(n):
for j in range(m):
if i + 1 < n:
good &= abs(field[i + 1][j] - field[i][j]) > 1
if j + 1 < m:
good &= abs(field[i][j + 1] - field[i][j]) > 1
return good
all_odd = list(range(1, n * m + 1, 2))
all_even = list(range(2 , n * m + 1, 2))
g = arrange(all_odd, all_even)
if g:
return field
all_odd = all_odd[::-1]
if g:
return field
all_even = all_even[::-1]
if g:
return field
all_odd = all_odd[::-1]
if g:
return field
return -1;
ret = solve0(n, m)
if ret == -1:
print(ret)
else:
for x in ret:
print(' '.join(map(str, x))) | Title: Planting Trees
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is a Greencode wildlife preservation society proponent. One day he found an empty field nobody owned, divided it into *n*<=×<=*m* squares and decided to plant a forest there. Vasya will plant *nm* trees of all different heights from 1 to *nm*. For his forest to look more natural he wants any two trees growing in the side neighbouring squares to have the absolute value of difference in heights to be strictly more than 1. Help Vasya: make the plan of the forest planting for which this condition is fulfilled.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of rows and columns on Vasya's field
Output Specification:
If there's no solution, print -1. Otherwise, print *n* lines containing *m* numbers each — the trees' planting plan. In every square of the plan the height of a tree that should be planted on this square should be written. If there are several solutions to that problem, print any of them.
Demo Input:
['2 3\n', '2 1\n']
Demo Output:
['3 6 2\n5 1 4\n', '-1\n']
Note:
none | ```python
n, m = map(int, input().split())
def solve0(n, m):
swapped = False
if n < m:
n, m = m, n
swapped = True
ret = solve(n, m)
new_ret = [[0 for i in range(n)] for j in range(m)]
if swapped and ret != -1:
for i in range(m):
for j in range(n):
new_ret[i][j] = ret[j][i]
ret = new_ret
return ret
def solve(n, m):
if m == 1 and n == 4:
return [[3], [1], [4], [2]]
if m == 2 and n == 3:
return [[5, 3], [1, 6], [4, 2]]
field = [[0 for i in range(m)] for j in range(n)]
def adv(i, j):
j += 1
if j == m:
j = 0
i += 1
return i, j
def arrange(vals0, vals1):
i, j = 0, 0
for val in vals0:
field[i][j] = val
i, j = adv(i, j)
for val in vals1:
field[i][j] = val
i, j = adv(i, j)
good = True
for i in range(n):
for j in range(m):
if i + 1 < n:
good &= abs(field[i + 1][j] - field[i][j]) > 1
if j + 1 < m:
good &= abs(field[i][j + 1] - field[i][j]) > 1
return good
all_odd = list(range(1, n * m + 1, 2))
all_even = list(range(2 , n * m + 1, 2))
g = arrange(all_odd, all_even)
if g:
return field
all_odd = all_odd[::-1]
if g:
return field
all_even = all_even[::-1]
if g:
return field
all_odd = all_odd[::-1]
if g:
return field
return -1;
ret = solve0(n, m)
if ret == -1:
print(ret)
else:
for x in ret:
print(' '.join(map(str, x)))
``` | 3.955015 |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of length *d*3 directly connecting these two shops to each other. Help Patrick calculate the minimum distance that he needs to walk in order to go to both shops and return to his house.
Patrick always starts at his house. He should visit both shops moving only along the three existing roads and return back to his house. He doesn't mind visiting the same shop or passing the same road multiple times. The only goal is to minimize the total distance traveled. | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length of the path connecting both shops. | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house.
In the second sample one of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house. | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,618,310,064 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | # A. Patrick and Shopping
a,b,c=map(int,input().split())
x1=a+c+b
x2=2*a+2*b
print(min(x1,x2)) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of length *d*3 directly connecting these two shops to each other. Help Patrick calculate the minimum distance that he needs to walk in order to go to both shops and return to his house.
Patrick always starts at his house. He should visit both shops moving only along the three existing roads and return back to his house. He doesn't mind visiting the same shop or passing the same road multiple times. The only goal is to minimize the total distance traveled.
Input Specification:
The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length of the path connecting both shops.
Output Specification:
Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house.
Demo Input:
['10 20 30\n', '1 1 5\n']
Demo Output:
['60\n', '4\n']
Note:
The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house.
In the second sample one of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house. | ```python
# A. Patrick and Shopping
a,b,c=map(int,input().split())
x1=a+c+b
x2=2*a+2*b
print(min(x1,x2))
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,605,540,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 34 | 109 | 0 | s = input()
test = 'hello'
counter = 0
for i in range(len(s)):
if counter == 4:
break
else:
if s[i] == test[counter]:
counter+=1
if counter == 4:
print('YES')
else:
print('NO')
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
s = input()
test = 'hello'
counter = 0
for i in range(len(s)):
if counter == 4:
break
else:
if s[i] == test[counter]:
counter+=1
if counter == 4:
print('YES')
else:
print('NO')
``` | 0 |
591 | B | Rebranding | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired *m* designers. Once a company hires the *i*-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters *x**i* by *y**i*, and all the letters *y**i* by *x**i*. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that *x**i* coincides with *y**i*. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descriptions of the designers' actions: the *i*-th of them contains two space-separated lowercase English letters *x**i* and *y**i*. | Print the new name of the corporation. | [
"6 1\npolice\np m\n",
"11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n"
] | [
"molice\n",
"cdcbcdcfcdc\n"
] | In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/de89ad7bc7f27c46ec34f5e66ce0dc23bd5bc90a.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/812e653c8d7ff496e6a0f04c676423806751531e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19c564fcefb8dde36256240a8b877bb6a4792bfe.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/e1cafd93792430ad1a49e893e04715383bdae757.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "6 1\npolice\np m",
"output": "molice"
},
{
"input": "11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b",
"output": "cdcbcdcfcdc"
},
{
"input": "1 1\nf\nz h",
"output": "f"
},
{
"input": "1 1\na\na b",
"output": "b"
},
{
"input": "10 10\nlellelleel\ne l\n... | 1,446,204,154 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 717 | 1,126,400 | n,m = [int(x) for x in input().split()]
name = input()
alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
for i in range(m):
x,y = input().split()
indexX = alphabet.index(x)
indexY = alphabet.index(y)
alphabet[indexX],alphabet[indexY] = alphabet[indexY],alphabet[indexX]
newName = ''
for character in name:
newName += alphabet[ord(character)-97]
print(newName)
#for i in range(m):
# x,y = input().split()
# name = name.replace(x,'.').replace(y,x).replace('.',y)
#for i in range(m):
# newName = ""
# x,y = input().split()
# for character in name:
# if character == x:
# newName+=y
# elif character == y:
# newName += x
# else:
# newName += character
# name = newName | Title: Rebranding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired *m* designers. Once a company hires the *i*-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters *x**i* by *y**i*, and all the letters *y**i* by *x**i*. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that *x**i* coincides with *y**i*. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descriptions of the designers' actions: the *i*-th of them contains two space-separated lowercase English letters *x**i* and *y**i*.
Output Specification:
Print the new name of the corporation.
Demo Input:
['6 1\npolice\np m\n', '11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n']
Demo Output:
['molice\n', 'cdcbcdcfcdc\n']
Note:
In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/de89ad7bc7f27c46ec34f5e66ce0dc23bd5bc90a.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/812e653c8d7ff496e6a0f04c676423806751531e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19c564fcefb8dde36256240a8b877bb6a4792bfe.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/e1cafd93792430ad1a49e893e04715383bdae757.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
n,m = [int(x) for x in input().split()]
name = input()
alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
for i in range(m):
x,y = input().split()
indexX = alphabet.index(x)
indexY = alphabet.index(y)
alphabet[indexX],alphabet[indexY] = alphabet[indexY],alphabet[indexX]
newName = ''
for character in name:
newName += alphabet[ord(character)-97]
print(newName)
#for i in range(m):
# x,y = input().split()
# name = name.replace(x,'.').replace(y,x).replace('.',y)
#for i in range(m):
# newName = ""
# x,y = input().split()
# for character in name:
# if character == x:
# newName+=y
# elif character == y:
# newName += x
# else:
# newName += character
# name = newName
``` | 3 | |
478 | C | Table Decorations | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a program that for given values *r*, *g* and *b* will find the maximum number *t* of tables, that can be decorated in the required manner. | The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space. | Print a single integer *t* — the maximum number of tables that can be decorated in the required manner. | [
"5 4 3\n",
"1 1 1\n",
"2 3 3\n"
] | [
"4\n",
"1\n",
"2\n"
] | In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | 1,500 | [
{
"input": "5 4 3",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "0 1 0",
"output": "0"
},
{
"input": "0 3 3",
"output": "2"
},
{
"input": "4 0 4",
"output": "2"
},
{
"input": "100000... | 1,675,221,314 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 77 | 131,379,200 | # author: ankan2526
import sys,math,heapq,bisect,random,itertools
input = sys.stdin.readline
sys.setrecursionlimit(10**5)
ints = lambda : list(map(int,input().split()))
#def gprint(ans=''):global t;print(f"Case #{t+1}:",*ans)
p = 10**9+7
inf = 10**20+7
ALPHA = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
alpha = "abcdefghijklmnopqrstuvwxyz"
#p2 = [1]
#for i in range(70):p2.append(p2[-1]*2)
"""
"""
a = ints()
a.sort()
if a[-1]>=2*(a[0]+a[1]):
print(a[0]+a[1])
else:
print(sum(a)//3)
| Title: Table Decorations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a program that for given values *r*, *g* and *b* will find the maximum number *t* of tables, that can be decorated in the required manner.
Input Specification:
The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space.
Output Specification:
Print a single integer *t* — the maximum number of tables that can be decorated in the required manner.
Demo Input:
['5 4 3\n', '1 1 1\n', '2 3 3\n']
Demo Output:
['4\n', '1\n', '2\n']
Note:
In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | ```python
# author: ankan2526
import sys,math,heapq,bisect,random,itertools
input = sys.stdin.readline
sys.setrecursionlimit(10**5)
ints = lambda : list(map(int,input().split()))
#def gprint(ans=''):global t;print(f"Case #{t+1}:",*ans)
p = 10**9+7
inf = 10**20+7
ALPHA = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
alpha = "abcdefghijklmnopqrstuvwxyz"
#p2 = [1]
#for i in range(70):p2.append(p2[-1]*2)
"""
"""
a = ints()
a.sort()
if a[-1]>=2*(a[0]+a[1]):
print(a[0]+a[1])
else:
print(sum(a)//3)
``` | 3 | |
36 | A | Extra-terrestrial Intelligence | PROGRAMMING | 1,300 | [
"implementation"
] | A. Extra-terrestrial Intelligence | 2 | 64 | Recently Vasya got interested in finding extra-terrestrial intelligence. He made a simple extra-terrestrial signals’ receiver and was keeping a record of the signals for *n* days in a row. Each of those *n* days Vasya wrote a 1 in his notebook if he had received a signal that day and a 0 if he hadn’t. Vasya thinks that he has found extra-terrestrial intelligence if there is a system in the way the signals has been received, i.e. if all the intervals between successive signals are equal. Otherwise, Vasya thinks that the signals were sent by some stupid aliens no one cares about. Help Vasya to deduce from the information given by the receiver if he has found extra-terrestrial intelligence or not. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of days during which Vasya checked if there were any signals. The second line contains *n* characters 1 or 0 — the record Vasya kept each of those *n* days. It’s guaranteed that the given record sequence contains at least three 1s. | If Vasya has found extra-terrestrial intelligence, output YES, otherwise output NO. | [
"8\n00111000\n",
"7\n1001011\n",
"7\n1010100\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "8\n00111000",
"output": "YES"
},
{
"input": "7\n1001011",
"output": "NO"
},
{
"input": "7\n1010100",
"output": "YES"
},
{
"input": "5\n10101",
"output": "YES"
},
{
"input": "3\n111",
"output": "YES"
},
{
"input": "10\n0011111011",
"outp... | 1,685,692,296 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 122 | 2,867,200 |
n=int(input())
s=input()
e,m=-1,-1
k=True
for i in range(n):
if e==-1 and s[i]=='1':
e=i
elif m==-1 and s[i]=='1':
m=i
elif s[i]=='1' and m-e!=i-m:
k=False
if k:
print("YES")
else:
print("NO")
| Title: Extra-terrestrial Intelligence
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Recently Vasya got interested in finding extra-terrestrial intelligence. He made a simple extra-terrestrial signals’ receiver and was keeping a record of the signals for *n* days in a row. Each of those *n* days Vasya wrote a 1 in his notebook if he had received a signal that day and a 0 if he hadn’t. Vasya thinks that he has found extra-terrestrial intelligence if there is a system in the way the signals has been received, i.e. if all the intervals between successive signals are equal. Otherwise, Vasya thinks that the signals were sent by some stupid aliens no one cares about. Help Vasya to deduce from the information given by the receiver if he has found extra-terrestrial intelligence or not.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of days during which Vasya checked if there were any signals. The second line contains *n* characters 1 or 0 — the record Vasya kept each of those *n* days. It’s guaranteed that the given record sequence contains at least three 1s.
Output Specification:
If Vasya has found extra-terrestrial intelligence, output YES, otherwise output NO.
Demo Input:
['8\n00111000\n', '7\n1001011\n', '7\n1010100\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none | ```python
n=int(input())
s=input()
e,m=-1,-1
k=True
for i in range(n):
if e==-1 and s[i]=='1':
e=i
elif m==-1 and s[i]=='1':
m=i
elif s[i]=='1' and m-e!=i-m:
k=False
if k:
print("YES")
else:
print("NO")
``` | -1 |
96 | A | Football | PROGRAMMING | 900 | [
"implementation",
"strings"
] | A. Football | 2 | 256 | Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not. | The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. | Print "YES" if the situation is dangerous. Otherwise, print "NO". | [
"001001\n",
"1000000001\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "001001",
"output": "NO"
},
{
"input": "1000000001",
"output": "YES"
},
{
"input": "00100110111111101",
"output": "YES"
},
{
"input": "11110111111111111",
"output": "YES"
},
{
"input": "01",
"output": "NO"
},
{
"input": "10100101",
"outp... | 1,692,917,547 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 92 | 0 | num = input()
valor =''
cant = 0
for x in range(len(num)):
if cant==7:
break
if x ==0:
valor = num[x]
cant +=1
elif valor == num[x]:
cant +=1
elif valor != num[x]:
cant = 1
valor = num[x]
if cant>=7:
print("YES")
else:
print("NO") | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.
Input Specification:
The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.
Output Specification:
Print "YES" if the situation is dangerous. Otherwise, print "NO".
Demo Input:
['001001\n', '1000000001\n']
Demo Output:
['NO\n', 'YES\n']
Note:
none | ```python
num = input()
valor =''
cant = 0
for x in range(len(num)):
if cant==7:
break
if x ==0:
valor = num[x]
cant +=1
elif valor == num[x]:
cant +=1
elif valor != num[x]:
cant = 1
valor = num[x]
if cant>=7:
print("YES")
else:
print("NO")
``` | 3.977 |
482 | A | Diverse Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Your task is to find such permutation *p* of length *n*, that the group of numbers |*p*1<=-<=*p*2|,<=|*p*2<=-<=*p*3|,<=...,<=|*p**n*<=-<=1<=-<=*p**n*| has exactly *k* distinct elements. | The single line of the input contains two space-separated positive integers *n*, *k* (1<=≤<=*k*<=<<=*n*<=≤<=105). | Print *n* integers forming the permutation. If there are multiple answers, print any of them. | [
"3 2\n",
"3 1\n",
"5 2\n"
] | [
"1 3 2\n",
"1 2 3\n",
"1 3 2 4 5\n"
] | By |*x*| we denote the absolute value of number *x*. | 500 | [
{
"input": "3 2",
"output": "1 3 2"
},
{
"input": "3 1",
"output": "1 2 3"
},
{
"input": "5 2",
"output": "1 3 2 4 5"
},
{
"input": "5 4",
"output": "1 5 2 4 3"
},
{
"input": "10 4",
"output": "1 10 2 9 8 7 6 5 4 3"
},
{
"input": "10 3",
"output": ... | 1,426,914,257 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 155 | 6,144,000 | # coding: utf-8
n, k = [int(i) for i in input().split()]
ans = ['1']
for i in range(k):
if i%2==0:
ans.append(str(int(ans[-1])+(k-i)))
else:
ans.append(str(int(ans[-1])-(k-i)))
ans += [str(i) for i in range(k+2,n+1)]
print(' '.join(ans))
| Title: Diverse Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Your task is to find such permutation *p* of length *n*, that the group of numbers |*p*1<=-<=*p*2|,<=|*p*2<=-<=*p*3|,<=...,<=|*p**n*<=-<=1<=-<=*p**n*| has exactly *k* distinct elements.
Input Specification:
The single line of the input contains two space-separated positive integers *n*, *k* (1<=≤<=*k*<=<<=*n*<=≤<=105).
Output Specification:
Print *n* integers forming the permutation. If there are multiple answers, print any of them.
Demo Input:
['3 2\n', '3 1\n', '5 2\n']
Demo Output:
['1 3 2\n', '1 2 3\n', '1 3 2 4 5\n']
Note:
By |*x*| we denote the absolute value of number *x*. | ```python
# coding: utf-8
n, k = [int(i) for i in input().split()]
ans = ['1']
for i in range(k):
if i%2==0:
ans.append(str(int(ans[-1])+(k-i)))
else:
ans.append(str(int(ans[-1])-(k-i)))
ans += [str(i) for i in range(k+2,n+1)]
print(' '.join(ans))
``` | 3 | |
626 | F | Group Projects | PROGRAMMING | 2,400 | [
"dp"
] | null | null | There are *n* students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the *i*-th student *a**i* minutes to finish his/her independent piece.
If students work at different paces, it can be frustrating for the faster students and stressful for the slower ones. In particular, the imbalance of a group is defined as the maximum *a**i* in the group minus the minimum *a**i* in the group. Note that a group containing a single student has an imbalance of 0. How many ways are there for the students to divide into groups so that the total imbalance of all groups is at most *k*?
Two divisions are considered distinct if there exists a pair of students who work in the same group in one division but different groups in the other. | The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=200, 0<=≤<=*k*<=≤<=1000) — the number of students and the maximum total imbalance allowed, respectively.
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=500) — the time it takes the *i*-th student to complete his/her independent piece of work. | Print a single integer, the number of ways the students can form groups. As the answer may be large, print its value modulo 109<=+<=7. | [
"3 2\n2 4 5\n",
"4 3\n7 8 9 10\n",
"4 0\n5 10 20 21\n"
] | [
"3\n",
"13\n",
"1\n"
] | In the first sample, we have three options:
- The first and second students form a group, and the third student forms a group. Total imbalance is 2 + 0 = 2. - The first student forms a group, and the second and third students form a group. Total imbalance is 0 + 1 = 1. - All three students form their own groups. Total imbalance is 0.
In the third sample, the total imbalance must be 0, so each student must work individually. | 2,500 | [
{
"input": "3 2\n2 4 5",
"output": "3"
},
{
"input": "4 3\n7 8 9 10",
"output": "13"
},
{
"input": "4 0\n5 10 20 21",
"output": "1"
},
{
"input": "20 1000\n50 50 100 100 150 150 200 200 250 250 300 300 350 350 400 400 450 450 500 500",
"output": "97456952"
},
{
"i... | 1,603,517,433 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 248,934,400 | import math
modulo = math.pow(10, 9) + 7
def findways(arr, curr, k, dp):
if(curr >= len(arr) - 1):
return 0
if(dp[curr][k] != -1):
return dp[curr][k]
c = 0
for i in range(curr + 1, len(arr)):
if(arr[i] - arr[curr] <= k):
c = c + 1
dp[i][k - (arr[i] - arr[curr])] = findways(arr, i, k - (arr[i] - arr[curr]), dp)
c = c + dp[i][k - (arr[i] - arr[curr])]
else:
break
dp[curr + 1][k] = z = findways(arr, curr + 1, k, dp)
dp[curr][k] = (c + z) % modulo
return int((c + z) % modulo)
n, k = list(map(int, input().split(" ")))
arr = list(map(int, input().split(" ")))
arr.sort()
dp = [[-1 for i in range(10000)] for j in range(10000)]
s = findways(arr, 0, k, dp)
print(s + 1)
| Title: Group Projects
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the *i*-th student *a**i* minutes to finish his/her independent piece.
If students work at different paces, it can be frustrating for the faster students and stressful for the slower ones. In particular, the imbalance of a group is defined as the maximum *a**i* in the group minus the minimum *a**i* in the group. Note that a group containing a single student has an imbalance of 0. How many ways are there for the students to divide into groups so that the total imbalance of all groups is at most *k*?
Two divisions are considered distinct if there exists a pair of students who work in the same group in one division but different groups in the other.
Input Specification:
The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=200, 0<=≤<=*k*<=≤<=1000) — the number of students and the maximum total imbalance allowed, respectively.
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=500) — the time it takes the *i*-th student to complete his/her independent piece of work.
Output Specification:
Print a single integer, the number of ways the students can form groups. As the answer may be large, print its value modulo 109<=+<=7.
Demo Input:
['3 2\n2 4 5\n', '4 3\n7 8 9 10\n', '4 0\n5 10 20 21\n']
Demo Output:
['3\n', '13\n', '1\n']
Note:
In the first sample, we have three options:
- The first and second students form a group, and the third student forms a group. Total imbalance is 2 + 0 = 2. - The first student forms a group, and the second and third students form a group. Total imbalance is 0 + 1 = 1. - All three students form their own groups. Total imbalance is 0.
In the third sample, the total imbalance must be 0, so each student must work individually. | ```python
import math
modulo = math.pow(10, 9) + 7
def findways(arr, curr, k, dp):
if(curr >= len(arr) - 1):
return 0
if(dp[curr][k] != -1):
return dp[curr][k]
c = 0
for i in range(curr + 1, len(arr)):
if(arr[i] - arr[curr] <= k):
c = c + 1
dp[i][k - (arr[i] - arr[curr])] = findways(arr, i, k - (arr[i] - arr[curr]), dp)
c = c + dp[i][k - (arr[i] - arr[curr])]
else:
break
dp[curr + 1][k] = z = findways(arr, curr + 1, k, dp)
dp[curr][k] = (c + z) % modulo
return int((c + z) % modulo)
n, k = list(map(int, input().split(" ")))
arr = list(map(int, input().split(" ")))
arr.sort()
dp = [[-1 for i in range(10000)] for j in range(10000)]
s = findways(arr, 0, k, dp)
print(s + 1)
``` | 0 | |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,695,718,183 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 342 | 307,200 | from collections import defaultdict
n,m = input().split()
n = int(n)
m = int(m)
arr = []
for i in range(n):
a = input()
arr.append(a)
ans = ""
for i in range(n):
for j in range(m):
letter = arr[i][j]
count = arr[i].count(letter)
flag = True
for k in range(n):
if k != i:
if arr[k][j] == letter:
flag = False
if flag and count == 1:
ans+=letter
print(ans)
| Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid.
Output Specification:
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Demo Input:
['3 3\ncba\nbcd\ncbc\n', '5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n']
Demo Output:
['abcd', 'codeforces']
Note:
none | ```python
from collections import defaultdict
n,m = input().split()
n = int(n)
m = int(m)
arr = []
for i in range(n):
a = input()
arr.append(a)
ans = ""
for i in range(n):
for j in range(m):
letter = arr[i][j]
count = arr[i].count(letter)
flag = True
for k in range(n):
if k != i:
if arr[k][j] == letter:
flag = False
if flag and count == 1:
ans+=letter
print(ans)
``` | 3.913928 |
0 | none | none | none | 0 | [
"none"
] | null | null | Valery is a PE teacher at a school in Berland. Soon the students are going to take a test in long jumps, and Valery has lost his favorite ruler!
However, there is no reason for disappointment, as Valery has found another ruler, its length is *l* centimeters. The ruler already has *n* marks, with which he can make measurements. We assume that the marks are numbered from 1 to *n* in the order they appear from the beginning of the ruler to its end. The first point coincides with the beginning of the ruler and represents the origin. The last mark coincides with the end of the ruler, at distance *l* from the origin. This ruler can be repesented by an increasing sequence *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* denotes the distance of the *i*-th mark from the origin (*a*1<==<=0, *a**n*<==<=*l*).
Valery believes that with a ruler he can measure the distance of *d* centimeters, if there is a pair of integers *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*), such that the distance between the *i*-th and the *j*-th mark is exactly equal to *d* (in other words, *a**j*<=-<=*a**i*<==<=*d*).
Under the rules, the girls should be able to jump at least *x* centimeters, and the boys should be able to jump at least *y* (*x*<=<<=*y*) centimeters. To test the children's abilities, Valery needs a ruler to measure each of the distances *x* and *y*.
Your task is to determine what is the minimum number of additional marks you need to add on the ruler so that they can be used to measure the distances *x* and *y*. Valery can add the marks at any integer non-negative distance from the origin not exceeding the length of the ruler. | The first line contains four positive space-separated integers *n*, *l*, *x*, *y* (2<=≤<=*n*<=≤<=105, 2<=≤<=*l*<=≤<=109, 1<=≤<=*x*<=<<=*y*<=≤<=*l*) — the number of marks, the length of the ruler and the jump norms for girls and boys, correspondingly.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<==<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<==<=*l*), where *a**i* shows the distance from the *i*-th mark to the origin. | In the first line print a single non-negative integer *v* — the minimum number of marks that you need to add on the ruler.
In the second line print *v* space-separated integers *p*1,<=*p*2,<=...,<=*p**v* (0<=≤<=*p**i*<=≤<=*l*). Number *p**i* means that the *i*-th mark should be at the distance of *p**i* centimeters from the origin. Print the marks in any order. If there are multiple solutions, print any of them. | [
"3 250 185 230\n0 185 250\n",
"4 250 185 230\n0 20 185 250\n",
"2 300 185 230\n0 300\n"
] | [
"1\n230\n",
"0\n",
"2\n185 230\n"
] | In the first sample it is impossible to initially measure the distance of 230 centimeters. For that it is enough to add a 20 centimeter mark or a 230 centimeter mark.
In the second sample you already can use the ruler to measure the distances of 185 and 230 centimeters, so you don't have to add new marks.
In the third sample the ruler only contains the initial and the final marks. We will need to add two marks to be able to test the children's skills. | 0 | [
{
"input": "3 250 185 230\n0 185 250",
"output": "1\n230"
},
{
"input": "4 250 185 230\n0 20 185 250",
"output": "0"
},
{
"input": "2 300 185 230\n0 300",
"output": "2\n185 230"
},
{
"input": "4 300 4 5\n0 6 7 300",
"output": "1\n11"
},
{
"input": "2 100 30 70\n0 ... | 1,567,070,138 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | class CodeforcesTask480BSolution:
def __init__(self):
self.result = ''
self.n_l_x_y = []
self.ruler = []
def read_input(self):
self.n_l_x_y = [int(x) for x in input().split(" ")]
self.ruler = [int(x) for x in input().split(" ")]
def process_task(self):
dists = {}
for a in self.ruler:
dists[a] = True
hasx = False
hasy = False
for a in self.ruler:
try:
if dists[a - self.n_l_x_y[2]]:
hasx = True
except KeyError:
pass
try:
if dists[a + self.n_l_x_y[2]]:
hasx = True
except KeyError:
pass
try:
if dists[a - self.n_l_x_y[3]]:
hasy = True
except KeyError:
pass
try:
if dists[a - self.n_l_x_y[3]]:
hasy = True
except KeyError:
pass
if hasx and hasy:
break
if hasx and hasy:
self.result = "0"
elif hasx:
self.result = "1\n{0}".format(self.n_l_x_y[3])
elif hasy:
self.result = "1\n{1}".format(self.n_l_x_y[2])
else:
res = [0, 0]
sgn = False
dst = self.n_l_x_y[2] + self.n_l_x_y[3]
for a in self.ruler:
try:
if dists[a - dst]:
sgn = True
res = a - self.n_l_x_y[2]
except KeyError:
pass
try:
if dists[a + dst]:
sgn = True
res = a + self.n_l_x_y[2]
except KeyError:
pass
if sgn:
break
if sgn:
self.result = "1\n{0}".format(res)
else:
self.result = "2\n{0} {1}".format(self.n_l_x_y[2], self.n_l_x_y[3])
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask480BSolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valery is a PE teacher at a school in Berland. Soon the students are going to take a test in long jumps, and Valery has lost his favorite ruler!
However, there is no reason for disappointment, as Valery has found another ruler, its length is *l* centimeters. The ruler already has *n* marks, with which he can make measurements. We assume that the marks are numbered from 1 to *n* in the order they appear from the beginning of the ruler to its end. The first point coincides with the beginning of the ruler and represents the origin. The last mark coincides with the end of the ruler, at distance *l* from the origin. This ruler can be repesented by an increasing sequence *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* denotes the distance of the *i*-th mark from the origin (*a*1<==<=0, *a**n*<==<=*l*).
Valery believes that with a ruler he can measure the distance of *d* centimeters, if there is a pair of integers *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*), such that the distance between the *i*-th and the *j*-th mark is exactly equal to *d* (in other words, *a**j*<=-<=*a**i*<==<=*d*).
Under the rules, the girls should be able to jump at least *x* centimeters, and the boys should be able to jump at least *y* (*x*<=<<=*y*) centimeters. To test the children's abilities, Valery needs a ruler to measure each of the distances *x* and *y*.
Your task is to determine what is the minimum number of additional marks you need to add on the ruler so that they can be used to measure the distances *x* and *y*. Valery can add the marks at any integer non-negative distance from the origin not exceeding the length of the ruler.
Input Specification:
The first line contains four positive space-separated integers *n*, *l*, *x*, *y* (2<=≤<=*n*<=≤<=105, 2<=≤<=*l*<=≤<=109, 1<=≤<=*x*<=<<=*y*<=≤<=*l*) — the number of marks, the length of the ruler and the jump norms for girls and boys, correspondingly.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<==<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<==<=*l*), where *a**i* shows the distance from the *i*-th mark to the origin.
Output Specification:
In the first line print a single non-negative integer *v* — the minimum number of marks that you need to add on the ruler.
In the second line print *v* space-separated integers *p*1,<=*p*2,<=...,<=*p**v* (0<=≤<=*p**i*<=≤<=*l*). Number *p**i* means that the *i*-th mark should be at the distance of *p**i* centimeters from the origin. Print the marks in any order. If there are multiple solutions, print any of them.
Demo Input:
['3 250 185 230\n0 185 250\n', '4 250 185 230\n0 20 185 250\n', '2 300 185 230\n0 300\n']
Demo Output:
['1\n230\n', '0\n', '2\n185 230\n']
Note:
In the first sample it is impossible to initially measure the distance of 230 centimeters. For that it is enough to add a 20 centimeter mark or a 230 centimeter mark.
In the second sample you already can use the ruler to measure the distances of 185 and 230 centimeters, so you don't have to add new marks.
In the third sample the ruler only contains the initial and the final marks. We will need to add two marks to be able to test the children's skills. | ```python
class CodeforcesTask480BSolution:
def __init__(self):
self.result = ''
self.n_l_x_y = []
self.ruler = []
def read_input(self):
self.n_l_x_y = [int(x) for x in input().split(" ")]
self.ruler = [int(x) for x in input().split(" ")]
def process_task(self):
dists = {}
for a in self.ruler:
dists[a] = True
hasx = False
hasy = False
for a in self.ruler:
try:
if dists[a - self.n_l_x_y[2]]:
hasx = True
except KeyError:
pass
try:
if dists[a + self.n_l_x_y[2]]:
hasx = True
except KeyError:
pass
try:
if dists[a - self.n_l_x_y[3]]:
hasy = True
except KeyError:
pass
try:
if dists[a - self.n_l_x_y[3]]:
hasy = True
except KeyError:
pass
if hasx and hasy:
break
if hasx and hasy:
self.result = "0"
elif hasx:
self.result = "1\n{0}".format(self.n_l_x_y[3])
elif hasy:
self.result = "1\n{1}".format(self.n_l_x_y[2])
else:
res = [0, 0]
sgn = False
dst = self.n_l_x_y[2] + self.n_l_x_y[3]
for a in self.ruler:
try:
if dists[a - dst]:
sgn = True
res = a - self.n_l_x_y[2]
except KeyError:
pass
try:
if dists[a + dst]:
sgn = True
res = a + self.n_l_x_y[2]
except KeyError:
pass
if sgn:
break
if sgn:
self.result = "1\n{0}".format(res)
else:
self.result = "2\n{0} {1}".format(self.n_l_x_y[2], self.n_l_x_y[3])
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask480BSolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
``` | 0 | |
57 | A | Square Earth? | PROGRAMMING | 1,300 | [
"dfs and similar",
"greedy",
"implementation"
] | A. Square Earth? | 2 | 256 | Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards our planet as a two-dimensional circle. No, wait, it's even worse — as a square of side *n*. Thus, the task has been reduced to finding the shortest path between two dots on a square (the path should go through the square sides). To simplify the task let us consider the vertices of the square to lie at points whose coordinates are: (0,<=0), (*n*,<=0), (0,<=*n*) and (*n*,<=*n*). | The single line contains 5 space-separated integers: *n*,<=*x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*) which correspondingly represent a side of the square, the coordinates of the first point and the coordinates of the second point. It is guaranteed that the points lie on the sides of the square. | You must print on a single line the shortest distance between the points. | [
"2 0 0 1 0\n",
"2 0 1 2 1\n",
"100 0 0 100 100\n"
] | [
"1\n",
"4\n",
"200\n"
] | none | 500 | [
{
"input": "2 0 0 1 0",
"output": "1"
},
{
"input": "2 0 1 2 1",
"output": "4"
},
{
"input": "100 0 0 100 100",
"output": "200"
},
{
"input": "4 0 3 1 4",
"output": "2"
},
{
"input": "10 8 10 10 0",
"output": "12"
},
{
"input": "26 21 0 26 14",
"ou... | 1,541,699,687 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 218 | 0 | def check(n, x, y):
if x == 0:
return y
if y == n:
return x + n
if x == n:
return 3 * n - y
return 4 * n - x
def earth(n, x1, y1, x2, y2):
r1, r2 = check(n, x1, y1), check(n, x2, y2)
result = abs(r1 - r2)
return min(result, 4 * n - result)
N, X1, Y1, X2, Y2 = [int(i) for i in input().split()]
print(earth(N, X1, Y1, X2, Y2))
| Title: Square Earth?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards our planet as a two-dimensional circle. No, wait, it's even worse — as a square of side *n*. Thus, the task has been reduced to finding the shortest path between two dots on a square (the path should go through the square sides). To simplify the task let us consider the vertices of the square to lie at points whose coordinates are: (0,<=0), (*n*,<=0), (0,<=*n*) and (*n*,<=*n*).
Input Specification:
The single line contains 5 space-separated integers: *n*,<=*x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*) which correspondingly represent a side of the square, the coordinates of the first point and the coordinates of the second point. It is guaranteed that the points lie on the sides of the square.
Output Specification:
You must print on a single line the shortest distance between the points.
Demo Input:
['2 0 0 1 0\n', '2 0 1 2 1\n', '100 0 0 100 100\n']
Demo Output:
['1\n', '4\n', '200\n']
Note:
none | ```python
def check(n, x, y):
if x == 0:
return y
if y == n:
return x + n
if x == n:
return 3 * n - y
return 4 * n - x
def earth(n, x1, y1, x2, y2):
r1, r2 = check(n, x1, y1), check(n, x2, y2)
result = abs(r1 - r2)
return min(result, 4 * n - result)
N, X1, Y1, X2, Y2 = [int(i) for i in input().split()]
print(earth(N, X1, Y1, X2, Y2))
``` | 3.9455 |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out.
On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day).
Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out. | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day. | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,595,846,257 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 108 | 6,963,200 | t = 1
for qwe in range(t):
# n = int(f.readline())
n = int(input())
# a = list(map(int, f.readline().split()))
a = list(map(int, input().split()))
temp = [0, 0, 0]
temp.extend(a)
a = temp
ans = 0
# Обработать случаи когда n = 1, 2, 3
for i in range(n+3):
if a[i] == 0:
ans += 1
elif a[i] == 3:
pass
elif a[i] == 1:
if a[i-1] == 0 or a[i-1] == 2:
pass
elif a[i-1] == 1:
ans += 1
elif a[i-1] == 3:
if a[i-2] == 0 or a[i-2] == 1:
pass
elif a[i-2] == 2:
ans += 1
elif a[i-2] == 3:
k = 2
ind = i - 2
while ind - 1 == 3:
ind -= 1
k += 1
ind -= 1
if k % 2 == 1:
if a[ind] == 0 or a[ind] == 1:
pass
elif a[ind] == 2:
ans += 1
else:
if a[ind] == 0 or a[ind] == 2:
pass
elif a[ind] == 1:
ans += 1
elif a[i] == 2:
if a[i-1] == 0 or a[i-1] == 1:
pass
elif a[i-1] == 2:
ans += 1
elif a[i-1] == 3:
if a[i-2] == 0 or a[i-2] == 2:
pass
elif a[i-2] == 1:
ans += 1
elif a[i-2] == 3:
k = 2
ind = i - 2
while ind - 1 == 3:
ind -= 1
k += 1
ind -= 1
if k % 2 == 1:
if a[ind] == 0 or a[ind] == 2:
pass
elif a[ind] == 1:
ans += 1
else:
if a[ind] == 0 or a[ind] == 1:
pass
elif a[ind] == 2:
ans += 1
print(ans-3)
| Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out.
On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day).
Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out.
Output Specification:
Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days.
Demo Input:
['4\n1 3 2 0\n', '7\n1 3 3 2 1 2 3\n', '2\n2 2\n']
Demo Output:
['2\n', '0\n', '1\n']
Note:
In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day. | ```python
t = 1
for qwe in range(t):
# n = int(f.readline())
n = int(input())
# a = list(map(int, f.readline().split()))
a = list(map(int, input().split()))
temp = [0, 0, 0]
temp.extend(a)
a = temp
ans = 0
# Обработать случаи когда n = 1, 2, 3
for i in range(n+3):
if a[i] == 0:
ans += 1
elif a[i] == 3:
pass
elif a[i] == 1:
if a[i-1] == 0 or a[i-1] == 2:
pass
elif a[i-1] == 1:
ans += 1
elif a[i-1] == 3:
if a[i-2] == 0 or a[i-2] == 1:
pass
elif a[i-2] == 2:
ans += 1
elif a[i-2] == 3:
k = 2
ind = i - 2
while ind - 1 == 3:
ind -= 1
k += 1
ind -= 1
if k % 2 == 1:
if a[ind] == 0 or a[ind] == 1:
pass
elif a[ind] == 2:
ans += 1
else:
if a[ind] == 0 or a[ind] == 2:
pass
elif a[ind] == 1:
ans += 1
elif a[i] == 2:
if a[i-1] == 0 or a[i-1] == 1:
pass
elif a[i-1] == 2:
ans += 1
elif a[i-1] == 3:
if a[i-2] == 0 or a[i-2] == 2:
pass
elif a[i-2] == 1:
ans += 1
elif a[i-2] == 3:
k = 2
ind = i - 2
while ind - 1 == 3:
ind -= 1
k += 1
ind -= 1
if k % 2 == 1:
if a[ind] == 0 or a[ind] == 2:
pass
elif a[ind] == 1:
ans += 1
else:
if a[ind] == 0 or a[ind] == 1:
pass
elif a[ind] == 2:
ans += 1
print(ans-3)
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,661,347,132 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 92 | 0 | n = int(input())
matrix = [[0]*3 for j in range(n)]
for i in range(len(matrix)):
matrix[i] = list(map(int, input().split()))
xsum, ysum, zsum = 0,0,0
for i in range(len(matrix)):
xsum += matrix[i][0]
ysum += matrix[i][1]
zsum += matrix[i][2]
if xsum == 0 and ysum == 0 and zsum == 0:
print('YES')
else:
print('NO')
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n = int(input())
matrix = [[0]*3 for j in range(n)]
for i in range(len(matrix)):
matrix[i] = list(map(int, input().split()))
xsum, ysum, zsum = 0,0,0
for i in range(len(matrix)):
xsum += matrix[i][0]
ysum += matrix[i][1]
zsum += matrix[i][2]
if xsum == 0 and ysum == 0 and zsum == 0:
print('YES')
else:
print('NO')
``` | 3.977 |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of currency you all know against the burle for tomorrow. Now Anton knows that tomorrow the exchange rate will be an even number, which can be obtained from the present rate by swapping exactly two distinct digits in it. Of all the possible values that meet these conditions, the exchange rate for tomorrow will be the maximum possible. It is guaranteed that today the exchange rate is an odd positive integer *n*. Help Anton to determine the exchange rate of currency you all know for tomorrow! | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained from today's exchange rate by swapping exactly two digits. Exchange rate representation should not contain leading zeroes. | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,694,600,185 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 93 | 2,867,200 | n,m,k=map(int,input().split())
a=[[2]+[0]*m+[2] for i in range(n)]
a.insert(0,[2]*(m+2))
a.insert(n+1,[2]*(m+2))
for x in range(1,k+1):
i,j=map(int,input().split())
i-=1
j-=1
a[i][j]=1
if a[i][j]==a[i][j+1]==1:
if a[i+1][j]==a[i+1][j+1]==1:print(x);break
elif a[i-1][j]==a[i-1][j+1]==1:print(x);break
if a[i][j]==a[i][j-1]:
if a[i+1][j]==a[i+1][j-1]==1:print(x);break
elif a[i-1][j]==a[i-1][j-1]==1:print(x);break
else:print(0)
| Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of currency you all know against the burle for tomorrow. Now Anton knows that tomorrow the exchange rate will be an even number, which can be obtained from the present rate by swapping exactly two distinct digits in it. Of all the possible values that meet these conditions, the exchange rate for tomorrow will be the maximum possible. It is guaranteed that today the exchange rate is an odd positive integer *n*. Help Anton to determine the exchange rate of currency you all know for tomorrow!
Input Specification:
The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes.
Output Specification:
If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained from today's exchange rate by swapping exactly two digits. Exchange rate representation should not contain leading zeroes.
Demo Input:
['527\n', '4573\n', '1357997531\n']
Demo Output:
['572\n', '3574\n', '-1\n']
Note:
none | ```python
n,m,k=map(int,input().split())
a=[[2]+[0]*m+[2] for i in range(n)]
a.insert(0,[2]*(m+2))
a.insert(n+1,[2]*(m+2))
for x in range(1,k+1):
i,j=map(int,input().split())
i-=1
j-=1
a[i][j]=1
if a[i][j]==a[i][j+1]==1:
if a[i+1][j]==a[i+1][j+1]==1:print(x);break
elif a[i-1][j]==a[i-1][j+1]==1:print(x);break
if a[i][j]==a[i][j-1]:
if a[i+1][j]==a[i+1][j-1]==1:print(x);break
elif a[i-1][j]==a[i-1][j-1]==1:print(x);break
else:print(0)
``` | -1 | |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of currency you all know against the burle for tomorrow. Now Anton knows that tomorrow the exchange rate will be an even number, which can be obtained from the present rate by swapping exactly two distinct digits in it. Of all the possible values that meet these conditions, the exchange rate for tomorrow will be the maximum possible. It is guaranteed that today the exchange rate is an odd positive integer *n*. Help Anton to determine the exchange rate of currency you all know for tomorrow! | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained from today's exchange rate by swapping exactly two digits. Exchange rate representation should not contain leading zeroes. | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,662,536,006 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 77 | 11,468,800 | # Python3 code for the above implementation
import sys
# Make the largest even number
def makeEven(arr, n):
# index to first even no,if any
first_e_i = -1
# index to last even no, if any
last_e_i = -1
# index to last no
last_n_i = n - 1
# Start traversing the String
for i in range(n):
# if it finds any first even no less
# than last digit then break the loop
if (int(arr[i]) % 2 == 0 and
int(arr[i]) < int(arr[last_n_i])):
first_e_i = i
break
# it finds last even no
if int(arr[i]) % 2 == 0:
last_e_i = i
if first_e_i != -1:
# swap even and odd value
(arr[first_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[first_e_i])
return arr
if first_e_i == -1 and last_e_i != -1:
# swap even and odd value
(arr[last_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[last_e_i])
return arr
# Return original String if there is
# no even number
return arr
# Driver Code
string = input()
result = "".join(makeEven(list(string),
len(list(string))))
if(result==string):
print(-1)
else:
print(result)
# This code is contributed
# by Vikash Kumar 37
| Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of currency you all know against the burle for tomorrow. Now Anton knows that tomorrow the exchange rate will be an even number, which can be obtained from the present rate by swapping exactly two distinct digits in it. Of all the possible values that meet these conditions, the exchange rate for tomorrow will be the maximum possible. It is guaranteed that today the exchange rate is an odd positive integer *n*. Help Anton to determine the exchange rate of currency you all know for tomorrow!
Input Specification:
The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes.
Output Specification:
If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained from today's exchange rate by swapping exactly two digits. Exchange rate representation should not contain leading zeroes.
Demo Input:
['527\n', '4573\n', '1357997531\n']
Demo Output:
['572\n', '3574\n', '-1\n']
Note:
none | ```python
# Python3 code for the above implementation
import sys
# Make the largest even number
def makeEven(arr, n):
# index to first even no,if any
first_e_i = -1
# index to last even no, if any
last_e_i = -1
# index to last no
last_n_i = n - 1
# Start traversing the String
for i in range(n):
# if it finds any first even no less
# than last digit then break the loop
if (int(arr[i]) % 2 == 0 and
int(arr[i]) < int(arr[last_n_i])):
first_e_i = i
break
# it finds last even no
if int(arr[i]) % 2 == 0:
last_e_i = i
if first_e_i != -1:
# swap even and odd value
(arr[first_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[first_e_i])
return arr
if first_e_i == -1 and last_e_i != -1:
# swap even and odd value
(arr[last_e_i],
arr[last_n_i]) = (arr[last_n_i],
arr[last_e_i])
return arr
# Return original String if there is
# no even number
return arr
# Driver Code
string = input()
result = "".join(makeEven(list(string),
len(list(string))))
if(result==string):
print(-1)
else:
print(result)
# This code is contributed
# by Vikash Kumar 37
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself. | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 0 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,508,057,290 | 2,590 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | #!/usr/bin/env python3
from sys import stdin, stdout
def rint():
return map(int, stdin.readline().split())
#lines = stdin.readlines()
q = int(input())
for i in range(q):
n = int(input())
ans = n//4
res = n%4
if res == 1:
if ans >= 2:
ans -=1
else:
ans = -1
elif res == 2:
if ans >=1:
ans = ans
else:
ans = -1
elif res == 3:
if ans >= 2:
ans -= 1
else:
ans = -1
print(ans)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself.
Input Specification:
The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query.
Output Specification:
For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings.
Demo Input:
['1\n12\n', '2\n6\n8\n', '3\n1\n2\n3\n']
Demo Output:
['3\n', '1\n2\n', '-1\n-1\n-1\n']
Note:
12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | ```python
#!/usr/bin/env python3
from sys import stdin, stdout
def rint():
return map(int, stdin.readline().split())
#lines = stdin.readlines()
q = int(input())
for i in range(q):
n = int(input())
ans = n//4
res = n%4
if res == 1:
if ans >= 2:
ans -=1
else:
ans = -1
elif res == 2:
if ans >=1:
ans = ans
else:
ans = -1
elif res == 3:
if ans >= 2:
ans -= 1
else:
ans = -1
print(ans)
``` | 0 | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at some subject, if there is no student who got a higher mark for this subject. Let's consider a student successful, if there exists a subject he is the best at.
Your task is to find the number of successful students in the group. | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepatated by spaces. | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,645,695,383 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 30 | 0 | n , m = map(int,input().split())
a =[]
for i in range(n):
x = list(map(int,input()))
a.append(x)
b = []
for i in range(max(n,m)):
for j in range(min(n,m)):
b.append(a[j][i])
ans = []
for j in range(n):
for i in range(0,len(b),3):
if max(b[i:i+3]) == b[i:i+3][j]:
ans.append(j)
last=[]
for i in ans:
if i == 0:
last.append(0)
break
for i in ans:
if i == 1:
last.append(1)
break
for i in ans:
if i == 2:
last.append(2)
break
print(len(last)) | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at some subject, if there is no student who got a higher mark for this subject. Let's consider a student successful, if there exists a subject he is the best at.
Your task is to find the number of successful students in the group.
Input Specification:
The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepatated by spaces.
Output Specification:
Print the single number — the number of successful students in the given group.
Demo Input:
['3 3\n223\n232\n112\n', '3 5\n91728\n11828\n11111\n']
Demo Output:
['2\n', '3\n']
Note:
In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | ```python
n , m = map(int,input().split())
a =[]
for i in range(n):
x = list(map(int,input()))
a.append(x)
b = []
for i in range(max(n,m)):
for j in range(min(n,m)):
b.append(a[j][i])
ans = []
for j in range(n):
for i in range(0,len(b),3):
if max(b[i:i+3]) == b[i:i+3][j]:
ans.append(j)
last=[]
for i in ans:
if i == 0:
last.append(0)
break
for i in ans:
if i == 1:
last.append(1)
break
for i in ans:
if i == 2:
last.append(2)
break
print(len(last))
``` | -1 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part.
In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0.
Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length.
Now you are going to take part in Shapur's contest. See if you are faster and more accurate. | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,540,536,918 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n=input()
m=input()
n=int(n,2)
m=int(m,2)
k=n^m
if len(n)!=len(k):
for i in range(abs(len(k)-len(n))):
print(0,end="")
k=bin(k).replace("0b","")
print(k) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part.
In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0.
Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length.
Now you are going to take part in Shapur's contest. See if you are faster and more accurate.
Input Specification:
There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100.
Output Specification:
Write one line — the corresponding answer. Do not omit the leading 0s.
Demo Input:
['1010100\n0100101\n', '000\n111\n', '1110\n1010\n', '01110\n01100\n']
Demo Output:
['1110001\n', '111\n', '0100\n', '00010\n']
Note:
none | ```python
n=input()
m=input()
n=int(n,2)
m=int(m,2)
k=n^m
if len(n)!=len(k):
for i in range(abs(len(k)-len(n))):
print(0,end="")
k=bin(k).replace("0b","")
print(k)
``` | -1 |
464 | A | No to Palindromes! | PROGRAMMING | 1,700 | [
"greedy",
"strings"
] | null | null | Paul hates palindromes. He assumes that string *s* is tolerable if each its character is one of the first *p* letters of the English alphabet and *s* doesn't contain any palindrome contiguous substring of length 2 or more.
Paul has found a tolerable string *s* of length *n*. Help him find the lexicographically next tolerable string of the same length or else state that such string does not exist. | The first line contains two space-separated integers: *n* and *p* (1<=≤<=*n*<=≤<=1000; 1<=≤<=*p*<=≤<=26). The second line contains string *s*, consisting of *n* small English letters. It is guaranteed that the string is tolerable (according to the above definition). | If the lexicographically next tolerable string of the same length exists, print it. Otherwise, print "NO" (without the quotes). | [
"3 3\ncba\n",
"3 4\ncba\n",
"4 4\nabcd\n"
] | [
"NO\n",
"cbd\n",
"abda\n"
] | String *s* is lexicographically larger (or simply larger) than string *t* with the same length, if there is number *i*, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, ..., *s*<sub class="lower-index">*i*</sub> = *t*<sub class="lower-index">*i*</sub>, *s*<sub class="lower-index">*i* + 1</sub> > *t*<sub class="lower-index">*i* + 1</sub>.
The lexicographically next tolerable string is the lexicographically minimum tolerable string which is larger than the given one.
A palindrome is a string that reads the same forward or reversed. | 500 | [
{
"input": "3 3\ncba",
"output": "NO"
},
{
"input": "3 4\ncba",
"output": "cbd"
},
{
"input": "4 4\nabcd",
"output": "abda"
},
{
"input": "2 2\nab",
"output": "ba"
},
{
"input": "2 2\nba",
"output": "NO"
},
{
"input": "1 2\na",
"output": "b"
},
... | 1,411,846,683 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 62 | 0 | n, p = map(int, input().split())
def f(t, k):
a, b = min(t[k - 1], 2), min(t[k], 2)
if a == b: a = 1
return [3 - a - b, a, b]
def g(t, k):
j = t[k]
for i in range(j + 1, p):
if i != t[k - 1] and i != t[k - 2]:
t[k] = i
return f(t, k)
return None
def h(t):
t = [ord(c) - 97 for c in t] + [2, 2]
for k in range(n - 1, -1, -1):
s = g(t, k)
if s:
d = n - k - 1
t = t[: k + 1] + s * (d // 3) + s[: d % 3]
return ''.join(chr(i + 97) for i in t)
return 'NO'
t = input()
q = 'NO'
if p == 2:
if t == 'a': q = 'b'
elif t == 'ab': q = 'ba'
elif p > 2: q = h(t)
print(q) | Title: No to Palindromes!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Paul hates palindromes. He assumes that string *s* is tolerable if each its character is one of the first *p* letters of the English alphabet and *s* doesn't contain any palindrome contiguous substring of length 2 or more.
Paul has found a tolerable string *s* of length *n*. Help him find the lexicographically next tolerable string of the same length or else state that such string does not exist.
Input Specification:
The first line contains two space-separated integers: *n* and *p* (1<=≤<=*n*<=≤<=1000; 1<=≤<=*p*<=≤<=26). The second line contains string *s*, consisting of *n* small English letters. It is guaranteed that the string is tolerable (according to the above definition).
Output Specification:
If the lexicographically next tolerable string of the same length exists, print it. Otherwise, print "NO" (without the quotes).
Demo Input:
['3 3\ncba\n', '3 4\ncba\n', '4 4\nabcd\n']
Demo Output:
['NO\n', 'cbd\n', 'abda\n']
Note:
String *s* is lexicographically larger (or simply larger) than string *t* with the same length, if there is number *i*, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, ..., *s*<sub class="lower-index">*i*</sub> = *t*<sub class="lower-index">*i*</sub>, *s*<sub class="lower-index">*i* + 1</sub> > *t*<sub class="lower-index">*i* + 1</sub>.
The lexicographically next tolerable string is the lexicographically minimum tolerable string which is larger than the given one.
A palindrome is a string that reads the same forward or reversed. | ```python
n, p = map(int, input().split())
def f(t, k):
a, b = min(t[k - 1], 2), min(t[k], 2)
if a == b: a = 1
return [3 - a - b, a, b]
def g(t, k):
j = t[k]
for i in range(j + 1, p):
if i != t[k - 1] and i != t[k - 2]:
t[k] = i
return f(t, k)
return None
def h(t):
t = [ord(c) - 97 for c in t] + [2, 2]
for k in range(n - 1, -1, -1):
s = g(t, k)
if s:
d = n - k - 1
t = t[: k + 1] + s * (d // 3) + s[: d % 3]
return ''.join(chr(i + 97) for i in t)
return 'NO'
t = input()
q = 'NO'
if p == 2:
if t == 'a': q = 'b'
elif t == 'ab': q = 'ba'
elif p > 2: q = h(t)
print(q)
``` | 0 | |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the end of it are also considered to be fillers. For example, the words ogo, ogogo, ogogogo are fillers, but the words go, og, ogog, ogogog and oggo are not fillers.
The fillers have maximal size, for example, for ogogoo speech we can't consider ogo a filler and goo as a normal phrase. We should consider ogogo as a filler here.
To print the interview, Polycarp has to replace each of the fillers with three asterisks. Note that a filler word is replaced with exactly three asterisks regardless of its length.
Polycarp has dealt with this problem in no time. Can you do the same? The clock is ticking! | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,631,782,113 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 7,475,200 | import re
n = int(input())
s = input()
print(re.subn('ogo(go)*', '***', s)) | Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the end of it are also considered to be fillers. For example, the words ogo, ogogo, ogogogo are fillers, but the words go, og, ogog, ogogog and oggo are not fillers.
The fillers have maximal size, for example, for ogogoo speech we can't consider ogo a filler and goo as a normal phrase. We should consider ogogo as a filler here.
To print the interview, Polycarp has to replace each of the fillers with three asterisks. Note that a filler word is replaced with exactly three asterisks regardless of its length.
Polycarp has dealt with this problem in no time. Can you do the same? The clock is ticking!
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters.
Output Specification:
Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences.
Demo Input:
['7\naogogob\n', '13\nogogmgogogogo\n', '9\nogoogoogo\n']
Demo Output:
['a***b\n', '***gmg***\n', '*********\n']
Note:
The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | ```python
import re
n = int(input())
s = input()
print(re.subn('ogo(go)*', '***', s))
``` | 0 | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the strings only of length *p* or to the strings only of length *q* (see the second sample test). | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The string should be in order of their appearing in string *s* — from left to right.
If there are several solutions print any of them. | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,537,982,110 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 170 | 409,600 | import re
def splitText():
input1 = input().split()
n = int(input1[0])
p = int(input1[1])
q = int(input1[2])
string = input()
subPalabras = []
a = "." * p
b = "." * q
if n%p == 0:
subPalabras.extend(re.findall(a,string))
elif n%q == 0:
subPalabras.extend(re.findall(b,string))
else:
subPalabras.extend(re.findall(max(a,b) + "?",string))
lenTotal = 0
for i in range(0,len(subPalabras)):
lenTotal += len(subPalabras[i])
if(lenTotal != n):
print("-1")
return
for i in range(0,len(subPalabras)):
print(subPalabras[i])
splitText() | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the strings only of length *p* or to the strings only of length *q* (see the second sample test).
Input Specification:
The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits.
Output Specification:
If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The string should be in order of their appearing in string *s* — from left to right.
If there are several solutions print any of them.
Demo Input:
['5 2 3\nHello\n', '10 9 5\nCodeforces\n', '6 4 5\nPrivet\n', '8 1 1\nabacabac\n']
Demo Output:
['2\nHe\nllo\n', '2\nCodef\norces\n', '-1\n', '8\na\nb\na\nc\na\nb\na\nc\n']
Note:
none | ```python
import re
def splitText():
input1 = input().split()
n = int(input1[0])
p = int(input1[1])
q = int(input1[2])
string = input()
subPalabras = []
a = "." * p
b = "." * q
if n%p == 0:
subPalabras.extend(re.findall(a,string))
elif n%q == 0:
subPalabras.extend(re.findall(b,string))
else:
subPalabras.extend(re.findall(max(a,b) + "?",string))
lenTotal = 0
for i in range(0,len(subPalabras)):
lenTotal += len(subPalabras[i])
if(lenTotal != n):
print("-1")
return
for i in range(0,len(subPalabras)):
print(subPalabras[i])
splitText()
``` | 0 | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true. | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards. | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,651,050,612 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | a = input()
ans = 0
for i in range(0 , len(a)):
if a[i] == 'a' or a[i] == 'e' or a[i] == 'y' or a[i] == 'i' or a[i] == 'o' or a[i] == 'u':
ans += 1
print(ans) | Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a card has a vowel on one side, then it has an even digit on the other side." More specifically, a vowel is one of 'a', 'e', 'i', 'o' or 'u', and even digit is one of '0', '2', '4', '6' or '8'.
For example, if a card has 'a' on one side, and '6' on the other side, then this statement is true for it. Also, the statement is true, for example, for a card with 'b' and '4', and for a card with 'b' and '3' (since the letter is not a vowel). The statement is false, for example, for card with 'e' and '5'. You are interested if the statement is true for all cards. In particular, if no card has a vowel, the statement is true.
To determine this, you can flip over some cards to reveal the other side. You would like to know what is the minimum number of cards you need to flip in the worst case in order to verify that the statement is true.
Input Specification:
The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit.
Output Specification:
Print a single integer, the minimum number of cards you must turn over to verify your claim.
Demo Input:
['ee\n', 'z\n', '0ay1\n']
Demo Output:
['2\n', '0\n', '2\n']
Note:
In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on them.
In the third sample, we need to flip the second and fourth cards. | ```python
a = input()
ans = 0
for i in range(0 , len(a)):
if a[i] == 'a' or a[i] == 'e' or a[i] == 'y' or a[i] == 'i' or a[i] == 'o' or a[i] == 'u':
ans += 1
print(ans)
``` | 0 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,640,942,320 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 77 | 0 | n=int(int(input()))
lis=list(map(int,input().split()))
lis1=sorted(lis)[::-1]
lis2=[]
for i in range(len(lis1)):
lis2.append(lis1.index(lis[i])+1)
print(*lis2)
| Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*).
Output Specification:
In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input.
Demo Input:
['3\n1 3 3\n', '1\n1\n', '5\n3 5 3 4 5\n']
Demo Output:
['3 1 1\n', '1\n', '4 1 4 3 1\n']
Note:
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | ```python
n=int(int(input()))
lis=list(map(int,input().split()))
lis1=sorted(lis)[::-1]
lis2=[]
for i in range(len(lis1)):
lis2.append(lis1.index(lis[i])+1)
print(*lis2)
``` | 3 | |
343 | B | Alternating Current | PROGRAMMING | 1,600 | [
"data structures",
"greedy",
"implementation"
] | null | null | Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended up entangled and now have to be untangled again.
The device is powered by two wires "plus" and "minus". The wires run along the floor from the wall (on the left) to the device (on the right). Both the wall and the device have two contacts in them on the same level, into which the wires are plugged in some order. The wires are considered entangled if there are one or more places where one wire runs above the other one. For example, the picture below has four such places (top view):
Mike knows the sequence in which the wires run above each other. Mike also noticed that on the left side, the "plus" wire is always plugged into the top contact (as seen on the picture). He would like to untangle the wires without unplugging them and without moving the device. Determine if it is possible to do that. A wire can be freely moved and stretched on the floor, but cannot be cut.
To understand the problem better please read the notes to the test samples. | The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise. | Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled. | [
"-++-\n",
"+-\n",
"++\n",
"-\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"No\n"
] | The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full revolution around the "minus" wire. Thus the wires cannot be untangled:
In the third testcase the "plus" wire simply runs above the "minus" wire twice in sequence. The wires can be untangled by lifting "plus" and moving it higher:
In the fourth testcase the "minus" wire runs above the "plus" wire once. The wires cannot be untangled without moving the device itself: | 1,000 | [
{
"input": "-++-",
"output": "Yes"
},
{
"input": "+-",
"output": "No"
},
{
"input": "++",
"output": "Yes"
},
{
"input": "-",
"output": "No"
},
{
"input": "+-+-",
"output": "No"
},
{
"input": "-+-",
"output": "No"
},
{
"input": "-++-+--+",
... | 1,643,348,934 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | s=input('enter a string')
stack=[]
top=-1
for i in s:
if top==-1:
stack.append(i)
top+=1
else:
if i==stack[top]:
stack.pop()
top-=1
else:
stack.append(i)
top+=1
if top==-1:
print('Yes')
else:
print('No') | Title: Alternating Current
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended up entangled and now have to be untangled again.
The device is powered by two wires "plus" and "minus". The wires run along the floor from the wall (on the left) to the device (on the right). Both the wall and the device have two contacts in them on the same level, into which the wires are plugged in some order. The wires are considered entangled if there are one or more places where one wire runs above the other one. For example, the picture below has four such places (top view):
Mike knows the sequence in which the wires run above each other. Mike also noticed that on the left side, the "plus" wire is always plugged into the top contact (as seen on the picture). He would like to untangle the wires without unplugging them and without moving the device. Determine if it is possible to do that. A wire can be freely moved and stretched on the floor, but cannot be cut.
To understand the problem better please read the notes to the test samples.
Input Specification:
The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise.
Output Specification:
Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled.
Demo Input:
['-++-\n', '+-\n', '++\n', '-\n']
Demo Output:
['Yes\n', 'No\n', 'Yes\n', 'No\n']
Note:
The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full revolution around the "minus" wire. Thus the wires cannot be untangled:
In the third testcase the "plus" wire simply runs above the "minus" wire twice in sequence. The wires can be untangled by lifting "plus" and moving it higher:
In the fourth testcase the "minus" wire runs above the "plus" wire once. The wires cannot be untangled without moving the device itself: | ```python
s=input('enter a string')
stack=[]
top=-1
for i in s:
if top==-1:
stack.append(i)
top+=1
else:
if i==stack[top]:
stack.pop()
top-=1
else:
stack.append(i)
top+=1
if top==-1:
print('Yes')
else:
print('No')
``` | 0 | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents. | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,583,524,161 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 307,200 | n = int(input())
snack_sizes = [int(c) for c in input().split(" ")]
saved = [0] * n
s = 0
for i in snack_sizes:
if (not s):
s = i
saved[i-1] = i
if (not 0 in saved[s-1:n]):
tower_built = saved[s-1:n][::-1]
saved = saved[0:s-1]
s = 0
print(*tower_built)
else:
print()
| Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents.
Input Specification:
The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*.
Output Specification:
Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty.
Demo Input:
['3\n3 1 2\n', '5\n4 5 1 2 3\n']
Demo Output:
['3\n\xa0\n2 1', '5 4\n\xa0\n\xa0\n3 2 1\n']
Note:
In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | ```python
n = int(input())
snack_sizes = [int(c) for c in input().split(" ")]
saved = [0] * n
s = 0
for i in snack_sizes:
if (not s):
s = i
saved[i-1] = i
if (not 0 in saved[s-1:n]):
tower_built = saved[s-1:n][::-1]
saved = saved[0:s-1]
s = 0
print(*tower_built)
else:
print()
``` | 0 | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality).
All *a**i* are distinct. All *b**i* are distinct. | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,686,997,517 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 124 | 0 | for _ in range(int(input())):
i,j=input().split()
if i!=j:
print('Happy Alex')
exit()
print('Poor Alex')
| Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality).
All *a**i* are distinct. All *b**i* are distinct.
Output Specification:
If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).
Demo Input:
['2\n1 2\n2 1\n']
Demo Output:
['Happy Alex\n']
Note:
none | ```python
for _ in range(int(input())):
i,j=input().split()
if i!=j:
print('Happy Alex')
exit()
print('Poor Alex')
``` | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,662,271,407 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n=int(input())
l=[]
c=0
for i in range(n):
b=list(map(int,input().split()))
l.append(b)
for i in range(len(l)):
sum=0
for j in range(len(l)):
sum+=l[j][i]
if(sum==0):
c+=1;
if(c==n):
print("YES")
else:
print("N0") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n=int(input())
l=[]
c=0
for i in range(n):
b=list(map(int,input().split()))
l.append(b)
for i in range(len(l)):
sum=0
for j in range(len(l)):
sum+=l[j][i]
if(sum==0):
c+=1;
if(c==n):
print("YES")
else:
print("N0")
``` | 0 |
631 | A | Interview | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x**l*,<=*x**l*<=+<=1,<=...,<=*x**r*, where *x**i* is the *i*-th element of the array *x*. You are given two arrays *a* and *b* of length *n*. You need to determine the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109). | Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | [
"5\n1 2 4 3 2\n2 3 3 12 1\n",
"10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n"
] | [
"22",
"46"
] | Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *f*(*a*, 2, 4) + *f*(*b*, 2, 4) = (2 *OR* 4 *OR* 3) + (3 *OR* 3 *OR* 12) = 7 + 15 = 22. Other ways to get maximum value is to choose *l* = 1 and *r* = 4, *l* = 1 and *r* = 5, *l* = 2 and *r* = 4, *l* = 2 and *r* = 5, *l* = 3 and *r* = 4, or *l* = 3 and *r* = 5.
In the second sample, the maximum value is obtained for *l* = 1 and *r* = 9. | 500 | [
{
"input": "5\n1 2 4 3 2\n2 3 3 12 1",
"output": "22"
},
{
"input": "10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6",
"output": "46"
},
{
"input": "25\n12 30 38 109 81 124 80 33 38 48 29 78 96 48 96 27 80 77 102 65 80 113 31 118 35\n25 64 95 13 12 6 111 80 85 16 61 119 23 65 73 65 20 9... | 1,457,249,266 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 156 | 1,024,000 | import sys
# sys.stdin = open("ivo.in")
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
ans = 0
for beg in range(len(a)):
max1 = 0
max2 = 0
cur1 = 0
cur2 = 0
for e in range(beg, len(a)):
cur1 |= a[e]
cur2 |= b[e]
if cur1 + cur2 > max1 + max2:
max1 = cur1
max2 = cur2
ans = max([ans, max1 + max2])
print(ans) | Title: Interview
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x**l*,<=*x**l*<=+<=1,<=...,<=*x**r*, where *x**i* is the *i*-th element of the array *x*. You are given two arrays *a* and *b* of length *n*. You need to determine the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109).
Output Specification:
Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*.
Demo Input:
['5\n1 2 4 3 2\n2 3 3 12 1\n', '10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n']
Demo Output:
['22', '46']
Note:
Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *f*(*a*, 2, 4) + *f*(*b*, 2, 4) = (2 *OR* 4 *OR* 3) + (3 *OR* 3 *OR* 12) = 7 + 15 = 22. Other ways to get maximum value is to choose *l* = 1 and *r* = 4, *l* = 1 and *r* = 5, *l* = 2 and *r* = 4, *l* = 2 and *r* = 5, *l* = 3 and *r* = 4, or *l* = 3 and *r* = 5.
In the second sample, the maximum value is obtained for *l* = 1 and *r* = 9. | ```python
import sys
# sys.stdin = open("ivo.in")
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
ans = 0
for beg in range(len(a)):
max1 = 0
max2 = 0
cur1 = 0
cur2 = 0
for e in range(beg, len(a)):
cur1 |= a[e]
cur2 |= b[e]
if cur1 + cur2 > max1 + max2:
max1 = cur1
max2 = cur2
ans = max([ans, max1 + max2])
print(ans)
``` | 3 | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue. | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,695,182,777 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | strr = input()
count = 0
for i in range(1,len(strr)):
if strr[i-1] == strr[i]:
count += 1
print(count) | Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['3\nRRG\n', '5\nRRRRR\n', '4\nBRBG\n']
Demo Output:
['1\n', '4\n', '0\n']
Note:
none | ```python
strr = input()
count = 0
for i in range(1,len(strr)):
if strr[i-1] == strr[i]:
count += 1
print(count)
``` | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,681,148,005 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | '''
m, n = map(int, input().split())
s = m * n
print(s//2)
'''
m, n = map(int, input().split())
ans = (n // 2) * m
if n % 2 == 1:
if m >= 2:
ans += m // 2
print(ans)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
'''
m, n = map(int, input().split())
s = m * n
print(s//2)
'''
m, n = map(int, input().split())
ans = (n // 2) * m
if n % 2 == 1:
if m >= 2:
ans += m // 2
print(ans)
``` | 3.977 |
934 | B | A Prosperous Lot | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount of money to give out. He considers loops to be lucky since it symbolizes unity and harmony.
He would like to find a positive integer *n* not greater than 1018, such that there are exactly *k* loops in the decimal representation of *n*, or determine that such *n* does not exist.
A loop is a planar area enclosed by lines in the digits' decimal representation written in Arabic numerals. For example, there is one loop in digit 4, two loops in 8 and no loops in 5. Refer to the figure below for all exact forms. | The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops. | Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018. | [
"2\n",
"6\n"
] | [
"462",
"8080"
] | none | 1,000 | [
{
"input": "2",
"output": "8"
},
{
"input": "6",
"output": "888"
},
{
"input": "3",
"output": "86"
},
{
"input": "4",
"output": "88"
},
{
"input": "5",
"output": "886"
},
{
"input": "1000000",
"output": "-1"
},
{
"input": "1",
"output":... | 1,518,676,251 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 62 | 5,632,000 | k = int(input())
print(-1 if k > 36 else k // 2 * '8' + k % 2 * '4')
| Title: A Prosperous Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount of money to give out. He considers loops to be lucky since it symbolizes unity and harmony.
He would like to find a positive integer *n* not greater than 1018, such that there are exactly *k* loops in the decimal representation of *n*, or determine that such *n* does not exist.
A loop is a planar area enclosed by lines in the digits' decimal representation written in Arabic numerals. For example, there is one loop in digit 4, two loops in 8 and no loops in 5. Refer to the figure below for all exact forms.
Input Specification:
The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops.
Output Specification:
Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018.
Demo Input:
['2\n', '6\n']
Demo Output:
['462', '8080']
Note:
none | ```python
k = int(input())
print(-1 if k > 36 else k // 2 * '8' + k % 2 * '4')
``` | 3 | |
381 | A | Sereja and Dima | PROGRAMMING | 800 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. | On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. | [
"4\n4 1 2 10\n",
"7\n1 2 3 4 5 6 7\n"
] | [
"12 5\n",
"16 12\n"
] | In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | 500 | [
{
"input": "4\n4 1 2 10",
"output": "12 5"
},
{
"input": "7\n1 2 3 4 5 6 7",
"output": "16 12"
},
{
"input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13",
"output": "613 418"
},
{
"input": "43\n32 ... | 1,691,864,261 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n = int(input())
cards = list(map(int, input().split()))
sereja_score = 0
dima_score = 0
turn = True
left = 0
right = n - 1
for _ in range(n):
if turn:
sereja_score += max(cards[left], cards[right])
else:
dima_score += max(cards[left], cards[right])
if cards[left] > cards[right]:
left += 1
else:
right -= 1
turn = not turn
print(sereja_score, dima_score)
| Title: Sereja and Dima
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.
Output Specification:
On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.
Demo Input:
['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n']
Demo Output:
['12 5\n', '16 12\n']
Note:
In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | ```python
n = int(input())
cards = list(map(int, input().split()))
sereja_score = 0
dima_score = 0
turn = True
left = 0
right = n - 1
for _ in range(n):
if turn:
sereja_score += max(cards[left], cards[right])
else:
dima_score += max(cards[left], cards[right])
if cards[left] > cards[right]:
left += 1
else:
right -= 1
turn = not turn
print(sereja_score, dima_score)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,558,536,861 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | s=input()
f=int(0)
for i in range(0,len(s)):
if(s[i]=='h'):
for j in range(i+1,len(s)):
if(s[j]=='e'):
for k in range(j+1,len(s)):
if(s[k]=='l'):
for l in range(k+1,len(s)):
if(s[l]=='l'):
for o in range(l+1,len(s)):
if(s[o]=='o'):
print("YES")
f=0
break
else:
f=1
if(f==0):
break
if(f==0):
break
if(f==0):
break
if(f==0):
break
if(f!=0):
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
s=input()
f=int(0)
for i in range(0,len(s)):
if(s[i]=='h'):
for j in range(i+1,len(s)):
if(s[j]=='e'):
for k in range(j+1,len(s)):
if(s[k]=='l'):
for l in range(k+1,len(s)):
if(s[l]=='l'):
for o in range(l+1,len(s)):
if(s[o]=='o'):
print("YES")
f=0
break
else:
f=1
if(f==0):
break
if(f==0):
break
if(f==0):
break
if(f==0):
break
if(f!=0):
print("NO")
``` | 0 |
84 | A | Toy Army | PROGRAMMING | 900 | [
"math",
"number theory"
] | A. Toy Army | 2 | 256 | The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of *n* men (*n* is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game. | The input data consist of a single integer *n* (2<=≤<=*n*<=≤<=108, *n* is even). Please note that before the game starts there are 2*n* soldiers on the fields. | Print a single number — a maximum total number of soldiers that could be killed in the course of the game in three turns. | [
"2\n",
"4\n"
] | [
"3\n",
"6\n"
] | The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | 500 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "6"
},
{
"input": "6",
"output": "9"
},
{
"input": "8",
"output": "12"
},
{
"input": "10",
"output": "15"
},
{
"input": "140",
"output": "210"
},
{
"input": "500",
"output": "75... | 1,380,262,023 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | #!/usr/bin/python3
def readln(): return tuple(map(int, input().split()))
n, = readln()
print(n * 3 // 2)
| Title: Toy Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of *n* men (*n* is always even). The current player specifies for each of her soldiers an enemy's soldier he will shoot (a target) and then all the player's soldiers shot simultaneously. This is a game world, and so each soldier shoots perfectly, that is he absolutely always hits the specified target. If an enemy soldier is hit, he will surely die. It may happen that several soldiers had been indicated the same target. Killed soldiers do not participate in the game anymore.
The game "GAGA" consists of three steps: first Valera makes a move, then Arcady, then Valera again and the game ends.
You are asked to calculate the maximum total number of soldiers that may be killed during the game.
Input Specification:
The input data consist of a single integer *n* (2<=≤<=*n*<=≤<=108, *n* is even). Please note that before the game starts there are 2*n* soldiers on the fields.
Output Specification:
Print a single number — a maximum total number of soldiers that could be killed in the course of the game in three turns.
Demo Input:
['2\n', '4\n']
Demo Output:
['3\n', '6\n']
Note:
The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | ```python
#!/usr/bin/python3
def readln(): return tuple(map(int, input().split()))
n, = readln()
print(n * 3 // 2)
``` | 3.977 |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimum unfortunate sum? | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,615,023,885 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 311 | 51,814,400 | def uloz_z_liczb(m, s):
n = len(m)
po = [[0 for _ in range(s+1)] for _ in range(n)]
po[0][m[0]] = 1
for i in range(0, s+1, m[0]):
if i == 0:
continue
po[0][i] = po[0][i-m[0]] + 1
min_ = 1234567890
if po[0][s] > 0:
min_ = po[0][s]
for i in range(1, n):
for j in range(0, m[i]):
po[i][j] = po[i-1][j]
if m[i] <= s:
po[i][m[i]] = 1
for j in range(m[i]+1, s+1):
min__ = 0
if po[i][j-m[i]] > 0:
min__ = po[i][j-m[i]]+1
if po[i-1][j] > 0:
if min__ == 0 or po[i-1][j] < min__:
min__ = po[i-1][j]
po[i][j] = min__
for i in range(1,s+1):
if po[n-1][i] == 0:
return i
return -1
n = int(input())
tab = input().split(" ")
for i in range(n):
tab[i] = int(tab[i])
print(uloz_z_liczb(tab,tab[-1]))
| Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimum unfortunate sum?
Input Specification:
The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes.
Output Specification:
Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1.
Demo Input:
['5\n1 2 3 4 5\n']
Demo Output:
['-1\n']
Note:
none | ```python
def uloz_z_liczb(m, s):
n = len(m)
po = [[0 for _ in range(s+1)] for _ in range(n)]
po[0][m[0]] = 1
for i in range(0, s+1, m[0]):
if i == 0:
continue
po[0][i] = po[0][i-m[0]] + 1
min_ = 1234567890
if po[0][s] > 0:
min_ = po[0][s]
for i in range(1, n):
for j in range(0, m[i]):
po[i][j] = po[i-1][j]
if m[i] <= s:
po[i][m[i]] = 1
for j in range(m[i]+1, s+1):
min__ = 0
if po[i][j-m[i]] > 0:
min__ = po[i][j-m[i]]+1
if po[i-1][j] > 0:
if min__ == 0 or po[i-1][j] < min__:
min__ = po[i-1][j]
po[i][j] = min__
for i in range(1,s+1):
if po[n-1][i] == 0:
return i
return -1
n = int(input())
tab = input().split(" ")
for i in range(n):
tab[i] = int(tab[i])
print(uloz_z_liczb(tab,tab[-1]))
``` | -1 | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such that positions with indexes *i* and *i*<=+<=1 contain children of different genders (position *i* has a girl and position *i*<=+<=1 has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line. | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multiple optimal solutions, print any of them. | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,616,528,823 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 204,800 | n, m = map(int, input().split())
ans=[]
t = n + m
if n > m:
for i in range(0, t):
if (0 + i)%2 == 0 or (1+i)//2>m: ans.append('B')
elif (1 + i)//2 <= m: ans.append('G')
else:
for i in range(0, t):
if (0 + i)%2 == 0 or (1+i)//2 > n: ans.append('G')
elif (1 + i)//2 <= n: ans.append('B')
print(''.join(ans))
| Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such that positions with indexes *i* and *i*<=+<=1 contain children of different genders (position *i* has a girl and position *i*<=+<=1 has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line.
Input Specification:
The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multiple optimal solutions, print any of them.
Demo Input:
['3 3\n', '4 2\n']
Demo Output:
['GBGBGB\n', 'BGBGBB\n']
Note:
In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | ```python
n, m = map(int, input().split())
ans=[]
t = n + m
if n > m:
for i in range(0, t):
if (0 + i)%2 == 0 or (1+i)//2>m: ans.append('B')
elif (1 + i)//2 <= m: ans.append('G')
else:
for i in range(0, t):
if (0 + i)%2 == 0 or (1+i)//2 > n: ans.append('G')
elif (1 + i)//2 <= n: ans.append('B')
print(''.join(ans))
``` | -1 | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem. | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,549,880,026 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 187 | 307,200 | n=int(input())
x,y=[],[]
if n==3:
print(1,2)
exit()
if n==4:
print(1,3)
exit()
for i in range(1,1001):
for j in range(1,1001):
if i%j==0:
x.append(i//j)
y.append(x)
x=[]
for i in range(len(y)):
if len(y[i])==2:
x.append(y[i][0])
for i in range(len(x)-1,-1,-1):
if x[i]<n:
print(n-x[i-1],x[i-1])
break
| Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem.
Input Specification:
In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction.
Output Specification:
Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum.
Demo Input:
['3\n', '4\n', '12\n']
Demo Output:
['1 2\n', '1 3\n', '5 7\n']
Note:
none | ```python
n=int(input())
x,y=[],[]
if n==3:
print(1,2)
exit()
if n==4:
print(1,3)
exit()
for i in range(1,1001):
for j in range(1,1001):
if i%j==0:
x.append(i//j)
y.append(x)
x=[]
for i in range(len(y)):
if len(y[i])==2:
x.append(y[i][0])
for i in range(len(x)-1,-1,-1):
if x[i]<n:
print(n-x[i-1],x[i-1])
break
``` | 0 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.
Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book. | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero. | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second sample:
On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book. | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,697,457,732 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n = int(input())
time = input().split()
time = list(map(lambda x: int(x), time))
counter = 0
while n >= 0:
n -= time[counter]
counter = (counter + 1) % 7
print(counter) | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.
Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book.
Input Specification:
The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero.
Output Specification:
Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Demo Input:
['100\n15 20 20 15 10 30 45\n', '2\n1 0 0 0 0 0 0\n']
Demo Output:
['6\n', '1\n']
Note:
Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second sample:
On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book. | ```python
n = int(input())
time = input().split()
time = list(map(lambda x: int(x), time))
counter = 0
while n >= 0:
n -= time[counter]
counter = (counter + 1) % 7
print(counter)
``` | 0 | |
755 | B | PolandBall and Game | PROGRAMMING | 1,100 | [
"binary search",
"data structures",
"games",
"greedy",
"sortings",
"strings"
] | null | null | PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You're given two lists of words familiar to PolandBall and EnemyBall. Can you determine who wins the game, if both play optimally? | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=103) — number of words PolandBall and EnemyBall know, respectively.
Then *n* strings follow, one per line — words familiar to PolandBall.
Then *m* strings follow, one per line — words familiar to EnemyBall.
Note that one Ball cannot know a word more than once (strings are unique), but some words can be known by both players.
Each word is non-empty and consists of no more than 500 lowercase English alphabet letters. | In a single line of print the answer — "YES" if PolandBall wins and "NO" otherwise. Both Balls play optimally. | [
"5 1\npolandball\nis\na\ncool\ncharacter\nnope\n",
"2 2\nkremowka\nwadowicka\nkremowka\nwiedenska\n",
"1 2\na\na\nb\n"
] | [
"YES",
"YES",
"NO"
] | In the first example PolandBall knows much more words and wins effortlessly.
In the second example if PolandBall says kremowka first, then EnemyBall cannot use that word anymore. EnemyBall can only say wiedenska. PolandBall says wadowicka and wins. | 1,000 | [
{
"input": "5 1\npolandball\nis\na\ncool\ncharacter\nnope",
"output": "YES"
},
{
"input": "2 2\nkremowka\nwadowicka\nkremowka\nwiedenska",
"output": "YES"
},
{
"input": "1 2\na\na\nb",
"output": "NO"
},
{
"input": "2 2\na\nb\nb\nc",
"output": "YES"
},
{
"input": "... | 1,625,497,384 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n, m = map(int, input().split())
poland = 0
enemy = 0
pknown = set()
eknown = set()
for i in range(n):
pknown.add(input())
poland += len(pknown)
for i in range(m):
enemy_word = input()
if enemy_word not in eknown:
eknown.add(enemy_word)
if enemy_word in pknown:
poland -= 1
else:
enemy += 1
print("YES" if poland >= enemy else "NO")
| Title: PolandBall and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You're given two lists of words familiar to PolandBall and EnemyBall. Can you determine who wins the game, if both play optimally?
Input Specification:
The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=103) — number of words PolandBall and EnemyBall know, respectively.
Then *n* strings follow, one per line — words familiar to PolandBall.
Then *m* strings follow, one per line — words familiar to EnemyBall.
Note that one Ball cannot know a word more than once (strings are unique), but some words can be known by both players.
Each word is non-empty and consists of no more than 500 lowercase English alphabet letters.
Output Specification:
In a single line of print the answer — "YES" if PolandBall wins and "NO" otherwise. Both Balls play optimally.
Demo Input:
['5 1\npolandball\nis\na\ncool\ncharacter\nnope\n', '2 2\nkremowka\nwadowicka\nkremowka\nwiedenska\n', '1 2\na\na\nb\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
In the first example PolandBall knows much more words and wins effortlessly.
In the second example if PolandBall says kremowka first, then EnemyBall cannot use that word anymore. EnemyBall can only say wiedenska. PolandBall says wadowicka and wins. | ```python
n, m = map(int, input().split())
poland = 0
enemy = 0
pknown = set()
eknown = set()
for i in range(n):
pknown.add(input())
poland += len(pknown)
for i in range(m):
enemy_word = input()
if enemy_word not in eknown:
eknown.add(enemy_word)
if enemy_word in pknown:
poland -= 1
else:
enemy += 1
print("YES" if poland >= enemy else "NO")
``` | 0 | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
- Four sticks represent the animal's legs, these sticks should have the same length. - Two remaining sticks represent the animal's head and body. The bear's head stick must be shorter than the body stick. The elephant, however, has a long trunk, so his head stick must be as long as the body stick. Note that there are no limits on the relations between the leg sticks and the head and body sticks.
Your task is to find out which animal can be made from the given stick set. The zoo keeper wants the sticks back after the game, so they must never be broken, even bears understand it. | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,593,518,700 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 139 | 20,172,800 | l=list(map(int,input().split()))
s=list(set(l))
t=len(s)
if t==1:
print('Elephant')
elif t==2:
if (l.count(s[0])==4 or l.count(s[1])==4):
print('Elephant')
else:
print('Alien')
elif t==3:
if (l.count(s[0])==4 or l.count(s[1])==4 or l.count(s[2])==4):
print('Bear')
else:
print('Alien')
else:
print('Alien') | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
- Four sticks represent the animal's legs, these sticks should have the same length. - Two remaining sticks represent the animal's head and body. The bear's head stick must be shorter than the body stick. The elephant, however, has a long trunk, so his head stick must be as long as the body stick. Note that there are no limits on the relations between the leg sticks and the head and body sticks.
Your task is to find out which animal can be made from the given stick set. The zoo keeper wants the sticks back after the game, so they must never be broken, even bears understand it.
Input Specification:
The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks.
Output Specification:
If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes).
Demo Input:
['4 2 5 4 4 4\n', '4 4 5 4 4 5\n', '1 2 3 4 5 6\n']
Demo Output:
['Bear', 'Elephant', 'Alien']
Note:
If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | ```python
l=list(map(int,input().split()))
s=list(set(l))
t=len(s)
if t==1:
print('Elephant')
elif t==2:
if (l.count(s[0])==4 or l.count(s[1])==4):
print('Elephant')
else:
print('Alien')
elif t==3:
if (l.count(s[0])==4 or l.count(s[1])==4 or l.count(s[2])==4):
print('Bear')
else:
print('Alien')
else:
print('Alien')
``` | 0 | |
305 | B | Continued Fractions | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | A continued fraction of height *n* is a fraction of form . You are given two rational numbers, one is represented as and the other one is represented as a finite fraction of height *n*. Check if they are equal. | The first line contains two space-separated integers *p*,<=*q* (1<=≤<=*q*<=≤<=*p*<=≤<=1018) — the numerator and the denominator of the first fraction.
The second line contains integer *n* (1<=≤<=*n*<=≤<=90) — the height of the second fraction. The third line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018) — the continued fraction.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print "YES" if these fractions are equal and "NO" otherwise. | [
"9 4\n2\n2 4\n",
"9 4\n3\n2 3 1\n",
"9 4\n3\n1 2 4\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/5ff92f27aebea2560d99ad61202d20bab5ee5390.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/221368c79c05fc0ecad4e5f7a64f30b832fd99f5.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4fb4b411afc0fbad27a1c8fdd08ba88ec3830ef5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 1,000 | [
{
"input": "9 4\n2\n2 4",
"output": "YES"
},
{
"input": "9 4\n3\n2 3 1",
"output": "YES"
},
{
"input": "9 4\n3\n1 2 4",
"output": "NO"
},
{
"input": "39088169 24157817\n36\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2",
"output": "YES"
},
{
... | 1,369,042,340 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 62 | 102,400 | def gcd (x, y):
while (x > 0) and (y > 0):
if (x > y):
x %= y
else:
y %= x
return x + y
p, q = map(int, input().split())
n = int (input ())
a = list (map (int, input ().split ()))
p1 = 1
q1 = a[n - 1]
for i in range(n - 2, -1, -1):
p1 += a[i] * q1
if (i != 0):
z = p1
p1 = q1
q1 = z
g = gcd (p, q)
if (g != 0):
p /= g
q /= g
g = gcd (p1, q1)
if (g != 0):
p1 /= g
q1 /= g
if (p == p1) and (q == q1):
print ("YES")
else:
print ("NO") | Title: Continued Fractions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A continued fraction of height *n* is a fraction of form . You are given two rational numbers, one is represented as and the other one is represented as a finite fraction of height *n*. Check if they are equal.
Input Specification:
The first line contains two space-separated integers *p*,<=*q* (1<=≤<=*q*<=≤<=*p*<=≤<=1018) — the numerator and the denominator of the first fraction.
The second line contains integer *n* (1<=≤<=*n*<=≤<=90) — the height of the second fraction. The third line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018) — the continued fraction.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print "YES" if these fractions are equal and "NO" otherwise.
Demo Input:
['9 4\n2\n2 4\n', '9 4\n3\n2 3 1\n', '9 4\n3\n1 2 4\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/5ff92f27aebea2560d99ad61202d20bab5ee5390.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/221368c79c05fc0ecad4e5f7a64f30b832fd99f5.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4fb4b411afc0fbad27a1c8fdd08ba88ec3830ef5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | ```python
def gcd (x, y):
while (x > 0) and (y > 0):
if (x > y):
x %= y
else:
y %= x
return x + y
p, q = map(int, input().split())
n = int (input ())
a = list (map (int, input ().split ()))
p1 = 1
q1 = a[n - 1]
for i in range(n - 2, -1, -1):
p1 += a[i] * q1
if (i != 0):
z = p1
p1 = q1
q1 = z
g = gcd (p, q)
if (g != 0):
p /= g
q /= g
g = gcd (p1, q1)
if (g != 0):
p1 /= g
q1 /= g
if (p == p1) and (q == q1):
print ("YES")
else:
print ("NO")
``` | 0 | |
622 | B | The Time | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock). | The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed. | The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format. | [
"23:59\n10\n",
"20:20\n121\n",
"10:10\n0\n"
] | [
"00:09\n",
"22:21\n",
"10:10\n"
] | none | 0 | [
{
"input": "23:59\n10",
"output": "00:09"
},
{
"input": "20:20\n121",
"output": "22:21"
},
{
"input": "10:10\n0",
"output": "10:10"
},
{
"input": "12:34\n10000",
"output": "11:14"
},
{
"input": "00:00\n10000",
"output": "22:40"
},
{
"input": "00:00\n14... | 1,606,436,238 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 109 | 0 | # https://codeforces.com/problemset/problem/622/B
# 900
hh,mm = map(int, input().split(":"))
a = int(input())
h = int(a / 60)
m = a % 60
mm += m
if mm > 59:
mm = mm % 60
h += 1
hh += h
if hh > 23:
hh = hh % 24
print(f"{hh:02}:{mm:02}") | Title: The Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock).
Input Specification:
The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed.
Output Specification:
The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Demo Input:
['23:59\n10\n', '20:20\n121\n', '10:10\n0\n']
Demo Output:
['00:09\n', '22:21\n', '10:10\n']
Note:
none | ```python
# https://codeforces.com/problemset/problem/622/B
# 900
hh,mm = map(int, input().split(":"))
a = int(input())
h = int(a / 60)
m = a % 60
mm += m
if mm > 59:
mm = mm % 60
h += 1
hh += h
if hh > 23:
hh = hh % 24
print(f"{hh:02}:{mm:02}")
``` | 3 | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercises: "chest" exercises, "biceps" exercises and "back" exercises. Besides, his training is cyclic, that is, the first exercise he does is a "chest" one, the second one is "biceps", the third one is "back", the fourth one is "chest", the fifth one is "biceps", and so on to the *n*-th exercise.
Now Greg wonders, which muscle will get the most exercise during his training. We know that the exercise Greg repeats the maximum number of times, trains the corresponding muscle the most. Help Greg, determine which muscle will get the most training. | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the most exercise. | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,616,947,618 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 204,800 | n = int(input())
arr = list(map(int, input().split()))
ans = [0,0,0]
c = 0
for i in range(n):
if c == 0:
ans[c] += arr[i]
elif c == 1:
ans[c] += arr[i]
else:
ans[c] += arr[i]
c = -1
c += 1
p = ['chest', 'biseps', 'back']
print(p[ans.index(max(ans))]) | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercises: "chest" exercises, "biceps" exercises and "back" exercises. Besides, his training is cyclic, that is, the first exercise he does is a "chest" one, the second one is "biceps", the third one is "back", the fourth one is "chest", the fifth one is "biceps", and so on to the *n*-th exercise.
Now Greg wonders, which muscle will get the most exercise during his training. We know that the exercise Greg repeats the maximum number of times, trains the corresponding muscle the most. Help Greg, determine which muscle will get the most training.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises.
Output Specification:
Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous.
Demo Input:
['2\n2 8\n', '3\n5 1 10\n', '7\n3 3 2 7 9 6 8\n']
Demo Output:
['biceps\n', 'back\n', 'chest\n']
Note:
In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the most exercise. | ```python
n = int(input())
arr = list(map(int, input().split()))
ans = [0,0,0]
c = 0
for i in range(n):
if c == 0:
ans[c] += arr[i]
elif c == 1:
ans[c] += arr[i]
else:
ans[c] += arr[i]
c = -1
c += 1
p = ['chest', 'biseps', 'back']
print(p[ans.index(max(ans))])
``` | 0 | |
19 | D | Points | PROGRAMMING | 2,800 | [
"data structures"
] | D. Points | 2 | 256 | Pete and Bob invented a new interesting game. Bob takes a sheet of paper and locates a Cartesian coordinate system on it as follows: point (0,<=0) is located in the bottom-left corner, *Ox* axis is directed right, *Oy* axis is directed up. Pete gives Bob requests of three types:
- add x y — on the sheet of paper Bob marks a point with coordinates (*x*,<=*y*). For each request of this type it's guaranteed that point (*x*,<=*y*) is not yet marked on Bob's sheet at the time of the request. - remove x y — on the sheet of paper Bob erases the previously marked point with coordinates (*x*,<=*y*). For each request of this type it's guaranteed that point (*x*,<=*y*) is already marked on Bob's sheet at the time of the request. - find x y — on the sheet of paper Bob finds all the marked points, lying strictly above and strictly to the right of point (*x*,<=*y*). Among these points Bob chooses the leftmost one, if it is not unique, he chooses the bottommost one, and gives its coordinates to Pete.
Bob managed to answer the requests, when they were 10, 100 or 1000, but when their amount grew up to 2·105, Bob failed to cope. Now he needs a program that will answer all Pete's requests. Help Bob, please! | The first input line contains number *n* (1<=≤<=*n*<=≤<=2·105) — amount of requests. Then there follow *n* lines — descriptions of the requests. add x y describes the request to add a point, remove x y — the request to erase a point, find x y — the request to find the bottom-left point. All the coordinates in the input file are non-negative and don't exceed 109. | For each request of type find x y output in a separate line the answer to it — coordinates of the bottommost among the leftmost marked points, lying strictly above and to the right of point (*x*,<=*y*). If there are no points strictly above and to the right of point (*x*,<=*y*), output -1. | [
"7\nadd 1 1\nadd 3 4\nfind 0 0\nremove 1 1\nfind 0 0\nadd 1 1\nfind 0 0\n",
"13\nadd 5 5\nadd 5 6\nadd 5 7\nadd 6 5\nadd 6 6\nadd 6 7\nadd 7 5\nadd 7 6\nadd 7 7\nfind 6 6\nremove 7 7\nfind 6 6\nfind 4 4\n"
] | [
"1 1\n3 4\n1 1\n",
"7 7\n-1\n5 5\n"
] | none | 0 | [] | 1,669,918,427 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 122 | 1,126,400 |
from bisect import insort_left as il, bisect_left as bl
M,d=10**9+2,2023
d=[
d,
M//d+1,
[[[(0,0),(M,M)],[0,M]] for _ in range(d)],
[(0,0)]*2*d,
set()
]
def f(x,y):
def w(x,y):
h,l=0,d[3]
while h<d[0]:
i=h<<1
j=i|1
m,n={},[]
if l[i][0]>=x and l[i][1]>=y:
m[l[i]]=i
n+=[l[i]]
if l[j][0]>=x and l[j][1]>=y:
m[l[j]]=j
n+=[l[j]]
if n:
h=m[min(n)]
elif j!=1:
return w((x//d[1]+1)*d[1],y)
else:
return M,M
l=d[2][h-d[0]]
h=1
if x>l[0][1][0]:
h=bl(l[0],(x,y))
for k in l[0][h:]:
if k[1]>=y:
break
if k==(M,M):
k=w((x//d[1]+1)*d[1],y)
return k
q()
k=w(x+1,y+1)
if k==(M,M):
print(-1)
else:
print(*k)
def q():
for k in d[4]:
l=d[2][k]
h=(l[0][-2][0],l[1][-2])
k,l=d[0]+k,d[3]
if l[k]!=h:
l[k]=h
while k>1:
i,j=k>>1,k^1
l[i]=(max(l[k][0],l[j][0]),max(l[k][1],l[j][1]))
k=i
d[4]=set()
def a(x, y):
if x and y:
k=x//d[1]
l=d[2][k]
il(l[0],(x,y))
il(l[1],y)
d[4].add(k)
def r(x,y):
if x and y:
k=x//d[1]
l=d[2][k]
del l[0][bl(l[0],(x,y))]
del l[1][bl(l[1],y)]
d[4].add(k)
for i in range(int(input())):
s = input().split()
{'a':a,'r':r,'f':f}[s[0][0]](int(s[1]),int(s[2]))
| Title: Points
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Pete and Bob invented a new interesting game. Bob takes a sheet of paper and locates a Cartesian coordinate system on it as follows: point (0,<=0) is located in the bottom-left corner, *Ox* axis is directed right, *Oy* axis is directed up. Pete gives Bob requests of three types:
- add x y — on the sheet of paper Bob marks a point with coordinates (*x*,<=*y*). For each request of this type it's guaranteed that point (*x*,<=*y*) is not yet marked on Bob's sheet at the time of the request. - remove x y — on the sheet of paper Bob erases the previously marked point with coordinates (*x*,<=*y*). For each request of this type it's guaranteed that point (*x*,<=*y*) is already marked on Bob's sheet at the time of the request. - find x y — on the sheet of paper Bob finds all the marked points, lying strictly above and strictly to the right of point (*x*,<=*y*). Among these points Bob chooses the leftmost one, if it is not unique, he chooses the bottommost one, and gives its coordinates to Pete.
Bob managed to answer the requests, when they were 10, 100 or 1000, but when their amount grew up to 2·105, Bob failed to cope. Now he needs a program that will answer all Pete's requests. Help Bob, please!
Input Specification:
The first input line contains number *n* (1<=≤<=*n*<=≤<=2·105) — amount of requests. Then there follow *n* lines — descriptions of the requests. add x y describes the request to add a point, remove x y — the request to erase a point, find x y — the request to find the bottom-left point. All the coordinates in the input file are non-negative and don't exceed 109.
Output Specification:
For each request of type find x y output in a separate line the answer to it — coordinates of the bottommost among the leftmost marked points, lying strictly above and to the right of point (*x*,<=*y*). If there are no points strictly above and to the right of point (*x*,<=*y*), output -1.
Demo Input:
['7\nadd 1 1\nadd 3 4\nfind 0 0\nremove 1 1\nfind 0 0\nadd 1 1\nfind 0 0\n', '13\nadd 5 5\nadd 5 6\nadd 5 7\nadd 6 5\nadd 6 6\nadd 6 7\nadd 7 5\nadd 7 6\nadd 7 7\nfind 6 6\nremove 7 7\nfind 6 6\nfind 4 4\n']
Demo Output:
['1 1\n3 4\n1 1\n', '7 7\n-1\n5 5\n']
Note:
none | ```python
from bisect import insort_left as il, bisect_left as bl
M,d=10**9+2,2023
d=[
d,
M//d+1,
[[[(0,0),(M,M)],[0,M]] for _ in range(d)],
[(0,0)]*2*d,
set()
]
def f(x,y):
def w(x,y):
h,l=0,d[3]
while h<d[0]:
i=h<<1
j=i|1
m,n={},[]
if l[i][0]>=x and l[i][1]>=y:
m[l[i]]=i
n+=[l[i]]
if l[j][0]>=x and l[j][1]>=y:
m[l[j]]=j
n+=[l[j]]
if n:
h=m[min(n)]
elif j!=1:
return w((x//d[1]+1)*d[1],y)
else:
return M,M
l=d[2][h-d[0]]
h=1
if x>l[0][1][0]:
h=bl(l[0],(x,y))
for k in l[0][h:]:
if k[1]>=y:
break
if k==(M,M):
k=w((x//d[1]+1)*d[1],y)
return k
q()
k=w(x+1,y+1)
if k==(M,M):
print(-1)
else:
print(*k)
def q():
for k in d[4]:
l=d[2][k]
h=(l[0][-2][0],l[1][-2])
k,l=d[0]+k,d[3]
if l[k]!=h:
l[k]=h
while k>1:
i,j=k>>1,k^1
l[i]=(max(l[k][0],l[j][0]),max(l[k][1],l[j][1]))
k=i
d[4]=set()
def a(x, y):
if x and y:
k=x//d[1]
l=d[2][k]
il(l[0],(x,y))
il(l[1],y)
d[4].add(k)
def r(x,y):
if x and y:
k=x//d[1]
l=d[2][k]
del l[0][bl(l[0],(x,y))]
del l[1][bl(l[1],y)]
d[4].add(k)
for i in range(int(input())):
s = input().split()
{'a':a,'r':r,'f':f}[s[0][0]](int(s[1]),int(s[2]))
``` | -1 |
0 | none | none | none | 0 | [
"none"
] | null | null | Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer number of centimeters. There the properties of the hexagon ended and Gerald decided to draw on it.
He painted a few lines, parallel to the sides of the hexagon. The lines split the hexagon into regular triangles with sides of 1 centimeter. Now Gerald wonders how many triangles he has got. But there were so many of them that Gerald lost the track of his counting. Help the boy count the triangles. | The first and the single line of the input contains 6 space-separated integers *a*1,<=*a*2,<=*a*3,<=*a*4,<=*a*5 and *a*6 (1<=≤<=*a**i*<=≤<=1000) — the lengths of the sides of the hexagons in centimeters in the clockwise order. It is guaranteed that the hexagon with the indicated properties and the exactly such sides exists. | Print a single integer — the number of triangles with the sides of one 1 centimeter, into which the hexagon is split. | [
"1 1 1 1 1 1\n",
"1 2 1 2 1 2\n"
] | [
"6\n",
"13\n"
] | This is what Gerald's hexagon looks like in the first sample:
<img class="tex-graphics" src="https://espresso.codeforces.com/84d193e27b02c38eb1eadc536602a2ec0b9f9519.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's what it looks like in the second sample:
<img class="tex-graphics" src="https://espresso.codeforces.com/e29076a96da8ca864654cc6195654d9bf07d31ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 0 | [
{
"input": "1 1 1 1 1 1",
"output": "6"
},
{
"input": "1 2 1 2 1 2",
"output": "13"
},
{
"input": "2 4 5 3 3 6",
"output": "83"
},
{
"input": "45 19 48 18 46 21",
"output": "6099"
},
{
"input": "66 6 65 6 66 5",
"output": "5832"
},
{
"input": "7 5 4 8 ... | 1,680,979,907 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | from math import *
l = list(map(int, input().split()))
mx = max(l)
mn = min(l)
theta = radians(60)
Total_Area = (1/2)* (mx + mn)**2 * sin(theta) * cos(theta) - (1/2) * (mn)**2 * sin(theta)
Total_Area += (mx + mn)*cos(theta)
Reg = (1/2)*sin(theta)
print(int((2*Total_Area)//Reg)) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer number of centimeters. There the properties of the hexagon ended and Gerald decided to draw on it.
He painted a few lines, parallel to the sides of the hexagon. The lines split the hexagon into regular triangles with sides of 1 centimeter. Now Gerald wonders how many triangles he has got. But there were so many of them that Gerald lost the track of his counting. Help the boy count the triangles.
Input Specification:
The first and the single line of the input contains 6 space-separated integers *a*1,<=*a*2,<=*a*3,<=*a*4,<=*a*5 and *a*6 (1<=≤<=*a**i*<=≤<=1000) — the lengths of the sides of the hexagons in centimeters in the clockwise order. It is guaranteed that the hexagon with the indicated properties and the exactly such sides exists.
Output Specification:
Print a single integer — the number of triangles with the sides of one 1 centimeter, into which the hexagon is split.
Demo Input:
['1 1 1 1 1 1\n', '1 2 1 2 1 2\n']
Demo Output:
['6\n', '13\n']
Note:
This is what Gerald's hexagon looks like in the first sample:
<img class="tex-graphics" src="https://espresso.codeforces.com/84d193e27b02c38eb1eadc536602a2ec0b9f9519.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's what it looks like in the second sample:
<img class="tex-graphics" src="https://espresso.codeforces.com/e29076a96da8ca864654cc6195654d9bf07d31ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
from math import *
l = list(map(int, input().split()))
mx = max(l)
mn = min(l)
theta = radians(60)
Total_Area = (1/2)* (mx + mn)**2 * sin(theta) * cos(theta) - (1/2) * (mn)**2 * sin(theta)
Total_Area += (mx + mn)*cos(theta)
Reg = (1/2)*sin(theta)
print(int((2*Total_Area)//Reg))
``` | 0 | |
55 | B | Smallest number | PROGRAMMING | 1,600 | [
"brute force"
] | B. Smallest number | 2 | 256 | Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the next three minutes he took two numbers from the blackboard (not necessarily adjacent) and replaced them with their sum or their product. In the end he got one number. Unfortunately, due to the awful memory he forgot that number, but he remembers four original numbers, sequence of the operations and his surprise because of the very small result. Help Vladimir remember the forgotten number: find the smallest number that can be obtained from the original numbers by the given sequence of operations. | First line contains four integers separated by space: 0<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000 — the original numbers. Second line contains three signs ('+' or '*' each) separated by space — the sequence of the operations in the order of performing. ('+' stands for addition, '*' — multiplication) | Output one integer number — the minimal result which can be obtained.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cin (also you may use %I64d). | [
"1 1 1 1\n+ + *\n",
"2 2 2 2\n* * +\n",
"1 2 3 4\n* + +\n"
] | [
"3\n",
"8\n",
"9\n"
] | none | 1,000 | [
{
"input": "1 1 1 1\n+ + *",
"output": "3"
},
{
"input": "2 2 2 2\n* * +",
"output": "8"
},
{
"input": "1 2 3 4\n* + +",
"output": "9"
},
{
"input": "15 1 3 1\n* * +",
"output": "18"
},
{
"input": "8 1 7 14\n+ + +",
"output": "30"
},
{
"input": "7 17 3... | 1,404,245,752 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 124 | 0 | def delete(i , j, l):
t = []
m = 0
while m < len(l):
if m != i and m != j:
t.append(l[m])
m += 1
return t
n = list(map(int,input().split()))
o = list(input().split())
n = [n]
def brute(l , u):
i = 0
second = list()
while i < len(l):
j = 0
while j < len(l[0]):
k = 0
while k < len(l[0]):
x = list()
if k != j:
x.append(eval(str(l[i][j]) + o[u] + str(l[i][k])))
second.append(x + delete(k,j,l[i].copy()))
k += 1
j += 1
i += 1
return second
second = brute(n, 0)
third = brute(second, 1)
fourth = brute(third, 2)
m = 2 ** 12
for i in fourth:
m = min(m, i[0])
print(m) | Title: Smallest number
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the next three minutes he took two numbers from the blackboard (not necessarily adjacent) and replaced them with their sum or their product. In the end he got one number. Unfortunately, due to the awful memory he forgot that number, but he remembers four original numbers, sequence of the operations and his surprise because of the very small result. Help Vladimir remember the forgotten number: find the smallest number that can be obtained from the original numbers by the given sequence of operations.
Input Specification:
First line contains four integers separated by space: 0<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000 — the original numbers. Second line contains three signs ('+' or '*' each) separated by space — the sequence of the operations in the order of performing. ('+' stands for addition, '*' — multiplication)
Output Specification:
Output one integer number — the minimal result which can be obtained.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cin (also you may use %I64d).
Demo Input:
['1 1 1 1\n+ + *\n', '2 2 2 2\n* * +\n', '1 2 3 4\n* + +\n']
Demo Output:
['3\n', '8\n', '9\n']
Note:
none | ```python
def delete(i , j, l):
t = []
m = 0
while m < len(l):
if m != i and m != j:
t.append(l[m])
m += 1
return t
n = list(map(int,input().split()))
o = list(input().split())
n = [n]
def brute(l , u):
i = 0
second = list()
while i < len(l):
j = 0
while j < len(l[0]):
k = 0
while k < len(l[0]):
x = list()
if k != j:
x.append(eval(str(l[i][j]) + o[u] + str(l[i][k])))
second.append(x + delete(k,j,l[i].copy()))
k += 1
j += 1
i += 1
return second
second = brute(n, 0)
third = brute(second, 1)
fourth = brute(third, 2)
m = 2 ** 12
for i in fourth:
m = min(m, i[0])
print(m)
``` | 0 |
465 | B | Inbox (100500) | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
- Move from the list of letters to the content of any single letter.- Return to the list of letters from single letter viewing mode.- In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of letters in the mailbox.
The second line contains *n* space-separated integers (zeros and ones) — the state of the letter list. The *i*-th number equals either 1, if the *i*-th number is unread, or 0, if the *i*-th letter is read. | Print a single number — the minimum number of operations needed to make all the letters read. | [
"5\n0 1 0 1 0\n",
"5\n1 1 0 0 1\n",
"2\n0 0\n"
] | [
"3\n",
"4\n",
"0\n"
] | In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | 1,000 | [
{
"input": "5\n0 1 0 1 0",
"output": "3"
},
{
"input": "5\n1 1 0 0 1",
"output": "4"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "9\n1 0 1 0 1 0 1 0 1",
"output": "9"
},
{
"input": "5\n1 1 1 1 1",
"output": "5"
},
{
"input": "14\n0 0 1 1 1 0 1 ... | 1,617,715,367 | 4,967 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n=int(input())
s=input()
op=0
if( n>=1 and n<=100):
op=s.count('1')
if(op>1):
op=op+1
if(op==1 and s[0]=='1' or s[len(s)-1]=='1'):
op=0
print(op) | Title: Inbox (100500)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
- Move from the list of letters to the content of any single letter.- Return to the list of letters from single letter viewing mode.- In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of letters in the mailbox.
The second line contains *n* space-separated integers (zeros and ones) — the state of the letter list. The *i*-th number equals either 1, if the *i*-th number is unread, or 0, if the *i*-th letter is read.
Output Specification:
Print a single number — the minimum number of operations needed to make all the letters read.
Demo Input:
['5\n0 1 0 1 0\n', '5\n1 1 0 0 1\n', '2\n0 0\n']
Demo Output:
['3\n', '4\n', '0\n']
Note:
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | ```python
n=int(input())
s=input()
op=0
if( n>=1 and n<=100):
op=s.count('1')
if(op>1):
op=op+1
if(op==1 and s[0]=='1' or s[len(s)-1]=='1'):
op=0
print(op)
``` | 0 | |
194 | A | Exams | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could have spoilt the Codeforces round. On the other hand, if the sum of his marks is strictly less than *k*, the author's mum won't be pleased at all.
The Codeforces authors are very smart and they always get the mark they choose themselves. Also, the Codeforces authors just hate re-sitting exams.
Help the author and find the minimum number of exams he will have to re-sit if he passes the exams in the way that makes the sum of marks for all *n* exams equal exactly *k*. | The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*. | Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*. | [
"4 8\n",
"4 10\n",
"1 3\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | 500 | [
{
"input": "4 8",
"output": "4"
},
{
"input": "4 10",
"output": "2"
},
{
"input": "1 3",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "50 234",
"output": "0"
},
{
"input": "50 100",
"... | 1,650,027,494 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 122 | 0 |
m=map(int,input().split())
n,k=m
if k<(3*n):
print((3*n)-k)
else:
print(0)
| Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could have spoilt the Codeforces round. On the other hand, if the sum of his marks is strictly less than *k*, the author's mum won't be pleased at all.
The Codeforces authors are very smart and they always get the mark they choose themselves. Also, the Codeforces authors just hate re-sitting exams.
Help the author and find the minimum number of exams he will have to re-sit if he passes the exams in the way that makes the sum of marks for all *n* exams equal exactly *k*.
Input Specification:
The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*.
Output Specification:
Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*.
Demo Input:
['4 8\n', '4 10\n', '1 3\n']
Demo Output:
['4\n', '2\n', '0\n']
Note:
In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | ```python
m=map(int,input().split())
n,k=m
if k<(3*n):
print((3*n)-k)
else:
print(0)
``` | 3 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win. | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,591,182,447 | 2,147,483,647 | PyPy 3 | OK | TESTS | 36 | 310 | 0 | import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int (input ()))
def inlt():
return (list (map (int, input ().split ())))
def insr():
s = input()
return (list (s[:len (s) - 1]))
def invr():
return (map (int, input ().split ()))
y, w = invr()
x = max(y,w)
x = 7 - x
if x == 1:
print("1/6")
elif x == 2:
print("1/3")
elif x == 3:
print("1/2")
elif x == 4:
print("2/3")
elif x == 5:
print("5/6")
elif x == 6:
print("1/1") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | ```python
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int (input ()))
def inlt():
return (list (map (int, input ().split ())))
def insr():
s = input()
return (list (s[:len (s) - 1]))
def invr():
return (map (int, input ().split ()))
y, w = invr()
x = max(y,w)
x = 7 - x
if x == 1:
print("1/6")
elif x == 2:
print("1/3")
elif x == 3:
print("1/2")
elif x == 4:
print("2/3")
elif x == 5:
print("5/6")
elif x == 6:
print("1/1")
``` | 3.845 |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe from the left is called safe *i*. There are *n* banknotes left in all the safes in total. The *i*-th banknote is in safe *x**i*. Oleg is now at safe *a*. There are two security guards, one of which guards the safe *b* such that *b*<=<<=*a*, i.e. the first guard is to the left of Oleg. The other guard guards the safe *c* so that *c*<=><=*a*, i.e. he is to the right of Oleg.
The two guards are very lazy, so they do not move. In every second, Oleg can either take all the banknotes from the current safe or move to any of the neighboring safes. However, he cannot visit any safe that is guarded by security guards at any time, becaues he might be charged for stealing. Determine the maximum amount of banknotes Oleg can gather. | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the number of banknotes.
The next line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109), denoting that the *i*-th banknote is located in the *x**i*-th safe. Note that *x**i* are not guaranteed to be distinct. | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first security guard. Thus, he can take a maximum of 4 banknotes.
For the second sample, Oleg can't take any banknotes without bumping into any of the security guards. | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,598,421,138 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 155 | 9,011,200 | a, b, c=map(int, input().split())
n=int(input())
x=list(map(int, input().split()))
ans=0
for i in range(n):
if b<x[i] and x[i]<c:
ans+=1
print(ans) | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe from the left is called safe *i*. There are *n* banknotes left in all the safes in total. The *i*-th banknote is in safe *x**i*. Oleg is now at safe *a*. There are two security guards, one of which guards the safe *b* such that *b*<=<<=*a*, i.e. the first guard is to the left of Oleg. The other guard guards the safe *c* so that *c*<=><=*a*, i.e. he is to the right of Oleg.
The two guards are very lazy, so they do not move. In every second, Oleg can either take all the banknotes from the current safe or move to any of the neighboring safes. However, he cannot visit any safe that is guarded by security guards at any time, becaues he might be charged for stealing. Determine the maximum amount of banknotes Oleg can gather.
Input Specification:
The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the number of banknotes.
The next line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109), denoting that the *i*-th banknote is located in the *x**i*-th safe. Note that *x**i* are not guaranteed to be distinct.
Output Specification:
Output a single integer: the maximum number of banknotes Oleg can take.
Demo Input:
['5 3 7\n8\n4 7 5 5 3 6 2 8\n', '6 5 7\n5\n1 5 7 92 3\n']
Demo Output:
['4\n', '0\n']
Note:
In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first security guard. Thus, he can take a maximum of 4 banknotes.
For the second sample, Oleg can't take any banknotes without bumping into any of the security guards. | ```python
a, b, c=map(int, input().split())
n=int(input())
x=list(map(int, input().split()))
ans=0
for i in range(n):
if b<x[i] and x[i]<c:
ans+=1
print(ans)
``` | 3 | |
413 | A | Data Recovery | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Not so long ago company R2 bought company R1 and consequently, all its developments in the field of multicore processors. Now the R2 laboratory is testing one of the R1 processors.
The testing goes in *n* steps, at each step the processor gets some instructions, and then its temperature is measured. The head engineer in R2 is keeping a report record on the work of the processor: he writes down the minimum and the maximum measured temperature in his notebook. His assistant had to write down all temperatures into his notebook, but (for unknown reasons) he recorded only *m*.
The next day, the engineer's assistant filed in a report with all the *m* temperatures. However, the chief engineer doubts that the assistant wrote down everything correctly (naturally, the chief engineer doesn't doubt his notes). So he asked you to help him. Given numbers *n*, *m*, *min*, *max* and the list of *m* temperatures determine whether you can upgrade the set of *m* temperatures to the set of *n* temperatures (that is add *n*<=-<=*m* temperatures), so that the minimum temperature was *min* and the maximum one was *max*. | The first line contains four integers *n*,<=*m*,<=*min*,<=*max* (1<=≤<=*m*<=<<=*n*<=≤<=100; 1<=≤<=*min*<=<<=*max*<=≤<=100). The second line contains *m* space-separated integers *t**i* (1<=≤<=*t**i*<=≤<=100) — the temperatures reported by the assistant.
Note, that the reported temperatures, and the temperatures you want to add can contain equal temperatures. | If the data is consistent, print 'Correct' (without the quotes). Otherwise, print 'Incorrect' (without the quotes). | [
"2 1 1 2\n1\n",
"3 1 1 3\n2\n",
"2 1 1 3\n2\n"
] | [
"Correct\n",
"Correct\n",
"Incorrect\n"
] | In the first test sample one of the possible initial configurations of temperatures is [1, 2].
In the second test sample one of the possible initial configurations of temperatures is [2, 1, 3].
In the third test sample it is impossible to add one temperature to obtain the minimum equal to 1 and the maximum equal to 3. | 500 | [
{
"input": "2 1 1 2\n1",
"output": "Correct"
},
{
"input": "3 1 1 3\n2",
"output": "Correct"
},
{
"input": "2 1 1 3\n2",
"output": "Incorrect"
},
{
"input": "3 1 1 5\n3",
"output": "Correct"
},
{
"input": "3 2 1 5\n1 5",
"output": "Correct"
},
{
"input... | 1,556,014,886 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 109 | 0 | n,m,mi,ma = map(int, input().split())
a = list(map(int,input().split())) #m
if any(list(map(lambda x:x>ma or x<mi, a))):
print("Incorrect")
exit(0)
c=0
if mi not in a: c+=1
if ma not in a: c+=1
if c<=(n-m):
print("Correct")
else:
print("Incorrect") | Title: Data Recovery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Not so long ago company R2 bought company R1 and consequently, all its developments in the field of multicore processors. Now the R2 laboratory is testing one of the R1 processors.
The testing goes in *n* steps, at each step the processor gets some instructions, and then its temperature is measured. The head engineer in R2 is keeping a report record on the work of the processor: he writes down the minimum and the maximum measured temperature in his notebook. His assistant had to write down all temperatures into his notebook, but (for unknown reasons) he recorded only *m*.
The next day, the engineer's assistant filed in a report with all the *m* temperatures. However, the chief engineer doubts that the assistant wrote down everything correctly (naturally, the chief engineer doesn't doubt his notes). So he asked you to help him. Given numbers *n*, *m*, *min*, *max* and the list of *m* temperatures determine whether you can upgrade the set of *m* temperatures to the set of *n* temperatures (that is add *n*<=-<=*m* temperatures), so that the minimum temperature was *min* and the maximum one was *max*.
Input Specification:
The first line contains four integers *n*,<=*m*,<=*min*,<=*max* (1<=≤<=*m*<=<<=*n*<=≤<=100; 1<=≤<=*min*<=<<=*max*<=≤<=100). The second line contains *m* space-separated integers *t**i* (1<=≤<=*t**i*<=≤<=100) — the temperatures reported by the assistant.
Note, that the reported temperatures, and the temperatures you want to add can contain equal temperatures.
Output Specification:
If the data is consistent, print 'Correct' (without the quotes). Otherwise, print 'Incorrect' (without the quotes).
Demo Input:
['2 1 1 2\n1\n', '3 1 1 3\n2\n', '2 1 1 3\n2\n']
Demo Output:
['Correct\n', 'Correct\n', 'Incorrect\n']
Note:
In the first test sample one of the possible initial configurations of temperatures is [1, 2].
In the second test sample one of the possible initial configurations of temperatures is [2, 1, 3].
In the third test sample it is impossible to add one temperature to obtain the minimum equal to 1 and the maximum equal to 3. | ```python
n,m,mi,ma = map(int, input().split())
a = list(map(int,input().split())) #m
if any(list(map(lambda x:x>ma or x<mi, a))):
print("Incorrect")
exit(0)
c=0
if mi not in a: c+=1
if ma not in a: c+=1
if c<=(n-m):
print("Correct")
else:
print("Incorrect")
``` | 3 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c* is the sum of *a* and *b*. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros?
For example if the equation is 101<=+<=102<==<=203, if we removed all zeros it will be 11<=+<=12<==<=23 which is still a correct equation.
But if the equation is 105<=+<=106<==<=211, if we removed all zeros it will be 15<=+<=16<==<=211 which is not a correct equation. | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,601,731,218 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 404 | 0 | a = int(input())
b = int(input())
c = a+b
d,e,f = "","",""
for i in str(a):
if i !="0":
d += i
for i in str(b):
if i !="0":
e += i
for i in str(c):
if i !="0":
f += i
if int(f) == int(d) + int(e):
print("YES")
else:
print("NO") | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c* is the sum of *a* and *b*. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros?
For example if the equation is 101<=+<=102<==<=203, if we removed all zeros it will be 11<=+<=12<==<=23 which is still a correct equation.
But if the equation is 105<=+<=106<==<=211, if we removed all zeros it will be 15<=+<=16<==<=211 which is not a correct equation.
Input Specification:
The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*.
Output Specification:
The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.
Demo Input:
['101\n102\n', '105\n106\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
a = int(input())
b = int(input())
c = a+b
d,e,f = "","",""
for i in str(a):
if i !="0":
d += i
for i in str(b):
if i !="0":
e += i
for i in str(c):
if i !="0":
f += i
if int(f) == int(d) + int(e):
print("YES")
else:
print("NO")
``` | 3.899 |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morning and wants to eat the pineapple, but he can't eat it when it's barking. Barney plans to eat it at time *x* (in seconds), so he asked you to tell him if it's gonna bark at that time. | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and 52. | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,472,816,814 | 2,147,483,647 | Python 3 | OK | TESTS | 95 | 77 | 0 | a,b,c=list(map(int,input().split()))
if (a==c):
print("YES")
elif c>=a+b and ((c-a)%b==1 or (c-a)%b==0):
print("YES")
else:
print("NO")
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morning and wants to eat the pineapple, but he can't eat it when it's barking. Barney plans to eat it at time *x* (in seconds), so he asked you to tell him if it's gonna bark at that time.
Input Specification:
The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively.
Output Specification:
Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output.
Demo Input:
['3 10 4\n', '3 10 3\n', '3 8 51\n', '3 8 52\n']
Demo Output:
['NO\n', 'YES\n', 'YES\n', 'YES\n']
Note:
In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and 52. | ```python
a,b,c=list(map(int,input().split()))
if (a==c):
print("YES")
elif c>=a+b and ((c-a)%b==1 or (c-a)%b==0):
print("YES")
else:
print("NO")
``` | 3 | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at some subject, if there is no student who got a higher mark for this subject. Let's consider a student successful, if there exists a subject he is the best at.
Your task is to find the number of successful students in the group. | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepatated by spaces. | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,680,010,381 | 181 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n,m = map(int, input().split())
ans = 0
for i in range(n):
l=list(map(int,input().split()))
for j in range(len(l)):
if l[j] >= m:
ans+=1
print(ans) | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at some subject, if there is no student who got a higher mark for this subject. Let's consider a student successful, if there exists a subject he is the best at.
Your task is to find the number of successful students in the group.
Input Specification:
The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepatated by spaces.
Output Specification:
Print the single number — the number of successful students in the given group.
Demo Input:
['3 3\n223\n232\n112\n', '3 5\n91728\n11828\n11111\n']
Demo Output:
['2\n', '3\n']
Note:
In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | ```python
n,m = map(int, input().split())
ans = 0
for i in range(n):
l=list(map(int,input().split()))
for j in range(len(l)):
if l[j] >= m:
ans+=1
print(ans)
``` | 0 | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their height. But as there's virtually no time to do that, the soldiers lined up in the arbitrary order. However, the general is rather short-sighted and he thinks that the soldiers lined up correctly if the first soldier in the line has the maximum height and the last soldier has the minimum height. Please note that the way other solders are positioned does not matter, including the case when there are several soldiers whose height is maximum or minimum. Only the heights of the first and the last soldier are important.
For example, the general considers the sequence of heights (4, 3, 4, 2, 1, 1) correct and the sequence (4, 3, 1, 2, 2) wrong.
Within one second the colonel can swap any two neighboring soldiers. Help him count the minimum time needed to form a line-up which the general will consider correct. | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginning of the line to its end. The numbers are space-separated. Numbers *a*1,<=*a*2,<=...,<=*a**n* are not necessarily different. | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 76, 40) 1. (10, 58, 10, 31, 76, 63, 40) 1. (10, 58, 31, 10, 76, 63, 40) 1. (10, 58, 31, 76, 10, 63, 40) 1. (10, 58, 31, 76, 63, 10, 40) 1. (10, 58, 76, 31, 63, 10, 40) 1. (10, 76, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 40, 10) | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,689,853,577 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | def minimum_swaps(n, heights):
max_height = max(heights)
min_height = min(heights)
max_height_idx = heights.index(max_height)
min_height_idx = heights.index(min_height)
# If the tallest soldier is at the beginning and the shortest soldier is at the end
if max_height_idx == 0 and min_height_idx == n - 1:
second_max_height = max(heights[1:])
second_min_height = min(heights[:-1])
count_taller_than_second_max = sum(height > second_max_height for height in heights)
count_shorter_than_second_min = sum(height < second_min_height for height in heights)
return count_taller_than_second_max + count_shorter_than_second_min
# Otherwise, we have to swap both soldiers
return max_height_idx + (n - 1 - min_height_idx) - 1
# Input
n = int(input())
heights = list(map(int, input().split()))
# Output
print(minimum_swaps(n, heights))
| Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their height. But as there's virtually no time to do that, the soldiers lined up in the arbitrary order. However, the general is rather short-sighted and he thinks that the soldiers lined up correctly if the first soldier in the line has the maximum height and the last soldier has the minimum height. Please note that the way other solders are positioned does not matter, including the case when there are several soldiers whose height is maximum or minimum. Only the heights of the first and the last soldier are important.
For example, the general considers the sequence of heights (4, 3, 4, 2, 1, 1) correct and the sequence (4, 3, 1, 2, 2) wrong.
Within one second the colonel can swap any two neighboring soldiers. Help him count the minimum time needed to form a line-up which the general will consider correct.
Input Specification:
The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginning of the line to its end. The numbers are space-separated. Numbers *a*1,<=*a*2,<=...,<=*a**n* are not necessarily different.
Output Specification:
Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like.
Demo Input:
['4\n33 44 11 22\n', '7\n10 10 58 31 63 40 76\n']
Demo Output:
['2\n', '10\n']
Note:
In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 40, 76) 1. (10, 58, 10, 31, 63, 76, 40) 1. (10, 58, 10, 31, 76, 63, 40) 1. (10, 58, 31, 10, 76, 63, 40) 1. (10, 58, 31, 76, 10, 63, 40) 1. (10, 58, 31, 76, 63, 10, 40) 1. (10, 58, 76, 31, 63, 10, 40) 1. (10, 76, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 10, 40) 1. (76, 10, 58, 31, 63, 40, 10) | ```python
def minimum_swaps(n, heights):
max_height = max(heights)
min_height = min(heights)
max_height_idx = heights.index(max_height)
min_height_idx = heights.index(min_height)
# If the tallest soldier is at the beginning and the shortest soldier is at the end
if max_height_idx == 0 and min_height_idx == n - 1:
second_max_height = max(heights[1:])
second_min_height = min(heights[:-1])
count_taller_than_second_max = sum(height > second_max_height for height in heights)
count_shorter_than_second_min = sum(height < second_min_height for height in heights)
return count_taller_than_second_max + count_shorter_than_second_min
# Otherwise, we have to swap both soldiers
return max_height_idx + (n - 1 - min_height_idx) - 1
# Input
n = int(input())
heights = list(map(int, input().split()))
# Output
print(minimum_swaps(n, heights))
``` | 0 | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to letter on *i*th, then sum up all these quantities, such a number of coins Appleman should give to Toastman.
Given the description of Appleman's cards. What is the maximum number of coins Toastman can get? | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,695,847,588 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 77 | 0 | n,k=map(int,input().split())
a=input()
a=list(a)
a.sort()
r=[]
v=1
for i in range(n-1) :
if a[i] == a[i+1] :
v+=1
if i == n-2 :
r.append(v)
elif a[i] != a[i+1]:
r.append(v)
v=1
sum=0
answer=0
for i in range(len(r)):
if sum + r[i] == k :
answer+=r[i]*r[i]
break
elif sum + r[i] > k :
answer+=(k-sum)*(k-sum)
break
elif sum + r[i] < k :
sum+=r[i]
answer+=r[i]*r[i]
print(answer) | Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to letter on *i*th, then sum up all these quantities, such a number of coins Appleman should give to Toastman.
Given the description of Appleman's cards. What is the maximum number of coins Toastman can get?
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman.
Output Specification:
Print a single integer – the answer to the problem.
Demo Input:
['15 10\nDZFDFZDFDDDDDDF\n', '6 4\nYJSNPI\n']
Demo Output:
['82\n', '4\n']
Note:
In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | ```python
n,k=map(int,input().split())
a=input()
a=list(a)
a.sort()
r=[]
v=1
for i in range(n-1) :
if a[i] == a[i+1] :
v+=1
if i == n-2 :
r.append(v)
elif a[i] != a[i+1]:
r.append(v)
v=1
sum=0
answer=0
for i in range(len(r)):
if sum + r[i] == k :
answer+=r[i]*r[i]
break
elif sum + r[i] > k :
answer+=(k-sum)*(k-sum)
break
elif sum + r[i] < k :
sum+=r[i]
answer+=r[i]*r[i]
print(answer)
``` | 0 | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,617,910,093 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 77 | 0 | n,m=map(int,input().split())
x=n%m
if(x==0):
print(n+m)
else:
print(n+(m-x))
| Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109).
Output Specification:
Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*.
Demo Input:
['5 3\n', '25 13\n', '26 13\n']
Demo Output:
['6\n', '26\n', '39\n']
Note:
none | ```python
n,m=map(int,input().split())
x=n%m
if(x==0):
print(n+m)
else:
print(n+(m-x))
``` | 3 | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem. | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,674,102,406 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 62 | 0 | a=int(input())
b=list(map(int,input().split()))
q=[]
m=min(b)
for i in b:
if i!=m:
q.append(i)
print(min(q))
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem.
Input Specification:
The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value.
Output Specification:
If the given sequence has the second order statistics, output this order statistics, otherwise output NO.
Demo Input:
['4\n1 2 2 -4\n', '5\n1 2 3 1 1\n']
Demo Output:
['1\n', '2\n']
Note:
none | ```python
a=int(input())
b=list(map(int,input().split()))
q=[]
m=min(b)
for i in b:
if i!=m:
q.append(i)
print(min(q))
``` | -1 |
730 | J | Bottles | PROGRAMMING | 1,900 | [
"dp"
] | null | null | Nick has *n* bottles of soda left after his birthday. Each bottle is described by two values: remaining amount of soda *a**i* and bottle volume *b**i* (*a**i*<=≤<=*b**i*).
Nick has decided to pour all remaining soda into minimal number of bottles, moreover he has to do it as soon as possible. Nick spends *x* seconds to pour *x* units of soda from one bottle to another.
Nick asks you to help him to determine *k* — the minimal number of bottles to store all remaining soda and *t* — the minimal time to pour soda into *k* bottles. A bottle can't store more soda than its volume. All remaining soda should be saved. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the amount of soda remaining in the *i*-th bottle.
The third line contains *n* positive integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=100), where *b**i* is the volume of the *i*-th bottle.
It is guaranteed that *a**i*<=≤<=*b**i* for any *i*. | The only line should contain two integers *k* and *t*, where *k* is the minimal number of bottles that can store all the soda and *t* is the minimal time to pour the soda into *k* bottles. | [
"4\n3 3 4 3\n4 7 6 5\n",
"2\n1 1\n100 100\n",
"5\n10 30 5 6 24\n10 41 7 8 24\n"
] | [
"2 6\n",
"1 1\n",
"3 11\n"
] | In the first example Nick can pour soda from the first bottle to the second bottle. It will take 3 seconds. After it the second bottle will contain 3 + 3 = 6 units of soda. Then he can pour soda from the fourth bottle to the second bottle and to the third bottle: one unit to the second and two units to the third. It will take 1 + 2 = 3 seconds. So, all the soda will be in two bottles and he will spend 3 + 3 = 6 seconds to do it. | 0 | [
{
"input": "4\n3 3 4 3\n4 7 6 5",
"output": "2 6"
},
{
"input": "2\n1 1\n100 100",
"output": "1 1"
},
{
"input": "5\n10 30 5 6 24\n10 41 7 8 24",
"output": "3 11"
},
{
"input": "1\n1\n100",
"output": "1 0"
},
{
"input": "1\n100\n100",
"output": "1 0"
},
{
... | 1,688,613,643 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 81,510,400 | from collections import *
from functools import *
from itertools import *
from bisect import *
from heapq import *
from math import *
import re
import io
import os
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
def LI():
return list(input().split())
def LII():
return list(map(int, input().split()))
n = II()
A = LII()
B = LII()
@cache
def dfs(i,diff):
if i==n:
return (0,0) if diff==0 else (inf,inf)
a,b = dfs(i+1,diff-A[i])
res = (a,b+A[i])
for x in range(A[i]==0,B[i]-A[i]+1):
a,b = dfs(i+1,diff+x)
res = min(res,(1+a,b+x))
return res
a,b = dfs(0,0)
print(a,b//2) | Title: Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nick has *n* bottles of soda left after his birthday. Each bottle is described by two values: remaining amount of soda *a**i* and bottle volume *b**i* (*a**i*<=≤<=*b**i*).
Nick has decided to pour all remaining soda into minimal number of bottles, moreover he has to do it as soon as possible. Nick spends *x* seconds to pour *x* units of soda from one bottle to another.
Nick asks you to help him to determine *k* — the minimal number of bottles to store all remaining soda and *t* — the minimal time to pour soda into *k* bottles. A bottle can't store more soda than its volume. All remaining soda should be saved.
Input Specification:
The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the amount of soda remaining in the *i*-th bottle.
The third line contains *n* positive integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=100), where *b**i* is the volume of the *i*-th bottle.
It is guaranteed that *a**i*<=≤<=*b**i* for any *i*.
Output Specification:
The only line should contain two integers *k* and *t*, where *k* is the minimal number of bottles that can store all the soda and *t* is the minimal time to pour the soda into *k* bottles.
Demo Input:
['4\n3 3 4 3\n4 7 6 5\n', '2\n1 1\n100 100\n', '5\n10 30 5 6 24\n10 41 7 8 24\n']
Demo Output:
['2 6\n', '1 1\n', '3 11\n']
Note:
In the first example Nick can pour soda from the first bottle to the second bottle. It will take 3 seconds. After it the second bottle will contain 3 + 3 = 6 units of soda. Then he can pour soda from the fourth bottle to the second bottle and to the third bottle: one unit to the second and two units to the third. It will take 1 + 2 = 3 seconds. So, all the soda will be in two bottles and he will spend 3 + 3 = 6 seconds to do it. | ```python
from collections import *
from functools import *
from itertools import *
from bisect import *
from heapq import *
from math import *
import re
import io
import os
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
def LI():
return list(input().split())
def LII():
return list(map(int, input().split()))
n = II()
A = LII()
B = LII()
@cache
def dfs(i,diff):
if i==n:
return (0,0) if diff==0 else (inf,inf)
a,b = dfs(i+1,diff-A[i])
res = (a,b+A[i])
for x in range(A[i]==0,B[i]-A[i]+1):
a,b = dfs(i+1,diff+x)
res = min(res,(1+a,b+x))
return res
a,b = dfs(0,0)
print(a,b//2)
``` | 0 | |
435 | A | Queue on Bus Stop | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand in queue by groups.
The bus stop queue has *n* groups of people. The *i*-th group from the beginning has *a**i* people. Every 30 minutes an empty bus arrives at the bus stop, it can carry at most *m* people. Naturally, the people from the first group enter the bus first. Then go the people from the second group and so on. Note that the order of groups in the queue never changes. Moreover, if some group cannot fit all of its members into the current bus, it waits for the next bus together with other groups standing after it in the queue.
Your task is to determine how many buses is needed to transport all *n* groups to the dacha countryside. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). The next line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*). | Print a single integer — the number of buses that is needed to transport all *n* groups to the dacha countryside. | [
"4 3\n2 3 2 1\n",
"3 4\n1 2 1\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "4 3\n2 3 2 1",
"output": "3"
},
{
"input": "3 4\n1 2 1",
"output": "1"
},
{
"input": "1 5\n4",
"output": "1"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "6 4\n1 3 2 3 4 1",
"output": "5"
},
{
"input": "6 8\n6 1 1 1 4 5",
... | 1,590,229,853 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | z=lambda:map(int,input().split());a,b=z();c=list(z());s=i=0;from math import*
while(i<a):
k=ceil(c[i]/b);l=k*b-c[i];i+=1;s+=k
while(i<a):
if l>=c[i]:l-=c[i];i+=1
else:break
print(s) | Title: Queue on Bus Stop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand in queue by groups.
The bus stop queue has *n* groups of people. The *i*-th group from the beginning has *a**i* people. Every 30 minutes an empty bus arrives at the bus stop, it can carry at most *m* people. Naturally, the people from the first group enter the bus first. Then go the people from the second group and so on. Note that the order of groups in the queue never changes. Moreover, if some group cannot fit all of its members into the current bus, it waits for the next bus together with other groups standing after it in the queue.
Your task is to determine how many buses is needed to transport all *n* groups to the dacha countryside.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). The next line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*).
Output Specification:
Print a single integer — the number of buses that is needed to transport all *n* groups to the dacha countryside.
Demo Input:
['4 3\n2 3 2 1\n', '3 4\n1 2 1\n']
Demo Output:
['3\n', '1\n']
Note:
none | ```python
z=lambda:map(int,input().split());a,b=z();c=list(z());s=i=0;from math import*
while(i<a):
k=ceil(c[i]/b);l=k*b-c[i];i+=1;s+=k
while(i<a):
if l>=c[i]:l-=c[i];i+=1
else:break
print(s)
``` | 3 | |
201 | A | Clear Symmetry | PROGRAMMING | 1,700 | [
"constructive algorithms",
"dp",
"math"
] | null | null | Consider some square matrix *A* with side *n* consisting of zeros and ones. There are *n* rows numbered from 1 to *n* from top to bottom and *n* columns numbered from 1 to *n* from left to right in this matrix. We'll denote the element of the matrix which is located at the intersection of the *i*-row and the *j*-th column as *A**i*,<=*j*.
Let's call matrix *A* clear if no two cells containing ones have a common side.
Let's call matrix *A* symmetrical if it matches the matrices formed from it by a horizontal and/or a vertical reflection. Formally, for each pair (*i*,<=*j*) (1<=≤<=*i*,<=*j*<=≤<=*n*) both of the following conditions must be met: *A**i*,<=*j*<==<=*A**n*<=-<=*i*<=+<=1,<=*j* and *A**i*,<=*j*<==<=*A**i*,<=*n*<=-<=*j*<=+<=1.
Let's define the sharpness of matrix *A* as the number of ones in it.
Given integer *x*, your task is to find the smallest positive integer *n* such that there exists a clear symmetrical matrix *A* with side *n* and sharpness *x*. | The only line contains a single integer *x* (1<=≤<=*x*<=≤<=100) — the required sharpness of the matrix. | Print a single number — the sought value of *n*. | [
"4\n",
"9\n"
] | [
"3\n",
"5\n"
] | The figure below shows the matrices that correspond to the samples: | 1,000 | [
{
"input": "4",
"output": "3"
},
{
"input": "9",
"output": "5"
},
{
"input": "10",
"output": "5"
},
{
"input": "12",
"output": "5"
},
{
"input": "1",
"output": "1"
},
{
"input": "19",
"output": "7"
},
{
"input": "3",
"output": "5"
},
... | 1,594,917,969 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 280 | 20,172,800 | import math
x=int(input())
n=math.ceil(math.sqrt(2*x-1))
print(n) | Title: Clear Symmetry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider some square matrix *A* with side *n* consisting of zeros and ones. There are *n* rows numbered from 1 to *n* from top to bottom and *n* columns numbered from 1 to *n* from left to right in this matrix. We'll denote the element of the matrix which is located at the intersection of the *i*-row and the *j*-th column as *A**i*,<=*j*.
Let's call matrix *A* clear if no two cells containing ones have a common side.
Let's call matrix *A* symmetrical if it matches the matrices formed from it by a horizontal and/or a vertical reflection. Formally, for each pair (*i*,<=*j*) (1<=≤<=*i*,<=*j*<=≤<=*n*) both of the following conditions must be met: *A**i*,<=*j*<==<=*A**n*<=-<=*i*<=+<=1,<=*j* and *A**i*,<=*j*<==<=*A**i*,<=*n*<=-<=*j*<=+<=1.
Let's define the sharpness of matrix *A* as the number of ones in it.
Given integer *x*, your task is to find the smallest positive integer *n* such that there exists a clear symmetrical matrix *A* with side *n* and sharpness *x*.
Input Specification:
The only line contains a single integer *x* (1<=≤<=*x*<=≤<=100) — the required sharpness of the matrix.
Output Specification:
Print a single number — the sought value of *n*.
Demo Input:
['4\n', '9\n']
Demo Output:
['3\n', '5\n']
Note:
The figure below shows the matrices that correspond to the samples: | ```python
import math
x=int(input())
n=math.ceil(math.sqrt(2*x-1))
print(n)
``` | 0 | |
864 | E | Fire | PROGRAMMING | 2,000 | [
"dp",
"sortings"
] | null | null | Polycarp is in really serious trouble — his house is on fire! It's time to save the most valuable items. Polycarp estimated that it would take *t**i* seconds to save *i*-th item. In addition, for each item, he estimated the value of *d**i* — the moment after which the item *i* will be completely burned and will no longer be valuable for him at all. In particular, if *t**i*<=≥<=*d**i*, then *i*-th item cannot be saved.
Given the values *p**i* for each of the items, find a set of items that Polycarp can save such that the total value of this items is maximum possible. Polycarp saves the items one after another. For example, if he takes item *a* first, and then item *b*, then the item *a* will be saved in *t**a* seconds, and the item *b* — in *t**a*<=+<=*t**b* seconds after fire started. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of items in Polycarp's house.
Each of the following *n* lines contains three integers *t**i*,<=*d**i*,<=*p**i* (1<=≤<=*t**i*<=≤<=20, 1<=≤<=*d**i*<=≤<=2<=000, 1<=≤<=*p**i*<=≤<=20) — the time needed to save the item *i*, the time after which the item *i* will burn completely and the value of item *i*. | In the first line print the maximum possible total value of the set of saved items. In the second line print one integer *m* — the number of items in the desired set. In the third line print *m* distinct integers — numbers of the saved items in the order Polycarp saves them. Items are 1-indexed in the same order in which they appear in the input. If there are several answers, print any of them. | [
"3\n3 7 4\n2 6 5\n3 7 6\n",
"2\n5 6 1\n3 3 5\n"
] | [
"11\n2\n2 3 \n",
"1\n1\n1 \n"
] | In the first example Polycarp will have time to save any two items, but in order to maximize the total value of the saved items, he must save the second and the third item. For example, he can firstly save the third item in 3 seconds, and then save the second item in another 2 seconds. Thus, the total value of the saved items will be 6 + 5 = 11.
In the second example Polycarp can save only the first item, since even if he immediately starts saving the second item, he can save it in 3 seconds, but this item will already be completely burned by this time. | 2,500 | [
{
"input": "3\n3 7 4\n2 6 5\n3 7 6",
"output": "11\n2\n2 3 "
},
{
"input": "2\n5 6 1\n3 3 5",
"output": "1\n1\n1 "
},
{
"input": "9\n13 18 14\n8 59 20\n9 51 2\n18 32 15\n1 70 18\n14 81 14\n10 88 16\n18 52 3\n1 50 6",
"output": "106\n8\n1 4 9 8 2 5 6 7 "
},
{
"input": "5\n12 4... | 1,673,386,654 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 93 | 37,171,200 | n = int(input())
arr = []
for i in range(n):
t,d,p = [int(x) for x in input().split()]
arr.append([t,d,p,i+1])
arr.sort(key= lambda x: x[1])
dp = [[0 for i in range(2002)] for i in range(2002)]
ans = [[] for j in range(2002)]
for i in range(1,n+1):
t,d,p, ind = arr[i-1]
for j in reversed(range(d)):
if j>= t:
# dp[i][j] = max(dp[i-1][j-t] + p,dp[i][j])
if dp[i][j] <= dp[i-1][j-t] + p:
dp[i][j] = dp[i-1][j-t] + p
ans[j] = ans[j-t] + [ind]
else:
dp[i][j] = max(dp[i][j], dp[i-1][j])
print(max(dp[n]))
ind = dp[n].index(max(dp[n]))
print(len(ans[ind]))
print(*ans[ind])
| Title: Fire
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is in really serious trouble — his house is on fire! It's time to save the most valuable items. Polycarp estimated that it would take *t**i* seconds to save *i*-th item. In addition, for each item, he estimated the value of *d**i* — the moment after which the item *i* will be completely burned and will no longer be valuable for him at all. In particular, if *t**i*<=≥<=*d**i*, then *i*-th item cannot be saved.
Given the values *p**i* for each of the items, find a set of items that Polycarp can save such that the total value of this items is maximum possible. Polycarp saves the items one after another. For example, if he takes item *a* first, and then item *b*, then the item *a* will be saved in *t**a* seconds, and the item *b* — in *t**a*<=+<=*t**b* seconds after fire started.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of items in Polycarp's house.
Each of the following *n* lines contains three integers *t**i*,<=*d**i*,<=*p**i* (1<=≤<=*t**i*<=≤<=20, 1<=≤<=*d**i*<=≤<=2<=000, 1<=≤<=*p**i*<=≤<=20) — the time needed to save the item *i*, the time after which the item *i* will burn completely and the value of item *i*.
Output Specification:
In the first line print the maximum possible total value of the set of saved items. In the second line print one integer *m* — the number of items in the desired set. In the third line print *m* distinct integers — numbers of the saved items in the order Polycarp saves them. Items are 1-indexed in the same order in which they appear in the input. If there are several answers, print any of them.
Demo Input:
['3\n3 7 4\n2 6 5\n3 7 6\n', '2\n5 6 1\n3 3 5\n']
Demo Output:
['11\n2\n2 3 \n', '1\n1\n1 \n']
Note:
In the first example Polycarp will have time to save any two items, but in order to maximize the total value of the saved items, he must save the second and the third item. For example, he can firstly save the third item in 3 seconds, and then save the second item in another 2 seconds. Thus, the total value of the saved items will be 6 + 5 = 11.
In the second example Polycarp can save only the first item, since even if he immediately starts saving the second item, he can save it in 3 seconds, but this item will already be completely burned by this time. | ```python
n = int(input())
arr = []
for i in range(n):
t,d,p = [int(x) for x in input().split()]
arr.append([t,d,p,i+1])
arr.sort(key= lambda x: x[1])
dp = [[0 for i in range(2002)] for i in range(2002)]
ans = [[] for j in range(2002)]
for i in range(1,n+1):
t,d,p, ind = arr[i-1]
for j in reversed(range(d)):
if j>= t:
# dp[i][j] = max(dp[i-1][j-t] + p,dp[i][j])
if dp[i][j] <= dp[i-1][j-t] + p:
dp[i][j] = dp[i-1][j-t] + p
ans[j] = ans[j-t] + [ind]
else:
dp[i][j] = max(dp[i][j], dp[i-1][j])
print(max(dp[n]))
ind = dp[n].index(max(dp[n]))
print(len(ans[ind]))
print(*ans[ind])
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,689,619,603 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 61 | 0 | n,k,a=list(map(int,input().split()))
if(n*k==a**2):
print(a)
elif(a==1):
print(n*k)
elif(n*k<a**2):
print(1)
else:
if(n%a==0 or k%a==0):
print(int((n*k)//(a*a))+int(k//a))
else:
print(int((n*k)//(a*a))+int(k//a)+1) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
n,k,a=list(map(int,input().split()))
if(n*k==a**2):
print(a)
elif(a==1):
print(n*k)
elif(n*k<a**2):
print(1)
else:
if(n%a==0 or k%a==0):
print(int((n*k)//(a*a))+int(k//a))
else:
print(int((n*k)//(a*a))+int(k//a)+1)
``` | 0 |
175 | B | Plane of Tanks: Pro | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has *n* records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
- "noob" — if more than 50% of players have better results; - "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results; - "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results; - "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results; - "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category. | The first line contains the only integer number *n* (1<=≤<=*n*<=≤<=1000) — a number of records with the players' results.
Each of the next *n* lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000. | Print on the first line the number *m* — the number of players, who participated in one round at least.
Each one of the next *m* lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order. | [
"5\nvasya 100\nvasya 200\nartem 100\nkolya 200\nigor 250\n",
"3\nvasya 200\nkolya 1000\nvasya 1000\n"
] | [
"4\nartem noob\nigor pro\nkolya random\nvasya random\n",
"2\nkolya pro\nvasya pro\n"
] | In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | 500 | [
{
"input": "5\nvasya 100\nvasya 200\nartem 100\nkolya 200\nigor 250",
"output": "4\nartem noob\nigor pro\nkolya random\nvasya random"
},
{
"input": "3\nvasya 200\nkolya 1000\nvasya 1000",
"output": "2\nkolya pro\nvasya pro"
},
{
"input": "1\nvasya 1000",
"output": "1\nvasya pro"
},... | 1,608,518,332 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 436 | 3,072,000 | from collections import defaultdict
R = lambda: map(int, input().split())
n = int(input())
mp = defaultdict(int)
for i in range(n):
name, sc = input().split()
sc = int(sc)
mp[name] = max(sc, mp[name])
players = sorted([(k, v) for k, v in mp.items()], key=lambda x: x[1])
print(len(players))
j = 0
for i, playerAndScore in enumerate(players):
player, score = playerAndScore
while j < len(players) and players[j][1] <= score:
j += 1
if j / len(players) < 0.5:
print(' '.join([player, 'noob']))
elif 0.5 <= j / len(players) < 0.8:
print(' '.join([player, 'random']))
elif 0.8 <= j / len(players) < 0.9:
print(' '.join([player, 'average']))
elif 0.9 <= j / len(players) < 0.99:
print(' '.join([player, 'hardcore']))
else:
print(' '.join([player, 'pro']))
| Title: Plane of Tanks: Pro
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has *n* records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
- "noob" — if more than 50% of players have better results; - "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results; - "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results; - "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results; - "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input Specification:
The first line contains the only integer number *n* (1<=≤<=*n*<=≤<=1000) — a number of records with the players' results.
Each of the next *n* lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output Specification:
Print on the first line the number *m* — the number of players, who participated in one round at least.
Each one of the next *m* lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Demo Input:
['5\nvasya 100\nvasya 200\nartem 100\nkolya 200\nigor 250\n', '3\nvasya 200\nkolya 1000\nvasya 1000\n']
Demo Output:
['4\nartem noob\nigor pro\nkolya random\nvasya random\n', '2\nkolya pro\nvasya pro\n']
Note:
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | ```python
from collections import defaultdict
R = lambda: map(int, input().split())
n = int(input())
mp = defaultdict(int)
for i in range(n):
name, sc = input().split()
sc = int(sc)
mp[name] = max(sc, mp[name])
players = sorted([(k, v) for k, v in mp.items()], key=lambda x: x[1])
print(len(players))
j = 0
for i, playerAndScore in enumerate(players):
player, score = playerAndScore
while j < len(players) and players[j][1] <= score:
j += 1
if j / len(players) < 0.5:
print(' '.join([player, 'noob']))
elif 0.5 <= j / len(players) < 0.8:
print(' '.join([player, 'random']))
elif 0.8 <= j / len(players) < 0.9:
print(' '.join([player, 'average']))
elif 0.9 <= j / len(players) < 0.99:
print(' '.join([player, 'hardcore']))
else:
print(' '.join([player, 'pro']))
``` | 3 | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manhattan considers the distance between watchmen *i* and *j* to be |*x**i*<=-<=*x**j*|<=+<=|*y**i*<=-<=*y**j*|. Daniel, as an ordinary person, calculates the distance using the formula .
The success of the operation relies on the number of pairs (*i*,<=*j*) (1<=≤<=*i*<=<<=*j*<=≤<=*n*), such that the distance between watchman *i* and watchmen *j* calculated by Doctor Manhattan is equal to the distance between them calculated by Daniel. You were asked to compute the number of such pairs. | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs (1, 1), (1, 5) and (7, 5), (1, 5) Doctor Manhattan and Daniel will calculate the same distances. | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,653,284,483 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 71 | 2,480 | 42,598,400 | n = int(input())
p = []
for i in range(n):
p.append(list(map(int, input().split())))
p.sort()
ans = 0
cx, cy, ce = 1, 1, 1
for i in range(1, n):
if(p[i][0] == p[i - 1][0]):
cx += 1
else:
ans += cx * (cx - 1) // 2
cx = 1
ans += cx * (cx - 1) // 2
for i in range(1, n):
if(p[i][0] == p[i - 1][0] and p[i][1] == p[i - 1][1]):
ce += 1
else:
ans -= ce * (ce - 1) // 2
ce = 1
ans -= ce * (ce - 1) // 2
p.sort(key = lambda x : x[1])
for i in range(1, n):
if(p[i][1] == p[i - 1][1]):
cy += 1
else:
ans += cy * (cy - 1) // 2
cy = 1
ans += cy * (cy - 1) // 2
print(ans) | Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manhattan considers the distance between watchmen *i* and *j* to be |*x**i*<=-<=*x**j*|<=+<=|*y**i*<=-<=*y**j*|. Daniel, as an ordinary person, calculates the distance using the formula .
The success of the operation relies on the number of pairs (*i*,<=*j*) (1<=≤<=*i*<=<<=*j*<=≤<=*n*), such that the distance between watchman *i* and watchmen *j* calculated by Doctor Manhattan is equal to the distance between them calculated by Daniel. You were asked to compute the number of such pairs.
Input Specification:
The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide.
Output Specification:
Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel.
Demo Input:
['3\n1 1\n7 5\n1 5\n', '6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n']
Demo Output:
['2\n', '11\n']
Note:
In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs (1, 1), (1, 5) and (7, 5), (1, 5) Doctor Manhattan and Daniel will calculate the same distances. | ```python
n = int(input())
p = []
for i in range(n):
p.append(list(map(int, input().split())))
p.sort()
ans = 0
cx, cy, ce = 1, 1, 1
for i in range(1, n):
if(p[i][0] == p[i - 1][0]):
cx += 1
else:
ans += cx * (cx - 1) // 2
cx = 1
ans += cx * (cx - 1) // 2
for i in range(1, n):
if(p[i][0] == p[i - 1][0] and p[i][1] == p[i - 1][1]):
ce += 1
else:
ans -= ce * (ce - 1) // 2
ce = 1
ans -= ce * (ce - 1) // 2
p.sort(key = lambda x : x[1])
for i in range(1, n):
if(p[i][1] == p[i - 1][1]):
cy += 1
else:
ans += cy * (cy - 1) // 2
cy = 1
ans += cy * (cy - 1) // 2
print(ans)
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,608,296,747 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 216 | 0 | m,n = map(int,input().split(' '))
print(int((m*n)/2)) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
m,n = map(int,input().split(' '))
print(int((m*n)/2))
``` | 3.946 |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1. | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,689,708,846 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 46 | 0 | n,t = map(int, input().split())
l = pow(10,n-1)
if n ==1:
for i in range(1, t+1):
if i % t == 0:
print(i)
break
else:
for i in range(l+1, pow(l,10)):
if i% t == 0:
print(i)
break | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1.
Input Specification:
The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by.
Output Specification:
Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.
Demo Input:
['3 2\n']
Demo Output:
['712']
Note:
none | ```python
n,t = map(int, input().split())
l = pow(10,n-1)
if n ==1:
for i in range(1, t+1):
if i % t == 0:
print(i)
break
else:
for i in range(l+1, pow(l,10)):
if i% t == 0:
print(i)
break
``` | 0 | |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding. | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket. | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,594,828,271 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,656,000 | n, k = [int(x) for x in input().split()]
ns = [int(x) for x in input().split()]
b = max([x for x in ns if n % x == 0])
print(n // b) | Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding.
Input Specification:
The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket.
Output Specification:
Print one integer number — the minimum number of hours required to water the garden.
Demo Input:
['3 6\n2 3 5\n', '6 7\n1 2 3 4 5 6\n']
Demo Output:
['2\n', '7\n']
Note:
In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | ```python
n, k = [int(x) for x in input().split()]
ns = [int(x) for x in input().split()]
b = max([x for x in ns if n % x == 0])
print(n // b)
``` | 0 | |
14 | B | Young Photographer | PROGRAMMING | 1,000 | [
"implementation"
] | B. Young Photographer | 2 | 64 | Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. But the problem was that not all the runners passed him. The total amount of sportsmen, training at that racetrack, equals *n*. And each of them regularly runs distances within a particular segment of the racetrack, which is the same for each sportsman. For example, the first sportsman runs from position *a*1 to position *b*1, the second — from *a*2 to *b*2
What is the minimum distance that Bob should move to have a chance to take pictures of each sportsman? Bob can take a picture of a sportsman, if he stands within the segment that this sportsman covers on the racetrack. | The first line of the input file contains integers *n* and *x*0 (1<=≤<=*n*<=≤<=100; 0<=≤<=*x*0<=≤<=1000). The following *n* lines contain pairs of integers *a**i*,<=*b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000; *a**i*<=≠<=*b**i*). | Output the required minimum distance in the same units as the positions on the racetrack. If there is no such a position, output -1. | [
"3 3\n0 7\n14 2\n4 6\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "3 3\n0 7\n14 2\n4 6",
"output": "1"
},
{
"input": "1 1\n0 10",
"output": "0"
},
{
"input": "2 2\n1 2\n3 2",
"output": "0"
},
{
"input": "3 2\n1 2\n2 3\n3 4",
"output": "-1"
},
{
"input": "2 4\n10 4\n1 5",
"output": "0"
},
{
"input": "1 10\n... | 1,613,669,758 | 2,147,483,647 | PyPy 3 | OK | TESTS | 52 | 218 | 0 | n, x0 = map(int, input().split())
x1, x2 = 0, 1000
for i in range(n):
a, b = map(int, input().split())
x1 = max(x1, min(a, b))
x2 = min(x2, max(a, b))
print(max(0, x1 - x0, x0 - x2) if x2 >= x1 else -1) | Title: Young Photographer
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. But the problem was that not all the runners passed him. The total amount of sportsmen, training at that racetrack, equals *n*. And each of them regularly runs distances within a particular segment of the racetrack, which is the same for each sportsman. For example, the first sportsman runs from position *a*1 to position *b*1, the second — from *a*2 to *b*2
What is the minimum distance that Bob should move to have a chance to take pictures of each sportsman? Bob can take a picture of a sportsman, if he stands within the segment that this sportsman covers on the racetrack.
Input Specification:
The first line of the input file contains integers *n* and *x*0 (1<=≤<=*n*<=≤<=100; 0<=≤<=*x*0<=≤<=1000). The following *n* lines contain pairs of integers *a**i*,<=*b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000; *a**i*<=≠<=*b**i*).
Output Specification:
Output the required minimum distance in the same units as the positions on the racetrack. If there is no such a position, output -1.
Demo Input:
['3 3\n0 7\n14 2\n4 6\n']
Demo Output:
['1\n']
Note:
none | ```python
n, x0 = map(int, input().split())
x1, x2 = 0, 1000
for i in range(n):
a, b = map(int, input().split())
x1 = max(x1, min(a, b))
x2 = min(x2, max(a, b))
print(max(0, x1 - x0, x0 - x2) if x2 >= x1 else -1)
``` | 3.9455 |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem. | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,570,411,840 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 108 | 0 |
def distinctPhotobooks(N):
combinations_adding_one_letter = 26*(len(str_) + 1)
repeated_words = len(str_)
return combinations_adding_one_letter - repeated_words
n = str(input())
print(distinctPhotobooks(n))
| Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?
Please help Haruhi solve this problem.
Input Specification:
The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters.
Output Specification:
Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.
Demo Input:
['a\n', 'hi\n']
Demo Output:
['51\n', '76\n']
Note:
In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | ```python
def distinctPhotobooks(N):
combinations_adding_one_letter = 26*(len(str_) + 1)
repeated_words = len(str_)
return combinations_adding_one_letter - repeated_words
n = str(input())
print(distinctPhotobooks(n))
``` | -1 | |
216 | D | Spider's Web | PROGRAMMING | 1,700 | [
"binary search",
"sortings",
"two pointers"
] | null | null | Paw the Spider is making a web. Web-making is a real art, Paw has been learning to do it his whole life. Let's consider the structure of the web.
There are *n* main threads going from the center of the web. All main threads are located in one plane and divide it into *n* equal infinite sectors. The sectors are indexed from 1 to *n* in the clockwise direction. Sectors *i* and *i*<=+<=1 are adjacent for every *i*, 1<=≤<=*i*<=<<=*n*. In addition, sectors 1 and *n* are also adjacent.
Some sectors have bridge threads. Each bridge connects the two main threads that make up this sector. The points at which the bridge is attached to the main threads will be called attachment points. Both attachment points of a bridge are at the same distance from the center of the web. At each attachment point exactly one bridge is attached. The bridges are adjacent if they are in the same sector, and there are no other bridges between them.
A cell of the web is a trapezoid, which is located in one of the sectors and is bounded by two main threads and two adjacent bridges. You can see that the sides of the cell may have the attachment points of bridges from adjacent sectors. If the number of attachment points on one side of the cell is not equal to the number of attachment points on the other side, it creates an imbalance of pulling forces on this cell and this may eventually destroy the entire web. We'll call such a cell unstable. The perfect web does not contain unstable cells.
Unstable cells are marked red in the figure. Stable cells are marked green.
Paw the Spider isn't a skillful webmaker yet, he is only learning to make perfect webs. Help Paw to determine the number of unstable cells in the web he has just spun. | The first line contains integer *n* (3<=≤<=*n*<=≤<=1000) — the number of main threads.
The *i*-th of following *n* lines describe the bridges located in the *i*-th sector: first it contains integer *k**i* (1<=≤<=*k**i*<=≤<=105) equal to the number of bridges in the given sector. Then follow *k**i* different integers *p**ij* (1<=≤<=*p**ij*<=≤<=105; 1<=≤<=*j*<=≤<=*k**i*). Number *p**ij* equals the distance from the attachment points of the *j*-th bridge of the *i*-th sector to the center of the web.
It is guaranteed that any two bridges between adjacent sectors are attached at a different distance from the center of the web. It is guaranteed that the total number of the bridges doesn't exceed 105. | Print a single integer — the number of unstable cells in Paw the Spider's web. | [
"7\n3 1 6 7\n4 3 5 2 9\n2 8 1\n4 3 7 6 4\n3 2 5 9\n3 6 3 8\n3 4 2 9\n"
] | [
"6"
] | none | 2,000 | [
{
"input": "7\n3 1 6 7\n4 3 5 2 9\n2 8 1\n4 3 7 6 4\n3 2 5 9\n3 6 3 8\n3 4 2 9",
"output": "6"
},
{
"input": "3\n1 1\n1 2\n1 3",
"output": "0"
},
{
"input": "3\n2 1 2\n2 3 4\n2 5 6",
"output": "0"
},
{
"input": "5\n3 2 4 10\n2 1 6\n2 8 7\n3 2 4 10\n2 1 6",
"output": "2"
... | 1,680,636,002 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | from bisect import bisect_left as left
from bisect import bisect_right as right
n = int(raw_input())
B = [[x for x in sorted(int(i) for i in raw_input().split()[1:])] for i in xrange(n)]
ct = 0
for i in xrange(-1, n-1):
for j in xrange(1, len(B[i])):
if right(B[i+1], B[i][j])-left(B[i+1], B[i][j-1]) != \
right(B[i-1], B[i][j])-left(B[i-1], B[i][j-1]):
ct += 1
print ct
| Title: Spider's Web
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Paw the Spider is making a web. Web-making is a real art, Paw has been learning to do it his whole life. Let's consider the structure of the web.
There are *n* main threads going from the center of the web. All main threads are located in one plane and divide it into *n* equal infinite sectors. The sectors are indexed from 1 to *n* in the clockwise direction. Sectors *i* and *i*<=+<=1 are adjacent for every *i*, 1<=≤<=*i*<=<<=*n*. In addition, sectors 1 and *n* are also adjacent.
Some sectors have bridge threads. Each bridge connects the two main threads that make up this sector. The points at which the bridge is attached to the main threads will be called attachment points. Both attachment points of a bridge are at the same distance from the center of the web. At each attachment point exactly one bridge is attached. The bridges are adjacent if they are in the same sector, and there are no other bridges between them.
A cell of the web is a trapezoid, which is located in one of the sectors and is bounded by two main threads and two adjacent bridges. You can see that the sides of the cell may have the attachment points of bridges from adjacent sectors. If the number of attachment points on one side of the cell is not equal to the number of attachment points on the other side, it creates an imbalance of pulling forces on this cell and this may eventually destroy the entire web. We'll call such a cell unstable. The perfect web does not contain unstable cells.
Unstable cells are marked red in the figure. Stable cells are marked green.
Paw the Spider isn't a skillful webmaker yet, he is only learning to make perfect webs. Help Paw to determine the number of unstable cells in the web he has just spun.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=1000) — the number of main threads.
The *i*-th of following *n* lines describe the bridges located in the *i*-th sector: first it contains integer *k**i* (1<=≤<=*k**i*<=≤<=105) equal to the number of bridges in the given sector. Then follow *k**i* different integers *p**ij* (1<=≤<=*p**ij*<=≤<=105; 1<=≤<=*j*<=≤<=*k**i*). Number *p**ij* equals the distance from the attachment points of the *j*-th bridge of the *i*-th sector to the center of the web.
It is guaranteed that any two bridges between adjacent sectors are attached at a different distance from the center of the web. It is guaranteed that the total number of the bridges doesn't exceed 105.
Output Specification:
Print a single integer — the number of unstable cells in Paw the Spider's web.
Demo Input:
['7\n3 1 6 7\n4 3 5 2 9\n2 8 1\n4 3 7 6 4\n3 2 5 9\n3 6 3 8\n3 4 2 9\n']
Demo Output:
['6']
Note:
none | ```python
from bisect import bisect_left as left
from bisect import bisect_right as right
n = int(raw_input())
B = [[x for x in sorted(int(i) for i in raw_input().split()[1:])] for i in xrange(n)]
ct = 0
for i in xrange(-1, n-1):
for j in xrange(1, len(B[i])):
if right(B[i+1], B[i][j])-left(B[i+1], B[i][j-1]) != \
right(B[i-1], B[i][j])-left(B[i-1], B[i][j-1]):
ct += 1
print ct
``` | -1 | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,590,308,594 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 1 | 187 | 2,048,000 | import sys
def solve(n, a):
t = [0] * (n + 1)
a = [0] + a
for i in range(1, n + 1):
if a[i] > a[i - 1]:
t[i] = t[i - 1] + 1
else:
t[i] = 1
r = 0
for i in range(1, n + 1):
r = max(r, t[i])
cur_max = t[i]
if a[i - cur_max] > t[i] and a[i - cur_max - 1] < a[i - cur_max + 1]:
new_max = t[i] + 1 + t[i - cur_max - 1]
r = max(r, new_max)
elif a[i - cur_max] < a[i - cur_max + 2]:
new_max = t[i] + t[i - cur_max]
r = max(r, new_max)
return r
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().strip().split()))
r = solve(n, a)
print(r)
| Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
In a single line print the answer to the problem — the maximum length of the required subsegment.
Demo Input:
['6\n7 2 3 1 5 6\n']
Demo Output:
['5\n']
Note:
You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | ```python
import sys
def solve(n, a):
t = [0] * (n + 1)
a = [0] + a
for i in range(1, n + 1):
if a[i] > a[i - 1]:
t[i] = t[i - 1] + 1
else:
t[i] = 1
r = 0
for i in range(1, n + 1):
r = max(r, t[i])
cur_max = t[i]
if a[i - cur_max] > t[i] and a[i - cur_max - 1] < a[i - cur_max + 1]:
new_max = t[i] + 1 + t[i - cur_max - 1]
r = max(r, new_max)
elif a[i - cur_max] < a[i - cur_max + 2]:
new_max = t[i] + t[i - cur_max]
r = max(r, new_max)
return r
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().strip().split()))
r = solve(n, a)
print(r)
``` | -1 |
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