message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,643 | 0 | 25,286 |
Yes | output | 1 | 12,643 | 0 | 25,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,644 | 0 | 25,288 |
Yes | output | 1 | 12,644 | 0 | 25,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,645 | 0 | 25,290 |
Yes | output | 1 | 12,645 | 0 | 25,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,646 | 0 | 25,292 |
No | output | 1 | 12,646 | 0 | 25,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,647 | 0 | 25,294 |
No | output | 1 | 12,647 | 0 | 25,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,648 | 0 | 25,296 |
No | output | 1 | 12,648 | 0 | 25,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 12,649 | 0 | 25,298 |
No | output | 1 | 12,649 | 0 | 25,299 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,654 | 0 | 25,308 |
Tags: dp, strings
Correct Solution:
```
def make_array(n, m):
new_arr = []
for _ in range(n):
new_arr += [[0] * m]
return new_arr
def catching_cheaters():
n, m = [int(x) for x in input().split(' ')]
str_a = input()
str_b = input()
dp = make_array(n + 1, m + 1)
ans = 0
for... | output | 1 | 12,654 | 0 | 25,309 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,655 | 0 | 25,310 |
Tags: dp, strings
Correct Solution:
```
import sys
import os
from io import BytesIO, IOBase
#Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mo... | output | 1 | 12,655 | 0 | 25,311 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,656 | 0 | 25,312 |
Tags: dp, strings
Correct Solution:
```
from collections import deque
n,m = list(map(int,input().split()))
a = input()
b = input()
l1 = len(a)
l2 = len(b)
dp = [[0 for j in range(l2+1)] for i in range(l1+1)]
mv = 0
for i in range(1,l1+1):
for j in range(1,l2+1):
if a[i-1]==b[j-1]:
dp[i][j] = dp[... | output | 1 | 12,656 | 0 | 25,313 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,657 | 0 | 25,314 |
Tags: dp, strings
Correct Solution:
```
# coding: utf-8
n, m = map(int, input().split())
a = input()
b = input()
dp = [[0 for j in range(m + 1)] for i in range(n + 1)]
maximal = 0
for i in range(1, n + 1):
for j in range(1, m + 1):
dp[i][j] = max(dp[i - 1][j] - 1, dp[i][j - 1] - 1, dp[i - 1][j - 1] + 2 if a[i -... | output | 1 | 12,657 | 0 | 25,315 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,658 | 0 | 25,316 |
Tags: dp, strings
Correct Solution:
```
n,m=map(int,input().split())
a=input()
b=input()
dp=[[0 for i in range(m+1)] for j in range(n+1)]
ans=0
for i in range(1,n+1):
for j in range(1,m+1):
if a[i-1]==b[j-1]:
dp[i][j]=max(dp[i][j],dp[i-1][j-1]+2)
ans=max(ans,dp[i][j])
else:
... | output | 1 | 12,658 | 0 | 25,317 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,659 | 0 | 25,318 |
Tags: dp, strings
Correct Solution:
```
''' ===============================
-- @uthor : Kaleab Asfaw
-- Handle : kaleabasfaw2010
-- Bio : High-School Student
==============================='''
# Fast IO
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newl... | output | 1 | 12,659 | 0 | 25,319 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,660 | 0 | 25,320 |
Tags: dp, strings
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import threading
from bisect import bisect_right
from math import gcd,log
from collections import Counter,defaultdict
from pprint import pprint
def lcs(a,b):
ans=0
dp=[[0]*(len(b)+1) for i ... | output | 1 | 12,660 | 0 | 25,321 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, where LCS(C,D) denotes the length of the Longest C... | instruction | 0 | 12,661 | 0 | 25,322 |
Tags: dp, strings
Correct Solution:
```
#include <CodeforcesSolutions.h>
#include <ONLINE_JUDGE <solution.cf(contestID = "1447",questionID = "A",method = "GET")>.h>
"""
Author : thekushalghosh
Team : CodeDiggers
I prefer Python language over the C++ language :p :D
Visit my website : thekush... | output | 1 | 12,661 | 0 | 25,323 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,662 | 0 | 25,324 |
Yes | output | 1 | 12,662 | 0 | 25,325 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,663 | 0 | 25,326 |
Yes | output | 1 | 12,663 | 0 | 25,327 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,664 | 0 | 25,328 |
Yes | output | 1 | 12,664 | 0 | 25,329 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,665 | 0 | 25,330 |
Yes | output | 1 | 12,665 | 0 | 25,331 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,666 | 0 | 25,332 |
No | output | 1 | 12,666 | 0 | 25,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,667 | 0 | 25,334 |
No | output | 1 | 12,667 | 0 | 25,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,668 | 0 | 25,336 |
No | output | 1 | 12,668 | 0 | 25,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings A and B representing essays of two students who are suspected cheaters. For any two strings C, D we define their similarity score S(C,D) as 4⋅ LCS(C,D) - |C| - |D|, whe... | instruction | 0 | 12,669 | 0 | 25,338 |
No | output | 1 | 12,669 | 0 | 25,339 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,160 | 0 | 26,320 |
"Correct Solution:
```
N = int(input())
*A, = map(int, input().split())
def check(K):
st = []
for i, a in enumerate(A):
#print(K, i, st, a)
while st and a < st[-1][0]:
st.pop()
u = i > 0 and A[i-1] >= A[i]
if not st:
st.append([a, u])
continue... | output | 1 | 13,160 | 0 | 26,321 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,161 | 0 | 26,322 |
"Correct Solution:
```
import sys
stdin = sys.stdin
sys.setrecursionlimit(10**5)
def li(): return map(int, stdin.readline().split())
def li_(): return map(lambda x: int(x)-1, stdin.readline().split())
def lf(): return map(float, stdin.readline().split())
def ls(): return stdin.readline().split()
def ns(): return s... | output | 1 | 13,161 | 0 | 26,323 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,162 | 0 | 26,324 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
ok, ng = n, 0
while ok-ng > 1:
x = (ok+ng)//2
#d = defaultdict(int)
d = dict()
last = 0
valid = True
if x == 1:
for i in range(n-1):
if a[i] >= a[i+1]:
valid = False
break
if valid:
ok = x
else:
ng = x
continue
... | output | 1 | 13,162 | 0 | 26,325 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,163 | 0 | 26,326 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
A = [int(x) for x in input().split()]
A.append(1)
B = [A[0]]
B_cnt = [1]
for i,(x,y) in enumerate(zip(A[:-1],A[1:])):
if x < y and y < A[i+2]:
continue
if x == y:
B_cnt[-1] += 1
else:
B.append(y)
... | output | 1 | 13,163 | 0 | 26,327 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,164 | 0 | 26,328 |
"Correct Solution:
```
N = int(input())
A = [int(a) for a in input().split()]
def chk(k):
if k == 1:
for i in range(1, N):
if A[i] <= A[i-1]: return 0
return 1
X = [(0, 0)]
def add(x, y):
if x <= 0: return 0
if x > X[-1][0]:
X.append((x, 0 if x =... | output | 1 | 13,164 | 0 | 26,329 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,165 | 0 | 26,330 |
"Correct Solution:
```
def is_possible(x, A):
current = {}
length = 0
for a in A:
if a <= length:
if x == 1:
return False
current = {k: current[k] for k in current if k < a}
i = a - 1
if i not in current:
current[i] = 0
... | output | 1 | 13,165 | 0 | 26,331 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,166 | 0 | 26,332 |
"Correct Solution:
```
N = int(input())
A_raw = list(map(int, input().split()))
flg = 1
prev = 0
A = []
for i in range(N):
if A_raw[i] <= prev:
flg = 0
prev = A_raw[i]
if A_raw[i] <= 50:
A.append(A_raw[i])
if flg:
print(1)
exit()
N = len(A)
if N <= 1:
print(2)
exit()
ok =... | output | 1 | 13,166 | 0 | 26,333 |
Provide a correct Python 3 solution for this coding contest problem.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N holds lexicographically, where S_i is the i-th string fr... | instruction | 0 | 13,167 | 0 | 26,334 |
"Correct Solution:
```
def solve(aaa):
l = 1
r = 200000
while l < r:
m = (l + r) // 2
if check(m, aaa):
r = m
else:
l = m + 1
return r
def check(d, aaa):
if d == 1:
return all(a1 < a2 for a1, a2 in zip(aaa, aaa[1:]))
l = 0
word = [[0,... | output | 1 | 13,167 | 0 | 26,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,168 | 0 | 26,336 |
Yes | output | 1 | 13,168 | 0 | 26,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,169 | 0 | 26,338 |
Yes | output | 1 | 13,169 | 0 | 26,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,170 | 0 | 26,340 |
Yes | output | 1 | 13,170 | 0 | 26,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,171 | 0 | 26,342 |
Yes | output | 1 | 13,171 | 0 | 26,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,172 | 0 | 26,344 |
No | output | 1 | 13,172 | 0 | 26,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,173 | 0 | 26,346 |
No | output | 1 | 13,173 | 0 | 26,347 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,174 | 0 | 26,348 |
No | output | 1 | 13,174 | 0 | 26,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N strings arranged in a row. It is known that, for any two adjacent strings, the string to the left is lexicographically smaller than the string to the right. That is, S_1<S_2<...<S_N ... | instruction | 0 | 13,175 | 0 | 26,350 |
No | output | 1 | 13,175 | 0 | 26,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya owns three strings s , a and b, each of them consists only of first k Latin letters.
Let a template be such a string of length k that each of the first k Latin letters appears in it exact... | instruction | 0 | 13,339 | 0 | 26,678 |
No | output | 1 | 13,339 | 0 | 26,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya owns three strings s , a and b, each of them consists only of first k Latin letters.
Let a template be such a string of length k that each of the first k Latin letters appears in it exact... | instruction | 0 | 13,340 | 0 | 26,680 |
No | output | 1 | 13,340 | 0 | 26,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya owns three strings s , a and b, each of them consists only of first k Latin letters.
Let a template be such a string of length k that each of the first k Latin letters appears in it exact... | instruction | 0 | 13,341 | 0 | 26,682 |
No | output | 1 | 13,341 | 0 | 26,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya owns three strings s , a and b, each of them consists only of first k Latin letters.
Let a template be such a string of length k that each of the first k Latin letters appears in it exact... | instruction | 0 | 13,342 | 0 | 26,684 |
No | output | 1 | 13,342 | 0 | 26,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,411 | 0 | 26,822 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
def main():
n = int(input())
ss = list(zip(input(), range(0,n)))
res = [1]*n
max_colour = 1
nextx = [0] * 26
colours_after = [[True]+[False]*26 for _ in range(26)]
for i in range(n):
ch = ord(ss[i][0]) ... | output | 1 | 13,411 | 0 | 26,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,412 | 0 | 26,824 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
n = int(input())
s = input()
ans = [-1] * n
f = True
for i in range(n):
if ans[i] == -1:
ans[i] = 0
for j in range(i + 1, n):
if (s[j] < s[i]):
if ans[j] == -1:
ans[j] = (ans[i] - 1) ** ... | output | 1 | 13,412 | 0 | 26,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,413 | 0 | 26,826 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
n=int(input())
s=input()
last,last1='a','a'
ans=''
flag=1
for i in s:
if i<last and i<last1:
flag=0
break
elif i>=last:
last=i
ans+='0'
else:
last1=i
ans+='1'
if flag:
print(... | output | 1 | 13,413 | 0 | 26,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,414 | 0 | 26,828 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
import sys
def main():
n = int(sys.stdin.readline().split()[0])
s = sys.stdin.readline().split()[0]
color = [None]*n
color[0] = 0
for i in range(n):
if color[i] == None:
color[i] = 0
for j ... | output | 1 | 13,414 | 0 | 26,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,415 | 0 | 26,830 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
# ---------------------------iye ha aam zindegi---------------------------------------------
import math
import random
import heapq, bisect
import sys
from collections import deque, defaultdict
from fractions import Fraction
import sys
im... | output | 1 | 13,415 | 0 | 26,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,416 | 0 | 26,832 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
#t = int(input())
t=1
while t!=0:
t-=1
n = int(input())
s = input()
l1, l2 = 'a' , 'a'
ans = ''
for i in range(n):
if s[i]>=l1:
l1 = s[i]
ans+='0'
elif s[i]>=l2:
... | output | 1 | 13,416 | 0 | 26,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.
You are given a string s consisting of n... | instruction | 0 | 13,417 | 0 | 26,834 |
Tags: constructive algorithms, dp, graphs, greedy, sortings
Correct Solution:
```
def main():
n = int(input())
s = list(input())
colors = [-1]*n
for i in range(len(s)):
if colors[i] == -1:
colors[i] = 0
for j in range(i+1,n):
if s[j] < s[i]:
... | output | 1 | 13,417 | 0 | 26,835 |
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