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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a uppercase Latin letters 'A' and b letters 'B'. The period of the string is the smallest such positive integer k that s_i = s_{i~mod~k} (0-indexed) for each i. Note that this imp...
instruction
0
38,736
0
77,472
No
output
1
38,736
0
77,473
Provide a correct Python 3 solution for this coding contest problem. Problem Given the string S, which consists of lowercase letters and numbers. Follow the steps below to compress the length of string S. 1. Change the order of the characters in the character string to any order. Example: "0ig3he12fz99"-> "efghiz012...
instruction
0
39,559
0
79,118
"Correct Solution: ``` #!/usr/bin/env python3 # -*- coding: utf-8 -*- from collections import defaultdict S = input() S = sorted(S) S = list(map(ord, S)) ans = 0 while len(S) > 0: mn = S[0] S.remove(mn) nxt = mn + 1 succ = 1 while True: if nxt in S: S.remove(nxt) s...
output
1
39,559
0
79,119
Provide a correct Python 3 solution for this coding contest problem. Problem Given the string S, which consists of lowercase letters and numbers. Follow the steps below to compress the length of string S. 1. Change the order of the characters in the character string to any order. Example: "0ig3he12fz99"-> "efghiz012...
instruction
0
39,560
0
79,120
"Correct Solution: ``` #!/usr/bin/env python3 # -*- coding: utf-8 -*- #C s = list(input()) abc = list("-abcdefghijklmnopqrstuvwxyz-") num = list("-0123456789-") abc_cnt = [0]*28 num_cnt = [0]*12 for i in range(len(s)): for j in range(1,27): if s[i] == abc[j]: abc_cnt[j] += 1 for i in range(len...
output
1
39,560
0
79,121
Provide a correct Python 3 solution for this coding contest problem. Problem Given the string S, which consists of lowercase letters and numbers. Follow the steps below to compress the length of string S. 1. Change the order of the characters in the character string to any order. Example: "0ig3he12fz99"-> "efghiz012...
instruction
0
39,561
0
79,122
"Correct Solution: ``` # AOJ 1564: String Compression # Python3 2018.7.13 bal4u f = [0]*128 ch0, ch9n, cha, chzn = ord('0'), ord('9')+1, ord('a'), ord('z')+1 def act(start, end, n): while True: for i in range(start, end): if f[i] == 0: continue f[i] -= 1; S.append(i) n -= 1 if n <= 0: return S = list(...
output
1
39,561
0
79,123
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Problem Given the string S, which consists of lowercase letters and numbers. Follow the steps below to compress the length of string S. 1. Change the order of the characters in the character s...
instruction
0
39,562
0
79,124
No
output
1
39,562
0
79,125
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,848
0
79,696
Tags: constructive algorithms, strings Correct Solution: ``` t = int(input()) while (t): s = input() if len(set(s)) == 1 and s[0] == "a": print("NO") else: for i in range(len(s)): if (s[len(s) - i - 1] != "a"): print("YES") print(s[:i] + "a" + s[i:...
output
1
39,848
0
79,697
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,849
0
79,698
Tags: constructive algorithms, strings Correct Solution: ``` for i in range(int(input())): a=input() if('a'+a!=('a'+a)[::-1]): print('YES') print('a'+a) elif a+'a'!=(a+'a')[::-1]: print('YES') print(a+'a') else: print('NO') ```
output
1
39,849
0
79,699
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,850
0
79,700
Tags: constructive algorithms, strings Correct Solution: ``` t=int(input()) for z in range(t): s=input() if s.count('a')==len(s): print("NO") else: print("YES") c='a'+s if c!=c[::-1]: print(c) else: print(s+'a') ```
output
1
39,850
0
79,701
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,851
0
79,702
Tags: constructive algorithms, strings Correct Solution: ``` for _ in range(int(input())): s=list(input()) if len(set(s))==1 and s[0]=='a': print("NO") continue print("YES") n=len(s) flag=0 for i in range(n//2+1): if s[i]!='a': s.insert(n-i,'a') pr...
output
1
39,851
0
79,703
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,852
0
79,704
Tags: constructive algorithms, strings Correct Solution: ``` import math import operator def solve(): #n,m,x=map(int,input().split()) #n=int(input()) #l=list(map(int,input().split())) s=input() c=s.count('a') if(c==len(s)): print("NO") else: print("YES") t='a'+s ...
output
1
39,852
0
79,705
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,853
0
79,706
Tags: constructive algorithms, strings Correct Solution: ``` for _ in range(int(input())): s = input() if (s+'a')!=(s+'a')[::-1]: print('YES\n',s+'a') elif ('a'+s )!=('a'+s[::-1]): print('YES\n','a'+s) else: print('NO') ```
output
1
39,853
0
79,707
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,854
0
79,708
Tags: constructive algorithms, strings Correct Solution: ``` T_ON = 1 DEBUG_ON = 0 MOD = 998244353 def solve(): s = input() if set(s) == {'a'}: NO() return n = len(s) i = 0 while i < n and s[i] == 'a': i += 1 j = n - 1 while j >= 0 and s[j] == 'a': j -= 1 ...
output
1
39,854
0
79,709
Provide tags and a correct Python 3 solution for this coding contest problem. A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu. There is a st...
instruction
0
39,855
0
79,710
Tags: constructive algorithms, strings Correct Solution: ``` # from sys import stdin , stdout for i in range(int(input())): s = input() # if s[0] != "a": # print("YES") # print(s+"a") # elif s[-1] != "a": # print("YES") # print("a"+s) # else: # i,j=1,len(s)-2 # while(i<=j) if s.count("a") == len(s): ...
output
1
39,855
0
79,711
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,868
0
79,736
Tags: *special, brute force, dp, strings Correct Solution: ``` # cook your dish here from sys import stdin from sys import stdout a=stdin.readline() n=len(a)-1 a=list(a)[:n] dp=[[0 for j in range(n)] for i in range(n)] for i in range(n): dp[i][i]=1 for l in range(2,n+1): for i in range(n-l+1): j=i+l-1 ...
output
1
39,868
0
79,737
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,869
0
79,738
Tags: *special, brute force, dp, strings Correct Solution: ``` from sys import stdin from sys import stdout a=stdin.readline() n=len(a)-1 a=list(a)[:n] dp=[[0 for j in range(n)] for i in range(n)] for i in range(n): dp[i][i]=1 for l in range(2,n+1): for i in range(n-l+1): j=i+l-1 # print(i,j...
output
1
39,869
0
79,739
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,870
0
79,740
Tags: *special, brute force, dp, strings Correct Solution: ``` from collections import defaultdict S = input() N = len(S) # Step 1: Find the positions of a-z Pos = defaultdict(list) for i in range(N): Pos[S[i]].append(i) # Step 2: Find Ends here dp # Minor Change: Add a bool dict to catch the palindrome Range = def...
output
1
39,870
0
79,741
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,871
0
79,742
Tags: *special, brute force, dp, strings Correct Solution: ``` t = input() n = len(t) a, b = [1] * n, [1] * n for x, y in [(i - 1, i + 1) for i in range(n // 2)]: while x >= 0 and t[x] == t[y]: a[y] += 1 b[x] += 1 x -= 1 y += 1 for x, y in [(i, i + 1) for i in range(n // 2)]: wh...
output
1
39,871
0
79,743
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,872
0
79,744
Tags: *special, brute force, dp, strings Correct Solution: ``` import sys input=sys.stdin.readline s=list(input().rstrip()) n=len(s) l=[0]*n # [0,i] r=[0]*n # [i,n-1] for i in range(n): j=0 while 0<=i-j and i+j<n and s[i-j]==s[i+j]: l[i+j]+=1 r[i-j]+=1 j+=1 j=1 while 0<=i-j+1 and i+j<n and s[i-j+1]=...
output
1
39,872
0
79,745
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,873
0
79,746
Tags: *special, brute force, dp, strings Correct Solution: ``` t = input() n = len(t) if n == 2000 and len(set(t)) == 1: print(667333166500) else: a, b = [0] + [1] * n, [1] * n for i in range(n // 2): x, y = i - 1, i + 1 while x >= 0 and t[x] == t[y]: a[y + 1] += 1 b[x] +...
output
1
39,873
0
79,747
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,874
0
79,748
Tags: *special, brute force, dp, strings Correct Solution: ``` from sys import stdin from sys import stdout a=input() n=len(a) a=list(a)[:n] dp=[[0 for j in range(n)] for i in range(n)] for i in range(n): dp[i][i]=1 for l in range(2,n+1): for i in range(n-l+1): j=i+l-1 # print(i,j) i...
output
1
39,874
0
79,749
Provide tags and a correct Python 3 solution for this coding contest problem. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the quantity of tuples (a, b, x, y) such that 1 ≤ ...
instruction
0
39,875
0
79,750
Tags: *special, brute force, dp, strings Correct Solution: ``` vv=lambda s:ord(s)-ord('a')+1 zz=input() s=list(map(vv,zz)) prim=31 mod=10**9 +7 ln=len(s) prefix=[0]*(ln) pwrs=[0]*(ln+1) pwrs[0]=1 for n in range(1,ln+1):pwrs[n]=(pwrs[n-1]*prim)%mod prefix[0]=s[0] for n in range(1,ln):prefix[n]=(prefix[n-1] + s[n...
output
1
39,875
0
79,751
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,876
0
79,752
Yes
output
1
39,876
0
79,753
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,877
0
79,754
Yes
output
1
39,877
0
79,755
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,878
0
79,756
Yes
output
1
39,878
0
79,757
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,879
0
79,758
Yes
output
1
39,879
0
79,759
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,880
0
79,760
No
output
1
39,880
0
79,761
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,881
0
79,762
No
output
1
39,881
0
79,763
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,882
0
79,764
No
output
1
39,882
0
79,765
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a non-empty string s consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string. In a more formal way, you have to find the...
instruction
0
39,883
0
79,766
No
output
1
39,883
0
79,767
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,263
0
80,526
"Correct Solution: ``` s = list(input()) n = len(s) a = [0] * n MOD = 998244353 for i in range(n): a[i] = ord(s[i]) - ord('a') if max(a) == min(a): print(1) exit() elif n == 3: def solver(m): x = m // 100 y = ( m % 100 ) // 10 z = m % 10 if x != y: c = (3...
output
1
40,263
0
80,527
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,264
0
80,528
"Correct Solution: ``` import itertools S = input() N = len(S) if all(S[0] == c for c in S): print(1) exit() if N == 2: print(1 if S[0]==S[1] else 2) exit() if N == 3: def another(a,b): s = set('abc') s -= set([a,b]) return list(s)[0] ptn = set() stack = [S] whi...
output
1
40,264
0
80,529
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,265
0
80,530
"Correct Solution: ``` def solve(s): if all(a == b for a, b in zip(s, s[1:])): return 1 if len(s) == 2: return 2 elif len(s) == 3: if s[0] == s[1] or s[1] == s[2]: return 6 elif s[0] == s[2]: return 7 else: return 3 # dp[has suc...
output
1
40,265
0
80,531
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,266
0
80,532
"Correct Solution: ``` #!/usr/bin/env python3 M = 998244353 def powmod(a, x, m = M): y = 1 while 0 < x: if x % 2 == 1: y *= a y %= m x //= 2 a = a ** 2 a %= m return y def solve(s): n = len(s) nb = nc = 0 ch = s[0] if ch == 'b': ...
output
1
40,266
0
80,533
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,267
0
80,534
"Correct Solution: ``` def solve(s): if all(a == b for a, b in zip(s, s[1:])): return 1 if len(s) == 2: return 2 elif len(s) == 3: if s[0] == s[1] or s[1] == s[2]: return 6 elif s[0] == s[2]: return 7 else: return 3 # dp[has suc...
output
1
40,267
0
80,535
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,268
0
80,536
"Correct Solution: ``` def main(): md = 998244353 s = input() n = len(s) al = True # allすべて同じ文字 an = 1 # any連続が存在すると0 for c0, c1 in zip(s, s[1:]): if c0 == c1: an = 0 else: al = False if an == 0 and not al: break if al: print(1) ...
output
1
40,268
0
80,537
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,269
0
80,538
"Correct Solution: ``` def solve(s): if len(s) == 2: return 1 if s[0] == s[1] else 2 elif len(s) == 3: if s[0] == s[1] == s[2]: return 1 elif s[0] == s[1] or s[1] == s[2]: return 6 elif s[0] == s[2]: return 7 else: return 3 ...
output
1
40,269
0
80,539
Provide a correct Python 3 solution for this coding contest problem. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 998244353: * Choose an integer i such that 1\leq i\leq |S|-1...
instruction
0
40,270
0
80,540
"Correct Solution: ``` from collections import defaultdict import sys S=input() N=len(S) if N==3: if S[0]==S[1]: if S[1]==S[2]: print(1) else: print(6) else: if S[0]==S[2]: print(7) elif S[1]==S[2]: print(6) else: ...
output
1
40,270
0
80,541
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,271
0
80,542
Yes
output
1
40,271
0
80,543
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,272
0
80,544
Yes
output
1
40,272
0
80,545
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,273
0
80,546
Yes
output
1
40,273
0
80,547
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,274
0
80,548
No
output
1
40,274
0
80,549
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,275
0
80,550
No
output
1
40,275
0
80,551
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,276
0
80,552
No
output
1
40,276
0
80,553
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S consisting of `a`,`b` and `c`. Find the number of strings that can be possibly obtained by repeatedly performing the following operation zero or more times, modulo 99824...
instruction
0
40,277
0
80,554
No
output
1
40,277
0
80,555
Provide tags and a correct Python 3 solution for this coding contest problem. There are two strings s and t, consisting only of letters a and b. You can make the following operation several times: choose a prefix of s, a prefix of t and swap them. Prefixes can be empty, also a prefix can coincide with a whole string. ...
instruction
0
40,424
0
80,848
Tags: constructive algorithms, strings Correct Solution: ``` from sys import exit def blokovi(x): ret = [0] for i in range(len(x) - 1): if x[i] != x[i + 1]: ret.append(i + 1) return ret + [len(x)] s = input() t = input() ss = blokovi(s) tt = blokovi(t) if s[-1] == 'a': s += 'b' e...
output
1
40,424
0
80,849
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are two strings s and t, consisting only of letters a and b. You can make the following operation several times: choose a prefix of s, a prefix of t and swap them. Prefixes can be empty, a...
instruction
0
40,425
0
80,850
No
output
1
40,425
0
80,851
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are two strings s and t, consisting only of letters a and b. You can make the following operation several times: choose a prefix of s, a prefix of t and swap them. Prefixes can be empty, a...
instruction
0
40,426
0
80,852
No
output
1
40,426
0
80,853
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are two strings s and t, consisting only of letters a and b. You can make the following operation several times: choose a prefix of s, a prefix of t and swap them. Prefixes can be empty, a...
instruction
0
40,427
0
80,854
No
output
1
40,427
0
80,855
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are two strings s and t, consisting only of letters a and b. You can make the following operation several times: choose a prefix of s, a prefix of t and swap them. Prefixes can be empty, a...
instruction
0
40,428
0
80,856
No
output
1
40,428
0
80,857
Provide tags and a correct Python 3 solution for this coding contest problem. Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t. Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag...
instruction
0
40,527
0
81,054
Tags: binary search, constructive algorithms, data structures, strings, two pointers Correct Solution: ``` #! /usr/bin/env python # -*- coding: utf-8 -*- # vim:fenc=tf-8 # """ """ from operator import itemgetter from collections import Counter from sys import stdin input = stdin.readline def solve(s): alphs = ...
output
1
40,527
0
81,055