message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a... | instruction | 0 | 14,800 | 0 | 29,600 |
"Correct Solution:
```
from bisect import bisect_right
s = input()
t = input()
n = len(s)
mp = [[] for _ in range(26)]
s += s
for i in range(len(s)):
mp[ord(s[i]) - ord('a')].append(i)
ans = 0
now = -1
for i in range(len(t)):
a = ord(t[i]) - ord('a')
nxt = bisect_right(mp[a], now)
if len(mp[a]) == n... | output | 1 | 14,800 | 0 | 29,601 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a... | instruction | 0 | 14,801 | 0 | 29,602 |
"Correct Solution:
```
import string
import bisect
S = input()
T = input()
n = len(S)
sa = {_: [] for _ in string.ascii_lowercase}
for i, s in enumerate(S):
sa[s] += [i]
ans = 0
i = -1
for t in T:
if sa[t]:
j = bisect.bisect_left(sa[t], i + 1)
if j == len(sa[t]):
ni = sa[t][0] + n
... | output | 1 | 14,801 | 0 | 29,603 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a... | instruction | 0 | 14,802 | 0 | 29,604 |
"Correct Solution:
```
S = input()
T = input()
length = len(S)
ans = 0
pre = -1
for t in T:
x = S.find(t, pre+1, length)
if x != -1:
ans += x - pre
pre = x
else:
x = S.find(t, 0, pre+1)
if x != -1:
ans += length + x - pre
pre = x
else:
... | output | 1 | 14,802 | 0 | 29,605 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.
* Let s' be the concatenation of 10^{100} copies of s. t is a... | instruction | 0 | 14,803 | 0 | 29,606 |
"Correct Solution:
```
s = input()
n = len(s)
l = [[]for i in range(26)]
for i, c in enumerate(s * 2):
l[ord(c) - ord('a')].append(i)
from bisect import *
shukai = 0
now = 0
t = input()
for c in t:
x = ord(c) - ord('a')
if len(l[x]) == 0:
print(-1)
exit()
i = bisect_left(l[x], now)
... | output | 1 | 14,803 | 0 | 29,607 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,828 | 0 | 29,656 |
"Correct Solution:
```
import sys
#input = sys.stdin.buffer.readline
def main():
N = int(input())
S = input()
Q = input()
x = tuple(map(int,input().split()))
for k in x:
d,m,dm,dmc = 0,0,0,0
for i in range(N):
st = S[i]
if st == "D":
d += 1
... | output | 1 | 14,828 | 0 | 29,657 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,829 | 0 | 29,658 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
S = list(input())[: -1]
Q = int(input())
qs = list(map(int, input().split()))
cs = [0] * (N + 1)
c = []
d = []
for i in range(N):
cs[i + 1] = cs[i] + (S[i] == "M")
if S[i] == "C": c.append(i)
if S[i] == "D": d.append(i)
ccs = [0] * (N +... | output | 1 | 14,829 | 0 | 29,659 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,830 | 0 | 29,660 |
"Correct Solution:
```
n = int(input())
s = input()
q = int(input())
K = list(map(int,input().split()))
for ii in range(q):
# D = [[0] * 3 for i in range(n)]
d = 0
m = 0
dm = 0
ans = 0
k = K[ii]
for i in range(n):
# for j in range(3):
# D[i][j] = D[i-1][j]
... | output | 1 | 14,830 | 0 | 29,661 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,831 | 0 | 29,662 |
"Correct Solution:
```
def main():
n = int(input())
s = input()
q = int(input())
k = list(map(int, input().split()))
for ki in k:
ans = 0
DMC = [0]*3
for i in range(n):
if s[i] == "D":
DMC[0] += 1
elif s[i] == "M":
DMC[1... | output | 1 | 14,831 | 0 | 29,663 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,832 | 0 | 29,664 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
input = sys.stdin.readline
input = sys.stdin.buffer.readline
#sys.setrecursionlimit(10**9)
#from functools import lru_cache
def RD(): return sys.stdin.read()
def II(): return int(input())
def MI(): return map(int,input().split())
def MF(): return map(floa... | output | 1 | 14,832 | 0 | 29,665 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,833 | 0 | 29,666 |
"Correct Solution:
```
n=int(input())
s=input()
q=int(input())
k=list(map(int,input().split()))
for x in k:
d,m,dm,ans=0,0,0,0
for i in range(n):
ss=s[i]
if ss=='D':
d+=1
elif ss=='M':
m+=1
dm+=d
elif ss=='C':
ans+=dm
if i>=x-1:
ss=s[i-x+1]
if ss=='D':
... | output | 1 | 14,833 | 0 | 29,667 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,834 | 0 | 29,668 |
"Correct Solution:
```
N = int(input())
S = input()
Q = int(input())
K = list(map(int, input().split()))
for k in K:
res = 0
d = 0
m = 0
dm = 0
for i in range(N):
if S[i] == 'D':
d += 1
elif S[i] == 'M':
dm += d
m += 1
elif S[i] == 'C':
... | output | 1 | 14,834 | 0 | 29,669 |
Provide a correct Python 3 solution for this coding contest problem.
In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.
Given a string S of length N and an ... | instruction | 0 | 14,835 | 0 | 29,670 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
def main():
N = int(input())
S = input()
Q = input()
x = tuple(map(int,input().split()))
for k in x:
d,m,dm,dmc = 0,0,0,0
for i in range(N):
st = S[i]
if st == "D":
d += 1
... | output | 1 | 14,835 | 0 | 29,671 |
Provide a correct Python 3 solution for this coding contest problem.
()
Problem Statement
There is a string S. Initially, S is an empty string.
Perform the following processing in order of n.
* Add x_i p_i (=" (" or") ") to the end of S.
After processing, determine if S is a well-balanced string.
"The string is... | instruction | 0 | 15,025 | 0 | 30,050 |
"Correct Solution:
```
n = int(input())
s = 0
f = 0
for i in range(n):
p,x = input().split()
x = int(x)
if p == "(":
s += x
else:
s -= x
if s < 0:
f = 1
if f or s != 0:
print("NO")
else:
print("YES")
``` | output | 1 | 15,025 | 0 | 30,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,090 | 0 | 30,180 |
Tags: greedy, implementation, strings
Correct Solution:
```
from sys import stdin
input = stdin.readline
def is_good(arr):
digit = False
upper = False
lower = False
for c in arr:
if c.isdigit():
digit = True
elif c.isupper():
upper = True
else:
... | output | 1 | 15,090 | 0 | 30,181 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,091 | 0 | 30,182 |
Tags: greedy, implementation, strings
Correct Solution:
```
n = int(input())
abc = 'qwertyuiopasdfghjklzxcvbnm'
ABC = 'QWERTYUIOPASDFGHJKLZXCVBNM'
nu = '0123456789'
d = []
for i in range(n):
coa = 0
coA = 0
co1 = 0
s = input()
for j in range(len(s)):
if s[j] in abc:
coa += 1
... | output | 1 | 15,091 | 0 | 30,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,092 | 0 | 30,184 |
Tags: greedy, implementation, strings
Correct Solution:
```
def check_pass(password):
upper = False
num = False
lower = False
for ch in password:
if(ord(ch) >= 97 and ord(ch) <= 122):
lower = True
elif(ord(ch) >= 65 and ord(ch) <= 90):
upper = True
elif(int(ch) >= 0 and int(ch) <= 9):
... | output | 1 | 15,092 | 0 | 30,185 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,093 | 0 | 30,186 |
Tags: greedy, implementation, strings
Correct Solution:
```
t = int(input())
for _ in range(t):
s = str(input())
l = []
u = []
d = []
for i, c in enumerate(s):
if c.islower():
l.append(i)
elif c.isupper():
u.append(i)
else:
d.append(i)
... | output | 1 | 15,093 | 0 | 30,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,094 | 0 | 30,188 |
Tags: greedy, implementation, strings
Correct Solution:
```
for _ in range(int(input())):
C, s = {'0':0, 'A':0, 'a':0}, input()
first = '0' if s[0].isdigit() else 'A' if s[0].isupper() else 'a'
last = '0' if s[-1].isdigit() else 'A' if s[-1].isupper() else 'a'
for ch in s:
if ch.isdigi... | output | 1 | 15,094 | 0 | 30,189 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,095 | 0 | 30,190 |
Tags: greedy, implementation, strings
Correct Solution:
```
for _ in range(int(input())):
s=input()
counta=0
countA=0
count1=0
for j in range(len(s)):
if ord('a')<=ord(s[j])<=ord('z'):
counta+=1
elif ord('A')<=ord(s[j])<=ord('Z'):
countA+=1
else:
... | output | 1 | 15,095 | 0 | 30,191 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,096 | 0 | 30,192 |
Tags: greedy, implementation, strings
Correct Solution:
```
import string
(t,) = map(int, input().split())
def invalid(s):
minus = len(list(filter(lambda x: x in string.ascii_lowercase, s)))
mayus = len(list(filter(lambda x: x in string.ascii_uppercase, s)))
digits = len(list(filter(lambda x: x in string... | output | 1 | 15,096 | 0 | 30,193 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since EatForces takes care of the security of its users,... | instruction | 0 | 15,097 | 0 | 30,194 |
Tags: greedy, implementation, strings
Correct Solution:
```
n = int(input())
B = [{"0", "1", "2", "3", "4", "5", "6", "7", "8", "9"},{"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"} ,{"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K",... | output | 1 | 15,097 | 0 | 30,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,098 | 0 | 30,196 |
Yes | output | 1 | 15,098 | 0 | 30,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,099 | 0 | 30,198 |
Yes | output | 1 | 15,099 | 0 | 30,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,100 | 0 | 30,200 |
Yes | output | 1 | 15,100 | 0 | 30,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,101 | 0 | 30,202 |
Yes | output | 1 | 15,101 | 0 | 30,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,102 | 0 | 30,204 |
No | output | 1 | 15,102 | 0 | 30,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,103 | 0 | 30,206 |
No | output | 1 | 15,103 | 0 | 30,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,104 | 0 | 30,208 |
No | output | 1 | 15,104 | 0 | 30,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.
But since Eat... | instruction | 0 | 15,105 | 0 | 30,210 |
No | output | 1 | 15,105 | 0 | 30,211 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,157 | 0 | 30,314 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
from sys import stdin
n, k = [int(i) for i in stdin.readline().strip().split()]
s = stdin.readline().strip()
class Subsequences:
def __init__(self, sequence):
self._seq = list(sequence)
self._F = [len(sequence) * [0] for _ in ... | output | 1 | 15,157 | 0 | 30,315 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,158 | 0 | 30,316 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
# your code goes here
n,k=map(int,input().split())
s=input()
c=0
q=[s]
d=set()
ls=0
while q:
p=q.pop(0)
if p not in d:
ls+=1
c+=(n-len(p))
if ls==k:
break
d.add(p)
for i in range(len(p)):
temp=p[:i]+p[i+1:]
if temp not in d:
... | output | 1 | 15,158 | 0 | 30,317 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,159 | 0 | 30,318 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" i... | output | 1 | 15,159 | 0 | 30,319 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,160 | 0 | 30,320 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
import sys
n, k = map(int, sys.stdin.readline().split(' '))
s = sys.stdin.readline().strip()
lt = [s]
count = 0
flag = False
result = 0
while lt:
cur_s = lt[0]
lt.pop(0)
result += len(s) - len(cur_s)
count += 1
if count >= k:
... | output | 1 | 15,160 | 0 | 30,321 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,161 | 0 | 30,322 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
import sys
input=sys.stdin.readline
from collections import deque
n,k=map(int,input().split())
s=list(input().rstrip())
vis=set()
dq=deque(["".join(s)])
cnt=0
score=0
while dq:
ss=dq.popleft()
if ss not in vis:
score+=n-len(ss)
... | output | 1 | 15,161 | 0 | 30,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,162 | 0 | 30,324 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
if __name__ == '__main__':
n, k = map(int, input().split())
aa = list(input())
st = {"".join(aa)}
arr = [aa]
w = 0
c = 0
cst = 0
while len(arr) < k and w < len(arr):
wrd = arr[w][:c] + arr[w][c + 1:]
... | output | 1 | 15,162 | 0 | 30,325 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,163 | 0 | 30,326 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
n, k = map(int, input().split())
s = input()
dp = [[0] * 102 for i in range(102)]
dp1 = [[0] * 102 for i in range(30)]
for i in range(0, n + 1):
dp[i][0] = 1
for i in range(1, n + 1):
nm = ord(s[i - 1]) - ord('a')
for le in range(1, i ... | output | 1 | 15,163 | 0 | 30,327 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the order of the remaining symbols. Characters to b... | instruction | 0 | 15,164 | 0 | 30,328 |
Tags: dp, graphs, implementation, shortest paths
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" i... | output | 1 | 15,164 | 0 | 30,329 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,165 | 0 | 30,330 |
Yes | output | 1 | 15,165 | 0 | 30,331 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,166 | 0 | 30,332 |
Yes | output | 1 | 15,166 | 0 | 30,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,167 | 0 | 30,334 |
Yes | output | 1 | 15,167 | 0 | 30,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,168 | 0 | 30,336 |
Yes | output | 1 | 15,168 | 0 | 30,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,169 | 0 | 30,338 |
No | output | 1 | 15,169 | 0 | 30,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,170 | 0 | 30,340 |
No | output | 1 | 15,170 | 0 | 30,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,171 | 0 | 30,342 |
No | output | 1 | 15,171 | 0 | 30,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is constraints.
A subsequence is a string that can be derived from another string by deleting some or no symbols without changing the ... | instruction | 0 | 15,172 | 0 | 30,344 |
No | output | 1 | 15,172 | 0 | 30,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string s consisting of lowercase English letters only. Find its lexicographically largest palindromic s... | instruction | 0 | 15,341 | 0 | 30,682 |
Tags: binary search, bitmasks, brute force, greedy, implementation, strings
Correct Solution:
```
I = lambda: int(input())
IL = lambda: list(map(int, input().split()))
s = list(input())
print(max(s) * s.count(max(s)))
``` | output | 1 | 15,341 | 0 | 30,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string s consisting of lowercase English letters only. Find its lexicographically largest palindromic s... | instruction | 0 | 15,342 | 0 | 30,684 |
Tags: binary search, bitmasks, brute force, greedy, implementation, strings
Correct Solution:
```
## necessary imports
import sys
input = sys.stdin.readline
from math import ceil, floor, factorial;
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp
## gcd function
d... | output | 1 | 15,342 | 0 | 30,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string s consisting of lowercase English letters only. Find its lexicographically largest palindromic s... | instruction | 0 | 15,343 | 0 | 30,686 |
Tags: binary search, bitmasks, brute force, greedy, implementation, strings
Correct Solution:
```
def Filter(a, n):
j = 0
ans = []
while n > 0:
last_bit = n & 1
if last_bit:
ans.append(a[j])
j += 1
n = n >> 1
return ans
def subs(a):
ultimate = []
for... | output | 1 | 15,343 | 0 | 30,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string s consisting of lowercase English letters only. Find its lexicographically largest palindromic s... | instruction | 0 | 15,344 | 0 | 30,688 |
Tags: binary search, bitmasks, brute force, greedy, implementation, strings
Correct Solution:
```
c = input() ; print(max(c) * c.count(max(c)));
``` | output | 1 | 15,344 | 0 | 30,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string s consisting of lowercase English letters only. Find its lexicographically largest palindromic s... | instruction | 0 | 15,345 | 0 | 30,690 |
Tags: binary search, bitmasks, brute force, greedy, implementation, strings
Correct Solution:
```
s = input()
maxn = max(s)
for i in s:
if i == maxn:
print(i,end="")
print("")
``` | output | 1 | 15,345 | 0 | 30,691 |
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