message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply the following operations any number of times:
... | instruction | 0 | 50,255 | 0 | 100,510 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
[n, x, y] = [int(x) for x in input().split()]
A = input()
if len(A) == 1:
if A[0] == "1":
print("0")
else:
print(y)
else:
c = 0
if A[0] == "0":
c = 1
for i in range(1, len(A)):
if A[i] == "0... | output | 1 | 50,255 | 0 | 100,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply the following operations any number of times:
... | instruction | 0 | 50,256 | 0 | 100,512 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
n,x,y=map(int,input().strip().split())
count=0
r=input()
if r[0]=="0":
count=count+1
for i in range(1,n):
if r[i]=="0" and r[i-1]!="0":
count=count+1
if count==0:
print (0)
exit(0)
else:
if y<x:
print (y*count)
else:
print (x*(count-1)+y)... | output | 1 | 50,256 | 0 | 100,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,257 | 0 | 100,514 |
Yes | output | 1 | 50,257 | 0 | 100,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,258 | 0 | 100,516 |
Yes | output | 1 | 50,258 | 0 | 100,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,259 | 0 | 100,518 |
Yes | output | 1 | 50,259 | 0 | 100,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,260 | 0 | 100,520 |
Yes | output | 1 | 50,260 | 0 | 100,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,261 | 0 | 100,522 |
No | output | 1 | 50,261 | 0 | 100,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,262 | 0 | 100,524 |
No | output | 1 | 50,262 | 0 | 100,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,263 | 0 | 100,526 |
No | output | 1 | 50,263 | 0 | 100,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.
Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a.
You can apply ... | instruction | 0 | 50,264 | 0 | 100,528 |
No | output | 1 | 50,264 | 0 | 100,529 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,349 | 0 | 100,698 |
"Correct Solution:
```
L = int(input())
Ss = input()
Ts = input()
if Ss+Ts > Ts+Ss:
Ss, Ts = Ts, Ss
lenS, lenT = len(Ss), len(Ts)
for numS in reversed(range(L//lenS+1)):
numT = (L-lenS*numS) / lenT
if int(numT) == numT:
ans = Ss*numS + Ts*int(numT)
print(ans)
break
``` | output | 1 | 50,349 | 0 | 100,699 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,350 | 0 | 100,700 |
"Correct Solution:
```
l = int(input())
a = input()
b = input()
if len(a) > len(b):
k = b
b = a
a = k
mina = None
maxa = None
"""
f = [None] * (l + 1)
f[0] = ''
#print(f)
for i in range(l):
tmpa = None
tmpb = None
if i + 1 >= len(a) and f[i + 1 - len(a)] is not None:
tmpa = a + f[i + ... | output | 1 | 50,350 | 0 | 100,701 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,351 | 0 | 100,702 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
from fractions import gcd
L = int(readline())
S = readline().rstrip().decode('utf-8')
T = readline().rstrip().decode('utf-8')
ST = S + T
TS = T + S
if ST > TS:
S,T = T,S
# S... | output | 1 | 50,351 | 0 | 100,703 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,352 | 0 | 100,704 |
"Correct Solution:
```
def main():
L = int(input())
S, T = (input() for _ in [0] * 2)
ans = []
apnd = ans.append
a = S
b = T
i = 0
for _ in [0] * 2:
while 1:
x = L - (len(b) * i)
div_, mod_ = divmod(x, len(a))
if not mod_:
apnd... | output | 1 | 50,352 | 0 | 100,705 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,353 | 0 | 100,706 |
"Correct Solution:
```
def solve(l, s, t):
queue = [(1, 0), (0, 1)]
def gcd(a, b):
r = a % b
if r:
d = a // b
sb = queue.pop()
sa = queue.pop()
queue.append(sb)
queue.append(tuple(x - d * y for x, y in zip(sa, sb)))
return ... | output | 1 | 50,353 | 0 | 100,707 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,354 | 0 | 100,708 |
"Correct Solution:
```
n=int(input())
a=sorted([input()for i in range(2)])
s,t=len(a[0]),len(a[1])
c=[]
for i in range(n):
if (n-i*t)%s==0:
c.append(a[0]*((n-i*t)//s)+a[1]*i)
break
for i in range(n):
if (n-i*s)%t==0:
c.append(a[1]*((n-i*s)//t)+a[0]*i)
break
print(sorted(c)[0])
``... | output | 1 | 50,354 | 0 | 100,709 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
... | instruction | 0 | 50,355 | 0 | 100,710 |
"Correct Solution:
```
L = int(input())
s = input()
t = input()
if not s+t <= t+s:
s, t = t, s
ls = len(s); lt = len(t)
for i in range(L // ls, -1, -1):
if (L - ls*i) % lt == 0:
ans = s * i + t * ((L - ls*i) // lt)
break
print(ans)
``` | output | 1 | 50,355 | 0 | 100,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here... | instruction | 0 | 50,357 | 0 | 100,714 |
No | output | 1 | 50,357 | 0 | 100,715 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,360 | 0 | 100,720 |
"Correct Solution:
```
S=input()
L=len(S)//2-1
while S[:L]!=S[L:2*L]:
L-=1
print(2*L)
``` | output | 1 | 50,360 | 0 | 100,721 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,361 | 0 | 100,722 |
"Correct Solution:
```
S = input()[:-1]
while S[:len(S)//2] != S[len(S)//2:]:
S = S[:-1]
print(len(S))
``` | output | 1 | 50,361 | 0 | 100,723 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,362 | 0 | 100,724 |
"Correct Solution:
```
import re
S = input()
m = re.search(r'\A([a-z]+)\1', S[:len(S) - 1])
print(len(m.group(0)))
``` | output | 1 | 50,362 | 0 | 100,725 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,363 | 0 | 100,726 |
"Correct Solution:
```
s = input()[:-2]
ls = len(s) // 2
while s[:ls] != s[ls:]:
ls -= 1
s = s[:-2]
print(ls*2)
``` | output | 1 | 50,363 | 0 | 100,727 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,364 | 0 | 100,728 |
"Correct Solution:
```
s = list(input())
s = s[:-1]
while s[:len(s)//2] != s[len(s)//2 :]:
s = s[:-1]
# print(s)
print(len(s))
``` | output | 1 | 50,364 | 0 | 100,729 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,365 | 0 | 100,730 |
"Correct Solution:
```
S = input()
S = S[:-2]
while S[:len(S)//2] != S[len(S)//2:]:
S = S[:-2]
print(len(S))
``` | output | 1 | 50,365 | 0 | 100,731 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,366 | 0 | 100,732 |
"Correct Solution:
```
s = input()
for k in range(len(s)//2-1, 0, -1):
if s[:k] == s[k:2*k]: break
print(k*2)
``` | output | 1 | 50,366 | 0 | 100,733 |
Provide a correct Python 3 solution for this coding contest problem.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an even string S consisting of lowercase English letters. Fi... | instruction | 0 | 50,367 | 0 | 100,734 |
"Correct Solution:
```
s=input()[:-2]
while s[:len(s)//2] != s[len(s)//2:]:
s=s[:len(s)-2]
print(len(s))
``` | output | 1 | 50,367 | 0 | 100,735 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,368 | 0 | 100,736 |
Yes | output | 1 | 50,368 | 0 | 100,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,369 | 0 | 100,738 |
Yes | output | 1 | 50,369 | 0 | 100,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,370 | 0 | 100,740 |
Yes | output | 1 | 50,370 | 0 | 100,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,371 | 0 | 100,742 |
Yes | output | 1 | 50,371 | 0 | 100,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,372 | 0 | 100,744 |
No | output | 1 | 50,372 | 0 | 100,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,373 | 0 | 100,746 |
No | output | 1 | 50,373 | 0 | 100,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,374 | 0 | 100,748 |
No | output | 1 | 50,374 | 0 | 100,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will call a string that can be obtained by concatenating two equal strings an even string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.
You are given an e... | instruction | 0 | 50,375 | 0 | 100,750 |
No | output | 1 | 50,375 | 0 | 100,751 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,392 | 0 | 100,784 |
"Correct Solution:
```
s = list(input())
K = int(input())
for i in range(len(s)):
if s[i] == "a":
pass
elif 123 - ord(s[i]) <= K:
K -= (123 - ord(s[i]))
s[i] = 'a'
K = K % 26
while K > 0:
K -= 1
if s[-1] == "z":
s[-1] = "a"
else:
s[-1] = chr(ord(s[-1]) + 1)
... | output | 1 | 50,392 | 0 | 100,785 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,393 | 0 | 100,786 |
"Correct Solution:
```
s=input()
K=int(input())
S=[c for c in s]
def diff(c):
return ord('z')-ord(c)
for i in range(len(s)):
d=diff(S[i])
if d<min(25,K):
K-=d+1
S[i]='a'
k=K%26
S[-1]=chr(ord(S[-1])+k) if k<=diff(S[-1]) else chr(ord(S[-1])+k-26)
print(''.join(S))
``` | output | 1 | 50,393 | 0 | 100,787 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,394 | 0 | 100,788 |
"Correct Solution:
```
s=input()
k=int(input())
a=[]
for t in s[:-1]:
c=123-ord(t)
if k<c or t=='a':
a.append(t)
else:
k-=c
a.append('a')
a.append(chr((ord(s[-1])-97+k)%26+97))
print(''.join(a))
``` | output | 1 | 50,394 | 0 | 100,789 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,395 | 0 | 100,790 |
"Correct Solution:
```
s = input()
K = int(input())
s = list(s)
# print(diff)
for i in range(len(s)):
if s[i] != 'a':
dist = ord('z') - ord(s[i]) + 1
if dist <= K:
K -= dist
s[i] = 'a'
# print(s)
temp = K % 26
s[-1] = chr(ord(s[-1]) + temp)
# print(s)
print(''.join(s))
... | output | 1 | 50,395 | 0 | 100,791 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,396 | 0 | 100,792 |
"Correct Solution:
```
l = list(input())
k = int(input())
for i in range(len(l)):
if l[i] == "a":
continue
if 123 - ord(l[i]) <= k:
k -= 123 - ord(l[i])
l[i] = "a"
k %= 26
l[-1] = chr((ord(l[-1])-97+k)%26+97)
print("".join(l))
``` | output | 1 | 50,396 | 0 | 100,793 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,397 | 0 | 100,794 |
"Correct Solution:
```
s = input().strip()
k = int(input())
ans = ''
for _s in s[:-1]:
if _s == 'a':
ans += 'a'
elif 26 - ord(_s) + ord('a') <= k:
ans += 'a'
k -= 26 - ord(_s) + ord('a')
else:
ans += _s
ans += chr(ord('a') + (ord(s[-1]) - ord('a') + k) % 26)
print(ans)
``` | output | 1 | 50,397 | 0 | 100,795 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,398 | 0 | 100,796 |
"Correct Solution:
```
s=input()
l=len(s)
k=int(input())
z=''
for i in range(l):
t=123-ord(s[i])
if s[i]=='a':
z+='a'
elif t<=k:
z+='a'
k-=t
else:
z+=s[i]
v=ord(z[l-1])-97+k
z=z[:l-1]+chr(v%26+97)
print(z)
``` | output | 1 | 50,398 | 0 | 100,797 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
... | instruction | 0 | 50,399 | 0 | 100,798 |
"Correct Solution:
```
s = list(input())
k = int(input())
for i in range(len(s)):
if ord("z")-ord(s[i])+1<=k:
k -= (ord("z")-ord(s[i])+1)%26
s[i] = "a"
if k: s[-1] = chr((ord(s[-1])+k-ord("a"))%26+ord("a"))
print("".join(s))
``` | output | 1 | 50,399 | 0 | 100,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,508 | 0 | 101,016 |
Tags: greedy, strings
Correct Solution:
```
import os, sys, bisect
from collections import defaultdict, Counter, deque;
from functools import lru_cache #use @lru_cache(None)
if os.path.exists('in.txt'): sys.stdin=open('in.txt','r')
if os.path.exists('out.txt'): sys.stdout=open('out.txt', 'w')
#
input = lambda: sys.st... | output | 1 | 50,508 | 0 | 101,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,509 | 0 | 101,018 |
Tags: greedy, strings
Correct Solution:
```
n, k = map(int, input().split())
a = input()
b = input()
res = 0
ans = 0
for i in range(0, n):
res = min(res * 2 + (b[i] == 'b') - (a[i] == 'b'), k)
ans += min(res + 1, k)
print(ans)
``` | output | 1 | 50,509 | 0 | 101,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,510 | 0 | 101,020 |
Tags: greedy, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in f... | output | 1 | 50,510 | 0 | 101,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,511 | 0 | 101,022 |
Tags: greedy, strings
Correct Solution:
```
n,k=map(int,input().split())
a=input().strip()
b=input().strip()
add=1
count=0
for i in range(n):
if a[i]==b[i]:
add=add*2-1
elif a[i]=="a" and b[i]=="b":
add=add*2
else:
add=add*2-2
if add>k:
count+=(n-i)*k
break
co... | output | 1 | 50,511 | 0 | 101,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,512 | 0 | 101,024 |
Tags: greedy, strings
Correct Solution:
```
n,k=map(int,input().split())
s=input()
t=input()
res,tp=0,1
for i in range(n):
tp*=2
if s[i]=='b':
tp-=1
if t[i]=='a':
tp-=1
res+=min(tp,k)
tp=min(tp,1e9)
print(res)
``` | output | 1 | 50,512 | 0 | 101,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,513 | 0 | 101,026 |
Tags: greedy, strings
Correct Solution:
```
# x = int(input())
# m, n = map(int, input().split())
# nums = list(map(int, input().split()))
n,k=map(int,input().split())
s1=input()
s2=input()
cnt=1
ans=0
for i in range(n):
cnt*=2
if s1[i]=='b':
cnt-=1
if s2[i]=='a':
cnt-=1
cnt=min(1e18+7,c... | output | 1 | 50,513 | 0 | 101,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,514 | 0 | 101,028 |
Tags: greedy, strings
Correct Solution:
```
n,k=map(int,input().split())
a=input().strip()
b=input().strip()
add=1
count=0
for i in range(n):
add*=2
if a[i]=='b':
add-=1
if b[i]=='a':
add-=1
if add>k:
count+=(n-i)*k
break
count+=add
print(count)
``` | output | 1 | 50,514 | 0 | 101,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, the Fair Nut has written k strings of length n, consisting of letters "a" and "b". He calculated c — the number of strings that are prefixes of at least one of the written strings. Every string was counted only one time.
Then, he ... | instruction | 0 | 50,515 | 0 | 101,030 |
Tags: greedy, strings
Correct Solution:
```
def ii():
return int(input())
def mi():
return map(int, input().split())
def li():
return list(mi())
# B. The Fair Nut and Strings
n, k = mi()
s = input().strip()
t = input().strip()
ans = 0
jj = 0
for i in range(n):
if s[i] == t[i]:
ans += 1
... | output | 1 | 50,515 | 0 | 101,031 |
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