message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,528 | 0 | 81,056 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
import string
def solve():
s = input()
n = int(input())
alphabets = len(string.ascii_lowercase)
count = [[0] * alphabets for _ in range(len(s) + 1)]
for i, c in enumerate(s, 1):
count[i][ord(c)... | output | 1 | 40,528 | 0 | 81,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,529 | 0 | 81,058 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
from itertools import accumulate
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] *... | output | 1 | 40,529 | 0 | 81,059 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,530 | 0 | 81,060 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
s = input()
n = len(s)
memo = [None]*(n+1)
count = [0]*26
memo[0] = count.copy()
for i,char in enumerate(s):
count[ord(char)-97] += 1
memo[i+1] = count.copy()
def f():
l, r = [int(char) for char in i... | output | 1 | 40,530 | 0 | 81,061 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,531 | 0 | 81,062 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
import sys
input=sys.stdin.readline
s=input().rstrip('\n')
l=len(s)
ref=[[0]*26]
ref1=[0]*26
for i in range(l):
#print(ord(s[i]))
ref1[ord(s[i])-97]+=1
ref.append(ref1.copy())
#@print(ref)
q=int(input(... | output | 1 | 40,531 | 0 | 81,063 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,532 | 0 | 81,064 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
s = input()
n = len(s)
dp = [[0] * 26 for _ in range(n + 1)]
for i in range(1, n + 1):
dp[i] = dp[i - 1].copy()
dp[i][ord(s[i - 1]) - ord('a')] += 1
for _ in range(int(input())):
l, r = map(int, inpu... | output | 1 | 40,532 | 0 | 81,065 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,533 | 0 | 81,066 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
ALPHA = 26
def unique(cnt, l, r):
sum = 0
for a,b in zip(cnt[l-1],cnt[r]):
sum += a < b
return sum
s = list(map(lambda c: ord(c)-ord('a'),list(input())))
cnt = [[0 for j in range(ALPHA)]]
for... | output | 1 | 40,533 | 0 | 81,067 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anag... | instruction | 0 | 40,534 | 0 | 81,068 |
Tags: binary search, constructive algorithms, data structures, strings, two pointers
Correct Solution:
```
def first():
s = input()
cases = int(input())
lastChange = [0]*len(s)
lastChange[0] = 0
lc = s[0]
for i in range(1, len(s)):
c = s[i]
if c != lc:
lastChange[i]... | output | 1 | 40,534 | 0 | 81,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,535 | 0 | 81,070 |
Yes | output | 1 | 40,535 | 0 | 81,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,536 | 0 | 81,072 |
Yes | output | 1 | 40,536 | 0 | 81,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,537 | 0 | 81,074 |
Yes | output | 1 | 40,537 | 0 | 81,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,538 | 0 | 81,076 |
Yes | output | 1 | 40,538 | 0 | 81,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,539 | 0 | 81,078 |
No | output | 1 | 40,539 | 0 | 81,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,540 | 0 | 81,080 |
No | output | 1 | 40,540 | 0 | 81,081 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,541 | 0 | 81,082 |
No | output | 1 | 40,541 | 0 | 81,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.
Let's consider two strings s and t which are anagrams o... | instruction | 0 | 40,542 | 0 | 81,084 |
No | output | 1 | 40,542 | 0 | 81,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some days ago, WJMZBMR learned how to answer the query "how many times does a string x occur in a string s" quickly by preprocessing the string s. But now he wants to make it harder.
So he want... | instruction | 0 | 40,706 | 0 | 81,412 |
No | output | 1 | 40,706 | 0 | 81,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some days ago, WJMZBMR learned how to answer the query "how many times does a string x occur in a string s" quickly by preprocessing the string s. But now he wants to make it harder.
So he want... | instruction | 0 | 40,707 | 0 | 81,414 |
No | output | 1 | 40,707 | 0 | 81,415 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,779 | 0 | 81,558 |
Tags: greedy
Correct Solution:
```
s=input()
t=input()
n=len(s)
l=[]
dist=0
for i in range(n):
if s[i]!=t[i]:
dist+=1
if dist%2:
print("impossible")
else:
flag=0
for i in range(n):
if s[i]==t[i]:
l.append(s[i])
else:
if flag==0:
l.append(... | output | 1 | 40,779 | 0 | 81,559 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,780 | 0 | 81,560 |
Tags: greedy
Correct Solution:
```
n=list(input())
k=list(input())
j=0
for i in range(len(n)):
if n[i]!=k[i]:
j=j+1
if j%2==0:
n[i]=k[i]
if j%2==0:
print(*n,sep='')
else:
print("impossible")
``` | output | 1 | 40,780 | 0 | 81,561 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,781 | 0 | 81,562 |
Tags: greedy
Correct Solution:
```
s, t = input(), input()
a, w1, w2 = 0, 0, 0
l = len(s)
q = [0 for i in range(l)]
for i in range(0, l):
if s[i] != t[i]:
a += 1
if a%2 == 1:
print("impossible")
else:
for i in range(0, l):
if s[i] != t[i] and w1 < a//2:
q[i] = s[i]
w1... | output | 1 | 40,781 | 0 | 81,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,782 | 0 | 81,564 |
Tags: greedy
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
def main():
s=input()
t=i... | output | 1 | 40,782 | 0 | 81,565 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,783 | 0 | 81,566 |
Tags: greedy
Correct Solution:
```
a=list(map(int,input()))
b=list(map(int,input()))
n=0
x=[]
ans=a.copy()
for i in range(len(a)):
if a[i]!=b[i]:
n+=1
x.append(i)
if n%2!=0:
print("impossible")
else:
for i in range(n//2):
ans[x[i]]=b[x[i]]
print("".join(map(str,ans)))
``` | output | 1 | 40,783 | 0 | 81,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,784 | 0 | 81,568 |
Tags: greedy
Correct Solution:
```
s = list(input())
t = list(input())
n = len(s)
res = []
turn = 0
for i in range (n):
if s[i] == t[i]:
res.append(s[i])
else:
turn += 1
if turn % 2 == 0:
res.append(s[i])
else:
res.append(t[i])
if turn % 2 != 0:
print(... | output | 1 | 40,784 | 0 | 81,569 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,785 | 0 | 81,570 |
Tags: greedy
Correct Solution:
```
g=input()
h=input()
c=0
for i in range(len(g)):
if int(g[i])^int(h[i])==1:
c+=1
if c%2==0:
for i in range(len(g)):
if int(g[i])^int(h[i])==1:
if c%2==0:
print(g[i],end='')
else:
print(h[i],end='')
... | output | 1 | 40,785 | 0 | 81,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming distance:
We will define the distance between two ... | instruction | 0 | 40,786 | 0 | 81,572 |
Tags: greedy
Correct Solution:
```
class CodeforcesTask545BSolution:
def __init__(self):
self.result = ''
self.s = ''
self.t = ''
def read_input(self):
self.s = input()
self.t = input()
def process_task(self):
n = len(self.s)
res = [0] * n
cn... | output | 1 | 40,786 | 0 | 81,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,787 | 0 | 81,574 |
Yes | output | 1 | 40,787 | 0 | 81,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,788 | 0 | 81,576 |
Yes | output | 1 | 40,788 | 0 | 81,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,789 | 0 | 81,578 |
Yes | output | 1 | 40,789 | 0 | 81,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,790 | 0 | 81,580 |
Yes | output | 1 | 40,790 | 0 | 81,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,791 | 0 | 81,582 |
No | output | 1 | 40,791 | 0 | 81,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,792 | 0 | 81,584 |
No | output | 1 | 40,792 | 0 | 81,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,793 | 0 | 81,586 |
No | output | 1 | 40,793 | 0 | 81,587 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings contain only digits zero and one. She uses the definition of Hamming dist... | instruction | 0 | 40,794 | 0 | 81,588 |
No | output | 1 | 40,794 | 0 | 81,589 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase English letters. There are two players: Mister... | instruction | 0 | 40,896 | 0 | 81,792 |
Tags: games, greedy
Correct Solution:
```
def main(a, b, l, r):
qL = (l - 1) // (2 * a + 2 * b)
rL = (l - 1) % (2 * a + 2 * b) + 1
qR = (r - 1) // (2 * a + 2 * b)
rR = (r - 1) % (2 * a + 2 * b) + 1
#print(qL, qR, rL, rR)
if qL == qR:
#In b segment
if a < rL <= a + b and... | output | 1 | 40,896 | 0 | 81,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase English letters. There are two players: Mister... | instruction | 0 | 40,897 | 0 | 81,794 |
Tags: games, greedy
Correct Solution:
```
def main(a, b, l, r):
qL = (l - 1) // (2 * a + 2 * b)
rL = (l - 1) % (2 * a + 2 * b) + 1
qR = (r - 1) // (2 * a + 2 * b)
rR = (r - 1) % (2 * a + 2 * b) + 1
#print(qL, qR, rL, rR)
if qL == qR:
#In b segment
if a < rL <=... | output | 1 | 40,897 | 0 | 81,795 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase English letters. There are two players: Mister... | instruction | 0 | 40,898 | 0 | 81,796 |
Tags: games, greedy
Correct Solution:
```
def main(a, b, l, r):
qL = (l - 1) // (2 * a + 2 * b)
rL = (l - 1) % (2 * a + 2 * b) + 1
qR = (r - 1) // (2 * a + 2 * b)
rR = (r - 1) % (2 * a + 2 * b) + 1
#print(qL, qR, rL, rR)
if qL == qR:
#In b segment
if a < rL <= a + b and... | output | 1 | 40,898 | 0 | 81,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase... | instruction | 0 | 40,899 | 0 | 81,798 |
No | output | 1 | 40,899 | 0 | 81,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase... | instruction | 0 | 40,900 | 0 | 81,800 |
No | output | 1 | 40,900 | 0 | 81,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase... | instruction | 0 | 40,901 | 0 | 81,802 |
No | output | 1 | 40,901 | 0 | 81,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sometimes Mister B has free evenings when he doesn't know what to do. Fortunately, Mister B found a new game, where the player can play against aliens.
All characters in this game are lowercase... | instruction | 0 | 40,902 | 0 | 81,804 |
No | output | 1 | 40,902 | 0 | 81,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
G： 検閲により置換 (Censored String)
Problem Statement
You are given the string S, and the set of strings \mathcal P whose size is N. Now we consider applying the following operation to S:
* Choose e... | instruction | 0 | 41,166 | 0 | 82,332 |
No | output | 1 | 41,166 | 0 | 82,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
G： 検閲により置換 (Censored String)
Problem Statement
You are given the string S, and the set of strings \mathcal P whose size is N. Now we consider applying the following operation to S:
* Choose e... | instruction | 0 | 41,167 | 0 | 82,334 |
No | output | 1 | 41,167 | 0 | 82,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
G： 検閲により置換 (Censored String)
Problem Statement
You are given the string S, and the set of strings \mathcal P whose size is N. Now we consider applying the following operation to S:
* Choose e... | instruction | 0 | 41,168 | 0 | 82,336 |
No | output | 1 | 41,168 | 0 | 82,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
G： 検閲により置換 (Censored String)
Problem Statement
You are given the string S, and the set of strings \mathcal P whose size is N. Now we consider applying the following operation to S:
* Choose e... | instruction | 0 | 41,169 | 0 | 82,338 |
No | output | 1 | 41,169 | 0 | 82,339 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,449 | 0 | 82,898 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
import sys
s = input().strip()
N = len(s)
if len(s) == 1:
print(1, s[0])
sys.exit()
X = [s[-1], s[-2]+s[-1] if s[-2]!=s[-1] else ""]
Y = [1, 2 if s[-2]!=s[-1] else 0]
for i in range(N-3, -1, -1):
c = s[i]
k1 = c+X[-1]
ng = Y[-1]+1
i... | output | 1 | 41,449 | 0 | 82,899 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,450 | 0 | 82,900 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
import io
import os
from collections import deque
def solve(S):
N = len(S)
ans = []
suff = deque()
suffUnique = deque()
count = 0
for i in reversed(range(N)):
x = S[i]
if i == N - 1 or S[i] != S[i + 1]:
... | output | 1 | 41,450 | 0 | 82,901 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,451 | 0 | 82,902 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
def main(s):
if len(s) == 0:
return []
if len(s) == 1:
return [[s], [1]]
s = s[::-1]
sres = [s[0]]
nres = [1]
if s[0] == s[1]:
sres.append('')
nres.append(0)
else:
sres.append(s[1] + s[0])... | output | 1 | 41,451 | 0 | 82,903 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,452 | 0 | 82,904 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
s = input()
n = len(s)
res = ['',s[-1]]
l = [1]
flag = True
last = ['']
for i in range(n-2,-1,-1):
tmp = res[-1]
if flag and s[i]==tmp[0] and s[i]>last[-1]:
res.append(res[-2])
l.append(l[-1]-1)
flag = False
if l[-1]... | output | 1 | 41,452 | 0 | 82,905 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,453 | 0 | 82,906 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
self._fd = file.fileno()
self.buffer = BytesIO()... | output | 1 | 41,453 | 0 | 82,907 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Some time ago Lesha found an entertaining string s consisting of lowercase English letters. Lesha immediately developed an unique algorithm for this string and shared it with you. The algorithm is as follows.
Lesha chooses an arbitrary (pos... | instruction | 0 | 41,454 | 0 | 82,908 |
Tags: dp, greedy, implementation, strings
Correct Solution:
```
import sys
z=sys.stdin.readline
s=z().strip()
l=len(s)
b=[' ']
o=[]
m=[' ']
for i in range(l):
c=s[-1-i]
if c==b[-1]:
if c>m[-1].lower() or (c==m[-1].lower() and c>m[-2].lower()):
b.pop()
if b[-1].lower()!=m[-1].lower():m.pop()
b[-1]=b[-1].upp... | output | 1 | 41,454 | 0 | 82,909 |
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