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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with. String a is the divisor of string b if and only if the...
instruction
0
46,546
0
93,092
Yes
output
1
46,546
0
93,093
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with. String a is the divisor of string b if and only if the...
instruction
0
46,547
0
93,094
No
output
1
46,547
0
93,095
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with. String a is the divisor of string b if and only if the...
instruction
0
46,548
0
93,096
No
output
1
46,548
0
93,097
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with. String a is the divisor of string b if and only if the...
instruction
0
46,549
0
93,098
No
output
1
46,549
0
93,099
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with. String a is the divisor of string b if and only if the...
instruction
0
46,550
0
93,100
No
output
1
46,550
0
93,101
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Santa Claus likes palindromes very much. There was his birthday recently. k of his friends came to him to congratulate him, and each of them presented to him a string si having the same length n...
instruction
0
46,744
0
93,488
No
output
1
46,744
0
93,489
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Santa Claus likes palindromes very much. There was his birthday recently. k of his friends came to him to congratulate him, and each of them presented to him a string si having the same length n...
instruction
0
46,745
0
93,490
No
output
1
46,745
0
93,491
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Santa Claus likes palindromes very much. There was his birthday recently. k of his friends came to him to congratulate him, and each of them presented to him a string si having the same length n...
instruction
0
46,747
0
93,494
No
output
1
46,747
0
93,495
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,776
0
93,552
Tags: binary search, implementation, two pointers Correct Solution: ``` s=input() s1=set() for i in s: s1.add(i) l1=list(s1) an=len(s) for i in l1: st=-1 mx=0 for j in range(len(s)): if s[j]==i: mx=max(mx,j-st) st=j mx=max(mx,len(s)-st) an=min(an,mx) print(an) ```
output
1
46,776
0
93,553
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,777
0
93,554
Tags: binary search, implementation, two pointers Correct Solution: ``` import sys,math s=input() n=len(s) a=[[0] for i in range(26)] for i in range(n): a[ord(s[i])-97].append(i+1) for i in range(26): a[i].append(n+1) ans=n+1 for i in range(26): cur=0 for j in range(1,len(a[i])): cur=max(cu...
output
1
46,777
0
93,555
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,778
0
93,556
Tags: binary search, implementation, two pointers Correct Solution: ``` from math import ceil s=input() def isgood(k): d={} q=set(s[:k]) for x in range(26): d[chr(x+ord('a'))]=0 for x in range(k): d[s[x]]+=1 for x in range(k,len(s)): d[s[x-k]]-=1 d[s[x]]+=1 tm...
output
1
46,778
0
93,557
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,779
0
93,558
Tags: binary search, implementation, two pointers Correct Solution: ``` """ Author - Satwik Tiwari . 19th Jan , 2021 - Tuesday """ #=============================================================================================== #importing some useful libraries. from __future__ import division, print_function...
output
1
46,779
0
93,559
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,780
0
93,560
Tags: binary search, implementation, two pointers Correct Solution: ``` alphavite = 'abcdefghijklmnopqrstyvwxyz' s=input() minimal= len(s)+1 for i in alphavite: l= -1 maxl=0 for j in range (len(s)): if s[j]== i: maxl=max(maxl,j-l) l=j maxl=max(maxl,len(s)-l) minimal =...
output
1
46,780
0
93,561
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,781
0
93,562
Tags: binary search, implementation, two pointers Correct Solution: ``` s=input() c=float('Inf') for chr in set(s): l=0 for j in s.split(chr): l=max(l,len(j)) c=min(l,c) print(c+1) ```
output
1
46,781
0
93,563
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,782
0
93,564
Tags: binary search, implementation, two pointers Correct Solution: ``` s = input().strip() memomin = dict() memolast = dict() for i,e in enumerate(s): if e not in memomin: memomin[e] = i+1 memolast[e] = i else: memomin[e] = max(memomin[e], i - memolast[e]) memolast[e] = i for...
output
1
46,782
0
93,565
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minimum k such that there exists at least one k-domi...
instruction
0
46,783
0
93,566
Tags: binary search, implementation, two pointers Correct Solution: ``` import sys import math def check(L): vis = [True for i in range(26)] cnt = [0 for i in range(26)] for i in range(L): val = s[i] cnt[val] += 1 for i in range(len(cnt)): if not cnt[i]: vis[i] = Fal...
output
1
46,783
0
93,567
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,784
0
93,568
Yes
output
1
46,784
0
93,569
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,785
0
93,570
Yes
output
1
46,785
0
93,571
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,786
0
93,572
Yes
output
1
46,786
0
93,573
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,787
0
93,574
Yes
output
1
46,787
0
93,575
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,788
0
93,576
No
output
1
46,788
0
93,577
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,789
0
93,578
No
output
1
46,789
0
93,579
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,790
0
93,580
No
output
1
46,790
0
93,581
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of lowercase Latin letters. Character c is called k-dominant iff each substring of s with length at least k contains this character c. You have to find minim...
instruction
0
46,791
0
93,582
No
output
1
46,791
0
93,583
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,173
0
94,346
Tags: brute force, implementation, strings Correct Solution: ``` #!/usr/bin/env python3 target = "abacaba" def count(s): c = 0 for i in range(len(s) - len(target) + 1): c += (s[i:(i + len(target))] == target) return c def main(): t = int(input()) for _ in range(t): n = int(input(...
output
1
47,173
0
94,347
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,174
0
94,348
Tags: brute force, implementation, strings Correct Solution: ``` import math import collections def check(n,s): cnt = 0 for i in range(len(s)): if "".join(s[i:i+7]) == 'abacaba': cnt+=1 return cnt t = int(input()) for i in range(t): ...
output
1
47,174
0
94,349
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,175
0
94,350
Tags: brute force, implementation, strings Correct Solution: ``` import re t='abacaba' for s in[*open(0)][2::2]: i=0;f=1 while 1: q,f=re.subn(''.join(rf'({x}|\?)'for x in t),t,s[i:],1);q=s[:i]+q;i+=1 if f<1or q.find(t,q.find(t)+1)<0:break print(*(['NO'],['YES',q.replace('?','d')])[f]) ```
output
1
47,175
0
94,351
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,176
0
94,352
Tags: brute force, implementation, strings Correct Solution: ``` t = "abacaba" def count(s): cnt = 0 s = "".join(map(str,s)) for i in range(len(s)): if s[i:i+len(t)] == t: cnt += 1 return cnt def solve(n,s): ss = [] for i in range(n): ss.append(s[i]) temp = ss...
output
1
47,176
0
94,353
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,177
0
94,354
Tags: brute force, implementation, strings Correct Solution: ``` import sys import math import bisect from sys import stdin, stdout from math import gcd, floor, sqrt, log from collections import defaultdict as dd from bisect import bisect_left as bl, bisect_right as br from collections import Counter #sys.setrecursionl...
output
1
47,177
0
94,355
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,178
0
94,356
Tags: brute force, implementation, strings Correct Solution: ``` import sys input = sys.stdin.readline want = 'abacaba' T = int(input()) for _ in range(T): n = int(input()) s = input().strip() l = list(s) for i in range(n - 6): ll = l[:] works = True for c in range(7): ...
output
1
47,178
0
94,357
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,179
0
94,358
Tags: brute force, implementation, strings Correct Solution: ``` import re cases = int(input()) output = '' for t in range(cases): n = int(input()) s = input() # if t == 178: # print(n,s) f1 = s.find('abacaba') f2 = s.find('abacaba',f1+1) if f1>-1 and f2>-1: output += 'No\n' ...
output
1
47,179
0
94,359
Provide tags and a correct Python 3 solution for this coding contest problem. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English l...
instruction
0
47,180
0
94,360
Tags: brute force, implementation, strings Correct Solution: ``` def solve(): target = "abacaba" target_with_z = "abazaba" n = int(input()) s = input() for i in range(n - 6): possible = True for j in range(7): if not (s[i + j] == "?" or s[i + j] == target[j]): possible = False if possible and (s[:i] ...
output
1
47,180
0
94,361
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,181
0
94,362
Yes
output
1
47,181
0
94,363
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,182
0
94,364
Yes
output
1
47,182
0
94,365
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,183
0
94,366
Yes
output
1
47,183
0
94,367
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,184
0
94,368
Yes
output
1
47,184
0
94,369
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,185
0
94,370
No
output
1
47,185
0
94,371
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,186
0
94,372
No
output
1
47,186
0
94,373
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,187
0
94,374
No
output
1
47,187
0
94,375
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Acacius is studying strings theory. Today he came with the following problem. You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to ...
instruction
0
47,188
0
94,376
No
output
1
47,188
0
94,377
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,237
0
94,474
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` def solve(n, m, s, t): idx = [0] * m j = 0 for i in range(n): if j < m and t[j] == s[i]: idx[j] = i j += 1 res = 0 j = m - 1 for i in range(n - 1, -1, -1): if j >= 0 and t...
output
1
47,237
0
94,475
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,238
0
94,476
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` n,m=map(int,input().split()) a,b,q,w,e=input(),input(),[],[],0 for i in range(n): if b[e]==a[i]:q+=[i];e+=1 if e==m:break e-=1 for i in range(n-1,-1,-1): if b[e]==a[i]:w+=[i];e-=1 if e==-1:break w=w[::-1] print(max(w[i+...
output
1
47,238
0
94,477
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,239
0
94,478
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` #!/usr/bin/env python3.9 def findmax(s, t): l_indexies = [] start = 0 for c in t: idx = s.find(c, start) l_indexies.append(idx) start = idx + 1 r_indexies = [] end = len(s) for c in rev...
output
1
47,239
0
94,479
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,240
0
94,480
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` import math from bisect import bisect_right from bisect import bisect_left from collections import defaultdict n,m=map(int,input().split()) s=input() k=input() a=[] b=[] for j in s: a.append(j) for j in k: b.append(j) i...
output
1
47,240
0
94,481
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,241
0
94,482
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` def main(): n, m = map(int, input().split()) s = str(input()) t = str(input()) from collections import deque, defaultdict import bisect X = [[] for i in range(26)] for i, c in enumerate(s): c = ord...
output
1
47,241
0
94,483
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,242
0
94,484
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` for u in range(1): n, m = map(int, input().split()) s = input() t = input() left = [] right = [] p = 0 for i in range(n): if(s[i] == t[p]): left.append(i) p += 1 if(p == m): break p = m-1 for i in range(n-1,...
output
1
47,242
0
94,485
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,243
0
94,486
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` n,m = map(int,input().split(' ')) s = [w for w in input()] t = [w for w in input()] left = [] j = 0 for i in range(n): if s[i] == t[j]: left.append(i) j = j + 1 if j>=m: break right = [] i = n - 1 j =...
output
1
47,243
0
94,487
Provide tags and a correct Python 3 solution for this coding contest problem. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 < p_2 < … < p_m ≤ n, is called beautiful, if s_{...
instruction
0
47,244
0
94,488
Tags: binary search, data structures, dp, greedy, two pointers Correct Solution: ``` a, b = map(int, input().split()) s = input() t = input() l1 = len(s) l2 = len(t) p1 = [] pos1 = 0 pos2 = 0 while(pos1 < l1 and pos2 < l2): if(s[pos1] == t[pos2]): p1.append(pos1) pos2 += 1 pos1 += 1 p2 = [] pos1...
output
1
47,244
0
94,489
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 <...
instruction
0
47,245
0
94,490
Yes
output
1
47,245
0
94,491
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Your classmate, whom you do not like because he is boring, but whom you respect for his intellect, has two strings: s of length n and t of length m. A sequence p_1, p_2, …, p_m, where 1 ≤ p_1 <...
instruction
0
47,246
0
94,492
Yes
output
1
47,246
0
94,493